Answer:
73.2 pm
Explanation:
"The anions make contact along the diagonal of the face of the unit cell, so the diagonal of the face is equal to 4 ionic anion radii. By letting r represent the ionic radius of the anion, d represent the diagonal of the face of the unit cell, and x represent the edge length, then d=4r and
d^2=x^2+x^2= 2x^2
By substituting 4r for d, the second equation becomes
(4r)^2=(2)x^2
Solving this equation for r shows that
r=(x–√2)/4
Since the edge length x is 207 pm, the ionic radius of the anion is
r= ((207 pm) X [tex]\sqrt{2}[/tex])/4=73.2 pm
Notice that the formulae used to describe atomic radii include constants with exact values. Therefore, these values do not constrain the number of significant figures."
The ionic radius of the anion in the FCC unit cell where anions are in contact along the diagonal of the face of the unit cell is 73.1pm.
What is ionic radius?Ionic radius is the distance between the center of the atom and the outermost part.
As in the question it is given that anions are in contact along the diagonal of the face of the unit cell, so the length of the diagonal is represented as: d = 4r, where
r = ionic radius
Length of edge i.e. a = 207 pm (given)
Two adjacent edges and diagonal of a FCC unit cell makes a right angle triangle, by using pythagoras theorem we can write as:
a² + a² = d²
2a² = (4r)²
2a²/16 = r²
2(207)²/16 = r²
85,698/16 = r²
0r r = 73.18 pm
Hence, 73.18 pm is the ionic radius of the anion.
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The concentration of a benzene solution prepared by mixing 12.0 g
C6H6 with 38.0 g CCl4 is __________ molal
Answer: The concentration of a benzene solution is 4.05 molal
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
[tex]Molality=\frac{n\times 1000}{W_s}[/tex]
where,
n = moles of solute
[tex]W_s[/tex] = weight of solvent in g
moles of [tex]C_6H_6[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{12.0g}{78g/mol}=0.154mol[/tex]
Now put all the given values in the formula of molality, we get
[tex]molality=\frac{0.154\times 1000}{38.0g}=4.05[/tex]
Therefore, the concentration of a benzene solution is 4.05 molal
2) Calculate the percent composition of each element in Mgso,
3) Calculate the percentage of each element in Ag,o.
Answer:
2)
[tex]\% Mg=20.2\%\\\\\% S=26.6\%\\\\\% O=53.2\%[/tex]
3)
[tex]\% Ag=93.1\%\\\\\% O=6.9\%[/tex]
Explanation:
Hello!
2) In this case, since magnesium sulfate is MgSO₄, we can see how magnesium weights 24.305 g/mol, sulfur 32.06 g/mol and oxygen 64.00 g/mol as there is one atom of magnesium as well as sulfur but four oxygen atoms for a total of g/mol; thus the percent compositions are:
[tex]\% Mg=\frac{24.305}{120.36 } *100\%=20.2\%\\\\\% S=\frac{32.06}{120.36 } *100\%=26.6\%\\\\\% O=\frac{64.00}{120.36 } *100\%=53.2\%[/tex]
3) In this case, although the element seems to contain Ag and O, we infer its molecular formula is Ag₂O; thus, since we have two silver atoms weighing 215.74 g/mol and one oxygen atom weighing 16.00 g/mol for a total of 231.74 g/mol, we obtain the following percent compositions:
[tex]\% Ag=\frac{215.74}{231.74} *100\%=93.1\%\\\\\% O=\frac{16.00}{231.74} *100\%=6.9\%[/tex]
Best regards!
2. I need to find the angle of corner of a room, what tool could I use?
a. Combination square
b. Plumb-bob
c. Sliding t-bevel
d. Tri-square
Which of the following is the correct decreasing order of hydrogen ions concentrations?
Answer: A> B> C > D> E
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
[tex]pH=-\log [H^+][/tex]
a) Solution A: pH =2
[tex][H^+]=10^{-2}[/tex]
b) Solution B: pH =5
[tex][H^+]=10^{-5}[/tex]
c) Solution C: pH = 7
[tex][H^+]=10^{-7}[/tex]
d) Solution D: pH = 8
[tex][H^+]=10^{-8}[/tex]
e) Solution E: pH =13
[tex][H^+]=10^{-13}[/tex]
Thus the decreasing order of hydrogen ion concentration is A> B> C > D> E
Which units can be used to measure length or distance? Check all that apply.
gram
meter
kilometer
liter
inch
Answer:
Meter, kilometer & inch - used to measure length or distance.
How many atoms are in 90.43 moles of copper
Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 8.12×10²³ atoms are in 90.43 mole of copper.
What is mole?
The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance. It measure the number of elementary entities of a given substance that are present in a given sample. There are so many formula for calculating mole.
we know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number
number of atoms/molecules=number of moles × 6.022×10²³(Avogadro number)
number of moles of copper=90.43 moles
Substituting all the given values in the above equation, we get
number of atoms/molecules= 90.43 × 6.022×10²³
number of atoms/molecules=8.12×10²³ molecules
Therefore, 8.12×10²³ atoms are in 90.43 mole of copper.
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When the North Pole of one magnet is next to another North Pole of the other manger they will repel. True or false
Assume the copper was not thoroughly dried. How will the following calculations be affected?
The calculated mass of copper will be too low or too high?
The calculated moles of copper will be too low or too high?
The calculated mass of chlorine will be too low or too high?
The calculated moles of chlorine will be too low or too high?
What is the gravitational force on a 35.0kg object standing on the earth's surface ?
Answer:
Explanation:
F=mg
F=35*9.81
F=343.35N
What is the mole ratio of nitrogen (N2) to ammonia (NH3)?
N2 + 3 H2 → 2 NH3
a.2:3
b3:1
c.3:2
d.1:3
Mercury(II) oxide decomposes to form mercury and oxygen, like this:
2Hg (l) + O2 (g) → 2HgO (s)
At a certain temperature, a chemist finds that a reaction vessel containing a mixture of mercury(II) oxide, mercury, and oxygen at equilibrium has the following composition:
compound amount
Hg 14.7g
O2 13.4g
HgO 17.8g
Calculate the value of the equilibrium constant for this reaction. Round your answer to significant digits. Clears your work. Undoes your last action. Provides information about entering answers.
Solution :
For the reaction given :
[tex]$\text{2Hg}_{(l)}+\text{O}_2_{(g)} \rightarrow \text{2HgO}_{(s)}$[/tex]
Thus we know that the equilibrium constant [tex]$K_c$[/tex] contains aqueous an dgas species only.
∴ [tex]$K_c=\frac{1}{[O_2]}$[/tex] ............(1)
Now at the equilibrium, an amount of the 13.4 g of oxygen was found in the vessel of 6.9 liters. For determining the concentration of the oxygen gas, we use :
[tex]$[O_2]= \frac{n_{O_2}}{V_{soln}}$[/tex] ................... (2)
Here, [tex]$n_{O_2}$[/tex] = no. of moles of oxygen gas (mol)
[tex]$V_{soln}$[/tex] = volume of solution (L)
Therefore the number of moles of the oxygen gas is calculated by directly using the molecular weight (31.9988 g/mol) as the conversion factor.
∴ [tex]$n_{O_2}= 13.4 \ g \times \frac{\text{1 mol}}{31.9988 \ g}$[/tex]
= 0.418 mol
Now substituting the known values in (2), we can find the equilibrium concentration of the oxygen gas :
[tex]$[O_2] =\frac{0.418 \ \text{mol}}{6.9 \ \text{L}}$[/tex]
= 0.0605 M
Therefore substituting the result in (1), the equilibrium constant for the reaction is :
[tex]$K_c=\frac{1}{0.0605}$[/tex]
= 16.52
How many moles of hydrogen are in a 200. mg tablet of naproxen sodium, C14H13NaO3, the active ingredient in Aleve? Please show your work to receive full credit. MM = 252
Answer:
0.0103 mol
Explanation:
Step 1: Given data
Mass of the naproxen sodium tablet (m): 200. mgMolar mass of naproxen sodium (M): 252 g/molStep 2: Convert "m" to grams
We will use the conversion factor 1 g = 1000 mg.
200. mg × 1 g/1000 mg = 0.200 g
Step 3: Calculate the moles (n) of naproxen sodium
We will use the following expression.
n = m/M = 0.200 g / (252 g/mol) = 7.94 × 10⁻⁴ mol
Step 4: Calculate the moles of hydrogen in 7.94 × 10⁻⁴ moles of naproxen sodium
According to the chemical formula, the molar ratio of naproxen sodium to H is 1:13. The moles of H are 13/1 × 7.94 × 10⁻⁴ mol = 0.0103 mol.
Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional questions.
Online Content: Site 1
How did the gold rush transform Australia? (Site 1)
marking brainliest
Answer:
In 1851 gold-seekers from around the world began pouring into the colonies, changing the course of Australian history. The gold rushes greatly expanded Australia's population, boosted its economy, and led to the emergence of a new national identity.
Explanation:
Answer:
People from all over the world look for gold and in 1851 people started forming colonies to look for it which had a huge impact on the history of Australia. The gold rushes increased Australia's population which improved its economy.
can someone help me with this will mark brainliest
Answer:
3
Explanation:
Which statement best describes how matter and energy is cycled through the ecosystem?
A. Energy is recycled in an ecosystem, but matter is not recycled.
B. Matter and energy are both cycled throughout an ecosystem, and much of the energy at each level is changed to heat energy.
C. Energy is gained in each level on the energy pyramid, and matter is lost in an ecosystem.
D. Matter and energy are the same.
D. Matter and energy are the same.
oil has a density of 8.5kg/L. what is the volume of 5.4kg oil
Answer:
0.64 L
Explanation:
Step 1: Given data
Density of oil (ρ): 8.5 kg/LMass of oil (m): 5.4 kgVolume of oil (V): ?Step 2: Calculate the volume corresponding to 5.4 kg of oil
Density is an intrinsic property and it is equal to the quotient between the mass and the volume.
ρ = m/V
V = m/ρ
V = 5.4 kg/(8.5 kg/L) = 0.64 L
A gas takes
up a volume of 17 L, has a
pressure of 2.3 atm, and a temperature
of 299 K. If I raise the temperature to
350 K and lower the pressure to 1140
mmHg, what is the new volume?
Answer:
V₂ = 25.065 L
Explanation:
Given data:
Initial volume = 15L
Initial pressure = 1500 mmHg (1500/760 = 1.97 atm)
Initial temperature = 299 K
Final temperature = 350 K
Final volume = ?
Final pressure = 1050 mmHg (1050/760 = 1.38 atm)
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.97 atm × 15 L × 350 K / 299 K × 1.38 atm
V₂ = 10342.5 atm .L. K / 412.62 K.atm
V₂ = 25.065 L
How many moles of KBr are present in 500 ml of a 0.8 M KBr solution?
1. 1.6
2. .4
3. .625
4. 625
5. .0016
Answer:
2) 0.4 mol
Explanation:
Step 1: Given data
Volume of the solution (V): 500 mLMolar concentration of the solution (M): 0.8 M = 0.8 mol/LStep 2: Convert "V" to L
We will use the conversion factor 1 L = 1000 mL.
500 mL × 1 L/1000 mL = 0.500 L
Step 3: Calculate the moles of KBr (solute)
The molarity is the quotient between the moles of solute (n) and the liters of solution.
M = n/V
n = M × V
n = 0.8 mol/L × 0.500 L = 0.4 mol
A student mixes 5.00 mL of 0.0020 M Fe(NO3)3 with 3.00 mL of 0.0020 M KSCN solution and 2.00 mL water at a certain temperature. He places a sample of the resulting solution in a spectrometer, and measures the transmittance as 23% at 447 nm. What are the initial concentrations of [Fe3 ] and [SCN-]
Answer:
[Fe⁺³] = 0.0010 M
[SCN⁻] = 0.0006 M
Explanation:
First we calculate how many moles of Fe⁺³ and SCN⁻ were added, using the given volumes and concentrations:
Fe⁺³ ⇒ 5.00 mL * 0.0020 M = 0.010 mmol Fe⁺³SCN⁻ ⇒ 3.00 mL * 0.0020 M = 0.006 mmol SCN⁻Now we can calculate the initial concentrations, after calculating the new volume of the solution:
New volume = 5.00 mL + 3.00 mL + 2.00 mL = 10.00 mL[Fe⁺³] = 0.010 mmol / 10.00 mL = 0.0010 M[SCN⁻] = 0.006 mmol / 10.00 mL = 0.0006 MPlease help me, I can't figure this out. You have a 450.0 mL balloon filled with 0.0184 moles of Helium gas. The volume of the balloon will change, but the pressure of the gas inside will always match the 1.00 atm pressure outside. If the balloon is kept at a constant 25oC, how many moles of gas must you remove to shrink the balloon down to 200.0 mL?
Answer and Explanation:
V1/n1 = V2/n2
450.0 mL / 0.0184 mol = 200.0 mL / n2
n2 = 8.17X10^-3 mol
moles removed = 0.0184-8.17X10^-3 = 0.0102 mols removed, I think I'm right but I'm not 100% sure..
According to Avogadro's law, 0.008 moles of gas must be removed to shrink balloon to 200 ml.
What is Avogadro's law?Avogadro's law is a gas law which states that the total number of atoms or molecules has a direct proportion to the volume occupied by a gas at a constant temperature and pressure.
It is closely related to ideal gas equation as it links temperature, pressure, volume and the amount of substance.It is given as, V∝n,
The straight line graph of volume versus moles is a straight line passing through the origin which implies that zero moles of gas occupy zero volume.
Here, the number of moles is calculated as, V₁/n₁=V₂/n₂
Therefore on substitution, n₂=0.0184×200/450=0.008 moles.
Thus,0.008 moles are required to shrink the balloon to 200 ml.
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hi, if your looking for extra points (50+) and brainiest here is ur chance, answer this question correctly plz
Answer:
Answer is B
Explanation:
It's not A because we're boiling only water.
It's not C because the last dot for 2 cups ends at 70 min while the last dot for 4 cups ends at 90 min.
It's not D because water boils at around 100 C, as shown in the graph. The highest dot for both 2 cups and 4 cups were about the same near 100 C.
The graph shows that 4 cups of water is able to retain heat more (higher heat capacity), so it takes more time for water to cool down than 2 cups of water.
The percent by mass of iron(III) 1 Fe2S3
is _____%
Answer:
percent=69.94%
The following image is a prediction of how an earthquake would spread from the epicenter (marked by a star). Red indicates the
worst areas, and green indicates the places where there is the least shaking. Water is colored blue. Consider a seismic wave-an
earthquake that starts in the middle of the red area and travels outward along the surface of the earth.
Image courtesy of U.S. Geological Survey
Department of the Interio/
USOS
Point A is the same distance from the epicenter as point B. Using what you know about the movement of waves, how would you
expect the seismic waves to be different at point A and point B?
OA.
The waves would be larger at point A than at point B.
OB. The waves would be exactly the same at points A and B.
OC. The waves would arrive at point B before they arrived at point A.
OD
The ground would shake up and down at point A but back and forth at point B.
Answer:
its B
Explanation:
The earthquakes are occurring more in the land region of earth surface. Hence, the waves would arrive at point B before they arrived at point.
What is an earthquake?When two layers of the ground abruptly slide past one another, an earthquake results. The fault or fault plane is the area where they slide. The epicenter is the point on the earth's surface that is directly above the hypocenter, which is where the earthquake begins under the surface.
The energy that would typically force the blocks to move past one another is being saved up while the fault edges are glued together and the rest of the block is moving.
All that accumulated energy is released when the force of the sliding blocks ultimately displaces the resistance of the sharp edges of the fault and causes it to unstick. Like ripples on a pond, the energy radiates from the fracture in all directions as seismic waves. Therefore, point B in the land surface will first experience the seismic waves.
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Which set of coefficients will correctly balance the following skeleton equation?
Fe + Cl2 →FeCl3
Answer:
2Fe + 3Cl2 → 2FeCl3
Explanation:
PLEASE HELP ITS RLLY IMPORTANT.
Consider the model of Ammonia to the right. Which terms would be used to describe this model? Element, molecule, and/or compound? Explain your reasoning.
Plasma can be found naturally in
O water and ice.
O stars and lightning.
O wood and metal.
O comets and asteroids.
Answer:
stars and lightning. this is the answer ok
Scientists often use controlled experiments to answer questions. Choose ALL correct statements about controlled experiments. A) No changes are made to a test group in an experiment. B) A control group is used for comparison to other groups. C) Only one change can be made per test group in an experiment. D) Changes can only be made to the control group in an experiment. E) A controlled experiment must have a control group and test group(s).
Answer:
B) A control group is used for comparison to other groups.
E) A controlled experiment must have a control group and test group(s).
Explanation:
Answer:
B & E should be the answers
whose model was discarded as a result of Rutherford's model?
A Dalton's model
B Thomson's model
C Bohr's model
D Quantum's model
Answer:
A. Dalton's model
Explanation:
Dalton's model was discarded as a result of Rutherford's model.
[tex]{ }[/tex]
[tex]\small\sf\:\:\:\:\:\:\:\:{:}\:\Longrightarrow{\bold{\pink{\sf{Thomson's \:model}}}}[/tex]
thermal energy is what we call energy that come from ___ of matter
9.
Which of the following samples contains the greatest number of atoms?
a. 1 mole of CO2
c. 3 moles of N20
b. b. 2 moles of He
d. 4 moles of CO
Answer:
N2O.
Explanation:
Hello there!
In this case, according to the Avogadro's number, we can compute the number of atoms, taking into account that CO2 has three moles of atoms, N2O has three moles of atoms, He one mole of atoms and CO two moles of atoms:
[tex]atoms_{CO_2}=1molCO_2*\frac{3*6.022x10^{23}atoms}{1molCO_2}=1.81x10^{24}atoms\\\\atoms_{N_2O}=3molN_2O*\frac{3*6.022x10^{23}atoms}{1molN_2O}=5.4x10^{24}atoms\\\\atoms_{He}=2molHe*\frac{1*6.022x10^{23}atoms}{1molHe}=1.2x10^{24}atoms\\\\atoms_{CO}=4molCO*\frac{2*6.022x10^{23}atoms}{1molCO}=4.82x10^{24}atoms[/tex]
Thus, we infer that 3 moles of N2O have the greatest number of atoms.