Answers
Related Questions
Question 1 of 10‚Q(t) = Q¸e¯ktThe functionmay be used to model radioactive decay. Qrepresents the quantity remaining after tyears; k is the decay constant. Thedecay constant for plutonium-240 is k = 0.00011. What is the half-life, inyears?OA. 6,301 yearsOB. 1,512,321 yearsC. 0.076 yearsOD. 3,150 years
Answers
The half-life is 6300 years.
From the question, we have
t_1/2 = 0.693/k
where,
t_1/2 = half-life
k = decay constant = 0.00011
substituting the value, we get
⇒t_1/2 = 0.693/0.00011
⇒t_1/2 = 6300 years
Half Life Period:
One of the main terms used in physics to describe the radioactive decay of a specific sample or element over a predetermined amount of time is half-life, also known as half-life period. When studying the subject, nuclear physics students will frequently run into the phrase. The term "exponential decay" is also frequently used to refer to both exponential and non-exponential decay, which are both common forms of decay processes. In fields other than physics, the word is used to describe the biological half-life of specific substances in the human body or in medications.
To learn more about half-life period visit: https://brainly.com/question/9654500
#SPJ9
Use words to describe each algebraic expression. 3. 6c4. X-15. t/26. 3t - 4
Answers
3. 6c
It multiplication between six and c.
Six times a number c.
4.
x-1
Its a subtraction.
A number minus one.
5.
t/2
A number divided by two.
6.
3t-4
Three times a number minus 4
Sparks garden is in the shape of a trapezoid and the dimensions are shown belowa gardener needs to spread fertilizer over the flower beds each bag of fertilizer he uses covers 125 square meters and he can only buy full bags how many bags of fertilizer will he need to cover the entire garden
Answers
To be able to determine the bags of fertilizer that the gardener will need, let's first determine the area of the garden.
Since the shape of the garden is a trapezoid, we will be using the following formula:
[tex]\text{ Area = }\frac{1}{2}H(B_1+B_2)[/tex]We get,
[tex]\text{ Area = }\frac{1}{2}H(B_1+B_2)[/tex][tex]\text{ = }\frac{1}{2}(50)(70\text{ + 40)}[/tex][tex]\text{ = }\frac{1}{2}(50)(110\text{) = }\frac{50\text{ x 110}}{2}[/tex][tex]\text{ = }\frac{5,500}{2}[/tex][tex]\text{ Area = }2,75m^2[/tex]Let's determine how many bags of fertilizer will be used.
[tex]\text{ No. of Bags of Fertilizer = }\frac{\text{ Area of Garden}}{\text{ Area that a Bag of Fertilizer can cover}}[/tex]We get,
[tex]\text{ = }\frac{2,750(m^2)}{125\frac{(m^2)}{\text{bag}}}[/tex][tex]\text{ No. of Bags of Fertilizer = }22\text{ Bags}[/tex]Therefore, the gardener will be needing 22 Bags of Fertilizer.
From a 12 foot roll of rubber hose, a person cuts lengths of 2 3/8 feet, 2 1/2 feet, and 3 1/4 feet. How much hose is left on the roll?
Answers
Sum the lengths that the person cuts:
To sum mixed numbers:
[tex]2\frac{3}{8}ft+2\frac{1}{2}ft+3\frac{1}{4}ft=[/tex]1. Add the whole numbers:
[tex]2ft+2ft+3ft=7ft[/tex]2. Add fractions
[tex]\begin{gathered} \frac{3}{8}ft+\frac{1}{2}ft+\frac{1}{4}ft \\ \\ \text{Write all as fractions with denominator 8:} \\ \\ \frac{3}{8}ft+\frac{4}{8}ft+\frac{2}{8}ft=\frac{3ft+4ft+2ft}{8}=\frac{9}{8}ft \\ \\ \\ \end{gathered}[/tex]Then, the person cuts 7 9/8 ft, substract it from the initial 12 ft roll of rubber hose:
[tex]\begin{gathered} \text{Write the mixed number as a fraction:} \\ 7\frac{9}{8}ft=7ft+\frac{9}{8}ft=\frac{56ft+9ft}{8}=\frac{65}{8}ft \\ \\ \text{Substract the fraction above from 12ft}\colon \\ \\ 12ft-\frac{65}{8}ft=\frac{96ft-65ft}{8}=\frac{31}{8}ft \\ \\ \text{Write the result as a mixed number:} \\ \\ \frac{31}{8}ft=\frac{24}{8}ft+\frac{7}{8}ft=3\frac{7}{8}ft \end{gathered}[/tex]Then, 3 7/8 ft of hose are left on the rollwhat is the simplest form for the ratio of 24:48 and how
Answers
For 24 / 48 simplest form find the maximum common divisor ( m.c.d)
In this special case ( but this not common) 24 divides exactly 48
so then 24/24 = 1. And 48/24= 2.
then the simplest form is 24/48= 1/2
describe the appearance of the graph
Answers
the equation is a line because the variable is of the first degree, this is because x is raised to 1.
a first degree equation is a line and the slope is the coefficient of the variable, on this case the slope is -4, then the slope get down because the slope is negative
so the right option is fourth
generate ordered pairs for tha function y=x² - 9 using x = -4, -2,0,2 and 4
Answers
Generating ordered pairs is to solve for "y" using the function above with the given "x" values -4, -2, 0, 2, and 4.
If x = -4, then y = 7.
y = (-4)² - 9
y = 16 - 9
y = 7
If x = -2, then y = -5.
y = (-2)² - 9
y = 4 - 9
y = -5
If x = 0, then y = -9
y = 0² - 9
y = 0 - 9
y = -9
If x = 2, then y = -5
y = 2² - 9
y = 4 - 9
y = -5
If x = 4, then y = 7
y = (4)² - 9
y = 16 - 9
y = 7
To summarize, the ordered pairs for the function y = x² - 9 using the given x - values are:
1. (-4, 7)
2. (-2, -5)
3. (0, -9)
4. (2, -5)
5. (4, 7)
Below is the graph of the equation. Due to the nature of the equation, the graph is a parabola.
The equation of a circle is (x-2)²+(y-6)²=25. What is the radius of the circle?
Answers
Consider that the general equation of a circle is given by:
[tex](x-h)^2+(y-k)^2=r^2[/tex]where (h,k) is the center of the circle and r is the radius.
Then, by comparing the given equation with the general equation, you can notice that:
25 = r^2 => r = 5
Hence, the radius of the circle is 5
How to slove these problems2 7/8 - 15/161 1/5 x 2 1/32 1/5 ./. 4
Answers
The Solution:
Given the following:
[tex]\begin{gathered} 2\frac{7}{8}-\frac{15}{16} \\ \\ 1\frac{1}{5}\times2\frac{1}{3} \\ \\ \frac{2\frac{1}{5}}{4} \end{gathered}[/tex]We are asked to evaluate each of them.
Step 1:
we shall convert each fraction into an improper fraction.
[tex]\frac{23}{8}-\frac{15}{16}[/tex][tex]\frac{46-15}{16}=\frac{31}{16}=1\frac{15}{16}[/tex][tex]\begin{gathered} 1\frac{1}{5}\times2\frac{1}{3} \\ \\ \frac{6}{5}\times\frac{7}{3}=\frac{2\times7}{5}=\frac{14}{5}=2\frac{4}{5} \end{gathered}[/tex][tex]\frac{2\frac{1}{5}}{4}=\frac{\frac{11}{5}}{4}=\frac{11}{5}\times\frac{1}{4}=\frac{11}{20}[/tex]At a sale, a table is being sold for 24% of the regular price. The sale price is $110.40.What is the regular price?
Answers
Let x be the regular price. We are told that the sale price corresponds to the 24% of the regular price. That is, if we calculate the 24% of x, we would get the sale price, which is 110.40. Recall that to calculate the 24% of x, we simply multiply x by 24 and divide it by 100. So this expression would be
[tex]x\cdot\frac{24}{100}[/tex]We know that this quantity should be 110.40 so we have the following equation
[tex]x\cdot\frac{24}{100}=110.40[/tex]So, if we multiply both sides by 100, we get
[tex]24\cdot x\text{ =11040}[/tex]Now, we divide both sides by 24, so we get
[tex]x=\frac{11040}{24}=460[/tex]So the original price of the table was 460.
What are the coordinates (x,y) of the solution to the system of equations?
Answers
The system of equations given are
[tex]\begin{gathered} y=-8x+10 \\ y=x-8 \end{gathered}[/tex]ExplanationSolve the given system of equations using elimination method
[tex]\begin{gathered} y=-8x+10..........1 \\ y=x-8......2 \end{gathered}[/tex]Subtract equation 1 by equation 2.
[tex]\begin{gathered} (y+8x-10)-(y-x+8)=0 \\ 8x-10+x-8=0 \\ 9x=18 \\ x=2 \end{gathered}[/tex]Now find the value of y by substitute the value of x in equation 1.
[tex]\begin{gathered} y=-8\times2+10 \\ y=-16+10 \\ y=-6 \end{gathered}[/tex]AnswerHence the coordinates of x and y to the system of equations is
[tex](2,-6)[/tex]Write an equation for a function that has a graph with the given characteristics.The shape of y= 1/x shifted down 4 units.
Answers
Given:
y = 1/x
Required:
equation for a function that shifted down 4 units
Solution:
y' = 1/x - 4
Answer:
y' = 1/x - 4
The safe load, L, of a wooden beam of width w, height h, and length l, supported at both ends, varies directly as the product of the width and the square of the height, and inversely as the length. A wooden beam 4 inches wide, 8 inches high, and 216 inches long can hold a load of 5050 pounds. What load would a beam 2 inches wide, 5 inches high, and 144 inches long, of the same material, support? Round your answer to the nearest integer if necessary.
Answers
We have the following, L, of the beam varies as the product of the width and the square of the height:
[tex]L\propto w\cdot h^2[/tex]And varies inversely as the lenght of the wooden beam:
[tex]L\propto\frac{w\cdot h^2}{l}[/tex]therefore:
[tex]L=k\cdot\frac{w\cdot h^2}{l}[/tex]where k is the proportionality constant
w = 4, h=8, l = 216 and L = 5050
[tex]\begin{gathered} 5050=k\cdot\frac{4\cdot8^2}{216} \\ k=\frac{5050\cdot216}{256} \\ k=4260.93 \end{gathered}[/tex]now, if w = 2, h = 5, l = 144:
[tex]\begin{gathered} L=4260.93\cdot\frac{2\cdot5^2}{144} \\ L=1479.5 \end{gathered}[/tex]Morris borrowed $9,000 from a credit union at 13% simple interest for 42 months. What were his money installment payments (to the nearest whole cent)?$311.79 per month$307.89 per month$297.58 per month$377.12 per monthNone of these choices are correct.
Answers
Now the total interest for 42 months will be:-
[tex]\begin{gathered} S\mathrm{}I\mathrm{}=\frac{9000\times13\times7}{200} \\ =\frac{90\times13\times7}{2} \\ =45\times13\times17 \\ =4095 \end{gathered}[/tex]So the total amount he has to pay after 42 months will be = 9000+4095
= $13095
So
[tex]\begin{gathered} 42\text{ months = \$13095} \\ 1\text{ month =}\frac{13095}{42} \\ =311.79 \end{gathered}[/tex]So his monthly installment will be $ 311.79
So $ 311.79 is the correct option.
In which quadrant will the image lie if AB is reflected in the c-axis?
Answers
The quadrants on a xy frame are numbered as below:
The image is originally in the Quadrant I, if we reflect it in the x-axis, then it'll be placed on the fourth quadrant. So the answer is D Quadrant IV.
determine the composition of transformation that would map figure ABCD to figure A"B"C"D". 1. the transformation that would map vertex B to B' isa: a transformation down and rightb: a rotation of 90° about Bc: a rotation of 360° about B
Answers
Answer:
b: a rotation of 90° about B
Explanation:
A transformation down and right of the figure look like this:
Where the figure is just translated, so the orientation of the figure is the same.
In the same way, a rotation of 360° doesn't change the figure, because it is equivalent to make a full turn of the figure.
Finally, a rotation of 90° about B looks like this:
Where each segment of the initial figure forms an angle of 90° with its corresponding segment of the reflected figure. For example, BA is perpendicular to B'A'
Therefore, the answer is b: a rotation of 90° about B.
Can you help me figure out if figure in a polygon. is it a polygon the name of it by the number of the size
Answers
2)
A polygon has an infinite number of sides and they are connected to each other end to end. This means that it is an enclosed figure. Looking at the figure, it has all these characteristics. Thus,
It is a polygon
Next, we would count the number of sides. In this case, it is 10. A 10 sided polygon is called a Decagon. Thus, the given figure is a Decagon
The table shows a survey of 100 people selected at random at an airport. Find the experimental probability that a person selected at random is going to city B.City A - 26City B - 36City C - 18City D - 18City E - 2
Answers
Given:
The table shows a survey of 100 people selected at random at an airport
We will find the probability that a person selected at random is going to city B
As shown: City B - 36
So, the probability will be as follows:
[tex]probability=\frac{36}{100}=0.36[/tex]So, the answer will be probability = 0.36
I just need answers. No need longer to explain.Solve a
Answers
We need to find the period of the sinusoidal function in this case we have the next form
[tex]y=A\sin \frac{2\pi}{T}(x+a)+b[/tex]First, we need to find the amplitude in this case
[tex]A=\frac{5+1}{2}=\frac{6}{2}=3[/tex]The amplitude is 3
Then we need to find the period
[tex]T=\frac{2\pi}{3}[/tex]and the the displacement b is 2
Then for a we have
[tex]a=\frac{5}{12}\pi[/tex]Therefore we have
[tex]y=3\sin 3(x-\frac{5\pi}{12})+2[/tex]ANSWER
[tex]y=3\sin 3(x-\frac{5\pi}{12})+2[/tex]A bottle rocket is launched straight up. Its height in feet (y) above theground x seconds after launch is modeled by the quadratic function: y =-16x2 + 116x + 7.What was the maximum height of the rocket?
Answers
1) Looking at the function y= -16x² + 116x + 7
The maximum height is the vertex described by the parabola. The Vertex follows that formula:
[tex]\begin{gathered} V=(\frac{-b}{2a},\frac{-\Delta}{4a}) \\ \end{gathered}[/tex]2) Since the question wants only the height, let's keep with the y-coordinate of the Vertex. Let's call it Yv
[tex]Y_V=\frac{-(116^2-4(-16)(7))}{4(-16)}\Rightarrow\frac{-(13904)}{-64}=\text{ 217.25}[/tex]So the maximum height of that rocket is 217.25 feet above the ground.
the solution set of an equation of a circle is all if the points that lie on the circle true or false
Answers
A circle is the set of all points in a plane at a given distance called the radius of a given point called the center. In this sense the points that lie on the circle represent the solutions for the equation of a given circle. Therefore, the statement is true
Find the measure of angle R, given that the largest triangle is a right triangle.A)27B)18C)72D)45
Answers
we know that
The central angle is 90 degrees
so
18+R=45 degrees
R=45-18
R=27 degreesWrite - 4 - 2y= - x in standard form.
Answers
Answer:
[tex]-x\text{ + 2y = -4}[/tex]Explanation:
Here, we want to write the given equation in standard form
The equation of a line in standard form is as follows:
[tex]Ax\text{ + By = C}[/tex]What we have to do now is to bring the x and y terms together
We can have this as follows:
[tex]-x\text{ + 2y = -4}[/tex]-4 - 2y = -x
We want to leave -4 alone on the left
That means we have to transfer -2y that is there with it
To transfer -2y over the equality sign , its sign changes
-4 = +2y - x
But +2y can be written as 2y only
Finally by re-arrangement:
-x + 2y = -4
What is the probability of landing on a number less than 3 and then landing on a divisor of Write your answer as a percentage
Answers
The number less than 3 are {1,2}.
The total possible outcome is 4.
Determine the probability for number less than 3.
[tex]\begin{gathered} P(A)=\frac{2}{4} \\ =\frac{1}{2} \end{gathered}[/tex]The number divisor of 20 are {1,2,4}.
Determine the probability for landing on a number divisor of 20.
[tex]P(B)=\frac{3}{4}[/tex]The probability for number less than 3 and number divisor of 20 are independent events. So,
[tex]\begin{gathered} P(AandB)=P(A)\cdot P(B) \\ =\frac{1}{2}\cdot\frac{3}{4} \\ =\frac{3}{8} \end{gathered}[/tex]Determine the probability in percentage by multiply the fraction with 100.
[tex]\begin{gathered} P(AandB)=\frac{3}{8}\cdot100 \\ =37.5 \end{gathered}[/tex]So answer is 37.5 %.
An electric company calculates a person's monthly bill from the number of kilowatt-hours (kWh), x, used. The function b(x) = { x < 200 0.10x, 0.15(x – 200) + 20, x > 200 determines the bill. How much is the bill for a person who uses 800 kWh in a month? O A. $90 O B. $110 O C. $60 O D. $80
Answers
Since x = 800kWh which is greater than 200, we use the function
b(x) = 0.15(x - 200) + 20
b(800) = 0.15(800 - 200) + 20
=0.15(600) + 20
= 90 + 20
=$110
option B is the correct answer
4) B) determine the scope of each of the following lines assume the dots are on integer coordinates
Answers
Given the following question:
Part B:
Point A: (-8, -2) = (x1, y1)
Point B: (3, 2) = (x2, y2)
Formula for slope:
[tex]m=\frac{y2-y1}{x2-x1}[/tex][tex]\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ m=\frac{2--2}{3--8}=\frac{4}{11} \\ m=\frac{4}{11} \end{gathered}[/tex]The monthly cost (in dollars) of a long-distance phone plan is a linear function of the total calling time (in minutes). The monthly cost for 37 minutes of calls is$13.21 and the monthly cost for 70 minutes is $17.50. What is the monthly cost for 45 minutes of calls?
Answers
Given:
The monthly cost is 37 min is $13.21
70 min cost is $17.50
Find-:
The monthly cost for 45 minutes of calls
Explanation-:
The linear equation is:
[tex]\begin{gathered} y=mx+c \\ \end{gathered}[/tex]Where,
[tex]\begin{gathered} m=\text{ Slope} \\ \\ c=Y-\text{ Intercept} \end{gathered}[/tex]The formula of the slope is:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]The point is:
[tex]\begin{gathered} (x_1,y_1)=(37,13.21) \\ \\ (x_2,y_2)=(70,17.50) \end{gathered}[/tex]So, the slope is:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \\ m=\frac{17.50-13.21}{70-37} \\ \\ m=\frac{4.29}{33} \\ \\ m=0.13 \end{gathered}[/tex]Slope is:
The general equation of a line:
[tex]\begin{gathered} y=mx+c \\ \\ y=0.13x+c \end{gathered}[/tex]The value of "c" is:
[tex]\begin{gathered} y=0.13x+c \\ \\ (x,y)=(37,13.21) \\ \\ 13.21=0.13(37)+c \\ \\ c=13.21-4.81 \\ \\ c=8.4 \end{gathered}[/tex]The equation is:
[tex]\begin{gathered} y=mx+c \\ \\ y=0.13x+8.4 \end{gathered}[/tex]Cost at 45 min. is:
[tex]\begin{gathered} x=45 \\ \\ y=0.13x+8.4 \\ \\ y=0.13(45)+8.4 \\ \\ y=5.85+8.4 \\ \\ y=14.25 \end{gathered}[/tex]The 45 min cost is $14.25
Choose the description(s) of how I could graph the equation y = − 7 x + 1 . Choose all that apply. Hint: Push the negative either to the top or bottom of the fraction to help you graph.
Answers
We are given the following equation in slope-intercept form.
[tex]y=-7x+1[/tex]The general form of slope-intercept form is given by
[tex]y=mx+b[/tex]So, we see that
slope = m = -7
y-intercept = b = 1
The Slope can be written as
[tex]m=\frac{\text{rise}}{\text{run}}=\frac{7}{-1}=-7[/tex]Also, the y-intercept is the point at which the line crosses the y-axis.
So all those options that say to start on the x-axis are incorrect.
We start at 1 on the y-axis and plot that point.
Then from there, we go up (rise) 7 units and to the left (run) 1 unit.
Go up means positive and go left means negative so the slope becomes -7.
Then plot that point and draw the line connecting the points.
Therefore, there is only one correct answer and that is
Start at 1 on the y-axis. Plot that point. Then from there, go up seven units and left one. Plot that point. Then draw the line connecting the points.
its and left one. Plot that point. Then draw the line connecting the points.
its and left one. Plot that point. Then draw the line connecting the points.
its and left one. Plot that point. Then draw the line connectinits and left one. Plot that point. Then draw the line connectinits and left one. Plot that point. Then draw the line connectinStart at 1 on the y-axis. Plot that point. Then from there, go up seven unG
Please walk me through these questions step by step (Simplifying the following terms)
Answers
The only formulas you have to know are:
[tex]\begin{gathered} \sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b} \\ i^2=-1\rightarrow i=\sqrt{-1} \end{gathered}[/tex]When you do not know the root of a number, you have to express its root like a product of its main factors, for example:
[tex]\sqrt{75}=5\sqrt{3}[/tex]To find these factors, we can divide the original number among other numbers and multiply them, for example:
When we know those factors, we can use the laws of roots to simplify:
[tex]\begin{gathered} 75=5^2\cdot3 \\ \sqrt[]{75}=\sqrt{5^2\cdot3}=5^{\frac{2}{2}}\cdot\sqrt{3}=5\sqrt{3} \end{gathered}[/tex]With this in mind, we can now solve the exercise:
First term:
[tex]\begin{gathered} \frac{-20\pm\sqrt{75}}{5} \\ \\ \frac{-20\pm5\sqrt{3}}{5}\text{ \lparen Divide each term of the numerator by the denominator\rparen} \\ \\ -4\pm\sqrt[]{3} \end{gathered}[/tex]Second term:
*Notice that
[tex]\sqrt{-81}=\sqrt{(-1)\cdot(81)}=\sqrt{81}\cdot\sqrt{-1}=\sqrt{81}i=9i[/tex][tex]\begin{gathered} \frac{6\pm\sqrt{-81}}{3} \\ \\ \frac{6\pm9i}{3} \\ \\ 2\pm3i \end{gathered}[/tex]Third term:
*Notice the followings:
[tex]\sqrt{-28}=\sqrt{28\cdot-1}=\sqrt{28}\cdot\sqrt{-1}=\sqrt{4\cdot7}i=2\sqrt{7}i[/tex]Finally,
[tex]\begin{gathered} \frac{-4\pm\sqrt{-28}}{8} \\ \\ \frac{-4\pm2\sqrt{7}i}{8} \\ \\ \frac{-4}{8}\pm\frac{2\sqrt{7}}{8}i \\ \\ \frac{-1}{2}\pm\frac{\sqrt{7}}{4}\imaginaryI \end{gathered}[/tex]
on a map. 1 inch equals 10.1 miles . if two cities are 3.5 inches apart on the map, how far are they actually apart?
Answers
Since each inch equals 10.1 miles, mutliply 3.5 times 10.1 to find how far are two cities that are 3.5 inches apart on the map:
[tex]3.5\times10.1=35.35[/tex]Therefore, they are 35.35 miles apart.