What is the change in the internal energy of the system if 300 J of heat is removed to the system and the work done by the system is 100 J?

The wavelength of light is calculated to be 662.4 nm.

Monochromatic light is nothing but the single wavelength light where mono refers to single and chroma refers to colour. Visible light of a narrow band of wavelengths is classified as monochromatic lights.

Given that, width of fringe β = 0.552 * 10⁻³ m

Distance of screen, D = 1.75 m

Separation of slits, d = 2.10 mm = 2.1 * 10⁻³ m

The formula for fringe width is:

β = (λ* D)/d

Making λ as subject,

λ = β*d/D

λ = (0.552 * 10⁻³ * 2.1 * 10⁻³)/ 1.75 = 0.6624 * 10⁻⁶ = 662.4 nm

Thus, the wavelength of light is 662.4 nm.

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A uniform beam is suspended horizontally through two same vertical springs which can be connected among the ceiling and quit of the beam.

In physics, a force is a power that may trade the motion of an object. A pressure can purpose an item with mass to alternate its speed, i.e., to boost up. pressure can also be described intuitively as a push or a pull. A force has both importance and course, making it a vector quantity.

Pv = 2Mg

T = 0.5cos(0)Mg + 3/4 Mg cos0/sin0

Px = T

M = 48 kg, L = 8 m , 0 = 36°

T = 0.5 cos 36° × 48 * 9.8 + 3/4 × 48 × 9.8 cos 36°/sin36°

T = 875.84 N.

Force is defined as an external cause that adjustments or has a tendency to change the kingdom of the frame as soon as implemented. If the body is in motion, it comes to relaxation, and if at rest, then it's going to come to motion.

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The specific heat of the block is 3349J/kg C if a 500 g block of an unknown substance in an insulated container.

We know very well that if a system is in equilibrium state, it means that Heat loss = Heat gained

Also, Quantity of heat gained or released is given by = mcΔ∅

where m is defined as  mass of substance

c  is defined as the specific heat capacity

and Δ∅ is defined as the change in temperature

Therefore, applying the above formula by assuming heat lost by water will be heat gained by the block.

=>m₁×c₁×(∅₂-∅₁) = m₂×c₂×(∅₁-∅₃)

where m₁ is defined as the mass of block = 500g = 0.5kg

c₁ is defined as the specific heat capacity of unknown substance

∅₂ is defined as block initial temperature = 50°C

∅₁ is defined as equilibrium temperature of block and water after mix= 25°C

Also, we have m₂ as mass of water = 2kg

c₂ as specific heat capacity of water = 4186J/kg C

∅₃ as initial temperature of water = 20°C

Therefore, on putting the above quantities on above formula, we get

=>0.5×c₁×(50-25) = 2 x 4186×(25-20)

And we can find c₁ which is the unknown specific heat capacity

=>0.5×c₁×25=41860

=> c₁×12.5=41860

=>c₁=41860/12.5

=>c₁ =  3348.8J/kg C≅ 3349J/kg C

Hence, specific heat of the block is 3349J/kg C.

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During the new moon, the net gravitational force acting on the Earth in the Sun-Earth-Moon system is approximately 3.502 × 10²² Newtons.

Given data:

Mass of the Sun (M(S)) = 1.989 × 10³⁰ kg

Mass of the Earth (M(E)) = 5.972 × 10²⁴ kg

Mass of the Moon (M(M)) = 7.342 × 10²² kg

Distance between the Sun and the Earth (r(SE)) = 1.496 × 10¹¹ meters

Distance between the Moon and the Earth (r(ME)) = 3.844 × 10⁸ meters

The gravitational force between two objects is given by Newton's Law of Universal Gravitation:

F = (G × (m₁ × m₂)) ÷ r²

Gravitational force due to the Sun on the Earth:

F(SE) = G × (M(S) × M(E)) ÷ r(SE)²

Gravitational force due to the Moon on the Earth:

F(ME) = G × (M(M) × M(E)) ÷ r(ME)²

The net gravitational force on the Earth during the new moon is the vector sum of these forces:

F(net) = F(SE) - F(ME)

Gravitational force due to the Sun on the Earth

F(SE) = (6.67430 x 10⁻¹¹) × ((1.989 × 10³⁰) × (5.972 × 10²⁴)) ÷ (1.496 × 10¹¹)²

F(SE)= 3.52 × 10²² N

F(ME) = (6.67430 x 10⁻¹¹) × ((7.342 × 10²²) × (5.972 × 10²⁴)) ÷ (3.844 × 10⁸)²

F(ME) = 1.98 × 10²⁰ N

F(net) = F(SE) - F(ME)

F(net) = 3.52 × 10²² - 1.98 × 10²⁰ N

F(net) =  3.502 × 10²²

So, during the new moon, the net gravitational force acting on the Earth in the Sun-Earth-Moon system is approximately 3.502 × 10²² Newtons.

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The Table Below Gives The Masses Of The Earth, The Moon, And The Sun. Name Mass (Kg) Earth 5.97×10²⁴ Moon 7.35×10²² Sun 1.99×10³⁰ The Average Distance Between The Earth And The Moon Is 3.84×10⁸ m. The Average Distance Between The Earth And The Sun Is 1.50×10¹¹ m. Use

The table below gives the masses of the Earth, the Moon, and the Sun.

Name Mass (kg)

Earth 5.97×10²⁴

Moon 7.35×10²²

Sun          1.99×10³⁰

Find the net gravitational force Fnet acting on the Earth in the Sun-Earth-Moon system during the new moon (when the moon is located directly between the Earth and the Sun).

Express your answer in newtons to three significant figures.

At least one instance of a negative feedback loop can be found in the growth hormone axis So this claim is True.

Control of thyroid hormone secretion is an important example of a negative feedback loop. Thyroxine and triiodothyronine, also known as "T4 and T3," are thyroid hormones  produced and secreted by the thyroid gland that affect metabolism throughout the body.

The female menstrual cycle is controlled by a negative feedback loop involving the brain. The  hypothalamus of the brain contains glands that secrete gonadotropin-releasing hormone (GnRH). The pituitary gland in the brain produces follicle-stimulating hormone (FSH) under command from GnRH.

The use of negative feedback loops in processes is found in homeostatic systems such as: Thermoregulation (changes in body temperature induce mechanisms that restore normal temperature levels).

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Refreezing the liquid results in the formation of more densely packed upper layers (1/4 air by volume), and eventually, a solid mass of interconnecting ice.

Firn is typically understood to be snow that is least a year old and it has avoided turning into glacier ice during one melt season.The pressure from above causes fluffy snow to pack together and melt in some spots when it is sufficiently deep.

Snow is present.If there is snow on the ground for an extended period of time, the texture, size, and form of the individual grains will change, whether or not the temperature of the snow is below freezing. They may also gradually melt and refreeze before being compacted by consecutive snowfalls.

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The wavelength fringe is 0.431 m.

Diffraction grating with split space d, to find the fringe position ym, we must to find the angle from

d Sinα = mλ

A grating with N slits or lines per mm has slit spacing of

d = 1/N

d = (1/600mm)

d = 1.67×10⁻³mm

For 400nm wavelength:

α = Sin⁻¹(mλ/d)

α = Sin⁻¹(400*10⁻⁹/1.67*10⁻⁶)

α = 13.910°

And the position of first order lowest wavelength fringe on the screen is:

y₁ = L.tanα

y₁ = 2tan(13.910)

y₁ = 0.49445 m

For 700nm wavelength:

α = Sin⁻¹(mλ/d)

α = 24.83°

And the position of first order highest wavelength fringe on the screen is:

y₂ = L.tanα₂

y₂ = 0.925595 m

The difference between the first order lowest and highest wavelength fringe is

Δy = (0.925595 - 0.49445)m

Δy = 0.431m

Therefore, the wavelength fringe is 0.431 m.

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: White light (400–700 nm) is incident on a 600 line/mm diffraction grating. What is the wavelength of the first-order rainbow on a screen 2.0 m behind the grating?]

It is determined that the lens has 6.7 power.

We are aware that a refracting surface is what a lens is. In light of this, if we have a surface capable of refraction, it follows that such a surface must be a lens.

It is necessary to carefully read the question in order to determine the image distance and the object distance.

Image distance =  30 cm

Object distance =  32 cm

Using;

1/f = 1/v + 1/u

f = focal length

v = image distance

u object distance

1/f = 1/30 + 1/32

f = (0.033 + 0.032)^-1

f = 14.9 cm

Power of the lens = 100/f

= 100/14.9

= 6.7

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Hope it helps.

If you have any query, feel free to ask.

The approximate focal length of an objective lens which will give a total magnification of 200x is 0.8 cm.

The focal length of a lens is the distance from the principal focus of a lens to the center of curvature of the lens.

The focal length of the objective lens of the microscope is calculated as follows:

total magnification is 200x

tube length is 160 mm

eyepiece = 10x

magnification of the objective lens = 200 / 10

magnification = 20

the focal length in cm is 160 / 10 = 16

The focal length of the objective lens = assumed length / total magnification.

the focal length of the objective lens = 16 / 20

the focal length of the objective lens = 0.8 cm

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Thus inner diameter of hollow sperical iron shell is 57.3 cm.

How is density and diameter of sperical iron shell related?

We use the formula 4/3r3 to calculate the volume of a sphere. The volume of the hollow area must be subtracted from the total volume of the sphere in order to get the volume of a hollow sphere. Call the sphere's overall radius r1 and the radius of the hollowed-out area r2. As a result, we have 4/3π*r1^3 – 4/3π*r2^3.

When you know the radius, you may use the formula volume = (4/3) r3 to calculate the sphere's volume. The mass may then be calculated by multiplying the density and volume, as in mass = volume density, using the density formula density = mass/volume. The following formula might also be used: mass = (4/3) r3 density.

Estimate of V we interpret "almost completely submerged" to mean

V ≈ 4 πR^3 / 3

​here R =60cm.

Thus, equilibrium of forces (on the iron sphere) leads to

F = m (iron).g

ρ (water)gV  =ρ (iron) g( 4πR^3/ 3 - 4πr^3/ 3)

r is the inner radius (half the inner diameter).

Substituting in our estimate for V as well as the densities of water (1.0g/cm ^3) and iron(7.87g/cm ^3) we get the inner diameter:

[tex]2r = 2R(1 - \frac{1.0}{7.87})^{\frac{1}{3} }[/tex] =57.3cm.

Thus inner diameter is 57.3 cm.

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The acceleration due to gravity at this altitude is  1.26×10¹⁹m/s².

Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational field. It has the SI unit m/s². It is a vector quantity because it has both magnitude and direction. g is a unit used to measure gravitational acceleration. 9.8 m/s² is the standard value of g at sea level on the surface of the earth.

Newton's law of gravitation states that the acceleration can be calculated by

a = G M/r², where G is the Universal Gravitational constant 6.67 x 10⁻¹¹, M is the mass of the Earth 5.97 x 10²⁴ kg, and r is the distance from the center of the Earth 6.38 x 10⁶ m.

The attitude above the surface must be multiplied by the Earth's radius to determine r.

r = 25km + 6.38 x 10⁶ = 31.38x10⁶

a =  6.67 x 10⁻¹¹ × 5.97 x 10²⁴/ 31.38x10⁶

a = 3.98×10¹⁴/ 31.38x10⁶

a = 1.26×10¹⁹m/s².

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∴ p = 13.2 kgms⁻¹. As a result, the ball has a momentum of 13.2 kgms1.

Given conditions ⇒

Mass of the ball = 6 kg.

Velocity = 2.2 m/s.

Using the Formula,

Momentum = mass × velocity

∴ p = mv

⇒ p = 6 × 2.2

∴ p = 13.2 kgms⁻¹.

Hence, the momentum of the ball is 13.2 kgms⁻¹.

∴ p = 13.2 kgms⁻¹. As a result, the ball has a momentum of 13.2 kgms1.

Velocity (v) is a vector quantity that measures displacement (or change in position, Δs) over the change in time (Δt), represented by the equation v = Δs/Δt.

momentum = 5x2 = 10 kg m/s.

Any object's velocity is a measurement of how swiftly it moves. Therefore, it can be described as the change in an object's position divided by time.

Both a magnitude (a value) and a direction are associated with velocity. Meters per second (meter/second) is the unit used to measure velocity.

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Energy is required to remove a proton from ¹⁵N₇ with the masses of the atoms ¹⁵N₇, ¹⁴C₆ and H are 15.000109 u, 14.003242 u, and 1.007825 u, respectively is 10.2046375 MeV.

The energy required to remove a proton from ¹⁵N₇ is

The reaction to remove the proton is given as follows :

¹⁵N₇  ---->   ¹⁴C₆  +  H

The mass of ¹⁵N₇   =  15.000109

the mass of ¹⁴C₆ = 14.003242

The mass of H = 1.007825

The energy requires to remove a proton is given as:

E = ( 14.003242 + 1.007825 - 15.000109) u

E = 0.010958 × 9312.5 MeV

E = 10.2046375 MeV

A proton is a subatomic particle discovered within the nucleus of every atom. The particle has a fine electrical charge, identical and contrary to that of the electron. If isolated, a single proton might have a mass of the most effective 1.673. 10-27 kilogram, just barely less than the mass of a neutron.

A strong subatomic particle that has a positive rate equal in significance to a unit of electron fee and a relaxation mass of one.67262 × 10−27 kg, that's 1,836 times the mass of an electron. The proton become observed by Ernest Rutherford in the early 1900s. throughout this period, his research resulted in a nuclear response that led to the first 'splitting' of the atom, where he determined protons. He named his discovery “protons” based totally on the Greek word “protos” because of this first. Protons incorporate two up quarks and one down quark. Neutrons include one up quark and down quarks.

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Answer:

In an elastic collision, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision. This means that we can use the conservation of momentum to determine the velocity of the right ball after the collision.

The momentum of an object is equal to its mass multiplied by its velocity, so the initial momentum of the left ball is 0.25 kg * 2.0 m/s = 0.5 kgm/s. Since the initial velocity of the right ball is 0, the total initial momentum of the two balls is 0.5 kgm/s.

After the collision, the total momentum of the two balls must still be 0.5 kg*m/s. Since the mass of the two balls is the same, this means that the velocity of the right ball after the collision must be 2.0 m/s, which is the same as the initial velocity of the left ball.

Therefore, the velocity of the right ball after the elastic collision is 2.0 m/s.

The centre of mass's x-coordinates are 1/M(x)dm.

To determine the triangle's centre of mass, we place a strip with a width of dx at a distance of x from the vertex of the triangle. To determine the length of this strip dx, comparable triangles like

Mass of the strip = dm

vertical strips of width = dx

l = x . (a/b)

The mass of the strip is dm=(2M/ab)ldx

The distance of the center of mass from the vertexs of the triangle is

            xCM     = 1/M∫(x)dm

In a uniform gravity field, the "centre of mass" or "centre of gravity" is the distinctive place within an object or system that can be used to characterise how the system responds to external forces and torques. The centre of mass is thought to be the average of all the masses divided by their respective separations. The torques generated are analogous to balancing a seesaw around a pivot in one plane.

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Answer--  The formation ionic bond involve the transfer of valence electron.

What is ionic bond?

-- Ionic bond, also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound.

Dependence  

1. THe ease of formation  fo the positive and negative ions from the respective neutral atoms.

2. The arrangements of the positive and negative ions in the solids , that is  the lattice of the crystalline compounds.

-- The formation of a positive ion involves ionisation i.e. removal of electron from the neutral atom and that of the negative ion involves the addition of electron to the neutral atoms..

( Ionic bonds will be formed more easily between elements with comparatively low ionization enthalpies and elements with comparatively high negative value of electron gain enthalpy.)

What is electron gain enthalpy?

--The electron gain enthalpy is the enthalpy change, when a gas phase atom in its ground state gain an electron.

-- EGE process may be exothermic or endothermic.

What is ionisation energy?

Ionisation energy is the minimum amount of energy required to remove the most loosely bound electron, the valence electron, of an isolated neutral gaseous atom or molecule

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a) The kind of mirror it is concave.

b) to find the focal length we use the formula,

V  = uf/(u-f)

6.5 = -2.4f/(-2.4-f)

f = 3.8

c) magnification = v/u

=6.5/2.4

=2.7

d) image which is oriented to the object is  virtual and erect

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Answer:

Non-metals

a covalent bond is a bond where atoms share electrons

Nonmetals are most likely to form this type of bond

-384 jewels energy (in j) must the shock absorbers of a 1140 kg car dissipate in order to damp a bounce that initially has a velocity of 0.850 m/s at the equilibrium position

In a damped system, oscillatory motion is suppressed by frictional forces. The increase in the internal energy of the damping system makes up for the decrease in kinetic energy connected to oscillatory motion according to the law of conservation of energy.

We specify that the car's vertical equilibrium position is where the potential energy zero is located. The car's initial total mechanical energy is There has been a decrease of -384 jewels in energy.

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The radius of the new planet is equal to 2R. Therefore, option D is correct.

Newton’s gravitation law can be demonstrated as every particle with mass in the universe attracts every other particle having mass with a definite force. The magnitude of gravitational force can be represented as:

[tex]\displaystyle F =G\frac{M_1M_2}{r^2}[/tex]

The gravitational field of the earth can be represented as:

[tex]\displaystyle g =G\frac{M}{R_e^2}[/tex]

Given, the new planet has mass, M' = 4 M

[tex]\displaystyle g' =G\frac{M'}{R^2}[/tex]

g' = g

[tex]\displaystyle g' = g=G\frac{4M}{R^2}[/tex]

[tex]\displaystyle {R^2} = \frac{4GM}{g}[/tex]

[tex]\displaystyle {R^2}= 4R_e^2[/tex]

[tex]R = 2 R_e[/tex]

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Answer:

divide the number of times the event occurs by the length of time.

Explanation:

The final speed of a 2.0 kg body that is initially traveling at 40 m/s east and has a constant force of 10 N applied to the object for 5.0 s is 65 m/s.

This problem can be solved using the concept of momentum-impulse. Where the magnitude of the impulse is equal to the change in momentum.

The equation is:

F x Δt = m x v

We have,

The constant force = 10 N ⇒ F

Δt = 5.0 s ⇒ t

Mass of the body = 2.0 kg ⇒ m

And, the change in velocity is:

10 x 5 = 2.0 x v

v = 25 m/s

so, the final speed of the body is:

Initial velocity + change in velocity

= 40 m/s + 25 m/s

= 65 m/s

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She has poor vision. She needs a divergent lens of some kind, either converging or diverging. given that divergent lenses are often prescribed with a -1.33 D diopter strength, the lens strength is 1.33 D.

(A) The person is nearsighted if they have trouble seeing objects farther away than 75 cm.

(b) The type of corrective lens must be divergent in order to balance out the excessive converging power of the wearer's eye (which by the way carries by convention a negative focal length)

(c) The equation f = 1/d = 1/0.75 = 1.33D gives the focal length's absolute value (f).

As a result, it would typically be written with a negative sign indicating a contrasting lens.

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The centripetal force acting on the car is  36,000 N.

Centripetal force is the force that is directed towards the center of a circle and is necessary to keep an object in a curved path.

Step 1: Find the mass of the car.

Mass = 900 kg

Step 2: Find the velocity of the car.

Velocity = 10 m/s

Step 3: Find the radius of the circle.

Radius = 25.0 m

Step 4: Calculate the centripetal force.

Centripetal force = m*v2/r

Centripetal force = 900 kg * (10 m/s)2 / 25.0 m

Centripetal force = 36,000 N

Centripetal force is the force that is directed inward and is responsible for the circular motion of an object. It is directed towards the center of the circle and is perpendicular to the velocity of the object. It is usually caused by a combination of gravitational and/or electro-magnetic forces. It is the force that keeps an object in orbit around a larger object and keeps the moon in its orbit around the Earth.

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The speed at which a wave travels is unaffected by its wavelength. Waves C and D move forward at the same rate. Only changes in the characteristics of the medium a wave travels through can change its speed.

In a particular medium, the speed of propagation is constant; only the wavelength varies as the frequency does.

The characteristics of the medium have an impact on most waves' wave propagation speed in addition to frequency and wavelength variations. Tension, density, rigidity, and temperature are some of the variables that influence the speed of wave propagation.

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Answer:

17.8 m/s

Explanation:

This is a conservation of momentum problem.

Momentum = p = mv

x =  speed of the cannon ball

(200 kg)(0.8 m/s) = (9 kg)(x)

x = (160 kg·m/s) / (9 kg) = 17.8 m/s

The energy of the moving vehicle is 208.41 KJ.

The energy of a moving object or the energy possessed by an object in motion is called as the kinetic energy.

Where,

mass of the object/vehicle = m,

the speed at which the body is moving is v.

Mass of the vehicle = 1500 kg

Velocity of the vehicle = 60 km/hr

1 km/hr = 0.277 m/sec

60 Km/hr = 16.67 m/sec

Kinetic energy of the vehicle =  (1/2)*m*v²

K.E. =  (1/2)*1500*(16.67)²

K.E. = (1/2)*1500*277.88

K.E. = 208416.67 J

K.E. = 208.41 KJ

The energy in a moving vehicle of mass 1500 kg at 60km/hr is 208.41KJ.

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Answer:25 feet

Explanation:

The acceleration of a 1500 kg car when 3000 N of force is applied is

2 m/s².

According to Newton's second law of motion, acceleration of a body depends on two variables, the net force acting on the object and mass of the object. The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body.

If the force acting on an object increases, the acceleration of the body also increases. Likewise, if mass of an object is increased, the acceleration of the body decreases.

The equation of Newton's second law of motion is given as,

F = m*a

where, F is net force

m is mass

a is acceleration

Given that, m = 1500 kg

F = 3000 N

Making ' a ' as subject for the above equation, we have

a = F/ m = 3000/1500 = 2 m/s²

Thus, the acceleration of the car is 2 m/s².

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The effective force constant while Treating the cantilever as an ideal, massless spring is 8.19 N

The term "spring constant" refers to the proportional constant k. It gauges the stiffness of the spring. A spring exerts a force F = -kx in the direction of its equilibrium position when it is stretched or compressed to a length that differs by an amount x from its equilibrium length.

This question requires us to find the effective force constant.

The frequency f is given as

[tex]f=\frac{1}{2\pi } (\sqrt{\frac{k}{m}) }[/tex]

from the equation that we have above, we have

[tex]k = 4\pi ^2*f^2*m[/tex]

we have the values as

f =  17.1 MHz

m = 7.10×10−16 kg

put these values in the equation

[tex]k = 4 * 3.14^2 * (17.1*10^6)^2*(7.10*10^-^1^6)[/tex]

k = 8.19N/m

The effective force constant has been calculated as 8.19N/m

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Weighing a Bacterium Scientists are using tiny, nanoscale cantilevers 4 micrometers long and 500 nanometers wide-essentially miniature diving boards-as a sensitive way to measure mass. The cantilevers oscillate up and down with a frequency that depends on the mass placed near the tip, and a laser beam is used to measure the frequency. A single E. coli bacterium was measured to have a mass of 710 femtograms = 7.10×10−16 kg with this device, as the cantilever oscillated with a frequency of 17.1 MHz .

Treating the cantilever as an ideal, massless spring, find its effective force constant.