Suppose that an item regularly costs $100.00 and is discounted 24%. If it is then marked up 24%, is the resulting price $100.00? If not, what is it?

Answers

Answer 1

Given the cost of item =$ 100

If it is discounted 24%

So, the discount will be = 24% of 100 = 0.24 x 100 = $24

The cost after discount = 100 - 24 = $76

If it is marked up 24%

so, the rise will be = 24% of 76 = 0.24 x 76 = $18.24

The cost after marked up = 76 + 18.24 = $94.24

So, the answer is : No, and the cost will be = $94.24


Related Questions

The number line represents -4 1/2 +3 1/4 What is the sum?

Answers

Answer

Option C is correct.

-4 ½ + 3 ¼ = -1 ¼

Explanation

We are asked to solve the expression

-4 ½ + 3 ¼

To solve this, we first convert the mixed fractions into improper fractions

-4 ½ = -(9/2)

3 ¼ = (13/4)

We can then take the LCM by expressing both fractions to have the same denominatorr

-4 ½ = -(9/2) = -(18/4)

3 ¼ = (13/4)

-4 ½ + 3 ¼

= -(18/4) + (13/4)

= (-18 + 13)/4

= (-5/4)

= -1 ¼

Hope this Helps!!!

Which sequence is generated by the function f(n+1)(n)-2for f(1)=10?

Answers

Given the following:

[tex]\begin{gathered} f(n+1)=f(n)-2 \\ \text{where f(1)=10} \end{gathered}[/tex]

To generate the sequence, we have:

[tex]\begin{gathered} \text{when n=1} \\ f(1+1)=f(1)-2 \\ f(2)=10-2=8 \end{gathered}[/tex][tex]\begin{gathered} \text{when n=2} \\ f(2+1)=f(2)-2 \\ f(3)=8-2=6 \end{gathered}[/tex][tex]\begin{gathered} \text{when n=3} \\ f(3+1)=f(3)-2_{} \\ f(4)=6-2=4 \end{gathered}[/tex][tex]\begin{gathered} \text{when n=4} \\ f(4+1)=f(4)-2 \\ f(5)=4-2=2 \end{gathered}[/tex]

Hence, the correct option is Option D

Given that y varies directly with x, and y=28 when x=7 What is y when x=52

Answers

Answer:

y=208

Explanation:

If y varies directly with x, the equation of variation is:

[tex]y=kx[/tex]

When y=28 and x=7

[tex]\begin{gathered} 28=7k \\ k=\frac{28}{7} \\ k=4 \end{gathered}[/tex]

The equation connecting y and x is:

[tex]y=4x[/tex]

Therefore, when x=52

[tex]\begin{gathered} y=4\times52 \\ y=208 \end{gathered}[/tex]

find a decimal that is equal to each fraction. round to the nearest thousandth if necessary 271/100

Answers

[tex]\frac{271}{100}\text{ = 2.71}[/tex]

Here, we want to find the decimal equal to the given fraction

To do this, we look at the number which is the denominator

The number here is 100

What this mean is that we are going to shift the decimal point two times (due to 2 zeros; if 1000, 3 times)

The decimal point is not visible on the numerator which means it is at the back of the last number 1 but it is not necessary to write it

By virtue of the movement, the decimal point will be moved two times, which will make it land at the back of the first number 2

So, we have the expression as;

[tex]\frac{271}{100}\text{ = 2.71}[/tex]

Find the perimeter of the figure below. Notice that one side length is not given.Assume that all intersecting sides meet at right angles.Be sure to include the correct unit in your answer.8 ftftft2ft9 ft151Х5?7 ft14 ftCheck2020 MCG Edus

Answers

We are asked to find the perimeter of the given figure.

Recall that the perimeter is basically the sum of all the sides in the figure.

But the length of one side is missing that can easily be found.

Let me draw the figure to illustrate the idea.

Step 1: Find the length of the missing side

As you can see in the above figure,

We found the length of the missing side by subtracting the length of 9 ft from the 14 ft, which will give us the length of the missing side drawn in red color.

Step 2: Find the parameter of the figure

Now we can proceed to find the perimeter of the figure.

Add up the lengths of each side

[tex]\begin{gathered} Perimeter=5ft+15ft+14ft+7ft+9ft+8ft \\ Perimeter=58ft \end{gathered}[/tex]

Therefore,

The length of the missing side is 5 ft

The perimeter of the figure is 58 ft

Note:

The unit of the perimeter of the rectangle is ft

Whereas the unit of the area of the rectangle is ft^2

In ∆JKL, j=7.9inches, k=2 inches and l =9.8. find the measure of

Answers

By cosine rule,

[tex]\cos K=\frac{j^2+l^2-k^2}{2jl}[/tex]

Where j = 7.9 inch, k = 2 inch and l = 9.8

[tex]\cos K=\frac{7.9^2+9.8^2-2^2}{2\times7.9\times9.8}=\frac{154.45}{154.84}=0.99748[/tex][tex]\begin{gathered} \cos K=0.99748 \\ K=\cos ^{-1}0.99748=4.067\approx4^o \end{gathered}[/tex]

Solution: The measure of angle K is 4 degrees

Options for the first box are: One valid solution, two valid solutions Options for the second box are: no extraneous solutions, one extraneous solution Options for the third box: 5, 0, 2, 4

Answers

ANSWER

The equation has one valid solution and one extraneous solution.

A valid solution for x is 5

[tex]\sqrt[]{x-1}-5=x-8[/tex]

Add 5 to both-side of the equation

[tex]\sqrt[]{x-1}-5+5=x-8+5[/tex][tex]\sqrt[]{x-1}=x-3[/tex]

Take the square of both-side

[tex]x-1=(x-3)^2[/tex]

x - 1=x²-6x + 9

Rearrange

x² - 6x + 9 - x + 1 =0

x² - 7x + 10 = 0

We can solve the above quadratic equation using factorization method

x² - 5x - 2x + 10 = 0

x(x-5) - 2(x - 5) = 0

(x-5)(x-2)=0

Either x -5 =0 OR x-2 =0

Either x =5 or x=2

To check whether the equation is valid or non-extraneous, let's plug the values into the equation and see if it gives a true statement

For x =5

[tex]\sqrt[]{5-1}-5=5-8[/tex]

[tex]\sqrt[]{4}-5=-3[/tex][tex]-3=-3[/tex]

The above is a true statement

For x =2

[tex]\sqrt[]{2-1}-5=2-8[/tex][tex]1-5=2-8[/tex]

The above is not a true statement

Therefore, the equation has one valid solution and one extraneous solution.

A valid solution for x is 5

I sent the attachment cuz I rather not type :3

Answers

If two matrices are equal, then each of its elements must be equal.

If:

[tex]\begin{bmatrix}{a+3} & {4} \\ {6} & {b-1}\end{bmatrix}=\begin{bmatrix}{-3} & {4} \\ {6} & {2}\end{bmatrix}[/tex]

This means that:

[tex]\begin{gathered} a+3=-3 \\ 4=4 \\ 6=6 \\ b-1=2 \end{gathered}[/tex]

Isolate a and b from their respective equations to find their value:

[tex]\begin{gathered} a+3=-3 \\ \Rightarrow a=-3-3 \\ \therefore a=-6 \end{gathered}[/tex][tex]\begin{gathered} b-1=2 \\ \Rightarrow b=2+1 \\ \therefore b=3 \end{gathered}[/tex]

Therefore, the value of a is -6 and the value of b is 3.

Write the congruence statements represented by the markers in each diagram

Answers

The congruence statements

PS= QR

<PSQ= <QRP

<UTV= <VWX

<TUV= <XWV

What is Congruence?

If all three corresponding sides and all three corresponding angles are equal in size, two triangles are said to be congruent. Slide, twist, flip, and turn these triangles to create an identical appearance.

Given:

From the Figure

PS= QR

<PSQ= <QRP

and, from another figure

<UTV= <VWX

<TUV= <XWV

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Which set of polar coordinates names the same point as (-5.5) ? ZT O O A. (5, O B. (5:59) O 5 57 4 377 O c. -5 O D. 7T 5. )

Answers

Recall that the following points represent the same point as the point (x,θ)

[tex]\begin{gathered} (-x,\theta+\pi), \\ (-x,\theta-\pi), \\ (x,\theta+2n\pi)\text{.} \end{gathered}[/tex]

Now, notice that:

[tex]\frac{5\pi}{4}=\frac{4\pi}{4}+\frac{\pi}{4}=\pi+\frac{\pi}{4}\text{.}[/tex]

Therefore, the point:

[tex](5,\frac{5\pi}{4})[/tex]

represent the same point as the point

[tex](-5,\frac{\pi}{4})\text{.}[/tex]

Answer: Option B.

If f(1) = 3, then what ordered pair is in f? (_,_)

Answers

Given:

if f(1) = 3

We are to find the ordered pair that is in f.

f(1) = 3 is a fuction.

f(1) = 3

Then,

f(x) = 3

f(x) = y

So,

f(1) = 3

Therefore,

x = 1, y = 3

So the ordered pair of f is (1, 3)

Use gaussian elimination to solveThe buries pay their babysitter $5 per hour before 11 p.m. and $7.50 after 11p.m. One evening they went out for 5 hours and paid the sitter $35.00. What time did they come home?

Answers

Let m represents the number of hours the buries spent before 11p.m

Let n represent the number of hours the buries spent after 11p.m

m + n = 5 -----------equation (1)

5m + 7.5n = 35 -------equation (2)

Using Gaussian elimination method to solve the simultaneous equations, we have

[tex]\begin{bmatrix}{1} & {1} & {5} \\ {5} & {7.5} & {35} \\ {} & {} & \end{bmatrix}-\begin{bmatrix}{\square} & {\square} & {\square} \\ {\square} & {\square} & {\square} \\ {\square} & {\square} & {\square}\end{bmatrix}[/tex]

The value of m = 1, while n = 4

This implies the buries spent 4 hours after 11 p.m

That means they come home by 3 a.m

what's the value of x for the equation 2(x-4)=6x+4

Answers

we have the equation

2(x-4)=6x+4​

solve for x

Apply distributive property left side

2x-2(4)=6x+4

2x-8=6x+4

Group terms

6x-2x=-8-4

combine like terms

4x=-12

divide by 4 both sides

x=-12/4

x=-3

Leah just accepted a job at a new company where she will make an annual salary of $65000. Leah was told that for each year she stays with the company, she will be given a salary raise of $2500. How much would Leah make as a salary after 6 years working for the company? What would be her salary after t years? Salary after 6 years: Salary after t years:

Answers

[tex]\begin{gathered} \text{after 6 years: 80000} \\ \text{after t years:}S=65000+2500t \end{gathered}[/tex]

Explanation

Step 1

let s represents the salaray

let t represents the number of years she works.

she will make an annual salary of $65000. Leah was told that for each year she stays with the company, she will be given a salary raise of $2500

hence.

[tex]S=65000+2500t[/tex]

and, we have the function for the salary:

for example, after 1 year

it means, t=1

replace

[tex]\begin{gathered} S=65000+2500t \\ S=65000+2500\cdot1 \\ S=65000+2500 \\ S=67500 \end{gathered}[/tex]

so After 6 years

it is, when t= 6

[tex]\begin{gathered} S=65000+2500t \\ S=65000+2500\cdot6 \\ S=65000+15000 \\ S=80000 \end{gathered}[/tex]

I hope this helps you

Can someone help me with this

Answers

The surface area of trapezoidal is 125 cm² that is the popcorn box has a surface area 125 cm².

Given that,

In the picture we have a popcorn with dimensions of trapezoidal.

We have to find what is the surface area of the trapezoidal.

We know that,

The surface area of trapezoidal is 1/2(b₁+b₂)×h

Here,

b₁=5 cm

b₂= 5cm

h= 25 cm

The surface area of trapezoidal= 1/2(b₁+b₂)×h

The surface area of trapezoidal= 1/2(5+5)×25

The surface area of trapezoidal= 1/2(10)×25

The surface area of trapezoidal= 5×25

The surface area of trapezoidal= 125

Therefore, The surface area of trapezoidal is 125 cm² that is the popcorn box has a surface area 125 cm².

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Pizza Orders Pizza Corner sells medium andlarge specialty pizzas. A medium Meat Lovers pizza costs$10.95, and a large Meat Lovers pizza costs $14.95. OneSaturday a total of 50 Meat Lovers pizzas were sold, andthe receipts from the Meat Lovers pizzas were $663.50.How many medium and how many large Meat Loverspizzas were sold?

Answers

Let x = number of medium Meat Lovers pizza sold

Let y = number of large Meat Lovers pizza sold

The cost of a medium Meat Lovers pizza is $10.95

Hence, the cost of x medium Meat Lovers pizza is $10.95x

The cost of a large Meat Lovers pizza is $14.95

Hence, the cost of y large Meat Lovers pizza is $14.95y

Since the total cost of Meat Lovers pizza sold is $663.50

This

Answer:

Let x = number of medium Meat Lovers pizzas sold

Let y = number of large Meat Lovers pizzas sold.

The cost of a medium Meat Lovers pizza is $10.95

Hence, the cost of x medium Meat Lovers pizza is $10.95x

The cost of a large Meat Lovers pizza is $14.95

Hence, the cost of y large Meat Lovers pizza is $14.95y

Since the total cost of Meat Lover's pizza sold is $663.50

This

Step-by-step explanation:

use the diagrams to answer the following questions Number 9

Answers

GIVEN:

We are given the circle with radius 5 units as shown in diagram number 9.

Required;

To determine the

(a) Diameter

(b) Circumference

(c) Area

Step-by-step solution;

The diameter of any given circle is twice the length of the radius.

This means for the circle given, we have;

[tex]\begin{gathered} Radius=5 \\ \\ Diameter=2\times R \\ \\ Diameter=2\times5 \\ \\ Diameter=10 \end{gathered}[/tex]

The circumference of a circle is given by the formula;

[tex]C=2\pi r[/tex]

Taking the value of pi as,

[tex]\pi=3.14[/tex]

We now have the circumference as;

[tex]\begin{gathered} C=2\times3.14\times5 \\ \\ C=31.4\text{ }units \end{gathered}[/tex]

The area of a circle is given by the formula;

[tex]A=\pi r^2[/tex]

Therefore, we now have;

[tex]\begin{gathered} A=3.14\times5^2 \\ \\ A=3.14\times25 \\ \\ A=78.5\text{ }units^2 \end{gathered}[/tex]

ANSWER:

[tex]\begin{gathered} Diameter=10\text{ }units \\ \\ Circumference=31.4\text{ }units \\ \\ Area=78.5\text{ }units^2 \end{gathered}[/tex]

Rewrite all the equation using the inverse operation.I WILL SEND PICTURES OF PROBLEM

Answers

[tex]\begin{gathered} 1.\text{ a=17} \\ 2.\text{ }b=87 \\ 3.x=10 \\ 4.x=42 \end{gathered}[/tex]

Explanation

Step 1

[tex]\begin{gathered} a+15=32 \\ \text{subtract 15 in both sides} \\ a+15-15=32-15 \\ a=17 \end{gathered}[/tex]

Step 2

[tex]\begin{gathered} b-12=75 \\ \text{add 12 in both sides} \\ b-12+12=75+12 \\ b=87 \end{gathered}[/tex]

Step 3

[tex]\begin{gathered} 9x=90 \\ we\text{ n}eed\text{ isolate x, so divide both sides by 9} \\ \frac{9x}{9}=\frac{90}{9} \\ x=10 \end{gathered}[/tex]

Step 4

[tex]\begin{gathered} \frac{x}{6}=7 \\ \text{Multiply both sides by 6} \\ \frac{x}{6}\cdot6=7\cdot6 \\ x=42 \end{gathered}[/tex]

I hope this helps you

Please help me resolve this, I’m not able Part (a)

Answers

To determine the volume of a cylinder you can use the following formula:

[tex]V=\pi r^2h,[/tex]

where h is the height, and r is the radius of the cylinder.

Substituting:

[tex]\begin{gathered} r=6ft, \\ h=9ft \end{gathered}[/tex]

in the formula, you get:

[tex]V=\pi(6ft)^2(9ft).[/tex]

Finally, you get:

[tex]V=324\pi ft^3.[/tex]Answer: [tex]324\pi ft^3.[/tex]

for each problem, identify the variables, write the equations, and solve

Answers

Let the 4-passenger cars be represented with F

Let the 6-passenger cars be represented with S

Rocket Coaster has 15 cars

So that F + S = 15 ----- Equation 1

Also, we were told that the total room for 72 passenger

so that 4F + 6S = 72 ----- Equation 2

Solving the two equations simultaneously using the substitution method,

Step 1

From equation 1:

Make F the subject of the formula

F = 15 - S ---- Equation 3

Step 2

substitute equation 3 into equation 2

4 (15 - S) + 6S = 72

Step 3

60 - 4S + 6S = 72

6S - 4S = 72 - 60

2S = 12

divide both sides by 2

S = 12/ 2

S= 6

Step 4

Substitute the value of S = 6 into equation 3

F = 15 - 6

F = 9

So the number of 4-passenger cars = 9

the number of 6-passenger cars = 6

Determine the equation of the line that goes through the following points. Write the final equation aslope-intercept form.(-2,6 ) and (4,-3)The equation is

Answers

The slope-intercept form is y = mx + b

Where m is the slope and b is constant represents y-intercept

given the points (-2, 6) and (4,-3)

So, the slope is = m

[tex]m=\frac{6-(-3)}{-2-4}=\frac{9}{-6}=-\frac{3}{2}=-1.5[/tex]

So, y = -1.5 x + b

To find b substitute with one of the given points

So,

When x = -2 , y = 6

So,

6 = -1.5 * -2 + b

6 = 3 + b

b = 6 - 3 = 3

So, y = -1.5 x + 3

So, the equation of the line is y = -1.5 x + 3

Consider the equation: x2 – 3x = 18A) First, use the "completing the square" process to write this equation in the form (x + D)² =or (2 – D)? = E. Enter the values of D and E as reduced fractions or integers.=z? - 3x = 18 is equivalent to:– 3rPreview left side of egn:B) Solve your equation and enter your answers below as a list of numbers, separated with a commawhere necessary.Answer(s):

Answers

Part A.

The quadratic equation,

[tex]ax^2+bx+c=0[/tex]

is equivalent to

[tex]a(x+\frac{b}{2a})^2=\frac{b^2}{4a}-c[/tex]

In our case a=1, b=-3 and c=-18. Then, by substituting these value into the last result, we have

[tex](x+\frac{-3}{2(1)})^2=(\frac{-3}{2(1)})^2+18[/tex]

which gives

[tex]\begin{gathered} (x-\frac{3}{2})^2=\frac{9}{4}+18 \\ (x-\frac{3}{2})^2=\frac{9}{4}+18 \\ (x-\frac{3}{2})^2=\frac{9+72}{4} \\ (x-\frac{3}{2})^2=\frac{81}{4} \end{gathered}[/tex]

Therefore, the answer for part A is:

[tex](x-\frac{3}{2})^2=\frac{81}{4}[/tex]

Part B.

Now, we need to solve the last result for x. Then, by applying square root to both sides, we have

[tex]x-\frac{3}{2}=\pm\sqrt[]{\frac{81}{4}}[/tex]

which gives

[tex]x-\frac{3}{2}=\pm\frac{9}{2}[/tex]

then, by adding 3/2 to both sides, we obtain

[tex]x=\frac{3}{2}\pm\frac{9}{2}[/tex]

Then, we have 2 solutions,

[tex]\begin{gathered} x=\frac{3}{2}+\frac{9}{2}=\frac{12}{2}=6 \\ \text{and} \\ x=\frac{3}{2}-\frac{9}{2}=\frac{-6}{2}=-3 \end{gathered}[/tex]

Therefore, the answer for part B is: -3, 6

An onion soup recipe calls for 3 2/3 cups of chopped onions Katrina has already chopped 1 1/3 cups of onions she wants to know how many more cups she needs to chop what X be the number of cups of onions Katrina still needs to chop write an equation to describe the situation

Answers

To determine the number of cups she still needs to chop we need to subtract the amount she already chopped to the amount she needs, then we have the equation:

[tex]x=3\frac{2}{3}-1\frac{1}{3}[/tex]

This can be written as:

[tex]x+1\frac{1}{3}=3\frac{2}{3}[/tex]

Now, we solve it:

[tex]\begin{gathered} x=3\frac{2}{3}-1\frac{1}{3} \\ x=\frac{11}{3}-\frac{4}{3} \\ x=\frac{7}{3} \end{gathered}[/tex]

Therefore she needs to chop 7/3 more cups of onions.

Please help me with this problem:The data shows the number of grams of fat found in 9 different health bars.11, 11.5, 10.5, 17, 14.5, 14.5, 18, 17, 19What is the IQR (interquartile range) for the data? 6.25714.517.5

Answers

Answer:

The interquartile range = 6.25

Explanation:

The given dataset is:

11, 11.5, 10.5, 17, 14.5, 14.5, 18, 17, 19

Rearrange the data in ascending order

10.5, 11, 11.5, 14.5, 14.5, 17, 17, 18, 19

The number of terms in the data, N = 9

The lower quartile is calculated as:

[tex]\begin{gathered} Q_1=(\frac{N+1}{4})^{th}term \\ \\ Q_1=\frac{9+1}{4}^{th}term \\ \\ Q_1=2.5th\text{ term} \\ \\ Q_1=\frac{11+11.5}{2} \\ \\ Q_1=\frac{22.5}{2} \\ \\ Q_1=11.25 \end{gathered}[/tex]

The upper quartile is calculated as:

[tex]\begin{gathered} Q_3=(\frac{3(N+1)}{4})^{th\text{ }}term \\ \\ Q_3=\frac{3(9+1)}{4}th\text{ terms} \\ \\ Q_3=7.5th\text{ term} \\ \\ Q_3=\frac{17+18}{2} \\ \\ Q_3=17.5 \end{gathered}[/tex]

The interquartile range = Upper quartile - Lower quartile

The interquartile range = 17.5 - 11.25

The interquartile range = 6.25

Perform the indicated operations and simplify the result so there are no quotients.

Answers

Given an expression:

[tex]\csc \theta(\sin \theta+\cos \theta)[/tex]

We have to simplify the given expression.

[tex]\begin{gathered} \csc \theta(\sin \theta+\cos \theta)=\csc \theta\sin \theta+\csc \theta\cos \theta \\ =\frac{1}{\sin\theta}\cdot\sin \theta+\frac{1}{\sin\theta}\cdot\cos \theta \\ =1+\frac{\cos \theta}{\sin \theta} \\ =1+\cot \theta \end{gathered}[/tex]

Thus, the answer is 1 + cot theta.

In a survey, 221people said theyhave cable TV. Thisrepresents 65% of thepeople surveyed.How many peoplewere surveyed?

Answers

1) Gathering the data

221 people = 65%

2) To find the 100% people surveyed let's set a direct proportion. And then cross multiply to have an equation:

% people

65-----------221

100-------- y

65y = 22100 Dividing both sides by 65

y =340

So, 340 people were surveyed.

7. A right triangle has a hypotenuse of 13 and a leg of 8. What is the other leg? Show your work.

Answers

Answer:

the other leg is √105

Explanation:

Given:

Hypotenuse = 13

one of the legs of the triangle = 8

To find:

the other leg of the triangle

The triangle is right-angled. So, to get the third side, we will apply Pythagoras theorem:

Hypotenuse² = opposite² + adjacent²

let opposite = leg 1 = 8

adjacent = leg 2

Hypotenuse² = = leg1² + leg2²

[tex]\begin{gathered} 13^2=\text{ 8}^2\text{ + leg}_2^2 \\ \\ 169\text{ = 64 + leg}_2^2 \\ \\ 169\text{ - 64 = leg}_2^2 \\ \\ 105\text{ = leg}_2^2 \end{gathered}[/tex][tex]\begin{gathered} square\text{ root both sides:} \\ \sqrt{105}\text{ = leg}_2 \\ Can^{\prime}t\text{ be reduced an further inradical form} \\ \\ leg_2\text{ = }\sqrt{105}\text{ } \end{gathered}[/tex]

Hence, the other leg is √105

Mitsu borrowed $1,250. She made 36 payments of $45.15 each. Howmuch did she pay in interest?a. $375.40b. $162.54c. $1,625.40d. $37.54

Answers

Amount borrowed = $1,250

Amount paid per payment = $45.15

Number of times payment was made = 36

This implies

The total amount paid is

[tex]36\times\text{\$}45.15=\text{\$}1625.40[/tex]

Hence, the total amount paid = $1,625.40

Interest is calculated using

Interest = Total amount paid - Amount borrowed

Hence, the interest is

[tex]\begin{gathered} I=\text{\$}1625.40-\text{\$}1250 \\ I=\text{\$}375.40 \end{gathered}[/tex]

Therefore, the interest she paid is $375.40

2. Which of the following statements istrue? (1 pt)a) The longest side in a right triangle iscalled the hypotenuse.b) Pythagorean Theorem works for alltriangles.c) The Pythagorean Theorem is used to findmissing angles.

Answers

Option A is correct

Explanation:

Pythagorean Theorem only work for right angle triangles.

Hence, the option Pythagorean Theorem works for all triangles is wrong

The Pythagorean Theorem is used to find missing sides of right angle triangles.

The option The Pythagorean Theorem is used to find missing angles is wrong

The longest side in a right triangle is called the hypotenuse.

This is correct

Option A is correct

5(1+s)=9s+6
----------------

Answers

Answer:

5(1+s) = -9s +6

Step-by-step explanation:

Other Questions
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