If Triangles ABC and DEF are similar. Side length AB is 2, side length AC is 4, and side length BC is 3 Side length DE is 1.34 then length of DF = 2.68 and length of EF = 2.01
What are Similar Triangles?Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .
Given,
Triangles ABC and DEF are similar.
AB = 2
AC = 4
BC = 3
DE = 1.34
We need to find the length of DF and EF
Given that ABC and DEF are similar, therefore:
AB/DE = BC/EF = AC/DF
2/1.34=3/EF=4/DF
1.49=3/EF=4/DF
Now,
1.49=3/EF
EF=3/1.49
EF=2.01
1.49=4/DF
DF=4/1.49
DF=2.68
Hence, length of DF = 2.68 and length of EF = 2.01
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yo i need some help this determines weather i pass or fail
To make 4 dozen cookies she would need
→ 3/2 cup peanut butter
→ 3 cup of vegetable shortening
→ 1 1/2 cups of firmly packed light brown sugar
→ 6 tablespoons of milk
→ 2 3/2 tablespoons of vanilla extract
→ 2 cups of flour
→ 3/2 teaspoon of baking soda
→ 1/2 teaspoon salt
To make 4 dozen cookies
she will need double the items which are mentioned in the list
thus the required list will look like this
3/4 × 2 = 3/2 cup peanut butter
3/2 cup of vegetable shortening = 3/2 × 2 = 3 cup of vegetable shortening
1 1/4 cups of firmly packed light brown sugar = 1 1/4 × 2 = 1 1/2 cups of firmly packed light brown sugar
3 tablespoons of milk = 3 × 2 = 6 tablespoons of milk
2 3/4 tablespoons of vanilla extract = 2 3/2 tablespoons of vanilla extract
1 large egg = 1× 2 = 2 large eggs
1 1/2 cups flour = 1 1/2×2 = 1 + 1 = 2 cups of flour
3/4 teaspoon baking soda = 3/2 teaspoon of baking soda
1/4 teaspoon salt = 1/4 × 2 = 1/2 teaspoon salt
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If u = 1 + 3i and v = -2 − i, what is u + v?
Answer:
2i - 1
Step-by-step explanation:
The expression is,
→ u + v
Simplifying the expression,
→ u + v
→ (1 + 3i) + (-2 - i)
→ (3i - i) + (1 - 2)
→ 2i - 1
Hence, the answer is 2i - 1.
Step-by-step explanation:
you need to replace definition of both u and v into the equation
u + v = (1+3i) + (-2-i)
= 1 + 3i -2 - i
= 3i - i + 1 - 2
= 2i - 1
please help help me write a story to describe the graph
I'll start first by finding the slope of the line at t = 2 mins up to t = 6 mins, t = 6 mins up to t = 8 mins, and t = 14 mins up to t = 20 mins.
For the first interval (2 mins to 6 mins), we have the coordinates (2, 7) and (6, 5). The slope of the line is
[tex]m=\frac{5-7}{6-2}=-\frac{2}{4}=-\frac{1}{2}[/tex]For the second interval (6 mins up to 8 mins), we have the coordinates (6, 5) and (8,0). The slope of the line is
[tex]m=\frac{0-5}{8-6}=-\frac{5}{2}[/tex]For the last interval (14 mins up to 20 mins), we have the coordinates (14,0) and (20,9). The slope of the line is
[tex]m=\frac{9-0}{20-14}=\frac{9}{6}[/tex]The x-axis of the given graph pertains to time while its y-axis pertains to distance from home. Let's try to make a story about a person from work going home and will prepare something before going outside again.
For the first 2 mins, the person walks out of his office and will go to his car. Since he is still in the office, the distance from home does not change for the first two minutes.
For the next 4 mins (2 mins to 6 mins interval), he starts driving going home at a rate of 1/2 miles per minute. Because of traffic, he is driving slower than his usual driving speed. Upon passing away from the traffic, the person now travels at a rate of 5/2 miles per minute for 2 mins (6 to 8 mins interval). At the 8th minute mark, he is already home. He prepared something at home during the 8 min to 14 min interval time. After the preparation, he went again outside for some business trip, traveling at the speed of 9/6 miles per minute.
In ΔOPQ, o = 9.2 cm, p = 2.4 cm and ∠Q=37°. Find the length of q, to the nearest 10th of a centimeter.
The length of q, to the nearest 10th of a centimeter is 7.6 cm.
Given in question,
In ΔOPQ,
o = 9.2 cm
p = 2.4 cm
∠Q = 37°
Cosine formula ⇒ cos θ = [tex]\frac{o^{2}+p^{2}-q^{2} }{2op}[/tex]
Putting the values in equation,
cos 37 = [tex]\frac{(9.2)^{2}+(2.4)^{2}-q^{2} }{2*9.2*2.4}[/tex]
0.799 = [tex]\frac{84.64 + 5.76-q^{2} }{44.16}[/tex]
0.799*44.16 = 90.4 - [tex]q^{2}[/tex]
32.28 = 90.4 - [tex]q^{2}[/tex]
[tex]q^{2}[/tex] = 90.4 - 32.28
[tex]q^{2}[/tex] = 58.12
[tex]q = \sqrt{58.12}[/tex]
[tex]q = 7.63[/tex]
q = 7.6 cm (to nearest 10th)
Hence, length of q is 7.6 cm.
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please answer this question
The value of m<2 = 107
Given:
m<SOX = 160
m<1 = x+14
m<2 = 3x - 10
x + 14 + 3x - 10 = 160
4x + 14 - 10 = 160
4x + 4 = 160
4x = 160 - 4
4x = 156
divide by 4 on both sides
4x/4 = 156/4
x = 39
m<2 = 3*39 - 10
= 117 - 10
= 107
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How many people did Trevor survey?
74
92
107
137
Answer:
92 I think because in my class I heard my friend tell me
pls help me answer these questions
Answer:
Length: 10 m
Width: 6 m
Step-by-step explanation:
The layout of the floor is l x w, which is 100 cm by 60 cm. Now, the confusing part: 1 meter (m) = 10 centimeters (cm)
To set this problem up, you'd first have to go through the logic. For every 10 centimeters of the floor layout, it is equal to 1 meter of the actualy floor plan. So you would have to scale 100 cm and 60 cm by [tex]\frac{1}{10}[/tex] (or divide by 10).
We will ignore the units, for now
Length: 100 * [tex]\frac{1}{10}[/tex] = 10 or (100/10 = 10)
Width: 60 * [tex]\frac{1}{10}[/tex] = 6 or (60/10 = 6)
Now that we've finalized the numerical value, lets move on to the units. Since the question wants us to respond in meters, the length of 10 and the width 6 6 would be in meters.
So the answer would be:
Length: 10 m
Width: 6 m
Hope this helped!
If you travel a 150 miles in 3 hours what was your average rate of speed
Distance (D): 150 miles
Time (t): 3 hours
[tex]Speed=\frac{D}{t}=\frac{150}{3}=50[/tex]Answer: 50 miles / hour
Answer to the nearest tenth:
12 is 90% of what number?
Answer:
13.33 is the answer im pretty sure
Step-by-step explanation:
Answer:
13.3
Step-by-step explanation:
1. If it's possible - try cutting the number down to 10%-:
We can do that by dividing 12 by 9, which would give us 10% of that
number.
2. We get 1.33, which is 10% of the number. To get 100 percent, we just need to multiply by 10
3: 1.33*10 is 13.3, so the answer has to be 13.3
For a certain casino slot machine, the odds in favor of a win are given as 67 to 33. Express the indicated degree of likelihood as a probability value between 0 and 1 inclusive. The probability is ___
Data:
• Odds in favor of a win are given as 67 to 33.
Procedure
• We have to find the total sample (,T,), which can be calculated as follows:
[tex]T=67+33=100[/tex]Then, to calculate the probability, we have to divide the odds in favor of a win by T.
[tex]\frac{67}{100}=0.67[/tex]Answer: 0.67
I am going to send the pictures Please solve question b(b) Canada like many countries use the metric system if the Canada news says it’s-2 degrees Celsius what is that in Fahrenheit ( Celsius is typically rounded to the tenth place
Given equation:
[tex]\text{ Wind Chill = }35.74\text{ }+\text{ }0.6215T\text{ }-\text{ 35}.75(V^{0.16})\text{ }+\text{ }0.4275T(V^{0.16})[/tex]Where T = temperature in Fahrenheit and
V = wind speed in miles per hour
Conversion formulas:
[tex]\begin{gathered} A_s\text{ = }M_s\text{ }\times\text{ }0.62 \\ F\text{ = 1.8C + 32} \end{gathered}[/tex]Question (b)
We are required to convert -2 degree Celsius to Fahrenheit
Using the conversion formula:
[tex]\begin{gathered} F\text{ = }1.8\text{ }\times-2\text{ + 32} \\ =\text{ 28.4} \end{gathered}[/tex]Answer: 28.4 F
Solve the quadratic equation x² + 2√2x-6=0 for x
Step-by-step explanation:
D = b²-4ac
D = (2√2)²-4×1×(-6)
D = 8+24 = 32 = 4√2
X1 =
[tex] \\ \frac{ - 2 \sqrt{2} + 4 \sqrt{2} }{ 2 } = \frac{2 \sqrt{2} }{2} = \sqrt{2} [/tex]
X2 =
[tex] \frac{ - 2 \sqrt{2 } - 4 \sqrt{2} }{2} = - 3 \sqrt{2} [/tex]
There is a 40% chance that it is rainy in California. If there are 365 days in a year, how many of them would you expect to be rainy?
It is expected that 146 days will be rainy
Based on the given percentage, we want to calculate the number of rainy days
What we have to do here is to multiply the percentage by the number of days
That would be 40% of 365 days
We have this as;
[tex]\frac{40}{100}\times365\text{ = 146}[/tex]Study the figures, figure 1 is similar to figure 2Part A : Describe a series of transformations and dilations that map figure 1 to figure 2Part 2: Describe a second series of transformations and dilations that map figure 1 to figure 2
In order to go from figure 1 to figure 2, there are a number of different transformations that can be selected.
First, notice that figure 2 is exactly three times as large as figure 1, therefore, there has been a dilation by a factor of three (3) that took place .
So Let's say that we do the dilation first.
Step 1: Dilation by a factor of "3" using the point (-1, -2) which is one of the vertices of the triangle, for reference. Then, the new triangle would have new coordinaes for the vertices at the points:
(-1, -2) (-1, 1) and (-6, -2)
I am making a drawing to show the change (give me a little time)
So, we see that the dilated triangle is represented by the green one in the image above.
Step 2: we are now going the "reflect the green triangle around the horizontal line y = 2 represented by the blue line . When we reflect the green triangle around that line, we obtain the orange triangle.
Step 3: we are going to do another reflection, this time a reflection around the vertical line x = 1 (noted in purple in the image above). After this, we obtain the triangle in figure 2.
So we
There is a rope running from the top of a flagpole to a hook in the ground. The flagpole is 21 feet high, and the hook is 20 feet from its base. How long is the rope?
Given f(x)=3x^3 - 4x^2 + 2x - 1 and g(x) = x - 4, state the quotient and remainder of f(x)/g(x), in the form q(x) + r(x)/g(x)
Dividing f(x) = 3x³ - 4x² + 2x - 1 by g(x) = x - 4 will yield a quotient of q(x) = 3x² - 8x + 34 and a remainder of 135, that is (3x² - 8x + 34) + 135/(x - 4).
Calculating for the quotient and remainderApplying the long division method will require us to; divide, multiply, subtract, bring down the next number and repeat the process to end at zero or arrive at a remainder.
We shall divide the dividend f(x) = 3x³ - 4x² + 2x - 1 by the divisor g(x) = x - 4 as follows;
3x³ divided by x equals 3x²
x - 4 multiplied by 3x² equals 3x³ - 12x²
subtract 3x³ - 12x² from 3x³ - 4x² + 2x - 1 will result to 8x² + 2x - 1.
8x² divided by x equals 8x
x - 4 multiplied by 8x² equals 8x² - 32x
subtract 8x² - 32x from 8x² + 2x - 1 will result to 34x - 1.
34x divided by x equals 34
x - 4 multiplied by 34 equals 34x - 136
subtract 34x - 136 from 34x - 1. will result to a remainder of 135.
Therefore by the long division method, f(x) = 3x³ - 4x² + 2x - 1 divided by g(x) = x - 4 gives a quotient q(x) = 3x² - 8x + 34 with a remainder of 135.
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Multiply the two polynomials (3a² + 5a - 2)(5a² - 3a + 4)
SOLUTION
The polynomials expression given are
[tex]\mleft(3a^2+5a-2\mright)\mleft(5a^2-3a+4\mright)[/tex]Expand the expression by distributing the parentheses
[tex]3a^2\cdot\: 5a^2+3a^2\mleft(-3a\mright)+3a^2\cdot\: 4+5a\cdot\: 5a^2+5a\mleft(-3a\mright)+5a\cdot\: 4-2\cdot\: 5a^2-2\mleft(-3a\mright)-2\cdot\: 4[/tex]Simplify
[tex]\begin{gathered} 15a^4-9a^3+12a^2+25a^3-15a^2+20a-10a^2+6a-8 \\ \text{Rearranging and simplify} \\ 15a^4-9a^3+25a^3+12a^2-15a^2-10a^2+20a+6a-8 \\ 15a^4+16a^3-13a^2+26a-8 \end{gathered}[/tex]Hence, the answer is
[tex]15a^4+16a^3-13a^2+26a-8[/tex]A floor has 15 1/2 tiles in an area of 2 2/5 sqft how many tiles are in a square foot
Since in 2 2/5 sqft are 15 1/2 tiles, then in 1 square foot, there are:
[tex]\frac{15\frac{1}{2}}{2\frac{2}{5}}[/tex]tiles.
To compute the above division we transform the mixed fractions into improper fractions:
[tex]\begin{gathered} 15\text{ }\frac{1}{2}=\frac{31}{2}, \\ 2\frac{2}{5}=\frac{12}{5}. \end{gathered}[/tex]Therefore:
[tex]\frac{15\frac{1}{2}}{2\frac{2}{5}}=\frac{\frac{31}{2}}{\frac{12}{5}}=\frac{31\times5}{12\times2}=\frac{155}{24}\text{.}[/tex]Answer: 6 11/24 tiles.
I need help with this practice problem It’s asks to Drag the angle measure to each box to match the quadrant location of the terminal ray of the angle op
Note that the range in quadrants are :
[tex]\begin{gathered} Q1\colon\text{From}\quad 0\pi-0.5\pi \\ Q2\colon\text{From}\quad 0.5\pi-1.0\pi \\ Q3\colon\text{From}\quad 1.0\pi-1.5\pi \\ Q4\colon\text{From}\quad 1.5\pi-2\pi \end{gathered}[/tex]From the problem,
[tex]\begin{gathered} \frac{3\pi}{4}=0.75\pi\Rightarrow Q2 \\ \frac{57\pi}{8}=7.125\pi \\ \text{Note that 1 whole circle is}\quad 2\pi \\ \text{Subtracting three}\quad 2\pi \\ 7.125\pi-3(2\pi)=1.125\pi \\ \text{and}\quad 1.125\pi\quad \text{ is at Q3} \\ \\ \frac{13\pi}{6}=2.167\pi \\ Subtract\quad 2\pi \\ 2.167\pi-2\pi=0.167\pi\Rightarrow Q1 \end{gathered}[/tex]The first three answers are :
Q2, Q3 and Q1
For the second set, we have negative angles.
The range of negative angles will be the reversal of the positive angles.
This will be :
[tex]\begin{gathered} Q1\colon\text{From}\quad -1.5\pi\quad to\quad -2\pi \\ Q2\colon\text{From}\quad -1.0\pi\quad to\quad -1.5\pi \\ Q3\colon\text{From}\quad -0.5\pi\quad to\quad -1.0\pi \\ Q4\colon\text{From}\quad -0\pi\quad to\quad -0.5\pi \end{gathered}[/tex]The following angles are :
[tex]\begin{gathered} -\frac{35\pi}{4}=-8.75\pi \\ \text{Add four}\quad 2\pi \\ -8.75+4(2\pi)=-0.75\pi \\ -0.75\pi\Rightarrow Q3 \\ \\ -\frac{5\pi}{6}=-0.83\pi\Rightarrow Q3 \\ \\ -\frac{5\pi}{11}=-0.45\pi\Rightarrow Q4 \end{gathered}[/tex]The last three answers are :
Q3, Q3 and Q4
To summarized :
[tex]\begin{gathered} Q1\colon\frac{13\pi}{6} \\ Q2\colon\frac{3\pi}{4} \\ Q3\colon\frac{57\pi}{8},\quad -\frac{35\pi}{4},\quad -\frac{5\pi}{6} \\ Q4\colon-\frac{5\pi}{11} \end{gathered}[/tex]2/9x20 as a fraction
Answer:
40/9 OR 4 4/9
Step-by-step explanation:
2/9 x 20 = 2*20/9 = 40/9
3.13 geom Which triangle congruence postulate or theorem proves that these triangles are congruent?
The AAS triangle congruence postulate proves that these triangles are congruent .
In the question,
two triangles are given that are triangle KLM and triangle XYZ .
Consider the triangle KLM and triangle XYZ .
we can see that
(i) angle L = angle Y = angle 1 .....given in the figure
(ii) angle m = angle Z = angle 2 .... given in the figure
(iii) side KM = side XZ ....given in the figure
From the above three statements we conclude that
ΔKLM ≅ ΔXYZ
both the triangles KLM and XYZ are congruent by AAS Congruence Postulate .
Therefore , The AAS triangle congruence postulate proves that these triangles are congruent .
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slove the equation 4c + 7 = 23
We need to solve the expression:
[tex]4c+7=23[/tex]The first step is to subtract "7" on both sides.
[tex]\begin{gathered} 4c+7-7=23-7 \\ 4c=16 \end{gathered}[/tex]Then we need to divide both sides by 4.
[tex]\begin{gathered} \frac{4c}{4}=\frac{16}{4} \\ c=4 \end{gathered}[/tex]The result of the equation is "c=4".
if i did
what would i get?
?
be more specific :)
can you help me find BD. under the letter A the number is 25°
arc BD is 25°
Explanation:We would apply the secant-secant theorem:
[tex]\begin{gathered} \angle A\text{ =}\frac{large\text{ arc - small arc}}{2} \\ \angle A\text{ =}\frac{arc\text{ CE - arc BD}}{2} \end{gathered}[/tex]angle A = ∠A =25°
arc BD =?
arc CE = 100°
[tex]\begin{gathered} 25\text{ = }\frac{100-arc\text{ BD}}{2} \\ \text{cross multiply:} \\ 2(25)\text{ = 100 - arc BD} \end{gathered}[/tex][tex]\begin{gathered} 50\text{ = 100 - arc BD} \\ \text{subtract 100 from both sides:} \\ 50\text{ - 100 = 100 - 100 - arc BD} \\ -50\text{ = - arc BD} \end{gathered}[/tex][tex]\begin{gathered} \text{DIvide both sides by -1:} \\ \frac{-50}{-1\text{ }}=\frac{-arc\text{ BD}}{-1} \\ \text{arc BD = 50}\degree \end{gathered}[/tex]There are two integers that
multiply to -45 and combine to -4. Find
the two integers, then the LARGER
integer is your answer for this question.
Answer:
5
Step-by-step explanation:
-9 × 5 = -45
-9 + 5 = -4
5 is greater than -9, therefore 5 is the answer
is 6(2x-7)-3=12x-21 a no solution one solution or infinitely
Step-by-step explanation:
let's do the operations :
6(2x - 7) - 3 = 12x - 21
12x - 42 - 3 = 12x - 21
-45 = -21
that is never true, no matter what values for x we come up with.
and therefore, there is no solution.
EASY POINTS WILL GIVE BRAINLSIT TO BEST ASNWER HELP!!
write the slope intercept form of an equation though given points
through (3,-5) and (1,3)
Inscribed angles, I’m being asked for a, and b but I don’t understand this question
Given the figure of a circle.
There are 3 arcs with the following measures: a, 100, and 136
the sum of the measures of the arcs = 360
So, we can write the following equation:
[tex]a+100+136=360[/tex]Solve the equation to find (a):
[tex]\begin{gathered} a+236=360 \\ a=360-236=124 \end{gathered}[/tex]The angle (b) is the Inscribed angle opposite the arc (a)
[tex]b=\frac{1}{2}a=\frac{1}{2}*124=62[/tex]So, the answer will be:
[tex]\begin{gathered} a=124 \\ b=62 \end{gathered}[/tex]Given the lengths of the sides of a triangle, determine if it is an acute, anobtuse, or a right triangle.
Use the Pythagorean theorem to determine if the triangle is acute, obtuse or right triangle.
[tex]\begin{gathered} a^2+b^2=c^2 \\ \text{where} \\ c\text{ is the longest side of the triangle} \\ a\text{ and }b\text{ are the other 2 sides} \end{gathered}[/tex][tex]\begin{gathered} a^2+b^2=c^2 \\ (18)^2+(29)^2\questeq(46)^2 \\ 324+841\questeq2116 \\ 1165\questeq2116 \\ 1165<2116 \end{gathered}[/tex][tex]\begin{gathered} \text{IF} \\ a^2+b^2c^2 \\ \text{THEN, the triangle is an acute triangle} \\ \\ \text{IF} \\ a^2+b^2=c^2 \\ \text{THEN, the triangle is a right triangle} \end{gathered}[/tex]Since the sum of the square of the side of the two angles is less than the square of the longest side, then given the length of a triangle 18-29-46, the triangle is an obtuse triangle.
Find the slope (-19,12) (-9,1)
Answer:
m= -11/10
Step-by-step explanation:
Refer to formula m= y2-y1
x2-x1
1-12 = -11 (negative bc 1 comes first but is less than 12.)
Think of it as -12+1 it would be -11 going towards 0.
-9--19 = 10