We can rewrite the question as the probability of getting the event E is 23:77. Find the probability of getting the event not E.
The number 23:77 is a ratio and is it equivalent to:
[tex]\frac{23}{77}[/tex]To get the probability of the event not-E, we can proceed as follows:
[tex]1-\frac{23}{77}=\frac{77}{77}-\frac{23}{77}=\frac{53}{77}\approx0.7013[/tex]So the probability for the event not-E is about 53/77 or 0.7013 (or a little more than 70%).
- x - 8 = -4x - 23 Solve for x
x=-5
Explanation
[tex]-x-8=-4x-23[/tex]Step 1
solve for x means we have to find the value for x that makes the equality true, to do that we need to isolate x
then
to isolate x we can apply the addition property of equality,it states that If two expressions are equal to each other, and you add the same value to both sides of the equation, the equation will remain equal.
hence
Add 4x in both sides
[tex]\begin{gathered} -x-8=-4x-23 \\ -x-8+4x=-4x-23+4x \\ 3x-8=-23 \end{gathered}[/tex]Now, add 8 in both sides
[tex]\begin{gathered} 3x-8=-23 \\ 3x-8+8=-23+8 \\ 3x=-15 \end{gathered}[/tex]Step 2
now, we have a multiplication ( 3 multiplied by x), to isolate x we can apply the multiplication property,it says when you divide or multiply both sides of an equation by the same quantity, you still have equality
hence
divide both sides by 3
[tex]\begin{gathered} 3x=-15 \\ \frac{3x}{3}=\frac{-15}{3} \\ x=-5 \end{gathered}[/tex]therefore, the answer is
x=-5
I hope this helps you
Perform the operation. Write your answer in scientific notation. 7.86×10^9________3×10^4
Answer:
2.62 * 10^ 5
Explanation:
To perform the operation given we rewrite it as
[tex]\frac{7.86}{3}\times\frac{10^9}{10^4}^{}[/tex]Now,
[tex]\frac{7.86}{3}=2.62[/tex]and
[tex]\frac{10^9}{10^4}^{}=10^{9-4}=10^5[/tex]therefore,
[tex]\frac{7.86}{3}\times\frac{10^9}{10^4}^{}=2.62\times10^5[/tex]which is our answer!
what is the lcm of 25 and 37
SOLUTION:
Step 1:
In this question, we are given the question:
What is the lcm of 25 and 37?
Step 2:
From the question, we need to know the definition of LCM:
The least common multiple, lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by lcm(a, b), is the smallest positive integer that is divisible by both a and b
Step 3:
The details of the solution are as follows:
CONCLUSION:
The LCM of 25 and 37 =925
Which of the qqq-values satisfy the following inequality?6−3q≤16−3q≤16, minus, 3, q, is less than or equal to, 1Choose all answers that apply:Choose all answers that apply:(Choice A)Aq=0q=0q, equals, 0(Choice B)Bq=1q=1q, equals, 1(Choice C)Cq=2q=2q, equals, 2
Given -
6 - 3q ≤ 1
To Find -
The q-values that satisfy inequality =??w
Step-by-Step Explanation - ion
We will check for each of the given values;
A) q = 0
Putting q = 0, we get:
6 - 3(0) ≤ 1
6 ≤ 1
But, Six is greaterr than onee
So, this is the incorrect option.
B) q = 1
Putting q = 1, we get:
6 - 3(1) ≤ 1
3 ≤ 1
But, three is greater than one
So, this is the incorrect option.
C) q = 2
Putting q = 2, we get:
6 - 3(2) ≤ 1
0 ≤ 1
zero is less than one.
So, this is the correct option.
Final Answer -
Option (C) q = 2
Given the function g(x) = x2 – 2, find the range when the domain is {-2, -1, 1, 3} A. {-1, 2, 7} B. {-6, -3, 3, 11} C. {-7, -2, -1, 1} D. {-11, -3,3, 6}
The domain of the function is the values of x
Domain = {-2, -1, 1, 3}
We will substitute x by these values to find g(x)
g(x) is the range of the function
x = -2
[tex]g(-2)=(-2)^2-2=4-2=2[/tex]x = -1
[tex]g(-1)=(-1)^2-2=1-2=-1[/tex]x = 1
[tex]g(1)=(1)^2-2=1-2=-1[/tex]x = 3
[tex]g(3)=(3)^2-2=9-2=7[/tex]The range of the function is the values of g(x)
Range = {-1, 2, 7}
The answer is A
7. Solve 3(x-4)=-5 for x.
Explantion:
3(x-4) = -5
Expand the bracket:
3x -12 = -5
Collect like
the scale of a map say that 4 cm represents 5km what distance on the map in cm represents an actual distance of 10 km
We can do as follow s
centimeters km
4 5
x 10
which is the same as saying that 4 centimeters are 5km, so x centimeters are 10 km. We want to find the value of x. To do so, we use the fact that this is a proportion, so it must happen that
[tex]\frac{4}{5}\text{ = }\frac{x}{10}[/tex]So if we multiply on both sides by 10, we get
[tex]x\text{ = }\frac{4_{}\cdot10}{5}\text{ = }\frac{40}{5}=8[/tex]So 8 cm represent 10 km.
Jim is cutting up apples to serve at a meeting.He is planning to serve 1/3ofvan apple to each of the 8 people at the meeting
How many apples does Jim need to serve
1. d decreased by three
We need to write the expression:
d decreased by three
So. the new value will be less than the old value by 3
The word decreased mean the negative sign
So, the expression will be:
[tex]d-3[/tex]
What is the solution to -1-7? + 4 5 6 9 10 2 -10-9-8-7 6-5- 4 -3
Solution
To find the best expression, we need to first approximate the values before dividing it
[tex]\begin{gathered} 6\frac{3}{4}=6.75 \\ \\ We\text{ approximate to get} \\ 6.75\cong7 \end{gathered}[/tex]Similarly
[tex]\begin{gathered} 1\frac{2}{3}=1.6666666666667 \\ \\ we\text{ approximate to get} \\ \\ 1.6666667\cong2 \end{gathered}[/tex]Therefore, the answer is
[tex]7\div2[/tex]A landscape architect uses molds for castingrectangular pyramids and rectangular prisms to makegarden statues. He plans to place each finishedpyramid on top of a prism. If one batch of concretemix makes one prism or three pyramids, how doesthe volume of one pyramid compare to the volume ofone prism? Explain.
Volume of a rectangular pyramid:
[tex]V=\frac{1}{3}(L\cdot W)\cdot h[/tex]Volume of a rectangular prism:
[tex]V=L\cdot W\cdot h[/tex]As you can see the volume of a rectangular pyramid (y) is a thrid part of the volume of a rectangular prism (x). Then, if the length, width and height of both molds is the same the volume of the rectangular prism (x) is three times the volume of the volume of the rectangular pyramid (y).
[tex]\begin{gathered} x=3y \\ y=\frac{1}{3}x \end{gathered}[/tex]what is 10+5 rounded to the nearest thousand
the given expression is,
10 + 5 = 15
now we will round off it to the nearest
can you please help me
The relation between arcs AB and CD and angle x is:
[tex]m\angle x=\frac{1}{2}(m\hat{AB}+m\hat{CD})[/tex]Substituting with data, we get:
[tex]\begin{gathered} m\angle x=\frac{1}{2}(110+160) \\ m\angle x=\frac{1}{2}\cdot270 \\ m\angle x=135\text{ \degree} \end{gathered}[/tex]Use the pair of functions to find f(g(x)) and g(f(x)) . Simplify your answers. f(x)=x−−√+4 , g(x)=x2+1
We have a case of composite functions, we must evaluate or replace one function as x value of the other one. In other words and doing the calculations
[tex]\begin{gathered} f(g(x))=f(x^2+1)=\sqrt{x^2+1}+4 \\ g(f(x))=(\sqrt{x})^2+8\sqrt{x}+16+1=x+8\sqrt{x}+17 \end{gathered}[/tex]Thus, the answer to the exercise is
f(g(x))=√(x^2+1) +4
g(f(x))=x+8√x+17
An 8-lb cut of roast beef is to be medium roasted at 350 Fahrenheit. Total roasting time is determined by allowing 15 minutes roasting time for every pound of beef . If the roast is placed in a preheated oven at 2:00 pm., what time should it be removed ?
Given:
15 minutes roasting time for every pound of beef.
Total amount of beef is 8-lb
[tex]\begin{gathered} \text{Total time taken to roast 8-lb of beef}=15\times8 \\ \text{Total time taken to roast 8-lb of beef}=120\min utes\text{ } \\ \text{Total time taken to roast 8-lb of beef}=2\text{ hours} \end{gathered}[/tex][tex]\begin{gathered} \text{Time to remove from the over =2:00 pm +2 hours } \\ \text{Time to remove from the over =}4\colon00pm \end{gathered}[/tex]The following chart below represents the bedtimes of 100 students at Waller Junior High in a recent survey Number of Students Bedtime 8:00 PM 22 8.30 PM 17 9:00 PM 36 9:30 PM 25 If all 750 students at WJH were surveyed, what is the best prediction of the number of students who would have a bedtime of 9:00 PM in
Answer
The predicted number of students with bedtime of 9:00 PM
= 270 students
Explanation
For surveying and sampling, the fraction of a particular case in the sample is generalized for the entire population to predict that case for the population.
So, if we want the number of students who would have a bedtime of 9:00 PM, we first find the percentage of students with bedtime of 9:00 PM in the sample.
Number of students with bedtime of 9:00 PM in the survey = 36
Total number of students in the survey = 22 + 17 + 36 + 25 = 100
Percentage of students with bedtime of 9:00 PM in the survey = (36/100) = 0.36
So, in the population of 750 students,
The predicted number of students with bedtime of 9:00 PM = (0.36) (750) = 270 students
Hope this Helps!!!
how do i solve for scale factor from smaller to larger?
Answer:
1) k = 3
2) k = 2
Explanation:
To find the scale factor from the smaller to the larger figure, we need to divide the length of the larger figure by the length of the smaller figure.
The figures are similar, so we will use corresponding sides. Then:
[tex]\begin{gathered} k=\frac{\text{ larger length}}{\text{ smaller length}} \\ \text{ For the first figure:} \\ k=\frac{21}{7}=3 \\ \text{For the second figure:} \\ k=\frac{8}{4}=2 \end{gathered}[/tex]Therefore, the answers are:
1) k = 3
2) k = 2
1. According to the story of Pythagoras's discoveries and your own exploration during the lesson,
when does the relationship a² + b² = c² hold true?
The given relationship using the Pythagorean theorem holds true for a right-angled triangle.
We are given a mathematical relationship using the Pythagorean theorem. The Pythagorean theorem, also known as Pythagoras' theorem, is a fundamental relationship between the three sides of a right triangle in Euclidean geometry. The equation is given below.
a² + b² = c²
We need to describe the situation when this relationship holds true. The variables "a", "b", and "c" represent the sides of a triangle. The Pythagorean theorem is applicable to a right-angled triangle. It states that the sum of the squares of the base and the perpendicular is equal to the square of the hypotenuse.
Here a, b, and c denote the lengths of the base, the perpendicular, and the hypotenuse of the triangle, respectively.
To learn more about triangles, visit :
https://brainly.com/question/2773823
#SPJ1
Complete the table for y = 2x + 2 and graph the resulting line.
Answer
The table is
x | y
-2 | -2
0 | 2
2 | 6
4 | 10
6 | 14
The graph is then
Explanation
In the absence of the table, I will use a couple of values for x to obtain corresponding values of y.
Then, these points will be marked on the graph and the line connecting the points is drawn.
y = 2x + 2
when x = -2
y = 2x + 2
y = 2(-2) + 2
y = -4 + 2
y = -2
The point will then be (-2, -2)
when x = 0
y = 2x + 2
y = 2(0) + 2
y = 0 + 2
y = 2
The point will then be (0, 2)
when x = 2
y = 2x + 2
y = 2(2) + 2
y = 4 + 2
y = 6
The point will then be (2, 6)
when x = 4
y = 2x + 2
y = 2(4) + 2
y = 8 + 2
y = 10
The point will then be (4, 10)
when x = 6
y = 2x + 2
y = 2(6) + 2
y = 12 + 2
y = 14
The point will then be (6, 14)
The full table and graph will then be presented under 'Answer'.
Hope this Helps!!!
Please help!! slope-intercept form!!
Answer: y=1x+4
Step-by-step explanation: the b (y-intercept) is 4 and when you go up 1/1 (1) it crosses the lines
write a ratio that is equivalent to 12:36 using the collums for 2 and 6
The given ratio is 12:36, which can be expressed as a fraction 12/36. An equivalent expression to this one can be obtained by simplifying
[tex]\frac{12}{36}=\frac{6}{18}[/tex]Therefore, the answer is 6/18.A man starts his job with a certain monthlysalary and earns a fixed increment every year. If his salary was$7500 after 4 years of service and $9000 after 10 years ofservice, what was his starting salary and what is the annualincrement? Do you consider it a fair increment according to ourpresent cost of life and infletion?
Let starting salary = x
Increment every year = y
Therefore:
Salary after 4 years of service = x+4y
Salary after 10 years of service = x+10y
We have the equations:
[tex]\begin{gathered} x+4y=7500 \\ x+10y=9000 \end{gathered}[/tex]Substracting equation 1 from equation 2, we get:
[tex]x+10y-(x+4y)=9000-7500[/tex]Simplify:
[tex]\begin{gathered} x+10y-x-4y=1500 \\ 6y=1500 \\ Solve\text{ for y} \\ \frac{6y}{6}=\frac{1500}{6} \\ y=250 \end{gathered}[/tex]Next, substitute y = 250 in the equation 1:
[tex]x+4(250)=7500[/tex]And solve for x:
[tex]\begin{gathered} x+1000=7500 \\ x+1000-1000=7500-1000 \\ x=6500 \end{gathered}[/tex]Answer:
Starting salary = $6500
Annual increment = $250
11. A map is drawn so that 2 inches represents 700 miles. If the distance betweentwo cities is 3850 miles, how far apart are they on the map?a. 5.5 inchesb. 11 inchesc. 22 inchesd. 6 inchese. 12 inches
Given:
• 2 inches represents 700 miles on the map.
,• Actual distance between two cities = 3850 miles
Let's find the distance on the map.
Let's first find how many miles 1 inch represent.
We have:
[tex]\frac{700}{2}=350\text{ miles}[/tex]This means on the map, 1 inch represent 350 miles.
Now, to find the distance between the two cities on the map, we have:
[tex]\frac{3850}{350}=11\text{ inches}[/tex]Therefore, the distance between the two cities on the map is 11 inches.
ANSWER:
b. 11 inches
What input value produces the same output value for the two functions on the graph ? X=-1X= 0 X= 3X= 4
At x = 4 both f(x) and g(x) are qual to 3
How long will it take for a $2500 investment to grow to $4000 at an annual rate of 7.5%, compounded quarterly? Assume that no withdrawals are made. Donot round any intermediate computations, and round your answer to the nearest hundredth.If necessary, refer to the list of financial formulas.years I need help with this math problem
Answer:
6.33 years
Explanation:
The formula for investment at compound interest is given below::
[tex]A(t)=P\left(1+\frac{r}{k}\right)^{tk}\text{ where }\begin{cases}P=\text{Principal Invested} \\ r=\text{Interest Rate} \\ k=\text{Number of compounding periods}\end{cases}[/tex]From the statement of the problem:
• The initial investment, P = $2500
,• Annual Interest Rate, r = 7.5% = 0.075
,• Compounding Period (Quarterly), k = 4
,• Amount after t years, A(t) = $4000
,• Time, t = ?
Substitute these values into the compound interest formula above:
[tex]4000=2500\left(1+\frac{0.075}{4}\right)^{4t}[/tex]We then solve the equation for the value of t.
[tex]\begin{gathered} \begin{equation*} 4000=2500\left(1+\frac{0.075}{4}\right)^{4t} \end{equation*} \\ \text{ Divide both sides by 2500} \\ \frac{4000}{2500}=\left(1+0.01875\right)^{4t} \\ 1.6=\left(1.01875\right)^{4t} \\ \text{ Take the log of both sides} \\ \log(1.6)=\log(1.01875)^{4t} \\ \text{ By the power law of logs, }\log a^n=n\log a \\ \log(1.6)=4t\log(1.01875) \\ \text{ Divide both sides by 4}\log(1.01875) \\ \frac{\operatorname{\log}(1.6)}{4\operatorname{\log}(1.01875)}=\frac{4t\operatorname{\log}(1.01875)}{4\operatorname{\log}(1.01875)} \\ t\approx6.33\text{ years} \end{gathered}[/tex]It will take approximately 6.33 years for a $2500 investment to grow to $4000.
Identify the underlined place and 27.3856. Then round the number to that place.
Based on the positiion of the underlined decimal places, the underlined number is in the hundredths place.
Rounding it off, next to 8 in the hundredths place is 5 in the thousandths place.
If the number is 5 or greater, we add 1 to the previous decimal place therefore it is rounded to 27.39
the measure of an interior angle of an equilateral triangle is given as 3n-6. solve for the value of nA. 22B. 60C.6D. 2
Hi i need help with unit rate fractions and ill show an example i need to have this figured out by thurday for a test and i have no clue so pls help
To find the rate in teaspoons per cup we divide the number of teaspoons by the cups:
[tex]\frac{4}{\frac{2}{3}}=\frac{12}{2}=6[/tex]Therefore, the unit rate is 6 teaspoons per cup.
which of the following is equivalent to the expression below? In(e^7)
Answer: C. 7
Explanation
When the exponent of a natural logarithm has an exponent, we can do the following:
[tex]\ln(e^7)=7\ln(e)[/tex]Additionally, we are given a natural logarithm, and the base for the natural logarithm is the mathematical constant e. When the argument of the logarithm is equal to the base, then it is equal to 1:
[tex]7\ln(e)=7\cdot1[/tex][tex]=7[/tex]1.Given the graph, find the following:A: Identify the slope of the lineB.Identify the y-intercept of the lineC.Identify the x-intercept of the lineD. Write the equation of the line in slope-intercept form (y = mx+b)
A.
The slope of a line is the rate of change of the dependent variable (y) with respect to the independent variable (x).
Notice that for each increase of 3 units in the variable x, the variable y decreases 2 units. Then, the change in y is -2 when the change in x is 3. Then, the rate of change is:
[tex]m=\frac{\Delta y}{\Delta x}=\frac{-2}{3}[/tex]B.
The y-intercept of a line is the value of y in which the line crosses the Y-axis. In this case, the line crosses the Y-axis at y=4. Then, the y intercept is:
[tex]4[/tex]C.
Similarly, the x-intercept is the value of x in which the line crosses the X-axis. In this case, we can see that the x-intercept is:
[tex]6[/tex]D.
Since the slope m is equal to -2/3 and the y-intercept b is equal to 4, then the equation of the line is:
[tex]y=-\frac{2}{3}x+4[/tex]