Answer: 1.625
Step-by-step explanation:
13/8 = 1 5/8 = 1.625
Rebekah walks 10 miles in 3 hours. At what unit rate does Rebekahwalk?10/3 miles / 1 hour3 miles / 10 hoursООО10 miles / 3 hours3 hours / 10 miles
ANSWER
(10/3 miles) / (1 hour)
EXPLANATION
A unit rate is a rate where the denominator is 1. In this problem, the denominator is the time in hours. If Rebekah walks 10 miles in 3 hours, we have to find how many miles will she walk in 1 hour,
[tex]1hour\cdot\frac{10miles}{3hours}=\frac{10}{3}miles[/tex]She will run 10/3 miles in 1 hour. Hence the unit rate is (10/3 miles) / (1 hour).
-21x + 3 (-x-4) - 8x
Answer:
Step-by-step explanation:
-21x + 3(-x-4) -8x =
-21x -3x -12 - 8x=
-32x -12=
-32x = 12
X= -3/8
4. A garden sells flowers in trays. Each tray has 11 flowers on it. If the garden sells 124 trays, how many flowers did the garden sell in all?
A garden sells flowers in trays
each tray has 11 flowers on it
mathematically,
1 tray = 11 flowers
if the garden now sells 124 trays, then how many flowers do we have
1 tray = 11 flowers
124 trays = x flowers
cross multiplication
x * 1 = 124 x 11
x = 1364 flowers
,the answer is 1364 flowers 11 flowers
if the garden now sells 124 trays, then how many flowe
At the local pizzeria, a slice of pizza costs $3.00. if there are eight slices in one pizza . how much would two whole pizzas cost?
Answer:
48 dollars
Step-by-step explanation:
3 x 8 = 24
24 x 2 = 48
Two whole pizzas will cost forty-eight dollars
Answer:
48 dollars
Step-by-step explanation:
because for each slice is 3 dollars and there is 8 slices in 1 pizza so 8*3=24 so for 1 whole pizza its 24 dollars and because we want 2 we multiply it by 2 so 24*2= 48 so for 2 whole pizzas it equals 48 dollars.
A easier way, in 2 pizzas there is a total of 16 slices so 16*3= 48
your gross income is 4520.00 your deductions are FICA (7.65%), federal tax withholding (11.75%), and state tax withholding (8.5%). Your fixed expenses are 30% of your realized income. You saved 5 months' worth in an emergency fund, placing 75% in a 60-day CD at a 5.25% APR and the rest in a regular savings account at a 3.8% APR. How much is the total interest earned between both accounts in 60 days?
The total interest earned between both accounts in 60 days is $92.01.
What is the interest?Given gross income = $4520/ month
Deductions = FICA+federal withholding + state with holding
Deductions = 7.65%+ 11.75%+8.5%= 27.9%
Total deductions = 27.9% of 4520= $1261.08
Net income = Gross income - Deductins = 4520-1261.08= $3258.92
Now 30 % of these are fixed expenses
Fixed expenses = 30% of 3258.92= $977.676
Amount left for month = 3258.92-977.676= $2281.244
5 months worth = 5*2281.244= $11406.22
Total money in the emergency fund = $11406.22
Since 75% in CD, amount imvested = 75% of 11406.22= 8554.665
APR= 5.25%
Number of days = 60
A= P*(1+r) ^n
Assuming they compound daily
r= 0.0525/365= 0.0001438
n= 60
A= 8554.665*(1+0.0001448) ^60
A= $8628.81
Regular savings:
25% in RS, Amount invested = 25% of 11406.22= 2851.55
APR= 3.8%
Number of days = 60
A= P*(1+r) ^n
Assuming they compound daily
r= 0.038/365= 0.0001041
n= 60
A= 2851.55*(1+0.0001041) ^60
A= $2869.42
Total interest earned = (2869.42+8628.81) -11406. l22
= $92.01
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There are two numbers that
multiply to 45 and combine to 18. Find
the two numbers, then the SMALLER
number is your answer for this question.
Answer: 3 x 15= 45, 3 + 15= 18, 3 is the smaller number
Step-by-step explanation:
1st find the factors of 45 then find which factors add to 18
Make g the subject
X = 3g + 2
Answer:
g = X - 2/3
Step-by-step explanation:
X = 3g + 2
Try to make g stand alone and collect the terms.
X - 2 = 3g
Divide both sides by the coefficient of g, which is 3
X - 2/3 = 3g/3
g = X - 2/3
I just need to answer I'm trying to verify question
You have the following system of equations:
x + 3y = 1
y = 2x + 5
in order to solve the previous system, replace the expression y = 2x + 5, into the first equation and solve for x, as follow:
x + 3y = 1
x + 3(2x + 5) = 1 apply distribution property
x + 6x + 15 = 1 simplify lef side
7x + 15 = 1 subtrac 15 both sides
7x = 1 - 15
7x = -14 divide by 2 both sides
x = -14/2
x = -7
replace the previous value of x into the second equation to get y:
y = 2x + 5
y = 2(-7) + 5
y = -14 + 5
y = -9
Hence, the solution to the given system of equations is:
x = -7
y = -9
(-7 , -9)
What is 275 = 5 (1 - 6k)
Answer:k=-9
Step-by-step explanation:
275=5(1-6k)
55=1-6k
54=-6k
-9=k
which of the following could be the distant of Allyson's map
The real distance from Mumbai to Bangalore is 845 km.
The real distance from Mumbai to Dehli is 1160 km.
Allyson has made a map in which distance is in cm and is proportional to the real distance.
Since the real distance and the distance on the map are proportional then their ratio must be equal.
Let us compare the ratio of real distance with the distance in given options.
Option A:
Bangalore to Mumbai = 116.5 cm
Mumbai to Dehli = 174 cm
[tex]\begin{gathered} \frac{845}{1160}=\frac{116.5}{174} \\ 0.728\ne0.669 \end{gathered}[/tex]As you can see, the ratio is not equal so this is wrong.
Option B:
Bangalore to Mumbai = 42.25 cm
Mumbai to Dehli = 58 cm
[tex]\begin{gathered} \frac{845}{1160}=\frac{42.25}{58} \\ 0.728=0.728 \end{gathered}[/tex]As you can see, the ratio is equal so this is correct.
Option C:
Bangalore to Mumbai = 23.4 cm
Mumbai to Dehli = 29 cm
[tex]\begin{gathered} \frac{845}{1160}=\frac{23.4}{29} \\ 0.728\ne0.807 \end{gathered}[/tex]As you can see, the ratio is not equal so this is wrong.
Option D:
Bangalore to Mumbai = 16.9 cm
Mumbai to Dehli = 23.2 cm
[tex]\begin{gathered} \frac{845}{1160}=\frac{16.9}{23.2} \\ 0.728=0.728 \end{gathered}[/tex]As you can see, the ratio is equal so this is correct.
Option E:
Bangalore to Mumbai = 25.35 cm
Mumbai to Dehli = 34.8 cm
[tex]\begin{gathered} \frac{845}{1160}=\frac{25.35}{34.8} \\ 0.728=0.728 \end{gathered}[/tex]As you can see, the ratio is equal so this is correct.
Therefore, the following can be the possible distances on Allyson's map
Option B
Option D
Option E
may you please help me! Whether you can help or not I hope you are doing amazing!!the instructions at the top fully say " use the compass and straightedge to construct a segment congruent to WX with endpoint P."
Step Guide:
Step 1: Place your compass at W and extend it to X.
Step 2: Using the same length, place your compass at P and mark an arc.
Step 3: Using the straightedge, draw a line from P to meet the arc.
Step 4: Label the point of intersection of the line and the curve Q.
This gives segment PQ that is congruent to WX,
19) Given that f(x)x² - 8x+ 15x² - 25find the horizontal and vertical asymptotes using the limits of the function.A) No Vertical or Horizontal asymptotesB) No Vertical asymptotesHorizontal asymptote aty - 1Vertical asymptote at x = 5Horizontal asymptote at y = 1D) Vertical asymptote at x = -5Horizontal asymptote at y = 1
EXPLANATION
Since we have the function:
[tex]f(x)=\frac{x^2-8x+15}{x^2}[/tex]Vertical asymptotes:
[tex]For\:rational\:functions,\:the\:vertical\:asymptotes\:are\:the\:undefined\:points,\:also\:known\:as\:the\:zeros\:of\:the\:denominator,\:of\:the\:simplified\:function.[/tex]Taking the denominator and comparing to zero:
[tex]x+5=0[/tex]The following points are undefined:
[tex]x=-5[/tex]Therefore, the vertical asymptote is at x=-5
Horizontal asymptotes:
[tex]\mathrm{If\:denominator's\:degree\:>\:numerator's\:degree,\:the\:horizontal\:asymptote\:is\:the\:x-axis:}\:y=0.[/tex][tex]If\:numerator's\:degree\:=\:1\:+\:denominator's\:degree,\:the\:asymptote\:is\:a\:slant\:asymptote\:of\:the\:form:\:y=mx+b.[/tex][tex]If\:the\:degrees\:are\:equal,\:the\:asymptote\:is:\:y=\frac{numerator's\:leading\:coefficient}{denominator's\:leading\:coefficient}[/tex][tex]\mathrm{If\:numerator's\:degree\:>\:1\:+\:denominator's\:degree,\:there\:is\:no\:horizontal\:asymptote.}[/tex][tex]\mathrm{The\:degree\:of\:the\:numerator}=1.\:\mathrm{The\:degree\:of\:the\:denominator}=1[/tex][tex]\mathrm{The\:degrees\:are\:equal,\:the\:asymptote\:is:}\:y=\frac{\mathrm{numerator's\:leading\:coefficient}}{\mathrm{denominator's\:leading\:coefficient}}[/tex][tex]\mathrm{Numerator's\:leading\:coefficient}=1,\:\mathrm{Denominator's\:leading\:coefficient}=1[/tex][tex]y=\frac{1}{1}[/tex][tex]\mathrm{The\:horizontal\:asymptote\:is:}[/tex][tex]y=1[/tex]In conclusion:
[tex]\mathrm{Vertical}\text{ asymptotes}:\:x=-5,\:\mathrm{Horizontal}\text{ asymptotes}:\:y=1[/tex]help pleaseee !!
thank you !!!!!
The value of x for the given figure is 7.
According to the question,
We have the following information:
We have a figure where two parallel lines are cut by another line. Some of the measurements of angles are given.
Now, we know that angle made on a straight line is 180°.
So, we have the following expression:
∠4+118 = 180
∠4 = 180-118
∠4 = 62°
Now, we know that alternate interior opposite angles are equal. In this case, ∠4 and (8x+6) are alternate interior opposite angles.
(8x+6) = m∠4
8x+6 = 62
Subtracting 6 from both the sides:
8x = 62-6
8x = 56
x = 56/8
x = 7
Hence, the value of x for the given figure is 7.
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Factor the trinomial completely.3x2 - 13x - 10
3x2 - 13x - 10
multiplying the first and third terms we have
-30x2
The factors of -30 that will be added to get - 13 are -15 and 2
so we split the expression further
= 3x2 - 15x + 2x - 10
= 3x (x - 5) + 2 (x - 5)
= (x -5)(3x + 2)
Julia works for a company selling light bulbs. She sells fluorescent light bulbs for $5 a piece and incandescent light bulbs for $2. To meet her quota, she needs to sell over 100 light bulbs and make at least $350.If the solution region is the amount of light bulbs Julia needs to sell to meet her quota, which graph's shaded area represents the solution region?
Given:
Julia works for a company selling light bulbs. She sells fluorescent light bulbs for $5 a piece and incandescent light bulbs for $2.
Let the number of the fluorescent light bulbs = y
And the number of the incandescent light bulbs = x
To meet her quota, she needs to sell over 100 light bulbs and make at least $350.
So, we can write the following system of inequalities:
[tex]\begin{gathered} x+y>100 \\ 2x+5y\ge350 \end{gathered}[/tex]Now, we will graph the system of the inequalities to find the area of the solution
The graph will be as follows:
So, the answer will be the graph that is on the upper right-side.
Graph x
Which equations represent a linear function? Select two. a. y = x-1 b. y = – 4.5 C. 3x – 4y = 2 d. 5x2 = 10y e. y = 1/2x2 +6
Explanation
a linear function must have
dependent and independent variables, ( y and x in this case)and the exponent of the independent vairable must be 1, so
Step 1
Check
a)
[tex]a)\text{ y=x-1}[/tex]this is a linear function
b)
[tex]y=4.5[/tex]this is not a functin, this expression has not x
c)
[tex]3x-4y=2[/tex]this functin has x and y, and the exponent of x is 1, so, this is a linear function
d)
[tex]5x^2=10y[/tex]this function has x and y, but the exponent is 2, so this is not a linear function
e)
[tex]y=\frac{1}{2}x^2+6[/tex]this function has x and y, but the exponent is 2, so this is not a linear function
i hope this helps you
Sketch a graph of the polynomial function f(x) = –x3 + 5x2 – 2x – 8. Use the graph to complete the following:f is __________ on the intervals (–∞, 1/3) and (3, ∞)f is __________ on the interval (1/3, 3)f is __________ on the intervals (–∞, -1) and (2, 4)
To sketch the graph, we need to find the x-intercepts and y-intercepts.
To find the x-intercepts we solve the equation when y = 0.
That is
[tex]-x^3+5x^2-2x-8=0[/tex][tex]\begin{gathered} f(-1)=-(-1)^3+5(-1)^2-2(-1)-8=1+5+2-8=0 \\ \text{Hence} \\ x=-1\text{ is a zero of f(x)} \\ \Rightarrow\text{ x+1 is a factor of f(x)} \end{gathered}[/tex]Next, we find the result of :
[tex]\frac{f(x)}{x+1}[/tex][tex]\begin{gathered} So \\ \frac{-x^3+5x^2-2x-8}{x+1}=-x^2+6x-8 \end{gathered}[/tex]Now we solve
[tex]\begin{gathered} -x^2+6x-8=0 \\ \Rightarrow-x^2+2x+4x-8=0 \\ \Rightarrow-x(x-2)+4(x-2)=0 \\ \Rightarrow(4-x)(x-2)=0 \\ \Rightarrow x=4\text{ or 2} \end{gathered}[/tex]So the zeros of f(x) are -1, 2, and 4
Next, we find the stationary points.
[tex]\begin{gathered} \frac{df(x)}{dx}=-3x^2+10x-2 \\ \text{When }\frac{df(x)}{dx}=0,\text{ we have} \end{gathered}[/tex][tex]\begin{gathered} -3x^2+10x-2=0 \\ \text{Dividing through by -3 we have} \\ x^2-\frac{10}{3}x+\frac{2}{3}=0 \end{gathered}[/tex][tex]\begin{gathered} (x-\frac{5}{3})^2-(-\frac{5}{3})^2-2=0 \\ \Rightarrow(x-\frac{5}{3})^2=2+\frac{25}{9}=\frac{43}{9} \\ \Rightarrow x=\frac{5\pm\sqrt[]{43}}{3} \\ \Rightarrow x=2.55\text{ or }0.78 \end{gathered}[/tex][tex]\frac{d\frac{df(x)}{dx}}{dx}=-6x+10[/tex]At x = 2.55
[tex]\frac{d\frac{df(x)}{dx}}{dx}=-6(2.55)+10=-5.3<0[/tex]Hence we have a maximum point at x = 2.55
[tex]\frac{d\frac{df(x)}{dx}}{dx}=-6(0.78)+10=5.32>0[/tex]Hence, there is a minimum point at x = 0.78
[tex]\begin{gathered} f(0.78)\text{ = }-6.99 \\ f(2.550=2.83 \end{gathered}[/tex][tex]\begin{gathered} To\text{ check the intervals where the function increasing or decreasing} \\ \text{For x < 0.78 } \\ \frac{df(x)}{dx}=(x-0.78)(x-2.83)\text{ is positive} \\ \text{For 0.78 < x < 2.83 } \\ \frac{df(x)}{dx}=(x-0.78)(x-2.83)\text{ is negative} \\ \text{For x > 2.83} \\ \frac{df(x)}{dx}=(x-0.78)(x-2.83)\text{ is positive} \end{gathered}[/tex]This implies that
f is increasing on the intervals (–∞, 1/3) and (3, ∞)
find the area of 2 1/2 units * 2 units
Answer:
5 square units
Explanation:
Emma's Rectangle is:
• 2½ units long.
,• 2 units wide.
[tex]\begin{gathered} \text{Area}=2\frac{1}{2}\times2 \\ =\frac{5}{2}\times2 \\ =5\text{ units}^2 \end{gathered}[/tex]Answer: its 5
Step-by-step explanation:
You pick a card at random without putting the 1st card back you pick a second card at random what is the probability of picking a 7 and then picking a 7
Given:
There are four cards numbered as
[tex]6,\text{ }7,\text{ }8,\text{ and }9.[/tex]Required:
We have to find the probability of picking a 7 and then picking a 7.
Explanation:
When you pick the first card there are four possibilities out of which only one card is numbered as 7.
Therefore, the probability of picking a 7 is
[tex]\frac{1}{4}[/tex]Before picking the second card you have put back the first card. So when you pick the second card there are four possibilities out of which only one card is numbered as 7.
Therefore, the probability of picking a 7 is
[tex]\frac{1}{4}[/tex]Hence the probability of picking a 7 and then picking a 7 is
[tex]\frac{1}{4}\times\frac{1}{4}=\frac{1}{16}[/tex]Final answer:
Hence the final answer is
[tex]\frac{1}{16}[/tex]
PLS HELP ME ASAP!! I WILL GIVE U BRAINLYEST!! NO LINKS!Frankie worked at the gas station for four months. He earned $4,800.00 andmust pay a total of 12% in income taxes. What is his net pay if there are noadditional deductions? A. 576.00B.5,376.00C.3,600.00D.4,224.00
Frankie worked at the gas station for four months. He earned $4,800.00 and
must pay a total of 12% in income taxes. What is his net pay if there are no
additional deductions?
A. 576.00
B.5,376.00
C.3,600.00
D.4,224.00
we have that
12%=12/100=0.12
Multiply $4,800.00 by 0.12
$4,800.00*0.12=$576.00
answer is option AA basket contains 5 pieces of paper numbered from 1 to 5. A hat contains the letters A, B, C and D. If a blindfolded person picks a number and then a letter, what is the probability that the number is greater than 3 AND the letter is C?
We have a basket and a hat.
The basket has the numbers 1, 2, 3, 4 and 5.
The hat contains the letters A, B, C and D.
We have to calculate the probabiltiy of drawing a number that is greater than 3 from the basket and drawing the letter C from the hat.
We have two events:
- Drawing a number greater than 3 from the basket
- Drawing a C from the hat
They are independent as the probability of each on does not depend on the outcome of the other event.
Then, we can calculate the probability of the two events happening together as the product of its probabilities:
[tex]P(n>3&l=C)=P(n>3)\cdot P(l=C)[/tex]The probability of drawing a number greater than 3 can be described as 2/5, as we have 2 numbers greater than 3 (4 and 5) out of 5 numbers in the basket.
The probability of drawing a letter C can be described as 1/4, as we have one letter C out of 4 letters available.
Then, we can calculate the probability as:
[tex]\begin{gathered} P(n>3&l=C)=P(n>3)\cdot P(l=C) \\ P(n>3&l=C)=\frac{2}{5}\cdot\frac{1}{4}=\frac{2}{20}=\frac{1}{10} \end{gathered}[/tex]Answer: the probability is 1/10 or 0.1.
9. Use the Distributive Property to solve the
equation 28-(3x+4)= 2(x+6) +x.
WITH SOLUTION please
Answer:
x=2
Step-by-step explanation:
T= 2
28 - (3æ+4) = 2(r + 6) + *
We need to use the distributive property for the
right side.
28 - 3z -4 = 2a + 12 + z
28 -3z -4 = (2) (æ) + (2)(6) + æ)
From here we need to subtract 3æ from both side.
-3æ + 24 -3 = 3æ + 12 – 3¢
3æ + 24 = 3z + 12
6z + 24 = 12
Transfer +24 on the right side. (P.S. don't forget to
change the sign)
62 = 12 - 24
6 = - 12
Finally, divide both sides by -6
6x/-6 = -13/-6
x=2
I hope I helped you
11. What are the zeros for the following quadratic relation: *
y = 5x² - 1125
O x = 0
O x = 5,15
O x= -15,5
O x=-15, 15
Answer:
x=15,-15
Step-by-step explanation:
5x^2-1125=0
5x^2=1125
x^2=225
x=square root of 225
x=+15 or -15
Don Williams wised his small motorboat to go 5 miles upstream to his favorite fishing spot. Against the current, the trip takes 5/6 hour. With the current the trip takes 1/2 hour. How fast can the boat travel in still water ? What is the speed of the current in still water the boat speed is __ mph. The speed of the current is ___ mph
let s = speed in still water
let c = rate of the current
then
(s-c) = effective speed up-stream
and
(s+c) = effective speed down-stream
Write a distance equation for each way; dist = time * speed
5/6*(s-c) = 5
1/2 *(s+c) = 5
Now we get rid of the fractions
5(s-c)=30
s + c = 10
5s - 5c = 30
s + c = 10
siplifying:
s - c = 6 (1)
s + c = 10 (2)
adding:
2s = 16, then s = 8
8 mph is the boat speed in still water
According with (2):
8 + c = 10, then c = 2
2 mph is the speed of the current
Solve the equation 5.9g + 4 = 3.9g + 12.
Rearranging an equation:
isolating for a variable (g)merge like terms and solveuse inverse operations[tex]5.9g+4=3.9g+12[/tex]
[tex]5.9g-3.9g=12-4[/tex]
[tex]2g= 8[/tex]
[tex]\frac{2g}{2} = \frac{8}{2}[/tex]
[tex]g = 4[/tex]
g = 4
Answer:
g=4
Step-by-step explanation:
5.9g+4=3.9g+12
-4 -4
5.9g= 3.9g+8
-3.9g -3.9g
2g=8
/2 /2
g=4
Please help meeeeeeeeeee
Answer:
Okay
Step-by-step explanation:
want me to come over to your place
where can I find L1 and L4 ? for missing alternate angles
< 1 = 113.1 degrees
< 4 = 66.9 degrees
Explanation:Alternate interior angles are equal
< 1 = < 3 = 113.1 degrees
< 2 = < 4 = 66.9 degrees
Javier biked 4 miles on Tuesday, 2 miles on Wednesday , and 7 miles on Saturday . if he hopes to bikes a total of 30 miles for the week , how many miles should Javier bike on Sunday
Answer:
Step-by-step explanation:
4 miles plus 2 miles equals 6 miles, then you add 7 miles to the 6 which equals 13, lastly you minus 13 from 30 then you get your answer, which is 17.
This pyramid has the same base as the prism and its height is three times the height of the prism. What is the ratio of the volume of thepyramid to the volume of the prism?1A} volume of Pyramidvolume of priamB} volume of pyramidvolume of priuamC} volume of pyramidvolume of priimD} Volume of pyramidvolume of priem
This pyramid has the same base as the prism and its height is three times the height of the prism. What is the ratio of the volume of the
pyramid to the volume of the prism?
1
A} volume of Pyramid
volume of priam
B} volume of pyramid
volume of priuam
C} volume of pyramid
volume of priim
D} Volume of pyramid
volume of
prime
____________________________________________
volume of the prism
#11 i
Solve 7w-9=13 - 4w.
W =
Answer:
w=2
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
7w−9=13−4w
7w+−9=13+−4w
7w−9=−4w+13
Step 2: Add 4w to both sides.
7w−9+4w=−4w+13+4w
11w−9=13
Step 3: Add 9 to both sides.
11w−9+9=13+9
11w=22
Step 4: Divide both sides by 11.
11w/11=22/11
w=2