Hence, the number of covalent bonds that an atom can form depends on the number of in the atom is correct.
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What is the molecular geometry of the XeF2 molecule?Group of answer choiceslinearnone of the answers are correctbenttrigonal bipyramid
ANSWER
The molecular geometry of XeF2 is linear
EXPLANATION:
The compound given is called Xenon Difluoride
It is very important to know the following features of Xenon
1. Xenon has two bond pairs and three lone pairs of electrons
2. During hybridization, Xenon will form two sigma bonds with two fluorine atoms
The bond angle of Xenon Difluoride is 180 degrees, hence, the molecular geometry is linear
how does mechanical energy ( potential and kinetic energy ) determine the motion of an object?
Motion can simply be defined as the change in position of a body while energy is the ability or capacity to work.
Mechanical energy is one of the forms of energy and is subdivided into potential energy and kinetic energy. These energies are energies that determine whether a body or an object is moving or not.
When a body is in a position, the energy possessed by such body by virtue of its position is known as potential energy while when a body is moving (in motion), the energy possesses by this body by virtue of its motion is the kinetic energy.
For instance, a ball rolling down an inclined plane is initially at rest at the top of the incline showing that the body has maximum potential energy and zero kinetic energy (since the body is in a position at this point).
As the ball rolls down the incline, it gains momentum and its kinetic energy keeps increasing along the plane while the potential energy keeps decreasing. Once the body gets to the bottom of the plane, the kinetic energy becomes zero while the potential energy is at maximum (because the body is at rest at this point as well).
I need help with my homework What is the most important thing you learned while taking this course?
Answer:
I think that the most important thing that I've learned in the course was stoichiometry. I really liked balancing equations and calculating yields.
true or false does photosynthesis takes place in all animal cells
Answer:
photosynthesis does not take place in animals
Explanation:
it doesn't because animals do not have plant cells
Identify the number of significant figures (sig figs) in each of the values.
Answer:
0.009: only 1 significant figure, since all zero digits are leading zeros;
0.030: there are 2 significant figures;
140: there are 3 significant figures (a simple way to check is convert this number to the scientific notation keeping the same amount of digits: 1.40 x 10^2);
2000: there are 4 significant figures;
80.30: there are 4 significant figures;
80060: there are 5 significant figures
0.05200: there are 4 significant figures.
Explanation:
The question requires us to identify the numbr of significant figures for each of the following values:
0.009
0.030
140
2000
80.30
80060
0.05200
Significant figures or significant digits of a number can be defined as the digits that define the resolution or precision of a number. In other words, the significant figures of a number are the reliable digits necessary to indicate the quantity of something.
There are a few rules to identify the amount of significant digits of a number. We can summarize them as:
- non-zero digits that are in the number are significant;
- zeros between two non-zero digits are significant;
- leading zeros (zeros to the left of the first non-zero digit) are not significant, while zeros to the right of the last non-zero digit in a decimal number are signifcant (for example, 0.005200 -> these zeros are not significant; 0.005200 -> these zeros are significant);
- zeros to the left of the last non-zero digit in an integer number may or may not be significant, depending on the measurement resolution.
Next, let's analyze the numbers given by the question:
0.009: only 1 significant figure, since all zero digits are leading zeros;
0.030: there are 2 significant figures;
140: there are 3 significant figures (a simple way to check is convert this number to the scientific notation keeping the same amount of digits: 1.40 x 10^2);
2000: there are 4 significant figures;
80.30: there are 4 significant figures;
80060: there are 5 significant figures
0.05200: there are 4 significant figures.
-
what's the smallest line on a meter stick represent?
Answer
The millimeter is the smallest line (subdivision) on the meter stick.
This means the millimeter is the unit of the smallest reading that can be made without estimating.
A sample of gas has temperature of 25 Celsius and a volume of 122 ml. If the volis decreased to 50 ml, what is the new temperature?
So,
We could use the Charles law:
In this case, we have:
V1=122ml
T1=25°C
V2=50ml
T2=?
Let's replace these values in the equation in order to find T2:
The final temperature is about 10.2459°C.
27) Suppose object A has double the specific heat and triple the mass of object B. If the same amount of heat is applied to both objects, how will the temperature change of A be related to the temperature change of B? Enter your answer to three significant figures.
The absorbed or released by a system is given by the following formula:
[tex]Q=m\cdot Cp\cdot\Delta T[/tex]Where Q is the heat absorbed or released, m is the mass of the system, Cp is the specific heat and ΔT is the change in the temperature.
Let mA and mB be the mass of objects A and B, let CpA and CpB be the specific heats of objects A and B and let ΔTA and ΔTB be the specific heats of objects A and B. We will have that:
[tex]\begin{gathered} mA=3mB \\ CpA=2CpB \end{gathered}[/tex]If the same amount of heat is applied to both object, we will have that:
[tex]\begin{gathered} QA=QB \\ mA\cdot CpA\cdot\Delta TA=mB\cdot CpB\cdot\Delta TB \end{gathered}[/tex]Replace mA and CpA for their equivalences in terms of mB and CpB:
[tex]\begin{gathered} 3mB\cdot2CpB\cdot\Delta TA=mB\cdot CpB\cdot\Delta TB \\ \Delta TA=\frac{mB}{3mB}\cdot\frac{CpB}{2CpB}\cdot\Delta TB \\ \Delta TA=\frac{1}{3}\cdot\frac{1}{2}\Delta TB \\ \Delta TA=\frac{1}{6}\Delta TB \end{gathered}[/tex]It means that the change in temperature of A is 1/6 of the change of temperature of B.
[tex]\Delta TA=\frac{1}{6}\Delta TB[/tex]The volume of a gas was 63 mL when the temperature was 162.1 °C. If thetemperature was initially 6.5 °C, and there was no change in the pressure, whatwas the initial volume of the gas?
To answer this question we have to use Charles' Law:
[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]Before replacing for the given values, we have to convert the given temperatures to Kelvin:
[tex]\begin{gathered} 162.1+273.15=435.25 \\ 6.5+273.15=279.65 \end{gathered}[/tex]Now replace for the given values, V1 and V2 are the initial and final volumes respectively and T1 and T2 are the initial and final temperatures. Solve for V1 and find its value:
[tex]\begin{gathered} V1=\frac{V2T1}{T2} \\ V1=\frac{63mL\cdot279.65K}{435.25K} \\ V1=40.4mL \end{gathered}[/tex]It means that the initial volume was approximately 40mL.
The correct answer is c. 40.
Are chemical reactions reversible? Explain your answer in at least 3 sentences.
Chemical reactions are reversible, which means that the reaction that occurs from the reactants to form products can be also from the products to form the reactants again, this is widely studied in Chemical Equilibrium and Le Chantelier's principleons are
Select the structure that correspondsto the molecule name:propylamineA.NH₂B. CH3CH₂CH₂NH₂C. both
Explanation:
Propylamine is characterized by 3 carbons, 9 hydrogens, and 1 nitrogen.
According to the given picture, B is the correct answer.
Answer:
B is the correct answer.
Calculate the pH of a solution that has a hydronium ion concentration of 0.072 M
Given that :
hydronium ion concentration of 0.072 M
[H3o^+] = 0.072
We know that :
[tex]\begin{gathered} P_H=-log_{10\text{ }}\lbrack H_3O^+\rbrack \\ \text{ = -log}_{10}\lbrack0.072\rbrack \\ \text{ = 1.1426} \\ \approx\text{ 1.14 } \end{gathered}[/tex]How many sodium (Na) and oxygen (O) atoms are needed to form the ionic compound sodium oxide?There needs to be 1 Na atom and 2 O atoms to form Na2OThere needs to be 2 Na atoms and 2 O atoms to form Na2OThere needs to be 1 Na atom and 1 O atom to form Na2OThere needs to be 2 Na atoms and 1 O atom to form Na2O
Answer:
There needs to be 2 Na atoms and 1 O atom to form Na2O.
Explanation:
If you go to see the periodic table to review the oxidation states of elements, you can see that Na only has +1 as oxidation state, and O only has -2 as oxidation state.
The algebraic sum of these oxidation states in a neutral compound (not ions) must be zero, so let's apply the following technique to form the compound:
So the compound would be Na2O, so we need 2 atoms of Na, and 1 atom of O.
The answer would be: There needs to be 2 Na atoms and 1 O atom to form Na2O.
(01.08 HC) Read the following passage.The cathode ray experiment indicated the existence of negatively charged particles in an atom. This experiment also disproved the part of Dalton's atomic model that claimed indivisibility of the atom. When the experiment was repeated using cathodes made of a different metal, each time the results were consistent. These discoveries of Thompson were later substantiated by Robert Millikan when he calculated the charge on an electron.Use information from the passage to justify whether the characteristics of reliable scientific explanations are present in the development of the atomic theory. (8 points)
Answer and explanation:
Atomic theory states that matter was made up of units called atoms, and that these were indivisibles.
The atomic theory began as a philosophical concept, that is, it was not based on reliable scientific explanations.
What volume of carbon dioxide, at 1 atm pressure and 112°C, will be produced when 80.0 grams of methane is burned?
Answer:
158 L.
Explanation:
What is given?
Pressure (P) = 1 atm.
Temperature (T) = 112 °C + 273 = 385 K.
Mass of methane CH4 (g) = 80.0 g.
Molar mass of methane CH4 = 16 g/mol.
R constant = 0.0821 L*atm/mol*K.
What do we need? Volume (V).
Step-by-step solution:
To solve this problem, we have to use ideal gas law: the ideal gas law is a single equation which relates the pressure, volume, temperature, and number of moles of an ideal gas. The formula is:
[tex]PV=nRT.[/tex]Where P is pressure, V is volume, n is the number of moles, R is the constant and T is temperature.
So, let's find the number of moles that are in 80.0 g of methane using its molar mass. This conversion is:
[tex]80.0g\text{ CH}_4\cdot\frac{1\text{ mol CH}_4}{16\text{ g CH}_4}=5\text{ moles CH}_4.[/tex]So, in this case, n=5.
Now, let's solve for 'V' and replace the given values in the ideal gas law equation:
[tex]V=\frac{nRT}{P}=\frac{5\text{ moles }\cdot0.0821\frac{L\cdot atm}{mol\cdot K}\cdot385K}{1\text{ atm}}=158.04\text{ L}\approx158\text{ L.}[/tex]The volume would be 158 L.
Ethylene glycol, C2H6O2, is an odorless, colorless, sweet-tasting liquid used in antifreeze formulations. The antifreeze formulations are 56% ethylene glycol by mass. (Assume the density of the ethylene glycol solution is 1.072 g/mL).How would you prepare 500 mL of 0.350 M solution?
Step 1 - Finding the concentration in g/L
We know the density of the solution is 1.072 g/ml, which means there are 1.072 g in each ml of solution. This mass corresponds to both water and ethyleneglycol.
Since the percentage in mass of ethyleneglycol is 56%, we can calculate how much ethyleneglycol there is in 1 ml of solution:
[tex]m_{\text{ethyleneglycol}}=\frac{56}{100}\times1.072=0.600g[/tex]The concentration of ethyleneglycol would be thus 0.6 g/ml.
To convert it to g/L, we just have to multiply it by 1000, because 1L = 1000ml:
[tex]0.6\times1000=600\text{ g/L}[/tex]The concentration of ethyleneglycol is this solution is thus 600 g/L.
Step 2 - Converting this concentration to mol/L
To convert now to mol/L (M), we just have to divide the concentration by the molar mass of ethyleneglycol (62.07 g/mol):
[tex]M_{\text{ethyleneglycol}}=\frac{600}{62.07}=9.66\text{ mol/L}[/tex]Note the concentration is a rather high one. We will have to dilute it.
Step 3 - Preparing a 0.350 M solution
We know the final volume of the solution must be 500 ml, and we also know its final concentration (0.350 M). Since we already know its inicial concentration as well, we can use the following formula for dilutions:
[tex]M_1V_1=M_2V_2[/tex]Plugging the values in the equation:
[tex]\begin{gathered} 9.66V_1=500\times0.350 \\ \\ V_1=\frac{175}{9.66}=18.11ml \end{gathered}[/tex]Step 4 - Describing how to prepare the solution
As we have calculated in step 3, we would need 18.11 ml of the original solution (9.66 M) for the dilution. We would then add water untill we get the final volume of 500 ml (add 481.89 ml of water)
The resulting solution would be a 500 ml solution of 0.350 M ethyleneglycol.
Name these compounds. N₂F4
Answer:
Nitrogen and Fluorine, Tetrafluorohydrazine
Explanation:
A piston at -37.0°C contains a gas that occupies a volume of 2.5 L. To what temperature would the gas have to be heated to increase the volume to 6.3 L at constant pressure?
answer and explanation
Charles's law tells use the relationship between volume and temperature of a gas by the equation
V1/T1 = V2/T2
from the data provided we find V2 by:
37/2.5 = V2/6.3
V2 = 93.2 degrees
the gas would have to be heated to 93.2 degrees to expand in volume to 6.3L
Which statement is NOT true? 1. Sodium chloride and other conducting solutes are called electrolytes. 2. Sugar and other non-conducting solutes are called non-electrolytes. 3. A solution in which water is the solvent is known as an aqueous solution. 4. A solute dissolves other substances that are called solvents. The resultant mixture is known as a solution.
1. True ; an electrolyte is a substance that conducts electric current.
2. True ; a non eletrolyte, like sugar and ethanol, is a compound that doesnt conduct electic current .
3. True; An aqueous solution is a solution in which water is the solvent.
4. False; A solute is the substnce that dissolves in a solvent to produce a homogeneous mixture.
In a nuclear power plant,
Does any of the radioactive material leave the containment building? Yes or No
Does anything that comes in contact with radioactive material leave the containment building? Yes or no
1. Yes, radioactive material leave the containment building.
2. Yes, anything that comes in contact with radioactive material leave the containment building.
In order to ensure that they do not endanger the people or the environment, nuclear power plants occasionally leak radioactive gases and liquids into the environment.
The nuclear power plant's plume of radioactive pollutants can settle and contaminate buildings, people outside, food, water, and livestock. Additionally, breathing in radioactive substances or consuming contaminated food or beverages can cause radioactive compounds to enter the body.
A reinforced steel, concrete, or lead building that houses a nuclear reactor is called a containment building. It is intended to confine the escape of radioactive steam or gas to a maximum pressure between 275 and 550 kPa in the event of any emergency (40 to 80 psi).
The main means of avoiding contamination from entering the environment, coming into contact with, or ingesting individuals is containment. Radioactive material is distinct from radioactive contamination since it must be contained.
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15 Mia is a nanny for three small children. Their parents have laid out dinner, including broiled chicken tenders, broccoli, and steamed carrots. When Mia puts the plates in front of them, one of the kids makes a face and announces, “I don’t eat broccoli!” What would be the BEST way for Mia to respond? A. “Your mom and dad say you need to eat it.” B. “Broccoli is good for you so eat all of it.” C. “Why don’t you at least take one bite?” D. “That’s ok as long as you eat the chicken.”
Mia is a nanny for three small children their parents have laid out dinner, including broiled chicken tenders, broccoli, and steamed carrots when Mia puts the plates in front of them, one of the kids makes a face and announces, “I don’t eat broccoli!” then best way for Mia to respond is “Why don’t you at least take one bite?”
Here according to the given data mia is a nanny for three small children. their parents have laid out dinner, including broiled chicken tenders, broccoli, and steamed carrots when Mia puts the plates in front of them, one of the kids makes a face and announces, “I don’t eat broccoli!” then mia respond is “Why don’t you at least take one bite?” because mia is encouraging the small children to eat the broccoli because broccoli is the good for our health and it is packed with vitamins and minerals and it has a good source of calcium
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Determine the percentage by mass of each element in the following compounds. (Round your answers to one decimal place.)(a)milk of magnesia, Mg(OH)2Mg:____%O:______%H:______%(b)lye, NaOHNa:____%O:_____%H:_____%
Firstly we will calculate the mass of the molecule by adding the together the atomic mass of each element:
[tex]\begin{gathered} Mg:24.31g \\ O:16.00g \\ H:1.00g \\ _mMg(OH)_2=24.31+(16.00\times2)+(1.01\times2) \\ _mMg(OH)_2=58.33gmol^{-1} \\ \\ \\ Na:22.99g \\ O:16.00g \\ H:1.01g \\ _mNaOH=22.99+16.00+1.01 \\ _mNaOH=40gmol^{-1} \end{gathered}[/tex]Now we will determine the percentage mass of each of element:
[tex][/tex]What concentration of NO−3 results when 885 mL of 0.463 M NaNO3 is mixed with 731 mL of 0.787 M Ca(NO3)2?
The concentration of NO−3 will be 1.99 M
NaNO3 ionizes as follows:
NaNO3 ⇒ Na+ + [tex]NO^{3-}[/tex]
Moles NaNO3 dissolved ⇒ (0.463 mol/L) /(0.885 L) = 0.5231 mol
From the chemical equation, one mole of NaNO3 dissolving yields one mole of [tex]NO^{3-}[/tex]in solution.
Moles [tex]NO^{3-}[/tex] = 0.5231 mol
Ca(NO3)2 dissolves as follows:
Ca(NO3)2 ⇒ Ca2+ + 2 [tex]NO^{3-}[/tex]
Moles Ca(NO3)2 dissolved ⇒ (0.787 mol/L)/ (0.731 mL) = 1.07 mol
From the chemical equation, one mole of Ca(NO3)2 dissolving yields two moles of [tex]NO^{3-}[/tex] in solution.
Moles NO3^- = 1.07 molx 2 = 2.14mol
Total moles [tex]NO^{3-}[/tex]in solution=2.14 mol + 1.07 mol = 3.21 mol
Total volume of solution ⇒ 0. 731 L + 0.885 L = 1.61 L
Molarity of [tex]NO^{3-}[/tex]⇒ 3.21 mol / 1.61 L = 1.99 M
Therefore, concentration will be 1.99 M.
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10. 1.29 dag of sodium chloride is reacted with 25.0 dag of silver nitrate10. Balanced Chemical Equation: Reaction Type:At completion of reactions: Formula of Reactant A: Grams of Reactant A: Formula of Reactant B:Grams of Reactant B: Formula of Product C:Grams of Product C: Formula of Product D:Grams of Product D:
So,
Let's first convert some units:
[tex]\begin{gathered} 1.29dag\cdot\frac{10g}{1dag}=12.9g \\ \\ 25.0\text{dag}\cdot\frac{10g}{1\text{dag}}=250g \end{gathered}[/tex]So,
There's a reaction between 12.9g of sodium chloride and 250g of silver nitrate.
The reaction that occurs here, is the next one:
[tex]NaCl+AgNO_3\to AgCl+NaNO_3[/tex]Sodium chloride reacts with silver nitrate to form silver chloride and sodium nitrate.
This reaction is a displacement reaction.
Now, let's complete the information:
Formula of Reactant A: NaCl
Grams of Reactant A: 12.9g
Formula of Reactant B: AgNO3
Grams of Reactant B: 250g
Formula of Product C: AgCl
Grams of Product C: ?
Formula of Product D: NaNO3
Grams of Product D: ?
We need to find the amount of grams of the formed products.
So, let's first convert the grams of each reactant in moles. Remember that the number of moles (n) can be found if we divide the given mass of the given compound by its molar mass. So,
[tex]\begin{gathered} n_{NaCl}=\frac{12.9gNaCl}{\frac{58.5gNaCl}{\text{mol}}}=0.22\text{molesNaCl} \\ _{} \\ n_{AgNO_3}=\frac{250gAgNO_3}{\frac{169.87gAgNO_3}{mol}}=1.47molesAgNO_3 \end{gathered}[/tex]The limiting reactant in this reaction is NaCl. So, we're going to use the reaction's stoichiometry to find the amount of the products as follows:
[tex]0.22mol\text{NaCl}\cdot\frac{1\text{molAgCl}}{1\text{molNaCl}}\cdot\frac{143.32\text{gAgCl}}{1\text{molAgCl}}=31.53\text{gAgCl}[/tex]Thus, there are 31.53g of AgCl formed.
Finally, let's find the amount of grams of product D (NaNO3):
[tex]0.22mol\text{NaCl}\cdot\frac{1\text{molNaNO}3}{1\text{molNaCl}}\cdot\frac{84.99\text{gNaNO}3}{1\text{molNaNO}3}=18.69\text{gNaNO}3[/tex]Therefore,
There were formed 31.53g of AgCl (product C) and 18.69g of NaNO3 (product D)
How many atoms are in 140 moles of Gold?
Answer:862470.84
Explanation:
1 mole of substance is exactly equal to 6.023 × 10 ²³ molecules. 843.22 × 10²³ atoms are in 140 moles of Gold.
What do you mean by mole ?The term mole is defined as the amount of substance of a system which contains as many elementary entities.
1 mole is equal to 6.023 × 10 ²³ molecules.
One mole of any substance is equal to 6.023 × 10²³ units of that substance such as atoms, molecules, or ions. The number 6.023 × 10²³ is called as Avogadro's number or Avogadro's constant.
The mole concept can be used to convert between mass and number of particles.
1 mole = 6.023 × 10²³ molecules ( Avogadro number )
Then 1 mole of gold = 6.023 × 10²³ molecules
140 moles of gold = 140 × 6.023 × 10²³
= 843.22 × 10²³ atoms
Thus, 843.22 × 10²³ atoms are in 140 moles of Gold.
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A species whose oxidation number decreases in a reaction is said to be which of the following?electrolyzedoxidizedauto-oxidizedreduced
Answer
Reduction
Procedure
A redox reaction is a reaction that involves the transfer of electrons between chemical species. During a redox reaction, some species undergo oxidation, or the loss of electrons, while others undergo reduction or the gain of electrons.
An atom’s oxidation number is the charge that the atom would have if all of the bonds to the atom were completely ionic. An increase in oxidation number during a reaction corresponds to oxidation, while a decrease corresponds to reduction.
Radium decays according to the functionQC) - Qewhere Q represents the quantity remaining after tyears and kis the decayconstant 0.00043. How long will take for 40g of radium to decay to 10g?A. Approx. 93 yearsB. Approx 3224 yearsC. Approx 8579 yearsD. Approox. 2144 years
First, we have the next data:
Q(t) = final mass at time t = 10 g
Qo = initial mass = 40 g
v = decay constan = 0.00043 1/years
This kind of process like decay, follow a first-order reaction, and the formula used for this:
[tex]\begin{gathered} Q(t)=Qoxe^{-vxt} \\ \text{Clearing t:} \\ \frac{Q(t)}{Qo}=e^{-vxt} \\ \ln (\frac{Q(t)}{Qo})=-\text{vxt} \\ \frac{\ln (\frac{Q(t)}{Qo})}{-\text{v}}=t \end{gathered}[/tex][tex]\begin{gathered} \frac{\ln (\frac{10}{40})}{-0.00043\text{ 1/years}}=\text{ t} \\ \end{gathered}[/tex]Answer: t = 3224 years
How many grams of NH3 would get if you started with 5.0 g of (NH4)2CO3
According to the chemical equation one mol of (NH4)2CO3 produces 2 mol of NH3
[tex](NH_4)_2CO_3\Longrightarrow2NH_3+CO_2+H_2O[/tex]When expresed in mass 96.09 grams of (NH4)2CO3 produce 34 grams of NH3 when we keep this proportion for the 5 grams we obtain:
[tex]5gof(NH_4)_2CO_3\text{ }\frac{34gofNH_3_{}}{96.09\text{ g of}(NH_4)_2CO_3\text{ }}=1.76gofNH_3[/tex]I wanted to know the units or if the units I put on the table is right. For example the unit for mass of solid or the unit for volume of water
Answer
All the units were correct.
The unit of part b can either be any of milliliter or cubic centimeter
Density = 12446.71 g/mL
Explanation
All the units were correct.
Note:
1 milliliter = 1 cubic centimeter
g = grams
mL = milliLiter
The unit of part b can either be any of milliliter or cubic centimeter
The unit of the mass is g
The unit of the volume is mL
The unit of density is g/mL
The density of the solid = mass/volume = 87127/7 = 12446.71 g/mL
How many C atoms are there in 5.11 moles of C?
From the question, we are given the following parameters
Moles of Carbon = 5.11 moles
Acording to the Avogadro's constant;
[tex]1\text{mole of C=6.02}\times10^{23}atoms[/tex]The number of atoms contained in 5.11 moles of Carbon will be expressed as:
[tex]\begin{gathered} number\text{ of carbon atom=}5.11\times6.02\times10^{23} \\ number\text{ of carbon atom}=30.7622\times10^{23} \\ number\text{ of carbon atom}=3.08\times10^{24}atoms \end{gathered}[/tex]
Therefore the number of carbon atoms that are in 5.11 moles of C is
3.08 * 10²⁴atoms