Question 24 (1 point)—A beam of white light hits a prism and is dispersed into the its spectral componentsred, orange, yellow, green, blue, indigo, and violet. If a second prism is placed so thatonly the red band of light can pass through, what will happen?No light will pass through the second prism because red light does not haveenough energyThe prism will disperse the red light into many shades of redThe prism will polarize the red lightThe prism will refract the red light but it will still be the same color of red
Answers
prism can disperse a compound light
red is a single coloured light
when it will pass through the prism it will get refracted again but the output will be the red one
so the answer is
The prism will refract the red light but it will still be the same color of red
Related Questions
Question 2
An object has a momentum of 500 kg mls. If its mass is 20 kg, its speed must be
O 25 m/sO 20 m/s50 m/sO 500
Answers
Given:
The momentum of the object is p = 500 kg m/s
The mass of the body is m = 20 kg
To find the speed of the object.
Explanation:
Speed can be calculated by the formula
[tex]\begin{gathered} p=mv \\ v=\frac{p}{m} \end{gathered}[/tex]On substituting the values, the speed of the object will be
[tex]\begin{gathered} v=\frac{500}{20} \\ =25\text{ m/s} \end{gathered}[/tex]Thus, the speed of the object is 25 m/s
a ray of light hits a flat mirror with an incident angle of 39.20 degrees. What angle does it reflect at? (do not put in units)
Answers
Given
A ray of light hits a flat mirror with an incident angle of 39.20 degrees.
To find
What is the angle of reflection?
Explanation
According to the law of reflection,
The angle of incidence is equal to the angle of reflection.
Here the angle of incidence is 39.20 deg
So the angle of reflection is 39.20 deg
Conclusion
The angle of reflection is 39.20 deg
The Taipei Tower is a 508 meter, 101 story skyscraper. If you were to toss a orange of 0.13 kg off the top, how much kinetic energy would it have when it hits the sidewalk? Ignore air resistance .
Answers
Answer:
647.19 J
Explanation:
By the conservation of energy, the potential energy when you toss the orange is converted to kinetic energy when it hits the sidewalk, so
Ef = Ei
KE = PE
KE = mgh
Where m is the mass, g is 9.8 m/s², and h is the height of the Tower. Replacing m by 0.13 kg and h by 508 meters, we get
KE = (0.13kg)(9.8 m/s²)(508 m)
KE = 647.19 J
So, the orange would have 647.19 J of kinetic energy when it hits the sidewalk.
What is the resistance of a lamp which draws 250 milliamperes when connected toa 12.6 volt battery
Answers
V = I*R
R = V / I
250 ma = 0.25 A
R = 12.6 / 0.25
R =50.4 ohm
URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!!
Answers
Answer: Your answer will be D
Explanation:
How far did a runner travel if they ran 3 mph for 30 minutes?
Answers
Given:
Speed = 3 mph
Time = 30 minutes
Let's determine how far(distance) the runner travelled.
To find the distance, apply the formula:
[tex]Dis\tan ce=speed\ast time[/tex]Since the time is in minutes, let's convert to hours by dividing the time by 60 minutes.
Thus, we have:
[tex]\begin{gathered} D=3\ast\frac{30}{60} \\ \\ D=3\ast\frac{1}{2} \\ \\ D=1.5\text{ m} \end{gathered}[/tex]Therefore, the runner travelled 1.5 miles
The radioactive isotope 239Pu has a half-life of approximately 24100 years. After 2000 years, there are 5g of 239Pu.(1) What was the initial quantity? (Round your answer to three decimal places.) g Tries 0/99(2) How much of it remains after 20000years? (Round your answer to three decimal places.) g Tries 0/99
Answers
Using the following formula:
[tex]\begin{gathered} N(t)=N_o(0.5)^{\frac{t}{t_{1/2}}} \\ where: \\ N(t)=Remaining_{\text{ }}quantity_{\text{ }}after_{\text{ }}time_{\text{ }}t \\ N_o=Initial_{\text{ }}quantity \\ t=time_{\text{ }}in_{\text{ }}years \\ t_{1/2}=half-life=24100 \end{gathered}[/tex](1)
[tex]\begin{gathered} t=2000 \\ t_{1/2}=24100 \\ N(2000)=5g \\ so: \\ 5=N_o(0.5)^{\frac{2000}{24100}} \\ N_o=\frac{5}{(0.5)^{\frac{2000}{24100}}} \\ N_o\approx5.296 \end{gathered}[/tex](2)
Using the initial quantity calculated previously:
[tex]\begin{gathered} t=20000 \\ N(20000)=5.296(0.5)^{\frac{20000}{24100}} \\ N(20000)=2.979 \end{gathered}[/tex]Answers:
For (1): 5.296
For (2): 2.979
A dog barks with an intensity level of 80 decibels. Two barking dogs produce what intensity level?
Answers
We are given that a dog barks with an inetensity level of 80 dB and asked to find out the intensity level produced by two barking dogs.
The combined intensity level of both dogs is the sum of each dog's intensity level.
[tex]\begin{gathered} I_{net}=I_1+I_2 \\ I_{net}=2I_{} \\ I_{net}=2\cdot I_0\cdot10^{\frac{\beta}{10}}_{} \end{gathered}[/tex]Where β is 80 dB and I0 is the reference intensity (1x10^-12 W/m^2)
[tex]\begin{gathered} I_{net}=2\cdot10^{-12}\cdot10^{\frac{80}{10}}_{} \\ I_{net}=2\cdot10^{-12}\cdot10^8_{} \\ I_{net}=2\cdot10^{-12+8} \\ I_{net}=2\cdot10^{-4} \end{gathered}[/tex]The net β is given by
[tex]\begin{gathered} \beta_{\text{net}}=10\log (\frac{I_{net}}{I_0}) \\ \beta_{\text{net}}=10\log (\frac{2\cdot10^{-4}}{10^{-12}}) \\ \beta_{\text{net}}=10\log (2\cdot10^{-4+12}) \\ \beta_{\text{net}}=10\log (20^8) \\ \beta_{\text{net}}=10(8.301) \\ \beta_{\text{net}}=83\; dB \end{gathered}[/tex]Therefore, two barking dogs produce 83 dB intensity level.
why short circuit are dangrous
Answers
Short circuits occur when a high-volume electrical current is passed through a low-resistance path that isn't meant to carry electricity. Short circuits occur when a live wire makes contact with a conductive object that it should not have.
The most dangerous aspect of a short circuit is that it will cause a sudden and dramatic change in electrical resistance. Electrical systems can cause a large amount of resistance and will be constantly sending electricity to different areas when appliances are plugged in or outlets are being used. This has the possibility to cause bodily harm and appliance damage to those who are using electrical appliances at the time a short circuit happens, and can also cause structural damage to your home through fires and burns
Wires with faulty or unstable connections will create a situation in which the electrical current can take a detour down an unintended path if it is the one of least resistance. This can be unpredictable, and the route that the current travels could be through flammable materials or a human being.
Short circuits are liable to cause fires, electrical burns, and electrocution. Stray electrical currents can also cause considerable damage to appliances and a home’s electrical system.
To know more about short circuits
https://brainly.com/question/14184862?referrer=searchResults
13 Dion is writing a survival guide for hikers who visit the nearby state park. Since the forest in the park is so dense, it is not unusual for hikers to get lost for days at a time before Dion and the other rangers can locate them. Dion creates a list of plant life that a lost hiker could eat to keep themselves going in an emergency. Which sentence will Dion MOST likely include about wild mushrooms? A. The forest floor in our park is very dense and wet so you will not find mushrooms to eat. B. If you look closely at the base of trees or fallen logs, you may find mushrooms to eat. C. It is best not to eat mushrooms that you find because some varieties are poisonous. D. Mushrooms must be heated to kill any harmful bacteria before they can be consumed.
Answers
Answer: C
Explanation: Some varieties of mushrooms are poisonous or may make you ill.
Calculate the Mach number for sound given the temperature and the speeda. 332 m/s at 30°Cb. 340 m/s at -10°Cc. 6000 km/h at 13°Cd. 6000 km/h at -13°0
Answers
The Mach number indicates how many times a speed is greater than the speed of sound.
So, to find the Mach number, we just need to divide the speed by the speed of sound.
a) at 30°C, the speed of sound is 349 m/s, so we have:
[tex]\frac{332}{349}=0.95[/tex]b) at -10°C, the speed of sound is 325 m/s, so we have:
[tex]\frac{340}{325}=1.05[/tex]c) at 13°C, the speed of sound is 339 m/s. First, let's convert the speed from km/h to m/s:
[tex]\begin{gathered} 6000\text{ km/h}=\frac{6000}{3.6}\text{ m/s}=1666.67\text{ m/s} \\ \frac{1666.67}{339}=4.92 \end{gathered}[/tex]d) at -13°C, the speed of sound is 323 m/s, so we have:
[tex]\frac{1666.67}{323}=5.16[/tex]Scenario 3: a clock attached to the wall.
1. State the object stationary.
2. State the outside, external, unbalanced force acting on the object.
Answers
answer: this object is stationary because it is in rest position until or unless the external force act on it we can say this by netwons 1st law
and the stationaty object has relatively zero velocity.
netwons 1st law: Newton's first law states that unless compelled to change its state by the action of an external force, every object will remain at rest or in uniform motion in a straight line.
to learn more about netwons 1st law link
https://brainly.in/question/4132747#:~:text=Expert%2Dverified%20answer,question&text=According%20to%20Newton%27s%20first%20law,moving%20with%20the%20same%20velocity.
#SPJ1
2. here the object has contact with the wall hence there is a normal force between clock and wall
the clock is at rest this means that the forcee is balanced and normal force is balanced by gravitational force .the normal force is always perpendicular to the surface of the object.
there is no external force is acting on the clock.
to learn more about netwons 1st law link
https://brainly.in/question/4132747#:~:text=Expert%2Dverified%20answer,question&text=According%20to%20Newton%27s%20first%20law,moving%20with%20the%20same%20velocity.
#SPJ1
The largest single publication in the world is the 1112-volume set of British Parliamentary Papers for 1968 through 1972. The complete set has a mass of 3,548 kg. Suppose the entire publication is placed on a cart that can move without friction. The cart is at rest, and a librarian is sitting on top of it, just having loaded the last volume. The librarian jumps off the cart with a horizontal velocity relative to the floor of 2.65 m/s to the right. The cart begins to roll to the left at a speed of 0.03 m/s. Assuming the cart’s mass is negligible, what is the librarian’s mass? Round to the hundredths.
Answers
ANSWER:
40.17 kg
STEP-BY-STEP EXPLANATION:
Given:
m1 = 3548 kg
V1 = -0.03 m/s
V2 = 2.65 m/s
We apply law of conservation of linear momentum:
[tex]\begin{gathered} P_i=P_f \\ P_i=0 \\ P_f=m_1\cdot V_1+m_2\cdot V_2 \end{gathered}[/tex]We replace and calculate the mass as follows:
[tex]\begin{gathered} m_1\cdot V_1+m_2\cdot V_2=0 \\ 3548\cdot-0.03+2.65\cdot m_2=0 \\ -106.44+2.65\cdot m_2=0 \\ m_2=\frac{106.44}{2.65} \\ m_2=40.17\text{ kg} \end{gathered}[/tex]Therefore the mass is equal to 40.17 kg
URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!!
Answers
Answer:
Thermal energy flows from the flask on the left to the flask on the right
Explanation:
As the flask on the left is hot water the temperature of it will be higher meaning that the metal bar will conduct the heat at a faster rate than the flask on the left. Due to this, the metal bar will gradually begin to increase in temperature slowly throughout the whole bar. This means that the heat will travel through the bar reaching tho whole flask.
Hope this helps, have a great day!
Which of the following is the type of force that pulls objects towards the center of motion?A. Inertia B. MomentumC. AccelerationD. Centripetal
Answers
When an object is in a circular motion, the acceleration responsible for changing the direction of the movement is known as the centripetal acceleration:
This acceleration points towards the center of the circular motion.
Using the second law of newton, we can find the centripetal force Fc:
[tex]F_c=m*a_c[/tex]Therefore the force that pulls objects towards the center of motion is the centripetal force.
Correct option: D.
The example of a book falling off of a table shows a(n) _____.1) contact force2) scalar quantity3) absence of acceleration4) field force
Answers
anotherGravity is the force of attraction between two objects. A gravitational force field is modeled as space around a massive body in which other bodies experiences force.
In Newtonian gravity, a particle of mass M creates a gravitational force field around itself given as,
[tex]g=\frac{GM}{r^2}[/tex]Here, G is the universal gravitational constant, and r is the separation between the bodies.
Hence, the example of a book falling off of a table shows a(n) field force. Therefore, option (4) is the correct choice.
What will be the effect of multiplying negative scalar number with a vector.. Explain with the help of drawing.
Answers
When we multiply a vector by a scalar number, each dimension of the vector will be multiplied by the number.
For example, multiplying the vector <3, 4> by 2 would create the vector <6, 8>.
But if this scalar is negative, the dimensions of the vector will change the signal:
vector <3, 4> multiplied by -2 creates the vector <-6, -8>.
This causes the original vector to change its direction to the opposite direction, that is, it flips 180°:
When the length of a pendulum is doubled, its frequency will be cut in half. Is this true or false?
Answers
The period T of a pendulum with length L is given by the formula:
[tex]T=2\pi\cdot\sqrt[]{\frac{L}{g}}[/tex]Where g is the acceleration of gravity:
[tex]g=9.81\frac{m}{s^2}[/tex]If the length of the pendulum is doubled, the period will be:
[tex]\begin{gathered} T^{\prime}=2\pi\cdot\sqrt[]{\frac{2L}{g}} \\ =\sqrt[]{2}\times2\pi\cdot\sqrt[]{\frac{L}{g}} \\ =\sqrt[]{2}\times T \end{gathered}[/tex]On the other hand, the frequency is the reciprocal of the period. Then:
[tex]\begin{gathered} f=\frac{1}{T} \\ f^{\prime}=\frac{1}{T^{\prime}}=\frac{1}{\sqrt[]{2}\times T}=\frac{1}{\sqrt[]{2}}\times\frac{1}{T}=\frac{1}{\sqrt[]{2}}\times f \end{gathered}[/tex]Then, if the length of the pendulum is doubled, the frequency is cut by a factor of 1/√2:
[tex]f^{\prime}=\frac{1}{\sqrt[]{2}}\times f[/tex]This is not the same as if the frequency was cut by a factor of 1/2.
Therefore, the statement is:
[tex]\text{False}[/tex]A rocket weighing 220,000 N is taking off from Earth with a total thrust of 500,000 N at an angle of 20 degrees, as shown in the image below. What is the approximate vertical component of the net force that is moving the rocket away from Earth?A. 400,000 NB. 350,000 NC. 250,000 ND. 300,000 N
Answers
ANSWER
[tex]C.250,000N[/tex]EXPLANATION
Parameters given:
Weight of rocket, W = 220,000 N
Thrust, F = 500,000N
Angle of thrust, θ = 20°
The vertical forces acting on the rocket are the thrust (acting at an angle) and its weight. This means that the sum of vertical forces is:
[tex]F_y=F\cos \theta-W[/tex]Note: W is negative since it acts opposite the motion of the rocket.
Therefore, we have that the net vertical force (vertical component of forces) is:
[tex]\begin{gathered} F_y=500000\cos 20-220000 \\ F_y=469,846.31-220000 \\ F_y=249,846.31N \\ F_y\approx250,000N \end{gathered}[/tex]The answer is option C.
If a ball is thrown with an initial horizontal velocity of 2.3m/s, from a tall building, how far away from thebuilding does the ball land if it takes 4s to land?Referring to the ball above, how tall is the building? (2 sig figs)
Answers
Given,
The initial velocity of the ball, u=2.3 m/s
The time interval in which the ball hits the ground, t=4 s
As the ball was thrown horizontally, the angle of projection is θ=0°
The distance traveled by the ball in the horizontal direction is given by,
[tex]\begin{gathered} x=u_xt \\ \Rightarrow x=u\cos \theta\times t \end{gathered}[/tex]Where uₓ is the x-component of the initial velocity.
On substituting the known values,
[tex]\begin{gathered} x=2.3\times\cos 0^{\circ}\times4 \\ =9.2\text{ m} \end{gathered}[/tex]Therefore the distance traveled by the ball in the x-direction is 9.2 m. That is the ball landed 9.2 meters away from the building.
Applying the equation of the motion in the y-direction,
[tex]\begin{gathered} y=y_0+u_yt+\frac{1}{2}gt^2 \\ =y_0+u\sin \theta\times_{}t+\frac{1}{2}gt^2 \end{gathered}[/tex]Where y is the final height of the ball which is zero meters, y₀ is the initial height of the ball, i.e., the height of the building, uy is the y-component of the initial velocity.
Let us consider that the upward direction is positive while the downward direction is negative. This makes the acceleration due to gravity, g, a negative value, and the height of the building a positive value.
On substituting the known values,
[tex]\begin{gathered} 0=y_0+2.3\times\sin (0^{\circ})\times4+\frac{1}{2}\times-9.8\times4^2 \\ \Rightarrow-y_0=0-4.9\times4^2 \\ y_0=78.4\text{ m} \\ \approx78\text{ m} \end{gathered}[/tex]Therefore the height of the building is 78 m
Which of the following X-Y tables agrees withthe information in this problem?A puck moves 2.35 m/s in a -22.0° direction. A hockeystick pushes it for 0.215 s, changing its velocity to 6.42m/s in a 50.0° direction. What was the acceleration?A)хYYYC)хV 0.8802.18-0.8802.35-2.18ViVE4.134.92B)XVi2.35VE6.42a?Ax 0.2156.42> > 04.924.13a???Ax0.215ΔΧ??t0.2150.215tt 0.2150.215H
Answers
let's find the components for the initial velocity
[tex]v_ix=2.35\cdot\cos (-22)=2.18[/tex][tex]v_iy=2.35\cdot\sin (-22)=-0.88_{}[/tex]then for the final velocity
[tex]v_fx=6.42\cdot\cos (50)=4.13[/tex][tex]v_fy=6.42\cdot\sin (50)=4.92[/tex]The table that agrees with the problem is A)
Then for the acceleration, we will use the next formula
[tex]a=\frac{v_f-v_i_{}}{t}[/tex]for the acceleration in x
[tex]a_x=\frac{v_fx-v_ix}{t}=\frac{4.13-2.18}{0.215}=9.06m/s^2[/tex]then for the acceleration in y
[tex]a_y=\frac{v_fy-v_iy}{t}=\frac{4.92-(-0.88)}{0.215}=26.97m/s^2[/tex]then we calculate the magnitude
[tex]a=\sqrt[]{9.06^2+26.97^2}=28.45\text{ m/s}^2[/tex]How much force must I lift with to lift a 30kg object off the ground?
Answers
The force required to lift the object is 294 N.
Given data:
The mass of object is m=30 kg.
The force applied to lift an object will be equal to the weight of the object.
The weight of the object can be calculated as,
[tex]\begin{gathered} W=mg \\ W=(30)(9.8) \\ W=294\text{ N} \end{gathered}[/tex]The weight of the object is 294 N; therefore, the force required to lift the object is 294 N.
please help me work through this, thank you for your time!
Answers
Given
The equation of the height is
[tex]h(t)=-16t^2+20t+950[/tex]To find
The velocity when the stone reach the ground
Explanation
When the stone reaches the ground
[tex]\begin{gathered} h(t)=0 \\ \Rightarrow-16t^2+20t+950=0 \\ \Rightarrow16t^2-20t-950=0 \\ \Rightarrow t=\frac{20\pm\sqrt{20^2-(4\times16\times(-950)}}{2\times16} \\ \Rightarrow t=\frac{20\pm247.38}{2\times16}=8.35\text{ s} \end{gathered}[/tex]Thus the time taken to reach the ground is 8.35s . (Here only the positive value is considered)
We know the velocity is the change in distance per unit time,
Thus,
[tex]\begin{gathered} v(t)=h^{\prime}(t) \\ \Rightarrow v(t)=-32t+20 \end{gathered}[/tex]At t=8.35 s
[tex]\begin{gathered} v(8.35)=-32\times8.35+20 \\ \Rightarrow v(8.35)=-247.2\text{ feet/s} \end{gathered}[/tex]Conclusion
The velocity is -247.20 feet/s
Resistances of 2.0 Ω, 4.0 Ω, and 6.0 Ω and a 24-V emf device are all in parallel. The current in
the 2.0-Ω resistor is
Answers
Answer:
The current in the 2.0 Ω resistor is 12 A
Explanation:
Given:
R₁ = 2.0 Ω
R₂ = 4.0 Ω
R₃ = 6.0 Ω
ξ = 24 V
______________
I₁ - ?
With parallel connection:
U₁ = U₂ = U₃ = ξ
Ohm's law:
I₁ = U₁ / R₁ = 24 / 2,0 = 12 A
Resistances of 2.0 Ω, 4.0 Ω, and 6.0 Ω and a 24-V emf device are all in parallel, the current in the 2.0-Ω resistor is 6 A.
The voltage across each resistor in a parallel circuit is the same, while the current divides among the different branches.
The sum of the currents passing through each resistor equals the total current flowing into the parallel circuit.
1/RTotal = 1/R1 + 1/R2 + 1/R3
1/RTotal = 1/2.0 Ω + 1/4.0 Ω + 1/6.0 Ω
1/RTotal = 3/12 Ω
1/RTotal = 1/4 Ω
RTotal = 4 Ω
Now,
I = V / RTotal
I = 24 V / 4 Ω
I = 6 A
Thus, the current in the 2.0-Ω resistor is 6 A.
For more details regarding current, visit:
https://brainly.com/question/15141911
#SPJ2
What is the momentum of a 0.144kg baseball thrown at a speed of 46m/s? Give your answer in kgm/s.
Answers
ANSWER:
6.624 kgm/s
STEP-BY-STEP EXPLANATION:
Given:
Mass (m) = 0.144 kg
Speed (v) = 46 m/s
We can calculate momentum using the following formula:
[tex]\begin{gathered} P=m\cdot v \\ \\ \text{ We replacing} \\ \\ P=0.144\cdot46 \\ \\ P=6.624\text{ kgm/s} \end{gathered}[/tex]The momentum is 6.624 kgm/s
Write 8.0090 x 10^2 in standard form . (Example of standard form: 4550)Blank 1:
Answers
We are given the following number in scientific notation:
[tex]8.0090\times10^2[/tex]To convert this number into standard form we will move the decimal point a number of times equal to the exponent of the ten. Since the exponent is positive we will move the point to the right, like this:
[tex]8.0090\times10^2=800.90[/tex]Therefore, the standard form of the number is 800.90
A block of ice is sliding down a ramp of slope 40 to the horizontal. What is the rate of acceleration of the block? Assume the force of friction is not significant.
Answers
The given problem can be exemplified in the following diagram:
Since there is no friction or any other external force, the only force acting in the direction of the movement is the component of the weight of the block, therefore, applying Newton's second law:
[tex]\Sigma F=ma[/tex]Replacing the values:
[tex]mg\sin 40=ma[/tex]We may cancel out the mass:
[tex]g\sin 40=a[/tex]Using the gravity constant as 9.8 meters per square second:
[tex]9.8\frac{m}{s^2}\sin 40=a[/tex]Solving the operations:
[tex]6.3\frac{m}{s^2}=a[/tex]Therefore, the acceleration is 6.3 meters per square second.
Anyone available for teaching me simple pendulum in physics
Answers
Simple pendulum is a device that has a periodic motion.
In periodic motion, the object repeats its path after an interval of time.
The simple pendulum can be drawn as
It has a simple bob connected to a fixed end through a massless string.
Our galaxy, the Milky Way, contains approximately 4.0 x 1011 stars with anaverage mass of 2.0 X 1030 kg each. How far away is the Milky Way from ournearest neighbor, the Andromeda Galaxy, if Andromeda contains roughly thesame number of stars and attracts the Milky Way with a gravitational force of2.4 x 1030 N?
Answers
We will have the following:
First, we remember:
[tex]F=\frac{Gm_1m_2}{r^2}[/tex]Then, from the problem we will have that:
[tex]2.4\ast10^{30}N=\frac{G(2.0\ast10^{30}kg)(2.0\ast10^{30}kg)}{r^2}[/tex][tex]\Rightarrow r^2=\frac{G(2.0\ast10^{30}kg)^2}{2.4\ast10^{30}N}\Rightarrow r\approx1.1116666667\ast10^{20}m[/tex]So, the Andromeda galaxy is approximately 1.1*10^20 meters from the milky way.
The acceleration of the Andromeda galaxy towards the milky way is:
[tex]2.4\ast10^{30}N=(2.0\ast10^{30}kg)a\Rightarrow a=1.2m/s^2[/tex]So, the acceleration towards the milky ways is 1.2m/s^2.
A force gives energy to an object and that energy can:set the object in motion.stop its motion.change the speed and direction of its motion.All of the choices are correct.
Answers
To find:
Which of the given statements is the correct answer?
Explanation:
The work done is the measure of the transfer of energy through the application of force.
The force thus applied can either change the state of motion of the object or the speed and direction of the motion.
That is, when a force is applied to an object, the force can bring the object in motion to rest or set the object in rest, into motion. Or it can also change the speed or direction of motion of the object.
Final answer:
The correct answer is option D, All of the choices are correct.