Round .00000572. Using single digit and power of 10

Answers

Answer 1

Given that

There is a number and we have to round it using the single digit and in powers of 10.

Explanation -

Whenever we convert a decimal number into powers of 10.

The power of 10 is always equal to the negative number of digits after the decimal.

Then, the number 0.00000572 can be written as0

[tex]0.00000572=5.72\times10^{-6}[/tex]

Now we have to round off it to a single digit.

Then,

[tex]5.72\times10^{-6}\approx6\times10^{-6}[/tex]

Final answer -

Therefore the final answer is 6 x 10^(-6)

Related Questions

If D and R denote the degree and radian measure of an angle, then prove that D/180=R/pie

Answers

Given: D and R denote the degree and radian measure of an angle

To Determine: The prove that D/180=R/pie​

Solution

Please note that

[tex]180^0=\pi radians[/tex]

So

[tex]1^0=\frac{\pi}{180^}radian[/tex]

Then

[tex]\begin{gathered} D^0=D\times\frac{\pi}{180}radian \\ D^0=\frac{D\pi}{180}radians \end{gathered}[/tex]

Therefore

[tex]\frac{D\pi}{180}=R[/tex]

Let us divide both sides by pie

[tex]\frac{D\pi}{180}\div\pi=R\div\pi[/tex]

[tex]\begin{gathered} \frac{D\pi}{180}\times\frac{1}{\pi}=R\times\frac{1}{\pi} \\ \frac{D}{180}=\frac{R}{\pi} \end{gathered}[/tex]

Hence, the above help to prove that D/180 = R/pie

Five hundred students in your school took the SAT test. Assuming that a normal curve existed for your school, how many of those students scored within 2 standard deviations of the mean? (Give the percent and the number.)

Answers

In order to find the percentage of students within 2 standard deviations, let's look at the z-table for the percentages when z = -2 and z = 2.

From the z-table, we have that the percentage for z = -2 is 0.0228 and for z = 2 is 0.9772.

The percentage between z = -2 and z = 2 is given by:

[tex]0.9772-0.0228=0.9544[/tex]

Therefore the percentage is 95.44%.

Now, calculating the number of students within this percentage, we have:

[tex]500\cdot0.9544=477.2[/tex]

Rounding to the nearest whole, we have 477 students.

while shopping at a 30% off sale, Robin was told that the sale price would saver her $6 on her purchase. Since the original price tag was missing, she had to calculate the price. what was the original price.

Answers

To do this, let x be the original price. Since the sale price would save you $ 6 on your purchase and this equates to 30% off, then using the rule of three you can find the original price, like this

[tex]\begin{gathered} \text{ \$6}\Rightarrow30\text{ \%} \\ x\Rightarrow100\text{ \%} \\ x=\frac{100\text{ \%}\cdot\text{ \$6}}{30\text{ \%}} \\ x=\text{ \$}\frac{600}{30} \\ x=\text{ \$20} \end{gathered}[/tex]

Therefore, the original price was $20.

Verifying you have

[tex]\text{ \$20}\ast30\text{ \%= \$20}\cdot\frac{30}{100}=\text{ \$20}\cdot0.3=\text{ \$6}[/tex]

Which was the $6 that Robin saved on his purchase.

Parabola in the form x^2=4pyIdentify Vertex, value of P, focus, and focal diameter.Identify endpoints of latus rectumWrite equations for the directrix and axis of symmetry X^2= -12y

Answers

Answer:

(a)

• The vertex of the parabola, (h,k)=(0,0)

,

• The value of p = -3

• The focus is at (0,-3).

,

• The focal diameter is 12

(b)The endpoints of latus rectum are (-1/12, -1/6) and (-1/12, 1/6).

(c)See Graph below

(d)

• I. The equation for the directrix is y=3.

,

• II. The axis of symmetry is at x=0.

Explanation:

Given the equation of the parabola:

[tex]x^2=-12y[/tex]

For an up-facing parabola with vertex at (h, k) and a focal length Ipl, the standard equation is:

[tex](x-h)^2=4p(y-k)[/tex]

Rewrite the equation in the given format:

[tex]\begin{gathered} (x-0)^2=4(-3)(y-0) \\ \implies(h,k)=(0,0) \\ \implies p=-3 \end{gathered}[/tex]

• The vertex of the parabola, (h,k)=(0,0)

,

• The value of p = -3

The focus is calculated using the formula:

[tex]\begin{gathered} (h,k+p) \\ \implies Focus=(0,0-3)=(0-3) \end{gathered}[/tex]

• The focus is at (0,-3).

Focal Diameter

Comparing the given equation with x²=4py, we have:

[tex]\begin{gathered} x^2=4ay \\ x^2=-12y \\ 4a=-12 \\ \implies a=-3 \\ \text{ Focal Diameter =4\mid a\mid=4\mid3\mid=12} \end{gathered}[/tex]

The focal diameter is 12

Part B (The endpoints of the latus rectum).

First, rewrite the equation in the standard form:

[tex]\begin{gathered} y=-\frac{1}{12}x^2 \\ \implies a=-\frac{1}{12} \end{gathered}[/tex]

The endpoints are:

[tex]\begin{gathered} (a,2a)=(-\frac{1}{12},-\frac{1}{6}) \\ (a,-2a)=(-\frac{1}{12},\frac{1}{6}) \end{gathered}[/tex]

The endpoints of latus rectum are (-1/12, -1/6) and (-1/12, 1/6).

Part C

The graph of the parabola is given below:

Part D

I. The equation for the directrix is of the form y=k-p.

[tex]\begin{gathered} y=0-(-3) \\ y=3 \end{gathered}[/tex]

The equation for the directrix is y=3.

II. The axis of symmetry is the x-value at the vertex.

The axis of symmetry is at x=0.

Evaluate the function.
f(x)=(x−7)2+4
for f(−6)
f(−6)

Answers

F(-6) = x^2 + 14x + 53

Answer:

F(-6) = 173

Hope this helps!

Can you please write the basic equation forConstant parent functionInverse sine parent functionInverse cosine parent function Inverse tangent parent function

Answers

Answer:

• In order to understand this, we need to know that an inverse trigonometric function “undo” what the original trigonometric function

• e.g Trig function : inverse of trig. function .

Explanations :(a) Inverse sine parent function:

The inverse y = six x parent function will be

[tex]\begin{gathered} y=sinx^{-1}\text{ ; meaning } \\ x\text{ = sin y } \end{gathered}[/tex]

• y = sinx ^-1 , has domain at [-1;1] and range at (-/2; /2)

(b)Inverse cosine parent function

the inverse of y = cos x parent function will be :

[tex]\begin{gathered} y=cosx^{-1};\text{ meaning } \\ x\text{ = cos y } \end{gathered}[/tex]

• y = cosx^-1 , has domain at [-1;1] and range at (0;)

(c)Inverse tangent parent function

The inverse of y = tan x parent function will be :

[tex]\begin{gathered} y=tanx^{-1\text{ }},\text{ meaning } \\ x\text{ = tan y } \end{gathered}[/tex]

• y = tanx^-1 has domain at (-∞;∞) and range at (- /2 ; /2)

see the graphs below that shows the asympotes of the trigonometric function.

11/8 Percent / Valuehow can I find it please help me understand it

Answers

Answer:

20 candies represent 3%

Explanation:

Sincne 15% = 100

Let x% = 20, then

100x = 20 * 15

100x = 300

x = 300/100 = 3

Therefore, 20 candies represent 3%

A group of five will rent a car for a spring break trip and divide the costs associated with the car among them. The rental costs $480 for the week. Insurance is an additional $175, they estimated they’ll use 120 gallons of gas, and gas costs around $2.80 per gallon. Estimate how much each friend will pay for the cost associated with the car

Answers

Solution:

Given:

[tex]\begin{gathered} car\text{ rental cost}=\text{ \$}480 \\ Insurance=\text{ \$}175 \\ Gas=120\times2.80=\text{ \$}336 \end{gathered}[/tex]

Thus, the total cost associated with the car is;

[tex]480+175+336=\text{ \$}991[/tex]

Each friend will pay;

[tex]\frac{991}{5}=\text{ \$}198.20[/tex]

Therefore, each friend will pay $198.20

if you travel 35 miles per hour for 4.5 hours hovú far will you travle

Answers

We need to multiply 4.5 hours by 35 miles per hour, as follows:

[tex]4.5\text{ hours}\cdot35\frac{miles}{hour}=157.5\text{ miles}[/tex]

You will travel 157.5 miles

what is the factor of the expression of 39-13 using gcf

Answers

We are asked to find out the GCF of the given expression

[tex]39-13[/tex]

GCF (greatest common factor) is the greatest common factor between two or more numbers.

To find the GCF, let us first list out the common factors of both numbers

Factors of 13 = 1, 13

Factors of 39 = 1, 3, 13, 39

Now which factor is common to both and is greatest?

Yes, it is 13

Therefore, the GCF of the given expression is 13

[tex]39-13=13(3-1)[/tex]

Which of the following options results in a graph that shows exponentialdecay?5 pointsO f(x) 0.4(0.2)^xf(x) = 4(4)^xf(x) = 0.7(1.98)^xOf(x) = 5(1+.1)^x

Answers

Answer

Option A is the answer.

f(x) = 0.4(0.2)ˣ

The value carrying the power of x is less than 1, so, this expression represents exponential decay.

Explanation

The key to knowing which expression is represents an exponential decay or exponential growth is the value of the number carrying the power of x.

If that number is greater than 1, then it represents exponential growth.

But, if that number is lesser than 1 (but greater than 0), then it represents exponential decay.

(2)ˣ represents exponential growth.

(0.5)ˣ represents exponetial decay.

f(x) = 0.4(0.2)ˣ

The value carrying the power of x is less than 1, so, this expression represents exponential decay.

f(x) = 4(4)ˣ

The value carrying the power of x is greater than 1, so, this expression represents exponential growth.

f(x) = 0.7(1.98)ˣ

The value carrying the power of x is greater than 1, so, this expression represents exponential growth.

f(x) = 5(1 + .1)ˣ

The value carrying the power of x is greater than 1, so, this expression represents exponential growth.

Hope this Helps!!!

Fill in the blanks (B1, B2, B3) in the equation based on the graph.(a-B1)2 + (y-B2)² = (B3)²8182=83=Blank 1:

Answers

Given: a circle is given with center (3,-3) and equation

[tex](x-B_1)^2+(y-B_2)^2=(B_3)^2[/tex]

Find:

[tex]B_{1,\text{ }}B_{2,}B_3[/tex]

Explanation: the general equation of the circle with center (a,b) and radius r is

[tex](x-a)^2+(y-b)^2=r^2[/tex]

in the given figure the center of the circle is at (3,-3)

so the equatio of the circle becomes

[tex](x-3)^2+(y+3)^2=(3)^2[/tex]

on comparing eith the given equation we get

[tex]B_1=3,\text{ B}_2=-3\text{ and B}_3=3[/tex]

Use the given row transformation to transform the following matrix.

Answers

The 2 x 2 matrix is given

[tex]\begin{bmatrix}{2} & {8} \\ {10} & {7} \\ {} & {}\end{bmatrix}[/tex]

The row transformation given is:

[tex]\frac{1}{2}R_1[/tex]

this means we take half of all the elements of Row 1

The process is shown below:

[tex]\begin{gathered} \begin{bmatrix}{\frac{1}{2}\times2} & {\frac{1}{2}\times8} & \\ {10} & {7} & {} \\ {} & {} & {}\end{bmatrix} \\ =\begin{bmatrix}{1} & {4} & \\ {10} & {7} & {} \\ {} & {} & {}\end{bmatrix} \end{gathered}[/tex]

Hence, the final matrix Row 2 is same as previous matrix, but Row 1 is half of the elements of previous matrix.

Answer:

[tex]\begin{bmatrix}{1} & {4} & \\ {10} & {7} & {} \\ {} & {} & {}\end{bmatrix}[/tex]

Lucy's mom started a 529 college fund for her when she was 4 years old inorder to save money for college. She put $9,000 into an account that earnsa 5% compounded annually. Lucy wants to know how much money she willhave when she is 18. Look at her work below.Is her solution correct? If not, describe the mistake(s) in her work.y = 900011+ 9(e)y = 9000 (1.5) 18y = 8133010 26.92

Answers

Explanation:

P = $9000

i = 5% 0.05

We nee to apply the formula:

[tex]\begin{gathered} \frac{FV}{(i+i)^n}=\text{ PV} \\ FV\text{ = }PV\text{ }(1+i)^n \\ FV=9000(1+0.05)^{18}\text{ } \end{gathered}[/tex][tex]undefined[/tex]

I need help please, it’s my math assignment also can you add simple answers

Answers

a)

Step 1:

Draw the scatter diagram from the table

x represents days and y represent set up time

Step 2:

b)

Draw the scatter diagram

Step 3:

c)

Pick two points from the graph to find the linear equation

Points (2 , 16 ) and (6, 11)

[tex]\begin{gathered} \frac{y-y_1}{x-x_1}\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ \frac{y\text{ - 16}}{x\text{ - 2}}\text{ = }\frac{11\text{ - 16}}{6\text{ - 2}} \\ \frac{\text{y - 16}}{x\text{ - 2}}\text{ = }\frac{-5}{4} \\ \frac{y-16}{x-2}\text{ = -1.25} \\ y\text{ - 16 = -1.25x + 2.5} \\ y\text{ = -1}.25x\text{ + 18.5} \end{gathered}[/tex]

The equation is y = -1.25x + 18.5

write the thirteen million, three hundred two thousand, fifty in expanded form.

Answers

Let's begin by listing out the information given to us:

[tex]13,302,050=13,000,000+300,000+2,000+0+50[/tex]

thirteen million = 13,000,000

three hundred and two thousands = 300,000 + 2,000

fifty = 50

13,302,050 = 13,000,000 + 300,000 + 2,000 + 50

NEED HELP ASAPP!!!!!!

Answers

Answer:

second line

Step-by-step explanation:

no more than :

x≤ 52 (the dot is full, 52 is a value)

all of the Patron in part shade and rewrite (x × y)^nas a product of two single powers

Answers

we have

(2*3)^5

we know that

(2*3)^5=(2^5)(3^5)

Rewrite each term as product of two single powers

so

(2^5)(3^5)=(2^3)(2^2)(3^3)(3^2)

Part c

we have

10^2/10^0

when divide, subtract the exponents

so

10^(2-0)

10^2

another way

Any number elevated to zero is equal to 1

so

10^0=1

substitute

10^2/1=10^2

Part f

we have

(2/3)^5

we know that

(2/3)^5=2^5/3^5

Help with Algebra 2 question.14) An angle is in standard position and is terminal side pauses through point (-2,5), find sec.

Answers

Given:

An angle is in standard position and is terminal side passes through the point (-2,5),

Required:

To find the value of the secant function.

Explanation:

The value of the secant function is given as:

[tex]sec\theta=\frac{r}{x}[/tex]

Where

[tex]r=\sqrt{x^2+y^2}[/tex]

Consider x= -2 and y = 5

Now calculate the value of r by using the formula:

[tex]\begin{gathered} r=\sqrt{(-2)^2+(5)^2} \\ r=\sqrt{4+25} \\ r=\sqrt{29} \end{gathered}[/tex]

Thus the required value is:

[tex]sec\theta=\frac{\sqrt{29}}{-2}[/tex]

Final Answer:

[tex]sec\theta=-\frac{\sqrt{29}}{2}[/tex]

For each equation chose the statement that describes its solution

Answers

GIven:

The equations

[tex]\begin{gathered} -6(u+1)+8u=2(u-3) \\ 2(v+1)+7=3(v-2)+2v \end{gathered}[/tex]

Required:

Find the correct solution.

Explanation:

The equations,

[tex]\begin{gathered} -6(u+1)+8u=2(u-3) \\ -6u-6+8u=2u-6 \\ -6u+8u=2u \\ -8u+8u=0 \\ 0=0 \\ Hence,\text{ true for all }u. \end{gathered}[/tex]

And

[tex]\begin{gathered} 2(v+1)+7=3(v-2)+2v \\ 2v+2+7=3v-6+2v \\ 9=3v-6 \\ 3v=15 \\ v=5 \end{gathered}[/tex]

Answer:

[tex]\text{ In equation 1, equation is true for all }u\text{ and equation 2 is true for }v=5.[/tex]

graph the line y=-4x

Answers

Solution

x=-2 , y = 8

x=-1, y= 4

x=0, y=0

x= 1, y= -4

x= 2, y=-8

Segment XY measures 5cm. How long is the image of XY after a dilation with: A scale factor of a?

Answers

The image of the XY will be 5 times larger than the after dilation.

What is dilation?

resizing an object is accomplished through a change called dilation. The objects can be enlarged or shrunk via dilation. A shape identical to the source image is created by this transformation. The size of the form does, however, differ. A dilatation ought to either extend or contract the original form. The scale factor is a phrase used to describe this transition.

The scale factor is defined as the difference in size between the new and old images. An established location in the plane is the center of dilatation. The dilation transformation is determined by the scale factor and the center of dilation.

Segment XY mesured as 5cm

It will undergo dilation.

If X(0,0) and Y(x,y)

XY = √x²+y²

The factor we need to multiply, a

X'(0,0), Y'(ax,ay)

So the X'Y'=√a²x²+a²y²

X'Y'=a√x²+y²

X'Y'=aXY = 5a

Hence the image of the XY will be 5 times larger than the after dilation.

Learn more about dilation, by the following link

https://brainly.com/question/20137507

#SPJ1

A hotel swimming pool is made for semi circle and square. Find The perimeter of the swimming pool. Round your answer to the nearest tenth.

Answers

Combining the 4 semi-circles of the pool, we can make 2 circles, with a diameter of 10 yd.

The perimeter of a circle is calculated as follows:

[tex]P=\pi\cdot D[/tex]

where D is the diameter.

Then, the perimeter of the swimming pool is:

[tex]\begin{gathered} P=2\cdot\pi\cdot10 \\ P=62.8yd^{} \end{gathered}[/tex]

log 2-log 5 can also be written as ?.

Answers

The formula for difference of two logarthimic terms are,

[tex]\log a-\log b=\log (\frac{a}{b})[/tex]

Determine the expression for log 2 -log 5.

[tex]\log 2-\log 5=\log (\frac{2}{5})[/tex]

Answer: log(2/5)

In the picture shown b and F are midpoints solve for x

Answers

ANSWER:

x = 10

EXPLANATION:

Given:

Recall that the Midpoint Theorem states that the line segment joining the midpoints of any two sides of a triangle is parallel to the third side and equal to half of the third side.

We can go ahead and solve for x as seen below;

[tex]\begin{gathered} BF=\frac{1}{2}*AE \\ \\ 23=\frac{1}{2}*(5x-4) \\ \\ 23*2=5x-4 \\ \\ 46=5x-4 \\ \\ 5x=46+4 \\ \\ 5x=50 \\ \\ x=\frac{50}{5} \\ \\ x=10 \end{gathered}[/tex]

Therefore, the value of x is 10

The cost of any soda from a soda machine is $0.50. The graph representing this relationship is shown below. Soda Machine Total Cost 3 2 Number & Sodas 6 6 What is the slope of the line that models this relationship?

Answers

Answer:

The slope of the line is;

[tex]m=\frac{1}{2}=0.5[/tex]

Explanation:

Given the attached graph.

Recall that the formula for calculating the slope m of a line is;

[tex]m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}[/tex]

From the graph, let us select two points on the line;

We have;

[tex]\begin{gathered} (2,1)\text{ } \\ \text{and} \\ (4,2) \end{gathered}[/tex]

The slope can then be calculated by substituting this points into the formula;

[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1}=\frac{2-1}{4-2} \\ m=\frac{1}{2}=0.5 \end{gathered}[/tex]

Therefore, the slope of the line is;

[tex]m=\frac{1}{2}=0.5[/tex]

Are the triangles similar?.. help me with this problem! Thank you :)

Answers

In similar triangles, corresponding sides are always in the same ratio.

Find the ratio of corresponding sides in the given triangles, to identify corresponding sides the greater side in one triangle is corresponding with the greater side of the other triangle.

[tex]\begin{gathered} \frac{QR}{TU}=\frac{28}{8}=\frac{7}{2} \\ \\ \frac{RP}{US}=\frac{21}{6}=\frac{7}{2} \\ \\ \frac{PQ}{ST}=\frac{14}{4}=\frac{7}{2} \end{gathered}[/tex]As the ratio of corresponding sides is the same, triangle PQR is similar to triangle STU

For similar triangles the corresponding angles are equal.

Corresponding angles for triangles PQR and STU:

P and S

Q and T

R and U

[tex]\begin{gathered} \angle P=\angle S=70º \\ \angle Q=\angle T \\ \angle R=\angle U=46º \end{gathered}[/tex]

The sum of the interior angles in any triangle is always 180º:

[tex]\begin{gathered} \angle P+\angle Q+\angle R=180º \\ \angle Q=180º-\angle P-\angle R \\ \angle Q=180º-70º-46º \\ \angle Q=64º \\ \\ \angle Q=\angle T=64º \end{gathered}[/tex]

Classify the polynomial as constant, linear, quadratic, cubic, or quartic, anddetermine the leading term, the leading coefficient, and the degree of thepolynomial.g(x) = - 2x^4 - 6

Answers

Given:

[tex]g(x)=-2x^4-6[/tex]

To classify: The polynomial name, degree, leading term, and leading coefficient

Explanation:

Since the degree of the polynomial is the highest or the greatest power of a variable in a polynomial equation.

Here, 4 is the greatest power of a variable x.

So, the degree of the polynomial is 4.

As we know,

The leading term is the term containing the highest power of the variable.

So, the leading term is,

[tex]-2x^4[/tex]

Since the coefficient of the term of the highest degree in a given polynomial is -2.

So, the leading coefficient is -2.

Since the degree of the polynomial is 4.

So, the given polynomial is a quartic polynomial.

Final answer: Option C. Quartic polynomial.

6. F(x) is the function that determines the absolute value of the cube of the input. Part 1. Evaluate: F(5) Part 2. Evaluate: F(-7) Part 3. Determine: F(5). F(-7) Or is the function defined by the following graph. The graph window is:

Answers

We have that F(x) is the function that determines the absolute value of the cube of the input, then we have that f(x) is:

[tex]f(x)=\lvert x^3\rvert[/tex]

Part 1. Evaluate F(5): x = 5

[tex]f(5)=\lvert5^3\rvert=\lvert125\rvert=125[/tex]

Part 2. Evaluate F(-7): x = -7

[tex]f(-7)=\lvert-7^3\rvert=\lvert-343\rvert=343[/tex]

Part 3. Evaluate F(5)xF(-7)

[tex]f(5)\cdot f(-7)=125\cdot343=42875[/tex]

The steps to derive the quadratic formula are shown below:Step 1 ax2 + bx + c = 0Step 2 ax2 + bx = - CStep 3Provide the next step to derive the quadratic formula.

Answers

Here, we are given the first two steps to derive the quadratic formula:

Step 1: ax² + bx + c = 0

Step 2: ax² + bx = -c

Let's determine the next step to derive the quadratic formula.

To provide the next step, let's divide all terms by a:

We have:

Step 3.

[tex]\begin{gathered} \frac{ax^2}{a}+\frac{bx}{a}=-\frac{c}{a} \\ \\ \frac{x^2}{a}+\frac{b}{a}x=-\frac{c}{a} \end{gathered}[/tex]

Therefore, the next step to derive the quadratic formula is:

[tex]\frac{x^2}{a}+\frac{b}{a}x=-\frac{c}{a}[/tex]

ANSWER:

[tex]\frac{x^2^{}}{a}+\frac{b}{a}x=-\frac{c}{a}[/tex]

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