The tree diagram below represents the relationships between the sets and subsets of real numbers. Real Numbers Rational Numbers {..., V2, e, , ...) ? Non-integer Rational Numbers {0, 1, 2, 3, ---) Whole Number Opposites Which group of numbers could replace the question mark in the tree diagram

Answers

Answer 1

The diagram starts with Real Numbers which comprehend all numbers except for complex numbers.

The second level is formed by rational numbers and irrational numbers.

The third level is formed by subsets of rational numbers non-integers rational numbers and integers rational numbers.

Therefore, the right answer is C. -7, 8, -4, since these numbers are rational and integers.

Related Questions

A train is traveling at a constant speed of 105 mph how many feet does a travel in three seconds remember that 1 mile is 5280 feet

Answers

We are given that a train is traveling at the following constant speed:

[tex]v=\frac{105\text{ miles}}{hour}[/tex]

We are asked to determine the distance after 3 seconds. To do that, let's remember that speed is the ratio between distance and time, that is:

[tex]v=\frac{d}{t}[/tex]

Where:

[tex]\begin{gathered} d=\text{ distance} \\ t=\text{ time} \end{gathered}[/tex]

Since we want to determine the distance we will multiply both sides of the equation by "t":

[tex]vt=d[/tex]

Now, we substitute the values:

[tex]\frac{105\text{ miles}}{hour}\times(3s)=d[/tex]

Since the velocity is given per unit of hour, we need to convert the 3 seconds into hours. We do that using the following conversion factor:

[tex]1\text{hour}=3600s[/tex]

Now we multiply the time by the conversion factor:

[tex]3s\times\frac{1h}{3600s}=\frac{1}{1200}h[/tex]

Now we substitute in the formula for the distance:

[tex]\frac{105\text{ miles}}{hour}\times(\frac{1}{1200}hour)=d[/tex]

Solving the operations:

[tex]\frac{7}{80}miles=d[/tex]

Now, we convert the miles into feet using the given conversion factor:

[tex]1\text{mile}=5280\text{feet}[/tex]

Now, we multiply by the conversion factor:

[tex]d=\frac{7}{80}\text{miles}\times\frac{5280feet}{1mile}[/tex]

Solving the operations:

[tex]d=462feet[/tex]

Therefore, the distance is 462 feet.

Person above is correct

(-3x² + 6x - 12) + (5x + 9) is equivalent to expression

Answers

[tex]\begin{gathered} \mleft(-3x^2+6x-12\mright)+(5x+9) \\ =-3x^{2}+6x-12+5x+9 \\ =-3x^{2}+11x-3 \end{gathered}[/tex]

Find a best-fit linear model for the following data:xy−3196−2139−1820251−322−893−146y = −57xy = 57xy = 57x + 25y = −57x + 25

Answers

Explanation

We are given a set of x and y values in the table

To compute the best-fit model for the data, we will use the graphing calculator

From the graph above, we have the function to be

[tex]y=-57x+25[/tex]

Thus, the answer is y= -57x +25

Can you please help me out with a question

Answers

To find the point S we first need to find the equation of the circle which is given by:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where (h,k) is the center and r is the radius.

In this case we don't have the radius but we know that the radius is the distance between the center and any point on the circle, then the radius is equal to the distance:

[tex]\begin{gathered} r=d(A,R)=\sqrt[]{(5-3)^2+(4-(-1))^2} \\ =\sqrt[]{4+25} \\ =\sqrt[]{29} \end{gathered}[/tex]

hence the equation of the circle is:

[tex](x-3)^2+(y+1)^2=29[/tex]

Now that we have this equation we need to determine which of the options given fullfil the equation. From the options given we conclude that the only point that fullfils the equation is the point D, this come from the fact that:

[tex]\begin{gathered} (1-3)^2+(-6+1)^2=29 \\ 4+25=29 \\ 29=29 \end{gathered}[/tex]

Therefore this point is in the circle. Therefore we conclude that the coordinates of point D are (1,-6) and the answer is D.

This can be seen in the graph below:

b Exit Ticket COS 28 = C 12 tan 28 = b с 12 28 b Download image X

Answers

Answer

b = 22.6 units

c = 25.6 units

Explanation

In a right angle triangle, the side opposite the right angle is the Hypotenuse, the side opposite the given angle that is non-right angle is the Opposite and the remaining side is the Adjacent.

For this question,

Hypotenuse = c

Opposite = 12

Adjacent = b

Trignometric ratios can then be used to find b and c.

CAH and TOA

Cos 28° = (Adj/Hyp)

Cos 28° = (b/c)

Tan 28° = (Opp/Adj)

Tan 28° = (12/b)

Cross multiply

b = 12/(Tan 28°)

b = 12/0.5317

b = 22.57

We can then solve for c

Cos 28° = (b/c)

Cos 28° = (22.57/c)

Cross multiply

c = (22.57/Cos 28°)

c = (22.57/0.8829)

c = 25.56 units

Hope this Helps!!!

Prove #8Given: PR congruent to TR angle P is congruent to angle T

Answers

[tex]PR\cong TR[/tex]

Reason: Given

[tex]\angle P\cong\angle T[/tex]

Reason: Given

[tex]m\angle PRQ\cong m\angle SRT[/tex]

Reason: Definition of Vertical angles

If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent by ASA (Angle-Side-Angle).

With the enthusiasm for statistics at an all-time high, students were found sprinting from their vehicle to the classroom just to be the first person to grab a seat. The times of the students were recorded (in seconds) and given in the stemplot below.What is the 9th fastest time a student took to go from his/her vehicle to a seat in the classroom? Make sure to use labels and avoid the use of abbreviations

Answers

Answer:

The 9th fastest time is 28 seconds

Explanation:

We have been given a stem plot diagram of the time it took the students to grab a seat.

We need to find the 9th fastest time

To do this, we first need to list out the time in seconds:

13, 14, 15, 19, 19

21, 27, 27, 28

32

45, 49, 49

Since the right side is empty, there is no list of 50 plus

62, 62

combining the list (all in seconds):

13, 14, 15, 19, 19, 21, 27, 27, 28, 32, 45, 49, 49, 62, 62

The lower the number, the faster the time. Since the list is ordered in ascending order, we will count to the 9th place

The ninth place on the list = 28

The 9th fastest time a student took to go from his/her vehicle to a seat in the classroom is 28 seconds

I need help with math

Answers

a)

3000x - 2000 = 10 000

Add 2000 to both-side of the equation

3000x - 2000 + 2000 = 10 000 + 2000

3000x = 12000

Divide both-side of the equation by 3000

3000x/3000 = 12000/3000

x = 4

b) -2x/3

[tex]\frac{-2x}{3}-\frac{x}{7}=\text{ 17}[/tex]

Multiply through the equation by 21

[tex]21(\frac{-2x}{3})-21(\frac{x}{7})=\text{ 17(21)}[/tex][tex]7(-2x)\text{ - 3x =357}[/tex]

-14x - 3x = 357

-17x = 357

Divide both-side of the equation by -17

x = -21

c)

[tex]\frac{5}{2}x-\frac{1}{3}=\text{ 13}[/tex]

Add 1/3 to both-side of the equation

[tex]\frac{5x}{2}=13\text{ +}\frac{1}{3}[/tex][tex]\frac{5x}{2}=\text{ }\frac{39+1}{3}[/tex]

[tex]\frac{5x}{2}=\frac{40}{3}[/tex]

cross-multiply

15x = 80

Divide both-side of the equation by 15

x= 5.33

d)

[tex]\frac{3}{10}+\frac{2x}{5}=\frac{1}{2}[/tex]

multiply through the equation by 10

[tex]10(\frac{3}{10})+10(\frac{2x}{5})=10(\frac{1}{2})[/tex]

3 + 2(2x) = 5

3 + 4x = 5

subtract 3 from both-si

Use prime factorization to reduce each fraction 1. 22/165 2. 35/210

Answers

Lets find the prime factorization of 22, 165, 35 and 210. Prime factorization of a number is breaking a number down into the set of prime numbers which multiply together to result in the original number.

The prime factorization of the number 22 is:

[tex]22=2\times11[/tex]

Similarly, for 165, 35 and 210 we have

[tex]\begin{gathered} 165=3\times5\times11 \\ 35=5\times7 \\ 210=2\times3\times5\times7 \end{gathered}[/tex]

Then, we can solve the given questions.

Question 1.

[tex]\frac{22}{165}=\frac{2\times11}{3\times5\times11}[/tex]

so we can cancel out the number 11 and get

[tex]\frac{22}{165}=\frac{2}{3\times5}=\frac{2}{15}[/tex]

Then, the answer is

[tex]\frac{2}{15}[/tex]

Question 2.

[tex]\frac{35}{210}=\frac{5\times7}{2\times3\times5\times7}[/tex]

and we can cancel out the number 5 and 7, then we obtain

[tex]\frac{35}{210}=\frac{1}{2\times3}[/tex]

then, the answer is

[tex]\frac{1}{6}[/tex]

At Fry's supermarket, each 12-1b bag of apples costs $4. Write an equation to represent the relationship between the number of pounds of apples, p, and cost, c I

Answers

if a 12 lb bag costs $4, then a 1 lb bag costs $4/12, which is equal to $1/3 dollars, so if we let p be the number of pounds that we are going to buy and c the amount that we must pay

[tex]c=\frac{1}{3}p[/tex]

that is the relation between c and p

Scooby needs to ship some DVDs. He has 16 comedy movies, 12 scary movies and 8 action movies. He can pack only one type of DVD in each box and he must pack the same number of DVDs in each box. What is the greatest number of DVDs Scooby can pack in each box?A.2B.4C.6D.8

Answers

He has 16 comedy movies, 12 scary movies and 8 action movies.

He can pack only one type of DVD in each box and he must pack the same number of DVDs in each box

So, we need to find the greatest common factor between 16 , 12 and 8

16 = 2 * 2 * 2 * 2

12 = 2 * 2 * * 3

8 = 2 * 2 * 2

---------------------------------

2 * 2 = 4

So,

The greatest number of DVDs Scooby can pack in each box = 2 * 2 = 4

The answer is option B. 4

----------------------------------------------------------

More explanations :

So, he will pack 16 comedy movies at 4 packs, each pack has 4 DVDs

And he will pack 12 scary movies at 3 packs, each pack has 4 DVDs

And he will pack 8 action movies at 2 packs, each pack has 4 DVDs

So, the total number of packs = 4 + 3 + 2 = 9 packs

Find the probability of getting a 1, 5, or 6 when you roll a standard six-sided die.Select the correct answer below:1/61/31/22/35/6

Answers

Step 1

Write out the expression for the probability of an event occurring

[tex]Pr(\text{event occurring) = }\frac{number\text{ of required outcomes}}{\text{Total number of outcomes}}[/tex]

Where,

Total of required outcomes= 6

Step 2

Find the probability of getting a 1

[tex]Pr(1)=\text{ }\frac{1}{6}[/tex]

Step 3

Find the probability of getting a 5

[tex]Pr(5)\text{ =}\frac{1}{6}[/tex]

Step 4

Find the probability of getting a 6

[tex]Pr(6)=\frac{1}{6}[/tex]

Step 4

Find the probability of getting a 1,5 or 6

[tex]Pr(1,5\text{ or 6)=Pr}(1)+Pr(5)+Pr(6)_{}[/tex][tex]\begin{gathered} Pr(1,5\text{ or 6) = }\frac{1}{6}+\frac{1}{6}+\frac{1}{6} \\ Pr(1,5\text{ or 6) = }\frac{1}{2} \end{gathered}[/tex]

Hence, the probability of getting a 1, 5 or 6 when you roll a standard six-sided die = 1/2

The markings on the number line are evently spaced. Label the other markings on the number line. + + А B C -30 0 F 45 A= B = C = D = E = F=can someone please tell me the answers

Answers

The points are evenly spaced at a distance of 15 units between each other, then when we go to the right side of the graph from 0 we increase 15 units until we reach the point E, 15 units further we get to the point F, then we have the following labels:

E = 15

F = 15 + 15 = 30

As we got the left side from 0, we subtract 15 units for each marking, then we get:

D = 0 -15 = -15

C = -30 -15 = -45

B = -45 - 15 = -60

A = -60 - 15

Write a equivalent unit rate to running 5/4 a mile in 9 minutes

Answers

To determine the unit rate to running 5/4 a mile in 9 minutes you have to determine the distance in miles run in one minute.

You can use corss multiplication to do the calculation:

9min____5/4miles

1min_____xmiles

[tex]\begin{gathered} \frac{\frac{5}{4}}{9}=\frac{x}{1} \\ x=\frac{5}{36} \end{gathered}[/tex]

The unite rate is 5/36miles/minute, expressed as a decimal value is 0.14miles/min

2 by 6 rectangle is inscribed in circle 5 by 6 rectangle is inscribed in circle 2 by 15 rectangle is inscribed in circle 1 by 12 rectangle is inscribed in circle what is the circumference?

Answers

21:51

it seems that your questions has multiple questions in it. Unfortunately, the tutoring app is meant to answer only one problem per session. So, I encourage you to start another session with your the remainder of the questionsk, so one of my colleague can help you out.

can you see what I'm writing?

Which problem could be solved with the expression 5 (2 + 4) = 6?Choose 1 answer:Hayden made 2 bracelets before school and 4 after school each day for 5 days. Then he split thebracelets into 6 equal groups. How many bracelets did Hayden have in each group?(вShadi is building a new back deck. He puts 2 nails and 4 screws in each board. He did this to 5boards. How many total screws and nails did he use?Khai, the dog, ate 2 bones on Monday, 4 bones on Tuesday and 6 bones on Wednesday. OnThursday, she ate 5 times more bones than the other days combined. How many bones did Khai eaton Thursday?Stuck? Review related articles/videos or use a hint.Report a problem

Answers

Let us attempt to solve the options to check which one will give the expression

[tex]5\times(2+4)\div6[/tex]

OPTION A:

If Hayden makes 2 bracelets before school and 4 after school daily, then the bracelets she makes daily is gotten by

[tex]2+4[/tex]

In 5 days, the number of bracelets will be the expression above multiplied by 5:

[tex]5\times(2+4)[/tex]

If she breaks the total bracelets into 6 groups, this means that we divide the expression above by 6:

[tex]5\times(2+4)\div6[/tex]

This tallies with the expression in the question.

Hence, OPTION A is correct.

I am confused. Please help. Give answer options and simple explanation. Thanks!

Answers

Given the functions

[tex]\begin{gathered} f(x)=2x^2+4x-5 \\ g(x)=6x^3-2x^2+3 \end{gathered}[/tex][tex]\begin{gathered} (f-g)(x)=f(x)-g(x) \\ =2x^2+4x-5-(6x^3-2x^2+3) \\ =2x^2+4x-5-6x^3+2x^2-3 \\ =-6x^3+2x^2+2x^2+4x-5-3 \\ =-6x^3+4x^2+4x-8 \end{gathered}[/tex]

The final answer is OPTION C

In triangle ABC, angle A is a right angle. What are possible measurements for B & C?

Answers

Given the triangle ABC.

Angle A is a right angle which equals 90 degree.

And sum of angles in a triangle equals 180 degree.

[tex]\begin{gathered} A+B+C=180^0 \\ 90^0+B+C=180^0 \\ B+C=180^0-90^0 \\ B+C=90^0 \end{gathered}[/tex]

So, the possible measurement of B and C must be the ones who's sum is 90 degree.

[tex]\begin{gathered} 40\text{ \& 50 }\rightarrow40+50=90 \\ 30\text{ \& 60}\rightarrow30+60=90 \\ 45\text{ \& 45}\rightarrow45+45=90 \\ 80\text{ \& 30}\rightarrow80+30=110 \\ 60\text{ \& 40}\rightarrow60+40=100 \end{gathered}[/tex]

Therefore, the ones whose sum equals 90 degree are the answers;

[tex]\begin{gathered} 40\text{ \& 50} \\ 30\text{ \& 60} \\ 45\text{ \& 45} \end{gathered}[/tex]

3(2x - 5) – 4x > 7x + 10.Please help

Answers

EXPLANATION.

To solve the inequality we must follow some steps:

1.1.the number 3 must multiply the values ​​that are inside the parentheses

need answer with steps[tex](7 + 9i) + ( - 5i)[/tex]

Answers

Gy, this is the solution:

(7 + 9i) + ( - 5i)

Solving the parenthesis:

7 + 9i - 5i

7 + 4i

Can you please throughly explain this question. I don't get it.

Answers

In graphing y > 2x - 7, a dashed line is used.

Answer: True

Explanation

Whenever we graph > or < , the boundary line is not inclusive of the range of solutions. Hence, we use a dashed line on the boundary.

On the other hand, whenever we have the inequality <= or >= , the

answer: true

explanation: my teacher just did it

Solve the equation.5/6=1/3+d

Answers

Solving a linear equation

We have the following equation

[tex]\begin{gathered} \frac{5}{6}=\frac{1}{3}+d \\ \end{gathered}[/tex]

We substract 1/3 each side:

[tex]\begin{gathered} -\frac{1}{3}+\frac{5}{6}=-\frac{1}{3}+\frac{1}{3}+d \\ -\frac{1}{3}+\frac{5}{6}=0+d \\ -\frac{1}{3}+\frac{5}{6}=d \\ \end{gathered}[/tex]

We multiply each side of the fraction 1/3 by 2:

[tex]-\frac{1}{3}=-\frac{1\cdot2}{3\cdot2}=-\frac{2}{6}[/tex]

Then

[tex]\begin{gathered} -\frac{1}{3}+\frac{5}{6}=d \\ -\frac{2}{6}+\frac{5}{6}=d \\ \frac{3}{6}=\frac{1}{2}=d \end{gathered}[/tex]Answer: d = 1/2

john ran at a pace of 3.5 miles per hr for a distance of 10.5 miles. how many minutes did it take them to run 10.5miles? use the distance formula: d= rt to where d is total distance, r is rate and t is time

Answers

d=rt

divide both-side of the equation by r

t =d/r

distance = 10.5 miles

we will go ahead and find the rate r

r = 3.5/60

r=0.05833

substituting into t= d/r

t = 10.5 / 0.05833

t=180 minutes

Last year, Jenny opened an investment account with $7400. At the end of the year, the amount in the account had decreased by6.5%. How much is this decrease in dollars? How much money was in her account at the end of last year?

Answers

if the decreasing amount is 6.5% the r in our decay function will be:

[tex]1-0.065=0.935[/tex]

and in one yeat t=1 so the equation will be:

[tex]\begin{gathered} y=7400(0.936)^1 \\ y=6925.4 \end{gathered}[/tex]

Nathan and Tony hiked in the woods yesterday and came home with poison ivy. Tony has 5 times as many spots as Nathan. How many spots does Nathan have, x? Which table represents this situation?

Answers

Here, we want to get the correct equation and select the correct table

From the question, we have it that Tony has 5 times what Nathan had

Hence, given that Nathan has x, Tony has 5 times this and we have it as;

[tex]5\times x\text{ = 5x}[/tex]

What this mean is that the right column of the table will be 5 times what is on the left column

Hence, the correct table here is the table with the heading 5x

Find bc if your answer is not an integer, leave it in simplest radical form

Answers

Hello!

We know that this is a right triangle and the angle C is 45º.

Knowing it, we have:

Considering the information above, we must use the sine of 45º to calculate the value of side BC, look:

[tex]\sin(45\degree)=\frac{\mathrm{opposite}}{\mathrm{hypotenuse}}[/tex]

As we know, the sine of 45º is:

[tex]\sin(45)=\frac{\sqrt{2}}{2}[/tex]

Let's replace all the values in the formula:

[tex]\begin{gathered} \sin(45\operatorname{\degree})=\frac{\mathrm{oppos\imaginaryI te}}{\mathrm{hypotenuse}} \\ \\ \dfrac{\sqrt{2}}{2}=\frac{10}{\mathrm{BC}} \\ \\ \mathrm{BC}\sqrt{2}=10\cdot2 \\ \mathrm{BC}\sqrt{2}=20 \\ BC=\frac{20}{\sqrt{2}} \\ \\ BC=\frac{20\cdot\sqrt{2}}{\sqrt{2}\cdot\sqrt{2}}=\frac{20\sqrt{2}}{\sqrt{4}}=\frac{20\sqrt{2}}{2}=\boxed{10\sqrt{2}\text{ ft}} \end{gathered}[/tex]

Answer:

Alternative B.

Find Sec A and Cot B exactly if a=8 and b=7

Answers

The given triangle is right angle triangle with side a = 8 and b 7

Apply pythagoras theorem for the side c;

In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides.

Hypotenuse² = Perpendicular² + Base²

Here, perpendicular, a =8 and Base b = 7

[tex]\begin{gathered} c^{2}=a^{2}+b^{2} \\ c^{2}=8^{2}+7^{2} \\ c^2=113 \\ c=\sqrt[]{113} \end{gathered}[/tex]

The trignometric ratio for sec of an angle define as the ratio of the hypotenuse to the side adjacent to a given angle in a right triangle.

[tex]\begin{gathered} \sec A=\frac{Hypotenuse}{Adjacent\text{ side of angle A}} \\ \sec A=\frac{c}{b} \\ \sec A=\frac{\sqrt[]{113}}{7} \end{gathered}[/tex]

The trignometric ratio for cosine of angle define as the ratio of the adjacent side to the the opposite side of the angle,

[tex]\begin{gathered} CotB=\frac{\text{Adjacent side to angle B}}{\text{Opposite side to angle B}} \\ CotB=\frac{a}{b} \\ CotB=\frac{8}{7} \end{gathered}[/tex]

Answer; a)

[tex]\text{SecA}=\frac{\sqrt[]{113}}{7},\cot B=\frac{8}{7}[/tex]

Elizabeth is signing up for a gym membership with a one-time fee to join and then a monthly fee to remain a member. The total cost of the gym membership over t months is given by the equation C = 25t + 100. What is the y-intercept of the equation and what is its interpretation in the context of the problem?

Answers

The y-intercept of the equation is 100

For this problema the y-intercep is equal to the one-time fee

if m<10=77, m<7=47 and m<16=139, find the measure of the missing angle m<15=?

Answers

Step 1: Quoting the theorem of a straight line

The theorem of a straight line says Total angles on a straight line is equal to 180°.

Step 2:

m<16 and m<15 are angles on a straight line from the diagram given,

[tex]\begin{gathered} \text{where} \\ m<16=139^0 \\ m<15=\text{?} \\ \text{therefore,} \\ m<16+m<15=180^0 \\ 139^0+m<15=180^0 \\ \text{Collecting like terms} \\ m<15=180^0-139^0 \\ m<15=41^0 \end{gathered}[/tex]

Hence the value of m<15= 41°.

An angle measures 83∘. Find a. its supplement and b. its complement.

Answers

Let

A = Angle (83°)

S = Supplement of A

C = Complement of A.

1) Finding the Supplement of A.

Supplementary angles are the angles whose sum is equal to 180°.

Then,

A + S = 180

Substituting A, we can find S.

83 + S = 180

S = 180 - 83

S = 97°

2) Finding the Complement of A.

Complementary angles are the angles whose sum is equal to 90°.

Then,

A + C = 90

83 + C = 90

C = 90 - 83

C = 7 °C.

Answer:

Supplement = 97 °C

Complement = 7 °C

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