Parker offers to pay for 5 of his friends to play laser tag, but 3 of them don't want to play. If laser tag costs $6 per person, how much will Parker spend on his friends? Choose the correct expression and solution to this problem. O A. The expression is 5(6 - 3). Parker will spend $10. B. The expression is 6.5 - 3. Parker will spend $27
Answers
Expression: 6 (5-3) (option C)
Parker will spend $12
Explanation:
number of friends = 5
number of friends that don't play laser tag = 3
The cost of laser tag per person = $6
Amount Parker spend on his friends = 6 (5-3)
Expression: 6 (5-3)
Amount Parker spend on his friends = 6 (5-3) = 6(2)
Parker will spend $12
Related Questions
What is the approximate area of the shaded region? 6 5 3 a 2 1 X 0 1 2 3 4 5 6 O A. 3 units? B. 6 units c. 10 units D. 13 units
Answers
Area aof shaded region is
Difference of areas between square, and circle
Area of square is = (5-1)^2 = 16
Area of circle is = π•[(5-1)/2]^2 = π•2^2 = π•4
Shaded Area = 16 - (π•4) = 16 - 12.564 = 3.436
THEN option A , is the value most aproximate to 3.436
Piper works at a camera store. He is paid an hourly rate plus 16% commission on everything he sells. One week, he was paid $515 for working 20 hours and selling $1,500 worth of camera equipment. What is his hourly rate?
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His hourly rate is $13.75
Here, we want to get Piper's hourly pay at work
Let the hourly rate be h
Thus, for working 20 hours, the amount for this will be; 20 * h = 20h
Now, out of the $1500 sales, he is entitled to 16%
That means;
[tex]\frac{16}{100}\times\text{ 1500 = 240}[/tex]Thus, we have it that;
[tex]\begin{gathered} 20h\text{ + 240 = 515} \\ 20h\text{ = 515-240} \\ 20h\text{ = 275} \\ h\text{ = }\frac{275}{20} \\ h\text{ = \$13.75} \end{gathered}[/tex]What type of angle is shown on the protractor below?
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Given data:
The given angle .
The given angle AOB is an obtuse angle.
Thus, third option is correct.
based on the graph which equation can be used to describe the relationship between x and y?
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hello
to solve this problem, we can easily find the slope of the line
this will give us the an insight to the answer
[tex]\text{slope(m)}=\frac{y_2-y_1}{x_2-x_1}[/tex]now let's identify our points
[tex]\begin{gathered} y_2=2 \\ y_1=-4.5 \\ x_2=-13.5 \\ x_1=6 \end{gathered}[/tex][tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{2--4.5}{-13.5-6} \\ m=\frac{6.5}{-19.5} \\ m=-\frac{1}{3} \end{gathered}[/tex]the slope of the line is -1/3 and this corresponds to option B
the equation of the line is given as
[tex]y=-\frac{1}{3}x-2.5[/tex]Lynn is tracking the progress of her plant's growth. The plant is already 8 centimeters high. The plant grows 1.5 centimeters per day. Which function shows this relationship? y=8x+1.5y=1.5x+8y=9.5x
Answers
Given the information, we know that the plant is already 8 centimeters, therefore that would be our intercept with the y-axis (i.e. b = 8). Now, to find the slope, we have that on the first day the plant grows 1.5 centimeters, therefore for day 1, the plant is 9.5 centimeters high. With this observations we have the following:
[tex]\begin{gathered} \text{Given (0,8) and (1,9.5)} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ \Rightarrow m=\frac{9.5-8}{1-0}=1.5 \\ m=1.5 \end{gathered}[/tex]Using the formula y=mx+b, we obtain the desired function:
[tex]\begin{gathered} y=mx+b \\ \Rightarrow y=1.5x+8 \end{gathered}[/tex]Therefore, the function that shows the relationship is y=1.5x+8
e inverse operations to solve the equations below. x^2+3=19
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We have the expression:
[tex]x^2+3=19\Rightarrow x^2=16[/tex][tex]\Rightarrow x=\pm4[/tex]You are performing a left-tailed test with test statistic z = -2.329, find the p-value accurate to 4
decimal places.
p-value =
Answers
The p-value is 0.00993
What is critical value ?
The distribution's critical values are the points that have the same probability as your test statistic and are equal to the significance level. It is considered that these values are at least as extreme as those essential values.
The points with the property that the area under the density curve of the test statistic from those points to the tails is equal to can be readily represented as critical values:
Left-tailed test: The critical value to the left of the area under the density curve is equal to ;
Right-tailed test: The density curve's area under the right side of the critical value equals ; and
Two-tailed test: The total area is equal to since the area under the density curve from the left critical value to the left is equal to ∝/2 and the area under the curve from the right critical value to the right is equal to ∝/2 as well.
When z = -2.329
After left-tailed test the p-value from the graph is 0.00993
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Solve the system of linear equations using the graphing method. Use “no solution” and “infinitely many” when appropriate.
Answers
Given the system of equations:
[tex]\begin{gathered} y=\frac{1}{2}x+2 \\ \\ y=\frac{1}{2}x+1 \end{gathered}[/tex]Let's solve the system using graphing method.
Let's plot both equations on a graph. The point where both lines meet.
• Equation 1:
Let's plot using 3 points.
Substitute random values of x and solve for y.
We have:
[tex]\begin{gathered} x=-4;\text{ y = }\frac{1}{2}(-4)+2=-2+2=0 \\ \\ x=0;y=\frac{1}{2}(0)+2=0+2=2 \\ \\ x=4;y=\frac{1}{2}(4)+2=2+2=4 \end{gathered}[/tex]For equation 1, we have the points:
(x, y) ==> (-4, 0), (0, 2), (4, 4)
Plot the points and connect the points with a straight line.
• Equation 2:
Let's create 3 points:
[tex]\begin{gathered} x=-2;y=\frac{1}{2}(-2)+1=-1+1=0 \\ \\ x=0;y=\frac{1}{2}(0)+1=0+1=1 \\ \\ x=2;y=\frac{1}{2}(2)+1=1+1=2 \end{gathered}[/tex]FOr equation 2, we have the points:
(x, y) ==> (-2, 0), (0, 1), (2, 2)
Now, plot the points and connect using a straight line.
We have the graph of both equations below:
From the graph, we can see that both lines do not meet at any point.
They are parallel lines,
Since they will not meet at any point, there is NO SOLUTION.
ANSWER:
No solution.
Can you help me please? If there is a solution what’s the solution as well
Answers
Solution:
Given;
[tex]-7y^2+7y+1=0[/tex]Where;
[tex]a=-7,b=7,c=1[/tex]Thus;
[tex]\begin{gathered} b^2-4ac=7^2-4(-7)(1) \\ \\ b^2-4ac>0 \end{gathered}[/tex]Hence, the quadratic equation has two different real solutions.
Then;
[tex]\begin{gathered} y=\frac{-7\pm\sqrt{7^2-4(-7)(1)}}{2(-7)} \\ \\ y=1.13,y=-0.13 \end{gathered}[/tex]Given triangle ABC below, if angle B=(x-60)^ and angle C=(x- 45)^ find the measure of angle x
Answers
Given:
m∠B = (x - 60)°
m∠C = (x - 45)°
Opposite angle = x°
Let's find the measure of angle x.
To find the measure of angle x, apply the Exterior Angle Theorem which states that the exterior angle of a triangle is equal to the sum of the two opposite angles.
Thus, we have:
∠B + ∠C = x
(x - 60) + (x - 45) = x
Solve for x.
• Remove the parentheses and combine like terms:
x - 60 + x - 45 = x
x + x - 60 - 45 = x
2x - 105 = x
• Move all terms containing x to the left, then move 105 to the right
2x - x = 105
x = 105°
Therefore, the measure of angle x is 105°
ANSWER:
x = 105°
Oh no! You have just discovered Superhero C is actually a villain! He plans toactivate an underwater volcano that is 50 miles away. Superhero A is goingto try to stop him.Suppose getting to the underwater volcano requires a combination ofrunning, flying, and swimming.Using the rates from Table 1, make a plan for how far each Superheroshould run, fly, and swim to make sure that Superhero A gets to the volcanobefore Superhero C and can save the world.Note: You must use all three modes of travel.
Answers
SOLUTION:
First, let's calculate for superhero C the villian.
Using the three modes of travelling,
He needs to cover a distance of 50 miles
If he:
i. Runs
1 mile in 2 minutes, Hence
50 miles will be in 100 minutes
ii) Flys
2 miles in 2 minutes, Hence
50 miles will be in 50 minutes
iii) Swims
4 miles in 3 minutes, Hence
50 miles will be in 37.5 minutes
Next, let's calculate for superhero A.
Using the three modes of traveling,
He needs to cover a distance of 50 miles
If he:
i. Runs
4 miles in 1 minute, Hence
50 miles will be in 12.5 minutes
ii) Flys
4 miles in 4 minutes, Hence
50 miles will be in 50 minutes
iii) Swims
3 miles in 1 minute, Hence
50 miles will be in 16.67 minutes.
Finally, let's calculate for superhero B.
Using the three modes of traveling,
He needs to cover a distance of 50 miles
If he:
i. Runs
5 miles in 1 minute, Hence
50 miles will be in 10 minutes
ii) Flys
7 miles in 2 minutes, Hence
50 miles will be in 14.29 minutes
iii) Swims
10 miles in 3 minutes, Hence
50 miles will be in 15 minutes.
what is the name of the geometric figure that begins at a point and is a set of all points that make a never-ending straight path extending in only one direction?
Answers
hi.
to start this exercise, let's remember some definitions about the alternatives:
a. ray
distance between the center of the circle and a point on its circumference (one straight line)
b. vertex
is a point where two edges meet
c. angle
is formed by two semi-straights that come from the same origin
d. opposite rays
is the same definition of radius, only now it considers two rays: one and its opposite. joining a radius to its opposite, we get a straight line.
Three support beams for a bridge form a pair of complementary angles. Find the measure of each angle.(2x - 20)INNISmaller angle:Larger angle:O0UNSFANA(4x - 10)
Answers
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Define complementary angles
When the sum of two angles is 90°, then the angles are known as complementary angles.
STEP 2: Write the pairs of the angles formed
[tex]\begin{gathered} (2x-20)\degree \\ (4x-10)\degree \end{gathered}[/tex]STEP 3: find the value of x
Following the definition in step 1, this goes that;
[tex]\begin{gathered} (2x-20)+(4x-10)=90\degree \\ 2x-20+4x-10=90\degree \\ 6x-30=90 \\ 6x=90+30 \\ 6x=120 \\ x=\frac{120}{6}=20 \end{gathered}[/tex]STEP 4: Find the two pair of angles
[tex]\begin{gathered} (2x-20)=2(20)-20=40-20=20\degree \\ 4x-10=4(20)-10=80-10=70\degree \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} smaller\text{ }angle=20\degree \\ Larger\text{ }angle=70\degree \end{gathered}[/tex]Evaluate the expression (-4-4i) +(-8-11) and write the result in the form a + bi.The real number a equalsThe real number b equals
Answers
The answer is supposed to be in the form
[tex]a+bi[/tex]Therefore,
[tex](-4-4i)+(-8-1i)[/tex][tex]\begin{gathered} -4-4i-8-1i \\ \end{gathered}[/tex]combine like terms
[tex]-4-8-4i-1i[/tex]Finally,
[tex]-12-5i[/tex]a = -12
b = -5
What is the measure of the 5x+25
Answers
As you can see:
RM+MT = RT
Where:
RM = 5x + 9
MT = 8x - 6
RT = 198
Replacing the data:
5x + 9 + 8x - 6 = 198
Add like terms:
(5x + 8x) + (9 - 6) = 198
13x + 3 = 198
Solve for x:
Subtract 3 from both sides:
13x + 3 - 3 = 198 - 3
13x = 195
Divide both sides by 13:
13x/13 = 195/13
x = 15
Find the scale factor of the two prisms, the ratio of their surface areas, and the ratio of theirvolumes. List the larger values first.6 cm8 cm9 cm10 cm12 cm15 cmScale FactorSurface AreasVolumesBlank 1:Blank 2:Blank 3:Blank 4:Blank 5:Blank 6:
Answers
We will operate as follows:
*Scale factor:
We determine the scale factor using two respective sides, that is:
[tex]9x=6\Rightarrow x=\frac{6}{9}\Rightarrow x=\frac{2}{3}[/tex]So, the scale factor is 2 : 3.
*Surface area:
We determine the surface are of each prism:
[tex]S_{A1}=(9\cdot12)+2(\frac{15\cdot9}{2})+(12\cdot\sqrt[]{15^2+9^2})+(15\cdot12)\Rightarrow S_{A1}=(108)+(135)+(36\sqrt[]{34})+(180)[/tex][tex]\Rightarrow S_{A1}=423+36\sqrt[]{34}\Rightarrow S_{A1}=632.9142682\ldots[/tex][tex]S_{A2}=(6\cdot8)+2(\frac{6\cdot10}{2})+(10\cdot8)+(8\cdot\sqrt[]{6^2+10^2})\Rightarrow S_{A2}=(48)+(60)+(80)+(16\sqrt[]{34})[/tex][tex]\Rightarrow S_{A2}=188+16\sqrt[]{34}\Rightarrow S_{A2}=281.2952303\ldots[/tex]Now:
[tex](423+36\sqrt[]{34})x=188+16\sqrt[]{34}\Rightarrow x=\frac{188+16\sqrt[]{34}}{423+36\sqrt[]{34}}\Rightarrow x=\frac{4}{9}[/tex]So, the ratio of the surface areas is 4 : 9.
*Volume:
We determine the volume of each prism and proceed as before:
[tex]V_1=\frac{9\cdot15\cdot12}{2}\Rightarrow V_1=810[/tex][tex]V_2=\frac{6\cdot10\cdot8}{2}\Rightarrow V_2=240[/tex]Now:
[tex]810x=240\Rightarrow x=\frac{240}{810}\Rightarrow x=\frac{8}{27}[/tex]So, the ratio for the volumes is 8 : 27.
homework practice what is the 5th term of this sequence?
Answers
Nancy bought a pack of 10 cookies for her 3 children to share equally. How many cookies should each child get if the cookies are shared equally between the 3 children?
Answers
Given:
Total pack is 10.
Share divied in 3 children.
So each children share is:
[tex]\begin{gathered} 3\text{ total share is 10} \\ for\text{ each share}=\frac{10}{3} \\ =3.33 \end{gathered}[/tex]each children share is 3.33 cookies.
Delta Airlines' flights from Chicago to Atlanta are on time 80 % of the time. Suppose 14 flights are randomly selected, and the number on-time flights is recorded.1.The probability that at least 9 flights are on time is =2.The probability that at most 2 flights are on time is =3.The probability that exactly 10 flights are on time is =
Answers
Hello there. To solve this question, we'll have to remember some properties about probabilities.
Given that 14 flights are randomly selected from the record list and that the flights from Chicago to Atlanta are on time 80% of the time, we have to determine:
a) The probability that at least 9 flights are on time
If we choose a flight randomly out of the 14 and 80% of the time it is on time (success), then we can use the binomial theorem for probability:
[tex]\binom{n}{x}p^x(1-p)^{n-x}[/tex]Where p is the probability of success and x is the number of times we want to check.
In this case, let p = 80% or 0.8, n = 14, such that
[tex]\binom{14}{x}0.8^x\cdot0.2^{14-x}[/tex]To find the probability that at least 9 flights are on time, we calculate the probability that at least 5 are not on time. That is, we make
[tex]\begin{gathered} 14-x=5 \\ x=9 \end{gathered}[/tex]Thus
[tex]\binom{14}{9}0.8^9\cdot0.2^5=\frac{14!}{9!\cdot(14-9)!}\cdot0.8^9\cdot0.2^5\approx0.086[/tex]In fact, we have to sum all of the contributions as follows:
[tex]\sum ^{14}_{x=9}\binom{14}{x}0.8^x\cdot0.2^{14-x}[/tex]And we get:
[tex]\approx0.956[/tex]In other words, the probability that at least 9 flights are on time is 95.6%
b) The probability that at most 2 flights are on time
For this, we need to find the probability that at least 13 flights are not on time, such that
[tex]undefined[/tex]7. Write an equation that results when f(x) = 5^xhas been transformed by:a. Shifted to the left 2 and up 3b. Shifted right 3 and down 1
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The given function is:
[tex]undefined[/tex]I need help on this equationTo simplify each and state the excluded value.
Answers
To answer this question, we need to factor each of the polynomials as follows:
First Polynomial
[tex]x^2+4x+3[/tex]To factor it, we need to find two numbers:
a*b = 3
a + b = 4
These numbers are:
a = 3
b = 1
Therefore, we have:
[tex]x^2+4x+3=(x+1)(x+3)[/tex]A painter charges $20 for every hour that he paints. Let h equal the number of hours he paints and e represent his earnings.Select TWO equations that represent the situation.A. e= 20hB. h=20+eC. 20=h+eD. 20=hxeE. e/h=20
Answers
The form of the linear equation is
[tex]y=mx+b[/tex]m is the rate of change
b is the initial amount
Since The painter charges $20 every hour, then
The rate is 20
m = 20
Since there is no initial amount of payment, then
b = 0
Since the number of hours is h, then
x = h
Since the earning is e, then
y = e
The equation is
[tex]e=20h[/tex]Then the first equation is A
Divide both sides by h
[tex]\begin{gathered} \frac{e}{h}=\frac{20h}{h} \\ \frac{e}{h}=20 \end{gathered}[/tex]The 2nd equation is E
The sequence below shows the number of trees that a nursery plants each year.2, 8, 32, 128 ...Let an represent the current term in the sequence and an-1 represent the previous term in thesequence. Which formula could be used to determine the number of trees the nursery will plantin year n?
Answers
According to the given sequence, the formula that could be used to determine the number of trees the nursery will plant in year n is [tex]a_{n}= 4a_{n-1}[/tex]. Thus, option (A) is correct.
The given sequence of the number of trees that a nursery plants each year is -
2, 8, 32, 128, .....
[tex]a_{n}[/tex] = The current term in the sequence
[tex]a_{n-1}[/tex] = The previous term in the sequence
We have to find out the formula that could be used to determine the number of trees that the nursery will plant in the year n.
From the sequence we can see that -
8 = 2*4
32 = 8*4
128 = 32*4
So, this can be said that the current term in the sequence ([tex]a_{n}[/tex]) is 4 times the previous term in the sequence ([tex]a_{n-1}[/tex]).
=> [tex]a_{n}= 4a_{n-1}[/tex]
Thus, according to the given sequence, the formula that could be used to determine the number of trees the nursery will plant in year n is
[tex]a_{n}= 4a_{n-1}[/tex]
Thus, option (A) is correct.
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Please help!! I keep getting crazy fractions for the one for equation of a line and for the other one I have no idea how to solve. I'll be eternally grateful!
Answers
We will find the equation of the line passes through the points:
[tex](\frac{5}{8},\frac{31}{16})and(-\frac{-5}{7},\frac{13}{14})[/tex]The general neral
Choose the graph that illustrates both g (x) andg (x+4)
Answers
Explanation:
If we have a function f(x) = g(x + c), we can say that f(x) is g(x) shifted c units to the left.
So, the graph of g(x + 4) will be the same graph of g(x) shifted 4 units to the left
Answer:
The only graph that has two functions and one if equal to the other shifted 4 units to the left is the following:
the paper didnt explain how to do this clearly could you take me step by step how to do this
Answers
Given data:
The given point is (2,-2).
The equation of the line is y= -2x+3.
The standard equation of the line is,
[tex]y=mx+c[/tex]Compare the given equation with the above equation.
[tex]m=-2[/tex]Two parallel lines have equal slope, the equation of the line parallel to the given line and passing through (2, -2) is,
[tex]\begin{gathered} y-(-2)=m(x-2) \\ y+2=-2(x-2) \\ y+2=-2x+4 \\ y=-2x+2 \end{gathered}[/tex]Thus, the equation of the line is y= -2x+2.
If h is the function given by h(x) = (f • g)(x) where f(x) = squareroot of x and g(x) =(sqrtx)^3, then h(x) =
Answers
Given;
[tex]\begin{gathered} f(x)=\sqrt[]{x} \\ g(x)=(\sqrt[]{x)}^3=x^{\frac{3}{2}} \\ (f\circ g)(x)=\sqrt[]{x^{\frac{3}{2}}} \\ h(x)=(f\circ g)(x)=x^{\frac{3}{4}} \end{gathered}[/tex]CORRECT OPTION: D
Please help will mark Brainly
Answers
Answer:
y = 4x + 3
Step-by-step explanation:
if you try plugging in the x on the table to the x in the equation you should get the answer under the column y to match up
What is the domain of the cubic function f(x)= 9x³ + 2x-12 ?
Answers
GIVEN:
We are given the function below;
[tex]f(x)=9x^3+2x-12[/tex]Required;
To find the domain of the cubic function.
Step-by-step solution/explanation;
The domain of a function is the set of all input values (that is, x values) for which the function is defined.
For the function given, there is no constraint, which means the function is always true for any value of x.
Therefore,
ANSWER:
[tex]Domain=(-\infty,+\infty)[/tex]The domain is the set of all real numbers.
Option B
Find the value of each variable in the parallelogram.5u – 10162u + 2V3U =0V=
Answers
The diagonals of a parallelogram bisect each other. It means the segments, after bisection, are equal to each other.
From the figure, we can write:
[tex]\begin{gathered} 2u+2=5u-10 \\ \text{and} \\ 6=\frac{v}{3} \end{gathered}[/tex]We can solve the first equation and get the value of u:
[tex]\begin{gathered} 2u+2=5u-10 \\ 2+10=5u-2u \\ 12=3u \\ u=\frac{12}{3} \\ u=4 \end{gathered}[/tex]Solving the second equation, we find the value of v:
[tex]\begin{gathered} 6=\frac{v}{3} \\ 6\times3=v \\ v=18 \end{gathered}[/tex]Answer:
u = 4v = 18