Two common names for streets are Fourth Street and Main Street, with 14,593 streets bearing one of these names.There are 443 more streets named Fourth Street than Main Street. How many streets bear each name?

Answers

Answer 1

Let

x ----> number of streets that bear Fourth Street

y ----> number of streets that bear Main Street

we know that

x+y =14,593 --------> x=14,593-y -----> equation 1

and

x=y+443 ------> equation 2

Solve the system of equations

Equate both equations

14,593-y=y+443

solve for y

2y=14,593-443

2y=14,150

y=7,075

Find out the value of x

x=y+443 ---------> x=7,075+443=7,518

therefore

Fourth Street: 7,518 streetsMain Street: 7,075 streets

Related Questions

Which is the best estimate of 162% of 79?

Answers

We have to multiply 79 by the percentage in decimal form ( divided by 100)

79 x (162/100) = 79 x 1.62 = 127.98

rounded: 128

The best estimate is 128

Can someone please help me solve this problem number 9

Answers

The perimeter of the room was calculated in question 6, and it is 54 feet.

Since the borders come in 5-yard rolls, let's first convert 54 feet to yards.

Each yard has 3 feet, so we can divide the amount of feet by 3 to get it converted to yards:

[tex]\frac{54}{3}=18[/tex]

Thus, the perimeter of the room is 18 yards. Since each roll has 5 yards,we will need:

[tex]\frac{18}{5}=3.6[/tex]

Abou 3.6 rolls, but since we can only have whole rolls, we will have to approximate it to 4 rolls.

y=x-8 how would I do it

Answers

to find two points that satisfy the function, you need to give one value and calculate the other one, for example.

I will use x=4 and x=8

when x=4

y=4-8=-4

so one point is (4,-4)

and when x=8

y=8-8=0

so the other point is (8,0)

so you need to graph these points and then plot the line, like this:

Find the maximum value of the objective function and the values of x and y for which it occurs. F= 2x+y3x+5y ≤45 x ≥0 and y ≥02x+4y ≤32The maximum value of the objective function is ______.

Answers

The objective function is:

[tex]F=2x+y[/tex]

We need to find the shaded region where 4 inequalities overlap, then we need to graph the given inequalities:

[tex]\begin{gathered} 3x+5y\leq45 \\ 5y\leq-3x+45 \\ y\leq\frac{-3}{5}x+\frac{45}{5} \\ y\leq-\frac{3}{5}x+9 \end{gathered}[/tex]

And the other one:

[tex]\begin{gathered} 2x+4y\leq32 \\ 4y\leq-2x+32 \\ y\leq\frac{-2x}{4}+\frac{32}{4} \\ y\leq-\frac{1}{2}x+8 \end{gathered}[/tex]

And x>=0, y>=0

The graph is:

The coordinates of the shaded region are then:

(0,0), (0,8), (10,3) and (15,0)

To obtain the maximum value, let's evaluate the objective function in all the coordinates:

[tex]\begin{gathered} F(0,0)=2\times0+0=0+0=0 \\ F(0,8)=2\times0+8=0+8=8 \\ F(10,3)=2\times10+3=20+3=23 \\ F(15,0)=2\times15+0=30+0=30 \end{gathered}[/tex]

Then, the maximum value is the largest value obtained, then it's 30 and it occurs at x=15 and y=0.

Write an equation for each scenario, then find the solution.5. You're making a Wawa run for snacks and energy drinks on your bike. It takes you0.4 hours at x miles per hour to make it to Wawa. On your way back you have toride 3 miles per hour slower (you're weighed down by your Wawa goodies) and ittakes you 0.5 hours. How far is it from your house to Wawa?6. Laura retired from her job recently, and she has saved about $500,000 over the

Answers

Let y represent the distance from your house to wawa. This means that the distance from wawa to your house is also y miles.

It takes you 0.4 hours at x miles per hour to make it to Wawa.

Distance = speed * time

Therefore, on your way to wawa, the expression would be

y = 0.4 * x = 0.4x

On your way back you have to ride 3 miles per hour slower. This means that your speed was (x - 3) miles per hour. Since it took you 0.5 hours, the expression for distance would be

y = 0.5(x - 3)

Since the distance is the same, it means that

0.4x = 0.5(x - 3)

0.4x = 0.5x - 1.5

0.5x - 0.4x = 1.5

0.1x = 1.5

x = 1.5/0.1

x = 15

Therefore,

y = 0.4x = 0.4 * 15

y = 6

The distance from your house to wawa is 6 miles

What is (6/7)/(2/7)?

Answers

To find the value of;

[tex]\frac{(\frac{6}{7})}{(\frac{2}{7})}[/tex]

When dividing fractions, for example a divided by b is equals a times 1/b;

[tex]a\text{ divided by b = a }\times\frac{1}{b}[/tex]

note that the divisor which is b is inversed and multiplied.

So, let us apply the same rule to the given question.

The divisor which is the second fraction for the question is 2/7, we need to inverse 2/7 and multiply it by the first fraction.

The inverse of 2/7 is 7/2, So;

[tex]\frac{(\frac{6}{7})}{(\frac{2}{7})}=\text{ }\frac{6}{7}\times\frac{7}{2}=\frac{(6\times7)}{(7\times2)}=\frac{42}{14}[/tex]

And finally;

[tex]\frac{42}{14}=3[/tex]

Therefore the final answer is 3.

[tex]\frac{(\frac{6}{7})}{(\frac{2}{7})}=\text{ 3}[/tex]

A full one- gallon container can beused to fill the one-liter containers, as shownbelow. Write a unit rate that estimates thenumber of liters per gallons.

Answers

[tex]\text{ 3 liters per gallon}[/tex]

Explanation

Step 1

as we can see in the picture

[tex]1\text{ gallons}\rightarrow3\text{ liters}[/tex]

so, to find the unit rate make

[tex]\begin{gathered} \text{unit rate=}\frac{Number\text{ of liters}}{Number\text{ of gallons}} \\ \text{replace} \\ \text{Unit rate=}\frac{3\text{ liters}}{1\text{ gallon}}=\text{ 3 liters per gallon} \end{gathered}[/tex]

I hope this helps you

Find the length of x.43a. 2.5b. 3C. 4d. 5e. 656

Answers

the given triangle is a right angle triangle.

by Pythagoras theorem.

4^2 + 3^2 = x^2

16 + 9 = X^2

25 = x^2

[tex]\begin{gathered} x^2=25 \\ x=5 \end{gathered}[/tex]

so, the answer is x = 5.

nine cubes are glued together to form the solid shown in the digram .

Answers

ANSWER

D. 272.25 mm²

EXPLANATION

First we have to find the area of one face of one cube:

[tex]A=2.75^2=7.5625\operatorname{mm}^2[/tex]

Now we have to count how many faces of the squares are in the surface of the solid. Or a faster way is to multiply the total number of faces of the 9 cubes: 6*9=54 and subtract the number of faces that are not on the surface:

There are 18 faces of the cubes that are not on the surface of the solid. The number of faces from the 9 cubes that are on the surface of the solid is:

[tex]54-18=36[/tex]

The surface area of the solid is the area of a face of one cube multiplied by the number of faces on the surface of the solid:

[tex]SA=36\cdot A=36\cdot7.5625=272.25\operatorname{mm}^2[/tex]

Answer:

D. 272.25 mm²

Step-by-step explanation:

What is the the musical instrument that is a pair of clash cymbals, originating in the Indian subcontinent, which makes high- pitched percussion sounds?

Answers

SOLUTION:

Step 1:

In this question, we are asked to find the musical instrument that is a pair of clash cymbals, originating in the Indian subcontinent, which makes high- pitched percussion sounds​.

Step 2:

The details of the solution are as follows:

The Taal is a pair of clash cymbals, originating in the Indian subcontinent, which makes high-pitched percussion sounds. In its simplest form, it consists of a pair of small hand cymbals.

usi

Solve the equation involving absolute value. Type you answers from smallest to largest. If an answer is not an integer then type it as a decimal rounded to the nearest hundredth. |x^2+2x-36|=12 x=Answer, Answer, Answer and Answer

Answers

Given:

The euqation is,

[tex]|x^2+2x-36|=12[/tex]

Explanation:

Simplify the equation.

[tex]\begin{gathered} |x^2+2x-36|=12 \\ x^2+2x-36=\pm12 \end{gathered}[/tex]

Solve the x^2 + 2x - 36 = 12 for x.

[tex]\begin{gathered} x^2+2x-36=12 \\ x^2+2x-36-12=0 \\ x^2+8x-6x-48=0 \\ x(x+8)-6(x-8)=0 \\ (x+8)(x-6)=0 \\ x=-8,6 \end{gathered}[/tex]

Solve the equation x^2 + 2x - 36 = -12 for x.

[tex]\begin{gathered} x^2+2x-36+12=0 \\ x^2+2x-24=0 \\ x^2+6x-4x-24=0 \\ x(x+6)-4(x+6)=0 \\ (x+6)(x-4)=0 \\ x=-6,4 \end{gathered}[/tex]

Thus solution of the equation is x = -8, -6, 4, and 6

Use the Law of Cosines to determine the indicated angle 0. (Assume a = 65.01, b = 36.38, and c = 42.05. Round your answer to two decimal places.)

Answers

a = 65.01, b = 36.38, and c = 42.05.

And it is required to find the measure of angle 0 which will be the angle B

Using the law of cosine

[tex]\begin{gathered} b^2=a^2+c^2-2\cdot a\cdot c\cdot\cos B \\ \cos B=\frac{a^2+c^2-b^2}{2\cdot a\cdot c}=\frac{65.01^2+42.05^2-36.38^2}{2\cdot65.01\cdot42.05}=0.854 \\ \end{gathered}[/tex][tex]\angle\emptyset=\angle B=\cos ^{-1}0.854=31.31[/tex]

the answer is rounded to two decimals

Find the perimeter of each circle. Use 3 for pi.

Answers

Part 1

We need to find the perimeter of a circle with a diameter of 18 inches.

The relation between the perimeter P and the diameter d is given by:

[tex]P=\pi d[/tex]

Since d = 18 inches and we need to use 3 for π, we obtain:

[tex]P=3\cdot18\text{ inches }=54\text{ inches}[/tex]

Therefore, the ribbon needs to be 54 inches long.

Part 2

We need to find the perimeter of a semicircle with a radius of 8 in.

The perimeter of this semicircle is the sum of half the perimeter of the whole circle and the line segment formed by two radii.

The relation between the perimeter P and the radius r of a circle is:

[tex]P=2\pi r[/tex]

Thus, half the perimeter is:

[tex]\frac{P}{2}=\pi r[/tex]

Since we need to use 3 for π and r = 8 in, we obtain:

[tex]\frac{P}{2}=3\cdot8\text{ in }=24\text{ in}[/tex]

And the line segment measures:

[tex]2\cdot8\text{ in }=16\text{ in}[/tex]

Therefore, the perimeter of the calzone is:

[tex]24\text{ in }+16\text{ in }=40\text{ in}[/tex]

Answer: 40 in.

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $30 and same-day tickets cost $15. For one performance,there were 50 tickets sold in all, and the total amount paid for them was $1275. How many tickets of each type were sold?

Answers

Given:

there are two types of tickets to a show: advance and same-day

Let the number of tickets from the type of Advance = x

And the number of tickets from the type of Same-day = y

there were 50 tickets sold in all

So,

[tex]x+y=50\rightarrow(1)[/tex]

Advance tickets cost $30 and same-day tickets cost $15.

the total amount paid for them was $1275

So,

[tex]30x+15y=1275\rightarrow(2)[/tex]

Solve the equations (1) and (2) to find (x) and (y)

[tex]\begin{gathered} x+y=50\rightarrow(\times-15) \\ 30x+15y=1275 \\ ============= \\ -15x-15y=-750 \\ 30x+15y=1275 \\ ============= \\ 15x=525 \\ x=\frac{525}{15}=35 \\ y=50-x=50-35=15 \end{gathered}[/tex]

So, The answer will be:

The number of tickets from the type of Advance = x = 35

And the number of tickets from the type of Same-day = y = 15

Find f in:f ÷ -2/3 = -1/3

Answers

ANSWER

[tex]f\text{ = }\frac{2}{9}[/tex]

EXPLANATION

We want to find f in:

[tex]f\text{ }\div\text{ -}\frac{2}{3}\text{ = -}\frac{1}{3}[/tex]

To do that, we multiply both sides by -2/3.

That way, it cancels out the -2/3 on the left hand side and isolates f.

So we have:

[tex]\begin{gathered} f\text{ }\div(-\frac{2}{3})\cdot\text{ (-}\frac{2}{3})\text{ = -}\frac{1}{3}\cdot\text{ -}\frac{2}{3} \\ f\text{ = }\frac{2}{9} \end{gathered}[/tex]

That is the answer.

At an amusement park, the two most popular rollercoasters are the Python and the Vortex. The Python is 212 feet long and the Vortex is 210 feet long. How many times as long is the Python as the Vortex?

Answers

Answer:

About 1.01 times longer

Step-by-step explanation:

we have to divide 212 by 210 since these are the lengths to get about 1.01.

Hopes this helps please mark brainly

Jane has a pre-paid cell phone with A Fee and Fee. She can't remember the exact costs, but her plan has a monthly fee and a charge for each minute of calling time. In June she used 430 minutes and the cost was $227.50. In July she used 780 minutes and the cost was $385.00.

Answers

Given:

the plan of the pre-paid cell phone

The plan has a monthly fee and a charge for each minute

Let the monthly cost = C

and the number of minutes = x

the general equation will be:

C = ax + b

Where (b) is the monthly fee, and (a) is the charge per minute

We will find the values of (a) and (b) using the following:

1) 430 minutes cost $227.50

2) 780 minutes cost $385.00.

So, we have the following equations:

[tex]\begin{gathered} 430a+b=227.5\rightarrow(1) \\ 780a+b=385\rightarrow(2) \end{gathered}[/tex]

Solve the equations, subtract equation (1) from (2) to eliminate (b), and solve for (a):

[tex]\begin{gathered} 780a-430a=385-227.5 \\ 350a=157.5 \\ a=\frac{157.5}{350}=0.45 \end{gathered}[/tex]

Substitute with (a) into equation (1) to find the value of (b)

[tex]\begin{gathered} 430\cdot0.45+b=227.5 \\ 193.5+b=227.5 \\ b=227.5-193.5=34 \end{gathered}[/tex]

So, the equation of the monthly cost will be:

[tex]C=0.45x+34[/tex]

Part (b): When x = 484 minutes, we will find C

so, substitute with (x) into the equation of C

[tex]\begin{gathered} C=0.45\times484+34 \\ C=217.8+34 \\ C=251.8 \end{gathered}[/tex]

So, the answer will be:

A) C = 0.45x + 34

B) $251.8

Suppose that a regression line for some data transformed with logarithmspredicts that when y equals 8, log(%) will equal 1.603. What does theregression line predict y will equal when y equals 8? Round your answer to thenearest whole number.

Answers

Given the relationship between y and x to be

[tex]y=a^x\text{ ------ equation 1}[/tex]

Take the logarithm of both sides,

[tex]\begin{gathered} \log y=\log ^{}_{}a^x \\ \Rightarrow\log \text{ y = x }\times\text{ log a ---- equation 2} \end{gathered}[/tex]

But when x = 8, log y = 1.603.

Thus, substituting the above values into equation 2, we have

[tex]\begin{gathered} 1.603\text{ = 8 }\times\text{ log a} \\ \text{divide both sides by 8} \\ \log \text{ a= }\frac{1.603}{8} \\ \Rightarrow\log \text{ a =0.2}004 \\ \text{Thus, } \\ a=1.586 \end{gathered}[/tex]

From equation 1,

[tex]\begin{gathered} y=a^x \\ \Rightarrow y=1.586^x\text{ ----- equation 3} \end{gathered}[/tex]

Thus, when x = 8

[tex]\begin{gathered} y=1.586^x \\ y=1.586^8 \\ \Rightarrow y=40.03 \end{gathered}[/tex]

Thus, the value of y will be 40 (to the nearest whole number)

The correct option is D

Identify the normal equations of an exponential curve.ΣxY = AΣx + BΣx2 and ΣY = nA + BΣxΣxY = AΣx + BΣx2 and ΣY = A + BΣxΣxY = AΣx - BΣx2 and ΣY = nA + BΣxΣxY = AΣx + BΣx2 and ΣY = nA - BΣx

Answers

Given

The normal equations of an exponential curve.



Solution

[tex]The\text{ exponential equation is y=ax}^b[/tex]

taking logarithm on both sides, we get

[tex]\begin{gathered} log10y=log10a+blog10x \\ \\ Y=A+bXwhereY=log10y,A=log10a,X=log10x \end{gathered}[/tex]

which linear in Y,X

So the corresponding normal equations are

[tex]\begin{gathered} ∑Y=nA+b∑X \\ \\ ∑XY=A∑X+b∑X2 \end{gathered}[/tex]

The final answer

Option A

Fourteen more than 4 times a number is 42what is equation?what is solution?

Answers

We have to express this phrase in mathematical terms.

We call the number x.

Then, four times a number is "4x".

Fourtenn more than 4x is "4x+14", and this is equal to 42.

Then, we can write:

[tex]4x+14=42[/tex]

And solve as:

[tex]\begin{gathered} 4x+14=42 \\ 4x=42-14 \\ 4x=28 \\ x=\frac{28}{4} \\ x=7 \end{gathered}[/tex]

Answer: the equation is 4x+14=42 and the solution is x=7

the sum of three consecutive integers is 267.what is that largest interger

Answers

The sum of three consecutive integers is 267. If the first one is a, then the second would be a + 1, while the third would be a + 2. Therefore, you would have;

[tex]\begin{gathered} a+(a+1)+(a+2)=267 \\ a+a+1+a+2=267 \\ 3a+3=267 \\ \text{Subtract 3 from both sides} \\ 3a=264 \\ \text{Divide both sides by 3} \\ a=88 \end{gathered}[/tex]

The largest (third) integer is a + 2, therefore

[tex]\begin{gathered} a+2=88+2 \\ a+2=90 \end{gathered}[/tex]

The largest integer therefore is 90.

help!!! thanks :))))))

Answers

The length of given sides BC = 38 and EF = 38.

Given:

ΔABC ≅ ΔDEF

BC = x + 30 , EF = 4x + 6

we know that

BC = EF

x + 30 = 4x +  6

30 - 6 = 4x - x

24 = 3x

divide by 3 on both sides

3x/3 = 24/3

x = 8

BC = x + 30

= 8 + 30

= 38

EF = 4x + 6

= 4*8 + 6

= 32+6

= 38

Therefore the length of given sides BC = 38 and EF = 38.

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Equivalent Linear Expressions MC 2.02
Which expression is equivalent to (-3 1/3d + 3/4) - (3 5/6d + 7/8)
A: 1/2d-1/8
B: 1/2d-1 5/8
C: 43/6d-1/8
D: -43/6d-1/8

Answers

The expression is equivalent to the given expression is -43/6d-1/8.

What is expression?

An expression in math is a sentence with a minimum of two numbers or variables and at least one math operation.

Given an expression [tex]-3\frac{1}{3d} +\frac{3}{4} - (3\frac{5}{6d}+\frac{7}{8} )[/tex]

= -10/3d +3/4 - 23/6d - 7/8

= -10/3d - 23/6d + 3/4 - 7/8

= -43/6d - 1/8

Hence, The expression is equivalent to the given expression is -43/6d-1/8.

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Answer:

- 4/15x + 4

Step-by-step explanation:

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which line is steeper y=+2 or y= -7/3x -5

Answers

The inclination of the lines in the coordinate system is given by their slopes, so to determine which line is steeper you have to compare the absolute values of both slopes.

The first equation y=2 has no slope, if you draw it you will see that for any value of x, y doesn't change, it is always 2.

You can also say that the slope of this equation is equal to zero.

For the second equation y=-7/3x-5, the slope is equal to -7/3.

The second equation is steeper than the first one since the absolute value of its slope is greater.

Find the following values of the function6(-7+8f(x) = 75 - 2.c12-2 < -2– 2 4f(-4)=f(-2) =f(-1) =f(9) =91)Answers in progress)

Answers

Find the following values of the function

6

(-7+8

f(x) = 7

5 - 2.c

12

-

2 < -2

– 2a> 4

f(-4)=

f(-2) =

f(-1) =

f(9) =

9

1)

2cuestionAngelique is buying towels for her apartment. She finds some green towels, x, that cost $5 each and bluetowels, y, that cost $9 each. She wants to buy at least 4 towels, but does not want to spend more than$38. How many of each towel can she purchase?Enter the system of inequalities that represents the situation. Then select the graph of the system andselect one possible solution.The system of inequalities

Answers

x: green towels (each one cost $5)

y: blue towels (each one cost $9)

She wants to buy at least 4 towels:

[tex]x+y\ge4[/tex]

She does not want to spend more than $38:

[tex]5x+9y\leq38[/tex]

The sytem of inequalitites is:

[tex]\begin{gathered} x+y\ge4 \\ 5x+9y\leq38 \end{gathered}[/tex]

Graph: First inequality in red, second inequality in blue

Solution: Area shaded of both colours

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GIVEN: P(N) = 0.25 and P(R) = 0.6If the probability of P(N R) = 0.15, are N and Rindependent events?a) Yes, because P(N) + P(R) +0.15b) No, because P(N).P(R) +0.15c) Yes, because P(N) X P(R) = 0.15d) Not enough information

Answers

P(N∩R) represents the probability of A and B.

When two events are independent events, the joint probability is calculated by multiplying their individual probabilities.

P(N∩R) For independent events:

[tex]P\mleft(N\cap R\mright)=P(N)\times P(R)[/tex]

Substituting the known values for P(N) and P(R):

[tex]\begin{gathered} P(N\cap R)=0.25\times0.6 \\ P(N\cap R)=0.15 \end{gathered}[/tex]

0.15 is the value of P(N∩R) given by the problem, and since we get the same result using the formula for independent events, we can affirm that N and R independent events.

Answer:

c) Yes, because P(N) X P(R) = 0.15

Which expression represents the simplest factorization of 56st – 21t?

Answers

The expression which represents the simplest factorization of 56st – 21t is 7t(8s - 3).

How to factorise an expression?

Factorization is the process of creating a list of factors. It is also an expression listing items that when multiplied together will produce a desired quantity.

Greatest common factor is the largest positive integer or polynomial that is a divisor of several different numbers.

56st - 21t

Factors of

56st = 1, 2, 4, 7, 8, 14, 28,:56, t, s

21t = 1, 3, 7, 21

The common factors of 56st and 21t is 7 and t

56st - 21t

= 7t(8s - 3)

Check:

7t(8s - 3)

= 56st - 21t

In conclusion, the simplest factorization of the expression 56st - 21t is 7t(8s - 3).

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11. Determine if the following sequence is arithmetic or geometric. Then, find the 12th term. 2, 6, 18, 54, ... a. arithmetic: 35 b. arithmetic: 354,294 c. geometric: 35 d. geometric: 354,294

Answers

We have the sequence: 2, 6, 18, 54...

If the sequence is arithmetic, there must be a common difference between the terms that remains constant.

This is not the case for this sequence.

We can try by seeing if there is a common factor k such that:

[tex]a_n=k\cdot a_{n-1}[/tex]

We can do it by:

[tex]\frac{a_2}{a_1}=\frac{6}{2}=3[/tex][tex]\frac{a_3}{a_2}=\frac{18}{6}=3[/tex][tex]\frac{a_4}{a_3}=\frac{54}{18}=3[/tex]

There, we have a geometric sequence, with factor k=3:

[tex]a_n=3\cdot a_{n-1}[/tex]

We can relate it to the first term as:

[tex]\begin{gathered} a_2=3\cdot a_1 \\ a_3=3\cdot a_2=3\cdot3\cdot a_1=3^2\cdot a_1 \\ a_4=3\cdot a_3=3\cdot3^2\cdot a_1=3^3\cdot a_1 \\ a_n=3^{n-1}\cdot a_1=3^{n-1}_{}\cdot2 \end{gathered}[/tex]

For n=12, we have:

[tex]a_{12}=3^{12-1}\cdot2=3^{11}\cdot2=177,147\cdot2=354,294[/tex]

The value of a12 is 354,294.

The answer is d) Geometric, 354,294.

options 1. a (-3,50) b (-2,0) c (0,-4) d (1,-6) 2. a (-3,50) b (0,-4) c (-1,-6) d (2,0)3. a (-3,50) b (-2,0) c (0,-4) d (2,0)

Answers

Answer:

The x-intercepts shown in the table are (-2, 0) and (2, 0).

The y-intercept shown in the table is (0, -4)

Explanation:

The x-intercepts are the points where the value of f(x) is 0. Then, these points are (-2, 0) and (2, 0)

Additionally, the y-intercept is the point where the value of x is 0, so the y-intercept is (0, -4).

Then, the answers are:

The x-intercepts shown in the table are (-2, 0) and (2, 0).

The y-intercept shown in the table is (0, -4)

Other Questions
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