state the solution for the quadratic equation depicted in the graph.

State The Solution For The Quadratic Equation Depicted In The Graph.

Answers

Answer 1

For this problem, we were provided with the graph of a quadratic equation, and we need to determine the solutions for this graph.

The solutions of a quadratic equation are the values of "x" that make the expression equal to "0". Therefore, we need to look at the graph for the values at which the graph crosses "y=0".

We have two points for this problem. The first one is approximately -5, and the second is 6.


Related Questions

James received 60 texts yesterday. Of those texts 3/5 were from his friend Chris. Of the texts from Chris 1/3 referenced football. How many texts did James receive about football?

Answers

Out of the 60 texts that James recieved,

[tex]60\cdot\frac{3}{5}\cdot\frac{1}{3}=12[/tex]

12 were about football.

Find mZCEF if mZCEF= 2x + 30,mZDEC = x + 102, and mZDEF = 132°DEFA) 30°C) 410B) 29°D) 320

Answers

1) Gathering the data

m∠CEF=2x +30

m∠DEC=x+102

m∠DEF=132

2) From the picture we infer that

m∠DEF = m∠CEF+m∠DEC

132 = m∠CEF +x +102

132-x-102=m∠CEF

m∠CEF=30

How can I draw a histogram to illustrate the information? How do I calculate the median age of the population?

Answers

We can see from the question that we have 8 class intervals, and they are all of the same lengths. We have the frequency for age in each interval.

We need to remember that a histogram is similar to a bar plot. However, it does not have any description on the x-axis. Instead, it will have the given class intervals.

In this case, we have that the class intervals do not overlap, and it is easier to graph the histogram as follows:

1. We need to graph the class intervals on the x-axis, and then we have to draw the frequencies for each interval on the y-axis.

At East Zone University (Ezu) thereare 564 students taking College Algebra or English Comp . 454 are taking college Algebra ,148 are taking English Comp and 38 are taking both College Algebra and English Comp . How many are taking Algebra but Not English Comp?

Answers

Step 1: Write the information given in a set notation.

[tex]\begin{gathered} n(U)=564,U\Rightarrow\mleft\lbrace The\text{ entire students}\mright\rbrace \\ E\Rightarrow\mleft\lbrace e\text{nglish comp.}\mright\rbrace \\ C\Rightarrow\mleft\lbrace\text{college algebra}\mright\rbrace \\ \end{gathered}[/tex]

Step 2: State the number of students that partake in each subject.

[tex]\begin{gathered} n(C\cap E)=38 \\ n(C\cap E^{\prime})=454-38=416 \\ n(E\cap C^{\prime})=148-38=110 \\ n(C\cup E)^{\prime}=x \end{gathered}[/tex]

Step 3: Draw a Venn diagram showing the information above

Step 4: To find the number of students that College Algebra but not English comp., we will check for the number of students that take only College Algebra. This is shown below

[tex]n(C\cap E^{\prime})=416[/tex]

Hence, the number of students that are taking Algebra but Not English Comp is 416

Will give brainliest if someone answers this problem correctly

Answers

The equation of the line in fully simplified slope intercept form is y = -5x + 8.

From the graph:

Take any two points:

suppose (1,3) and (2,-2)

slope m = y2 - y1 / x2 - x1

= -2 - 3 / 2 - 1

= -5/1

= -5

substitute m and (1,3) in y = mx + c

3 = -5*1 + c

3 = -5 + c

c = 3+5

c = 8

y = mx+c

y = -5x + 8.

Therefore the equation of the line in fully simplified slope intercept form is y = -5x + 8.

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A cylinder shaped above ground pool is 4.5 deep. If the diameter of the pool is 16 ft, determine the capacity of the swimming pool in cubic feet. Write your awnser in terms of pi

Answers

For this exercise you need to use the following formula for calculate the volume of a cylinder:

[tex]V=\pi r^2h[/tex]

Where "r" is the radius and "h" is the height of the cylinder.

In this case you can identify that:

[tex]h=4.5ft[/tex]

You know that the diameter of the pool is 16 feet. Since the radius is half the diameter:

[tex]\begin{gathered} r=\frac{16ft}{2} \\ \\ r=8ft \end{gathered}[/tex]

Knowing the radius and the height of the pool, you can substitute them into the formula and then you have to evaluate, in order to find the capacity of the swimming pool in cubic feet:

[tex]\begin{gathered} V=\pi(8ft)^2(4.5ft) \\ V=288\pi\text{ }ft^3 \end{gathered}[/tex]

The answer is:

[tex]288\pi\text{ }ft^3[/tex]

Go5. Given functions f(x) = 9x – 2, g(x) = 5 – 3x/2, and h(x) = 4x – 7/4(a) Find g(-8).(b) Find the value of x that makes g(x) = -7.(c) Find the value of x that makes f(x) = g(x).(d) Find the value of x that makes f(x) = h(x)(e) Find the x-intercept of h(x).

Answers

Answer

a) g(-8) = 17

b) When g(x) = -7, x = 8

c) When f(x) = g(x), x = (2/3)

d) When f(x) = h(x), x = (1/20)

e) x-intercept of h(x) = (7/16)

Explanation

f(x) = 9x - 2

g(x) = 5 - 3x/2

h(x) = 4x - 7/4

(a) Find g(-8).

g(x) = 5 - 3x/2

g(-8) means the value of g(x) when x = -8

g(-8) = 5 - [3×-8/2]

= 5 - (-12)

= 5 + 12

= 17

(b) Find the value of x that makes g(x) = -7.

g(x) = 5 - 3x/2

When g(x) = -7,

5 - 3x/2 = -7

5 - (3x/2) - 5 = -7 - 5

-(3x/2) = -12

[tex]\begin{gathered} \frac{-3x}{2}=-12 \\ \text{Cross multiply} \\ -3x\text{ = 2}\times-12 \\ -3x\text{ = -24} \\ \text{divide both sides by -3} \\ \frac{-3x}{-3}=\frac{-24}{-3} \\ x\text{ = 8} \end{gathered}[/tex]

(c) Find the value of x that makes f(x) = g(x).

f(x) = 9x - 2

g(x) = 5 - 3x/2

When f(x) = g(x)

9x - 2 = 5 - (3x/2)

9x + (3x/2) = 5 + 2

(21x/2) = 7

[tex]\begin{gathered} \frac{21x}{2}=7 \\ \text{Cross multiply} \\ 21x\text{ = 2}\times7 \\ 21x=14 \\ \text{Divide both sides by 21} \\ \frac{21x}{21}=\frac{14}{21} \\ x=\frac{14}{21}=\frac{2}{3} \end{gathered}[/tex]

(d) Find the value of x that makes f(x) = h(x)

f(x) = 9x - 2

h(x) = 4x - 7/4

When f(x) = h(x)

9x - 2 = 4x - (7/4)

9x - 4x = 2 - (7/4)

5x = (1/4)

[tex]\begin{gathered} 5x=\frac{1}{4} \\ \text{Divide both sides by 5} \\ \frac{5x}{5}=\frac{1}{4\times5} \\ x\text{ =}\frac{1}{20} \end{gathered}[/tex]

(e) Find the x-intercept of h(x).

h(x) = 4x - 7/4

The x-intercept is the value of x when h(x) = 0

When h(x) = 0

4x - (7/4) = 0

4x = (7/4)

[tex]\begin{gathered} 4x=\frac{7}{4} \\ \text{Divide both sides by 4} \\ \frac{4x}{4}=\frac{7}{4\times4} \\ x=\frac{7}{16} \end{gathered}[/tex]

Hope this Helps!!!

Students and adults purchased tickets for a recent school play. All tickets were sold atthe ticket booth (discounts of any type) were not allowed.Student tickets cost $8 each, and adult tickets cost $10 each. A total of $1,760 wascollected. 200 tickets were sold.a. Write a system of equations that can model the number of student and adulttickets sold at the ticket booth for the play.

Answers

Given:

Cost of students tickets is, c (s) = $8.

Cost of adult tickets is, c (a) = $10.

Total cost collected for by selling the tickets is, c (t) = $1,760.

Number of tickets sold is, n = 200.

The objective is to find the system of equations that can model the number of students and adults tickets sold at the booth.

Consider the number of students as x and number of adults as y.

Then, the equation of total numner of students will be,

[tex]\begin{gathered} \text{Number of students+Number of adults=n} \\ x+y=200\ldots\ldots\ldots..(1) \end{gathered}[/tex]

Now, the cost equation can be calculated as,

[tex]\begin{gathered} c(s)\cdot x+c(a)\cdot y=c(t) \\ 8x+10y=1760\ldots\ldots..\ldots..(2) \end{gathered}[/tex]

Hence, the system of equations that can model the number of students and adults tickets are x + y = 200 and 8x + 10y = 1760,

A science fair poster is a rectangle 36 inches long and 24 inches wide what is the area of the poster in square feet with sure to include the correct unit in your answer

Answers

Okay, here we have this:

Considering the provided information, we are going to calculate the area of the rectangle ins square inches and after we are going to convert it to square feet, so we obtain the following:

Area of the rectangle=36 inches * 24 inches = 864 square inches

Now, let's convert it to square feet, then we have:

[tex]\begin{gathered} 864in^2\cdot\frac{1ft^2}{144in^2} \\ =6ft^2 \end{gathered}[/tex]

Finally we obtain that the area in square feet of the rectangle is 6 square feet.

multiply or divide as indicated. be sure to reduce all answers to lowest terms. ( the numerator and denominator of the answer should not have any factors in common)

Answers

we have the expression

[tex]\frac{3a^2+3a}{a^2-36}\cdot\frac{a^2-6a}{12a}[/tex]

Simplify

we have that

a^2-36=(a+6)(a-6)

3a^2+3a=3a(a+1)

a^2-6a=a(a-6)

substitute in the given expression

[tex]\frac{3a(a+1)}{(a+6)(a-6)}\cdot\frac{a(a-6)}{12a}[/tex]

Simplify

[tex]\frac{(a+1)}{(a+6)}\cdot\frac{a}{4}[/tex]

therefore

the answer is

[tex]\frac{(a^2+a)}{(4a+24)}[/tex]

Point O is the center of this circle. What is m

Answers

The value of the angle ∠CAB subtended at the circumference of the circle is 48° .

It is given that the center of the circle is at O.

∠AOB = 96° .

We know that the angle subtended by an arc at the center is twice that subtended at the circumference.

Therefore ∠CAB = 1/2 of ∠AOB

or,  ∠CAB = 1/2 × 96°

or,  ∠CAB = 48°

An arc is any segment of a circle's circumference. The angle formed by the two line segments joining a point to an arc's endpoints at any given position is known as the arc's angle.

The circle in the following illustration features an arc that subtends an angle at both the center O and a point on the circumference AB is a chord.

The angle of an arc at the center of a circle is twice as large as its angle elsewhere on the circle's edge.

Therefore the value of ∠CAB is 48° .

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2. Yan also has three times as many apples as Xavier. Write a second expression for how many apples Yanhas.

Answers

For this case, let be "x" the number of apples Xavier has and "y" the number of apples Yan has.

According to the information given in the exercise, you know that Yan has three times as many apples as Xavier. In other words, to find the number of apples Yan has, you need to multiply the number of apples Xavier has by 3.

Then, knowing the above, you can write the following equation:

[tex]y=3x[/tex]

Therefore, you can determine that an expression that represents how many apples Yan has, is the one shown below:

[tex]3x[/tex]

The number of calories burnes by a 90-pound cyclist is proportional to the numer of hours the cyclist rides. the equation to represent this relationship is Y=225×. What is the constant of proportionality?

Answers

Answer

Constant of proportionality = 225

Explanation

If y varies directly as x, this can be written as

y ∝ x

Introducing the constant of variation, k, we have

y ∝ x

y = kx

So, for this question,

y = 225x

Constant of proportionality = 225

Hope this Helps!!!

The question is in the picture. Using the answer choice word bank, fill in the proportion to find the volume of the larger figure.

Answers

It is given that two similar solids have surface areas of 48 m² and 147 m², and the smaller solid has a volume of 34 m³.

It is required to find the volume of the larger solid.

Recall that the if the scale factor of similar solids is a/b, then the ratio of their areas is the square of the scale factor:

[tex]\frac{\text{ Area of smaller solid}}{\text{ Area of larger solid}}=\frac{a^2}{b^2}[/tex]

Substitute the given areas into the equation:

[tex]\frac{48}{147}=\frac{a^2}{b^2}[/tex]

Find the scale factor a/b:

[tex]\begin{gathered} \text{ Swap the sides of the equation:} \\ \Rightarrow\frac{a^2}{b^2}=\frac{48}{147} \\ \text{ Reduce the fraction on the right with }3: \\ \Rightarrow\frac{a^2}{b^2}=\frac{16}{49} \\ \text{ Take the square root of both sides:} \\ \Rightarrow\frac{a}{b}=\frac{4}{7} \end{gathered}[/tex]

Recall that if the scale factor of two similar solids is a/b, then the ratio of their volumes is the cube of the scale factor:

[tex]\frac{\text{ Volume of smaller solid}}{\text{ Volume of larger solid}}=\left(\frac{a}{b}\right)^3[/tex]

Let the volume of the larger solid be V and substitute the given value for the volume of the smaller solid:

[tex]\frac{34}{V}=\left(\frac{a}{b}\right)^3[/tex]

Substitute a/b=4/7 into the proportion:

[tex]\begin{gathered} \frac{34}{V}=\left(\frac{4}{7}\right)^3 \\ \\ \Rightarrow\frac{34}{V}=\frac{4^3}{7^3} \\ \\ \Rightarrow\frac{34}{V}=\frac{64}{343} \end{gathered}[/tex]

Find the value of V in the resulting proportion:

[tex]\begin{gathered} \text{ Cross multiply:} \\ 64V=343\cdot34 \\ \text{ Divide both sides by }64: \\ \Rightarrow\frac{64V}{64}=\frac{343\cdot34}{64} \\ \Rightarrow V\approx182.22\text{ m}^3 \end{gathered}[/tex]

Answers:

The required proportion is 34/V =64/343.

The volume of the larger solid is about 182.22 m³.

Write and equation of a line that passes through the point (5, -9) and is perpendicular to the line 2x + 11y = 22

Answers

The general equation of the line in slope - intercept form is :

[tex]y=m\cdot x+b[/tex]

Where m is the slope and b is y - intercept

Given the line : 2x + 11y = 22​

We need to write it in slope - intercept form to find the slope of it

so,

[tex]\begin{gathered} 2x+11y=22​ \\ 11y=-2x+22 \\ y=-\frac{2}{11}x+2 \end{gathered}[/tex]

So, the slope of the given line = -2/11

The required line is perpendicular to the given line

So, the product of the slope of the two lines = -1

So, if the slope of the given line is m , the slope of the required line will be = -1/m

So, the slope of the required line = 11/2

The equation of the required line will be :

[tex]y=\frac{11}{2}x+b[/tex]

Using the given point ( 5 , -9 ) to find the value of b

So, when x = 5 , y = -9

[tex]\begin{gathered} -9=\frac{11}{2}\cdot5+b \\ -9=\frac{55}{2}+b \\ b=-9-\frac{55}{2}=-\frac{73}{2} \end{gathered}[/tex]

so, the equation of the line is :

[tex]y=\frac{11}{2}x-\frac{73}{2}[/tex]

And the standard form will be :

[tex]\begin{gathered} 2y=11x-73 \\ \\ 11x-2y=73 \end{gathered}[/tex]

Two number cubes are rolled what is the probability that the sum of the numbers rolled is either a 1 and a 4 in either order

Answers

The first thing we have to know is that a cube with numbers is a dice that has 6 faces and that its numbers go from 1 to 6, so the probability that the sum of both dice gives 1 is zero, since the minimum that we are going to give is 2

[tex]P(sum=1)=0[/tex]

Now for the sum of both dice of 4 we have the following combinations

• 1 and 3

,

• 3 and 1

,

• 2 and 2

We have 3 combinatorics that we have to get the probability of each of the combinations in order to find our final probability

[tex]\begin{gathered} P(1|3)=P(1)P(3)=\frac{1}{6}\cdot\frac{1}{6}=\frac{1}{36} \\ P(3|1)=P(3)P(1)=\frac{1}{6}\cdot\frac{1}{6}=\frac{1}{36} \\ P(2|2)=P(2)P(2)=\frac{1}{6}\cdot\frac{1}{6}=\frac{1}{36} \end{gathered}[/tex]

The probability that the sum of 4 would be the sum of the probabilities of the combinatorcs

[tex]\begin{gathered} P(sum=4)=P(1|3)+P(3|1)+P(2|2) \\ P(sum=4)=\frac{1}{36}+\frac{1}{36}+\frac{1}{36} \\ P(sum=4)=\frac{3}{36} \\ P(sum=4)=\frac{1}{12} \end{gathered}[/tex]What is the probability of getting a 1 and a 4 in either order?

The probability of getting any number on a die will be 1/6 if we can get a 1 or a 4 then our population will be 2/6

[tex]\begin{gathered} P(1|4)=\frac{2}{6} \\ P(4|1)=\frac{2}{6} \\ P(1\&4)=\frac{2}{6}\cdot\frac{2}{6} \\ P(1\&4)=\frac{4}{36} \\ P(1\&4)=\frac{1}{9} \end{gathered}[/tex]

findvthe volume of the cylinder below to the nearest cubic foot.

Answers

Answer: The volume of the cylinder is 164.9 cubic foot

Given data

The diameter of the cylinder = 5ft

Height of the cylinder = 8.4 ft

Radius = diameter / 2

radius = 5/2

Radius = 2.5 ft

[tex]\begin{gathered} \text{Volume = }\pi\cdot r^2\cdot\text{ h} \\ \text{Volume = 3.14 }\cdot2.5^2\cdot\text{ 8.4} \\ \text{Volume = 3.14 x }6.25\text{ x 8.4 } \\ \text{Volume = }164.85ft^3 \\ Tothenearesttenth164.9ft^3 \end{gathered}[/tex]

The answer is 164.9 cubic foot

6. 6.5 ounces →g7.45 miles → km8.2.3 miles → cmCovert #6#7#8

Answers

Answer:

6. 184.275 gr

7. 72 km

8. 368000 cm

Explanation:

To make these conversions, we need to know the following relationships:

1 ounce = 28.35 gr

1 mile = 1.6 km

1 km = 100000 cm

Then, we can convert each expression as follows:

6.5 oz x 28.35gr / 1 oz = 184.275 gr

45 mi x 1.6 km / 1 mi = 72 km

2.3 mi x 1.6 km/ 1 mi = 3.68 km x 100000 cm/ 1km = 368000 cm

Therefore, the answers are:

6. 184.275 gr

7. 72 km

8. 368000 cm

. Noah may choose between two accounts in which to invest $4000. Account A offers 2.2% annual interest
compounded monthly. Account B offers continuous compound interest. Noah plans to leave his investment
untouched (no further deposits and no withdrawals) for 15 years.
(a) Which account will yield the greater balance at the end of 15 years?
(b) How much more money does Noah earn by choosing this more profitable account?
Answer:

Answers

Using the compound amount formula, account B will yield the greater balance at the end of 15 years and Noah earn $4 more money by choosing this more profitable account.

In the given question,

Noah may choose between two accounts in which to invest $4000.

Principal Amount(P) = $4000

Account A offers 2.2% annual interest compounded monthly.

Rate(r) = 2.2% = 0.022

In a year have twelve month so n=12

Account B offers continuous compound interest.

Noah plans to leave his investment untouched for 15 years.

Time(t) = 15

Formula for amount after t years = P(1+ r/n)^nt

Amount after 15 years = 4000(1+ 0.022/12)^12*15

Simplifying

Amount after 15 years = 4000(1+0.00183)^180

Amount after 15 years = 4000(1.00183)^180

Amount after 15 years = 4000*1.39

Amount after 15 years = $5560

Account B offers compounded continuously.

So formula used = Pe^(rt)

Amount after 15 years = 4000*e^(0.022*15)

Amount after 15 years = 4000*e^(0.33)

Amount after 15 years = 4000*1.391

Amount after 15 years = $5564

(a) We have to find which account will yield the greater balance at the end of 15 years.

As we can see in Account A amount after 15 years is $5550 and in Account B amount after 15 years is $5564.

So account B will yield the greater balance at the end of 15 years.

(b) We have to find how much more money does Noah earn by choosing this more profitable account.

Noah earn money more by profitable account=Account B amount-Account A amount

Noah earn money more by profitable account=$5564-$5560

Noah earn money more by profitable account=$4

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An animal shelter provides a bowl with 1.35 liters of water for 6 cats.About how much water will be left after the cats drink their average daily amount of water?Water ConsumptionAverage Amount(Liters per day)AnimalCanada Goose0.24Cat0.15Mink0.10Opossum0.30Bald Eagle0.16liter(s) of water will be left after the cats drink their average daily amount of water.

Answers

Data

1.35 litres of water

6 cats

0.15 litres per day

Procedure

Amount of water taken by the 6 cats

[tex]0.15\cdot6=0.9[/tex]

Left

[tex]1.35-0.9[/tex]

0.45 litres of water will be left

Roselle has three cups of popcorn and 6 oz of soda for a total of $246 calories. Carmel has one cup of popcorn and 14 oz of soda for a total of $274 calories. determine the number of calories per cup of popcorn and per ounce of soda

Answers

Let 'x' be the number of calories per cup of popcorn, and 'y' be the number of calories per ounce of soda.

Given that 3 cups of popcorn and 6 oz of soda constitute 246 calories,

[tex]3x+6y=246[/tex]

Also given that 1 cups of popcorn and 14 oz of soda constitute 274 calories,

[tex]x+14y=274[/tex]

Solve the equations using Elimination Method.

Subtract 3 times equation 2 from equation 1,

[tex]\begin{gathered} (3x+6y)-3(x+14y)=246-3(274) \\ 3x+6y-3x-42y=246-822 \\ -36y=-576 \\ y=16 \end{gathered}[/tex]

Substitute this value in equation 1, to obtain 'x' as,

[tex]\begin{gathered} 3x+6(16)=246 \\ 3x+96=246 \\ 3x=150 \\ x=50 \end{gathered}[/tex]

Thus, the solution of the system of equations is x=50 and y=16.

Therefore, there are 50 calories per cup of popcorn, and 16 calorie per ounce of soda.

During World War I, mortars were fired from trenches 3 feet below ground level. The mortars had a velocity of150 ft/sec. Determine how long it will take for the mortar shell to strike its target.• What is the initial height of the rocket? -3 ft.• What is the maximum height of the rocket? 348.56 ft• How long does it take the rocket to reach the maximum height ? 4.68750 sec.• How long does it take the rocket to hit the ground (ground level)? 9.35 sec.• How long does it take the rocket to hit a one hundred feet tall building that is in it's downward path?[ Select]• What is the equation that represents the path of the rocket? Select]

Answers

[tex]\begin{gathered} y=-\frac{g}{2}t^2+v_0t+y_0 \\ g\text{ in feets per seconds is 32} \end{gathered}[/tex][tex]\begin{gathered} \text{Now the height of the bilding is 100 hence y must be 100, i.e., y=100, hence one has} \\ 100=-16t^2+150t-3 \\ or \\ -16t^2+150t-103=0 \\ \text{the solutions are given by:} \end{gathered}[/tex][tex]\begin{gathered} t_1=\frac{-150+\sqrt[]{150^2-4(-16)(-103)}}{2(-16)} \\ t_2=\frac{-150-\sqrt[]{150^2-4(-16)(-103)}}{2(-16)} \end{gathered}[/tex][tex]\begin{gathered} t_1=\frac{-150+\sqrt[]{22500-6592}}{-32} \\ t_1=\frac{-150+\sqrt[]{15908}}{-32} \\ t_1=\frac{-150+126}{-32} \\ t_1=\frac{24}{-32}\text{ This solution is negative, it doesnt work. Let us s}ee\text{ the other solution:} \end{gathered}[/tex][tex]\begin{gathered} t_2=\frac{-150-\sqrt[]{150^2-4(-16)(-103)}}{2(-16)} \\ t_2=\frac{-150-\sqrt[]{22500^{}-6592}}{-32} \\ t_2=\frac{-150-\sqrt[]{15908}}{-32} \\ t_2=\frac{-150-126}{-32} \\ t_2=\frac{-276}{-32} \\ t=\frac{276}{32} \\ t=8.6\text{seg} \\ It\text{ takes 8.6 second to hit the bilding} \end{gathered}[/tex][tex]\begin{gathered} \text{the general equation of the parabolic motion is }y=-\frac{g}{2}t^2+v_0t+y_0\text{. In this case, this is} \\ y=-16t^2+150t-3 \end{gathered}[/tex]

Consider 4 consecutive odd integers. What is the sum of the 2nd and the 4th numbers if the first number is n?1. 2n+82.4n+123. n+64. 3n+6

Answers

4 consecutive odd integers

the next consecutive odd number is only 2 more than the first number so: n+2

n = first number

n + 2 = second number

n + 4 = third number

n + 6 = fourth number

the sum of the 2nd and the 4th numbers is:

n + 2 + n + 6 = n + n + 2 + 6 = 2n +8

2n + 8

Hence, option 1 is the correct answer

Determine the slope of the line represented by the equation: y=3/10x+6

Answers

The slope intercept form is given by the equation

[tex]\begin{gathered} y=mx+b \\ \text{where} \\ m\text{ is the slope} \\ b\text{ is the y-intercept} \end{gathered}[/tex]

Given:

[tex]y=\frac{3}{10}x+6[/tex]

Based on the given, it is already in the slope intercept form, and by inspection, we can determine the slope of the line is equal to 3/10.

Write an inequality for the word problem and answer the question about the inequality. Eric has an equal number of dimes and quarters that total less than 4 dollars. Could he have 12 dimes

Answers

Write an inequality for the word problem and answer the question about the inequality. Eric has an equal number of dimes and quarters that total less than 4 dollars. Could he have 12 dimes

Let

x -----> number of dimes coin

y -----> number of quarters coin

we have that

x=y ------> equation 1

and

0.10x+0.25y < 4 ------> inequality 1

substitute equation 1 in inequality 1

0.10x+0.25x < 4

solve for x

0.35x<4

x < 11.4

For 12 dimes

the value of x=12 not satisfy the inequality

that means

He couldn't have 12 dimes

Find the sum of the interior angles of the shape. Use the remaining angles to solve for x. Polygons Help91°120°899Sum of interior angles =degreesX =degrees

Answers

Solution

For this case we have 4 sides

Then the sum of the interior angles is givne by

[tex]180(n-2)=180(4-2)=180\cdot2=360\text{ }[/tex]

Sum of interior angles is 360º

And if we solve for x we can do this:

360-91-120-89= 60

x= 60 º

What is numeral value of 3/4 + 5/8

Answers

The given expression is

[tex]\frac{3}{4}+\frac{5}{8}[/tex]

We have to sum these fractions with the cross-rule. The image below shows this method.

E:Given f(x) = log x and g(x) = -x + 1,which is the graph of (fog)(x)?-2-2COMPLETEThe domain of (fog)(x) isDONEX>0x < 0X > 1x <1

Answers

Given data:

The first function is f(x) = log x .

The second function is g(x) = -x + 1.

The expression for (fog)(x) is,

[tex]\begin{gathered} \mleft(fog\mright)\mleft(x\mright)=f(g(x)) \\ =f(-x+1) \\ =\log (-x+1) \end{gathered}[/tex]

The domain of the above function is x<1.

What is 73 divided by 6

Answers

Answer:

12,1666666667

Step-by-step explanation:

I need help finding the answer and to show work

Answers

6) 4r + 8 + 5 = -15 - 3r

4r + 3r = -15 -8 - 5

7r = -28

r = -28/7

r = -4

8) 3n - 15 = 7n + n

-15 = 7n + n - 3n

-15 = 5n

n = -15/5

n = -3

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