T-Mobile charges a flat fee of $20 plus $10 per Gig of data used per month. AT&T charges $60 for an unlimiteddata use. How many Gigs of data would you have to use so that the cost will be the same for both companies?
For this case we can set uo an equation given by:
[tex]y=10x+20[/tex]Where y represent the final cost. x the number of Gig used and for this case we can set up the following equation:
[tex]60=10x+20[/tex]And solving for x we got:
[tex]x=\frac{60-20}{10}=\frac{40}{10}=4[/tex]And the final answer for this case woudl be 4 Gig of data used
You are to show how to correctly graph y = -x - 5
Answer and Explanation:
The slope-intercept form of the equation of a line is generally given as;
[tex]y=mx+b[/tex]where m = the slope of the line
b = the y-intercept of the line
So given the equation;
[tex]y=-x-5[/tex]Comparing the two equations, we can deduce the following;
* m = -1
This means that the line will have a negative slope
* b = -5
This means that the line will cut the y-axis at -5.
We can now choose values for x and determine the corresponding values of y and then proceed to plot the graph.
When x = 1;
[tex]\begin{gathered} y=-1-5 \\ y=-6 \end{gathered}[/tex]When x = 0,
[tex]\begin{gathered} y=-0-5 \\ y=-5 \end{gathered}[/tex]When x = -2,
[tex]\begin{gathered} y=-(-2)-5 \\ y=2-5 \\ y=-3 \end{gathered}[/tex]When x = -4,
[tex]\begin{gathered} y=-(-4)-5 \\ y=4-5 \\ y=-1 \end{gathered}[/tex]When x = -6;
[tex]\begin{gathered} y=-(-6)-5 \\ y=6-5 \\ y=1 \end{gathered}[/tex]With the above values and information, we can then go ahead and plot our graph as shown below;
The graph of y= 2x^2 - kx + 6 touches the x-axis. What are the possible value(s) of k?
Given:
The graph of
[tex]y=2x^2-kx+6[/tex]Required:
What are the possible value(s) of k?
Explanation:
[tex]Set\text{ y = 0, evaluate the quadratic at }h=-\frac{b}{2a}and\text{ solve for k}[/tex]You want to find the value the value of k such that the y coordinate of the vertex is 0.
[tex]\begin{gathered} y=2x^2-kx+6 \\ 0=2x^2-kx+6 \end{gathered}[/tex]The x coordinate, h , of the vertex is found, using the following equation:
[tex]\begin{gathered} D=b^2-4ac \\ b^2-4ac=0 \\ k^2-4\times2\times6=0 \\ k^2-48=0 \\ k^2=48 \\ k=\pm4\sqrt{3} \end{gathered}[/tex]Answer:
So, values of k are above.
-(1 – 7a) = 3(8a - 6)
what is the simplified form of the expression x^2+4x-21 over 4(x+7)
Answer:
x-3 over 4
Let me know if you need elaboration
A skating rink attendant monitored the number of injuries at the rink over the past year. He tracked the ages of those injured and the kinds of skates worn during injury. In-line skates Roller skates Age 8 11 10 Age 10 4 9 Age 12 3 16 What is the probability that a randomly selected injured skater was not age 12 and was not wearing roller skates? Simplify any fractions.
Given data:
The given table is shown.
The expression for the probability of that a randomly selected injured skater was not age 12 and was not wearing roller skates is,
[tex]undefined[/tex]Julie is buying chocolate chip and oatmeal cookies from the bakery. Chocolate chip cookies cost 25¢ each and oatmeal cookies cost 20c each. She wants to buy a mixture of at least 50 cookies. Julie is planning to spend less than $10. Let: C = number of chocolate chip cookies she can buy. M = number of oatmeal cookies she can buy. Select the system of inequalities that represents this situation.
Jennifer uses a coupon that gives you20% off your order. If the total was$18, how much money did she save?
let M be the money, hence, she saved
[tex]\begin{gathered} (0.2)\cdot18=3.6\text{ dollars} \\ \\ \end{gathered}[/tex]In the relationship shown by the data linear ? If so , model the data with an equation A. The relationship is not linear B. The relationship is linear; y+2=4/5 (x+9) C . The relationship is linear; y + 9 = - 4/5 (x+2) D. The relationship is linear; y+ 2 = -5/4 (x+9)
Let's take two points so that we can get the equation of the line which goes through those points. P1 (-9, -2), P2 (3, -17):
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-17-(-2)}{3-(-9)}=\frac{-17+2}{3+9}=-\frac{15}{12}=-\frac{5}{4}[/tex][tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(-2)=-\frac{5}{4}\cdot(x-(-9)) \\ y+2=-\frac{5}{4}\cdot(x+9)_{} \\ y=-\frac{5}{4}x-\frac{45}{9}-2 \\ y=-\frac{5}{4}x-7 \\ f(x)=-\frac{5}{4}x-7 \end{gathered}[/tex]So, y is the line which goes through the first and last points of the chart.
To proof that the rest of points go through the line as well, we will evalute each point
[tex]\begin{gathered} f(-5)=-\frac{5}{4}\cdot(-5)-7=\frac{25}{4}-7=-\frac{3}{4}\ne-7 \\ f(-1)=-\frac{5}{4}(-1)-7=\frac{5}{4}-7=-\frac{23}{4}\ne-12 \end{gathered}[/tex]Since the evaluation of these points don't correspond to the values of the chart we can assure that the relationship is not linear
HELPPPP MEEEEEE PLEASEEEEhey tutor how you doing doing I struggle with math so much.
Answer:
[tex]m\measuredangle8=110^o[/tex]Explanation:
The angles 4 and 8 are equal; therefore,
[tex]m\measuredangle8=m\measuredangle4[/tex][tex]3x+20=x+80[/tex]Subtracting x from both sides gives
[tex]2x+20=80[/tex]Subtracting 20 from both sides gives
[tex]2x=80-20[/tex][tex]2x=60[/tex]Finally, dividing both sides by 2 gives
[tex]\boxed{x=30.}[/tex]With the value of x in hand, we now find the measure of angle 8.
[tex]m\measuredangle8=x+80[/tex][tex]m\measuredangle8=30+80[/tex][tex]\boxed{m\measuredangle8=110^o\text{.}}[/tex]Hence, the measure of angle 8 is 110.
diana and her classmates are reading the same book.on Monday, diana started to write down the number of pages she has left to read at the end of each day from Monday through Thursday, which person is reading the same number of pages per day as diana.
From the diana table we can conclude:
[tex]\begin{gathered} x1=187 \\ x2=181 \\ x3=175 \\ x4=169 \\ x2-x1=x4-x3=6 \end{gathered}[/tex]She's reading 6 pages per day.
Since:
[tex]\begin{gathered} y1=180 \\ y2=174 \\ y3=168 \\ y4=162 \\ y2-y1=y4-y3=6 \end{gathered}[/tex]Keith is also reading 6 pages per day.
Erika is working on solving the exponential equation 50^x = 17; however, she is not quite sure where to start. Using complete sentences, describe to Erika how to solve this equation.
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
50^x = 17
Step 02:
exponential equation:
1. Apply logarithms to both sides of the equality.
[tex]log\text{ 50}^x=\text{ log 17}[/tex]2. Apply properties of logarithms.
[tex]x\text{ log 50 = log 17}[/tex]3. Apply the algebraic rules to find the value of x.
[tex]x\text{ = }\frac{log\text{ 17}}{log\text{ 50}}\text{ }[/tex]The answer is:
x = (log 17) / (log 50)
Select the correct answer. What is the difference of the values of the two variables in this system of equations? y= 2x + 1 x + 3y = 10 O A. 0 B. 1 KD C. 2 KD D. 3
According to the given data we have the following equation:
2x + 1 x + 3y = 10
There are two types of variables in the equation above.
The variable x and the variable y
In order to calculate the difference of the values of the two variables we would make the following:
First we would sum elements of variable x
variable x=2x + 1x=3x
variable y=3y
Therefore, the difference of the values=3x-3y=0
So, The right answer would be A, the value is 0.
The salesperson earned a commission of $1110.20 for selling $7930 worth of paper products. Find the commission rate
Commision = $1110.20
Selling= $7930
x is the commission rate
[tex]7930\cdot\frac{x}{100}=1110.20[/tex]Then we isolate the x
[tex]x=\frac{1110.20\cdot100}{7930}=14\text{ \%}[/tex]ANSWER
The commission rate is 14%
Solve each systems of the equations by elimination. 1* x-y=-13 x+y=-52* 2x-9y=17 2x+3y=-19
Let us solve the given system of equations by using the elimination method.
Question 1:
[tex]\begin{gathered} x-y=-13\quad eq.1 \\ x+y=-5\quad eq.2 \end{gathered}[/tex]Add these two equations so that the y variable cancels out
So, the value of x can be found now
[tex]\begin{gathered} 2x=-18 \\ x=-\frac{18}{2} \\ x=-9 \end{gathered}[/tex]Substitute the value x into any of the two equations to find the value of y.
[tex]\begin{gathered} x-y=-13 \\ -9-y=-13 \\ y=-9+13 \\ y=4 \end{gathered}[/tex]Therefore, the solution of this system is x = -9 and y = 4
What is the reason these triangles are congruent? M N Р o Not Congruent
Since the line in red is common to both triangles and segments PM and ON are parallel, then the angles in purple are congruent and so are the angles in green. So they are congruent by ASA
Dustin boat traveled 36 miles downstream in three hours. The same boat traveled 30 miles upstream in five hours. What is the speed of the boat and the speed of the current
Answer:
The speed of the boat is 9 miles/hour and the speed of the current is 3 miles/hour
Explanation:
Let's call x the speed of the boat and y the speed of the current.
The distance traveled is equal to the speed times the time, so the boat traveled 36 miles in three hours and we can write the following equation
(x + y)3 = 36
3(x + y) = 36
because when the boat traveled downstream, the total speed is the sum of x and y.
On the other hand, the boat traveled 30 miles upstream in 5 hours, so
(x - y)5 = 30
5(x - y) = 30
Therefore, the system of equations is
3(x + y) = 36
5(x - y) = 30
Solving the first equation for x, we get
[tex]\begin{gathered} 3(x+y)=36 \\ \\ \frac{3(x+y)}{3}=\frac{36}{3} \\ \\ x+y=12 \\ x+y-y=12-y \\ x=12-y \end{gathered}[/tex]Now, we can replace this expression on the second equation as follows
[tex]\begin{gathered} 5(x-y)=30 \\ \\ {\frac{5(x-y)}{5}}=\frac{30}{5} \\ \\ x-y=6 \\ \\ \text{ Replacing x = 12 - y} \\ 12-y-y=6 \\ 12-2y=6 \\ 12-2y-12=6-12 \\ -2y=-6 \\ \\ \frac{-2y}{-2}=\frac{-6}{-2} \\ \\ y=3 \end{gathered}[/tex]Then, the value of x is
x = 12 - y
x = 12 - 3
x = 9
So, the speed of the boat is 9 miles/hour and the speed of the current is 3 miles/hour
If y varies directly with x, and y = 12 when x = 8, write the direct linear variationequation.O y=8xO y = 12xO y=2/3xO y= 3/2 x
A direct linear variation of y with x has the general form:
[tex]y=mx[/tex]Where m is the ratio of y to x, which is a y divided by x.
Since we know that when x equals 8, y equals 12, we can calculate m, like this:
[tex]m=\frac{y}{x}=\frac{12}{8}=\frac{6}{4}=\frac{3}{2}[/tex]Now that we know that m=3/2, the linear variation equation would be:
[tex]y=\frac{3}{2}x[/tex]
Question 41: Find the product and express it in rectangular form.
ANSWER:
[tex]-18-18\sqrt[]{3}i[/tex]SOLUTION:
The Dover Symphony categorizes its donors as gold, silver, or bronze depending on the amount donated.
Explanation
Given the donors as
[tex]\begin{gathered} Gold=4 \\ silver=7 \\ Bronze=9 \end{gathered}[/tex]The total number of donors are
[tex]9+7+4=20[/tex]Therefore, the percent of donors at the bronze or silver level is
[tex]\frac{sum\text{ }of\text{ }bronze\text{ }and\text{ }silver\text{ donors}}{number\text{ of donors}}=\frac{9+7}{20}\times100=16\times5=80\text{\%}[/tex]Answer:
A homeowner has decided to fill in his pool. The pool is rectangular and measures 20ft wide, 40ft long, and 5.5ft deep throughout. Each cubic yard of fill dirt cost $12. How much will it cost to fill the pool?
The volume of the pool is
[tex]20ft\text{ }\times40ft\text{ }\times5.5ft=4400ft^3[/tex]a cubic foot is 0.037 cubic yards.
thus
[tex]4400ft^{3^{}}^{}=4400\times0.037=162.8yd^3[/tex]but a cubic yard of dirt costs $12, and we need 162.8 cubic yards.
that would cost
[tex]12\times162.8=\text{ \$1953.6}[/tex]
Marc se come un sándwich de huevo para el desayuno y una hamburguesa grande para el almuerzo todos los días.
El sándwich de huevo tiene 250 calorías. Si Marc come 5,250 calorías en el desayuno y almuerzo en toda la
semana en total, ¿cuántas calorías tiene una hamburguesa grande?
lón de juegos la primera vez ella ganó 60 boletos. La segunda vez,
Answer:Hay 500 calorías en una Big Burger.
Step-by-step explanation:
En una semana (7 días), Mark come 7 sándwiches de huevo, que son 1750 calorías. Reste la cantidad total de calorías que consumió por la cantidad de calorías consumidas a través de sándwiches de huevo; 5250-1750=3500. 3500 es el número total de calorías que Mark consumió al comer una Big Burger todos los días durante 7 días. Divide 3500 entre 7 = 500. Hay 500 calorías en una Big Burger.
how do i find out if a table is a linear function? i know the formula i just dont know how to figure out if its linear, thanks!
Answer:
Table 3
Explanation:
A linear function has a constant slope.
To determine if the table represents a linear function, find the slope for two different pairs of points.
Table 1
Using the points (1,-2), (2,-6)
[tex]\text{Slope},m=\frac{Change\text{ in y-axis}}{Change\text{ in x-axis}}=\frac{-6-(-2)}{2-1}=-6+2=-4[/tex]Using the points (2,-6), (3,-2)
[tex]\text{Slope},m=\frac{Change\text{ in y-axis}}{Change\text{ in x-axis}}=\frac{-2-(-6)}{3-2}=-2+6=4[/tex]The slopes are not the same, thus, the function is not linear.
Table 3
Using the points (1,-2), (2,-10)
[tex]\text{Slope},m=\frac{Change\text{ in y-axis}}{Change\text{ in x-axis}}=\frac{-10-(-2)}{2-1}=-10+2=-8[/tex]Using the points (2,-10), (3,-18)
[tex]\text{Slope},m=\frac{Change\text{ in y-axis}}{Change\text{ in x-axis}}=\frac{-18-(-10)}{3-2}=-18+10=-8[/tex]The slopes are the same, thus, the function is linear.
Table 3 is the correct option.
Sue receives $7 per hour when she works at the book store. Last week she earned $259.How many hours did she work at her job?
1 hour = $7
Number of hours = Amount/7
Therefore, 259/7 = 37 hours
Solution: Sue worked for 37 hours last week.
1. An account is opened with a balance of $2800earning 4.25% simple interest. What will be thebalance in the account in 30 years?
Answer:
$6370
Explanation:
The simple interest formula gives us the final amount A given the principal amount P:
[tex]A=P(1+rt)[/tex]where r is the interest rate and t is the time interval.
Now in our case we have
P = 2800
r = 4.25/100
t = 30 years
therefore, the above formula gives
[tex]A=2800(1+\frac{4.25}{100}\cdot30)[/tex]which simplifies to give
[tex]\boxed{A=\$6370}[/tex]Hence, the account balance after 30 years will be $6370.
Find the 38th term 359,352,345
Let's begin by listing out the information given to us:
1st term = 359, 2nd term = 352, 3rd term = 345
[tex]\begin{gathered} 359,352,345\ldots x_n \\ x_1=359,x_2=352,x_3=345 \\ x_1-x_2=x_2-x_3\Rightarrow359-352=352-345\Rightarrow7=7 \\ 7=7 \end{gathered}[/tex]This is an Arithmetic Progression (A.P.)
[tex]\begin{gathered} x_1=359 \\ x_2=359-7(2-1)\Rightarrow359-7(1)=359-7=352 \\ x_3=359-7(3-1)\Rightarrow359-7(2)=359-14=345 \\ x_n=x_1-7(n-1) \\ n_{38}=x_1-7(38-1)=359-7(37)=359-259=100 \\ n_{38}=100 \end{gathered}[/tex]Find the volume of a rectangular prism with the following dimensions.length: 4.2 cmwidth: 7 cmheight: 15 cmvolume = ____ cm3
Given:
length: 4.2 cm
width: 7 cm
height: 15 cm
Required:
volume = ____ cm3
Explanation:
volume of prism=
[tex]\begin{gathered} l\times w\times h \\ 4.2\times7\times15 \\ =441cm^3 \end{gathered}[/tex]Required answer:
[tex]441cm^3[/tex]
The average temperature on the planet A is 162°C. Convert this temperature to degrees Fahrenheit. Round to the nearestdegreeUse the formula F =+ 32162° Celsius is equivalent toFahrenheit.
Using the formula:
[tex]F=\frac{9}{5}c+32[/tex]We get:
[tex]\begin{gathered} F=\frac{9}{5}(162)+32 \\ F=323.6 \end{gathered}[/tex]162°C is equal to 323.6 F
Question 6 of 21Which of the following best describes the graph of the polynomial functiibelow?5Х-55-5-
Solution:
The zeros of a polynomial function are the points at which the graph of the function cuts the x-axis.
Given the graph of the polynomial function as shown below:
[tex]\begin{gathered} When\text{ the curve cuts the x-axis twice, this implies that the graph has 2 zeros.} \\ When\text{ the curve cuts the x-axis once, this implies that the graph has only 1 zero.} \\ \end{gathered}[/tex]Since the curve on the graph cuts the x-axis once, it implies that the graph has one zero.
The correct option is D.
of the 800 participants in a marathon, 120 are running to raise money for a cause. How many participants out of 100 are running for a cause?a.8 b. 20c. 15d. 12OMG i hate iready please heeeelp
To find how many participants out of 100 are running for a cause we can use the next proportion:
[tex]\frac{800\text{ total participants}}{100\text{ total participants}}=\frac{120\text{ running for a cause}}{x\text{ running for a cause}}[/tex]Solving for x:
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