Staples sells folders in packs of 12 for 4.80. Office max sells ffolders in packs of 17 for 7.50. Which has the better deal

Answers

Answer 1

The first step is to find the unit price of each seller. We were told that Staples sells folders in packs of 12 for 4.80. It means that the price per folder is

4.80/12 = 0.4 per folder

Also, Office max sells folders in packs of 17 for 7.50. It means that the price per pack is

7.50/17 = 0.44

Since the unit rate of Staples is low, then Staples has the better deal

Answer 2
Staples dived $4.80 by 12 $7.50 by 17 and the cheaper price is the better deal. In this case it’s staples at 40 cents whole office max is at 44 cents

Related Questions

5. A ball is thrown from a platform. The equation h = -4.9t2 + 18t + 14 gives the ball's height, h, in meters in terms of time, t, in seconds. Part A: What was the initial velocity of the ball? Part B: From what height was the ball thrown? Part C: If we measure the height in feet, how would the function change? What would be the gravity coefficient?

Answers

We have the following:

[tex]h=-4.9t^2+18t+14[/tex]

now,

This equation is divided as follows:

The quadratic part (-4.9t ^ 2) that represents the acceleration (gravity coefficient), the linear part (18t) that represents the velocity and the constant part (14) that is the initial height, therefore

Part A:

The initial velocity is 18 meters per seconds, the number that accompanies the linear term

Part B:

The initial height corresponds to 14 meters

Part C:

the equivalence between meters and feet is as follows

1 meter = 3.28 feet

Therefore the change of the function would be

[tex]\begin{gathered} h=3.28\cdot(-4.9t^2+18t+14) \\ h=-16.072t^2+59.04+45.92 \end{gathered}[/tex]

The gravity coefficiente is -16.072 feet per square seconds

Two ships were 700 miles apart at midnight and were headed directly towards each other if they collided at 10 a:m find the speeds of both ships if one was traveling 30 miles faster than the other

Answers

Given:

Two ships were 700 miles apart at midnight .

Let x be the speed of first ship and (x+30) be speed of second ship (faster ship).

The equation is,

[tex]\begin{gathered} Dis\tan ce=rate\times time \\ 10x+10(x+30)=700 \\ 10x+10x+300=700 \\ 20x=700-300 \\ 20x=400 \\ x=\frac{400}{20} \\ x=20 \end{gathered}[/tex]

Answer: the speed of first ship ( slower) is 20 miles and the speed of second ship ( faster) is 20+30=50 miles.

Find two numbers whose sum is 256, but whose product is a maximum?

Answers

ANSWER

The two numbers are 128 and 128

EXPLANATION

Let the two numbers be x and y.

We have that:

[tex]\begin{gathered} x+y=256 \\ x\cdot y=A \end{gathered}[/tex]

where A is a maximum.

From the first equation:

[tex]x=256-y[/tex]

Substitute that into the second equation:

[tex]\begin{gathered} (256-y)\cdot y=A \\ \Rightarrow256y-y^2=A \\ \Rightarrow y^2-256y+A=0 \end{gathered}[/tex]

The equation above is a quadratic equation in the general form:

[tex]ax^2+bx+c=0[/tex]

The parabola is downward facing and so, its vertex will be the maximum.

We can find the vertex (x, y) of the parabola by using:

[tex]x=\frac{-b}{2a}[/tex]

In the case given, the vertex can be found by using:

[tex]\begin{gathered} y=\frac{-(-256)}{2(1)}=\frac{256}{2} \\ y=128 \end{gathered}[/tex]

Recall that:

[tex]x=256-y[/tex]

Therefore, we have that:

[tex]\begin{gathered} x=256-128 \\ x=128 \end{gathered}[/tex]

Hence, the two numbers are 128 and 128.

I need help on this problem, it’s from my act prep guide

Answers

Answer:

Recall that:

[tex]\begin{gathered} \log _bx+\log _by=\log _b(xy), \\ \log _bx-\log _by=\log _b(\frac{x}{y})\text{.} \end{gathered}[/tex]

Therefore, Arjun used the properties incorrectly, he should´ve written:

[tex]\log _7x+\log _7y-\log _7z=\log _7(xy)-\log _7z=\log _y(\frac{xy}{z})\text{.}[/tex]

Find the value of x that makes A || B.AB5423142 3x10 and 23 = x + 30X=[? ]

Answers

∠2 and ∠3 are alternate interior angles. In order to A II B, the alternate interior angles must be equal.

Then,

[tex]\begin{gathered} \angle2=\operatorname{\angle}3 \\ 3x-10=x+30 \end{gathered}[/tex]

To find x, subtract x from both sides of the equation:

[tex]\begin{gathered} 3x-10-x=x+30-x \\ 3x-x-10=x-x+30 \\ 2x-10=30 \end{gathered}[/tex]

Now, add 10 to both sides of the equation:

[tex]\begin{gathered} 2x-10+10=30+10 \\ 2x=40 \end{gathered}[/tex]

Finally, divide both sides by 2:

[tex]\begin{gathered} \frac{2x}{2}=\frac{40}{2} \\ x=20 \end{gathered}[/tex]

Answer: x = 20.

Morgan wants to order at least $45 worth of merchandise, so she will get free shipping. If Morgan has picked out a key chain for $8 and a bag for $19, which inequality represents the amount of money, m, she needs to spend to get free shipping?

Answers

Morgan wants to order at least $45 worth of merchandise.

She spent $8 and $19. m represents the amount of money she needs to spend to get free shipping. The inequality is:

8 + 19 + m ≥ 45

m ≥ 45 - 8 - 19

m ≥ 18

Jonathan finds some nickels and quarters in his change purse. How many coins does he have if he has 12 nickels and 4 quarters? How many coins does he have if he has xx nickels and yy quarters?Total coins, 12 nickels and 4 quarters: Total coins, xx nickels and yy quarters:

Answers

Each nickel is worth 5 cents, and each quarter is worth 25 cents.

So, if we have 12 nickels, we can multiply this value by 5 to get its value in cents:

[tex]12\cdot5=60[/tex]

Similarly, if we have 4 quarters, we can multiply this value by 25 to get its value in cents:

[tex]4\cdot25=100[/tex]

So, in total, we have:

[tex]60+100=160[/tex]

So, for 12 nickels and 4 quarter, we have the value of 160 cents.

We can do this generally by setting the values of nickel and quarter to x and y.

If we have x nickels and each one is worth 5 cents, we have the value:

[tex]5x[/tex]

And if we have y quarters and each is worth 25 cents, we have the value:

[tex]25y[/tex]

So, in total, we have:

[tex]5x+25y[/tex]

So, for x nickels and y quarter, we have the value of 5x + 25y cents.

A board game uses a spinner like one below, where 0, 1, 2, and 3 are all equally likely.Each turn, a player spins twice and subtracts the results of the spins. The game only looks at non-negativedifferences. For example, if a player spins a 1 and a 3, the difference is 2.Let X represent the difference in given turn.Which tables represents the theoretical probability distribution of X?Choose 1 answer:

Answers

The possible outcomes are:

0: 1-1, 2-2, 3-3, 4-4 => 4

1: |2-1|, |3-2|, |4-3|, |1-2|, |2-3|, |3-4| => 6

2: |3-1|, |4-2|, |1-3|, |2-4| => 4

3: |4-1|, |1-4| => 2

The total number of outcomes is 4+6+4+2 = 16. Then, the table that represents the theoretical distribution is:

Answer:

It should be B, the one that has 0,1,2,3 on the top.

Step-by-step explanation:

right on khan

I’m sorry to keep bothering you guys but you’re the third person that I’m trying the last two their answers went partway and then stopped I just need to see how this is worked out

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01

Data:

Graph:

Height of Golf Ball

Step 02:

functions:

We must analyze the graph to find the solution.

Function:

Non linear

intercepts:

x-intercepts: 0 and 120

y-intercept: 0

symmetry:

x = 50

positive:

domain: (0 , 120)

negative:

there are no negative values

increasing:

interval on x: (0 , 50)

decreasing:

interval on x: (50, 120)

That is the full solution.

Find the value of x, if m<3 is 13x-13 and m<4 is 8x+67.2 points43Your answer

Answers

Answer

x = 6

Explanation:

m<3 and m<4 are supplementary angles

supplementarrh angles is 180 degrees

m<3 + m<4 = 180

13x - 13 + 8x + 67 = 180

collect the like terms

13x + 8x - 13 + 67 = 180

21x + 54= 180

Isolate 21x

21x = 180 - 54

21x = 126

divide both sides by 21

21x/21 = 126/21

x = 6.

Therefore, x = 6

that the triangles below are congruent select all options that would provide enough information to prove the triangles are congruent

Answers

The correct options are options C and D;

1) Angle C is congruent to E

2) BA and FD are congruent

Here, we want to select the options that would prove that the triangles are congruent

We can get that from the markings on the diagram

As we can see from the question, we already have two sides being equal as we can see from the markings

Hence, we need an extra information to see through that the two triangles are indeed congruent

If the sides BA and FD are equal, it will simply mean that the three sides of the triangle are equal. In that case, the two triangles are congruent by SSS (side-side-side)

Also, if the angles C and E are congruent, we will have that the two triangles are similar by the SAS (side-angle-side)

So, the correct options are C and D

Just need help with number 3. Please. Thankyou! Been stuck on this one for a while now.

Answers

A cosine function is given in the form:

[tex]y=A\cos(x-h)+k[/tex]

where |A| is the amplitude, h is the horizontal shift (also called a phase shift) and k is the vertical shift.

The function is given to be:

[tex]\begin{gathered} y=8\cos(\frac{1}{4}x) \\ A=8 \end{gathered}[/tex]

Therefore, the amplitude is 8.

(6,3) and (2, -9)equation in slope intercept form

Answers

Let:

(x1,y1)=(6,3)

(x2,y2)=(2,-9)

[tex]\text{slope}=m=\frac{y2-y1}{x2-x1}=\frac{-9-3}{2-6}=\frac{-12}{-4}=3[/tex]

Using the point-slope equation:

[tex]\begin{gathered} y-y1=m(x-x1) \\ y-3=3(x-6) \\ \text{Solve for y:} \\ y=3x-15 \end{gathered}[/tex]

You might need: Calculator h(r) = 72 +11r - 26 1) What are the zeros of the function? Write the smaller r first, and the larger r second.

Answers

1) Notice that:

[tex]r^2+11r-26=r^2+13r-2r-2(13).[/tex]

Grouping like terms we get:

[tex]\begin{gathered} r^2+13r-2r-2(13)=r(r+13)-2(r+13) \\ =(r-2)(r+13). \end{gathered}[/tex]

Therefore:

[tex]h(r)=(r-2)(r+13).[/tex]

Then the zeros of h(r) are:

[tex]r=2\text{ and }r=-13.[/tex]

2) Notice that:

[tex]\begin{gathered} h(r)=r^2+11r-26=r^2+11r+(\frac{11}{2})^2-(\frac{11}{2})^2-26 \\ =(r+\frac{11}{2})^2-\frac{121}{4}-26=(r+\frac{11}{2})^2-\frac{225}{4}. \end{gathered}[/tex]

Therefore the vertex of the given parabola is:

[tex](-\frac{11}{2},-\frac{225}{4}).[/tex]

Answer:

1)

[tex]\begin{gathered} smaller\text{ r=-13,} \\ larger\text{ r=2.} \end{gathered}[/tex]

2) Vertex:

[tex](-\frac{11}{2},-\frac{225}{4}).[/tex]

What is the image of (8,−4) after a dilation by a scale factor of 1/4 centered at the origin?

Answers

Answer:

[tex](2, -1)[/tex]

Step-by-step explanation:

When dilating with a scale factor of [tex]k[/tex] about the origin, [tex](x,y) \longrightarrow (kx, ky)[/tex].

57 es 95% de que número

Answers

60

1) Considerando que 57 es 95% de algun numero, vamos escribir esta ecuacion

0.95x = 57 Escribindo 95% como 0.95, dividir los dos lados por 0.95

x =57/0.95

x=60

2) Asi 57 es 95% de 60.

If trapezoid ABCD was dilated by a scale factor of 2\3 to form trapezoid A'B'C'D,what is the area of trapezoid ABCD?The area of trapezoid A'B'C'D is 12 units^2

Answers

As a general rule, we know that the area of a dilated figure is the area of the original figure multiplied by the square of the scale factor. We can see this in the following formula:

[tex]A=A^{\prime}\cdot k^2[/tex]

where A is the area of the original figure, A' is the area of the dilated figure and k is the scale factor.

In this case, we have that the area of the dilated figure (trapezoid A'B'C') is 12 square units, and the scale factor is k = 2/3. Then, using the equation we get the following:

[tex]\begin{gathered} A^{\prime}=12 \\ k=\frac{2}{3} \\ \Rightarrow A=12\cdot(\frac{2}{3})^2=12\cdot(\frac{4}{9})=\frac{12\cdot4}{9}=\frac{48}{9}=5\frac{1}{3} \\ A=5\frac{1}{3}u^2 \end{gathered}[/tex]

therefore, the area of trapezoid ABCD is 5 1/3 square units

solve the equation 3.75x+3.7=1.7+1.75xA 10 B -1 C 1D .1

Answers

The question is given to be:

[tex]3.75x+3.7=1.7+1.75x[/tex]

Step 1

Multiply every number by 100:

[tex]\begin{gathered} 3.75x\cdot100+3.7\cdot100=1.7\cdot100+1.75x\cdot100 \\ 375x+370=170+175x \end{gathered}[/tex]

Step 2

Subtract 370 from both sides:

[tex]\begin{gathered} 375x+370-370=170+175x-370 \\ 375x=175x-200 \end{gathered}[/tex]

Step 3

Subtract 175x from both sides:

[tex]\begin{gathered} 375x-175x=175x-200-175x \\ 200x=-200 \end{gathered}[/tex]

Step 4

Divide both sides by 200:

[tex]\begin{gathered} \frac{200x}{200}=-\frac{200}{200} \\ x=-1 \end{gathered}[/tex]

ANSWER

The correct option is OPTION B, the SECOND OPTION.

Arithmetic and Geometric Sequences (Context)

Answers

The formula for compound interest

A = P( 1 + r/n) ^ (nt)

A is the amount in the account at the end

P is the principal balance or the amount initially invested

r is the annual interest rate in decimal form

n is the number of times it is coupounded per year

t is the number of years

A = 1800 ( 1+ .0375/1) ^ (1*6)

A = 1800 ( 1.0375)^6

A = 2244.92138

Rounding to the nearest cent

A = 2244.92

2. Zero can be a negative number.OTrueFalse

Answers

In the real numbers system, any negative number x meets the following property:

[tex]x<0[/tex]

The symbol "<" means that x is smaller than 0 but never equal to 0 so the definition of negative numbers excludes the zero. Then this statement is False.

Find the intersection if possibleExpress your answer in interval notation

Answers

Solution:

The first set given as;

[tex][-9,-1)[/tex]

Then in list form, the set is;

[tex]\lbrace-9,-8,-7,-6,-5,-4,-3,-2\rbrace[/tex][tex]\lbrace-9,-8,-7,-6,-5,-4,-3,-2\rbrace[/tex]

Also, the second set given as;

[tex](-3,4)[/tex]

Then, in list form, the set is;

[tex]\lbrace-2,-1,0,1,2,3\rbrace[/tex]

The intersection of the two sets is;

[tex]\begin{gathered} \lbrace-9,-8,-7,-6,-5,-4,-3,-2\rbrace\cap\lbrace-2,-1,0,1,2,3\rbrace=\lbrace-2\rbrace \\ \\ \text{ Note that there are some real numbers on the number line} \end{gathered}[/tex]

Thus, the solution in interval notation is;

[tex](-3,-1)[/tex]

ANSWER: (-3,-1)

PLEASE HELP ME!!!!!

Subtract the linear expressions.

(-3 + 4x - 9x) - (9 - 11x + 7)

Answers

6x + 19 is the difference between both the linear expression.

What is linear equation ?

In a linear equation, the variable's greatest power always equals 1. It is also referred to as a one-degree equation. The usual form of a linear equation with one variable is written as Ax + B = 0. In this case, x is a variable, A is a coefficient, and B is a constant.

Calculation

-3 + 4x -9x - 9 + 11x - 7

= -19+6x

= 6x + 19

learn more about linear equation here :

brainly.com/question/11897796

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Answer:

Between the two linear expressions, there is a difference of 6x + 19.

How do linear equations work?

In a linear model, the largest power of the variable is always equal to 1. Another name for it is a one-degree equation. Ax + B = 0 is how a statistical model with one term is typically written. In this scenario, the variables x and A are coefficients, while B is a standard.

Calculation -3+4x-9x-09+11x-7-9

= -19+6x

= 6x + 19

Step-by-step explanation:

I'm also in k12 hope this helps! :3

evaluate each using the values given y+y-(y-x); use x = 1, and y = 4Options12154

Answers

The given expression is

y + y - (y - x)

We would substitute x = 1 and y = 4 into the expression. it becomes

4 + 4 - (4 - 1)

8 - 3

= 5

the correct answer is 5

in DEF, DE =29 feet, EF = 26 feet, and DF = 32 feet. Which correctly gives the order of the angle measure from largest to smallest?

Answers

Answer:

Choice A.

Explanation:

The sketch of the triangle is given below

The angle opposite the longest side is the widest.

The longest side is DF; therefore, the angle opposite to it (angle E) is the widest.

The second-longest side is DE; therefore, the angle opposite to it (angle F) is the second widest.

Lastly, the third-longest side is EF; therefore, the angle opposite to it (angle D) is the third widest (or the smallest angle).

Hence, the angle measures when ordered from greatest to smallest are

∠E, ∠F, ∠D

which is given by choice A.

i need the x and y intercept

Answers

so, the x intercept is when the line touches the x-axis, we can see from the graph, the line touches x-axis on 3, so the point is

[tex](3,0)[/tex]

the y intercept is when the lone touches the y-axis, we can see from the graph, the line touches y-axis on -9, so the point is

[tex](0,-9)[/tex]

unit 4: solving quadratic equations
Homework 9: quadratic equations applications
Help please !

Answers

Answer:

what is the Question

Step-by-step explanation:

math is ezy :3

? What the question

6x - 5y = - 4Direct variationХ5?k=Not direct variation2y = 14xDirect variationk ==Not direct variation

Answers

Direct Variation is of the form (directly proportional);

[tex]\begin{gathered} y\propto x \\ y=kx \end{gathered}[/tex]

While indirect variation (inversely proportional) is of the form;

[tex]\begin{gathered} y\propto\frac{1}{x} \\ y=\frac{k}{x} \end{gathered}[/tex]

So, for each of the given question we want to determine if they are direct or indirect variation;

1.

[tex]\begin{gathered} 6x-5y=-4 \\ -5y=-4-6x \\ -5y=-6x-4 \\ y=\frac{-6x-4}{-5} \\ y=\frac{6}{5}x+\frac{4}{5} \end{gathered}[/tex]

Therefore, this is a Direct variation with proportionality constant;

[tex]k=\frac{6}{5}[/tex]

2.

[tex]\begin{gathered} 2y=14x \\ y=\frac{14x}{2} \\ y=7x \end{gathered}[/tex]

Therefore, this is a Direct variation with proportionality constant;

[tex]k=7[/tex]

For the function f(x) = x2 + 2x - 15 solve the following.f(x) = 0

Answers

Given:

[tex]f\mleft(x\mright)=x^2+2x-15[/tex]

To find: The value of x when

[tex]f(x)=0[/tex]

Explanation:

Since,

[tex]f(x)=0[/tex]

We can write it as,

[tex]\begin{gathered} x^2+2x-15=0 \\ x^2+5x-3x-15=0 \\ x(x^{}+5)-3(x-5)=0 \\ (x+5)(x-3)=0 \\ x=-5,3 \end{gathered}[/tex]

Hence, the solution is x = -5, and 3.

Final answer: The solution is,

[tex]\mleft\lbrace-5,3\mright\rbrace[/tex]

2.Solve the inequality for x. Show each step to the solution.12x > 3(5x – 2) – 15

Answers

we have the inequality

12x > 3(5x-2)-15

step 1

apply distributive property right side

12x > 15x-6-15

combine like terms right side

12x > 15x-21

step 2

Adds both sides 21

12x+21 > 15x-21+21

simplify

12x+21 > 15x

step 3

subtract 12x both sides

12x+21-12x > 15x-12x

21 > 3x

step 4

Divide by 3 both sides

21/3 > 3x/3

7 > x

Rewrite

x < 7

We want to factor the following expression: x^3 - 25 which pattern can we use to factor the expression? U and V are either constant integers or single variable expression.

Answers

The pattern that is used to factor the expression x³ - 25 is given as follows:

B. (U - V)(U + V).

What is the subtraction of perfect squares?

The subtraction of perfect squares is a notable product that gives the simplification of an expression containing the subtraction of perfect squares, as the multiplication of the square roots of the two terms subtracted by the square of the two terms subtracted, as follows.

a² - b² = (a - b)(a + b).

In the context of this problem, the expression is presented as follows:

x³ - 25.

The square root of x³ is obtained as follows:

sqrt(x³) = (x³)^(0.5) = x^(3 x 0.5) = x^1.5 = [tex]\sqrt{x^3}[/tex]

The square root of 25 is obtained as follows:

5.

Because 5² = 25.

Then, applying the subtraction of perfect squares notable product, the factored expression is given as follows:

[tex]x^3 - 25 = (\sqrt{x^3} - 5)(\sqrt{x^3} + 5)[/tex]

Which is the pattern given by option B.

Missing Information

The complete problem is given by the image shown at the end of the answer.

A similar problem, also featuring subtraction of perfect squares, is presented at https://brainly.com/question/28792378

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