Answer:
A quadratic equation is an equation that has the following general form:
[tex]ax^2+bx+c=0.[/tex]Any equation that can be rewritten in the above form can be considered a quadratic equation, the important part is that there is a term that includes an
[tex]x^2,[/tex]and that 2 is the greatest exponent of any variable of the equation.
it says (6^2)^2 then it says select one Add, Subtract, Multiply
Multiply
Here, we want to select the arithmetic operation that could be used to evaluate the given indices expression
The key to solving this is to use an important indices relationship
That is;
[tex](a^x)^y=a^{xy}[/tex]Hence, we have to multiply the powers
So the correct option here is multiply
Use the factor theorem to determine whether x-2 is a factor
Factor theorem is usually used to factor and find the roots of polynomials. A root or zero is where the polynomial is equal to zero. Therefore, the theorem simply states that when f(k) = 0, then (x – k) is a factor of f(x).
In this case here, let's find out if 2 is a root of the polynomial given.
As we can see in the box below, 2 is not a root of the polynomial, therefore (x-2) isn't a factor.
[tex]\begin{gathered} P(x)=-2x^3+4x^2-4x-7 \\ P(2)=-2\cdot2^3+4\cdot2^2-4\cdot2-7 \\ P(2)=-16+16-8-7 \\ P(2)=-15 \end{gathered}[/tex]2.write the equation of a circle with the following parameters Center at (0,-1)Passing through (-35,0)
Solution:
Given:
[tex]\begin{gathered} center\text{ }=(0,-1) \\ Through\text{ p}oint\text{ }(-35,0) \end{gathered}[/tex]The equation of a circle is gotten by;
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ where: \\ x=-35 \\ y=0 \\ h=0 \\ k=-1 \\ \end{gathered}[/tex]Substituting these values into the equation to get the value of r;
[tex]\begin{gathered} (-35-0)^2+(0-(-1))^2=r^2 \\ (-35)^2+(1)^2=r^2 \\ 1225+1=r^2 \\ r^2=1226 \end{gathered}[/tex]Thus, the equation of the circle is;
[tex]\begin{gathered} (x-0)^2+(y-(-1))^2=1226 \\ x^2+(y+1)^2=1226 \end{gathered}[/tex]Find the z-value so that the area to the left of z (shaded in the picture) is 0.9131.
area shaded to the left = 0.9131
by using the Z cumulative table , we can see that the value that corresponds with Z= 0.913 is 0.838
In a textbook, 900 digits are used for the page numbers. How many pagesare in the textbook, starting with page 1? (Hint: First find how many digitsare used for pages 1-9 and 10-99.)
Given:
900 digits are used for the page numbers. How many pages are in the textbook, starting with page 1
We will find the number of the pages of the book as follows
The number of digits from 1 to 9 = 9
The number of digits from 10 to 99:
There are 90 numbers, each number has 2 digits
So, the number of digits from 10 to 99 = 90 x 2 = 180
The number of digits from 100 to 999:
There are 900 numbers, and each number has 3 digits
so, the number of digits from 100 to 999 = 900 x 3 = 2700
The overall digits are given = 900
So, number of digits from 1 to 99 = 9 + 180 = 189
Subtract 189 from 900 = 900 - 189 = 711
Divide 711 by 3 = 237
So, the number of pages that have 3 digits = 237
So, the number of pages of the book = 237 + 99 = 336
So, the answer will be 336 pages
Solve the system by substitution.y =10xY=4x+22
Given the system:
[tex]\begin{cases}y=10x \\ y=4x+22\end{cases}[/tex]Let's clear x from equation 1:
[tex]\begin{gathered} y=10x\rightarrow\frac{y}{10}=x \\ \rightarrow x=\frac{y}{10}\text{ (A)} \end{gathered}[/tex]And substitute (A) in equation 2:
[tex]\begin{gathered} y=4x+22 \\ \rightarrow y=4(\frac{y}{10})+22 \\ \rightarrow y=\frac{4}{10}y+22 \end{gathered}[/tex]Solving for y:
[tex]\begin{gathered} y=\frac{4}{10}y+22 \\ \rightarrow y-\frac{4}{10}y=22 \\ \rightarrow\frac{3}{5}y=22\rightarrow3y=110\rightarrow y=\frac{110}{3} \end{gathered}[/tex]Now, let's use (A) to calculate x:
[tex]\begin{gathered} x=\frac{y}{10} \\ \rightarrow x=\frac{\frac{110}{3}}{\frac{10}{1}}\rightarrow x=\frac{110}{30}\rightarrow x=\frac{11}{3} \end{gathered}[/tex]This way,
[tex]\begin{gathered} x=\frac{11}{3} \\ \\ y=\frac{110}{3} \end{gathered}[/tex]Yea I think and if it’s ok we
Explanation: To solve a derivate we can use a simple technique presented below
- First, we take the exponent and multiply it by the function. Second, we subtract a unit of the exponent. Let's visualize it better on the drawing below
Step 1: Now we can use the same concept to calculate all the derivates we need as follows
Final answer: So the final answers are
[tex]\begin{gathered} letter_{\text{ }}a=5x^4 \\ letter_{\text{ }}b=20x^3 \\ letter_{\text{ }}c=60x^2 \\ letter_{\text{ }}d=120x \end{gathered}[/tex].
#3) Ulices was charged $140 plus a pick up charge of $20 to ship 4 identical boxesbys Fast Ship. The pick up charge applies regardless of how many boxes are pickedup. What would have been the change to Ulices' account if he had shipped just 1box?
To determine the Ulices's account if he shipped just 1 box, calculate the charge for one box. To calculate the charge, compute the quotient between the charge for 4 boxes between 4 boxes, just as folow:
charge per one box = 140/4 = 35
Hence, for 1 box the charge is $35
Due to it is necessary to pay $20 idependenty of the number of boxex, you sum $20 to the cost for one box:
New Ulices's account = $35 + $20 = $55
Hence, Ulices's account would have been of $55
3. When people take medicine, the drug gets metabolized by the body and eliminated at a constant rate.Suppose the initial amount of a drug in the body is 549 mg and it is eliminated at a rate of 12% per hour.Let f(x) refer to the amount of drug left in the body after I hours.(a) Write down an exponential function to model this situation. Write your answer using functionnotation(b) How much of the drug is left in the body after 12 hours? Round to the nearest whole number.(c) How much of the drug is left in the body after 180 minutes? Round to the nearest whole number
When people take medicine, the drug gets metabolized by the body and eliminated at a constant rate.
Suppose the initial amount of a drug in the body is 549 mg and it is eliminated at a rate of 12% per hour.
Let f(x) refer to the amount of drug left in the body after I hours.
(a) Write down an exponential function to model this situation. Write your answer using function
notation
(b) How much of the drug is left in the body after 12 hours? Round to the nearest whole number.
(c) How much of the drug is left in the body after 180 minutes? Round to the nearest whole number
Part a)
Let
t -----> number of hours
f(x)=a(1+r)^t
where
a=549 mg
r=12%=0.12
substitute
f(x)=549(1+0.12)^t
f(x)=549(1.12)^tPart b)
For t=12 hours
substitute in the function
f(12)=549(1.12)^12
f(12)=2,139 mgPart c)
For t=180 minutes
Remember that
1 h=60 minutes
so
180 minutes=180/60=3 hours
For t=3 hours
substitute
f(3)=549(1.12)^3
f(3)=771 mgbased on the side lengths given (a, b, and c), which triangles are right triangles????A. a=4, b=6, c=8B. a=6, b=8, c=10C. a=5, b=6, c=(square root of) 61D. a=6, b=9, c=12 PLEASE HELP!!
Explanation
From the question, a right-angle triangle must obey Pythagoras theorem. Therefore, we can see that
[tex]6^2+8^2=10^2\text{ also, }5^2+6^2=(\sqrt{61})^2[/tex]The rest of the values do not obey Pythagoras theorem. Therefore;
Answer: Option B and Option C
If h(x) = 3(x2 + 1) - 6, what is the value of h(10)?
What is the average rate of change of f(x) from x1=-10 to x2=-3? Please write your answer rounded to the nearest hundredth. f(x)= the square root of -9x+5
We have the following information
[tex]\begin{gathered} x_1=-10 \\ x_2=-3 \end{gathered}[/tex]and the function
[tex]f(x)=\sqrt[]{-9x+5}[/tex]In order to find the average rate, we need to find y1 and y2. Then, by substituting x1 into the function, we have
[tex]\begin{gathered} f(-10)=\sqrt[]{-9(-10)+5} \\ f(-10)=\sqrt[]{90+5} \\ f(-10)=\sqrt[]{95} \end{gathered}[/tex]Similarly, by substituting x2, we get
[tex]\begin{gathered} f(-3)=\sqrt[]{-9(-3)+5} \\ f(-3)=\sqrt[]{27+5} \\ f(-3)=\sqrt[]{32} \end{gathered}[/tex]Therefore, the average rate is given by
[tex]\frac{f(x_2)-f(x_1)}{x_2-x_1}=\frac{\sqrt[]{32}-\sqrt[]{95}}{-3-(-10)}[/tex]which gives
[tex]\begin{gathered} \frac{f(x_2)-f(x_1)}{x_2-x_1}=\frac{\sqrt[]{32}-\sqrt[]{95}}{7} \\ \frac{f(x_2)-f(x_1)}{x_2-x_1}=\frac{5.6568-9.7467}{7} \\ \frac{f(x_2)-f(x_1)}{x_2-x_1}=-\frac{4.0899}{7} \end{gathered}[/tex]Therefore, the average rate is
[tex]\frac{f(x_2)-f(x_1)}{x_2-x_1}=-0.58[/tex]S-7>3Help please !Don’t really understand
The given inequality is
[tex]s-7>3[/tex]To solve it, we need to isolate s on one side and the numerical terms on the other side
To do that we need to move 7 from the left side to the right side with 3, so
Add 7 to both sides
[tex]\begin{gathered} s-7+7>3+7 \\ s+0>10 \\ s>10 \end{gathered}[/tex]The solution of the inequality is s > 10
We can represent it on the number line
Please help solve the following questions using the exponential equation
SOLUTION
We want to solve
[tex]7^{2x+4}=2^{x-5}[/tex]Taking logarithm of both sides, we have
[tex]\begin{gathered} \log 7^{2x+4}=\log 2^{x-5} \\ (2x+4)\log 7=(x-5)\log 2 \\ \text{expanding we have } \\ (2x)\log 7+(4)\log 7=(x)\log 2-(5)\log 2 \end{gathered}[/tex]Collecting like terms we have
[tex]\begin{gathered} (2x)\log 7-(x)\log 2=-(4)\log 7-(5)\log 2 \\ x(2\log 7-\log 2)=-4\log 7-5\log 2 \\ \text{dividing both sides by }(2\log 7-\log 2),\text{ we have } \\ x=\frac{-4\log 7-5\log 2}{2\log 7-\log 2} \end{gathered}[/tex]Hence the solution set expressed in terms of logarithm is
[tex]x=\frac{-4\log7-5\log2}{2\log7-\log2}[/tex]Using a calculator to obtain a decimal approximation, we have
[tex]\begin{gathered} x=\frac{-4\log7-5\log2}{2\log7-\log2} \\ x=\frac{-3.3804-1.5051}{1.6902-0.3010} \\ x=\frac{-4.8855}{1.3892} \\ x=-3.51677 \\ x=-3.52 \end{gathered}[/tex]Hence the answer is -3.52 to 2 decimal places
The figure below is a net for a right rectangular prism. Its surface area is 384 cm2 andthe area of some of the faces are filled in below. Find the area of the missing faces,and the missing dimension.Yes
Solution
For this case we know the total surface area given by:
384 cm^2
And we have the following: 108+48 +108+48 = 312 cm^2
the ramianing area is:
384 -312= 72 cm^2
And we can do the following:
2*9*? = 72
Solving for ? we got:
? = 72/18 = 4 cm
the final answer is:
The area of each missing face is: 36 cm^2
The lenght of each missing edge is: 4 cm
Translate thefollowing phaseinto an inequality-3 times r is at least 33A) inequality B) Solve the equality for r.C) express the solution in interval notation.
Given the phrase:
-3 times r is at least 33
Let's translate the given phrase into an inequality.
• Part A.
Let's figure out the inequality in steps.
-3 times r is written as:
-3r
-3 times s is at least 33 means that -3r is greater than or equal to 33.
Hence, we have the inequality:
[tex]-3r\ge33[/tex]• Part B.
Let's solve the inequality for r.
To solve for r, divide both sides of the inequality by -3:
[tex]\begin{gathered} \frac{-3r}{-3}\ge\frac{33}{-3} \\ \\ r\le-11 \end{gathered}[/tex]• Part C.
Let's express the solution in interval notation.
Here, the solution is:
[tex]r\le-11[/tex]It means s must be less than or equal to 11.
Therefore, the solution in interval notation is:
[tex](-\infty,-11\rbrack[/tex]ANSWER:
• A) -3r ≥ 33
• B) r ≤ -11
• C) (-∞, -11]
Solve equations x-27=56
Answer:
x = 83
Step-by-step explanation:
Add 27 to both sides
x - 27 +27 = 56 + 27
x = 83
Which sequence of rigid motions will definitely work to take triangle RPQ onto triangle CAB?
RPQ to CAB transform
Rotation needed = RPQ using C as center ,an angle ACP
Translations= Line RC
Reflections= None
Then answer is
Option D)
Translate RPQ by the direct line segment RC
Complete the conversion. 1 12, gal = qt Click the icon to view the customary units. 1 12 gal = 2 qt (Type an integer, fraction, or mixed number.)
1 gal = 4 qt
Multiply by 4
12 1/2 (4) = 50 qt
Which is the degree measure of an angle whose tangent is 1.19? Round the answer to the nearest whole number.
We know that:
[tex]\tan\theta=1.19[/tex]where theta is the angle we are trying to find; to get the angle we take the inverse tangent at both sides of the equation. Then:
[tex]\begin{gathered} \tan^{-1}(\tan\theta)=\tan^{-1}1.19 \\ \theta=50 \end{gathered}[/tex]Therefore, the angle we are looking for is 50°
hi please help me tysmYour mother places 6 flowers in a vase. How many vases does your mother need for 30 flowers?A. 9B. 7C. 5D. 3
SOLUTION:
Step 1:
In this question, we are given the following:
Your mother placed 6 flowers in a vase.
How many vases does your mother need for 30 flowers?
Step 2:
The details of the solutions are as follows:
[tex]\begin{gathered} 6\text{ flowers = 1 vase} \\ \text{Then, we have that:} \\ 30\text{ flowers = }\frac{(30\text{ x 1)}}{6}=\frac{30}{6}=\text{ 5 vases ( OPTION C)} \end{gathered}[/tex]
Identify an angle That's congruent to < PQR in the given figure.
You need to rotate the figure to see the new orientation
1 금35Lolo19.Which type of variation is modeled in the table?jointdirectcombinedInverse
The answer to your question is inverse varaiation.
Explanation: Inverse variation is a reciprocal term. Or say a variable is increasing while the other is decreasing.
So it is observed that as when y increases, then x decreases.
And also when y decreases, then x increases.
Thus, It is an inverse variation.
If the product is 900, and the two of its three factors are 3 and 50, what is the third factor?
We have the multiplication of 3 factors, one of them unknown, that give 900 as a result.
We can write this as:
[tex]\begin{gathered} 3\cdot50\cdot x=900 \\ 150x=900 \\ x=\frac{900}{150} \\ x=6 \end{gathered}[/tex]The third factor is 6.
Two electrical lines are parallel to each other. One of the lines is represented by theequation - 4x + y = 8. What is the slope of the other electrical line?
Use any method to add or subtract (1 point)
5/7 - (3/14 + 3/14)
Answer:
5/7 - (3/14 + 3/14) = 2/7See the steps of solution:
5/7 - (3/14 + 3/14) = Solve parenthesis first5/7 - (3 + 3)/14 = Add fractions with same denominator5/7 - 6/14 = Simplify5/7 - 3/7 = Subtract fractions with same denominator(5 - 3)/7 = Simplify2/7 AnswerAnswer:
2/7 (or) 0.285
Step-by-step explanation:
Given problem,
→ 5/7 - (3/14 + 3/14)
Let's solve the given problem,
→ 5/7 - (3/14 + 3/14)
→ (5/7) - (6/14)
→ ((5 × 2)/(7 × 2)) - (6/14)
→ (10/14) - (6/14)
→ (10 - 6)/14
→ 4/14 = 2/7
Hence, required answer is 2/7.
An eighth-grade student estimated that she needs $8,800 for tuition and fees for each year of college. She already has $5,000 in a savings account. The table shows the projected future value of the account in five years based on different monthly deposits.future value of a savings account. initial balance, dollars, $5000, $5000, $5000, $5000. Monthly deposit, dollars. $100, $200, $300, $400. Account value in five years, dollars. $12,273; $18,737; $25,202; $31,667.The student wants to have enough money saved in five years to pay the tuition and fees for her first two years of college. Based on the table, what is the minimum amount she should deposit in the savings account every month?AnswerF$200G$300H$100J$400
Since each year cost $8,800 for two years tuition he will need $17,600 then if he want to save at least this much in five years according to the table he needs to save $200 monthly
[tex]4a ^{2} - 12a - 16[/tex]I need help factoring
4(a-4)(a+1)
1) Factorizing 4a²-12a -16
4a²-12a -16 Note that the GCD (4,12,16) is 4, Rewrite them
4a²- 4*3a - 4* 4
2) 4(a² -3a -4) Rewrite a² -3a -4 answering the question, What are the numbers whose sum is 3 and product is 4?
Answer:
1 -4 = -3
1 x -4 = -4
3) Hence, the answer is:
4a²-12a -16= 4(a-4)(a+1)
i need help asap with this (Its ACD and not AGD just incase that confuses you)
4)
In the case of a square, its diagonals are equal and bisect each other, meeting at 90°.
In our case, using a diagram,
Therefore,
[tex]\begin{gathered} a+2b=90 \\ and \\ 2a-b=90 \end{gathered}[/tex]Solving the system of equations for a and b,
[tex]\begin{gathered} \Rightarrow a=90-2b \\ \Rightarrow2(90-2b)-b=90 \\ \Rightarrow5b=90 \\ \Rightarrow b=18 \end{gathered}[/tex]Finding a,
[tex]\begin{gathered} b=18 \\ \Rightarrow a=90-2*18=90-36=54 \end{gathered}[/tex]The answers are a=54, b=18What percentage is 1 m longer than 1 yard? Round to one tenth percent. 1 yard = 91.4 cm