The charge of an electron is negative (-1).
Complete the first row of the table.Express the volume in liters to three significant figures.
Answer:
[tex]V_2\text{ = 149 L}[/tex]Explanation:
Here, we want to get the missing volume
From Charles' law, we know that volume and temperature are directly proportional at constant pressure
Mathematically, we know that:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}_{}[/tex]We have to rewrite the formula in terms of the missing value as follows:
[tex]V_2\text{ = }\frac{V_1T_2}{T_1}[/tex]Before we proceed to input the values, we have to convert the temperatures in celsius to kelvin by adding 273.15 K to the celsius temperature
Thus, we have it that:
[tex]\begin{gathered} V_1\text{ = 112L} \\ V_2\text{ = ?} \\ T_1\text{ = 10.2 + 273.15 = 283.35 K} \\ T_2\text{ = 106.1 + 273.15 = 379.25 K} \end{gathered}[/tex]We can now proceed to substitute these values into the rewritten formula as follows:
[tex]V_2\text{ = }\frac{112\times379.25}{283.35}\text{ = 149 L}[/tex]Which statement best decribes the law of
conservation of mass?
d. The mass of the reactants and products is equal and is not dependent on the physical state of the substances explains the correct statement about the law of conservation of mass.
The law of conservation of mass is the law that states that matter or energy can neither be created nor destroyed. This means that the amount of matter in the universe is always the same. The law of conservation of mass is a fundamental law of physics and it is always obeyed by all physical processes.
The amount of matter in a closed system (one that is not subject to outside influences) will remain constant over time.
It is always obeyed even under the most extreme conditions, such as during nuclear reactions.
Hence, the correct option is d.
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A gas sample in a closed, expandable container of initial volume 5.00 L was allowed to warm from 25 °C to 35°C. What was its new volume?
Taking into account the Charles' Law, a sample of gas in a closed expandable container with an initial volume of 5.00 L was allowed to warm from 25°C to 35°C to a volume of 5.168 L.
Charles' LawCharles' Law consists of the relationship that exists between the volume and the temperature of a certain amount of ideal gas, which is maintained at a constant pressure.
This law says that for a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of motion of the gas molecules.
In summary, Charles's law is a law that says that when the amount of gas and the pressure remain constant, the ratio between the volume and the temperature will always have the same value:
V÷T=k
Considering an initial state 1 and a final state 2, it is fulfilled:
V₁÷ T₁= V₂÷ T₂
New volume in this caseIn this case, you know:
V₁= 5 LT₁= 25 °C= 298 KV₂= ?T₂: 35 °C= 308 KReplacing in Charles' law:
5 L÷ 298 K= V₂÷ 308 K
Solving:
(5 L÷ 298 K)× 308 K= V₂
5.168 L= V₂
Finally, the new volume is 5.168 L.
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What would the products of a double-replacement reaction between NaF andMgS be? (Remember: In double-replacement reactions, the two cationsswitch places and the two anions switch places.)O A. NaF and MgsB. MgF and NashO C. F2S and MgNa2O D. MgF2 and Na2SSUBMIT
Step 1
The reaction between NaF and MgS:
2NaF + MgS => Na2S + MgF2
(Remember: In double-replacement reactions, the two cations switch places and the two anions switch places.)
Answer: D. MgF2 and Na2S
A balloon is filled to a volume of 1.50 L with 2.50 moles of gas at 25 °C. With pressure and temperature held constant, what will be the volume of the balloon if 0.20 moles of gas are added?
The final volume of the balloon if 0.20 moles of gas are added will be 1.62 L.
What will be the volume of the balloon given that 0.20 moles of a gas is added to it?The volume of the balloon given that 0.20 moles of a gas is added to it is determined using the ideal gas equation as follows:
P₁V = nRT
Where;
P is pressureV is volumen is the number of moles of gasR is molar gas constant = 0.082 atm.L/K.molInitial volume, V₁ = 1.50 L
Initial mole of gas, n₁ = 2.50 mol
Initial temperature, T₁= 25°C or 298 K
Initial pressure, P₁ = RT₁n₁/V₁
P₁ = 0.082 * 298 * 2.50 /1.50
P₁ = 40.7 atm
With pressure and temperature held constant:
Final temperature, T₂ is equal to T₁ = 298 K
Final pressure, P₂ is equal to P₁ = 40.7 atm
Final moles of gas, n₂ = 0.20 + 2.5
n₂ = 2.70 mol
Final volume, V₂ = RT₂n₂/P₂
V₂ = 0.082 * 298 * 2.70 /40.7
V₂ = 1.62 L
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Which of the following are organic compounds? (a). CH3CH3 (b). NH3 (c). CH3SCH3 (d). CH3CH2OH (e). Mg(OH)2
CH3CH3
CH3SCH3
CH3CH2OH
Explanations;What are organic compounds?
Organic compounds are compounds that class of compounds that contains the carbon-hydrogen bond. This means that for a compound to be classified as an organic compound, they must contain the C-H bond in their compound
From the listed compouds, the compound that contains theC-H bonds are:
• CH3CH3
,• CH3SCH3
,• CH3CH2OH
These are therefore considered the required list of organic compounds from the given options
write any three chemical properties of carbon
Answer
• Carbon has the atomic symbol C,
,• Carbon is a nonmetallic chemical element with 4 electrons in its valence shell, which allows it to form 4 bonds forming compounds like CH₄.
,• Reactivity: Carbon does not dissolve in or react with water or acids.
,• The atomic mass of carbon is 12.011 g. It contains 6 protons in its nucleus.
How many moles in 2.24 L of a sample of gas.1 mol10 mole0.1 mole5 mol
Answer:
[tex]0.1\text{ mole}[/tex]Explanation:
Here, we want to get the number of moles in 2.24 L of a sample of gas
Mathematically,
At STP, 1 mole of a gas occupies a volume of 22.4 L
Thus x moles will occupy 2.24 L at STP
To get the value of x, we have it that:
[tex]\begin{gathered} x\times22.4\text{ = 1}\times2.24 \\ x\text{ = }\frac{2.24}{22.4} \\ \\ x\text{ = 0.1 mole} \end{gathered}[/tex]What is the Mass in grams of 1 formula unit or molecule of epsom salt MgSO4●7H2O?
MgSO4.7H2O
First of all, we need to calculate the molar mass of this molecule, using the periodic table.
Let's take each atomic mass of the elements that form this molecule from the periodic table.
Mg = 24.30 u
S = 32.06
O = 15.99 u
H = 1.007 u
Now, we have to do this:
Molar mass (g/mol) = 1 x 24.30 + 1 x 32.06 + 4 x 15.99 + 14 x 1.007 + 7 x 15.99
Molar mass = 246.3 g/mol
We have to be careful with this result because 246.3 g is the mass of 1 mole of MgSO4.7H2O and we want the mass of 1 formula unit or molecule.
Pay attention to this:
1 mole of MgSO4.7H2O = 246.3 g = 6.022 x 10^23 formula units or molecules of MgSO4.7H2O
(We want the mass of 1 molecule and we have just calculated the mass of 6.022x10^23 molecules)
----------------------------------------------------------------------------------------------------------------
For 1 formula unit or molecule:
246.3 g of MgSO4.7H2O ------------- 6.022 x 10^23 formula units or molec.
x ------------- 1 formula unit or molec.
[tex]x\text{ = }\frac{1formula\text{ unit x 246.3 g}}{6.022x10^{23}formula\text{ units}}=4.09x10^{-22}g[/tex]Answer: The mass of 1 formula unit or molecule of MgSO4.7H2O = 4.09x10^-22 g
Calculate the mass in grams of CO2 in 45.0 L of CO2 at STP
One of the options in the question is 22.4 L, which is the value for the volume of 1mol of gas in the old STP definition. Since there is no option for the updated STP conditions, we will need to assume it want in this old one.
In the old STP conditions, 1 mol of gas occupies 22.4 L, so we can use the rule of three to calculate how many moles are in 45.0L:
22.4L --- 1mol
45.0L --- n
[tex]\begin{gathered} \frac{22.4L}{45.0L}=\frac{1mol}{n} \\ n=45.0L\times\frac{1mol}{22.4L} \end{gathered}[/tex]Now, we want to convert to mass. Consulting the molar mass of CO₂, we can see that it is approximately 44.01g/mol, which is one of the optios. That is, in 1 mol of CO₂ there are 44.01 g. Using the rule of three:
1 mol --- 44.01 g
n --- m
[tex]\begin{gathered} \frac{1mol}{n}=\frac{44.01g}{m} \\ m=n\times\frac{44.01g}{1mol} \end{gathered}[/tex]Inputting the n we calculated earlier, we have:
[tex]m=45.0L\times\frac{1mol}{22.4L}\times\frac{44.01g}{1mol}\approx88.4g[/tex]So, there is approximately 88.4g of CO₂.
Hello I’ve been working on this for about an hour and still don’t get it May Someone help? Thank you!
Intensive properties: These are those that do not depend on the mass of the sample.
Density is an intensive property. For example, the density of an ice cube and an iceberg is the same (0.92 g/cm3 at temperatures below 0°C at sea level), which is less than that of water (1.0 g/cm^3 , under a temperature of approximately 4°C and a pressure at sea level, which is equal to 1.0 atm). Therefore, both an ice cube and an iceberg float on water.
2. Extensive properties: These are those that depend on the mass (“extension”) of the sample.
So mass is an extensive property and length as well.
Answer:
Extensive physical properties: mass of 18.45 g and 3.50 cm in length
Intensive physical properties: Density of 2.70 g/cm^3
The molecular mass of a compound with an empirical formula of SO2 is 256 g/mol. What is the molecular formula?
So,
The molecular mass of the empirical formula of the compound SO2, can be found multiplying the molar mass of each element by the number of atoms and then sum. Let me explain this here below:
[tex]\begin{gathered} S\colon\frac{32g}{\text{mol}}\cdot1 \\ O\colon\frac{16g}{\text{mol}}\cdot2 \\ mSO_2=\frac{64g}{mol} \end{gathered}[/tex]We're given that the molecular mass of the molecular formula is 256g/mol. So, we could find the ratio between the mass of both formulas:
[tex]\frac{256}{64}=4[/tex]This means that the mass of the molecular formula is 4 times greater than the mass of the empirical formula.
Thus, the molecular formula will be:
[tex]S_4O_8[/tex]2 NaOH + H2SO4 ------> 2 H2O + Na2SO4What is the mole ratio of H2O to H2SO4?
Answer
The mole ratio of H2O to H2SO4 is 2:1
Explanation
Given chemical equation:
[tex]2\text{NaOH }+H_2SO_4\rightarrow2H_2O+Na_2SO_4[/tex]From the balanced chemical equation above, 2 moles of NaOH react with sulfuric acid, 1 mole of H2SO4, to produce 2 moles of water and 1 mole sodium sulfate.
So, from the chemical equation, you have a 2:1 mole ratio between H2O and H2SO4
Standard temperature andpressure (STP) is [?] K and[ ] átm.
Remember that standard temperature and pressure (STP) is when the pressure is 1 atm and the temperature is 0 °C (273 K).
The answer is 273 K and 1 atm.
Use a diagram to illustrate how a carbon-carbon double bond forms.
Carbon forms a double bond with another carbon by sharing two pairs of electrons.
The electron dot diagram of the carbon double bond is illustrated in the figure below.
If the reaction in the given equation produced 0.364 moles of H2 gas at STP, how many liters would this amount of H2 occupy? [hint - the H2 gas is at STP! Is there a special conversion we can use?]
Equation: 6 HCl + 2 Al ---> 2 AlCl3 + 3 H2
In the given equation produced 0.364 moles of H₂ gas at STP, 22.4 liters volume would this amount of H₂ occupy.
What is moles?The mole, denoted by the sign "mol," is the volume of a system that has the same number of atoms in 0.012 kilograms of carbon-12 as there are elementary particles.
The equation becomes:
6 HCl + 2 Al → 2 AlCl₃ + 3 H₂
6 mol 2 mol 2 mol 3 mol
As we know,
one mole of a gas occupies 22.4 liters.
Here, in the above equation, 3 moles of H₂ gas is produced.
So, in STP condition 3 moles of H₂ gas occupy = 3 × 22.4 lit
= 67.2 lit
Thus, in the given equation produced 0.364 moles of H₂ gas at STP, 22.4 liters volume would this amount of H₂ occupy.
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Calculate how many grams of MgCl2 are needed to produce 12.15 grams
Answer
47.60 g
Explanation
Given that:
Molar mass of MgCl₂ = 95.20 g/mol
Mass of Mg produced = 12.15 grams
Equation: MgCl₂ → Mg + Cl₂
What to find:
To calculate the grams of MgCl₂ needed to produce 12.15 grams of Mg.
Step-by-step solution:
Step 1: Convert the mass of Mg produced to moles.
Using the molar mass of Mg (24.305 g/mol) and the mole formula, the moles of Mg produced is
[tex]Moles=\frac{mass}{molar\text{ }mass}=\frac{12.15\text{ }g}{24.305\text{ }g\text{/}mol}=0.49989714\text{ }mol[/tex]Step 2: Determine the moles of MgCl₂ needed to produce 12.15 g of Mg.
According to the given equation; 1 mol of MgCl₂ produced 1 mol of Mg
So, x mol of MgCl₂ will produce 0.49989714 mol of Mg
That is:
[tex]\begin{gathered} 1mol\text{ }MgCl₂=1mol\text{ }Mg \\ \\ x=0.49989714mol\text{ }Mg \\ \\ x=\frac{0.49989714mol\text{ }Mg}{1mol\text{ }Mg}\times1mol\text{ }MgCl₂ \\ \\ x=0.49989714mol\text{ }MgCl₂ \end{gathered}[/tex]Step 3: Convert the moles of MgCl₂ needed to produce 12.15 g of Mg to grams.
Using the molar mass of MgCl₂ = 95.20 g/mol, therefore the mass in grams of MgCl₂ needed to produce 12.15 g of Mg will be:
[tex]\begin{gathered} Mass\text{ }of\text{ }MgCl_2\text{ }needed=Molar\text{ }mass\times Moles \\ \\ Mass\text{ }of\text{ }MgCl_2\text{ }needed=95.20\text{ }g\text{/}mol\times0.49989714\text{ }mol \\ \\ Mass\text{ }of\text{ }MgCl_2\text{ }needed=47.60\text{ }g \end{gathered}[/tex]Hence, the grams of MgCl₂ needed to produce 12.15 grams of Mg is 47.60 g.
Draw the electron dot diagram for H2CO and determine how many bonded pairs of electrons there are.
Pleasseeeeeee
The electron dot diagram is shown in the image attached to this answer.
What is the electron dot diagram?We know that an electron dot diagram is used to show the electron pairs that are present in a compound. the electron dot diagram would include the symbols of the elements as well as the number of electron pairs that can be found on the valence shells of each of the atoms.
In this case, we can see that the electrons that are involved in a bod are shown as a single dash where the dash shows the electrons that are involved in a covalent bonding situation.
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When salt dissolves in water, it shows the property of
Answer: Solubility
Explanation:
The property by which substances dissolve in water is called solubility. Soluble substances (such as salt) dissolve in water.
Answer: Electical charge
Explanation:At the molecular level, salt dissolves in water due to electrical charges and due to the fact that both water and salt compounds are polar, with positive and negative charges on opposite sides in the molecule.
Which of these elements are often made in a lab?
transuranium
noble gas
alkali metal
halogen
Answer:
I am sure it's Transuranium.
Explanation:
Hope it's right
Which is the limiting reactant in the following chemical reaction: NH3 + 5 O2 —> 4 NO + 6 H2O, if 4 grams of O2 is used and 2 grams of NH3 is used ? Show work
The limitant reactant of a reaction is the reactant that we have the least number of mols considering its coefficient on the stoichiometry.
The reaction in this case is:
[tex]NH_3+5O_2\to4NO+6H_2O[/tex]The reactants are the one on the left side, so the answer can't be NO or H₂O.
The first thing to do is to calculate the number of moles of NH₃ and O₂, but for this we need their molar masses:
[tex]M_{NH_3}=1\cdot M_n+3\cdot M_H=(1\cdot14.0067+3\cdot1.00794)g/mol=17.03052g/mol[/tex][tex]M_{O_2}=2\cdot M_O=2\cdot15.9994g/mol=31.9988g/mol[/tex]Now, using them, let's calculate the number of moles of each:
[tex]\begin{gathered} M_{NH_{3}}=\frac{m_{NH_3}}{n_{NH_{3}}} \\ n_{NH_3}=\frac{m_{NH_3}}{M_{NH_{3}}}=\frac{2g}{17.03052g/mol}=0.11743\ldots.mol \end{gathered}[/tex][tex]\begin{gathered} M_{O_{2}}=\frac{m_{O_2}}{n_{O_{2}}} \\ n_{O_2}=\frac{m_{O_2}}{M_{O_{2}}}=\frac{4g}{31.9988g/mol}=0.12500\ldots mol \end{gathered}[/tex]Now, we can't compair directly, we need to consider their coefficients.
To do this, we divide the number of moles by the coefficient:
[tex]\begin{gathered} NH_3\colon\frac{n_{NH_3}}{1}=\frac{0.11743\ldots mol}{1}=0.11743\ldots mol \\ O_2\colon\frac{n_{O_{2}}}{5}=\frac{0.12500\ldots mol}{5}=0.025000\ldots mol \end{gathered}[/tex]Now, we can compair.
Since the value we have got to O₂ is less than NH₃, the limiting reactant is O₂
The question is in the photo (Sorry for being lazy lol )
• When Sodium Sulfate is mixed with Barium chloride, the following reaction occurs :
BaCl2 (aq) + Na2SO4 (aq) ------> BaSO4 ( s) + 2 NaCl( aq)• a precipitate is the solid that forms, the white solide will be BaSO4
,• So option 4 is correct. BaSo4.
According to the graph above what is the substances melting temperature?
ANSWER
At 90 degrees Celcius the substance will melt completely
EXPLANATION
Melting point is the process in which solid is completely converted to the liquid phase.
In the given graph, the point A the solid particles are closely packed due to strong intermolecular forces binding the particles together. When temperature is applied to the system, the particles of the solid substance vibrate about a point and the particles are said to move independently. Further increase in the temperature will break the bond holding the particles together and turn to liquid at 90 degrees Celcius
Therefore, at 90 degrees Celcius the substance will melt completely and turn to liquid.
A person has a 1.43mol sample of carbon dioxide. If the pressure if the sample is 34.56kpa, and the volume is 440.99mL, what will the temperature of the sample be in Kelvin?
Answer:
[tex]1.28K\text{ }[/tex]
Explanation:
Here, we want to get the temperature of the gas
We can use the ideal gas equation here
Mathematically, we have this as:
[tex]PV\text{ = nRT}[/tex]P is the pressure which is given as 34.56 kPa
V is the volume which is given as 440.99 mL
R is the molar gas constant which is 0.08205 L atm/mol k
n is the number of moles which is given as 1.43 mol
We need to convert the pressure to the correct unit (considering the molar gas consnat value in atm)
1 kPa = 0.00986923 atm
34.56 kPa will be = 34.56 * 0.00986923 = 0.341 atm
We need to convert the volume to Liters by dividing by 1000
We have that as 440.99/1000 = 0.44099 L
Finally,we rewrite the equation in terms of temperature and substitute the values as follows:
[tex]\begin{gathered} T\text{ = }\frac{PV}{nR} \\ \\ T\text{ = }\frac{0.341\times0.44099}{1.43\times0.08205}\text{ =1.28 K } \end{gathered}[/tex]Calculate the number of molecules in 8.21 x 10^-2 moles in (NH4)2Cr2O7
Answer
4.94x10^22 molecules
explanation
to calculate the number of molecules in 8.21x10^-2 moles ca be determined by using Avogadros number
we know that
1 mol has 6.022x10^23 molecules
therefore,
8.21x10^-2 moles have:
(8.21x10^-2) x (6.022x10^23)
= 4.94x10^22 molecules
A tank contains 8.5 L of fluorine at 268K and 549mm Hg. The gas is then transferred to a 5.0L tank. What temperature is required to obtain a final pressure of 675 mm Hg?
The temperature required to obtain a final pressure of 675 mm Hg194 is .86 K.
An ideal gas is a theoretical gas composed of many randomly transferring factor particles that aren't difficult to interparticle interactions. the best gasoline idea is beneficial because it obeys the precise gas law, a simplified equation of country, and is amenable to evaluation under statistical mechanics.
Volume is a degree of occupied three-dimensional space. it's far more frequently quantified numerically the usage of SI-derived gadgets or by way of diverse imperial gadgets. The definition of length is interrelated with the extent.
An ideal gas is described as one for which both the extent of molecules and forces between the molecules are so small that they have got no effect at the behavior of the gas.
Using the ideal gas equation:-
Given;
P₁ = 549mm Hg = 0.722369 atm
V₁ = 8.5 L
T₁ = 268 K
P₂ = 675 mm Hg = 0.89 atm
V₂ = 5
T₂ = ?
P₁V₁/T₁ =P₂V₂/T₂
T₂ = P₂V₂T₁/P₁V₁
= 0.89 × 5 × 268 / 8.5 × 0.72
= 194 .86 K
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Describe the solution if 274 g of potassium iodide (KI) is dissolved in 200 g of H2O at 10oC.
The following reaction takes place in an acidic solution. MnO4–(aq) + Cl–(aq) --> Mn2+ + Cl2(g) (unbalanced).Do Each Step Individually**: Write the half reactions. Balance the equations for atoms (except O and H). Balance the equations for atoms O and H using H2O and H+. Balance the charge in the half reactions. Multiply each half reaction by the proper number to balance charges in the reaction. Add the equations and simplify to get a balanced equation.
Answer
2MnO₄⁻(aq) + 10Cl⁻(aq) + 16H⁺ → 2Mn²⁺(aq) + 5Cl₂(g) + 8H₂O
Explanation
What is given:
The following reaction takes place in an acidic solution:
MnO₄⁻(aq) + Cl⁻(aq) → Mn²⁺(aq) + Cl₂(g) (unbalanced).
What to find:
To identify the half-reactions and balance the redox reaction.
Step-by-step solution:
Step 1: Identify the half-reactions.
The oxidation half-reaction is: Cl⁻(aq) → Cl₂(g)
The reduction half-reaction is: MnO₄⁻(aq) → Mn²⁺(aq)
Step 2: Balance the equations for atoms (except O and H).
Oxidation: 2Cl⁻(aq) → Cl₂(g)
Reduction: MnO₄⁻(aq) → Mn²⁺(aq)
Step 3: Balance the equations for atoms O and H using H₂O and H⁺.
Oxidation: 2Cl⁻(aq) → Cl₂(g)
Reduction: MnO₄⁻(aq) + 8H⁺ → Mn²⁺(aq) + 4H₂O
Step 4: Balance the charge in the half-reactions.
Oxidation: 2Cl⁻(aq) → Cl₂(g) + 2e⁻
Reduction: MnO₄⁻(aq) + 8H⁺ + 5e⁻ → Mn²⁺(aq) + 4H₂O
Step 5: Multiply each half-reaction by the proper number to balance charges in the reaction.
Oxidation: 2Cl⁻(aq) → Cl₂(g) + 2e⁻ x 5
Reduction: MnO₄⁻(aq) + 8H⁺ + 5e⁻ → Mn²⁺(aq) + 4H₂O x 2
↓
Oxidation: 10Cl⁻(aq) → 5Cl₂(g) + 10e⁻
Reduction: 2MnO₄⁻(aq) + 16H⁺ + 10e⁻ → 2Mn²⁺(aq) + 8H₂O
Step 6: Add the equations and simplify to get a balanced equation.
2MnO₄⁻(aq) + 10Cl⁻(aq) + 16H⁺ + 10e⁻ → 2Mn²⁺(aq) + 5Cl₂(g) + 8H₂O + 10e⁻
Simplifying the equation, we have:
2MnO₄⁻(aq) + 10Cl⁻(aq) + 16H⁺ → 2Mn²⁺(aq) + 5Cl₂(g) + 8H₂O
5 F2 (g) + 2 NH3 (g) → N2F4 (g) + 6 HF (g)If you reacted 7.78 moles of F2 how many moles of HF would be produced?
5 F2 (g) + 2 NH3 (g) → N2F4 (g) + 6 HF (g)
2. Determine mole proportions , then solveFrom the above balanced reaction, we can see that :
5 moles of F2 reacts to form : 6 moles of HF ,
so, 7.78moles F2 will give :x moles of HF
Therefore,x mole HF =( 6 moles HF * 7.78 mole F2)/ 5 mole F2
= 6 * 7.78/5
=9.336
≈9.34moles HF
• This means that , if you reacted 7.78 moles of F2 , ,9.34 moles of HF would be produced,.
Which pair of formulae represents two alkanes?a) CH4 and C8H18b) C2H6 and C5H8c) C3H6 and C5H12d) C10H8 and C4H8
Answer: the best option to answer the question is letter A
Explanation:
The question requires us to choose the option that presents the formula of two alkanes.
Alkanes are hydrocarbons that are saturated and acyclic (i.e., the molecule of an alkane do not present double or triple bonds between carbons and it is a linear structure). The general formula of alkanes tells us that there are double plus 2 the amount of hydrogen atoms as there is carbon atoms, as it follows:
[tex]C_nH_{2n+2}[/tex]where n indicates the number of carbon atoms in the molecule.
For example: we can say that the compound C2H6 is an alkane because it contains 2 carbon atoms (n = 2) and 6 hydrogen atoms (2n +2= 6).
Considering the options given by the question, only option A presents the formula of two alkanes:
CH4: n = 1; 2n+2 = 2+2 = 4
C8H18: n = 8; 2n+2 = 16+2 = 18
Therefore, the best option to answer the question is letter A.