SOLUTION:
First, let's calculate for superhero C the villian.
Using the three modes of travelling,
He needs to cover a distance of 50 miles
If he:
i. Runs
1 mile in 2 minutes, Hence
50 miles will be in 100 minutes
ii) Flys
2 miles in 2 minutes, Hence
50 miles will be in 50 minutes
iii) Swims
4 miles in 3 minutes, Hence
50 miles will be in 37.5 minutes
Next, let's calculate for superhero A.
Using the three modes of traveling,
He needs to cover a distance of 50 miles
If he:
i. Runs
4 miles in 1 minute, Hence
50 miles will be in 12.5 minutes
ii) Flys
4 miles in 4 minutes, Hence
50 miles will be in 50 minutes
iii) Swims
3 miles in 1 minute, Hence
50 miles will be in 16.67 minutes.
Finally, let's calculate for superhero B.
Using the three modes of traveling,
He needs to cover a distance of 50 miles
If he:
i. Runs
5 miles in 1 minute, Hence
50 miles will be in 10 minutes
ii) Flys
7 miles in 2 minutes, Hence
50 miles will be in 14.29 minutes
iii) Swims
10 miles in 3 minutes, Hence
50 miles will be in 15 minutes.
Figure ABCDE is similar to figure VWXYZ.Solve for the side length of WX.a 1/2b. 3c. 2.5 d 2
In similar figures the ratio of corresponding sides is the same:
Corresponding sides in given figure:
AB and VW
BC and WX
CD and XY
DE and YZ
EA and ZV
As you know the length of AE and ZV and need to find the value of WX taht is correspondig side of BC, you have the next:
[tex]\frac{ZV}{EA}=\frac{WX}{BC}[/tex][tex]\frac{4}{10}=\frac{WX}{5}[/tex]You use this equation to find the length of WX:
[tex]\begin{gathered} \frac{5\cdot4}{10}=WX \\ \\ \frac{20}{10}=WX \\ \\ \\ WX=2 \end{gathered}[/tex]Then, the length of WX is 2Convert 77.6% to an
equivalent decimal.
Answer:
Step-by-step explanation:
0.776 in decimal form.
Is AABC= ADEF? If so, name the postulate that applies.AGiven:ŁAZDZBZE
Step 1:
Knowing only angle-angle-angle (AAA) does not work because it can produce similar but not congruent triangles.
Step 2:
If the three angles (AAA) are congruent between two triangles, that does NOT mean that the triangles have to be congruent.
Final answer
Option A
Might not be congruent.
write the equation of the line that is perpendicular to the graph of y=3/4x-3, and whose y-intercept is -8
write the equation of the line that is perpendicular to the graph of y=3/4x-3, and whose y-intercept is -8
step 1
Find the slope of the given line
y=(3/4)x-3
the slope is m=3/4
step 2
Find the slope of the perpendicular line
REmember that
If two lines are perpendicular, then the product of their slopes is equal to -1 (inverse reciprocal)
so
the slope of the perpendicular line is
m=-4/3
step 3
Find the equation of the line
we have
m=-4/3
y-intercept is -8
so
b=-8
y=mx+b
substitute
y=-(4/3)x-8Part 2
write an equation of the line that is parallel to the graph of y=-4x-9, and whose y-intercept is 3
step 1
Find the slope of the given line
y=-4x-9
the lope is m=-4
step 2
Find the slope of the parallel line
Remember that
If two lines are parallel, then their slopes are the same
so
the slope of the parallel line is m=-4
step 3
Find the equation of the line in slope intercept form
y=mx+b
we ahve
m=-4
b=3
substitute
y=-4x+32b^2 (3a - 5b +8c)Multiply
Answer
2b² (3a - 5b + 8c)
= 6ab² - 10b³ + 16b²c
Explanation
We are told to multiply 2b² with (3a - 5b + 8c)
2b² (3a - 5b + 8c)
= 6ab² - 10b³ + 16b²c
Hope this Helps!!!
Instructions: Find the missing angle. Round your answer to the nearesttenth.
ANSWER
[tex]x=65.9^o[/tex]EXPLANATION
We are given a right-angled triangle.
We have that the hypotenuse is 46.
The side opposite the given angle is 42.
The angle given is x.
To solve this, we can use trigonometric ratios SOHCAHTOA.
We will use the SOH part of it:
[tex]\sin (x)\text{ = }\frac{opposite}{hypotenuse}[/tex]So, we have that:
[tex]\begin{gathered} \sin (x)\text{ = }\frac{42}{46} \\ \sin (x)\text{ = 0.9130 } \\ \text{ Find the sine inverse (sin}^{-1})\text{ of 0.9130 to get x:} \\ x=sin^{-1}(0.9130) \\ x=65.9^o \end{gathered}[/tex]That is the value of the missing angle x.
Which of the following graphs represents the equation 3x + 2y = 24?
Answer:
C
Step-by-step explanation:
if x=0
2y = 24
2/2 y = 24/2
y = 12
if y =0
3x = 24
3/3 x = 24/3
x = 8
Julian has a hundred songs on his media player he knows that 1/4 of the song or Jazz and the rest are pop which statement correctly describes the song on Julian media player
100 songs
1/4 of those are Jazz songs and the rest 3/4 are Pop songs
1/4=0.25
3/4=0.75
To know how many Jazz songs are multiply 100*0.25= 25 Jazz songs
Pop songs: 100*0.75= 75 pop songs
The correct answer is 2 and 5 only please explain why tho
We have that the graph has inflection points where the slope of the function is "0".
From this function we can see that the slope is "0" when x = 2 & x = 5; in all other places the slope is different from "0".
Area of a triangle = 16ft²B = 4ftH = ?
Given:
Area of a triangle, A = 16 ft²
Base of the triangle, b = 4 ft
Height of the triangle, h, is unknown.
To find the height of the triangle, h, apply the formula below:
[tex]A=\frac{1}{2}b\times h[/tex]Rewrite the formula for h.
Multiply both sides by 2:
[tex]\begin{gathered} 2A=\frac{1}{2}b\times h\times2 \\ \\ 2A=b\times h \end{gathered}[/tex]Divide both sides by b:
[tex]\begin{gathered} \frac{2A}{b}=\frac{b\times h}{b} \\ \\ \frac{2A}{b}=h \\ \\ h=\frac{2A}{b} \end{gathered}[/tex][tex]h=\frac{2A}{b}[/tex]Where,
A = 16 ft²
b = 4 ft
Substitute values into the formula and evaluate.
We have:
[tex]\begin{gathered} h=\frac{2A}{b} \\ \\ h=\frac{2(16)}{4} \\ \\ h=\frac{32}{4} \\ \\ h=8\text{ ft} \end{gathered}[/tex]Therefore, the value of h is 8 ft
ANSWER:
H = 8 ft
A certain paint mixture weighing 300 lb contains 20% solids suspended in water. How many pounds of water must be allowed to evaporate to raise the concentration of solids to 22%?
27.27 lb of water must be allowed to evaporate
Explanations:Weight of the paint mixture = 300 lb
The paint mixture contains 20% solids suspended in water
Weight of solids suspended in water = (20/100) x 300
Weight of solids suspended in water = 60 lb
Let the weight of the mixture after evaporation be w
[tex]\begin{gathered} \frac{22}{100}\times w\text{ = 60} \\ 0.22w\text{ = 60} \\ w\text{ = }\frac{60}{0.22} \\ w\text{ = }272.73\text{ lb} \end{gathered}[/tex]The weight of the mixture after evaporation = 272.73lb
The weight of water that will be allowed to evaporate = 300 lb - 272.73 lb
The weight of water that will be allowed to evaporate = 27.27 lb
Therefore, 27.27 lb of water must be allowed to evaporate
kareem correctly answered 85% of the questions on his math test. He missed 6 questions. How many questions were on his test
Answer:
40 questions
Explanation:
The total number of questions on his test represents 100%.
So, If he correctly answered 85% of the questions, then he missed 15% of the questions because:
100% - 85% = 15%
Therefore, 15% of the questions are equivalent to 6 questions, then we need to find the number equivalent to 100%. So 100% is equivalent to:
[tex]100\text{ \% }\times\frac{6}{15\text{ \%}}=40[/tex]Then, there were 40 questions on his test.
Lesson 6: Relate Division and Multiplication Cool-down: A Different Relay Race 1. Lin and Han ran a 5 mile relay race as a team. They each ran the same distance. Dras diagram to represent the situation.
Lin and Han ran a 5 miles relay race.
If they both ran same distance, that means each of them ran;
[tex]\frac{1}{2}(5\text{miles)}=2.5\text{miles}[/tex]So, Lin and Han ran 2.5miles each.
The diadramatic representation of this scenario is;
The image above shows a track race of 5 miles divided into two. LIN ran half of it (2.5 miles) and also Han ran the other half, also (2.5 miles)
add.(7k + 3) + (3k + 2)
PLEAS WILL GIVE BEST RATE OR BRANILEST NEED HELP ASAP
Given figure is of a quadrilateral, with four sides.
We have, the sum of all the interior angles in a quadrileteral is 360.
Thus, we have,
[tex]80+95+38+x=360[/tex]Solving for x, we have,
[tex]\begin{gathered} x+213=360 \\ x=360-213=147 \end{gathered}[/tex]Thus, x = 147.
What is the acceleration of a 50 kg object pushed with a force of 500 newtons?10 m/s225,500 m/s2490 m/s225 m/s2
Let's use Newton's second law of motion:
F = m*a
Where:
F= Force = 500
m = mass = 50
a = acceleration
So:
500 = 50*a
Solve for a:
Divide both sides by 50:
500/50 = 50a/50
10 = a
a = 10m/s²
A real estate agent earned $1,625 for selling a property. If his commission rate is 5%, find the selling price of the property.
Let x be the selling price of the property, then we know that the 5% of x is $1,625.
Now, recall that the n% of an amount can be computed by multiplying the amount by
[tex]\frac{n}{100}\text{.}[/tex]Therefore:
[tex]x\times\frac{5}{100}=1625.[/tex]Solving the above equation for x, we get:
[tex]x=\frac{1625\times100}{5}\text{.}[/tex]Simplifying the above result, we get:
[tex]x=32500.[/tex]Answer:
[tex]32500[/tex]dollars.
Solve the compound inequality.3x + 12 ≥ –9 and 9x – 3 ≤ 33 x ≥ –7 and x ≤ –4x ≥ 7 and x ≤ 4x ≥ 1 and x ≤ 4x ≥ –7 and x ≤ 4
To solve this problem, we will solve each inequality for x and the solution to the system will be the intersection of the solution sets.
1) Solving the first inequality for x we get:
[tex]\begin{gathered} 3x+12\ge-9, \\ 3x\ge-9-12, \\ 3x\ge-21, \\ x\ge-\frac{21}{3}, \\ x\ge-7. \end{gathered}[/tex]2) Solving the second inequality for x we get:
[tex]\begin{gathered} 9x-3\le33, \\ 9x\le33+3, \\ 9x\le36, \\ x\le\frac{36}{9}, \\ x\le4. \end{gathered}[/tex]Answer:
[tex]x\ge-7\text{ and x }\le4.[/tex]For each table below, describe whether the table represents a function that increasing or decreasing.
To determine the table that represents a function that is increasing, we check if the following holds.
• When x increases, f(x) increases.
In Options A, as x increases, f(x) increases.
In Options B, as x increases, g(x) decreases.
In Options C, as x increases, h(x) decreases.
In Options D, as x increases, z(x) increases.
Therefore, the table that
Evaluate / Solve b3 + ac – bif a = 4, b=5, and c = 10.A.170B.165C.160D.125
Answer
Option C is correct.
The answer is 160.
Explanation
We are told to evaluate or solve
b³ + ac - b
if a = 4, b = 5 and c = 10
So, to solve, we will just substitute the given values into the expression to be solved
b³ + ac - b
= (5)³ + (4 × 10) - 5
= 125 + 40 - 5
= 160
Hope this Helps!!!
Ciara has a bag of 50 colored marbles. There are yellow, green, and white marbles. She empties the bag, sorts the marbles, and counts11 yellow marbles and 19 green marbles. She wants to write a ratio of the number of green marbles to the number of white marbles. How can she find the number ofwhite marbles without counting them?
The total number of marbles is, 50.
11 yellow marbles
19 green marbles
x be the number of white marbles.
Without counting, x can be calculated as,
[tex]\begin{gathered} 11+19+x=50 \\ x=50-11-19=20 \end{gathered}[/tex]Therefore the ratio of green marbles to white marbles is,
[tex]\frac{G}{W}=\frac{19}{20}[/tex]Thus option B is correct.
is it possible for a rhombus to have a angle of 120 degrees and a angle of 30 degrees ? homework question
Solution:
From the properties of a Rhombus;
Opposite angles of a rhombus are equal.
The adjacent angles of a rhombus are supplementary, i.e. adds up to 180°
If one of the angles of a rhombus 120°, and the sum of the adjacent angles is 180°, then, the adjacent angle will be 60° (180° - 120° = 60°)
If one of the angles of a rhombus is 30°, then, the adjacent angle will be 150° (180° - 30° = 150°)
Thus, the sum of 120° and 30° is not supplementary and definitely can not be adjacent, since they do not sum up to 180°.
Hence, it is not possible
construct the perpendicular bisectors of each side of the triangle. Extend the bisectors until they intersect each other.
Solution:
Given:
To draw the perpendicular bisector of each side, place the compass at the two ends of the line.
Using the line WX, expand the compass to beyond half of the line and place the compass at the first point (point W), to draw an arc above and below.
Then place the compass at the other point of the line (point X), and draw an arc to intersect the initially drawn arcs.
Join the two points of intersection to get the perpendicular bisector of the line.
Repeat the same for the other two sides to get the perpendicular bisectors.
6cmA bakery sells hollow chocolate spheres. The larger diameter of eachsphere is 6 cm. The thickness of the chocolate of each sphere is 0.65 cm.Part A: What is the amount of chocolate in each hollow sphere? Stateyour answer to the nearest tenth of a cubic centimeter.o
As given by the question
There are given that the larger diameter of each sphereis 6 cm.
Now,
(A).
From the formula of volume:
[tex]V=\frac{4}{3}\pi\times r^3[/tex]Then,
[tex]\begin{gathered} V=\frac{4}{3}\pi\times r^3 \\ V=\frac{4}{3}\pi\times(3)^3 \\ V=\frac{4}{3}\pi\times27 \\ V=4\pi\times9 \\ V=113.097 \end{gathered}[/tex]Now,
From the formula without thickness:
[tex]\begin{gathered} V=\frac{4}{3}\times\pi\times r^3 \\ V=4\times\pi\times1.5 \\ V=18.8495 \end{gathered}[/tex]Then,
[tex]\begin{gathered} V=113.097-18.8495 \\ V=94.2475 \\ V=94.2cm^3 \end{gathered}[/tex]Hence, the volume of chocolate is 94.2 cm^3.
2.2Determine the value of n for which (3k - 2) = 70
The value of k is 24.
From the question, we have
(3k - 2) = 70
(3k) = 72
k=24
Subtraction:
Subtraction represents the operation of removing objects from a collection. The minus sign signifies subtraction −. For example, there are nine oranges arranged as a stack (as shown in the above figure), out of which four oranges are transferred to a basket, then there will be 9 – 4 oranges left in the stack, i.e. five oranges. Therefore, the difference between 9 and 4 is 5, i.e., 9 − 4 = 5. Subtraction is not only applied to natural numbers but also can be incorporated for different types of numbers.
The letter "-" stands for subtraction. Minuend, subtrahend, and difference are the three numerical components that make up the subtraction operation. A minuend is the first number in a subtraction process and is the number from which we subtract another integer in a subtraction phrase.
Complete question: Determine the value of k for which (3k - 2) = 70
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2 3/4 divided by 10
Find the quotient. If possible, rename the quotient as a mixed number or a whole number. Write your answer in simplest form, using only the blanks needed.
The quotient is 11/40.
What is a mixed number?It is formed by combining three parts a whole number, a numerator and a denominator. Here, the numerator and denominator are a part of the proper fraction that makes the mixed number. These are also known as mixed fractions. It contains both an integer or a whole number. A mixed fraction or number is therefore a product of a whole number and a proper fraction.
2 3/4= 11/4
11/4 is divided by 10 then,
It becomes 11/40
So, the quotient is 11/40
Here, 11/40 cannot be converted into a mixed number.
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change the quadratic equation from standard from to vertex form
Answer:
[tex]y=\left[x-\left(-2\right)\right]^2+\left(-9\right)[/tex]Explanation:
Given the quadratic equation in standard form:
[tex]y=x^2+4x-5[/tex]1. Transpose the c-value to the left side of the equation.
[tex]y+5=x^2+4x[/tex]2. Complete the square of the expression on the right side of the equation to get a perfect square trinomial. Add the resulting term to both sides.
[tex]\begin{gathered} y+5+(\frac{4}{2})^2=x^2+4x+(\frac{4}{2})^2 \\ \implies y+5+(2)^2=x^2+4x+(2)^2 \end{gathered}[/tex]3. Add the numbers on the left and factor the trinomial on the right.
[tex]$ y+9=(x+2)^2 $[/tex]4. Transpose the number across to the right side to get the equation into the vertex form, y=a(x-h)²+k.
[tex]y=(x+2)^2-9[/tex]5. Make sure the addition and subtraction signs are correct to give the proper vertex form.
[tex]y=\left[x-\left(-2\right)\right]^2+\left(-9\right)[/tex]The vertex form of the given quadratic equation is:
[tex]y=\left[x-\left(-2\right)\right]^2+\left(-9\right)[/tex]
find the ratio of the primeter to the area of the square
Given data:
The given figure of square.
The perimeter of the square is,
[tex]P=4(x+3)[/tex]The area of the square is,
[tex]A=(x+3)\times(x+3)[/tex]The ratio of the perimeter to the area of the given square is,
[tex]\begin{gathered} \frac{P}{A}=\frac{4(x+3)}{(x+3)(x+3)} \\ =\frac{4}{x+3} \end{gathered}[/tex]Thus, the ratio of the perimeter to the area of the given square is 4/(x+3).
Find the speed of each train (set up a table )
We have two trains that leave Mexico City at the same time, one to the east and the other to the west. The train that travels to the west is 10 mph slower than the other train. The diagram of the problem is:
The combined velocity is:
[tex]V_T=v+v-4=2v-4[/tex]The equation that relates the distance D between the trains and the time after t hours is:
[tex]D=V_T\cdot t[/tex]If after 1.5 hours the trains are 171 miles apart, then using the equation above:
[tex]\begin{gathered} 171=V_T\cdot1.5 \\ V_T=\frac{171}{1.5} \\ V_T=114 \\ 2v-4=114 \\ 2v=118 \\ v=59\text{ mph} \end{gathered}[/tex]Now, the speeds are:
[tex]\begin{gathered} \text{East}\colon59\text{ mph} \\ \text{West}\colon55\text{ mph} \end{gathered}[/tex]Find the area of the figure. Remember to label use ^2 for units squared.10 ft15 ftA=12 ft
Solution
Find the area of the figure.
Area of the figure : Area of a parallelogram = base x height
base = 15ft
height = 10ft
[tex]\begin{gathered} A=bh \\ A=(15\times10)ft^2 \\ A=150ft^2 \end{gathered}[/tex]Therefore the area of the figure = 150ft²