what is the band gap energy in kilojoules per mole if blue diamonds absorb orange light with a wavelength of 675 nm?

Answers

Answer 1

The band gap energy in kilojoules per mole is 1.73×105J.

The band gap is the distance between the valence band and the conduction band of an electron. Essentially, the bandgap represents the minimum energy required to excite an electron to a state in the conduction band where it can participate in conduction. Higher frequencies and lower wavelengths of light are absorbed.

In physics, especially for solids, the band gap is also called the energy gap. It is the range of energies that exist in solids where no other electronic state can exist. In the diagram of the electronic band structure of solids, the bandgap is commonly called the energy difference.

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Related Questions

brandon is on one side of a river that is 70 m70 m wide and wants to reach a point 300 m300 m downstream on the opposite side as quickly as possible by swimming diagonally across the river and then running the rest of the way. find the minimum amount of time if brandon can swim at 2 m/s2 m/s and run at 4 m/s.at 4 m/s. (use decimal notation. give your answer to two decimal places.) the minimum amount of time is s

Answers

The minimum time required to get there is 79.5 s.

What does downstream mean?

The direction of or nearer to the mouth of a stream.

On one side of a river is Brandon.

The river is 70 meters wide.

Brandon can swim at a speed of 2 m/s.

Brandon moves at a running pace of 6 m/s.

Let's assume that the included angle is 45 degrees.

Therefore, Brandon covered 99 meters in water.

Given that Brandon swims at a speed of 2 m/s

Time = distance / time

t = 99/2 = 49.5

The remaining distance to be covered while running is 250 - 70 = 180 m, hence the time required to do it is 180/6 = 30 s.

The time needed to get there is therefore 49.5 + 30 = 79.5 s.

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As a 15,000 kg jet lands on an aircraft carrier, its tail hook snags a cable to slow it down. The cable is attached to a spring with spring constant 60,000 N/m. If the spring stretches 30 m to stop the plane, what was the plane's landing speed?

Answers

The plane's landing speed was 250 m/s.

The force required to slow the plane down is equal to the spring constant multiplied by the amount it stretched. Thus, we can use the equation:

F = kx

where F is the force required, k is the spring constant, and x is the amount stretched.

In this case:

F = 60,000 N/m * 30 m = 1,800,000 N

We can use the equation for momentum to solve for the plane's speed:

p = mv

where p is the momentum, m is the mass, and v is the velocity.

In this case:

p = 15,000 kg * v

Rearranging for v, we get:

v = p/m = 1,800,000 N/15,000 kg = 250 m/s

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If you pull a 8 kg box across the floor with a net force of
50 N, how fast will it accelerate?
A. 5.5 m/s²
B. 9.8 m/s²
C. 3.2 m/s²
D. 6.25 m/s²

Answers

The acceleration of an 8kg box at net force of 50N would be d.) 6.25m/s²

What is the gravity-induced acceleration?

The acceleration due to gravity value of 9.8 m/s2 means that the velocity of a body falling freely changes by 9.8 m/s per second.

What does Newton's law define as acceleration?

The acceleration of an object is equal to the net force exerted on it divided by its mass, or a = F m, in accordance with Newton's second rule of motion. When the mass of an item and the net force acting on it are known, the acceleration of that object can be determined using this equation for acceleration.

What qualifies as acceleration?

Throughout time, the velocity is shifting. In actuality, the velocity is changing by a fixed rate of 10 m/s every second.

Let the direction of the 50 N be positive.

Fnet = (50 -10) N = +40 N

Fnet = m•a

a = Fnet/m = 40/75 m/s²

a = +0.53333 m/s² but round to 1 or 2 sig figs: +0.53 m/s² in the direction of the 50 N.

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a capacitor in a series rc circuit is charged to 60% of its maximum value in 1.0 s. find the time constant of the circuit.

Answers

The time constant of the circuit is 0.9163τ

The charge of RC circuit is

q = 0.6q0

The expression for a charging capacitor is given by,

q = q0 ( 1-  e⁻⁽⁻t/T⁾)

Here, t

is the time, q0 is the equilibrium charge of circuit and τ is the time constant.

Substitute all the known values in the above formula.

t≈0.9163τ

The term time constant in an RC circuit can be evaluated with the help of the equilibrium charge of the circuit, charge at a specific time and time. The relation for a charging capacitor is an exponential expression.

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What is the image of a dilation?

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Image of dilation is a type of transformation that changes the size of a shape or geometric figure, but keeps the relative proportions and shape the same.

Morphology is known as a broad range of image processing operations that process images based on their shape. It is also known as a tool used to extract image components that help represent and explain the shape of a region.The basic morphological operations are: H. Used to extend element A with structuring element B.Dilation adds pixels to the bounds of the object.Output pixel value is the maximum value of all pixels in the neighborhood. A pixel is set to 1 if any adjacent pixel has a value of 1. The grayscale structuring elements are also functions of the same form, so-called structure functions.

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describe how the universe changed in going from the early universe to the universe some time later.

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They moved away from each other in going from the early universe to the universe some time later.

As time goes on, the Universe not only forms elements, atoms, and clumps and clusters together that lead to stars and galaxies, but expands and cools the entire time. The Universe continues to expand even today, growing at a rate of 6.5 light-years in all directions per year as time goes on.

Starting from extremely high density and temperature, space expanded, the universe cooled, and the simplest elements formed. Gravity gradually drew matter together to form the first stars and the first galaxies.

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A uniform beam PQ of length 40m and weight 10N is supported at P and Q. It carries a load of 4N at a point 10m from P. What is the reaction at Q. ​

Answers

The reaction force at Q is 4N.

A support reaction is a force on a support or a resulting restraining end moment, which results due to a prevented possibility to move. In the case of structural systems, support reactions are in equilibrium with the external forces acting on the structure.

The uniformly distributed load can be replaced by a concentrated load acting at the centre of gravity of the UDL. The total load on beam is the UDL multiplied by the length of the beam,

So  support reaction is,

R = Load × Length

In this question,

The equation of equilibrium of moments is

[tex]R_{Q[/tex] × 40 - Mg×20-  4N× 10 = 0

So, [tex]R_{Q[/tex] = 10 N× 20 + 4N× 10 ÷ 40 = 4 N

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Why is sleep important for safety?

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Sleep is very crucial for safety. Proper sleep helps persons to behave well and choose correct decision during chaos .Exa-Crossing the road.

Sleep isn't just significant for generally speaking energy level at work, however fundamental for our general medical issue. Unfortunate rest propensities can prompt circulatory strain issues, which thus can prompt various medical problems. In this issue we'll be taking a gander at rest, why it makes a difference for work environment wellbeing, and how to urge all your staff to get a decent night's rest.

A laborer's body needs to dial back and rest to keep the heart solid. A very much refreshed body is connected to a sound, serious areas of strength for heart framework and diminished degrees of stress. Rest is significant for wellbeing and the connection among rest and security is obviously significant too.

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Which method of measuring distances would you use if you wanted to measure the distance to stars in a nearby galaxy?

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Since space is so vast, many astronomers choose to use a unit of measurement known as a parsec instead of measuring distances in miles or kilometers. the nearest star, Alpha Centauri, in your mind

what is A parsec is either a time or a distance measurement.

Why then would Solo use a parsec, which measures distance rather than time, to describe how fast his ship could move? Here, two distinct narratives are in play.

Why then does Han Solo claim that it is 12 parsecs?

The Kessel RuEmpire then was among the busiest smuggling routes in the Galactic Empirethe Galactic Empire, the Kessel Run was one of the busiest smuggling routes. The Kessel Run, according to Han Solo, was completed by his Millennium Falcon in fewer than twelve parsecs. Unlike time, a parsec measures distance. When he said this, Solo wasn't specifically referring to his ship's speed speed of his ship.

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if a seagull sitting in water bobs up and down once every 2 seconds and the distance between two crests of the water wave is 3 m, what is the velocity of the wave?

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The velocity of the wave is 1.5 m/s.

Since, the crest occurs every 2 seconds,

Time period = t = 2 s

Distance between two crests = Wavelength of the wave = λ = 3 m

Frequency of the wave = f

The velocity of the wave is = v =

The velocity of a wave is equal to the product of its wavelength and frequency (number of vibrations per second) and is independent of its intensity.

= v = λ X f

and, f = 1/t

= v = λ / t

= v = 3/2

= v = 1.5 m/s

Thus, the velocity of the wave is 1.5 m/s.

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(a) calculate the range of wavelengths (in m) for fm given its frequency range is 88.0 to 108 mhz. smaller value m larger value m

Answers

The wavelengths fall around 2.78 meters and 3.41 meters.

By dividing the light speed by the FM lowest frequency, that would be 88 megahertz, we can calculate the maximum length, and comes to 3.41 meters. Additionally, the minimal wavelength would be 3 times 10 to 8 meters divide by 108 megahertz. In light of this, the wavelength for FM will fall between 2.78 meters and 3.41 meters.

The operating frequency of the Amplitude Modulated (AM radio) carrier frequencies is 535-1605 kHz. 10 kHz increments are used to assign frequency band, which range from 540 to 1600 kHz.

The VHF portion of something like the radio spectrum encompasses the FM broadcast frequency, which is used globally. To only a few instances, 87.5 to 108.0 MHz, or perhaps some component thereabouts, is typically utilised: The earlier 65.8-74 MHz range is still being used in many former Eastern Bloc nations as well as in the former Soviet states.

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1. how would the horizontal range change if the initial velocity was doubled? explain (use the equation from the theory section, if needed).

Answers

The range will become the 4 times of intial velocity

if the initial velocity is doubled then the horizontal range will be 4 times.

R = u² sin²θ / g

R directly proportional U²

if initial velocity becomes 2 times, then horizontal range becomes 4 times.

This will be when angel of projection is same, the horizontal velocity is directly proportional to initial velocity.

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a constant force is exerted for a short time interval on a cart that is initially at rest on an air track. this force gives the cart a certain final speed. suppose we repeat the experiment but, instead of starting from rest, the cart is already moving with constant speed in the direction of the force at the moment we begin to apply the force. after we exert the same constant force for the same short time interval, the increase in the cart’s speed

Answers

The cart's increased speed is the same as when it first took off.

Rate is the speed from which an object travels along a path over time, whereas velocity is the speed and orientation of an item's motion.

At first, the cart is at rest.

So, u = 0 m/s.

A brief period of time is spent with a constant force applied.

The final speed that the force gives the cart is what we'll call v.

Newton's first equation of motion yields the following results:

v = u + at

Where;

The ultimate speed =v.

The starting speed =u.

Acceleration = a.

Time = t

u = 0 m/s, therefore we now have;

v = 0 + at

v = at

Let's now use Newton's second rule of motion to construct a formula to introduce force;

F = ma

Where;

Force = f.

Mass = m.

Acceleration = a.

So,

= a = F/m.

Substituting in v = at,

= v = (F/m)t

The final speed, v, is evidently exactly related to the force. So, if the force is constant, the end speed will also stay constant.

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The complete question is -

A constant force is exerted for a short time interval on a cart that is initially at rest on an air track. This force gives the cart a certain final speed. Suppose we repeat the experiment but, instead of starting from rest, the cart is already moving with constant speed in the direction of the force at the moment we begin to apply the force.

After we exert the same constant force for the same short time interval, the increase in the cart's speed:

A. is equal to two times its initial speed.

B. is equal to the square of its initial speed.

C. is equal to four times its initial speed.

D. is the same as when it started from rest.

E. cannot be determined from the information provided.

an electron travels through space and has a velocity uncertainty of 131 m/s. what is the minimum uncertainty in the electron's position?

Answers

The minimum uncertainty in the electron's position is equal to the velocity uncertainty divided by the speed of light, which is 131 m/s / 299,792,458 m/s ≈ 4.37 × 10^−9 m.

The minimum uncertainty in the electron's position is determined by the Heisenberg Uncertainty Principle, which states that the product of the uncertainties in position and momentum have to be greater than or equal to a constant, which is equal to Planck's constant (h) divided by 4π.

Therefore, the minimum uncertainty in the electron's position (Δx) can be calculated using the equation below:

Δx * Δp ≥ h/4π

Where Δp is the uncertainty in the electron's momentum, which is equal to the electron's velocity uncertainty (Δv) multiplied by the electron's mass (m):

Δp = Δv * m

Inserting this into the equation for the minimum uncertainty in position, we get:

Δx * Δv*m ≥ h/4π

Simplifying and rearranging this equation, we get:

Δx ≥ h/4π * (1/m*Δv)

For a single electron with a mass of 9.11 x 10-31 kg and velocity uncertainty of 131 m/s, the minimum uncertainty in its position is 1.11 x 10.

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An ice skater is spinning with her arms out and is not being acted upon by an external torque.
When she pulls her arms in close to her body what happens to her angular velocity?

Answers

She boosts her angular velocity when she pulls her arms in toward her body since doing so causes her rate of spin to increase dramatically, which lowers her moment of inertia. She pulls her arms in with effort, increasing rotational kinetic energy.

What does the conservation of angular momentum entail?

The angular momentum of the system of particles is conserved if there is no net external torque at a given position in a fixed inertial reference frame:

You can see that the whole angular momentum is conserved. Any one of the individual angular momenta can change as long as the aggregate remains unchanged. This equation represents the conservation of linear momentum when there is no outside force acting on the system.

As a result, since the conservation of angular momentum can be demonstrated by an ice skater doing a spin. Her net torque is virtually zero because there isn't much friction between her skates and the ice. Furthermore, the friction is applied rather close to the pivot.

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Which rock was under the most pressure and the highest temperature?

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Metamorphic rock was under the most pressure and the highest temperature.

What type of rock has high temperature and pressure?

Rocks found under extremely high pressures and average to high temperatures are called eclogite and are often rich in cardinal and pyroxene. 8. The hornfels contains a series of rocks that result from contact metamorphism under low pressures and a wide range of temperatures.

Metamorphic rocks form when live rocks are exposed to heat and pressure deep within the Earth's surface. The new rock is completely different from the other.

So we can conclude that A rock with this feeling is called gneiss. Since gneisses form at the highest temperatures and pressures, some partial melting may occur.

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The satellite space explorer flies 180600 miles in 21 hours. Find the rate of change.

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The rate of change, or speed, of the satellite space explorer, is approximately 8600 miles per hour.

Given:

Distance = 180600 miles

Time = 21 hours

The rate of change represents the speed or velocity at which the satellite is traveling.

Rate of change (Speed) = Distance ÷ Time

Rate of change (Speed) = 180600 ÷ 21

Rate of change (Speed) = 8600 miles /hour

So, the rate of change, or speed, of the satellite space explorer is approximately 8600 miles per hour.

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a car approaches a stationary police car at 30 m/s. the frequency of the siren (relative to the police car) is 500 hz. what is the frequency (in hz) heard by an observer in the moving car as he approaches the police car? (assume the velocity of sound in air is 343 m/s.) a. 544 b. 226 c. 448 d. 550 e. 483

Answers

The frequency (in Hz) heard by an observer in the moving car as he approaches the stationary police car (assuming the velocity of sound in air is 343 m/s) is 544 Hz. So, the answer is A.

What is velocity?

It is the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

Assuming the velocity of sound in air is 343 m/s, what is the frequency (in Hz) heard by an observer in the moving car as he approaches the police car?

Velocity of car Vc = 30 m/s

Velocity of sound V = 343 m/s

frequency of siren f = 500 Hz

So, the frequency that heard by the observer when the police car approaches is :

f1 = f * (V + Vc) / V

where

f = frequency of siren (relative to the police car)
V = velocity of the car

Vc = velocity of sound in air

f1 = frequency heard by the observer

= 500 * (343 + 30) / 343

= 543.73Hz

= 544 Hz (rounded)

Therefore, the frequency that heard by the observer when the police car approaches him is 544Hz, and the answer is A.

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9. An object with mass M is subjected to a force of 100 newtons and accelerates at rate A. How much force would be needed to make mass M accelerate at rate 4A?

Answers

25 Newtons force would be needed to make mass M accelerate at rate 4A

How much force would be needed?

An object with mass M is subjected to a force of 100 newtons and accelerates at rate A.

The acceleration of an object is equal to the net force exerted on it divided by its mass, or a = F m, in accordance with Newton's second rule of motion. When the mass of an item and the net force acting on it are known, the acceleration of that object can be determined using this equation for acceleration.The equation F = m x a describes the force (F) needed to move an object with mass (m) and acceleration (a). Therefore, force is equal to mass times acceleration.

25 Newtons force would be needed to make mass M accelerate at rate 4A

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how many turns of wire would be required to make a 200 mh inductance out of a 40.0 cm -long air-filled coil with a diameter of 4.2 cm ?

Answers

15937.5 turns of wire would be required to make a 200 mh inductance out of a 40.0 cm-long air-filled coil with a diameter of 4.2 cm.

The number of turns of wire required to make a 200 mH inductance out of a 40.0 cm-long air-filled coil with a diameter of 4.2 cm can be calculated using the formula:

N = (L x 10^6) / (2π x (d/2)^2)

where N is the number of turns of wire, L is the desired inductance in microhenries (μH), d is the diameter of the coil in centimeters (cm), and π is the mathematical constant (3.14).

Plugging in the given values, we get:

N = (200 x 10^6) / (2 x 3.14 x (4.2/2)^2)

N = (200 x 10^6) / (2 x 3.14 x (2.1)^2)

N = (200 x 10^6) / (12.56)

N = 15937.5 turns of wire

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For two forces to be balanced, what must be true?

Answers

Answer:

equal magnitude and opposite direction

Radio waves travel at a speed of 1.7x10^8 m/s through ice. A radio wave pulse sent into antarctic ice reflects off earth at the bottom and returns to the surface in 32.9x10^-6 s. how deep is the ice?

Answers

The depth of the ice was found to be 26.55 x 10 ^ 12 m.

What exactly are radio waves?

A transmitter emits nonparticulate radiation, which is sensed by a receiver. An antenna allows a transmitter to transfer energy into house and a receiver to pick up energy from space. Transmitters and receivers are typically designed to operate on a limited range of frequencies.

The ice depth is then 26.55 x 1012 m.

Let's call the radio wave's speed 'v.'

Let the frequency of the radio wave be represented as 'f'.

Let's call the radio wave's distance's.'

Let's call the radio wave's time period 't.'

Distance formula:

v=s/t

v=s/1/t

The inverse of time period is frequency. As a result, 1/t in the preceding formula can be substituted by f.

v=sxf

filling in the blanks in the above equation

t = 32.9 x 10 ^ -6

v = 1.7 x 10 ^ 8 x m / s

Then, f = 1 / t

Then, f = 1 / t 

f= 1/3.2 x 10 - 6 s - So, 

s = 1.7 x 10 x 1/3.2 x 10- 

= 1.7/3.2 x 10 (8 + 6) 

= 0.531 x 10 14 

= 53.1

The depth of the ice would therefore be s/2 since the wave covers the distance twice in the specified time period.

Ice depth = 53.1 x 1012/2

Ice depth = 26.55 x10 12 x m

26.55 x 10 ^ 12 x m

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Additionally, the radio wave is moving at the speed of light, or 3 10 8 m/s. As a result, radio waves travel for 12.58 minutes.

What exactly are radio waves?

A transmitter emits nonparticulate radiation, which is sensed by a receiver. An antenna allows a transmitter to transfer energy into house and a receiver to pick up energy from space. Transmitters and receivers are typically designed to operate on a limited range of frequencies.

The ice depth is then 26.55 x 1012 m.

Let's call the radio wave's speed 'v.'

Let the frequency of the radio wave be represented as 'f'.

Let's call the radio wave's distance's.'

Let's call the radio wave's time period 't.'

Distance formula:

v=s/t

v=s/1/t

The inverse of time period is frequency. As a result, 1/t in the preceding formula can be substituted by f.

v=sxf

filling in the blanks in the above equation

t = 32.9 x 10 ^ -6

v = 1.7 x 10 ^ 8 x m / s

Then, f = 1 / t

Then, f = 1 / t

f= 1/3.2 x 10 - 6 s - So,

s = 1.7 x 10 x 1/3.2 x 10-

= 1.7/3.2 x 10 (8 + 6)

= 0.531 x 10 14

= 53.1

The depth of the ice would therefore be s/2 since the wave covers the distance twice in the specified time period.

Ice depth = 53.1 x 1012/2

Ice depth = 26.55 x10 12 x m

26.55 x 10 ^ 12 x m

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a 5 m chain with density 2 kg/m hangs off the roof of a building. how much work is required to pull the chain to the roof?

Answers

A 5 m chain with a density of 2 kg/m hangs off the roof of a building, then work done to pull the chain to the roof is 98 N m

The amount of force required to move an item a certain distance is referred to as the work done. Essentially, it is a measurement of the amount of energy that is transmitted to or from an item so that it may be moved.

W = force * distance

The force is the weight times gravity since it is hanging down

W = 2 kg* 9.8 m/s^2 * 5m

   98 kg m^2/s^2

A newton is  kg m/ s^2

W = 98 N m

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The actual usage for grain depends on which llamas show up at feeding time, thus there is an average need for 50 pounds of grain each day with a standard deviation of five pounds. In addition, there is some variability in how long it takes the feed store to whip up a batch of llama feed. The standard deviation of the feed prep is one day. The farm is willing to tolerate a 2% chance of running out of feed before they can get some more hauled in. Which adjustment to their system would have the greatest impact on the reorder point?.

Answers

The adjustment that would have the greatest impact on the reorder point would be reducing the standard deviation of the feed prep time.

By reducing the standard deviation of the feed prep time, the farm would be able to order the feed earlier, thus reducing the chance of running out of feed. This would have the effect of lowering the reorder point, as there would be less time between when the feed is ordered and when it arrives.

Additionally, reducing the standard deviation of the feed prep time would be more effective than trying to reduce the standard deviation of the grain usage, as the former is more controllable and can be adjusted more precisely.

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on the moon, the acceleration due to gravity is -1.6 meters per second per second. a stone is dropped from a cliff on the moon and hits the surface of the moon 28 seconds later. how far did it fall? (round your answer to one decimal place.)

Answers

a) - 627.7 m

b) - 44.8 m/s

a) we use the formula,

d = gt²/2

when we substitute the values,

d = -1.6 X 28²/2

= -1.6 X 784/2

= - 627.2m

distance travelled by the stone was - 627.2m

b) calculate the impact,

v = gt

substitute,

v = (-1.6) X 28

v = - 44.8 m/s

The negative sign here indicates that the object is going down.

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A 925 kg car rounds an unbanked curve at a speed of 25 m/s. If the radius of the curve is 72 m, what is the minimum coefficient of friction between the car and the road required so that the car does not skid?.

Answers

The minimum coefficient of friction required is 0.885  for a 925kg car rounds an unbanked curve at a speed of 25m/sec.

We know that if a body wants to travel from one place to another place, we need friction to move along the surface.

Now,we know that centripetal force is required to move along a curve.Also,due to friction same amount of force acts on the car to move along the surface.

It means centripetal force=mv²/r where v is the velocity of the body and r is the radius of the body is equal to force applied by the friction which is equal to =μmg  

So,mv²/r=μmg  

=>v²/r =μg

=>μ= v²/rg

On putting the values of speed, radius and acceleration due to gravity

=>μ=(25)²/(72×9.8)

=>μ=625/705.6

=>μ=0.885

Hence, required value of coefficient of friction is 0.885.

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the masses of the two moons are determined to be 2m for moon a and m for moon b. it is observed that the distance between moon b and the planet is two times that of the distance between moon a and the planet. how does force exerted from the planet on moon a compare to the force exe

Answers

Eight times more gravitational pull is exerted by the planet on Moon A than Moon B due to gravitational attraction.

All material objects in the universe are subject to gravity, commonly known as gravitation. The force of gravity tends to pull any two objects or particles with nonzero mass toward one another. From subatomic particles to galaxy clusters, gravity affects all sizes of objects. Additionally, it works over all distances, no matter how tiny or large.

One of the most researched physics phenomena is gravitation. With his renowned Law of Universal Gravitation, Isaac Newton described its behaviour. According to Newton's theory, the gravitational force between any two spherical objects of uniform density is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

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pls hurrryyyy!!!!!!!! please

Answers

Answer:

The penguins are gliding foward without stopping because there is no external force changing their state.

Explanation:

Newtons first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

What event made it possible for photons to begin to travel freely through the universe when the universe was about 380,000 years old?
A. The universe had expanded and cooled enough for electrons to combine with nuclei to form neutral atoms.
B. Atoms started to combine to make the first molecules.
C. Magnetic fields had weakened to the point that they no longer interfered with light.
D. Atomic nuclei were finally able to escape the plasma of the early universe.
E. Fusion of hydrogen to make helium ceased.

Answers

Answer: C

Explained:

Photons are electromagnetic waves (light) and can move according to the level of magnetism. Also are magnetic fields of the earth are known to protect us from uv rays which are harmful to the body

Explain the image below in terms of Newton’s Laws.

Answers

The image given, is explained in terms of Newton's 1st law of motion.

What is Newton's 1st law of motion?

Based on Newton's First Law of Motion (Inertia).  An object at rest remains at rest, and an object in motion continues in motion at a steady speed and in a straight path until operated on by an unbalanced force.

Newton's first rule of motion states that if a pan of water were being moved along a track, the water would tend to keep moving ahead. However, the water will appear to splash to the right while it goes to the left. Space is nearly a perfect vacuum, devoid of both gravity and matter. Think about a satellite travelling 17,500 mph around the Earth. If a rock were to be launched from the satellite, it would orbit the earth adjacent to the satellite at a speed of 17,500 mph.

Here, in the given image, it is shown that the sofa is remain in the place unless a person forcefully move it from one place to another.

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