The phrase can be written as:
[tex]\lvert x+5\rvert=3[/tex]therefore the correct choice is the third one.
Identify how many solutions there are to the system of equations represented on the following graph. Treat the red and black graphs as one circle. H H
The solution of two or more equations is the point where the equation intersects. The more that the graph of the equation intersects, the more its solutions.
From the given graph of circle and parabola, they intersect three times. Therefore, there are 3 solutions in this given system of equations.
Please help if you can. I will only accept answers with work shown. Will give Brainliest.
Initial subscribers: 285
Increase rate : 75 % = 75/100 = 0.75 (decimal form)
years passed = 1994-1985 = 9 years
Apply the formula:
A = P (1 +r ) ^ t
Where:
A = number of cell phone subscribers after t years
P = initial suscribers
r= increase rate in decimal form
t= years
Replacing:
A = 285 (1 +0.75)^9 = 43,872
Phil wants to play full-back for his football team. The decision depends on who serves as head coach for a given game. Coach Sal is head coach about 75% of the time, and Coach Benny is head coach other 25% of the time. Coach Sal has faith in Phil, so he starts him at full-back in 70% of the games he coaches. Coach Benny is not so sure, so he starts Phil at full-back 30% of the time. What is the probability of Phil starting as full-back for the next game?0.3980.60.40.24
Given that
Coach Sal is the head coach about 75% of the time and coach Benny is the coach for the remaining 25% of the time.
Sal has faith in Phil, so he full-back in 70% of the time and Benny had the faith, so he full-back 30% of the time.
Explanation -
Since the coach, Sal is the coach for 75% of the time and Benny is for 25% of the time.
Also, Sal's faith in full-back is 70% and Benny's faith in full-back is 30%.
Then,
75% of 70% = 75/100 x 70/100 = 0.525
25% of 30% = 25/100 x 30/100 = 0.075
So the final probability of Phil will be 0.525 + 0.075 = 0.6
Final answer -
So the final answer is 0.6.Hence option B is correct.Answer this question based on the knowledge of angle in a Circle.
From the given diagram, PQ is a diameter and since the triangle inside a semicircle is right angled, hence triangle PQR is a right triangle.
Also since the side QR is parallel to OS, hence the line PR is perpendicular to the lines QR and OS
Hence;
PR ⊥ QR and OS ⊥ PR
Proof that From △PRQ,
Since OS ⊥ PR, hence △PSR is divided into two similar triangles by the line OS showing that the base angles (
Recall that for an isosceles triangle, the base angles and two opposite sides are equal. Based on the proof above, we can conclude that;△PSR is isosceles triangle showing that SP = SRwhich operation is applied to 3 and ×+5 in the expression 3(x+5) over 0.2
In the expression " 3(x+5) over 0.2" the word "over" indicates that 0.2 is dividing the first term 3(x+5), you can write the calculation as follows:
[tex]\begin{gathered} \frac{3(x+5)}{0.2} \\ \cdot-\cdot or\cdot-\cdot \\ 3(x+5)\div0.2 \end{gathered}[/tex]The operation is a division.
How many yards are there in 72 miles? Round answer to nearest 100th (2-decimal places).
Given,
The number of total miles are 72.
As know that,
There are 1760 yards in one mile.
The number of yards in 72 mile is,
[tex]\text{Number of yards=72}\times1760=126720\text{ miles}[/tex]Hence, the nnumber of yards in one mile is 126720.
find the perimeter of the given triangle. round to the nearest tenth
The perimeter of the triangle to the nearest tenth is 13.8 units.
How to find the perimeter of a triangle?The perimeter of a triangle is the sum of the whole sides of the triangle.
Therefore, let's find the perimeter of the triangle.
let's find the two missing sides of the triangle as follows;
tan 18 = opposite / adjacent
tan 18 = y / 5.8
y = 5.8 tan 18
y = 1.88453423815
y = 1.88
cos 18 = adjacent / hypotenuse
cos 18 = 5.8 / x
x = 5.8 / cos 18
x = 6.09848421123
x = 6.09
Therefore,
perimeter of the triangle = 5.8 + 1.9 + 6.1
perimeter of the triangle = 13.8 units
learn more on perimeter here: https://brainly.com/question/25617803
#SPJ1
The equation y = 40 + 3x represents the amount a company will pay to have stickers made, where x represents the item published and y represents the total cost in dollars in dollars. the equation y = 5x represents the company's income from selling the sticker, where y represents the money earned in dollars and x represents the number of items sold.5. At at one point the lines intersect?6. when will the company make a profit?
we have the equations
y=40+3x -----> blue line
and
y=5x -----> red line
Part 5
intersection point
Equate both equations
5x=40+3x
5x-3x=40
2x=40
x=20
Find the value of y
y=5(20)=100
the intersection point is (20,100)
Part 6
when will the company make a profit?
the company make a profit when 5x > 40+3x
Remember that
For x=20------> the profit is zero
so
the company make a profit when x>20
Verify
solve the inequality
5x > 40+3x
5x-3x > 40
2x > 40
x > 20 ----> is ok
Ayana drew a scale drawing of a house and its lot. The backyard, which is 70 feet long in real life, is 203 inches long in the drawing. What scale did Ayana use for the drawing?29 inches : [ ] feet
Let m be scale used by individual for drawing.
Then the product of scale factor and original length is equal to the length in drawing. So,
[tex]\begin{gathered} 70\times m=203 \\ m=\frac{203}{70} \\ =\frac{29}{10} \end{gathered}[/tex]So, 29 inches of drawing is corresponding to 10 feet of house.
graph g(x) where f(x) = 2x-5 and g(x) = f(x+1)
The graph therefore is shown below;
4.
The value of a truck decreases exponentially since its purchase. The two points on the
graph shows the truck's initial
value and its value a decade afterward.
[6040,000)
a) Express the car's value, in dollars, as a function of time
d, in decades, since purchase.
(1 24,000)
b) Write an expression to represent the car's value 4 years
after purchase.
c) By what factor is the value of the car changing each year? Show your reasoning.
Answer:
a. v = 40 000 (3/ 5)^d
b. v = 40 000 (3/5)^(4/10)
c. 0.95
Explanation:
The exponential growth is modelled by
[tex]v=A(b)^d[/tex]We know that points (0, 40 000) and (1, 24 000) lie on the curve. This means, the above equation must be satsifed for v = 40 000 and d = 0. Putting v = 40 000 and d = 0 into the above equation gives
[tex]40\; 000=Ab^0[/tex][tex]40\; 000=A[/tex]Therefore, we have
[tex]v=40\; 000b^d[/tex]Similarly, from the second point (1, 24 000) we put v = 24 000 and d = 1 to get
[tex]24\; 000=40\; 000b^1[/tex][tex]24\; 000=40\; 000b^{}[/tex]dividing both sides by 40 000 gives
[tex]b=\frac{24\; 000}{40\; 000}[/tex][tex]b=\frac{3}{5}[/tex]Hence, our equation that models the situation is
[tex]\boxed{v=40\; 000(\frac{3}{5})^d\text{.}}[/tex]Part B.
Remember that the d in the equation we found in part A is decades. Since there are 10 years in a decade, we can write
t = 10d
or
d = t/10
Where t = number of years
Making the above substitution into our equation gives
[tex]v=40\; 000(\frac{3}{5})^{\frac{t}{10}}[/tex]Therefore, the car's value at t = 4 is
[tex]\boxed{v=40\; 000(\frac{3}{5})^{\frac{4}{10}}}[/tex]Part C:
The equation that gives the car's value after t years is
[tex]v=40\; 000(\frac{3}{5})^{\frac{t}{10}}[/tex]which using the exponent property that x^ab = (x^a)^b we can rewrite as
[tex]v=40\; 000\lbrack(\frac{3}{5})^{\frac{1}{10}}\rbrack^t[/tex]Since
[tex](\frac{3}{5})^{\frac{1}{10}}=0.95[/tex]Therefore, our equation becomes
[tex]v=40\; 000\lbrack0.95\rbrack^t[/tex]This tells us that the car's value is changing by a factor of 0.95 each year.
What is the solution of the system?{4x−y=−38x+y=3Enter your answer in the boxes.
Solution:
Given:
[tex]\begin{gathered} 4x-y=-38 \\ x+y=3 \end{gathered}[/tex]Solving the system simultaneously by substitution method;
[tex]\begin{gathered} 4x-y=-38\ldots\ldots\ldots\ldots\ldots(1) \\ x+y=3\ldots\ldots\ldots\ldots\ldots\ldots.(2) \\ \\ \text{making y the subject of the formula from equation (2);} \\ x+y=3 \\ y=3-x\ldots\ldots\ldots\text{.}\mathrm{}(3) \\ \\ \text{Substituting equation (3) into equation (1);} \\ 4x-y=-38 \\ 4x-(3-x)=-38 \\ 4x-3+x=-38 \\ 4x+x=-38+3 \\ 5x=-35 \\ \text{Dividing both sides by 5;} \\ x=-\frac{35}{5} \\ x=-7 \\ \\ \text{Substituting the value of x into equation (3) to get y;} \\ y=3-x \\ y=3-(-7) \\ y=3+7 \\ y=10 \end{gathered}[/tex]Therefore, the solution of the system is;
[tex](x,y)=(-7,10)[/tex]Simplify the expression `2\sqrt{a^{2}b^{8}}\left(ab^{3}\right)^{-1}`You may type many lines to show your work. Enter equations inside the text using the square-root button below.
ANSWER
2b
EXPLANATION
To simplify this expression, we have to apply some of the exponents' properties. First, the square root is a fractional exponent,
[tex]\sqrt{x}=x^{1/2}[/tex]So we can rewrite the expression as,
[tex]2\sqrt{a^2b^8}(ab^3)^{-1}=2(a^2b^8)^{1/2}(ab^3)^{-1}[/tex]Then, we can distribute the exponents into the multiplication,
[tex](xy)^z=x^zy^z[/tex]In this problem,
[tex]2(a^2b^8)^{1/2}(ab^3)^{-1}=2(a^2)^{1/2}(b^8)^{1/2}(a)^{-1}(b^3)^{-1}[/tex]Exponents of exponents are multiplied,
[tex](x^y)^z=x^{yz}[/tex]In this problem,
[tex]2(a^2)^{1/2}(b^8)^{1/2}(a)^{-1}(b^3)^{-1}=2\cdot a^{2\cdot1/2}\operatorname{\cdot}b^{8\operatorname{\cdot}1/2}\operatorname{\cdot}a^{-1}\operatorname{\cdot}b^{3\operatorname{\cdot}(-1)}[/tex]Simplify if possible,
[tex]2\cdot a^{2\cdot1/2}\operatorname{\cdot}b^{8\operatorname{\cdot}1/2}\operatorname{\cdot}a^{-1}\operatorname{\cdot}b^{3\operatorname{\cdot}(-1)}=2\cdot a^1\operatorname{\cdot}b^4\operatorname{\cdot}a^{-1}\operatorname{\cdot}b^{-3}[/tex]Now, the product of two powers with the same base is equal to the base raised to the sum of the exponents,
[tex]x^y\cdot x^z=x^{y+z}[/tex]In this problem,
[tex]2\cdot a^1\operatorname{\cdot}b^4\operatorname{\cdot}a^{-1}\operatorname{\cdot}b^{-3}=2\cdot a^{1-1}\operatorname{\cdot}b^{4-3}[/tex]Solve the subtractions,
[tex]2\cdot a^{1-1}\operatorname{\cdot}b^{4-3}=2\cdot a^0\cdot b^1=2b[/tex]Hence, the simplified expression is 2b.
Ms. Friedman and Mrs. Elliot both teachsixth grade math. They share a storagecloset. What is the total area of both roomsand the storage closet?
The two classrooms are identical in length and width. On the other hand, the dimensions of the storage closet are
[tex](40-34)\times(36-30)=6\times6[/tex]The shape of both classrooms and the storage closet is rectangular; therefore, their areas are
[tex]\begin{gathered} A_{\text{rectangle}}=l\cdot w\to length\cdot width_{} \\ \Rightarrow A_{\text{Friedman}}=40\cdot36 \\ _{}A_{\text{Elliot}}=40\cdot36 \\ A_{storage}=6\cdot6 \\ \end{gathered}[/tex]Simplifying,
[tex]\begin{gathered} \Rightarrow A_{\text{storage}}=36ft^2 \\ \Rightarrow A_{\text{Friedman}}=A_{\text{Elliot}}=1440ft^2 \end{gathered}[/tex]Finally, the total area of the compound is
[tex]\begin{gathered} A_{\text{total}}=A_{\text{Friedman}}+A_{\text{Elliot}}-A_{\text{storage}} \\ \Rightarrow A_{\text{total}}=2\cdot1440-36=2844 \end{gathered}[/tex]Thus, the total area of the two classrooms plus the closet is 2844ft^2
Then,
Distance-Time Grapfoss Object ng Constant Speed - 9) Achillwit and string a speed The graph above shows the Giant the ball towed from starting pucat in 5 seconds.
In the given graph, the following are the records of the distance of the tennis ball at a certain time (seconds) after being hit:
Time (seconds) Distance (meters)
1 0.5
2 1
3 1.5
4 2
5 2.5
To be able to get the speed of the tennis ball, let's use any of the data (Time and Distance Covered) in the graph, and use the formula in calculating the speed.
[tex]\text{ Speed = }\frac{Dis\tan ce}{Time}[/tex]Let's use 1 second = 0.5 meter. We get,
[tex]\text{ Speed = }\frac{0.5\text{ meter}}{1\text{ second}}[/tex][tex]\text{Speed = 0.5 meter/second}[/tex]Therefore, the speed of the tennis ball is 0.5 m/s.
The answer is letter A.
A training field is formed by Joining a rectangle and two semicircles, as shown below. The rectangle is 96 m long and 74 m wide.Find the area of the training fleld. Use the value 3.14 for it, and do not round your answer. Be sure to include the correct unit in your answer.
To calculate the area of the training field, the first step is to calculate the area of the rectangular portion. The formula for calculating the area of a rectangle is expressed as
Area = length x width
From the information given,
length = 96
width = 74
Area of rectangular portion = 96 x 74 = 7104
The two semicircles would add up to form a complete circle because a semicircle is half of a circle. The diameter of the circle would be the width of the rectangular portion. The formula for calculating the area of a circle is expressed as
Area = pi x radius^2
From the information given,
pi = 3.14
diameter = 74
radius = diameter/2 = 74/2 = 37
By substituting the values into the formula, we have
Area of the two semicircular portions = 3.14 x 37^2 = 4298.66
Area of the training field = area of rectangular portion + area of the two semicircular portions = 7104 + 4298.66
Area of the training field = 11402.66 m^2
Translate this sentence into an equation.The sum of 21 and Mabel's score is 66.
The sum of 21 and Mabel's score is 66:
This means 21 was added to Mabel's score to give 66
let Mabel's score = m
21 + Mabel's score = 66
In the from equation:
[tex]\text{21 + m = 66}[/tex]Need help with the question I need to understand so I do good on my test
Given:-
There are two types of log to measure the density.
Pine log of radius 5-inch and 30-inch long.
Oak board that is 5.5 inch long and 1.5 inch thickness and 3 feet long.
To find the shapes which can be used.
The pine long is round in shape so the shape formed in pine log is CYLINDRICAL SHAPE.
Oak board is 5.5 inch long and 1.5 inch thickness and 3 feet long so the shape formed will be CUBOID.
So the required solutions are CYLINDER AND CUBOID.
Each participant must pay $14 to enter the race. Each runner will be given a T-shirt that cost race organizers $3.50. If the T-shirt was the only expense for the race organizers, which of the following expressions represents the proportion of the entry fee paid by each runner that would be donated to charity?
The total amount paid by each participant is $14, from which $3.5 will be used for the T-shirt. As that is the only expense, all the remaining money will be available to donate to charity.
[tex]14-3.5=10.5[/tex]Then, for each participant, $10.5 of the $14 paid will be donated to charity.
To find the proportion of the fee paid that would be donated we just need to divide those values:
[tex]\frac{\text{Amount of money donated}}{\text{Total fee paid}}[/tex][tex]\frac{10.5}{14}=\frac{3}{4}[/tex]Then, 3/4 is the proportion of the entry fee paid that will be donated to charity.
Find the solution for the given the system of equations:Y= (1/2)x - 1/2 and y=2^(x+3)
Answer:
This system has no solution.
Step-by-step explanation:
The solution of this system is the ordered pair that is the solution to both equations, we can solve this using the graphical method, which consists of graphing both equations in the same coordinate system.
The solution to the system will be at the point where the two functions intersect.
Since the functions do not intersect, this system has no solution.
The base of a triangle is given by a number, x (metres). The height of the triangle is ten metres less than the product of two and the number. The area of the triangle is equal to the product of seven and the base length.
According to the question the base of the triangle is x, the height is ten less than the product of two and x, this is 2x-10. The area of the triangle is the product of seven and the base, this is 7x.
The area of a triangle is given by:
[tex]A=\frac{b\cdot h}{2}[/tex]Replace each variable for the given expressions:
[tex]\begin{gathered} 7x=\frac{x\cdot(2x-10)}{2} \\ 7x=\frac{2x^2-10x}{2} \\ 7x=x^2-5x \\ 7=x-5 \\ x=7+5 \\ x=12 \end{gathered}[/tex]x has a value of 12.
Find the value of tan X rounded to the nearest hundredth, if necessary.
5
W
1
√26
X
The value of tan x is 5
We need to find the value of tan x
Tan is one of the trignometric functions and the range of a tan function varies from 0 ≤ tan x ≤ 2π
In the triangle vwx, the perpendicular of x is VW and the base is WX
tan x = perpendicular / base
Here, the perependicular is 5 and base is 1
tan x = 5/1
tan x = 5
Therefore, the value of tan x is 5
To learn more about trignometric functions refer here
https://brainly.com/question/25618616
#SPJ9
Two cards are drawn from a standard deck without replacement. What is the probability that the first card is a diamond and the second card is red
The probability that the first card drawn without replacement is a diamond and the second card drawn is red is approximately 0.12
Probability of an event without replacementThe probability for an event without replacement implies that once an item is drawn, then we do not replace it back to the sample space before drawing another item.
In a standard deck of cards, there is a total of 52 cards with 13 diamonds and 26 reds (including diamonds)
probability that the first card drawn is diamond = 13/52
probability that the first card drawn is red = 25/51 {because diamond is also a red and was drawn first without replacement}
So;
probability that the first card is a diamond and the second card is red = (13/52) × (25/51)
probability that the first card is a diamond and the second card is red = 325/2652
probability that the first card is a diamond and the second card is red = 0.1225
Therefore, the proprobability that the first card drawn without replacement a diamond and the second card is red is approximately 0.12
Learn more about probability here: https://brainly.com/question/20140376
#SPJ1
What is the radius of a circle with circumferenceC= 40 CM
Solution:
The circumference C, of a circle is;
[tex]C=\pi r^2[/tex]Given;
[tex]C=40cm,\pi=3.14[/tex]The radius r, is;
[tex]\begin{gathered} 40=3.14(r^2) \\ \text{Divide both sides by 3.14} \\ \frac{40}{3.14}=\frac{3.14(r^2)}{3.14} \\ r^2=12.74 \\ \text{Take the square root of both sides;} \\ \sqrt[]{r^2}=\sqrt[]{12.74} \\ r=3.57 \end{gathered}[/tex]The radius of the circle is 3.57cm
Find the volume of the sphere. Round your answer to the nearest tenth.A) 2,289.1 m^3B) 3,052.1 m^3C) 24,416.6 m^3D) 12,437.4 m^3
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
sphere:
diameter = 18 m
Step 02:
geometry:
volume of the sphere:
v = 4/3 π r³
π = 3.14
r = d / 2 = 18 m / 2 = 9 m
v = 4/3 π (9 m)³ = 3052.1 m³
The answer is:
3052.1 m³
Find the point on the curve y=5x+1 closest to the point (0,4).
Given the coordinates of two points P and Q, we can calculate the distance between them using the formula:
[tex]\begin{gathered} \begin{cases}P={(x_P},y_P) \\ Q={(x_Q},y_Q)\end{cases} \\ . \\ d=\sqrt{(x_P-x_Q)^2+(y_P-y_Q)^2} \end{gathered}[/tex]In this case, we want the smallest distance between a point in the curve and the point (0, 4)
Then, we know that there is a point that we can call Q = (x, y) that is the closest to the point (0, 4). We can write, using the distance formula:
[tex]d=\sqrt{(x-0)^2+(y-4)^2}=\sqrt{x^2+(y-4)^2}[/tex]The equation given is:
[tex]y=5x+1[/tex]We want to rewrite the distance formula to include the equation of the curve. Since there is a term 'x²', we can solve the equation for x and square on both sides:
[tex]\begin{gathered} y=5x+1 \\ . \\ y-1=5x \\ , \\ x=\frac{y}{5}-\frac{1}{5} \\ . \\ x^2=(\frac{y}{5}-\frac{1}{5})^2 \end{gathered}[/tex]Now we can substitute in the distance equation:
[tex]d=\sqrt{(\frac{y}{5}-\frac{1}{5})^2+(y-4)^2}[/tex]We can see that this is a distance function for any point of the curve to the point (0, 4). This is actually a function of y.
[tex]d(y)=\sqrt{(\frac{y}{5}-\frac{1}{5})^2+(y-4)^2}[/tex]Now, we can apply calculus to find the minimum of this function. Let's take the first derivative:
[tex]d^{\prime}(y)=\frac{\frac{2}{5}(\frac{y}{5}-\frac{1}{5})+2(y-4)}{2\sqrt{(\frac{y}{5}-\frac{1}{5})^2+(y-4)^2}}[/tex]Simplify:
[tex]d^{\prime}^(y)=\frac{26y-101}{25\sqrt{(\frac{y}{5}-\frac{1}{5})^2+(y-4)^2}}[/tex]And since we want to find a minimum, we need to also calculate the second derivative:
[tex]d^{\prime}^{\prime}(y)=\frac{26\sqrt{(y-4)^2+(\frac{y}{5}-\frac{1}{5})^2}-\frac{(2(y-4)+\frac{2}{5}(\frac{y}{5}-\frac{1}{5})(26y-101)}{2\sqrt{(y-4)^2+(\frac{y}{5}-\frac{1}{5})^2}}}{25((y-4)^2+(\frac{y}{5}-\frac{1}{5})^2)}[/tex]Simplify:
[tex]d^{\prime}^{\prime}(y)=\frac{9}{25((y-4)^2+(\frac{y}{5}-\frac{1}{5})^2)^{\frac{3}{2}}}[/tex]Now, we need to find the critical points of the function. The critical points are the x values where the first derivative is 0.
Then:
[tex]d^{\prime}(y)=\frac{26y-101}{25\sqrt{(y-4)^2+(\frac{y}{5}-\frac{1}{5})^2}}[/tex]Is a quotient, For a quotient to be 0, the only way this is possible is for the numerator to be 0. Then:
[tex]\begin{gathered} 26y-101=0 \\ . \\ y=\frac{101}{26} \end{gathered}[/tex]And now, to see if this critical point is a minimum, we evaluate it in the second derivative, if the second derivative is positive in this critical point, the function has a minimum at that point:
[tex]d^{\prime}^{\prime}(\frac{10}{26})=\frac{9}{25((\frac{101}{26}-4)^2+(\frac{101}{26}-\frac{1}{5})^2)^{\frac{3}{2}}}\approx1.76746[/tex]Then, the function d(y) has a minimum at y = 101/26
Now, we need to find the x coordinate of this point. We use the equation of the curve:
[tex]\begin{gathered} \frac{101}{26}=5x+1 \\ . \\ x=(\frac{101}{26}+1)\cdot\frac{1}{5}=\frac{15}{26} \end{gathered}[/tex]Thus, the answer to the point in the curve that is the closest to (0, 4) is:
[tex](\frac{15}{26},\frac{101}{26})[/tex]A certain strain of bacteria is growing at a rate of 44% per hour, and with 2,000 bacteria initially, this event can be modeled by the equation B(t) = 2,000(1.44)t. With this fast growth rate, scientists want to know what the equivalent growth rate is per minute. Using rational exponents, what is an equivalent expression for this bacterial growth, expressed as a growth rate per minute?
The given equation for the growth rate per hour is:
[tex]B(t)=2,000(1.44)^t[/tex]Where t is the time in hours.
The equivalent growth rate per minute would be the equivalent in minutes for hours, then:
[tex]1\min \cdot\frac{t\text{ hours}}{60\min }=\frac{t}{60}[/tex]Where t is the time in minutes, then the answer is:
[tex]B(t)=2,000(1.44)^{\frac{t}{60}}[/tex]45 pointsSolve the logarithmic equation below. All work must be shown to earn full credit and
We know that the substraction of two logarithm of the same base is related to a division:
[tex]\log _460-\log _44=\log _4(\frac{60}{4})[/tex]Since 60/4 = 15, then
[tex]\log _4(k^2+2k)=\log _415[/tex]Then, the expressions in the parenthesis are equal:
k² + 2k = 15
Factoring the expression
Now, we can solve for k:
k² + 2k = 15
↓ substracting 15 both sides
k² + 2k - 15 = 0
Since
5 · (-3) = -15 [third term]
and
5 - 3 = 2 [second term]
we are going to use 5 and -3 to factor the expression:
k² + 2k - 15 = (k -3) (k +5) = 0
We want to find what values should have k so
(k -3) (k +5) = 0
if k -3 = 0 or if k +5 = 0, the expression will be 0
So
k - 3 = 0 → k = 3
k +5 = 0 → k = -5
Answer: k = 3 or k = -5If a student got 10 answers out of 15 what’s the percent?
To calculate the percentage we have to write a simple fraction like this:
percentage = number of answers / total of questions
percentage = 10 / 15
percentage = 2 / 3
percentage = 0.667
Now, we have to multiply the result by 100:
percentage = 0.667 x 100
percentage = 66.7%
Answer: 66.7%
Please solve equation for maximum and minimum
Answer:
17^(1/11), which occurs at x=9
Step-by-step explanation:
To find the Absolute Extrema in a set of points, you need to evaluate (plug in) the endpoints, and maxima/minima of the equations and figure out the greatest and lowest ones.
1.) By using this method, the first step is to find the Relative Maximums/Minimums of these areas. We can do this by finding the derivative of the equation, and setting that equal to 0 and solving. [tex]\frac{d}{dx} (x^2-64)x^{\frac{1}{11}} = (x^2-64)^{-10/11} * 2x[/tex]. If we set this equal to 0, we will find that x = 0. Therefore, x=0 is a minimum. Since this point belongs to the interval of [-8, 9], we can use it.
2.) Plug the endpoints of the interval and the result from our calculations. If we do this, we get f(-8)=0, f(9) = 17^(1/11), f(0)=0
3.) Since we are finding the Maxima, we look for the greatest value, which is 17^(1/11), which occurs at x=9