What is the answer?
A)44
B)42
C)45
D)48

Answer:

111

Step-by-step explanation:

Use PEMDAS to solve this equation, so first we have to do parenthesis first. Simplify 4+16 to get 20. Simplify 2+3 to get 5. Therefore, the equation will now look like 180/(20)-8x3+7x(5). Because we can do either division or multiplication first, we have to solve the equation started from the left. Therefore, we do 180/20 which is 90. Then the equation will be 90-8x3+7x5. Multiply -8 and 3 together to get -24. Therefore, the equation will be 90-24+7x5. Because we always do multiplication/division before addition/subtraction. We have to do 7x5 which is equal to 35. Therefore, the equation will look like 90-24+35. Because there is only subtraction and addition now, we should start from the left hand side which is 90-24. Simplify this to get 76. Then the equation will be 76+35. Simplify this to get 111.

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Answer:

m = 4 + (2n)/(3)

Step-by-step explanation:

Move all terms that contain m to the right side and solve it.

24 divided by 12 equals 2,083

The division of 25 by 12  gives the quotient 2 and remainder is 1.

One of the four fundamental mathematical operations, along with addition, subtraction, and multiplication, is division. Division is the process of dividing a larger group into smaller groups so that each group contains an equal number of things. It is a mathematical operation used for equal distribution and equal grouping.

Given:

We have to divide 25 by 12.

The division is as follow:

                            12| 25 | 2

                                  24

                              ______

                                   1

Thus the Quotient is 2 and remainder is 1.

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Answer:

$0.30 per ounce

Step-by-step explanation:

16 ounces per pound

16 x 2 = 32 ounces per 2 pounds

9.60/32 = $0.30 per ounce

Answer:

[tex]3log2[/tex]

Step-by-step explanation:

Given

[tex]\frac{1}{3} log( \frac{125}{8} ) - 2 log( \frac{2}{5} ) + log( \frac{80}{125} )[/tex]

Required

Solve

Apply logarithm rules

[tex]log( \frac{125^{\frac{1}{3}}}{8^{\frac{1}{3}}} )- log( \frac{2^2}{5^2} ) + log( \frac{80}{125} )[/tex]

[tex]log( \frac{5}{2}} )- log( \frac{4}{25} ) + log( \frac{80}{125} )[/tex]

Apply quotient rule

[tex]log( \frac{5}{2} / \frac{4}{25} ) + log( \frac{80}{125} )[/tex]

[tex]log( \frac{5}{2} * \frac{25}{4} ) + log( \frac{80}{125} )[/tex]

[tex]log( \frac{100}{8} ) + log( \frac{80}{125} )[/tex]

Apply product rule

[tex]log( \frac{100*80}{8*125} )[/tex]

[tex]log( \frac{8000}{1000} )[/tex]

[tex]log(8)[/tex]

Express 8 as 2^3

[tex]log(2^3)[/tex]

[tex]3log2[/tex]

Answer:

[tex]2\frac{3}{50}[/tex]

Step-by-step explanation:

So 2 would be your whole number

and since 6 is in the hundredths place the fraction would be 6/100 which is reduced to 3/50

Answer:

0.9225 = 92.25% probability that two or more internship trained candidates are hired.

Step-by-step explanation:

Candidates are chosen without replacement, which means that we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

Group of 13 individuals:

This means that [tex]N = 13[/tex]

6 candidates are selected:

This means that [tex]n = 6[/tex]

6 in trained internships:

This means that [tex]k = 6[/tex]

Find the probability that two or more internship trained candidates are hired.

This is:

[tex]P(X \geq 2) = 1 - P(X < 2)[/tex]

In which

[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]

So

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,13,6,6) = \frac{C_{6,0}*C_{7,6}}{C_{13,6}} = 0.0041[/tex]

[tex]P(X = 1) = h(1,13,6,6) = \frac{C_{6,1}*C_{7,5}}{C_{13,6}} = 0.0734[/tex]

[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.0041 + 0.0734 = 0.0775[/tex]

[tex]P(X \geq 2) = 1 - P(X < 2) = 1 - 0.0775 = 0.9225[/tex]

0.9225 = 92.25% probability that two or more internship trained candidates are hired.

Answer:

[tex]dA(t)/dt = -\frac{3}{7}e^{-t/70}[/tex] g/min

Step-by-step explanation:

The mass flow rate dA(t)/dt = mass flowing in - mass flowing out

Since water is pumped in at a rate of 3 L/min, and it contains no salt, the concentration in is thus 0 g/L. the mass flow in is thus 0 g/L × 3 L/min = 0 g/min.

Let A(t) be the mass present at any time, t. The concentration at any time ,t is thus A(t)/volume = A(t)/210. Since water flows out at a rate of 3 L/min, the mass flow out is thus, A(t)/210 g/L × 3 L/min = A(t)/70 g/min.

So, dA(t)/dt = mass flowing in - mass flowing out

dA(t)/dt = 0 g/min - A(t)/70 g/min

dA(t)/dt =  - A(t)/70 g/min

 Since the tank initially contains 30 g of salt, the initial mass of salt in the tank is 30 g. So A(0) = 30

So, the initial value problem is thus  

dA(t)/dt =  - A(t)/70 , A(0) = 30

Separating the variables, we have

dA(t)/A(t) = -dt/70

Integrating both sides, we have

∫dA(t)/A(t) = ∫-dt/70

㏑A(t) = -t/70 + C

taking exponents of both sides, we have

A(t) = exp(-t/70 + C)

A(t) = exp(-t/70)expC

[tex]A(t) = e^{-t/70}e^{C}\\A(t) = Ce^{-t/70} whereC = e^{C}[/tex]

A(0) = 30, So

[tex]A(0) = Ce^{-0/70}\\30 = Ce^{0}\\C = 30[/tex]

[tex]A(t) = 30e^{-t/70}[/tex]

The rate at which the number of grams of salt in the tank is changing at time t is

[tex]dA(t)/dt = \frac{d30e^{-t/70} }{dt} \\dA(t)/dt = -\frac{30e^{-t/70} }{70}\\dA(t)/dt = -\frac{3}{7}e^{-t/70}[/tex]

So, the rate at which the number of grams of salt in the tank is changing at time t is

[tex]dA(t)/dt = -\frac{3}{7}e^{-t/70}[/tex] g/min

Answer:

It would be C

Step-by-step explanation:

I have done this before!

Answer:

x=1

y=1

Step-by-step explanation:

2x+3y=5.........eq1

x-2y=-1........eq2

therefore: x=-1+2y

Subt. eq 3 into eq2

2x+3y=5

2(-1+2y) +3y=5

-2+4y+3y=5

7y=5+2

7y/7=7/7

y=1

therefore: Subt. y=1 into eq2

x-2y=-1

x-2(1)=-1

x-2=-1

x=-1+2

x=1

Answer:

76%

Step-by-step explanation:

Times the decimal by 100 to get a percent

basically moving the decimal 2 spaces to the right.

Answer:

The answer is 3

Step-by-step explanation:

4 x 3 = 12

8 + 12 = 20

She pulled out 91.2 dollars

Answer:

1.A+B=2y²+3x-x²+3x²-y²=y²+3x+2x²

2.A-B=2y²+3x-x²-3x²+y²=3y²+3x-4x²

3.B+C=3x²-y²+5x²-3xy=8x²-3xy-y²

4.B-C=3x²-y²-5x²+3xy=3xy-2x²-y²

5.A+B+C=2y²+3x-x²+3x²-y²+5x²-3xy

=y²+3x+2x²+5x²-3xy=y²+3x-3xy+7x²

6.A+B-C=y²+3x+2x²-5x²+3xy=y²+3x+3xy-3x²

Answer: I thinnk the answer is 6.86

4.90 divided by 5=0.98

0.98 times 7=6.86

Step-by-step explanation:

Answer:

answer is. 200

ok my answrer is correct

Answer:

V=a3=33=27

Step-by-step explanation:

sorry if its wrong

Answer: 45 degrees

Step-by-step explanation:

Answer:

Michael: 24

Junior: 8

Step-by-step explanation:

8 is a multiple of 24, meaning if you ate 1/3 of 24 you get 16, which is doubled 8.

Answer:

Step-by-step explanation:

Did u find it? Because I can’t figure it out euther

Answer:

positive 8 i think

Step-by-step explanation:

-8=8

Answer:

B, and D or 2, and 4

Step-by-step explanation:

b=2 d=4

The surface area to be painted for a bedroom of 12 feet by 8 feet and 7 feet high is equal to the areas of five faces which is 376 ft²

An equation is an expression that shows the relationship between two or more numbers and variables.

The dimensions of his room are 7 feet by 12 feet by 8 feet. Hence:

The surface area of the wall = area of the four walls and ceiling = (7 * 8) + (12 * 7) + (7 * 8) + (12 * 7) + (8 * 12) = 376 ft²

The surface area to be painted for a bedroom of 12 feet by 8 feet and 7 feet high is equal to the areas of five faces which is 376 ft²

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Answer:

yes

Step-by-step explanation:

Answer:

4^5+2x3

Step-by-step explanation:

4^5+2x3