Roberto bought a new graduated cylinder for his chemistry class. it holds 650 mililiters of liquid. if the cylinder has a radius of 5 cm, then how tall is the cylinder.
Answers
8.27 cm
Explanation
Step 1
the volume of a cylinder is given by:
[tex]\begin{gathered} \text{Volume}=\text{ area of the circle}\cdot\text{ height} \\ \text{Volume}=(\pi\cdot raidus^2)\cdot\text{height} \end{gathered}[/tex]then
Let
Heigth=unknown=h
volume=650 ml
radius= 5 cm
also
1 mililiter= 1 cubic centimeter
so,replacing
[tex]\begin{gathered} \text{Volume}=(\pi\cdot raidus^2)\cdot\text{height} \\ \text{650 }=(\pi\cdot(5cm)^2)\cdot\text{h} \\ 650=25\pi\cdot h \\ \text{divide both sides by 25 }\pi \\ \frac{650}{25\pi}=\frac{25\pi h}{25\pi} \\ h=\frac{650}{25\pi}=8.27\text{ cm} \end{gathered}[/tex]so, the cylinder is 8.27 cm tall.
I hope this helps you
Related Questions
5/3x+1/3x=13 1/3 + 8/3
Answers
Is this correct?
Now we will add the terms of the left side
[tex]\begin{gathered} \frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x \\ \frac{6}{3}x=13\frac{1}{3}+\frac{8}{3}x \end{gathered}[/tex]Now subtract 8/3 x from both sides
[tex]\frac{6}{3}x-\frac{8}{3}x=\frac{40}{3}+\frac{8}{3}x-\frac{8}{3}x[/tex][tex]-\frac{2}{3}x=\frac{40}{3}[/tex]Cancel the denominator 3 from both sides
-2x = 40
Divide two sides by -2
[tex]\frac{-2x}{-2}=\frac{40}{-2}[/tex]x = -20
Write a compound inequality for the graph shown below.Use x for your variable.-10 -9 -8 -7 -6 -5 4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10xor x < 2and□<口>OOSONOS?AorX
Answers
Given:
Given that graph of the inequality.
Required:
To write a compound inequality for the given graph.
Explanation:
From the given graph,
[tex]x<-1[/tex]and x
[tex]x\ge2[/tex]Final Answer:
[tex]x<-1\text{ or }x\ge2[/tex]In the figure, BC||DE Angles_____1.CAF and EFA2.GAC and DFE3.CAF and EFH4.GAB and EFAare congruent______1.By the linear pair Theorem.2. because they are corresponding angles of parallel lines cut by transversal.3. by the vertical angles theorem.4. by the transitive property of congruence.GAC - CAFE because they are corresponding angles of parallel lines cut by a transversal.LAFE - HFD by the Vertical Angles Theorem.GAC - HFD by the_____1. Addition 2. Subtraction3. Substitution4. TransitiveProperty of Congruence.
Answers
CAF and EFH are congruent because they are corresponding angles of parallel lines cut by transversal.
Explanation:
BC is parallel to DE
Checking the options for angles that are congruent(the same):
1) CAF and EFA
Both angles are not corrsponding angles. They are not equal
2) GAC and DFE are not equal. DFE is a straight line.
3) CAF and EFH are corresponding angles. Hence the angles are congruent.
4) GAB and EFA are not equal. Hence, they are not congruent.
Hence, CAF and EFH are congruent because they are corresponding angles of parallel lines cut by transversal.
1. choose one of the theorems about chords of a circle and state it using your own words2. create a problem that uses the theorem you explained3. explain how to solve the problem you just did
Answers
ANSWER:
We have the following:
1. A given chord in a circle is perpendicular to a radius through its center and is a distance less than the radius of the circle.
2. A circle with center C has a radius of 5 units. If a 6-unit chord AB is drawn at a distance D from the center of the circle, determine the value of D.
3.
Given:
Radius = 5 units
Length of chord = 6 units
A radius that meets the chord at center O divides it into two equal parts. Therefore:
AO = OB = 3 units
We can apply the Pythagorean theorem on the resulting triangle COB to determine the distance D, like this:
[tex]\begin{gathered} h^2=a^2+b^2 \\ \\ h=CB=R=5 \\ \\ a=OC=D \\ \\ b=OB=3 \\ \\ \text{ We replacing:} \\ \\ 5^2=D^2+3^2 \\ \\ 25=D^2+9 \\ \\ D^2=25-9 \\ \\ D=\sqrt{16} \\ \\ D=4 \end{gathered}[/tex]Therefore, the chord is at a distance of 4 units to the center of the circle.
Type the correct answer in each box. Use numerals instead of words.Sabrina is researching the growth of a population of horses on a ranch. She models the population of horses using the function below, where n is the number of years after she begins the research and b is an unknown base.
Answers
The initial number of horses is given by n=0.
Replacing on the equation:
[tex]\begin{gathered} w(0)=15\ast b^0 \\ w(0)=15\ast1 \\ w(0)=15 \end{gathered}[/tex]The initial number of horses is 15.
Now, if b= 1.35
We need to convert it to percentage:
b = 1.35 = 135%
Therefore, the growth is:
135%-100% = 35%
Then,
If b = 1.35, the annual percentage growth rate of the number of horses would be 35%.
The angle of elevation from ground level to the top of a water tower that is 280 ft away measures 27 degrees. What is the height of the tower?
Answers
We can draw
x represents the height of the water tower
we have a right triangle
we can use a trigonometric function
[tex]\tan (27)=\frac{x}{280}[/tex]we need to clear x
[tex]x=\tan (27)\cdot280=142.66\text{ ft}[/tex]A swimmer dives into the pool from a 6 foot platform modeled by the following y=x- 12x + 6. What was the maximum depth that the swimmer reached?
Answers
The expression that models the swimmer dive is given by:
[tex]y=x^2-12x+6[/tex]Which is a parabolla, the maximum depth of the swimmer will be the value of "y" that corresponds to the vertex of this shape. We can calculate the vertex of the parabola by using the following formula:
[tex]x=-\frac{b}{2a}[/tex]Whera a is the number multiplying x² and b is the number multiplying x. Applying the data from the problem we have:
[tex]x=-\frac{(-12)}{2}=6[/tex]We can now find the depth by applying this value of x to the expression, we have:
[tex]\begin{gathered} y=(6)^2-12\cdot6+6 \\ y=36-72+6 \\ y=30 \end{gathered}[/tex]The maximum depth was 30 feet.
Simply the expression 11s(4)
Answers
44s
Explanation:[tex]\begin{gathered} \text{Given:} \\ 11s(4) \end{gathered}[/tex]To simplify the expression, we will expand the parenthesis:
[tex]\begin{gathered} 11s(4)\text{ = 11s }\times\text{ 4} \\ 11\text{ and 4 are numbers so we will multiply them together} \\ 11\text{ }\times\text{ 4 = 44} \end{gathered}[/tex][tex]\begin{gathered} 11s(4)\text{ = 11 }\times\text{ s }\times\text{ 4} \\ =\text{ 44 }\times\text{ s} \\ =\text{ 44s} \end{gathered}[/tex]consider the function w(x) = 2x^3 + 15x^2 -36x - 6 on interval -6 ≤ x ≤ 2
On the given interval this function has absolute:
Minimum at the point -
Maximum at the point -
Answers
The minimum absolute value of the function is at x = 1 and the maximum absolute value is at x = -6.
What is absolute value?Absolute value describes the distance from zero that a number is on the number line, without considering direction.
Given a function, f(x) = 2x³+15x²-36-6
f'(x) = 6x²+30-36
Let f'(x) = 0
6x²+30-36 = 0
On solving, we get,
x = 1 or -6
Putting x = 1,-6, 2 for maximum and minimum values
f(1) = -25
f(-6) = 318
f(2) = -2
Hence, the minimum absolute value of the function is at x = 1 and the maximum absolute value is at x = -6.
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complete the number sentence to solve enter this answer in simplest form 6 students share 8 granola bars equally how many granola bars does each student get?
Answers
4/3 of each granola bar ( 1 1/3)
1) Given that 6 students share 8 granola bars we can write the following fraction with 8 on the numerator and 6 on the denominator since it is a division:
[tex]\frac{8}{6}=\frac{4}{3}\text{ or 1.333}[/tex]2) Each student will get 4/3 of each granola bar or 1 and 1/3
2.) for the line represented by the given equation, find both the X intercept and the y-intercept. (Don’t simply look on the graphing calculator ). Make sure you indicate which answer is the x-intercept and which is the y-intercept . Then graph the line
Answers
Answer:
To find the y-intercept, we substitute x=0 in the given equation:
[tex]\begin{gathered} y=\frac{1}{2}\cdot0+3, \\ y=3. \end{gathered}[/tex]Therefore, the y-intercept has coordinates (0,3).
To find the x-intercept, we set y=0, and solve for x:
[tex]\begin{gathered} 0=\frac{1}{2}x+3, \\ 0-3=\frac{1}{2}x+3-3, \\ -3=\frac{1}{2}x, \\ 2\cdot(-3)=2\cdot(\frac{1}{2}x), \\ x=-6. \end{gathered}[/tex]Therefore, the x-intercept has coordinates (-6,0).
Finally, the graph of the given equation is:
Solve the following system of equations graphically on the set of axes below.y = -1/3x - 4 y = 2/3x + 2
Answers
Given:
[tex]\begin{gathered} y=-\frac{1}{3}x-4 \\ y=\frac{2}{3}x+2 \end{gathered}[/tex]Therefore, the system of solution is (-6,-2)
Ned Robinson buys a microwave for $149.99, a microwave cart for $119.95, andmicrowave cookware for $19.95. The sales tax rate is 5.5 percent. What is thetotal purchase price?
Answers
Ned Robinson buys a microwave for $149.99.
A microwave cart for $119.95.
A microwave cookware for $19.95.
tax rate is 5.5 %
total amount =
[tex]\begin{gathered} 149.99+119.95+19.95=28.89 \\ \end{gathered}[/tex]thus 5.5% of 28.89 is,
[tex]\begin{gathered} 28.89\times\frac{5.5}{100} \\ =15.94 \end{gathered}[/tex]thus total bill is,
[tex]28.89+15.94=44.83[/tex]Find the difference: (−1−5i)−(5−7i)
Answers
To determine the difference between complex number:
[tex](-1-5i)-(5-7i_{})[/tex]Step 1: Remove the bracket and find the difference
[tex]\begin{gathered} (-1-5i)-(5-7i_{}) \\ -1-5i-(5-7i_{}) \\ -1-5i-5+7i_{} \end{gathered}[/tex]Step2: Collect like terms
[tex]\begin{gathered} (-1-5i)-(5+7i_{}) \\ (-1-5i)-(5+7i_{} \\ -1-5-5i+7i \\ -6+2i \\ 2i-6 \end{gathered}[/tex]Hence the final answer is 2i - 6
Select the correct answer. Select the place of the digit 2 in this number. 296,743 ten thousands hundred thousands one thousands hundreds tens ones
Answers
the place of the digit 2 in the number 296,743 is: hundred thousands
A geometric sequence has allpositive terms. The sum of thefirst two terms is 15 and the sumto infinity is 27.a Find the value of the commonratio.b Hence, find the first term.
Answers
a) Common ratio = 2/7
b) First term = 135/7
Explanations:The formula for finding the sum of a geometric progression is expressed as:
[tex]S_n=\frac{a(r^n-1)}{r-1}[/tex]Since the sum of the first two terms is 15, then
S2 = 15
n = 2
Substitute into the formula:
[tex]\begin{gathered} S_2=\frac{a\mleft(r^2-1\mright)}{r^{}-1} \\ 15=\frac{a(r+1)\cancel{r-1}}{\cancel{r-1}} \\ 15=a(r+1) \end{gathered}[/tex]Also, the sum to infinity of a geometric sequence is expressed as:
[tex]\begin{gathered} S_{\infty}=\frac{a}{1-r} \\ _{} \end{gathered}[/tex]Substitute the given values into the formula:
[tex]27=\frac{a}{1-r}[/tex]Solve both expressions simultaneously
[tex]\begin{gathered} 15=a(r+1) \\ 27=\frac{a}{1-r} \end{gathered}[/tex]
Divide both expressions to have:
[tex]\frac{15}{27}=\frac{1-r}{r+1}[/tex]Cross multiply and solve for the common ratio "r"
[tex]\begin{gathered} 15(r+1)=27(1-r) \\ 15r+15=27-27r \\ 15r+27r=27-15 \\ 42r=12 \\ r=\frac{12}{42} \\ r=\frac{2}{7} \end{gathered}[/tex]Hence the value of the common ratio is 2/7
b) Get the first term of the sequence;
Using the formula:
[tex]\begin{gathered} 27=\frac{a}{1-r} \\ 27=\frac{a}{1-\frac{2}{7}} \\ 27=\frac{a}{(\frac{5}{7})} \\ a=27\times\frac{5}{7} \\ a=\frac{135}{7} \\ \end{gathered}[/tex]Hence the first term of the sequence is 135/7
I need help converting standard form to vertex form with quadratic equations. The equation is: y = -x^2 + 12x -4I think I am supposed to complete the square, but I am unsure how to do this. I am also unsure about what to do with the negative sign. I would love clear, step by step instructions on the process so I can know how to do it in the future.
Answers
Okay, here we have this:
Considering the provided equation in standard form, we are going to convert it to vertex form step by step, so we obtain the following:
y = -x²+ 12x -4
Considering that the model of an equation in standard form is y=ax²+bx+c. First we are going to axtract "a" from the first two terms:
y=-1(x²-12x)-4
Now, we are going to complete the square for the expressions with x, so we have:
y=-1(x²-12x+36-36)-4
y=-1((x - 6)²-36) -4
And, finally we are going to simplify:
y=-1(x - 6)²+36-4
y=-(x - 6)²+32
We obtain that the equation in vertex form is y=-(x - 6)²+32.
Find the value of X and each arc measurex =mGK=mHJ = mHGJ =mGKJ=
Answers
where:
[tex]\begin{gathered} m\angle GK=9x-22 \\ m\angle GH=61 \\ m\angle HJ=5x-7 \\ m\angle KJ=34 \\ so\colon \\ 9x-22+61+5x-7+34=360 \\ \end{gathered}[/tex]add like terms:
[tex]14x+66=360[/tex]Solve for x:
[tex]\begin{gathered} 14x=360-66 \\ 14x=294 \\ x=\frac{294}{14} \\ x=21 \end{gathered}[/tex]Hence:
[tex]\begin{gathered} m\angle GK=9x-22=9(21)-22=167 \\ m\angle HJ=5x-7=5(21)-7=98 \end{gathered}[/tex]6) Raul received a score of 74 on a history test for which the class mean was 70 with a standard deviation of 3. He received a score of 70 on a biology test for which the class mean was 70 with standard deviation 7. On which test did he do better relative to the rest of the class?a)biology testb)history test c)the same
Answers
Solution:
The z score value is expressed as
[tex]\begin{gathered} z=\frac{x-\mu}{\sigma} \\ where \\ x\text{ is the sample score} \\ \mu\text{ is the mean score} \\ \sigma\text{ is the standard deviation of the score} \end{gathered}[/tex]Given that
[tex]\begin{gathered} History: \\ x=74 \\ \mu=70 \\ \sigma=3 \\ Biology: \\ x=70 \\ \mu=70 \\ \sigma=7 \end{gathered}[/tex]To determine which test Raul did better,
step 1: Determine the z score value for the history test.
Thus,
[tex]\begin{gathered} z_{history}=\frac{74-70}{3}=1.333333333 \\ \end{gathered}[/tex]step 2: Determine the z score value for the biology test.
[tex]z_{biology}=\frac{70-70}{7}=0[/tex]step 3: Determine the probability that he did better in the history test.
Thus, from the normal distribution table,
[tex]Pr(history)=0.9088[/tex]step 4: Determine the probability that he did better in the biology test.
From the normal distribution table,
[tex]Pr(biology)=0.5[/tex]Since the probability that he did better in history is higher than the probability he did better in the biology test, this implies that he did better in the history test, relative to the rest of the class.
The correct option is B.
What is the exact solution of cos 2x? Thank you!
Answers
Answer:
119/169
Explanation:
We use the following trig identity
[tex]\cos2x=1-2\sin^2(x)[/tex]Now in our case, we know that
[tex]\sin x=-\frac{5}{13}[/tex]therefore, our formula gives
[tex]\cos2x=1-2*(\frac{5}{13})^2[/tex]which simplifies to give
[tex]\boxed{\cos2x=\frac{119}{169}.}[/tex]The following data values represent a population. What is the variance of thepopulation? μ = 11. Use the information in the table to help you.X8101214(x-μ)²9119OA. 10B. 5O C. 11OD. 20
Answers
The variance is calculated given the formula:
[tex]\begin{gathered} Variance=\frac{\sum(x-\mu)^2}{N} \\ \\ \sum(x-\mu)^2=9+1+1+9 \\ \\ \sum(x-\mu)^2=20 \end{gathered}[/tex]The sample
The profit P(x) obtained by manufacturing and selling x units of a certain product is given by P(x) = 60x - x2. Determine the number of units that must be produced and sold to maximize the profit. What is the maximum profit?
Answers
Answer:
The number of units that must be produced and sold to maximize the profit is 30 units
[tex]30\text{ units}[/tex]The maximum profit is;
[tex]\text{ \$900}[/tex]Explanation:
Given that the profit P(x) obtained by manufacturing and selling x units of a certain product is given by;
[tex]P(x)=60x-x^2[/tex]The maximum point is at;
[tex]P^{\prime}(x)=0[/tex]Differentiating P(x);
[tex]\begin{gathered} P^{\prime}(x)=60-2x=0 \\ 60-2x=0 \\ 2x=60 \\ x=\frac{60}{2} \\ x=30 \end{gathered}[/tex]The number of units that must be produced and sold to maximize the profit is 30 units
Substituting x into p(x);
[tex]\begin{gathered} P(30)=60(30)-30^2 \\ P(30)=900 \end{gathered}[/tex]The maximum profit is;
[tex]\text{ \$900}[/tex]Use the distributive property to write an equivalent expression. If you get stuck, consider drawing a diagram p( 4p + 9)
Answers
Given data:
The given expression is p( 4p + 9).
The given expression can be written as,
[tex]p(4p+9)=4p^2+9p[/tex]Thus, the simplification of the given expression is 4p^2 +9p.
Find the quotient and remainder using long division.x4 − 5x3 + x − 4 / x2 − 7x + 1
Answers
Given:
[tex]\frac{x^4-5x^3+x-4}{x^2-7x+1}[/tex]Required:
To find the quotient and remainder using long division.
Explanation:
Now
[tex]\begin{gathered} x^^2+2x+13 \\ ----------- \\ x^2-7x+1)x^4-5x^3+x-4 \\ \text{ }-x^4+7x^3-x^2 \\ --------------- \\ \text{ }+2x^3-x^2+x \\ \text{ }-2x^3+14x^2-2x \\ ---------------- \\ \text{ }+13x^2-x-4 \\ \text{ }-13x^2+91x-13 \\ ----------------- \\ \text{ }90x-17 \end{gathered}[/tex]Final Answer:
The quotient is
[tex]x^2+2x+13[/tex]The remainder is
[tex]90x-17[/tex]A marketing research company desires to know the mean consumption of meat per week Among people over age 31 they believe that the meat consumption has mean of 3.1 pounds and want to construct a 85% confidence interval with the maximum error of 0.06 pounds assuming a standard deviation of 0.8 pounds what is the minimum number of people over age 31 they must include in their sample? Round your answer up to the next integer
Answers
ANSWER:
369
STEP-BY-STEP EXPLANATION:
Given:
Mean (μ) = 3.1
Standard deviation (σ) = 0.8
Margin of error (E) = 0.06
At 85% confidence level the z is:
[tex]\begin{gathered} \alpha=1-\text{ confidence level} \\ \\ \alpha=1-85\%=1-0.85=0.15 \\ \\ \alpha\text{/2}=\frac{0.15}{2}=0.075 \\ \\ \text{ The corresponding value of z according to the table is:} \\ \\ Z_{\alpha\text{/2}}=1.44 \end{gathered}[/tex]We can determine the sample size using the following formula:
[tex]\begin{gathered} n=\:\left(\frac{Z_{\alpha\text{/2}}\cdot\sigma}{E}\right)^2 \\ \\ \text{ We replacing:} \\ \\ n=\left(\frac{1.44\cdot0.8}{0.06}\right)^2 \\ \\ n=368.64\cong369 \end{gathered}[/tex]The size of the sample is 369
the width of a rectangular rug is 3 1/4 inches longer than twice its length. if the perimeter of the rug is 54 1/2 inches, which equation represents this situation?
Answers
The equation represents the relation of perimeter with length and width is 109/4 = 24 l + 13.
What is meant by the perimeter of the rectangle?For the given question;
Let the dimensions of the rectangle be;
Length lWidth wPerimeter PFor the condition, width of a rectangular rug is 3 1/4 inches longer than twice its length.
w = 2×l + 3 1/4
Solve the mixed fraction;
w = 2×l + 13/4
Now, the perimeter is;
P = 2(l + w)
P = l x w
Put the value of w.
P = 2 ( l + 2×l + 13/4) ....eq1
P = 54 1/2 inches = 109/4
Put in eq 1
109/4 = 3 l + 13/4
109/4 = 24 l + 13
Multiplying equation by 4.
109/4 = 24 l + 13
Thus, the equation represents the relation of perimeter with length and width is 109/4 = 24 l + 13.
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Divide by multiplying by the reciprocal of the divisor 1/4 / 2/7
Answers
We want to divide 1/4 / 2/7
If we take the reciprocal of the 2/7, it means that the division sign will change to multiplication. Reciprocal of 2/7 = 7/2
Thus, the expression will be
1/4 x 7/2
= 7/8
Lin's mom bikes at a constant speed of 12 miles per hour. Lin walks at a constantspeed 1/3 of the speed her mom bikes. Sketch a graph of both of these relationships
Answers
ANSWER :
The graph is :
EXPLANATION :
From the problem we have the rates :
Lin's mom : 12 miles per hour
Lin : 1/3 of Lin's mom, that will be 12(1/3) = 4 miles per hour
Plot the points as (hour, miles).
(1, 12) and (1, 4)
Connect the points with the origin (0, 0)
That will be :
The black line represents Lin's mom and the orange line represents Lin.
PART E.)In terms of the trigonometry ratios for triangle BCD, what is the length of line BD. Insert text on the triangle to show the length of line BD. When you’re done use the formula for the area of a triangle area equals 1/2 times base times height write an expression for the area of triangle ABC this when you do this base your answer on what u did in part E
Answers
Sine formula
[tex]\sin (angle)=\frac{\text{opposite side}}{hypotenuse}[/tex]Considering angle C from triangle BCD, the opposite side is side BD and the hypotenuse is side BC which length is a units. Then:
[tex]\begin{gathered} \sin (\angle C)=\frac{BD}{a} \\ \text{ Isolating BD} \\ \sin (\angle C)\cdot a=BD \end{gathered}[/tex]The area of a triangle is calculated as follows:
[tex]A=\frac{1}{2}\cdot\text{base}\cdot\text{height}[/tex]In triangle ABC the base is b units long and its height is segment BD, then the area of triangle ABC is:
[tex]\begin{gathered} A=\frac{1}{2}\cdot b\cdot BD \\ \text{ Substituting with the previous result:} \\ A=\frac{1}{2}\cdot b\cdot a\cdot\sin (\angle C) \end{gathered}[/tex]
Solve the inequality and graph the solution set on a real number line. Express the solution set in interval notation|x2 + 3x - 29 > 25The solution set is(Type your answer in interval notation. Use integers or fractions for any numbers in the expression.)
Answers
Given:
[tex]|x^2+3x-29|>25[/tex]