Sketch a quick diagram of how all the quadrilaterals relate to one another
Answers
The diagram of various types of quadrilaterals are attached below.
A quadrilateral is polygon that has 4 sides.
Firstly we have a parallelogram which has both pairs of opposite side equal and parallel.
Second we have a trapezium where only one pair of side is parallels but other pair is not parallel.
A rhombus is a parallelogram whose all sides are equal but the angles are not right angles.
A rectangle has all angles 90° but the opposite sides are equal but adjacent sides are not equal.
A square has all sides equal and all angles 90° .
A kite has only 2 pairs of adjacent sides equal.
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Related Questions
Let’s say that the patient drinks an 8-ounce glass of orange juice. The nurse must convert that to milliliters (mL) or cubic centimeters (cc) in order to record the intake volume in the patient’s fluid input and output chart. (Remember 1 mL = 1 cc.)
Answers
Answer: 8 ounce = 237 ml
Explanation:
From the information given,
volume of drink taken by patient = 8 ounce
We want to convert 8 ounce to ml
Recall,
1 US fluid ounce = 29.57 ml
Thus,
8 ounce = 8 x 29.57 = 236.56
Approximately,
8 ounce = 237 ml
Write the equation of the line that is perpendicular to the line given and through the given point. Do not use spaces in your equation. y=-2X+1 (0,5) *
Answers
Answer:
y = 0.5x + 5
Explanation:
The equation of a line can be calculated as:
[tex]y=m(x-x_1)+y_1[/tex]Where m is the slope and (x1, y1) is a point in the line.
To find the slope of our line, we need to identify the slope of the given line.
Since the equation of the given line is y = -2x + 1, the slope of this line is -2, because it is the number beside the x.
Then, two lines are perpendicular if the product of their slopes is equal to -1. So, we can write the following equation:
[tex]-2\cdot m=-1[/tex]Therefore, the slope m of our line will be:
[tex]m=\frac{-1}{-2}=0.5[/tex]Now, we can replace the value f m by 0.5 and the point (x1, y1) by (0, 5) and we get that the equation of the line is:
[tex]\begin{gathered} y=0.5(x-0)+5 \\ y=0.5(x)+5 \\ y=0.5x+5 \end{gathered}[/tex]Therefore, the answer is y = 0.5x + 5
A. Translate the verbal phrases into algebraic expressions.3. The square of the quotient of 54 and j
Answers
ANSWER
(54/j)²
EXPLANATION
We have to translate this verbal phrase into an algebraic expression. An algebraic expression is a combination of variables, numbers, and arithmetic operations. For example, the expression (x² + 2) is an algebraic expression.
In this phrase, we have "the square of ...", so we will have an expression in the form (...)².
Then, the square is of a quotient, between 54 and j, where 54 is the numerator and j is the denominator.
Hence, the algebraic expression is (54/j)².
Accrotime is a manufacturer of quartz crystal watches. Accrotime researchers have shown that the watches have an average life of 30 months before certain electronic components deteriorate, causing the watch to become unreliable. The standard deviation of watch lifetimes is 4 months, and the distribution of lifetimes is normal.
A. a) If Accrotime guarantees a full refund on any defective watch for 2 years after purchase, what percentage of total production will the company expect to replace? (Round your answer to two decimal places.)\
B. If Accrotime does not want to make refunds on more than 6% of the watches it makes, how long should the guarantee period be (to the nearest month
Answers
a) The percentage of total production will the company expect to replace is of 6.62%.
b) The guarantee period should be of 23 months.
Normal Probability DistributionThe z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score represents how many standard deviations the measure X is above or below the mean of the distribution, depending if the obtained z-score is positive or negative.Using the z-score table, the p-value associated with the calculated z-score is found, and it represents the percentile of the measure X in the distribution.The mean and the standard deviation for the duration of the watches are given as follows:
[tex]\mu = 30, \sigma = 4[/tex]
The proportion of watches that will be replaced are those that last less than 2 years = 24 months, hence it is given by the p-value of Z when X = 24, as follows:
Z = (24 - 30)/4
Z = -1.5.
Z = -1.5 has a p-value of 0.0662.
Hence the percentage is of 6.62%.
For item b, the guarantee period should be the 6th percentile, which is X when Z = -1.555, hence:
-1.555 = (X - 30)/4
X - 30 = -1.555 x 4
X = 23 months.
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which of the fillowing statements must be true based on the diagram below?
Answers
Answer:
HI is a perpendicular bisector
H is the vertex of a right angle
H is the midpoint of a segment in the diagram
Explanation:
Taking into account the diagram, we can say that the segments GH and HF have the same length. Additionally, HI form an angle of 90° with segment GF.
So, the true statements are:
HI is a perpendicular bisector because it forms a 90° angle and divides the segment GF into two equal segments.
H is the vertex of a right angle because angle FHI is right ( measures 90°)
H is the midpoint of a segment in the diagram because point H divides segment GF into two equal parts.
Therefore, the answers are:
HI is a perpendicular bisector
H is the vertex of a right angle
H is the midpoint of a segment in the diagram
3. Which inequality is represented by the graph below?y < 3x + 2y =3x + 2y > 3x + 2y= 3. + 2
Answers
Answer
Option A is correct.
The inequality equation represented by the graph is
y < 3x + 2
Explanation
When plotting the graph of linear inequality equations, the first step is to first plot the graph of the straight line normally, using intercepts to generate two points on the linear graph.
Looking at the graph given, we can tell that the graph without considering the inequality yet is y = 3x + 2
If the inequality sign is (< or >), then the line drawn will be a broken line.
If the inequality sign is (≤ or ≥), then the line drawn is an unbroken one.
For this question, we can see that the lin is a broken line, so, the inequality sign will either be a < or >.
The shaded region now depends on whether the inequality sign is facing y or not.
If the inequality sign is facing y, it means numbers above the line plotted are the wanted region and the upper part of the graph is shaded.
If the inequality sign is not facing y, it means numbers below the line plotted are the wanted region and the lower part of the graph is shaded.
For this question, we can see that the lower part of the line is shaded, so, that means the inequality sign is not facing y.
So, the inequality equation represented by the graph is
y < 3x + 2
Hope this Helps!!!
Which of the following graphs have hamiltonian circuits?
Answers
Answer:
D
Step-by-step explanation:
A box contains different colored paper clips. The probability of drawing two red paper clips from the box without replacement is 1/7, and the probability of drawing one red paper clip is 2/5.What is the probability of drawing a second red paper clip, given that the first paper clip is red?1/65/142/32/35
Answers
SOLUTION
The probability of two red paper clips without replacement means
The probability of drawing the first and the probability of drawing the second one. This is represented as
[tex]P(R_{1st}\cap R_{2nd})[/tex]And this was given as
[tex]\frac{1}{7}[/tex]So
[tex]P(R_{1st}\cap R_{2nd})=\frac{1}{7}[/tex]Probalilty of drawing one red paper clip is
[tex]P(R_{1st})=\frac{2}{5}[/tex]Now the probability of drawing a second red paper clip, given that the first paper clip is red becomes
[tex]\begin{gathered} P(R_{1st}/R_{2nd})=\frac{P(R_{1st}\cap R_{2nd})}{P(R_{1st})} \\ \\ P(R_{1st}/R_{2nd})=\frac{\frac{1}{7}}{\frac{2}{5}} \\ \\ =\frac{5}{14} \end{gathered}[/tex]Find the perimeter and area of the figure, rounding to the nearest tent. Use 3.14 for π 7ft 25 ft 4 ft
Answers
Answer:
89.12 ft
Explanation:
The perimeter of the figure is the sum of all the sides. So, we need to find the length of the quarter of the circles. This length can be calculated as:
[tex]\frac{2\cdot\pi\cdot r}{4}=\frac{2\cdot3.14\cdot4ft}{4}=6.28\text{ ft}[/tex]Where r is the radius of the circle.
Then, the perimeter can be calculated as:
Perimeter = 2(7 ft) + 2(25 ft) + 4(6.28 ft)
Perimeter = 14 ft + 50 ft + 25.12 ft
Perimeter = 89.12 ft
Because there are 2 segments of 7 ft, 2 of 25 ft, and 4 corners of 6.28 ft
Therefore, the answer is 89.12 ft
What is the surface area of a pyramid if its one triangular face has an area of 20 sq. cm and its square base has a side of 5cm?A. 100 sq.cmB. 105 sq.cmC. 110 sq. cmD. 115 sq.cm
Answers
To solve this problem, we will use the following formula for the surface area of a square pyramid:
[tex]SA=BA+4A_t,[/tex]where BA= base area, and A_t is the area of one of the lateral triangles.
Now, we are given that:
[tex]A_t=20cm^2.[/tex]Recall that the area of a square is given by the following formula:
[tex]A_s=side^2.[/tex]We are given that the side of the base is 5 cm long, therefore, the base area is:
[tex]A_s=(5cm)^2=25cm^2.[/tex]Finally, we get that:
[tex]SA=25cm^2+4(20cm^2)=105cm^2.[/tex]Answer:
[tex]105cm^2.[/tex]+10B-10-8-644810Bc8--10and aWe can show that ABC is congruent to AA'BC by a translation ofunits)across the-axis.
Answers
ANSWER
ABC is congruent to A'B'C' by a translation of 2 units and a reflection across the x-axis
EXPLANATION
We want to identify the transformations that were carried out on ABC to obtain A'B'C'.
First, we notice that A'B'C' is not aligned with ABC because the vertex of B' is 2 units behind the vertex of B.
So, we can say that there was a translation of 2 units to the left or -2 units..
Also, we notice that the vertices of ABC were flipped over the x-axis to obtain A'B'C'.
Therefore, we can conclude that there was a reflection across the x axis.
Hence, ABC is congruent to A'B'C' by a translation of 2 units and a reflection across the x-axis.
Given that: 100 = 2^2 * 5^2, how is 400 written as a product of its prime factors?
Answers
Answer:
400 written as a product of it's prime factors is 2^4 * 5²
Step-by-step explanation:
We have to factore the number, dividing by prime factors(2, 3, 5, 7, ...)
400|2
200|2
100
We already have the factorization of 100. So
400 = 2²*100 = 2²*2²*5² = 2^4 * 5²
400 written as a product of it's prime factors is 2^4 * 5²
2^2*10^2=400
2^2=4
10^10=100
4*100=400
2) Reflection across the line y = x. B(-2, 1), S(-2, 2), R(3, 3), H(2, -2) B'( ) S/ ) R (2) J( )
Answers
Let's begin by identifying key information given to us:
[tex]B\mleft(-2,1\mright),S\mleft(-2,2\mright),R\mleft(3,3\mright),H\mleft(2,-2\mright)[/tex]Reflection is done over the line y = x, we have:
[tex]\begin{gathered} (x,y)\rightarrow(y,x) \\ B\mleft(-2,1\mright)\rightarrow B^{\prime}(1,-2) \\ S\mleft(-2,2\mright)\rightarrow S^{\prime}(2,-2)_{} \\ R\mleft(3,3\mright)\rightarrow R^{\prime}(3,3) \\ H\mleft(2,-2\mright)\rightarrow H^{\prime}(-2,2) \end{gathered}[/tex]Question 7 Luna's savings increases as a linear function of the number of chores she does, as shown in the table. How much money did Luna have saved before she started doing chores? Chores Savings ($) 1 74 2 78 3 82 4 86 $0 $70 $64 $68
Answers
Select all of the value below the satisfy the inequality
Answers
Given:
[tex]\frac{1}{2}(x-5)+9>8[/tex][tex]\frac{1}{2}(x-5)>8-9[/tex][tex]\frac{1}{2}(x-5)>-1[/tex][tex]x-5>-2[/tex][tex]x>5-2[/tex][tex]x>3[/tex]Values satisfying the inequality are:
[tex]5\text{ , }\frac{22}{7}\text{ , }3.015[/tex]A phone company charges for service according to the formula: C(n) = 19 + 0.08n , where n is the number of minutes talked , and C(n) is the monthly charge, in dollars .The rate of change in this equation is:The initial value in this equation is:
Answers
In a linear equation, the coefficient of the variable is the rate of change and the constant term is the initial value.
For example, a linear function with rate of change m and initial value b is:
[tex]f(x)=mx+b[/tex]In the given formula, the variable is n, its coefficient is 0.08 and the constant term is 19.
Since n is measured in minutes and C is measured in dollars (as well as the initial value), then, the coefficient 0.08 must have the units necessary for the minutes to cancel out, leaving dollars as the unit of 0.08n. Then, the units of the rate of change must be dollars per minute.
Since the constant term is 19, then the initial value is 19.
Therefore, the answers are:
The rate of change in the equation is 0.08 dollars per minute.
The initial value in the equation is 19 dollars.
The lengths of the diagonals of a rectangle are representedby 2x + 3 and 4x - 11. Find the value of x.
Answers
The problem says that there are formulas for the diagonals of a rectangle. they are both givan in terms of x
Now, recall that the diagonals of a rectangle should be equal to each other, therefore those two expressions must equal ech other
2 x + 3 = 4 x - 11
Now let's solve for x:
move all terms with "x" to one side of the equation, and all "numerical" terms to the other side:
start by subtracting 2x from both sides:
3 = 4 x - 2 x - 11
3 = 2 x - 11
Now add 11 to both sides:
11 + 3 = 2 x
14 = 2 x
then x is 7
The surface area of a rectangular prism is 60. Which of the following are possible dimensions of the rectangular prism? 1 Pt
Answers
The surface area of a rectangular prism with sides a, b and c is given by the formula:
[tex]S=2(ab+ac+bc)[/tex]Use that formula to find the surface area that a prism with the given dimensions on each option would have.
A. 6, 2, 1 1/2
[tex]\begin{gathered} S=2(6\cdot2+6\cdot1\frac{1}{2}+2\cdot1\frac{1}{2}) \\ =2(12+9+3) \\ =2(24) \\ =48 \end{gathered}[/tex]B. 5, 4, 1 1/4
[tex]\begin{gathered} S=2(5\cdot4+5\cdot1\frac{1}{4}+4\cdot1\frac{1}{4}) \\ =2(20+\frac{25}{4}+5) \\ =2(\frac{125}{4}) \\ =\frac{125}{2} \\ =62.5 \end{gathered}[/tex]C. 3, 4, 1 1/2
[tex]\begin{gathered} S=2(3\cdot4+3\cdot1\frac{1}{2}+4\cdot1\frac{1}{2}) \\ =2(12+3\frac{3}{2}+6) \\ =2(21\frac{3}{2}) \\ =45 \end{gathered}[/tex]D. 6, 3, 1 1/3
[tex]\begin{gathered} S=2(6\cdot3+6\cdot1\frac{1}{3}+3\cdot1\frac{1}{3}) \\ =2(18+8+4) \\ =2(30) \\ =60 \end{gathered}[/tex]Therefore, the only possible dimensions of a rectangular prism with surface area 60 listed on the options, are 6, 3 and 3 1/3. The answer is:
[tex]\text{Option D}[/tex]Simplify the following expression by combining liker terms: 4x +9 -6x +610X-1510x+15-2x+152x+15
Answers
We have the expression 4x+9-6x+6 and we have to simplify it.
We can group the terms that are alike. We have two groups of terms: the ones that are multiplied by "x" and the ones that are just numbers alone.
Then, the terms 4x and (-6x) are alike and we can add them, getting (-2x). In this terms, x is the common denominator of both terms.
The other terms that are alike are 9 and 6, that can be added to get 15.
[tex]\begin{gathered} 4x+9-6x+6 \\ (4-6)x+(9+6) \\ -2x+15 \end{gathered}[/tex]The answer is -2x+15.
A water tower tank in the shape of a right circular cylinder is44 meters tall and has a diameter of26 meters. What is the volume of the tank? UseT = 3.14 and round to the nearest hundredth, if necessary.
Answers
We have that the volume of a cylinder is given by the following equation:
[tex]V=\pi\cdot r^2\cdot h[/tex]h is tall and r the radius, the radius is:
[tex]\begin{gathered} r=\frac{d}{2}=\frac{26}{2}=13 \\ \end{gathered}[/tex]replacing:
[tex]\begin{gathered} V=3.14\cdot(13)^2\cdot44 \\ V=23349.04 \end{gathered}[/tex]The volumen of the cylinder is 23349.04 cubic meters
I need help with this question... the correct answer choice
Answers
The given a parallelogram with 4 coordnates in the corner.
The transformation that carries the parallegoram below itself is ,
the rotation of 180 counterclockwise about the origin.
a rational function with at least one vertical asymptote, and a horizontal asymptote. You will describe the characteristics of your function, and give a numerical example of the function at one of the vertical asymptotes.
Answers
ANSWERS
Function:
[tex]h(x)=\frac{x+1}{(x-1)(x+3)}[/tex]Key features:
• Asymptotes: x = 1, x = -3, (vertical), and ,y = 0, (horizontal).
,• Intercepts: (0, -1/3), (-1, 0)
,• Symmetry: none
,• Example of end behavior: as x → 1⁺, y → infinity,, while, as x → 1⁻, y → -infinity
EXPLANATION
The vertical asymptotes of a rational function are given by the zeros of the denominator. For example, the function,
[tex]h(x)=\frac{x+1}{(x-1)(x+3)}[/tex]Has two vertical asymptotes: one at x = 1, and one at x = -3.
The horizontal asymptote is determined by the degrees of the numerator (n) and denominator (m):
• If n < m then the horizontal asymptote is the x-axis
,• If n = m then the horizontal asymptote is y = a/b, where a and b are the leading coefficients of the numerator and denominator, respectively.
,• If n > m then there is no horizontal asymptote
In the given example, the degree of the numerator is 1, while the degree of the denominator is 2. Thus, function h(x) has a horizontal asymptote that is the x-axis.
Now, we have to find the key features for this function:
• y-intercept:, occurs when x = 0
[tex]h(0)=\frac{0+1}{(0-1)(0+3)}=\frac{1}{-3}=-\frac{1}{3}[/tex]Hence, the y-intercept is (0, -1/3)
• x-intercepts:, the x-intercepts are the x-intercepts of the numerator: ,(-1, 0),.
,• The ,asymptotes, are the ones mentioned above: ,x = 1, x = -3, (vertical), and ,y = 0, (horizontal).
,• The ,symmetry, is determined as follows:
[tex]\begin{gathered} Even\text{ }functions:f(-x)=f(x) \\ Odd\text{ }functions:f(-x)=-f(x) \end{gathered}[/tex]If we replace x with -x in function h(x), we will find that the result is neither h(x) nor -h(x) and, therefore this function is neither even nor odd.
Finally, an example of the end behavior of this function around the asymptote x = 1 is that as x → 1⁺, y → infinity, while as x → 1⁻¹, y → -infinity.
If we take values of x greater than x = 1 - so we will approach 1 from the right, we will get values of the function that show an increasing behavior. Let's find h(x) for x = 4, x = 3, and x = 2,
[tex]\begin{gathered} h(4)=\frac{4+1}{(4-1)(4+3)}=\frac{5}{3\cdot7}=\frac{5}{21} \\ \\ h(3)=\frac{3+1}{(3-1)(3+3)}=\frac{4}{2\times6}=\frac{4}{12}=\frac{1}{3} \\ \\ h(2)=\frac{2+1}{(2-1)(2+3)}=\frac{3}{1\times5}=\frac{3}{5} \end{gathered}[/tex]And we will find the opposite behavior for values that are less than 1 - but greater than -1 because there the function has a zero and its behavior could change,
[tex]\begin{gathered} h(0)=\frac{0+1}{(0-1)(0+3)}=\frac{1}{-1\times3}=-\frac{1}{3} \\ \\ h(\frac{1}{2})=\frac{\frac{1}{2}+1}{(\frac{1}{2}-1)(\frac{1}{2}+3)}=\frac{\frac{3}{2}}{-\frac{1}{2}\times\frac{7}{2}}=\frac{\frac{3}{2}}{-\frac{7}{4}}=-\frac{3\cdot4}{2\cdot7}=-\frac{6}{7} \end{gathered}[/tex]The graph of the function and its key features is,
A line passes through the point (3,-8) and has a slope of -4 . Write an equation in slope-intercept form for this line.
Answers
The slope-intercept form of the line which passes through the point (3,-8) and with a slope of -4 is y = -4x + 4
We know that the equation of a line passing through a given point is as follows:
(y - y1) = m (x - x1) ….. (i)
Here, (x1, y1) ⇒ coordinates of the point
m ⇒ slope of the line
In the given question,
y1 = -8
x1 = 3
m = -4
Putting these values in equation (i),
(y - (-8)) = (-4) (x-3)
(y + 8) = -4x + 12
On rearranging, we get
y = -4x + 12 - 8
y = -4x + 4
Therefore, the slope-intercept form of the line which passes through the point (3,-8) and with a slope of -4 is y = -4x + 4.
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Triangles ACD and BCD are isosceles. Angle DBC has a measure of 84 degrees and angleBDA has a measure of 24 degrees. Find the measure of angle BAC.
Answers
The Solution.
The reflex angle DBC can be calculated as below:
[tex]\angle DBC=360-84=276^o\text{ ( angle at a point)}[/tex][tex]So,\text{ }\angle DBA=\angle CBA=\frac{276}{2}=138^o[/tex]Note that: angle BDA = angle BCA = 24 degrees
Thus, considering triangle CBA (which is similar to triangle DBA), we can find angle BAC.
[tex]\angle BAC+138+24=180\text{ (sum of angles in a triangle)}[/tex][tex]\begin{gathered} \angle BAC=180-(138+24) \\ \text{ =180-162} \\ \text{ =18 }^o \end{gathered}[/tex]Therefore, the correct answer is 18 degrees.
A blueprint of a shopping complex shows the bottom edge of the roof to be 68 feet above the ground. If the roof rises to a point 122 feet above the ground over a horizontal distance of 4.5 yards, what is the slope of the roof?41.2128
Answers
SOLUTION
Given:
A blueprint of a shopping complex shows the bottom edge of the roof to be 68 feet above the ground. If the roof rises to a point 122 feet above the ground over a horizontal distance of 4.5 yards, what is the slope of the roof?
[tex]Slope\text{ =}\frac{rise}{run}[/tex][tex]\begin{gathered} Rise\text{ =122-68=54 feet} \\ Run=4.5yards=13.5feet \end{gathered}[/tex][tex]\therefore Slope=\frac{54}{13.5}=4feet[/tex]
Final answer:
Select all inputs for which f (x)=2A:x=-7B:x=0C:x=4D:none of the above
Answers
To answer this question, we need to see the graph of the function carefully.
For x = -7, we can see that the function is equal to 2, that is:
[tex]f(-7)=2[/tex]For x = 0, we have that the function is equal to -1, that is:
[tex]f(0)=-1[/tex]For x = 4, we have that the function is equal to -2, that is:
[tex]f(4)=-2[/tex]We need to find the value of x. Then, we have to find the point where we "touch" the function, and then find the y-value of the function.
Therefore, in summary, we have that the only input for which f(x) = 2 is when x = -7 (option A).
a cellular phone company charges a base rate of $15.00 per month and $0.05 per minute,m, which equation could be used to find the total monthly charge in dollars,c?
Answers
Suppose you use "m" minutes in a month and each minute is $0.05, so your minute bill would be:
0.05 * m
Per month, there is a fixed rate of $15 , no matter how many minutes you use.
So, that's a fixed cost.
Total monthly charge would be:
15 + 0.05m
The cost, c, is:
[tex]c=0.05m+15[/tex]Correct Answer Choice is Option B
Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal to f(x) · g(t)?OA.41 - 81 + 61OB.SIKIAOC.21 + 6I + 2D.6
Answers
Given the following functions below,
[tex]\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}[/tex]Factorising the denominators of both functions,
Factorising the denominator of f(x),
[tex]\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}[/tex]Factorising the denominator of g(x),
[tex]\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}[/tex]Multiplying both functions,
[tex]undefined[/tex]in a survey of 1300 people who owned a certain type of car 585 said they would buy the type of car again what percent of people surveyed were satisfied with the car
Answers
In order to find the percentage of people that were satisfied with the car, we just need to divide this amount of people by the total amount of people surveyed.
So we have:
[tex]\frac{585}{1300}=0.45=45\text{\%}[/tex]So 45% of the surveyed people were satisfied with the car.
Please help with parts (a), (b),and (c).No need much explanation
Answers
Given the Histogram that summarizes the data obtained by Kemala:
(a) The Class Width is the length of the intervals.
In order to find the Class Width, you need to subtract the lowest value of each bar from the lowest value of the previous bar.
In this case, you get:
[tex]\begin{gathered} 5-2=3 \\ 8-5=3 \\ 11-8=3 \end{gathered}[/tex]Therefore:
[tex]Class\text{ }Width=3[/tex](b) You need to identify the number of beaches that had 10 or fewer pregnant turtles. Therefore, you need to add the corresponding number of beaches that correspond to these bars (A, B and C):
Then, you get:
[tex]3+8+4=15[/tex](c) You can identify that the interval of the last bar is from 11 to 13, and the number of beaches that corresponds to that bar is:
[tex]6[/tex]As you can see below
Hence, the answers are:
(a)
[tex]3[/tex](b)
[tex]15[/tex](c)
[tex]6[/tex]