We are being asked to subtract one function from another function.
[tex](f-g)(x)=f(x)-g(x)[/tex][tex]\begin{gathered} (f-g)(x)=(3x^2+4x-6)-(6x^3-5x^2-2)=3x^2+4x-6-6x^3+5x^2+2 \\ (f-g)(x)=-6x^3+8x^2+4x-4 \end{gathered}[/tex]Answer: .
I'll show you the picture of the question I'm struggling with
The proportion of the first row with the second row is
[tex]\frac{7}{12}=\frac{8}{16}=\frac{6}{12}=\frac{10}{20}=\frac{2}{4}=\frac{1}{2}[/tex]that is, we have the proportionality 1:2, which correspond to the pink square.
-16 = m - 3 solve m
m = -13
Explanations:-16 = m - 3
Add 3 to both sides of the equation
-16 + 3 = m - 3 + 3
-13 = m
m = -13
Find the algebraic form g(x) of the function g whose graph is produced by the following transformations on thegraph of f(x) = ×: The graph of f is reflected vertically, expanded horizontally by a factor of 2, shifted right 6 units, and shifteddown 4 units. Include graphs off and g as a part of your answer.
Given the function f(x) = x
We will find the function g(x) whose graph is produced by the following transformations on the graph of f(x)
First, The graph of f is reflected vertically
So,
[tex]\begin{gathered} f(x)\rightarrow f(-x) \\ g(x)=-x \end{gathered}[/tex]Second, expanded horizontally by a factor of 2
So,
[tex]\begin{gathered} f(-x)\rightarrow f(-2x) \\ g(x)=-2x \end{gathered}[/tex]Finally, shifted right 6 units, and shifted down 4 units.
So,
[tex]\begin{gathered} f(-2x)\rightarrow f(-2(x-6))-4 \\ g(x)=-2(x-6)-4 \end{gathered}[/tex]Simplifying the function g(x):
[tex]g(x)=-2x+8[/tex]The graph of the function (f) and (g) will be as shown in the following figure:
In order to accumulate enough money for a down payment on a house, a couple deposits $513 per month into an account paying 6% compounded monthly. Ifpayments are made at the end of each period, how much money will be in the account in 3 years?Type the amount in the account: $(Round to the nearest dollar)
Step 1- Write out the Future Value Ordinary Annuity formula:
[tex]FV=C\times\frac{(1+r)^n-1}{r}[/tex]Where,
[tex]\begin{gathered} FV=\text{ the future value} \\ C=\text{monthly payments} \\ r=\text{ the interest rate} \\ n=\text{ the number of payments} \end{gathered}[/tex]Step 2- Write out the given values and substitute them into the formula:
[tex]\begin{gathered} C=\$513,r=0.06, \\ n=3\times12=36 \end{gathered}[/tex]Substituting the given values into the formula, we have:
[tex]FV=513\times\frac{(1+0.06)^{36}-1}{0.06}[/tex]Hence,
[tex]FV=513\times\frac{(1.06)^{36}-1}{0.06}[/tex]Hence, the future value is approximately:
[tex]FV\approx\$61109.00[/tex]Hence, the amount in the account in 3 years is:
$61109.00
How to: determine if the side lengths could form a triangle. use an inequality to prove your answer
We need to simply use the triangle inequality Theorem, This theorem state that the sum of the two side lengths of a triangle must always be greater than the third side.
Now let's check from the given lengths
16 + 21 = 37 and 37 is less than 39 which is the third side
Hence, it cannot form a triangle
A scientist records 61 more
shooting stars in the fall than in the spring.
There are 15 shooting stars in the spring.
How many shooting stars are in the fall?
Answer:
I call this a simple solution because it does not involve probability distributions. It just requires simple knowledge of probability, that’s it!
The question says any 15-minute interval, so one hour can be thought of as four 15-minute intervals.
Now, the question asks the probability of seeing at least one shooting star in those four 15-minute intervals.
Such a probability is the same as the complement of the probability of not seeing any shooting star in those four 15-minute intervals.
All of those four 15-minute intervals are independent of each other. So, their combined probability is the product of the individual probabilities.
The individual probability of not seeing any shooting star in an interval of 15 minutes is 1 - 0.2 = 0.8.
So, the combined probability of not seeing any of the shooting stars in the four intervals is: 0.8 * 0.8 * 0.8 * 0.8 = 0.8⁴ = 0.4096
Now, the complement of its probability is 1 - 0.4096 = 0.5904
So, that is the answer or the probability of seeing at least one shooting star in an interval of an hour.
Step-by-step explanation:
Why?
Before diving into the Poisson process, let me explain why such a demonstration is helpful even if the problem can be solved simply.
The problems we encounter in the real-life can’t be solved by mere simple probability formulas. That is the reason more complex concepts are developed in mathematics. They help model real-life scenarios. When the scenarios are not exactly the same as the mathematical model, we do some assumptions and approximate the scenarios with mathematical models. Then, we do the modeling.
Mathematical modeling requires prior practice. To visualize the mathematical models and naturalize ourselves to such (abstract) models, good practice with the problems always helps. So, even if these problems can be solved easily using simpler methods, such problems provide us a good opportunity to practice mathematics and modeling.
Assumptions
At first, let’s see if the assumptions of the Poisson process hold here. The number of events can be counted. The occurrences of the events are independent of each other. The average rate at which the events occur can be calculated and let’s assume two events can not occur exactly at the same instant in time.
So, all the assumptions of the Poisson process hold here. That gives us the green light to move forward.
Mathematical Work
Let’s assume the rate of λ per minute. Then, the rate corresponds to 15λ per quarter.
Now, the formula for the probability distribution is:
P(X = x) = μ^x * e^-μ / x!
Before we go further, let’s understand the mathematical statement. The mathematical statement expresses the probability of seeing x events in a time period. μ is the average number of events seen in the time period. The time period can be a minute, an hour, or even a day. It can be any time period.
At first, let’s see the first statement — In any 15-minute interval, there is a 20% probability that you will see at least one shooting star.
Here, the interval is of 15 minutes. So, the average number of events in the interval is 15λ. The probability of seeing 0 events (i.e X = 0) is:
P(X = 0) = μ⁰ * e^-(15λ) / 0! = 1 / e^(15λ) — — (1)
(1) is equal to 80% as the probability of at least one event happening is 20%.
So, 1 / e^(15λ) = 0.8
or, e^(15λ) = 1.25
or, 15λ = ln(1.25) = 0.2231
=> λ = 0.0149 / min
So, the average number of events (shooting stars) is 0.0149 per minute.
Now, the average number of events in an hour is:
0.0149 * 60 = 0.8926 / hour
So, the Poisson distribution expression becomes:
P(X = x) = 0.8926^x * e^-0.8926 / x! — — (2)
Here, the time period is an hour.
Now, let’s find the probability of not having even a single event in an hour:
P(X = 0) = 0.8926⁰ * e^-0.8926 / 0! = 0.4096
So, the probability of having at least one event is the complement of the above probability.
So, P(X≥1) = 1 - P(X=0) = 1 - 0.4096 = 0.5904
Step-by-step explanation:
Solve for x and simplify your solutions:x^2 = 63Select ALL the correct answers.answer choices include:18√79√7-3√73√7-18√7-9√7
In order to find the correct answers, let's simplify the equation by calculating the square root of both sides of the equation:
[tex]\begin{gathered} x^2=63\\ \\ x=\pm\sqrt{63}\\ \\ x=\pm\sqrt{3^2\cdot7}\\ \\ x=\pm3\sqrt{7} \end{gathered}[/tex]Therefore the correct options are 3√7 and -3√7.
For a football game, 5,600 tickets were sold. The price for each adult ticket is $27.25, and the price for each childrens ticket is $12.00. The total revenue for the game was $117,311.50. How many children's tickets were sold for the football game?
We have a problem that can be solved with a system of equations.
First we need to identify the equations of the system.
We have two unknown variables, the number of adult's tickets sold and the number of children's tickets sold. Let's call them:
- number of adult's tickets sold: x
- number of children's tickets sold: y.
The total number of tickets sold, 5600, is the sum of these:
[tex]x+y=5600_{}[/tex]And since the prices are 27.25 (adult) and 12.00 (children), the total revenue (117311.50) will be the sum of these prices multiplyied by the number of tickets of each of them:
[tex]27.25x+12.00y=117311.50[/tex]So, the system of equations is:
[tex]\begin{gathered} _{}x+y=5600_{} \\ 27.25x+12.00y=117311.50 \end{gathered}[/tex]Since we want y the number of children's tickets sold, we can solve for the other varible, x, in one equation, and substitute into the other.
Solving in the first equation, we have:
[tex]\begin{gathered} x+y=5600 \\ x=5600-y \end{gathered}[/tex]And substituting into the other:
[tex]\begin{gathered} 27.25x+12.00y=117311.50 \\ 27.25(5600-y)+12.00y=117311.50 \\ 27.25\cdot5600-27.25y+12.00y=117311.50 \\ 152600-15.25y=117311.50 \\ -15.25y=117311.50-152600 \\ -15.25y=-35288.50 \\ y=\frac{-35288.50}{-15.25} \\ y=2314 \end{gathered}[/tex]Since y is the number of children's tickets sold, then the number of children's tickets sold is 2314.
If f(x) = 6x + 8(x + 2), find f-1(x).f-1(x) = (x - 16)/14f-1(x) = x +16/14f-1(x) = -x - 16/14f-1(x) = -x + 16/14
SOLUTION:
We want to find the inverse of f(x);
[tex]f(x)=6x+8(x+2)[/tex]We solve for x;
[tex]\begin{gathered} y=6x+8(x+2) \\ y=6x+8x+16 \\ y=14x+16 \\ y-16=14x \\ x=\frac{y-16}{14} \\ interchange\text{ }y\text{ }and\text{ }x \\ f^{-1}(x)=\frac{x-16}{14} \end{gathered}[/tex]Thus the answer is OPTION A
Amer class, Mrs. Sandoval picked up several piece of paper containing students' work from SHAVN ELLA LEVI 263.140)14) + 2(3.4)() 602.86 units 21314)(a)) 2512 unit 23.425) - 2/3 4729 RUBY KATRINA LORENZO 22 28.141815) 218.1489 663.12 units 2[3.2) 203.4)(48) + 213.)(4) 30144 units Which student found the total surface area of a cylinder with a height that was two times greater than its radius? O Ruby O Lorenzo O Ella O Levi
we know that
the total surface of a cylinder is equal to
[tex]SA=2B+Ph[/tex]where
B us the area of the circular base
P is the circumference of the circular base
h is the height of the cylinder
we have
h=2r
so
[tex]B=\pi\cdot r^2[/tex][tex]P=2\pi\cdot r^{}[/tex]substitute
[tex]SA=2(\pi\cdot r^2)+(2\pi\cdot r)\cdot h[/tex]substitute the value of h
[tex]\begin{gathered} SA=2(\pi\cdot r^2)+(2\pi\cdot r)\cdot2r \\ SA=2\pi r^2+4\pi r^2 \\ SA=6\pi r^2 \end{gathered}[/tex]therefore
the answer is Rudybecauser=4 and h=8Solve each system by elimination 10x-2y= -44x+5y= -19
10x - 2y = -4 ==== (1)
4x + 5y = -19 ==== (2)
To solve the system we should make the coefficients of y have the same values to eliminate it, then
Multiply equation (1) by 5 and equation (2) by 2
5(10x) - 5(2y) = 5(-4)
50x - 10y = -20 ===== (3)
2(4x) + 2(5y) = 2(-19)
8x + 10y = -38 ===== (4)
Now add equations (3) and (4) to eliminate y
(50x+8x) + (-10y + 10y) = (-20 + -38)
58x + 0 = -58
58x = -58
Divide both sides by 58 to find x
x = -1
Substitute the value of x in equation (1) or (2) to find the value of y
4(-1) + 5y = -19
-4 + 5y = -19
Add 4 to both sides
-4 + 4 + 5y = -19 + 4
0 + 5y = -15
5y = -15
Divide both sides by 5 to find y
y = -3
The solution of the system is (-1, -3)
7. In physics, the equation PV = nRT is called the ideal gas law. It is used toapproximate the behavior of many gases under different conditions. Whichequation is solved for T?
ANSWER:
[tex]\frac{PV}{nR}=T[/tex]STEP-BY-STEP EXPLANATION:
We have the following equation:
[tex]PV=nRT[/tex]We solve for T:
[tex]\begin{gathered} \frac{PV}{nR}=T \\ T=\frac{PV}{nR} \end{gathered}[/tex]Therefore, the correct answer is option 2.
solve the system of equations by graphing. y = -5x + 4 andy = 3x + 4
1) To solve this System of Solutions graphically, we'll need to plot those lines described by those respective equations.
2) Let's set two tables
y=-5x +4
x | y
1 -1 ( 1,-1)
2 -6 ( 2,-6)
3 -11
y=3x + 4
x | y
1 | 7 ( 1,7)
2 |10 ( 2,10)
3 | 13
2.2 Let's plot those equations and interpret the results:
3) As these lines have point (0,4) as their common point. Therefore we can state that the solution for this consistent system is S=(0,4)
If f(x) = 2x + 3 and g(x) = 4x - 1, find f(4).A. 11B. 15C. 5D.17
You have the following expression for the function f(x):
f(x) = 2x + 3
In order to calculate the value of f(4), just replace x=4 into the function f(x) and simplify it:
f(4) = 2(4) + 3
f(4) = 8 + 3
f(4) = 11
Hence, the answer is:
A) 11
Find the solution of the system of equations. 2x + 3y=-4 , x + 9y = 13
(-5, 2)
1) Solving this Linear System with the method of Addition/Elimination:
2x + 3y=-4
x + 9y = 13 x-2 Multiply the whole equation by -2
2x +3y = -4
-2x -18y= -26
--------------------
-15y= -30
15y= 30 Divide both sides by 15
y = 2
2) Plug into the simpler equation y=2
x +9y = 13
x + 9(2) = 13
x +18 = 13
x =13-18
x= -5
3) So the answer is (-5, 2)
Find at least three solutions to the equation y = 3x - 1, and graph the solutions as points on the coordinate plane.Connect the points to make a line. Find the slope of the line.
To find a solution to the equation y = 3x - 1, we have to replace a variable by a number and compute the other variable.
Assuming x = 0, then
y = 3(0) - 1
y = 0 - 1
y = -1
Then, the point (0, -1) is a solution
Assuming x = 1, then
y = 3(1) - 1
y = 3 - 1
y = 2
Then, the point (1, 2) is a solution
Assuming x = 2, then
y = 3(2) - 1
y = 6 - 1
y = 5
Then, the point (2, 5) is a solution
In the next graph, the solutions and the line are shown
The slope of the line that passes through the points (x1, y1) and (x2, y2) is computed as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Replacing with points (0, -1) and (1,2) we can compute the slope, as follows:
[tex]m=\frac{2-(-1)}{1-0}=3[/tex]The circle below has center S. Suppose that m QR = 84°. Find the following.
Given:
[tex]\text{m}\hat{\text{QR}}=84^{\circ}[/tex]b) To find:
[tex]\angle QSR[/tex]We know that,
[tex]\hat{QR}=\angle QSR=84^{\circ}[/tex]Thus, the answer is,
[tex]\angle QSR=84^{\circ}[/tex]a) To find:
[tex]\angle QPR[/tex]We know that,
[tex]\begin{gathered} \angle QPR=\frac{1}{2}\angle QSR \\ \angle QPR=\frac{1}{2}(84^{\circ}) \\ \angle QPR=42^{\circ} \end{gathered}[/tex]Thus, the answer is,
[tex]\angle QPR=42^{\circ}[/tex]what is the smallest angle of rotational symmetry of a pentagon
Answer:
72°
Step-by-step explanation:
Origin is completely 360° and its divided into 5 sides. So,360÷5=72°
(40s + 100t) + 6 distributive property to write the products in standard form
The given expression is
[tex](40s+100t)\div10[/tex]We will use the distributive property to solve it
Divide each term in the bracket by 10
[tex]\frac{40s}{10}+\frac{100t}{10}[/tex]Simplify each term
[tex]\begin{gathered} \frac{40s}{10}=4s \\ \\ \frac{100t}{10}=10t \\ \\ 4s+10t \end{gathered}[/tex]The answer in standard form is 4s + 10t
Question 4 When changing 67,430,000 to scientific notation, how many places is the decimal point mc 5 07
Observe that the given number is 67,430,000.
If we express it as a scientific notation, then we would have to move the decimal point 7 spots to the left.
[tex]6.743x\times10^{-7}[/tex]Therefore, the answer is 7.There are 4 options on the dessert menu at a restaurant. Bill and Laura like all of the choices equally, so theyeach choose a dessert at random from the menu. What is the probability that Bill will choose apple pie andLaura will choose strawberry cheesecake for dessert? Express your answer as a decimal. If necessary, roundyour answer to the nearest thousandth.O 0.083O 0.250 0.938O 0.063
So Bill and Laura like all of the choices equally. This means that the probability of each of them choosing one out of the four is the same for each options. So this probability is 1 out of 4: 1/4. So the probability of Bill choosing apple pie is 1/4 and that of Laura choosing strawberry cheesecake is also 1/4. The probability of both making those choices at the same time is given by the product of the mentioned probabilities. Then the probability we are looking for is:
[tex]\frac{1}{4}\cdot\frac{1}{4}=\frac{1}{16}=0.063[/tex]Then the answer is the fourth option.
4/8=28/x show your work
Given:
[tex]\frac{4}{8}=\frac{28}{x}[/tex]Simplify the equation,
[tex]\begin{gathered} \frac{4}{8}=\frac{28}{x} \\ 4x=28(8) \\ 4x=224 \\ x=\frac{224}{4} \\ x=56 \end{gathered}[/tex]Answer: x = 56.
convert the rectangular equation to polar form.Assume a > 0x=18
To convert a rectangular equation to polar forma, we use
[tex]x=r\cos (\theta),y=r\sin (\theta)[/tex]In the equation x=18, we only have x, so
[tex]\begin{gathered} 18=r\cos (\theta) \\ r=\frac{18}{\cos(\theta)}=18\sec (\theta) \end{gathered}[/tex]Patios Plus sold an outdoor lighting set for $119.95. The Markup on the set was $25.99. Find the selling price as a percent of cost. Round to the nearest percent
The selling price as a percent of the cost is given by the ratio between the selling price and the the cost. The selling price is given, which is $119.95 the cost is given by the difference between the selling price and the Markup($25.99). Combining all those informations in an equation, we have
[tex]\frac{119.95}{119.95-25.99}=1.27660706684\ldots[/tex]To write this as a percentage, we just multiply the ratio by 100.
[tex]1.27660706684\ldots\times100=127.660706684\ldots\approx128[/tex]The selling price is 128% of the cost.
Let f(x)=x2-2 and g(x)=9-X. Perform the composition or operation indicated.(fg)(-7)
Given the functions below
[tex]\begin{gathered} f(x)=x^2-2 \\ g(x)=9-x \end{gathered}[/tex]We are to find (fg)(-x)
SOLUTION
First of all, we have to get (fg)(x)
[tex](fg)(x)=(x^2-2)(9-x)[/tex]Expand the function
[tex]\begin{gathered} (fg)(x)=x^2(9-x)-2(9-x) \\ (fg)(x)=9x^2-x^3-18+2x \\ \therefore(fg)(x)=-x^3+9x^2+2x-18 \end{gathered}[/tex]Let us now solve for (fg)(-7)
[tex]\begin{gathered} (fg)(-7)=-(-7)^3+9(-7)^2+2(-7)-18 \\ (fg)(-7)=343+441-14-18=752 \end{gathered}[/tex]Hence,
[tex](fg)(-7)=752[/tex]
Please give me an explanation and the answers on question 3
We will illustrate on how to find the inverse function.
First, recall that the inverse function is a function that given the output of a function, it will give you back the input out of which that output came from.
when athe function has a formula, we can follow some steps to find the inverse function. Suppose we are given the function
[tex]f(x)=3x+5[/tex]Now, we first change f(x) with the letter y. So we get
[tex]y=3x+5[/tex]now, we interchange variables x and y. So we get
[tex]x=3y+5[/tex]Finally we solve this equation for y. We will first subtract 5 on both sides and then divide both sides by 3. So we get
[tex]y=\frac{x\text{ -5}}{3}[/tex]and now we replace the y with the symbol of the inverse function. So we have that
[tex]f^{\text{ -1}}(x)=\frac{x\text{ -5}}{3}[/tex]Given the recursive formula shown, what are the first 4 terms of the sequence? A) 5, 25, 100, 400B) 5, 14, 60, 236C) 5, 25, 125, 625D) 5, 20, 80, 320
SOLUTION:
Step 1:
In this question, we have the following:
Step 2:
Given:
[tex]\begin{gathered} f(n)=5,\text{ if n =1,} \\ f(n)\text{ = 4 f(n-1) if n > 1} \end{gathered}[/tex][tex]\begin{gathered} f(1)\text{ = 5} \\ f(2)\text{ = 4 f(2-1) = 4 x f(1) = 4 x 5 = 20} \\ f(3)\text{ = 4f(3-1) =4 x f(2) = 4x20 = 80} \\ f(4)\text{ = 4 f(4-1)=4xf(3) = 4 x 80 = 320} \\ \text{Hence, the first 4 terms of the sequence are:} \\ 5,\text{ 20, 80 , 320 --- OPTION D} \end{gathered}[/tex]Linear Inequalities (Level 1)Sep 30, 10:57:41 PMWatch help videoSolve the following inequality for p. Write your answer in simplest form.8p + 10 > -5p - 1P
Solve the following inequality for p. Write your answer in simplest form.
8p + 10 > -5p - 1
group terms
8p+5p > -1-10
13p > -11
p > -11/13
solve the following system y=5x-33x-8y=24
The given system is
[tex]\mleft\{\begin{aligned}y=5x-3 \\ 3x-8y=24\end{aligned}\mright.[/tex]We can multiply the first equation by 8, then we sum and solve for x.
[tex]\mleft\{\begin{aligned}8y=40x-24 \\ 3x-8y=24\end{aligned}\rightarrow3x=40x\mright.[/tex]Then we, solve for x.
[tex]\begin{gathered} 40x-3x=0 \\ 27x=0 \\ x=\frac{0}{27}=0 \end{gathered}[/tex]Now we use this value to find y.
[tex]\begin{gathered} 3x-8y=24 \\ 3(0)-8y=24 \\ -8y=24 \\ y=\frac{24}{-8}=-3 \end{gathered}[/tex]Therefore, the solution of the system is x = 0 and y = -3.Evaluate the following quotient. Leave your answer in scientific notation.(7.2 x 103) = (5 x 10)AnswerХ
To do a quotient between two numbers in scientific notation we must do the usual division with the number, and subtract the exponents, for example:
[tex]9\times10^7\div3\times10^3=3\times10^4[/tex]Therefore, we must divide
[tex]7.2\times10^3\div5\times10^5[/tex]Do the division:
[tex]\frac{7.2}{5}=1.44[/tex]Now we do the division of the exponents
[tex]\frac{10^3}{10^5}=10^{3-5}=10^{-2}[/tex]Now we put it all together:
[tex]7.2\times10^3\div5\times10^5=1.44\times10^{-2}[/tex]