The table below represents a linear function f(x) and the equation represents a function (x)f(x)-1-12g(x)09(x) = 2x + 610Part A: Write a sentence to compare the slope of the two functions and show the steps you used to determine the slope of f(x) and g(x), (6 points)Part B: Which function has a greater y-intercept? Justify your answer (4 points)I
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Answer:
(a)The slope of f(x) is greater than the slope of g(x).
(b)g(x) has a greater y-intercept.
Explanation:
Part A
From the table of f(x), we have the pairs:
(-1,-12),(0,-6) and (1,0).
First, we find the slope of f(x).
[tex]\begin{gathered} \text{Slope}=\frac{Change\text{ in y-axis}}{Change\text{ in x-axis}} \\ =\frac{-6-0}{0-1} \\ =-\frac{6}{-1} \\ =6 \end{gathered}[/tex]Given the function g(x) defined as follows:
[tex]g(x)=2x+6[/tex]Comparing g(x) with the slope-intercept form (y=mx+b), the slope of g(x) is m=2.
Sentence: The slope of f(x) is greater than the slope of g(x).
Part B
The y-intercept is the point in a function where x=0.
In f(x), When x=0, f(x)=-6
• The y-intercept of f(x) is -6.
Comparing g(x) with the slope-intercept form (y=mx+b), the y-intercept of g(x), b=6.
Therefore, g(x) has a greater y-intercept.
Related Questions
Yael used to have a square garage with 222 ft2 of floor space. She recently built an addition to it. The garage is still a square, but now it has 50% more floor space. What was the length of one side of the garage originally? What is the length of one side of the garage now
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• The length of one side of the garage originally is approximately 14.9 ft
,• The length of one side of the garage now is approximately 18.3 ft
Explanation:Old garage = 222 sq. ft
New garage has 50% more floor space.
50% of 222 = 111
Therefore, the new garage is (222 + 111) sq. ft = 333 sq. ft
Since the garage is square,
one side of the old garage is:
[tex]\sqrt[]{222}=14.9\text{ ft}[/tex]One side of the new garage is:
[tex]\sqrt[]{333}=18.3\text{ ft}[/tex]Determine whether each sequence is arithmetic. If so, identify the common difference. -34, -28, -22, -16
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Answer:
Question:
Determine whether each sequence is arithmetic. If so, identify the common difference. -34, -28, -22, -16
The numbers are given below as
[tex]-34,-28,-22,-16[/tex]Concept:
Define an arithmetic sequence
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
The general form of an arithmetic sequence is given below as
[tex]\begin{gathered} a_n=a_1+(n-1)d \\ a_1=first\text{ }term \\ n=number\text{ of terms} \\ d=common\text{ difference} \end{gathered}[/tex]To check if they have a common difference, we will use the formulas below
[tex]\begin{gathered} d=a_2-a_1=-28-(-34)=-28+34=6 \\ d=a_3-a_2=-22-(-28)=-22+28=6 \\ d=a_4-a_3=-16-(-22)=-16+22=6 \end{gathered}[/tex]Hence,
Since the sequence has a common difference,
It is therefore an ARITHMETIC SEQUENCE
Their common difference is
[tex]\Rightarrow6[/tex]r-9<-25. on a graph bar
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r-9<-25 is equal to solution: [tex]$\quad R < -16$[/tex], Interval Notation: [tex]$\quad(-\infty,-16)$[/tex]. The graph is shown in attachement.
R-9<-25
Add 9 to both sides
R-9+9<-25+9
Simplify
R<-16
A graph is simply an orderly representation of data. It aids us in comprehending the info. The numerical information gathered through observation is referred to as data.
Data is derived from the Latin term Datum, which meaning "anything supplied."
Data is collected continuously through observation when a research question is formulated. It is then organized, summarized, categorised, and graphically shown.
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15. WORK REQUIRED: Given : ZA = 2D and BA – ED. What congruent sides would allow us to use SAS to prove Triangle ABC is congruent to Triangle DEF? (write your answer in this form: WX=YZ with no spaces) NN TA Your answer This is a regulired question
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Let's begin by listing out the information given to us:
Both triangles have Line BD equal
[tex]BD=BD[/tex]Line AB equals Line CD
[tex]AB=CD[/tex]Angle A equals Angle C
[tex]m\angle A=m\angle C[/tex]Hence, Triangle ABD is congruent to Triangle CDB
Find the vbalie If K, and then write an equation to describee the direct variation.
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Given:
x = 9 and y = 6
Use the equation:
y = kx
Where y varies directly as x
K is the constant of proportionality.
Let's find the value of k:
[tex]\begin{gathered} y\text{ = kx} \\ \\ 6\text{ = 9k} \\ \\ \text{Divide both sides by 9:} \\ \frac{6}{9}=\frac{9k}{9} \\ \\ \frac{2}{3}=k \end{gathered}[/tex]k = ⅔
An equation to describe the direct variation is:
[tex]y\text{ = }\frac{2}{3}x[/tex]ANSWER:
[tex]undefined[/tex]Number 3.Light travels 1.9x10^5 kilometers per second.there are 6.4 x 10^5 seconds in one week .About how many kilometers does light travel.
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helloo
from the question given, we have some variables
[tex]\begin{gathered} \text{speed}=1.9\times10^5\operatorname{km}\text{ /s} \\ \text{time}=6.4\times10^5s \\ \text{distance}=x \end{gathered}[/tex]now the formula for speed is given as
[tex]\begin{gathered} \text{speed}=\frac{\text{distance}}{\text{time}} \\ 1.9\times10^5=\frac{x}{6.4\times10^5} \\ x=(1.9\times10^5)\times(6.4\times10^5) \\ x=1.22\times10^{11}\operatorname{km} \end{gathered}[/tex]If $4,780 is deposited in an account that pays 1.25% interest compounded annually, how much interest is in the account at the end of 8 years? A $5,279.44 B $500.44 C$ 478.00 D $499.44
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We can calculate the interest as the difference between the future and the present value of the investment:
[tex]I=FV-PV[/tex]The present value is $4780.
The annual interest rate is r=1.25/100=0.0125.
The number of years is 8, so n=8.
We can calculate the future value as:
[tex]\begin{gathered} FV=PV(1+r)^n \\ FV=4780\cdot(1+0.0125)^8 \\ FV=4780\cdot1.0125^8 \\ FV\approx4780\cdot1.1045 \\ FV\approx5279.44 \end{gathered}[/tex]Then, we can calculate the interest as:
[tex]I=FV-PV=5279.44-4780=499.44[/tex]Answer: D. $499.44
Please help me I don’t know how to do this
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Translations
One point located at (x,y), translated to the point (h,k) has been applied the rule:
T(x,y) -> (h,k)
And the translation changed the coordinates by ( h-x, k-y).
The point (4,-9) is mapped to (9,-14). The change is:
(9 - 4, -14 - (-9 ) = (5 , -5)
The rule of translation is:
T(x,y) -> (x + 5 , y -5)
If we translated the point (-9,-8) under the same rule:
T(-9,-8) -> (-9 + 5 , -8 -5)
T(-9,-8) -> ( -4 , -13)
The image of the point (-9,-8) is ( -4 , -13)
Rational and Irrational Numbers make up the____ system.
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We have the following:
Therefore, the answer is real numbers
1.) twenty-five and five hundred seventy-eight thousandths
2.) Six thousand one and one hundreadths
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Answer:
Here are the numbers:
1) 25.578
2) 6,001.01
u= ak - b solve for a
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To solve it for "a" is to isolate "a' in one side, by doing some algebraic operations.
U =ak -b
1) Let's rewrite it
-b+ak=u
2) Add b to both sides
-b +b +ak = u +b
ak = u+b
3) Divide both sides by k
[tex]\frac{ak}{k}=\frac{u+b}{k}[/tex]4) Finally, we have it for 'a':
[tex]a\text{ =}\frac{u}{k}\text{ + }\frac{b}{k}[/tex]express 0.004 in scientific notation
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We are asked to express 0.004 in scientific notation
The number 0.004 has the decimal point at the start, so we move this decimal point to the right until there is only one non-zero digit is left (4 in this case) and then count the number of times we moved.
[tex]0.0004=4\times10^{-3}[/tex]In this case, we moved 3 times so the exponent (power) is -3
The sign of exponent is negative when we move to the right (like in this case)
The sign of exponent is positive when we move to the left.
») A box has a length of 6 centimeters, a width of 4 centimeters, and a height of 5 centimeters. Jen filled the bottom layer of the box with 24 cubes. What is the volume of the box? 120 cubic centimeters 24 cubic centimeters 5 cm 4 cm 96 cubic centimeters 6 cm = 1 cubic centimeter 144 cubic centimeters
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We can find the volume of the box by multiplying the length, width and heigth.
We can write this as:
[tex]V=l\cdot w\cdot h=(6\operatorname{cm})\cdot(4\operatorname{cm})\cdot(5\operatorname{cm})=(24\operatorname{cm})(5\operatorname{cm})=120\operatorname{cm}^3[/tex]The base layer is 24 cm^3 (24 cubes of 1 cm^3) because its the volume of width 4 cm and length 6 cm, with a height of 1 cm (the height of the cube).
If we multiply the number of cubes, 24 of 1 cm^3, by the real height, that is 5 times 1 cm, we get: 24 cm^3 * 5 = 120 cm^3.
Answer: the box has a volume of 120 cm^3
For the following set of data, find the percentage of data within population standarddeviations of the mean, to the nearest percent.88, 92, 57, 62, 57, 56, 58, 57Copy Values for CalculatorOpen Statistics Calculator
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Answer: 100 %
Explanation:
The first step is to rearrange the numbes in ascending order. It becomes
56, 57, 57, 57, 58, 62, 88, 92
The next step is to calculate the population μ, mean.
μ = sum of terms/number of terms
From the information given
n = number of terms = 8
μ = (56 + 57 + 57 + 57 + 58 + 62 + 88 + 92)/8 = 65.875
μ = 65.875
The formula for calculating the population standard deviation, σ is
σ = √[Σ(x - μ)^2]/n
Σ(x - μ)^2/n = [(56 - 65.875)^2 + (57 - 65.875)^2 + (57 - 65.875)^2 + (57 - 65.875)^2 + (58 - 65.875)^2 + (62 - 65.875)^2 + (88 - 65.875)^2 + (92 - 65.875)^2)]/8 = 197.859375
σ = √197.859375
σ = 14.1
2 population standard deviations to the left of the mean = 65.875 - 2(14.1) = 37.675
2 population standard deviations to the rig tof the mean = 685875 -+2(14.1) == 94.075
Number of terms between 37.675 and 94.075 = 8
Thus,
the percentage of data within 2 population standard deviations of the mean
= 8/8 x 100 = 100%
An equilateral triangle is folded in half.IN60° 60°14 cm-4What is x, the height of the equilateral triangle?O 14V301407307
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An equilateral triangle is a triangle that has the same length on all its three sides. Therefore, we can say that:
Since the triangle is folded in half, then we can say that:
From this, we can solve "x" using the Pythagorean Theorem.
[tex]c^2=a^{2^{}}+b^2[/tex]where "c" = hypotenuse and "a" and "b" can be either of the remaining sides.
[tex]\begin{gathered} 14^2=7^2+x^2 \\ 196=49+x^2 \\ 196-49=49+x^2-49 \\ 147=x^2 \\ \sqrt[]{147}=\sqrt[]{x^2} \\ 7\sqrt[]{3}=x \end{gathered}[/tex]Therefore, the height of our equilateral triangle is 7√3. This is found in the third option.
A cylinder has a height of 10 ft and a volume of 25,456 ft^3.The radius of the cylinder is approximately ___ feet.Round your answer to the nearest whole number.
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From the question given, they provided us with the height,h = 10ft, and volume, V=25,456 cubic feet.
Thus, we have:
[tex]\begin{gathered} V=\pi\times r^2\times h \\ 25,456=\pi\times r^2\times10 \\ \frac{25,456}{10\pi}=r^2 \\ \text{Taking the value of }\pi\text{ as 3.142, we have:} \\ r^2=\frac{25,456}{10\times3.142} \\ r^2=810.1846 \\ r=\sqrt[]{810.1846} \\ r=28.46ft \end{gathered}[/tex]Hence, the radius of the cylinder is 28.46ft
please answer quickly I'm just trying to confirm my answer
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Given the following vector:
[tex]v=<-\sqrt{3},2\sqrt{3}>[/tex]The magnitude of the vector will be as follows:
[tex]||v||=\sqrt{(-\sqrt{3})^2+(2\sqrt{3})^2}=\sqrt{3+12}=\sqrt{15}[/tex]So, the answer will be option 2) ||v|| = √15
please finish this super fastWhat is the median travel time, in minutes? 21 24 29 36
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Given:
Required:
We need to find the median.
Explanation:
Recall that the vertical line that split the box in two is the median.
The vertical line that split the box in two is the median at 24 minutes.
The median is 24.
Final answer:
The median is 24.
46 = -6t - 8 what is t
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t=9,
1) Solving for t we have:
46 = -6t - 8 Add 8 to both sides
46+8 = -6t
54 = -6t Divide both sides by -6
9 = t Flipping it
t=9
2) So the Solution Set is S={9} for this equation.
Solve the following problems.a. After 6 points have been added to every score ina sample, the mean is found to be M=70 and thestandard deviation is s= 13. What were the valuesfor the mean and standard deviation for the originalsample?b. After every score in a sample is multiplied by 3, themean is found to be M=48 and the standard devia-tion is s=18. What were the values for the meanand standard deviation for the original sample?
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Original mean = 64
standand deviation = 13
Explanations:Let the value of of the originalmean be X. If after 6 points have been added to every score in a sample, the mean is found to be M = 70, then;
X + 6 = 70
Subtract 6 from both sides
X + 6 - 6 = 70 - 6
X = 70 - 6
X = 64
Hence the mean of the original sample will be 64.
The standard deviation of the data will remain unchanged since the distance from the mean will remain the same no matter the change in mean. Therefore the standard deviation of the sample will be 13.
CAN SOMEONE HELP WITH THIS QUESTION?✨
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The given function's f(t) = (t - 4)(t + 1)(t - 7), f-intercept is f(t) = 28 and the t-intercepts are t = - 1, 4, 7.
What are intercepts?A y-intercept, also known as a vertical intercept, is the location where the graph of a function or relation intersects the y-axis of the coordinate system in analytic geometry using the widely used convention that the horizontal axis represents a variable x and the vertical axis represents a variable y. Therefore, x = 0 is satisfied at these sites. The x-intercept and y-intercept are the points where a line crosses each axis.
An intercept is a location where an axis and a graph intersect. The x-intercept is the name given to this particular one.
Put t = 0 in the function f(t) = (t - 4)(t + 1)(t - 7)
f(t)= (0-4)(0+1)(0-7)
f(t) = (-4)(1)(-7)
f(t) = 28
So, the f-intercept is (0,28)
Put f(t) = 0 to find t- intercepts
0 = (t-4)(t+1)(t-7)
So, t - 4 = 0
t = 4
For t + 1 = 0
t = -1
For (t - 7) = 0
t = 7
So, the t intercepts are t = -1, 4, 7.
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6(__+x)-8(-3+8x) = 30-58xfill in the blank
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In this expression, we have the same value on the left side is equal to the same amount on the right side.
So, let's start operating it to simplify it
6(_+x) -8(-3+8x)=30-58x
6(_+x)+24-64x=30-58x
6( ) +6x +24 -64x =30 -58x
6( ) -58x+24=30-58x
6( )-58x +58x=30-24
6( ) =14 DIviding both sides by six
( ) =7/3
Testing:
6(7/3 +x) -8(-3+8x)=30-58x
14+6x +24 -64x =30-58x
38
Area of a cylinder: S = 2лr² + 2лrh; solve for h.
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The given equation for the area of a cylinder is:
S = 2πr² + 2лrh
Subtract 2πr² from both sides
S - 2πr² = 2πr² - 2πr² + 2лrh
S - 2πr² = 2лrh
Divide both sides 2лr
[tex]\begin{gathered} \frac{S-2\pi r^2}{2\pi r}=\frac{2\pi rh}{2\pi r} \\ \\ h=\frac{S-2\pi r^{2}}{2\pi r} \end{gathered}[/tex]Suppose 2' is a normally distributed random variable with ft = 10.3 and 0 = 3.8. For the following probability,draw an appropriate diagram, shade the appropriate region and then determine the value:P(9 <2 ≤ 14) = Note: Enter your answer up to 4 decimal places.
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GIVEN
The following values are given:
[tex]\begin{gathered} \mu=10.3 \\ \sigma=3.8 \end{gathered}[/tex]SOLUTION
The z-score for the x values 9 and 14 can be calculated using the formula:
[tex]z=\frac{x-\mu}{\sigma}[/tex]For x = 9:
[tex]\begin{gathered} z=\frac{9-10.3}{3.8} \\ z=-0.34 \end{gathered}[/tex]For x = 14:
[tex]\begin{gathered} z=\frac{14-10.3}{3.8} \\ z=0.97 \end{gathered}[/tex]The probability can be calculated as follows:
[tex]P(9\le x\le14)=Pr(-0.34The region that represents the solution is shown below:Therefore, the probability is given to be:
[tex]P(9\le x\le14)=0.4671[/tex]The probability is 0.4671.
In a music class of 20 students, there are 12 who play the Guitar (G), 7 who play the piano (P) and 4 who do not play any of his instruments.A) Represent the situation using a Venn diagram.B) What is the probability that a randomly selected student will play guitar and piano?C) What is the probability that a randomly selected student will play one of these two instruments?D) What is the probability that a randomly selected student will not play the piano?
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n(U) = 20
n(G) = 12
n(P) = 7
[tex]\text{ n(G u P)}^1=4[/tex]Let x represent students that play both instruments
n(PuG) = x
A. Venn diagram
B. What is the probability that a randomly selected student will play guitar and piano?
Firstly solve for x
12-x + x + 7-x + 4 = 20
23-x = 20
-x = 20 - 23
-x = -3
x = 3
Number of students that play guitar and piano = x = 3
Total students = 20
Probability that a randomly selected student will play guitar and piano = 3/20
C. What is the probability that a randomly selected student will play one of these two instruments?
[tex]\begin{gathered} \text{ = }\frac{12-x}{20}\text{ +}\frac{7-x}{20} \\ =\frac{12-3}{20}+\frac{7-3}{20} \\ =\frac{9}{20}+\frac{4}{20} \\ =\frac{13}{20} \end{gathered}[/tex]D. What is the probability that a randomly selected student will not play the piano?
Students who do not play piano are students that play guitar only and students who do not play any instrument
students that play guitar only = 12 -x = 12 -3 = 9 students
students who do not play any instrument = 4
Probability that a randomly selected student will not play the piano =
[tex]\frac{9}{20}+\frac{4}{20}\text{ = }\frac{13}{20}[/tex]
Find each probability of the events and place them in order
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Considering Box A,
Total number of pens = 3 + 5 = 8 pens
Probability of picking a purple (P) and black (B) pen is given below as,
[tex]\begin{gathered} P(P)=\frac{3}{8} \\ P(B)=\frac{5}{8} \end{gathered}[/tex]Considering Box B,
Total number of pens = 15 + 5 = 20 pens
Probability of picking a purple and black pen is given below as,
[tex]\begin{gathered} P(P)=\frac{15}{20} \\ P(B)=\frac{5}{20} \end{gathered}[/tex]For event 1, probability of choosing a red (R) pen from Box B is zero because there is no red pen in the Box.
Event 1 P(R) = 0
For event 2, probability of choosing a purple or black pen from Box A is,
[tex]P(P\text{ or B)=}\frac{3}{8}+\frac{5}{8}=\frac{3+5}{8}=\frac{8}{8}=1[/tex]Event 2 P(P or B) = 1
For event 3, probability of choosing a purple pen from Box A is,
[tex]P(P)=\frac{3}{8}[/tex]Event 3 (P) = 3/8
For event 4, probability of choosing a black pen from Box B is given below as,
[tex]P(B)=\frac{5}{20}=\frac{1}{4}[/tex]Event 4 P(B) = 1/4
Arranging each events from the least likely to the most likely is in the order below
[tex]\text{Event 1, Event 4, Event 3, Event 2}[/tex]Answer deduced above.
The sum of the two numbers is 133. Four times the smaller of the two numbers equals three times the greater number find the numbers using one variable.
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The Solution:
Let the two number be x and y133-x (
Such that:
[tex]\begin{gathered} x<133-x \\ x=small\text{ number} \\ 133-x=larger\text{ number} \end{gathered}[/tex]So,
[tex]\begin{gathered} 4x=3(133-x) \\ \end{gathered}[/tex]Solve for x:
[tex]\begin{gathered} 4x=399-3x \\ \text{ Collect the like terms.} \\ 4x+3x=399 \\ 7x=399 \end{gathered}[/tex]Divide both sides by 7.
[tex]x=\frac{399}{7}=57[/tex]Therefore, the correct nswers are:
57 and 76
Hi so some of the problems I don't know like I can't but I did do some problem by myself you can tell me whether it's correct
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The symmetric property of equality, if AB = YU. then YU = AB
As per the symmetric property of equality,
if AB = YU. then YU = AB
As per the symmetric property of congurence,
∠H ≅ ∠K then ∠K ≅ ∠H
As per the reflexive property of congurence,
∠PQR ≅ ∠PQR
As per the distibutive property, multiplying the sum of two or more term by a number produces the same result as when each term is multiplied individually by the number and the products are added together.
3(x - 1) = 3x - 3
As per the substitution property one value can replace another value in an expression or equation and the value will remain the same.
If LM = 7, EF + LM = NP
Then EF + 7 = NP
Therefore, the above bits are done as per the property mentioned.
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If V1 = (2,4) and V2 = (-1,5), then V1*V2is equal to which of the following? A. (-2,20) , B. 18 , C. 22 , D. (8,-5)
Answers
B. 18
Explanation
The dot product or scalar product is an algebraic operation that takes two equal-length sequences of numbers (usually coordinate vectors), and returns a single number
it is given by.
[tex]\begin{gathered} u=(u_x,u_y) \\ v=(v_{_x},v_y) \\ u\cdot v=(u_xv_x+u_yv_y) \end{gathered}[/tex]so, we can find the dot product by multiplying the corresponding values in each vector and adding them together
Step 1
get the dot product
let
[tex]\begin{gathered} v_1=(2,4) \\ v_2=(-1,5) \end{gathered}[/tex]then
[tex]\begin{gathered} v_1\cdot v_2=(2\cdot-1)+(4\cdot5) \\ v_1\cdot v_2=-2+20 \\ v_1\cdot v_2=18 \end{gathered}[/tex]therefore, the answer is
B. 18
I hope this helps you
SIMPLIFIED Uplift Summer Algebra 1 Final Assessment - Copy12 of 2012 of 20 ItemsQuestionColton solves -30=6(x-1) by dividing both sides by 6 first. Kaylee solves the same equation by using the Distributive Property first on the right side of the equation. Who is correct?
Answers
The method use by both students are correct. Hence the right answer to the question is OPTION D