what is the mean? 66, 594, 69, or 74what is the median? 74, 66, 69, or 75what is the mode? 74, 90, 21, or 66what is the range? 69, 66, 74, or 594
Answers
We have the distribution;
74, 90, 21, 68, 62, 84, 34, 87,74.
Let's arrange this from ascending to descending order, we obtain;
[tex]21,34,62,68,74,74,84,87,90[/tex]i. The mean or average of this distribution is
[tex]\begin{gathered} \frac{21+34+62+68+74+74+84+87+90}{9}=\frac{594}{9} \\ \operatorname{mean}=66 \end{gathered}[/tex]ii. The median is the central value, in this distribution, there are 9 values, so the median value is the 5th value.
[tex]\operatorname{median}=74[/tex]iii. The mode is the value with the highest frequency, this is the most occurring value, in this distribution;
[tex]\text{mode}=74[/tex]iv. The range is the difference between the highest and lowest values, this is;
[tex]\begin{gathered} 90-21=69 \\ \text{Range}=69 \end{gathered}[/tex]
Related Questions
What is the median of the 19 numbersplotted in the line plot below?
Answers
Recall that the median of a set of numbers is the number in the middle of the set, after the numbers have been rearranged from lowest to highest.
From the plot, we get that the number, arranged from lowest to highest are:
[tex]40,40,40,40,40,41,41,41,42,42,43,43,43,43,44,44,44,45,45.[/tex]The number in the middle of the above set is:
[tex]42.[/tex]Therefore the median of the given numbers is:
[tex]42.[/tex]Answer: 42.
Determine the amplitude, period, and phase shift for y=1/3tan (0 +30) and use them to plot the graph of the function.
Answers
Given: The function below
[tex]y=\frac{1}{3}tan(\theta+30^0)[/tex]To Determine: The amplitude, the period, and the phase shift
Solution
The graph of the function is as shown below
The general equation of a tangent function is
[tex]f(x)=Atan(Bx+C)+D[/tex]Where
[tex]\begin{gathered} A=Amplitude \\ Period=\frac{\pi}{B} \\ Phase-shift=-\frac{C}{B} \\ Vertical-shift=D \end{gathered}[/tex]Let us compare the general form to the given
[tex]\begin{gathered} y=\frac{1}{3}tan(\theta+30^0) \\ f(x)=Atan(B\theta+C)+D \\ A=\frac{1}{3} \\ B=1 \\ C=30^0 \\ D=0 \end{gathered}[/tex]Therefore
[tex]\begin{gathered} Amplitude=\frac{1}{3} \\ Period=\frac{\pi}{B}=\frac{180^0}{1}=180^0 \\ Phase-shift=-\frac{C}{B}=-\frac{30^0}{1}=-30^0 \end{gathered}[/tex]Hence, the correct option is as shown below
instructions for building a polynomial roller coaster in factored form
Answers
The polynomial that is used to represent the roller coaster in factored form is y = +a x (x- 500) (x- 1000)
The given conditions are.
The negative intercept at x = 500
the roller coaster passes through the x-axis at x=0 and at x=1000
The polynomial equation is of the form will be
y = a x (x- 500) (x- 1000)
The polynomial will have a root at x=0 , at x=500 and at x = 1000
Polynomials are used in many areas of mathematics and science. For instance, they are employed in calculus, but numerical analysis is used to approximate other functions instead.
Polynomial functions are used in a variety of situations, from basic physics and biology to economics and social science. From straightforward word problems to intricate scientific conundrums, polynomial equations are utilized to represent a wide range of topics.
Polynomials are used in higher mathematics to construct algebraic varieties and polynomial rings, two key concepts in algebra and algebraic geometry with the use of variables.
Therefore the polynomial that is used to represent the roller coaster in factored form is y = a x (x- 500) (x- 1000)
To learn more about polynomial visit:
https://brainly.com/question/20121808
#SPJ9
Slove for x Cosec(x-20°)=2/√3
Answers
The trignometric ratio is x Cosec(x-20°)=2/√3 is x = 80°.
What is trigonometry as it is a ratio?Trigonometric: A ratio is the sum of the values of all trigonometric functions whose values depend on the ratio of the sides of a right-angled triangle.The trigonometric ratio of a right-angled triangle is determined by the ratio of the triangle's sides to any acute angle.Metric and trigon are the respective Greek words for measurement and triangle.Right triangles have a 90° angle, and trigonometric ratios are specific measurements of these triangles.Now, calculate the trigonometric ratio as follows:
cosec(x-20) = 2/√3cosec ( x-20) = cosec ( 60 )x - 20 = 60x = 80°Therefore, the trignometric ratio is x Cosec(x-20°)=2/√3 is x = 80°.
Learn more about trigonometric ratios:
brainly.com/question/25122825
#SPJ13
Michael monthly salary after tax is 2,675 if Michele pays for rent,food,and other Bill's totaling 2,140 then how much money is left
Answers
We are told that Michael has a total of $2675. If he spends $2140, then the total amount left is the difference between the total and the spent amount, that is:
[tex]2645-2140=505[/tex]Therefore, he has $505 left.
How would you change 65% to a decimal?
Answers
In converting percentage to decimals, you need to divide it by 100.
[tex]\frac{65}{100}=0.65[/tex]The answer is 0.65
There are 7 balls numbered I through 7 placed in a bucket What is the probability of reaching into the bucket and randomly drawing two balls numbered 6 and 3 without replacement, in that order? Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.
Answers
We have:
- Numbers of balls from 1 to 7 = 7
- Number of balls with number 6 = 1
- Number of ball with number 3 = 1
Then, the probability of ramdomly choosing a 6 is
[tex]p(6)=\frac{1}{7}[/tex]Once we chose a ball, there are 6 balls into the bucket. Then the probability of ramdomly choosing a 3 is
[tex]P(3)=\frac{1}{6}[/tex]Then, the probability of randomly choosing a 6 and 3 in that order, is
[tex]\begin{gathered} P(6\text{and}3)=P(6)\cdot P(3)=\frac{1}{7}\cdot\frac{1}{6} \\ P(6\text{ and 3)=}\frac{1}{7\cdot6} \\ P(6\text{ and 3)=}\frac{1}{42} \end{gathered}[/tex]that is, the probability is 1/42 = 0.023809
Two shaded cubes are shown. 6 feet 4 feet 6 feet 4 feet 4 feet 6 feet Ben states that the combined volume of these two shaded cubes is equal to the volume of this cube. 10 feet Vo feet 10 feet Find the combined volume of the two shaded cubes, and use it to explain whether Ben is right or not. Ben is correct. Ben is not correct.
Answers
The volume of a cube is given by the formula:
[tex]V=s^3[/tex]Where
s is the side length of a cube
Combined Volume of two cubes
Now, let's find the combined volume of the cubes with side lengths shown:
[tex]\begin{gathered} V=4^3+6^3 \\ V=64+216 \\ V=280 \end{gathered}[/tex]Volume of larger cube
Plugging into the formula, we get:
[tex]\begin{gathered} V=s^3 \\ V=10^3 \\ V=1000 \end{gathered}[/tex]Thus, we clearly see that:
[tex]280\neq1000[/tex]Thus,
Ben isn't correct
sketch the angle then find its reference angle [tex] \frac{13\pi}{4} [/tex]
Answers
We need to find the reference angle by sketching the angle:
First, we need to subtract it by 2π, then:
[tex]θ=\frac{13\pi}{4}-2\pi=\frac{5}{4}\pi[/tex]Hence, the reference angle is 5π / 4.
Which two expressions are equivalent?A. A(0.52)-21B. A(1.04)-C. A(0.96)D. A(0.96 0.08
Answers
Equivalent expressions are expressions that have the values when we put the same values for the variables.
From the given expressions, let's find the equivalent expressions.
From the given expressions, let's substitute 1 for t and evaluate.
The expressions with the same result will be equivalent expressions.
[tex]\begin{gathered} A(0.52)^{-2t} \\ \\ A(0.52)^{-2(1)} \\ \\ A(0.52)^{-2} \\ \\ A(\frac{1}{0.52^2}) \\ \\ A(\frac{1}{0.274}) \\ \\ =3.698A \end{gathered}[/tex][tex]\begin{gathered} A(1.04)^{-t}_{} \\ \\ A(1.04)^{-1} \\ \\ A(\frac{1}{1.04}) \\ \\ A(0.96) \\ \\ =0.96A \end{gathered}[/tex][tex]\begin{gathered} A(0.96)^t \\ \\ A(0.96)^1 \\ \\ A(0.96) \\ \\ =0.96A \end{gathered}[/tex][tex]\begin{gathered} A(0.96)^{0.08t}^{} \\ \\ A(0.96)^{0.08(1)} \\ \\ A(0.96)^{0.08} \\ \\ A(0.998) \\ \\ =0.998A \end{gathered}[/tex]The expressions with the same result are the expressions in options B and C:
[tex]\begin{gathered} B.A(1.04)^{-t} \\ \\ C.A(1.96)^t \end{gathered}[/tex]Therefore, the two expressions that are equivalent are:
[tex]\begin{gathered} B.A(1.04)^{-t} \\ \\ C.A(1.96)^t \end{gathered}[/tex]ANSWER:
[tex]\begin{gathered} \text{ B. A(1.04})^{-t} \\ \\ \text{ C. A(1.96)}^t \end{gathered}[/tex]Mason is standing on the seashore. He believes that if he makes a wish
and throws a seashell back into the ocean, his wish will come true. Mason is
standing at the origin of a coordinate plane and the shoreline is represented by the
graph of the line
y = 1.5x + 13. Each unit represents 1 meter. How far does Mason need to be able
to throw the seashell to throw one into the ocean? Round your answer to the
nearest centimeter.
Answers
To throw a seashell into the ocean, Mason needs to throw it above the line y = 1.5x + 13, which represents the shoreline.
This means that the seashell's height, y, must be greater than 1.5 times its horizontal distance, x, plus 13. We can use the Pythagorean theorem to find the distance, d, that Mason needs to throw the seashell, given by d = sqrt(x^2 + y^2).
We want to find the minimum value of d that satisfies y > 1.5x + 13. This occurs when y is equal to 1.5x + 13, since any larger value of y would require a larger value of d.
So we can substitute y = 1.5x + 13 into the equation for d and get:
d = sqrt(x^2 + (1.5x + 13)^2)
To find the minimum value of d, we can use calculus and find the derivative of d with respect to x, and set it equal to zero. Alternatively, we can use a graphing calculator or an online tool to plot the function d and find its minimum point. Either way, we get that the minimum value of d occurs when x is approximately -5.2 meters and y is approximately 5.2 meters. The corresponding value of d is approximately 14.7 meters.
Therefore, Mason needs to be able to throw the seashell at least 14.7 meters, or 1470 centimeters, to throw it into the ocean.
Roxanne likes to fish. She estimates that 30% of the fish she catches are trout, 20% are bass, and 10% are perch. She designs a simulation.Let 0, 1, and 2 represent trout.Let 3 and 4 represent bass,Let 5 represent perch.Let 6, 7, 8, and 9 represent other fish.The table shows the simulation results. what is the estimated probability that at least one of the next four roxanne catches will be bass?
Answers
We have 20 equally probable events in the table. So, each box has probability equal to 1/20.
With this in mind, we must find the numbers 3 and 4 in each box. Then, we can see that there are 12 boxes containing these numbers. Therefore, the probability to catch a bass is
[tex]\begin{gathered} P(\text{bass)}=12\cdot(\frac{1}{20}) \\ P(\text{bass)}=\frac{12}{20} \\ P(\text{bass)}=\frac{3}{5} \end{gathered}[/tex]By converting these result in percentage, we have
[tex]\frac{3}{5}\cdot100=60[/tex]that is, 60% could be bass fish.
Kim owes her friend $235 and plans to pay $5 per week. Select the equation of the function that shows
Answers
Answer:
The function is: y = 235 - 5x
x-intercept: 47
y-intercept: 235
The x-intercept means that it takes Kim 47 weeks to pay all of her debt.
The y-intercept means that Kim owes her friend $235.
Step-by-step explanation:
The amount that Kim owes her friend after x weeks is given by the following function:
y = b - ax
In which b is the initial amount she owes and a is how much she pays per week.
Kim owes her friend $235 and plans to pay $5 per week.
So b = 235, a = 5.
The function is: y = 235 - 5x
x-intercept:
Value of x when y = 0, that is, the amount of weeks it takes for her to pay all her debt.
So
235 - 5x = 0
5x = 235
x = 235/5
x = 47
x-intercept: 47
The x-intercept means that it takes Kim 47 weeks to pay all of her debt.
y-intercept:
Value of y when x = 0, that is, the total amount that Kim owes.
235 - 5*0 = 235
y-intercept: 235
The y-intercept means that Kim owes her friend $235.
Question 18(1 point)Passes through the points, (0,6), (-8,6)What is the slope?
Answers
Given the coordinates of two points that passes through a line:
[tex]\text{ (0,6) and (-8,6)}[/tex]Let's name the points:
x1, y1 = -8,6
x2, y2 = 0,6
To be able to get the slope of the line (m), we will be using this formula:
[tex]\text{ m = }\frac{y_2-y_1}{x_2-x_1}[/tex]Let's plug in the coordinates to the formula to get the slope (m).
[tex]\text{ m = }\frac{y_2-y_1}{x_2-x_1}[/tex][tex]undefined[/tex]Four times a number b is six times the sum of b and five
Answers
The number b is -15
Here, we want to write an equation and solve it
We go step by step
Four times a number b
= 4 * b = 4b
is six times the sum of b and 5
The sum of b and 5 is b+ 5
six times this is = 6(b + 5)
Now euating the two, we have;
4b = 6(b + 5)
4b = 6b + 30
collect like terms
6b - 4b = -30
2b = -30
b = -30/2
b = -15
Write the equation of a function that has the given characteristics.The graph of y = |x|, shifted 8 units upwardоа y = |x-81y = |x+81y = x| + 8y = |x| - 8
Answers
The given function is
[tex]y=|x|[/tex]The transformation is shifted 8 units upwards.
Remember, to move the function upwards we have to sum outside the absolute value bars.
Therefore, the transformed function would be
[tex]y=|x|+8[/tex]What is the image of (-6, -2) after a dilation by a scale factor of 4 centered at theorigin?
Answers
The image of (-6, -2) after dilation by a scale of 4 is (-24, -8)
Explanation:The image of (-6, -2) after dilation by a scale of 4 is
(-6*4, -2*4)
= (-24, -8)
And the surface area of each hemisphere below.7.8C
Answers
The surface area of the hemisphere is computed using the equation
[tex]SA=3\pi r^2[/tex]For the hemisphere with a radius of 14 yds, the surface area of the hemisphere is
[tex]SA=3\pi(14)^2=588\pi[/tex]For the hemisphere with a diameter of 12.2 yds, we need to find its radius first. The radius is just half of the diameter, hence, the radius of this hemisphere is 6.1 yds. Computing for its surface area, we have
[tex]SA=3\pi(6.1)^2=111.63\pi[/tex]Solve this system of equations byusing the elimination method.3x + 3y = 182x + y = 4( [?]. []).
Answers
Given the system of equations:
3x + 3y = 18
2x + y = 4
Let's solve the system of equations using the elimination method.
Multiply one equation by a number which makes one variable of each equation opposite.
Multiply equation 2 by -3:
3x + 3y = 18
-3(2x + y) = -3(4)
3x + 3y = 18
-6x - 3y = -12
Add both equations:
3x + 3y = 18
+ -6x - 3y = -12
_________________
-3x = 6
Divide both sides by -3:
[tex]\begin{gathered} \frac{-3x}{-3}=\frac{6}{-3} \\ \\ x=-2 \end{gathered}[/tex]Substitute -2 for x in either of the equations.
Take the second equation:
2x + y = 4
2(-2) + y = 4
-4 + y = 4
Add 4 to both sides:
-4 + 4 + y = 4 + 4
y = 8
Therefore, we have the solutions:
x = -2, y = 8
In point form, we have the solution:
(x, y) ==> (-2, 8)
ANSWER:
(-2, 8)
Let f(x)=V3x and g(x)=×6. What'sthe smallest number that is in the domain off° g?
Answers
Answer:
Explanation:
Given:
[tex]\begin{gathered} f(x)\text{ = }\sqrt{3x} \\ g(x)\text{ = x - 6} \end{gathered}[/tex]To find:
the domain of f o g
fog = (f o g)(x) = f(g(x))
First, we will substitute the expression in g(x) with x in f(x)
[tex][/tex]I will show you the pic
Answers
Part b
we have
2y=-x-8
Remember that
the equation in slope intercept form is
y=mx+b
so
Isolate the variable y
divide by 2 both sides
2y/2=-(x/2)-8/2
y=-(1/2)x-4Part c
we have
y-4=-3(x-3)
apply distributive property right side
y-4=-3x+9
Adds 4 both sides
y=-3x+9+4
y=-3x+13solve the following inequality for z. write your answer in the simplest form.10z-3(z - 8)<-6z+ 9 - 1
Answers
Let's start!
As a first step you have to simplify both sides of the inequality:
7z+24<-6z+8
Then, add 6z to both sides:
7z+24+6z<-6z+8+6z
13z+24<8
Now, we are going to subtract 24 from the both sides of the inequality:
13z+24-24<8-24
13z<-16
As a final step, you have to divide both sides by 13.
13z/13<-16/13
z<-16/13
Can you please help me
Answers
The formula to calculate the volume of a prism is given as
[tex]V=\text{Base Area }\times Height[/tex]The volume is given as 45 and the height is 9.
Hence, we can get the base area as
[tex]\begin{gathered} A=\frac{V}{h} \\ A=\frac{45}{9} \\ A=5 \end{gathered}[/tex]Therefore, the area of the base is 5 ft².
The correct option is OPTION B.
POSSIBLE Match the function rule to the table of values. f(x)=2 х f (x) = (3) f(x) = 32 2 f () = ( 1 ) 28
Answers
First, we must evaluate each function at the given values of x.
When x=-2, we have
[tex]\begin{gathered} f(x)=2^x\Rightarrow f(-2)=2^{-2}=\frac{1}{2^2}=\frac{1}{4}=0.25 \\ \end{gathered}[/tex][tex]f(x)=(\frac{1}{3})^x\Rightarrow f(-2)=(\frac{1}{3})^{-2}=\frac{1}{3^{-2}}=3^2=9[/tex][tex]f(x)=3^x\Rightarrow f(-2)=3^{-2}=\frac{1}{3^2}=\frac{1}{9}=0.11[/tex][tex]f(x)=(\frac{1}{2})^x\Rightarrow f(-2)=(\frac{1}{2})^{-2}=\frac{1}{2^{-2}}=2^2=4[/tex]Now, we must compare these result with the tables. Then the solutions are:
What is the volume of the cone? 1 Use the formula 1 = 6 cm 1 1 18 cm 1 1 1 1 A 16-em> or < 50.3 cm B) 32cm or 100.5 CMS 8 cm or
Answers
A) Graph the ellipse. Use graph paper or sketch neatly on regular paper. The ellipse must be hand drawn - no computer tools or graphing calculator. Give the center of the ellipse. Give the vertices of the ellipse. Give the endpoints of the minor axis. Give the foci.
Answers
The general equation of an ellipse is:
[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1.[/tex]Where:
• (h, k) are the coordinates of the centre,
,• a and b are the lengths of the legs.
The parts of the ellipse are:
In this case, we have the equation:
[tex]\frac{(x+1)^2}{5^2}+\frac{(y-4)^2}{4^2}=1.[/tex]So we have:
• (h, k) = (-1, 4),
,• a = 5,
,• b = 4.
A) The graph of the ellipse is:
B) The center of the ellipse is (h, k) = (-1, 4).
C) The vertices of the ellipse are:
• (h + a, k) = (-1 + 5, 4) = ,(4, 4),,
,• (h - a, k) = (-1 - 5, 4) =, (-6, 4),,
D) The endpoints of the minor axis are:
• (h, k + b) = (-1, 4 + 4 ) = ,(-1, 8),,
,• (h, k - b) = (-1, 4 - 4) = ,(-1, 0),.
E) To find the focuses, we compute c:
[tex]c=\sqrt[]{a^2-b^2}=\sqrt[]{5^2-4^2}=\sqrt[]{25-16}=\sqrt[]{9}=3.[/tex]The focuses of the ellipse are:
• (h + c, k) = (-1 + 3, 4) = ,(2, 4),,
,• (h - c, k) = (-1 - 3, 4) = ,(-4, 4),.
Answer
A)
B) (-1, 4)
C) (4, 4), (-6, 4)
D) (-1, 8), (-1, 0)
E) (2, 4), (-4, 4)
It walks for 37.5 meters at a speed of 3 meters per minute. For how many minutes does it walk?
Answers
Data
• distance: 37.5 meters
,• speed: 3 meters/minute
,• time: ? minutes
,•
From definition:
speed = distance/time
Replacing with data, and solving for time:
3 = 37.5/time
time = 37.5/3
time = 12.5 minutes
f(x) = 3x2 + 4x – 6g(x) = 6x3 – 522 – 2Find (f - g)(x).O A. (f - g)(x) = -6x3 + 8x2 + 4x – 4O B. (f - g)(x) = 623 – 2x² + 4x - 8O C. (f - g)(x) = 6x3 – 8x2 - 4x + 4O D. (f - g)(x) = -6x3 – 2x2 + 4x – 8SUBMIT
Answers
We are being asked to subtract one function from another function.
[tex](f-g)(x)=f(x)-g(x)[/tex][tex]\begin{gathered} (f-g)(x)=(3x^2+4x-6)-(6x^3-5x^2-2)=3x^2+4x-6-6x^3+5x^2+2 \\ (f-g)(x)=-6x^3+8x^2+4x-4 \end{gathered}[/tex]Answer: .
-2x^3 - 10y-7 evaluate if x = 4 and y = -9
Answers
We are given the following expression:
[tex]-2x^3-10y-7[/tex]We are asked to evaluate the expression in the following points:
[tex]\begin{gathered} x=4 \\ y=-9 \end{gathered}[/tex]To determine the value of the expression we will substitute the value in the expression like this;
[tex]-2(4)^3-10(-9)-7[/tex]Now, we solve the exponents:
[tex]-2(4)^3-10(-9)-7=-2(64)-10(-9)-7[/tex]Now, we solve the products:
[tex]-2(64)-10(-9)-7=-128+90-7[/tex]Solving the operations:
[tex]-128+90-7=-45[/tex]Therefore, the numerical value is -45
Giving a test to a group of students, the grades and gender are summarized belowIf one student is chosen at random,Find the probability that the student was male OR got a(n) "A". (Please enter a reduced fraction.)
Answers
To find the probability that the student was male or got an A, we have to find the probabilities that the student was male (event A), got an A (event B) and the intersection between these events (A∩B).
[tex]P(A)=\frac{48}{75}=\frac{16}{25}[/tex][tex]P(B)=\frac{26}{75}[/tex][tex]P(A\cap B)=\frac{12}{75}=\frac{4}{25}[/tex]Now, to find the asked probability, use the following formula:
[tex]\begin{gathered} P(A\cup B)=P(A)+P(B)-P(A\cap B) \\ P(A\cup B)=\frac{48}{75}+\frac{26}{75}-\frac{12}{75} \\ P(A\cup B)=\frac{62}{75} \end{gathered}[/tex]The answer is 62/75.