Select all of the expressions that are less than 10103O A 103хB. 1x 10oC 103 x 2OD } x 103O E 103
Answers
Let's check every option:
[tex]10\frac{2}{3}=\frac{32}{3}\approx10.667[/tex]A.
[tex]10\frac{2}{3}\times\frac{9}{10}=9.6<10.667[/tex]This option is correct
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B.
[tex]1\times10\frac{2}{3}=10.667=10.667[/tex]This option is not correct.
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C.
[tex]10\frac{2}{3}\times2\frac{1}{3}\approx24.888>10.667[/tex]This option is not correct
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D.
[tex]\frac{1}{8}\times10\frac{2}{3}\approx1.33<10.667[/tex]This option is correct
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E.
[tex]10\frac{2}{3}\times\frac{3}{5}=6.4<10.667[/tex]This option is correct
Answer:
A
D
E
Related Questions
-8, {0, -3, 1, -1}, {-1, 1, -2}, {3, -5, 4, -1}, {4, -2, 2}
Answers
Solution
17. -8
18. 0, -3 ,1 , -1
19. -1 ,1 ,-2
20. 3, -5 ,4 ,-1
21. 4, -2. 2
A rectangular prism has volume 10,878 cubic feet, length 7 feet, and height 42 feet. Find its width, in feet.
Answers
Answer: The width is 37 feet
Given data
Volume = 10, 878 cubic feet
Length = 7 feet
Height = 42 feet
width = ?
Let width = w
Volume of the rectangular prism = l x w x h
10, 878 = 7 x 42 x w
10, 878 = 294 x w
10, 878 = 294w
Divide both sides by 294
10, 878 /294 = 294w/294
w = 10, 878 / 294
w = 37 feet
Therefore, the width is 37 feet
The circumference of a circle is 56.52 what is the diameter
Answers
SOLUTION
We have been given the circumfeence of the circle as 56.52 and we are told to find the diameter
Circumference of a circle C is found as
[tex]\begin{gathered} C\text{ }=\pi d \\ \text{Where }\pi\text{ = 3.14 and d is the diameter. So from } \\ C\text{ }=\pi d \\ 56.52\text{ }=3.14d \\ d\text{ = }\frac{56.52}{3.14} \\ \\ d\text{ = 18} \end{gathered}[/tex]Therefore, the diameter is 18
I kinda started it but I don’t know how to find the answer
Answers
Solution
[tex]\begin{gathered} x^2+2x-16=0 \\ \\ \text{ using quadratic formula} \\ \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ a=1,b=2,c=-16 \\ \\ \Rightarrow x=\frac{-2\pm\sqrt{2^2-4(1)(-16)}}{2(1)} \\ \\ \Rightarrow x=\frac{-2\pm\sqrt{4+64}}{2} \\ \\ \Rightarrow x=-1-\sqrt{17} \\ \\ \Rightarrow x=-1+\sqrt{17} \\ \\ \text{ since }x>0 \\ \\ \text{ Therefore the value of }x=-1+\sqrt{17} \end{gathered}[/tex]"Solve for all values of x on the given intervals. Write all answer in radians." I am stuck on number 4
Answers
Answer:
[tex]x=\frac{2\pi}{3}+2\pi n,x=\frac{4\pi}{3}+2\pi n[/tex]Explanation:
Given the equation:
[tex]\sin x\tan x=-2-\cot x\sin x[/tex]Add 2+cot(x)sin(x) to both sides of the equation.
[tex]\begin{gathered} \sin x\tan x+2+\cot x\sin x=-2-\cot x\sin x+2+\cot x\sin x \\ \sin x\tan x+2+\cot x\sin x=0 \end{gathered}[/tex]Next, express in terms of sin and cos:
[tex]\begin{gathered} \sin x\frac{\sin x}{\cos x}+2+\frac{\cos x\sin x}{\sin x}=0 \\ \frac{\sin^2x}{\cos x}+2+\cos x=0 \\ \frac{\sin^2x+2\cos x+\cos^2x}{\cos(x)}=0 \\ \implies\sin^2x+2\cos x+\cos^2x=0 \end{gathered}[/tex]Apply the Pythagorean Identity: cos²x+sinx=1
[tex]2\cos x+1=0[/tex]Subtract 1 from both sides:
[tex]\begin{gathered} 2\cos x+1-1=0-1 \\ 2\cos x=-1 \end{gathered}[/tex]Divide both sides by 2:
[tex]\cos x=-\frac{1}{2}[/tex]Take the arccos in the interval (-∞, ):
[tex]\begin{gathered} x=\arccos(-0.5) \\ x=\frac{2\pi}{3}+2\pi n,x=\frac{4\pi}{3}+2\pi n \end{gathered}[/tex]The values of x in the given interval are:
[tex]x=\frac{2\pi}{3}+2\pi n,x=\frac{4\pi}{3}+2\pi n[/tex]Convert repeating decimal 0.155….to fraction
Answers
Given the repeating decimal 0.155...
We will convert it to a fraction as follows:
[tex]\begin{gathered} 0.1555.\ldots=0.1+0.055\ldots \\ \\ =\frac{1}{10}+\frac{5}{100-10} \\ \\ =\frac{1}{10}+\frac{5}{90}=\frac{9}{90}+\frac{5}{90}=\frac{14}{90}=\frac{7}{45} \end{gathered}[/tex]so, the answer will be:
[tex]0.1555\ldots=\frac{7}{45}[/tex]How do I go about solving it. What would the answer be?
Answers
The given sum is
[tex]\sum ^9_{k\mathop=4}(5k+3)[/tex]This means we have to replace k = 4, 5, 6, 7, 8, 9, and then we sum
[tex]\begin{gathered} (5\cdot4+3)+(5\cdot5+3)+(5\cdot6+3)+(5\cdot7+3)+(5\cdot8+3)+(5\cdot9+3) \\ 20+3+25+3+30+3+35+3+40+3+45+3=213 \\ \end{gathered}[/tex]Hence, the sum is equal to 213. The right answer is C.Use the circle graph below to answer each question. 1. What percent of the Milton's budget is for rent? 2. What percent of the Milton's budget is for clothes? 3. If the Milton's have a $2,000 budget, how much of that budget will go in savings? 4. If the Milton's have a $2,000 budget, how much of that budget will go towards food? 5. If the Milton's have a $2,000 budget, how much of that budget will go towards misc items?
Answers
We are given the Pie chart of Milton's family budget with the following detail:
Food = 33%
Rent = 25%
Savings = 6%
Clothes = 15%
Misc = 21%
1. The percentage of the budget allocated to rent is 25%
2. The percentage of the budget allocated to clothes is 15%
3.
If the budget is $2,000, the amount allocated to Savings is:
[tex]\begin{gathered} Savings=6\text{\%}\times\text{\$}2,000 \\ Savings=\frac{6}{100}\times2,000 \\ Savings=\text{ \$}120 \end{gathered}[/tex]4.
If the budget is $2,000, the amount allocated to food is:
[tex]\begin{gathered} Food=33\text{\%}\times\text{\$}2,000 \\ Food=\frac{33}{100}\times2,000 \\ Food=\text{\$}660 \end{gathered}[/tex]5.
If the budget is $2,000, the amount allocated to Misc is:
[tex]\begin{gathered} Misc=21\text{\%}\times\text{\$}2,000 \\ Misc=\frac{21}{100}\times2,000 \\ Misc=\text{\$}420 \end{gathered}[/tex]Graph the line y = 3/2x + 7y=3/2 x + 2
Answers
Given:
The equation of line is,
[tex]y=\frac{3}{2}x+2[/tex]Find the points on line.
[tex]\begin{gathered} y=\frac{3}{2}x+2 \\ \text{For x=2} \\ y=\frac{3}{2}\times2+2=5 \\ \text{For x}=-2 \\ y=\frac{3}{2}\times(-2)+2=-1 \\ \text{For x=0} \\ y=\frac{3}{2}(0)+2=2 \\ \text{ For x=4} \\ y=\frac{3}{2}(4)+2=8 \end{gathered}[/tex]So, the points are ( 2,5),(-2,-1),(0,2),(4,8).
The graph of the equation of line is,
the cost of 9kg of rice is $111.24a)what is the cost of 10kg?b)what is the cost of 10.6kg?
Answers
SOLUTION:
Case: Unit rates
Given: 9kg of rice cost $111.24
First we calculate the cost per kg
Since 9kg cost $111.24
1kg will be:
[tex]\begin{gathered} 1kg\text{ of rice =}\frac{111.24}{9} \\ 1kg\text{ of rice = 12.36} \end{gathered}[/tex]1kg costs $12.36
a) the cost of 10kg
The cost of 10kg will be:
[tex]\begin{gathered} 10kg\text{ of rice will be} \\ =\text{ 10 }\times12.36 \\ =\text{ 123.60} \end{gathered}[/tex]The cost of 10kg of rice is $123.60
b) the cost of 10.6kg
The cost of 10.6kg will be:
[tex]\begin{gathered} 10.6kg\text{ of rice will be} \\ =10.6\text{ }\times12.36 \\ =\text{ 131.0}2 \end{gathered}[/tex]The cost of 10.6kg of rice is $131.02
Final answer:
a) The cost of 10kg of rice is $123.60
b) The cost of 10.6kg of rice is $131.02
10.6 kg cost will be 131.016
*DUE TODAY* ANSWER ASAP Olivia has read 40 pages of a 70 page book, 60 pages of an 85 page book and 43 of a 65 page book. What is the percentage of pages Olivia has not read? PLEASE GIVE ME A STEP BY STEP EXPLANATION PLEASE!
Answers
STEP2: turn all of the fractions you have just made into percentages ( divide the numerator by the denominator then, times by 100)
STEP 3: add all of the percentages up and put the sum of them all over 300 ( e.g each percentage added up / 300 )
STEP 4: turn that fraction you just made back into a percentage then that should be your answer!!!
If you need any more help just ask me!
3 view. writing simplity expressions The volume of a cube is calculated by multiplying all three side lengths. If a cube has a side of 16 cm, which expression can be used to calculate the volume? A. 161 B. 167 C. 162 D. 164 에 2y Click to add speaker notes
Answers
If we have a cube with a side length of 16 cm, we can calculate the volume as the length side powered to the 3rd or multiplying the side length 3 times:
[tex]V=l\cdot l\cdot l=l^3=16^3[/tex]Answer: V = 16^3 (Option C).
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into thecorrect position in the answer box. Release your mouse button when the item is place. If you change your mind, dragthe item to the trashcan. Click the trashcan to clear all your answers.Indicate in standard form the equation of the line through the given points.K(6,4), L(-6,4)
Answers
The equation between two points is given as:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]Plugging the values of the points given we have:
[tex]\begin{gathered} y-4=\frac{4-4}{-6-6}(x-6) \\ y-4=\frac{0}{-12}(x-6) \\ y-4=0(x-6) \\ y-4=0 \\ y=4 \end{gathered}[/tex]Therefore the equation in standar form is:
[tex]y=4[/tex]The length of an arc of a circle is 5/3 pi feet. Find the measure of the angle that subtends (forms)the arc if the diameter is 18 feet.
Answers
EXPLANATION
We are given the following parameters:
Length of arc= 5/3pi
Diameter = 18 feet
Therefore, radius =18/2 = 9 feets
The formula for the length of the arc is given below.
[tex]\text{length of arc =}\frac{\theta}{360}\times2\pi r^{}[/tex]We will substitute the given parameters into the formula above to get the measure of the angle.
[tex]\begin{gathered} \frac{5}{3}\pi=\frac{\theta}{360}2\pi\times9^{} \\ \frac{5}{3}\pi=\frac{18\theta}{360}\pi \\ crossmultiply\text{ } \\ 3\times18\theta\pi=360\times5\pi \\ 54\theta\pi=1800\pi \\ \text{Divide both sides by 54}\pi \\ \theta=\frac{1800\pi}{54\pi} \\ \theta=33.3^0 \end{gathered}[/tex]Therefore, the measure of the angle is
[tex]\theta=33.3^0[/tex]18. What is the multiple zero and multiplicity of f(x) = (x - 1)(x - 1)(x + 7)?multiple zero = 2; multiplicity = 1multiple zero = 2; multiplicity = -1multiple zero = -1; multiplicity = 2multiple zero = 1; multiplicity = 2
Answers
A polynomial written in factorized form is giving us the information we need about the roots or zeros.
In this case, the polynomial is:
[tex]f(x)=(x-1)(x-1)(x+7)=(x-1)^2(x+7)[/tex]In this case, we have two zeros: x=1 and x=-7.
NOTE: a zero "a" will be expressed in a factor (x-a). That is why the zeros are 1 and -7.
As x=1 appears 2 times as a factor, we can group the factor.
x=1 is a zero with multiplicity of 2.
Answer: the multiple zero is x=1 and has a multiplicity of 2.
multiple zero = 1; multiplicity = 2 [Fourth option]
please help with this question
Answers
if each u it cube has edge's of length 1/2 foot, what is the volume of the blue-outlined prism
we have that
the volume of each cube is equal to
V=(1/2)^3
V=1/8 ft3
the rectangular prism volume is equal to
calculate the volume by the numbers of cube
so
V=(5)(2)(2)=20 cubes
Multiply by the volume of each cube
20*(1/8)=2.5 ft3
the volume of the rectangular prism is 2.5 ft3
The scores of Janet in her math tests are 65, 78, 56, 73, 67, 92. Find themedian score of Janet.
Answers
Answer
70
Explanations;
Given the following datasets that represents the scores of Janet in her math tests
65, 78, 56, 73, 67, 92.
The median is the middle value of the dataset after rearrangement. On rearranging in ascending order;
56, 65 (67, 73) 78, 92
Since there are 2 numbers at the middle, hence the median is the mean value of the data
[tex]\begin{gathered} Median=\frac{67+73}{2} \\ Median=\frac{140}{2} \\ Median=70 \end{gathered}[/tex]Hence the median scores is 70
Parker has tangerines and apricots in a ratio of 12:95. How many apricots does hehave if he has 96 tangerines?On the double number line below, fill in the given values, then use multiplication ordivision to find the missing value.
Answers
We know that if Parker has 12 tangerines he has 95 apricots, so to find how many apricots he has we need to do a rule of tree
[tex]\begin{gathered} x\text{ apricots }\cdot\frac{12\text{ tangerines}}{95\text{ apricots}}=96\text{ tangerines} \\ x\text{ apricots = 96 tangerines }\cdot\frac{95\text{ apricots}}{12\text{ tangerines}} \\ x\text{ apricots =}\frac{96\cdot95}{12}\text{ apricots = }\frac{9120}{12}\text{ apricots} \\ x=760 \end{gathered}[/tex]So the answer is that Parker has 760 apricots is he has 96 tangerines.
A sequence is shown below.10, 12, 14, 16, ...Which function can be used to determine the nthnumber in the sequence?
Answers
Answer:
The nth term of the given sequence can be determined using the function;
[tex]a_n=2n+8[/tex]Explanation:
Given the sequence;
[tex]10,12,14,16,\ldots[/tex]The sequence is an arithmetic progression with a common difference d and first term a;
[tex]\begin{gathered} d=12-10 \\ d=2 \\ a=10 \end{gathered}[/tex]Recall that the nth term of an AP can be calculated using the formula;
[tex]a_n=a+(n-1)d[/tex]substituting the given values;
[tex]\begin{gathered} a_n=a+(n-1)d \\ a_n=10+(n-1)2 \\ a_n=10+2(n-1) \\ a_n=10+2n-2 \\ a_n=2n+10-2 \\ a_n=2n+8 \end{gathered}[/tex]Therefore, the nth term of the given sequence can be determined using the function;
[tex]a_n=2n+8[/tex]Find the degree and leading coefficient for the given polynomial.−5x^2 − 8x^5 + x − 40degree leading coefficient
Answers
The given polynomial is
- 5x^2 - 8x^5 + x - 40
It can be rewritten as
- 8x^5 - 5x^2 + x - 40
The degree of the polynomial is the highest exponent of the variable in the polynomial. The highest exponent of x is 5. Thus,
degree = 5
The leading coefficient is the coefficient of the term with the highest variable. The coefficient of x^5 is - 8. Thus,
Leading coefficient = - 8
If x varies directly as y, and x=-30 when y=-6, find x when y=-4.
Answers
Let us now introduce a constant 'k' inorder to get the relationship between x and y,
[tex]\begin{gathered} x\propto ky \\ x=ky \end{gathered}[/tex]Let us substitute x = -30 and y = -6 inorder to get the relationship,
[tex]\begin{gathered} -30=k\times-6 \\ -30=-6k \\ \text{divide both sides by -6} \\ \frac{-30}{-6}=\frac{-6k}{-6} \end{gathered}[/tex][tex]\begin{gathered} k=5 \\ \text{The relationshiop betw}een\text{ x and y is,} \\ x=5y \end{gathered}[/tex]Let us now solve for x when y = -4,
[tex]\begin{gathered} x=5y \\ x=5\times-4 \\ x=-20 \end{gathered}[/tex]Hence, x is -20.
John flew a kite. He started flying the cat at 2:20 p.m. and ended at 3:14 p.m. How many minutes did John fly a kite?A. 47 minutesB. 50 minutesC. 54 minutesD. 55 minutes
Answers
Given data:
The initial time is t=2:20 pm.
The final timme is t'=3:14 pm.
The time during which kite fly is,
[tex]\begin{gathered} T=3\colon14-2\colon20 \\ =54\text{ min} \end{gathered}[/tex]Thus, option (C) is correct.
How many solutions does the equation −5a + 5a + 9 = 8 have? (5 points)NoneOneTwoInfinitely many
Answers
ANSWER:
1st option: none
STEP-BY-STEP EXPLANATION:
We have the following equation:
[tex]−5a\:+\:5a\:+\:9\:=\:8\:[/tex]We solve for a:
[tex]\begin{gathered} −5a\:+\:5a\:+\:9\:=\:8\: \\ \\ 0+9=8 \\ \\ 9=8\rightarrow\text{ false} \end{gathered}[/tex]Therefore, the equation has no solution, the correct answer is 1st option: none
A patient takes three 25 mg capsules a day. How many milligrams is he taking daily?
Answers
Given:
A patient takes three 25 mg capsules a day.
[tex]3\times25\text{ mg=75mg}[/tex]Answer: A patient is taking 75 mg capsules every day.
18 18 After bisecting the original angle, there are two angles that each measure 18°. Which statement is true? A) The original angle of 2° was bisected into two congruent angles. B) The original angle of 9° was bisected into two congruent angles. Eliminate The original angle of 36° was bisected into two congruent angles. D) The original angle of 72° was bisected into two congruent angles.
Answers
After bisecting the original angle, there are two angles that each measure 18°. Which statement is true? A) The original angle of 2° was bisected into two congruent angles. B) The original angle of 9° was bisected into two congruent angles. Eliminate The original angle of 36° was bisected into two congruent angles. D) The original angle of 72° was bisected into two congruent angles.
we know that
when bisecting an angle, the angle is divided into two equal parts
so
The original measure of the angle is
18(2)=36 degrees
therefore
The statement that is true is
The original angle of 36° was bisected into two congruent anglesa. angle addition postulate with angles forming a straight line angle.b. triangle sum theorem c. linear pair postulate
Answers
A. angle addition postulate with angles forming a straight line angle
1) Examining that table, we can see that step 4 is a consequence of the third step, the triangle sum theorem.
2) Then in step 4, we have the following reason to state that the sum of those angles is 180º: Then as we can see below:
We have a Linear Pair between the angles ∠ABD, ∠DBE, and ∠CBE since those angles combined add up to 180º (a straight angle) in red.
3). Hence, the answer is A
Which of the following tables corresponds to the equation below?
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Solution:
Given the equation;
[tex]y=\frac{1}{4}(4^x)[/tex]We would create a table of values such that x ranges from 0 to 5;
[tex]\begin{gathered} x=0; \\ \\ y=\frac{1}{4}(4^0)=\frac{1}{4} \\ \\ (0,\frac{1}{4}) \\ \\ x=1; \\ \\ y=\frac{1}{4}(4^1)=1 \\ \\ (1,1) \\ \\ x=2; \\ \\ y=\frac{1}{4}(4^2)=4 \\ \\ (2,4) \end{gathered}[/tex]Then;
[tex]\begin{gathered} x=3; \\ \\ y=\frac{1}{4}(4^3)=16 \\ \\ (3,16) \\ \\ x=4; \\ \\ y=\frac{1}{4}(4^4)=64 \\ \\ (4,64) \\ \\ x=5; \\ \\ y=\frac{1}{4}(4^5)=256 \\ \\ (5,256) \end{gathered}[/tex]Thus, the correct table is;
Answer:
its D
Step-by-step explanation:
6y-(2y-5)=29 step by step
Answers
The given expression is
[tex]6y-(2y-5)=29[/tex]First, we use the distributive property to solve the parenthesis, we have to multiply the negative sign with each term inside the parenthesis.
[tex]6y-2y+5=29[/tex]We reduce like terms, 6y and -2y are like terms in this case,
[tex]4y+5=29[/tex]Then, we subtract 5 on each side.
[tex]\begin{gathered} 4y+5-5=29-5 \\ 4y=24 \end{gathered}[/tex]At last, we divide the equation by 4.
[tex]\begin{gathered} \frac{4y}{4}=\frac{24}{4} \\ y=6 \end{gathered}[/tex]Therefore, the solution is 6.the dot is on the secomd line if you cant see it
Answers
The fraction of the hour joey used for practicing the piano can be gotten from the gaps in the number line.
Since there are 3 equal gaps in the number line , this denotes the fraction of the hour that each gap would represent is
[tex]\frac{1}{3}[/tex]This implies that the first point is = 0
This implies that the second point is = 1/3
This implies that the third point is = 2/3
This implies that the fourth point is = 1
In conclusion, the answer is B for the second point.
What is the least common denominator for the following rational equation?x/x+2 + 1/x+4 = x-1/x^2-2x-24
Answers
Least Common Denominator (LCD)
We are required to find the LCD for the expression:
[tex]\frac{x}{x+2}+\frac{1}{x+4}=\frac{x-1}{x^2-2x-24}[/tex]We need to have every denominator as the product of the simplest possible expressions.
Since x+2 and x+4 are already factored, we need to factor the expression:
[tex]x^2-2x-24=(x-6)(x+4)[/tex]Now we have the following prime factors:
x+2, x+4, x-6 and x+4
The LCD is the product of all the prime factors:
LCD = (x+2)(x+4)(x-6)