Solution:
Given the points below;
[tex]\left(-2,3\right)\text{ }and\text{ }(1,4)[/tex]To find the equation of a straight line, the formula is
[tex]\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex]Where
[tex]\begin{gathered} (x_1,y_1)=(-2,3) \\ (x_2,y_2)=(1,4) \end{gathered}[/tex]Substitute the values of the coordinates into the formula to find the equation of a straight line above
[tex]\begin{gathered} \frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \frac{y-3}{x-(-2)}=\frac{4-3}{1-(-2)} \\ \frac{y-3}{x+2}=\frac{1}{1+2} \\ \frac{y-3}{x+2}=\frac{1}{3} \\ Crossmultiply \\ 3(y-3)=1(x+2) \\ 3y-9=x+2 \\ x+2=3y-9 \\ x+2-(3y-9)=0 \\ x+2-3y+9=0 \\ x-3y+2+9=0 \\ x-3y+11=0 \end{gathered}[/tex]Hence, the general equation of the line is
[tex]x-3y+11=0[/tex]Write a equivalent unit rate to running 5/4 a mile in 9 minutes
To determine the unit rate to running 5/4 a mile in 9 minutes you have to determine the distance in miles run in one minute.
You can use corss multiplication to do the calculation:
9min____5/4miles
1min_____xmiles
[tex]\begin{gathered} \frac{\frac{5}{4}}{9}=\frac{x}{1} \\ x=\frac{5}{36} \end{gathered}[/tex]The unite rate is 5/36miles/minute, expressed as a decimal value is 0.14miles/min
Elizabeth is signing up for a gym membership with a one-time fee to join and then a monthly fee to remain a member. The total cost of the gym membership over t months is given by the equation C = 25t + 100. What is the y-intercept of the equation and what is its interpretation in the context of the problem?
The y-intercept of the equation is 100
For this problema the y-intercep is equal to the one-time fee
if m<10=77, m<7=47 and m<16=139, find the measure of the missing angle m<15=?
Step 1: Quoting the theorem of a straight line
The theorem of a straight line says Total angles on a straight line is equal to 180°.
Step 2:
m<16 and m<15 are angles on a straight line from the diagram given,
[tex]\begin{gathered} \text{where} \\ m<16=139^0 \\ m<15=\text{?} \\ \text{therefore,} \\ m<16+m<15=180^0 \\ 139^0+m<15=180^0 \\ \text{Collecting like terms} \\ m<15=180^0-139^0 \\ m<15=41^0 \end{gathered}[/tex]Hence the value of m<15= 41°.
did the teacher go wrong in making the square in the circle?! that’s what the question is asking pls help
Given two arcs, we follow the steps:
1) Label the intersection point of each pair of arcs as U and V:
2) Next, we need to construct the perpendicular bisector of the segment UV and label the intersection points to the circumference as P and Q:
3) Finally, we draw four line segments connecting the successive points on the circumference of the circle:
Looking at the steps given in the problem, the answer is:
The teacher makes a mistake in Step 2
Use the graph to find the indicated values:line with y intercept at (0,3) and x intercept at (2,0)f(0)=AnswerIf f(x)=0 then x=?Answerf^{-1}(0)=AnswerIf f^{-1}(x)=0 then x=?Answer
From the graph:
[tex]f(0)=3[/tex]If:
[tex]\begin{gathered} f(x)=0 \\ then \\ x=2 \end{gathered}[/tex]For the last ones, we can use this fact:
The domain of the inverse of a function is the same as the range of the original function. Therefore:
[tex]f^{-1}(0)=2[/tex]If:
[tex]\begin{gathered} f^{-1}(x)=0 \\ then \\ x=3 \end{gathered}[/tex]In triangle ABC, angle A is a right angle. What are possible measurements for B & C?
Given the triangle ABC.
Angle A is a right angle which equals 90 degree.
And sum of angles in a triangle equals 180 degree.
[tex]\begin{gathered} A+B+C=180^0 \\ 90^0+B+C=180^0 \\ B+C=180^0-90^0 \\ B+C=90^0 \end{gathered}[/tex]So, the possible measurement of B and C must be the ones who's sum is 90 degree.
[tex]\begin{gathered} 40\text{ \& 50 }\rightarrow40+50=90 \\ 30\text{ \& 60}\rightarrow30+60=90 \\ 45\text{ \& 45}\rightarrow45+45=90 \\ 80\text{ \& 30}\rightarrow80+30=110 \\ 60\text{ \& 40}\rightarrow60+40=100 \end{gathered}[/tex]Therefore, the ones whose sum equals 90 degree are the answers;
[tex]\begin{gathered} 40\text{ \& 50} \\ 30\text{ \& 60} \\ 45\text{ \& 45} \end{gathered}[/tex]Can you please throughly explain this question. I don't get it.
In graphing y > 2x - 7, a dashed line is used.
Answer: True
Explanation
Whenever we graph > or < , the boundary line is not inclusive of the range of solutions. Hence, we use a dashed line on the boundary.
On the other hand, whenever we have the inequality <= or >= , the
answer: true
explanation: my teacher just did it
part 1- Selected Response
Which of the following linear equations
have a negative y- intercept? Circle all that
apply.
A. y = 6x
Cy=
-3x +2
2
E. y=
• X
3
B.y=-5 + 2x
D.y=-x+8
F.y=-5
Answer: B, C, D and F
Step-by-step explanation: The y-intercept of a linear equation is the point at which the line crosses the y-axis. The y-axis is the vertical axis on a graph, and it is the axis where the x-coordinate is always 0. To find the y-intercept of a linear equation, we can set the x-coordinate to 0 and solve for the y-coordinate.
For example, consider the linear equation y = 6x. If we set the x-coordinate to 0, we get the equation 0 = 6 * 0, which simplifies to 0 = 0. Therefore, the y-intercept of this equation is (0, 0).
On the other hand, consider the linear equation y = -3x + 2. If we set the x-coordinate to 0, we get the equation 0 = -3 * 0 + 2, which simplifies to 0 = 2. Therefore, the y-intercept of this equation is (0, -2).
In general, a linear equation will have a negative y-intercept if the constant term in the equation is negative. In this case, the linear equations that have a negative y-intercept are B, C, D, and F. Therefore, the correct answer is B, C, D, and F.
(-3x² + 6x - 12) + (5x + 9) is equivalent to expression
A bag contains 31 coins, some dimes and some quarters. The total amount of money in the bag is $4.45. How many dimes and how many quarters are in the bag?_____dimes_____quarters
A bag contains 31 coins, some dimes and some quarters. The total amount of money in the bag is $4.45. How many dimes and how many quarters are in the bag?
_____dimes
_____quarters
we know that
1 quarter=$0.25
1 dime=$0.10
Let
x -----> the number of quarters
y ----> the number of dimes
we have that
x+y=31 ------> equation A
0.25x+0.10y=4.45 -----> equation B
Solve the system of equations
Isolate the variable x in equation A
x=31-y ------> equation C
Substitute equation C in equation B
so
0.25(31-y)+0.10y=4.45
solve for y
7.75-0.25y+0.10y=4.45
0.25y-0.10y=7.75-4.45
0.15y=3.30
y=22 dimes
Find the value of x
x=31-22
x=9 quarters
therefore
the answer is
22 dimes9 quartersplease help me solve. blank I have 9 and blank 2 I have 5. blank 2 is correct but not blank 1.
We have that
[tex]\begin{gathered} 3\cdot\sqrt[]{45}=3\cdot(\sqrt[]{9\cdot5}) \\ =\text{ 3(}\sqrt[]{9}\cdot\sqrt[]{5}\text{)} \\ =\text{ 3(3 }\cdot\sqrt[]{5}) \\ =9\cdot\sqrt[]{5} \end{gathered}[/tex]So the answer is
[tex]9\cdot\sqrt[]{5}[/tex]Find a best-fit linear model for the following data:xy−3196−2139−1820251−322−893−146y = −57xy = 57xy = 57x + 25y = −57x + 25
Explanation
We are given a set of x and y values in the table
To compute the best-fit model for the data, we will use the graphing calculator
From the graph above, we have the function to be
[tex]y=-57x+25[/tex]Thus, the answer is y= -57x +25
Prove #8Given: PR congruent to TR angle P is congruent to angle T
Reason: Given
[tex]\angle P\cong\angle T[/tex]Reason: Given
[tex]m\angle PRQ\cong m\angle SRT[/tex]Reason: Definition of Vertical angles
If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent by ASA (Angle-Side-Angle).
b Exit Ticket COS 28 = C 12 tan 28 = b с 12 28 b Download image X
Answer
b = 22.6 units
c = 25.6 units
Explanation
In a right angle triangle, the side opposite the right angle is the Hypotenuse, the side opposite the given angle that is non-right angle is the Opposite and the remaining side is the Adjacent.
For this question,
Hypotenuse = c
Opposite = 12
Adjacent = b
Trignometric ratios can then be used to find b and c.
CAH and TOA
Cos 28° = (Adj/Hyp)
Cos 28° = (b/c)
Tan 28° = (Opp/Adj)
Tan 28° = (12/b)
Cross multiply
b = 12/(Tan 28°)
b = 12/0.5317
b = 22.57
We can then solve for c
Cos 28° = (b/c)
Cos 28° = (22.57/c)
Cross multiply
c = (22.57/Cos 28°)
c = (22.57/0.8829)
c = 25.56 units
Hope this Helps!!!
Find the probability of getting a 1, 5, or 6 when you roll a standard six-sided die.Select the correct answer below:1/61/31/22/35/6
Step 1
Write out the expression for the probability of an event occurring
[tex]Pr(\text{event occurring) = }\frac{number\text{ of required outcomes}}{\text{Total number of outcomes}}[/tex]Where,
Total of required outcomes= 6
Step 2
Find the probability of getting a 1
[tex]Pr(1)=\text{ }\frac{1}{6}[/tex]Step 3
Find the probability of getting a 5
[tex]Pr(5)\text{ =}\frac{1}{6}[/tex]Step 4
Find the probability of getting a 6
[tex]Pr(6)=\frac{1}{6}[/tex]Step 4
Find the probability of getting a 1,5 or 6
[tex]Pr(1,5\text{ or 6)=Pr}(1)+Pr(5)+Pr(6)_{}[/tex][tex]\begin{gathered} Pr(1,5\text{ or 6) = }\frac{1}{6}+\frac{1}{6}+\frac{1}{6} \\ Pr(1,5\text{ or 6) = }\frac{1}{2} \end{gathered}[/tex]Hence, the probability of getting a 1, 5 or 6 when you roll a standard six-sided die = 1/2
At Fry's supermarket, each 12-1b bag of apples costs $4. Write an equation to represent the relationship between the number of pounds of apples, p, and cost, c I
if a 12 lb bag costs $4, then a 1 lb bag costs $4/12, which is equal to $1/3 dollars, so if we let p be the number of pounds that we are going to buy and c the amount that we must pay
[tex]c=\frac{1}{3}p[/tex]that is the relation between c and p
2 by 6 rectangle is inscribed in circle 5 by 6 rectangle is inscribed in circle 2 by 15 rectangle is inscribed in circle 1 by 12 rectangle is inscribed in circle what is the circumference?
21:51
it seems that your questions has multiple questions in it. Unfortunately, the tutoring app is meant to answer only one problem per session. So, I encourage you to start another session with your the remainder of the questionsk, so one of my colleague can help you out.
can you see what I'm writing?
An angle measures 83∘. Find a. its supplement and b. its complement.
Let
A = Angle (83°)
S = Supplement of A
C = Complement of A.
1) Finding the Supplement of A.
Supplementary angles are the angles whose sum is equal to 180°.
Then,
A + S = 180
Substituting A, we can find S.
83 + S = 180
S = 180 - 83
S = 97°
2) Finding the Complement of A.
Complementary angles are the angles whose sum is equal to 90°.
Then,
A + C = 90
83 + C = 90
C = 90 - 83
C = 7 °C.
Answer:
Supplement = 97 °C
Complement = 7 °C
help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me
Given:
Three numbers are 42, 90 and 144.
Required:
What is the highest common factor
Required:
We know the factors of 42
Answer: 42, 90 and 144.
Step-by-step explanation:
john ran at a pace of 3.5 miles per hr for a distance of 10.5 miles. how many minutes did it take them to run 10.5miles? use the distance formula: d= rt to where d is total distance, r is rate and t is time
d=rt
divide both-side of the equation by r
t =d/r
distance = 10.5 miles
we will go ahead and find the rate r
r = 3.5/60
r=0.05833
substituting into t= d/r
t = 10.5 / 0.05833
t=180 minutes
need answer with steps[tex](7 + 9i) + ( - 5i)[/tex]
Gy, this is the solution:
(7 + 9i) + ( - 5i)
Solving the parenthesis:
7 + 9i - 5i
7 + 4i
8 pounds of bananas cost $24. How much would 31 pounds cost
31 pounds cost $93
Explanation
you can easily solve this by using a rule of three.
Step 1
Let x represents the cost for 31 pounds,the proportion is
[tex]\frac{x}{31}[/tex]Now
[tex]\begin{gathered} 24\text{ usd}\rightarrow8\text{ Pounds} \\ \text{the proportion must be the same, then} \\ \frac{24}{8}=\frac{x}{31} \\ 3=\frac{x}{31} \\ \end{gathered}[/tex]Step 2
solve for x
[tex]\begin{gathered} 3=\frac{x}{31} \\ x=3\cdot31 \\ x=93 \end{gathered}[/tex]Hence, 31 pounds cost $93
I hope this helps you
I need help with math
a)
3000x - 2000 = 10 000
Add 2000 to both-side of the equation
3000x - 2000 + 2000 = 10 000 + 2000
3000x = 12000
Divide both-side of the equation by 3000
3000x/3000 = 12000/3000
x = 4
b) -2x/3
[tex]\frac{-2x}{3}-\frac{x}{7}=\text{ 17}[/tex]Multiply through the equation by 21
[tex]21(\frac{-2x}{3})-21(\frac{x}{7})=\text{ 17(21)}[/tex][tex]7(-2x)\text{ - 3x =357}[/tex]-14x - 3x = 357
-17x = 357
Divide both-side of the equation by -17
x = -21
c)
[tex]\frac{5}{2}x-\frac{1}{3}=\text{ 13}[/tex]Add 1/3 to both-side of the equation
[tex]\frac{5x}{2}=13\text{ +}\frac{1}{3}[/tex][tex]\frac{5x}{2}=\text{ }\frac{39+1}{3}[/tex][tex]\frac{5x}{2}=\frac{40}{3}[/tex]cross-multiply
15x = 80
Divide both-side of the equation by 15
x= 5.33
d)
[tex]\frac{3}{10}+\frac{2x}{5}=\frac{1}{2}[/tex]multiply through the equation by 10
[tex]10(\frac{3}{10})+10(\frac{2x}{5})=10(\frac{1}{2})[/tex]3 + 2(2x) = 5
3 + 4x = 5
subtract 3 from both-si
Scooby needs to ship some DVDs. He has 16 comedy movies, 12 scary movies and 8 action movies. He can pack only one type of DVD in each box and he must pack the same number of DVDs in each box. What is the greatest number of DVDs Scooby can pack in each box?A.2B.4C.6D.8
He has 16 comedy movies, 12 scary movies and 8 action movies.
He can pack only one type of DVD in each box and he must pack the same number of DVDs in each box
So, we need to find the greatest common factor between 16 , 12 and 8
16 = 2 * 2 * 2 * 2
12 = 2 * 2 * * 3
8 = 2 * 2 * 2
---------------------------------
2 * 2 = 4
So,
The greatest number of DVDs Scooby can pack in each box = 2 * 2 = 4
The answer is option B. 4
----------------------------------------------------------
More explanations :
So, he will pack 16 comedy movies at 4 packs, each pack has 4 DVDs
And he will pack 12 scary movies at 3 packs, each pack has 4 DVDs
And he will pack 8 action movies at 2 packs, each pack has 4 DVDs
So, the total number of packs = 4 + 3 + 2 = 9 packs
Last year, Jenny opened an investment account with $7400. At the end of the year, the amount in the account had decreased by6.5%. How much is this decrease in dollars? How much money was in her account at the end of last year?
if the decreasing amount is 6.5% the r in our decay function will be:
[tex]1-0.065=0.935[/tex]and in one yeat t=1 so the equation will be:
[tex]\begin{gathered} y=7400(0.936)^1 \\ y=6925.4 \end{gathered}[/tex]Nathan and Tony hiked in the woods yesterday and came home with poison ivy. Tony has 5 times as many spots as Nathan. How many spots does Nathan have, x? Which table represents this situation?
Here, we want to get the correct equation and select the correct table
From the question, we have it that Tony has 5 times what Nathan had
Hence, given that Nathan has x, Tony has 5 times this and we have it as;
[tex]5\times x\text{ = 5x}[/tex]What this mean is that the right column of the table will be 5 times what is on the left column
Hence, the correct table here is the table with the heading 5x
3(2x - 5) – 4x > 7x + 10.Please help
EXPLANATION.
To solve the inequality we must follow some steps:
1.1.the number 3 must multiply the values that are inside the parentheses
What is the volume of the triangular prism?3.2 cm length 6 cm height5.4 cm width A: 8.64 cmB: 17.28 cmC: 51.84 cmD: 103.68 cm
The volume of a prism can be calculated by multiplying the area of the base of the prism times its height:
[tex]V=A\cdot h[/tex]On the other hand, the area of the base of a triangle can be found by multiplying 1/2 times its base times its height (don't confuse the height of the triangle with the height of the prism):
[tex]A=\frac{1}{2}b\times h[/tex]Substitute the values for the base of the triangle and its height to find the area of the base. Then, substitute the result for the area and the value of the height of the prism to find the volume of the triangular prism.
If the base of the triangle has a length of 5.4cm, and its height is 3.2cm, then:
[tex]\begin{gathered} A=\frac{1}{2}\times5.4\operatorname{cm}\times3.2\operatorname{cm} \\ =8.64cm^2 \end{gathered}[/tex]If the height of the prism is 6cm, then its volume is:
[tex]\begin{gathered} V=8.64cm^2\times6\operatorname{cm} \\ =51.84cm^3 \end{gathered}[/tex]Therefore, the volume of the triangular prism, is:
[tex]51.84cm^3[/tex]Solve the equation.5/6=1/3+d
We have the following equation
[tex]\begin{gathered} \frac{5}{6}=\frac{1}{3}+d \\ \end{gathered}[/tex]We substract 1/3 each side:
[tex]\begin{gathered} -\frac{1}{3}+\frac{5}{6}=-\frac{1}{3}+\frac{1}{3}+d \\ -\frac{1}{3}+\frac{5}{6}=0+d \\ -\frac{1}{3}+\frac{5}{6}=d \\ \end{gathered}[/tex]We multiply each side of the fraction 1/3 by 2:
[tex]-\frac{1}{3}=-\frac{1\cdot2}{3\cdot2}=-\frac{2}{6}[/tex]Then
[tex]\begin{gathered} -\frac{1}{3}+\frac{5}{6}=d \\ -\frac{2}{6}+\frac{5}{6}=d \\ \frac{3}{6}=\frac{1}{2}=d \end{gathered}[/tex]Answer: d = 1/2A train is traveling at a constant speed of 105 mph how many feet does a travel in three seconds remember that 1 mile is 5280 feet
We are given that a train is traveling at the following constant speed:
[tex]v=\frac{105\text{ miles}}{hour}[/tex]We are asked to determine the distance after 3 seconds. To do that, let's remember that speed is the ratio between distance and time, that is:
[tex]v=\frac{d}{t}[/tex]Where:
[tex]\begin{gathered} d=\text{ distance} \\ t=\text{ time} \end{gathered}[/tex]Since we want to determine the distance we will multiply both sides of the equation by "t":
[tex]vt=d[/tex]Now, we substitute the values:
[tex]\frac{105\text{ miles}}{hour}\times(3s)=d[/tex]Since the velocity is given per unit of hour, we need to convert the 3 seconds into hours. We do that using the following conversion factor:
[tex]1\text{hour}=3600s[/tex]Now we multiply the time by the conversion factor:
[tex]3s\times\frac{1h}{3600s}=\frac{1}{1200}h[/tex]Now we substitute in the formula for the distance:
[tex]\frac{105\text{ miles}}{hour}\times(\frac{1}{1200}hour)=d[/tex]Solving the operations:
[tex]\frac{7}{80}miles=d[/tex]Now, we convert the miles into feet using the given conversion factor:
[tex]1\text{mile}=5280\text{feet}[/tex]Now, we multiply by the conversion factor:
[tex]d=\frac{7}{80}\text{miles}\times\frac{5280feet}{1mile}[/tex]Solving the operations:
[tex]d=462feet[/tex]Therefore, the distance is 462 feet.