Answers
5)
The given equations are
- 4x - 2y + 3z = 7
- 3x + 5y - 3z = 13
- 5x + y - z = 11
From equation 3, we have
y = 11 + 5x + z
We would substitute y = 11 + 5x + z into equations 1 and 2. For equation 1, we have
- 4x - 2(11 + 5x + z) + 3z = 7
- 4x - 22 - 10x - 2z + 3z = 7
- 4x - 10x - 2z + 3z = 7 + 22
- 14x + z = 29
For equation 2, we have
- 3x + 5(11 + 5x + z) - 3z = 13
- 3x + 55 + 25x + 5z - 3z = 13
- 3x + 25x + 5z - 3z = 13 - 55
22x + 2z = - 42
Dividing both sides of the equation by 2, we have
11x + z = - 21
z = - 21 - 11x
Substituting z = - 21 - 11x into - 14x + z = 29, we have
- 14x - 21 - 11x = 29
- 14x - 11x = 29 + 21
- 25x = 50
x = 50/- 25
x = - 2
z = - 21 - 11(- 2) = - 21 + 22
z = 1
Substituting x = - 2 and z = 1 into y = 11 + 5x + z, we have
y = 11 + 5(-2) + 1
y = 11 - 10 + 1
y = 2
The solutions are
x = - 2, y = 2, z = 1
Related Questions
In 1994, the moose population in a park was measured to be 4930. By 1999, the population was measured again to be 6180. If the population continues to change linearly: A.) Find a formula for the moose population, P, in terms of t, the years since 1990. P(t) B.) What does your model predict the moose population to be in 2006?
Answers
We define the following variables for our problem:
P = population of mooses
t = number of years since 1990
m = growth ratio
In terms of the variables that we defined above and the fact that the population of moose in terms of the year is linear, we have the following equation:
[tex]P(t)=m\cdot t+P_0[/tex]Now, we use the data of the problem:
1) In 1994 the moose population was 4930, so we have:
[tex]\begin{gathered} t=1994-1990=4 \\ P(4)=4930 \end{gathered}[/tex]2) In 1999 the moose population was 6180, so we have:
[tex]\begin{gathered} t=1999-1990=9 \\ P(9)=6180 \end{gathered}[/tex]Now, using the data above and the equation for P(t) we construct the following system of equations:
[tex]\begin{gathered} P(4)=m\cdot4+P_0=4930 \\ P(9)=m\cdot9+P_0=6180 \end{gathered}[/tex]We solve the system of equations.
First, we solve the equations for P0:
[tex]\begin{gathered} P_0=4930-4m \\ P_0=6180-9m \end{gathered}[/tex]Now, because the right-hand-side of both equations is equal to P0, we equal them and then we solve for the variable m:
[tex]\begin{gathered} 4930-4m=6180-9m \\ 9m-4m=6180-4930 \\ 5m=1250 \\ m=250 \end{gathered}[/tex]Finally, we replace the value of m in one of the equations of P0 and solve for it:
[tex]\begin{gathered} P_0=4930-4\cdot m \\ P_0=4930-4\cdot250 \\ P_0=3930 \end{gathered}[/tex]A) The formula for the moose population, P, in terms of t, the years since 1990 is:
[tex]P(t)=250t+3930[/tex]B) We want to know the value of the moose population in 2006.
First, we compute the value of t:
[tex]t=2006-1990=16[/tex]Now, we replace the value of t in the equation of P(t) above:
[tex]P(6)=250\cdot16+3930=7930[/tex]Answer: 7930
5. The quotient of a and b is negative. Decide if each statement about a and b is true or false.
(4 pts)
True False
a. The quotient b + a is positive.
b. The product ab is negative.
c. Either a or b must be negative.
d. The quotient -a + b is negative.
Answers
Deciding if each statement about a and b is true or false.
a)False
b)True
c)True
d)False
Given:
The quotient of a and b is negative.
a.
If quotient is negative means the dividend or divisor any one is negative so when the quotient b+a is always negative so given statement is false.
b.
The product ab is always negative because if the quotient is negative means either a or b is negative so ab is negative.
So given statement is true.
c.
Either a or b must be negative is true because if no element a or b is not negative we cannot produce a negative quotient hence either a or b must be negative.
d.
The quotient -a+b is negative is false because if the quotient is negative the values of a and b is one positive and one negative the positive number that is b greater than -a in that case the statement is false.
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Printer Paper Store normally sells laser paper for 89,99 per ream, It has a special, 1
ream free with the purchase of 2. If you buy 2 reams and get 1 free, what is your (a)
cost per ream, and (b) markdown per ream?
Answers
The required (a) cost per ream becomes 59.99 and (b) the markdown per ream is 30.
Given that,
Printer Paper Store normally sells laser paper for 89,99 per ream, It has a special, 1 ream free with the purchase of 2. If you buy 2 reams and get 1 free.
In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication and division,
Here,
Cost of the 1 ream = 89,99
Cost of the 2 reams = 179.98
According to the question,
Cost of the 3 reams = 179.98
Cost of the one ream among the 3 reams = 179.88/3 = 59.99
markdown per ream = 89.99 - 59.99 = 30
Thus, the required (a) cost per ream becomes 59.99 and (b) the markdown per ream is 30.
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Kyra is participating in a fundraiser walk-a-thon. She walks 3 miles in 45 minutes. If she continues to walk at the same rate, determine how many minutes it will take her to walk 7 miles. Show how you found your answer.
Answers
3 milles ---> 45 minutes
7 miles ---> x minutes
then
[tex]\begin{gathered} 3\times x=7\times45 \\ 3x=315 \\ \frac{3x}{3}=\frac{315}{3} \\ x=105 \end{gathered}[/tex]answer: 105 minutes for walk 7 miles
the angle t is an acute angle and sin t and cos t are given. use identities to find tan t, csc t, sec t, and cot t. where necessary, rationalizing denominators.
Answers
Recall the following identities:
[tex]\begin{gathered} \tan (t)=\frac{\sin (t)}{\cos (t)} \\ \csc (t)=\frac{1}{\sin (t)} \\ \sec (t)=\frac{1}{\cos (t)} \\ \cot (t)=\frac{\cos (t)}{\sin (t)} \end{gathered}[/tex]Since sin(t)=12/13 and cos(t)=5/13, then:
[tex]\begin{gathered} \tan (t)=\frac{(\frac{12}{13})}{(\frac{5}{13})} \\ =\frac{12}{5} \end{gathered}[/tex][tex]\begin{gathered} \csc (t)=\frac{1}{(\frac{12}{13})} \\ =\frac{13}{12} \end{gathered}[/tex][tex]\begin{gathered} \sec (t)=\frac{1}{(\frac{5}{13})} \\ =\frac{13}{5} \end{gathered}[/tex][tex]\begin{gathered} \cot (t)=\frac{(\frac{5}{13})}{(\frac{12}{13})} \\ =\frac{5}{12} \end{gathered}[/tex]A construction crew built 1/2 miles of road in 1/6 days. What is the unit rate in simplest form.
Answers
For this problem, we are given the distance a construction crew built a road and the time in days it took to build it. We need to determine the unit rate for this problem, which is achieved by dividing the distance and time. We have:
[tex]\text{ unit rate}=\frac{\frac{1}{2}}{\frac{1}{6}}=\frac{1}{2}\cdot\frac{6}{1}=\frac{6}{2}=3\text{ miles per day}[/tex]The unit rate is 3 miles per day.
Which of the functions below could have created this graph?OA. F(x)=x²+2x-2OB. F(x)---4C. F(x)=3x²+2x²OD. F(x)=-²
Answers
The functions [tex]F(x)=-\frac{1}{2}x^{4}-x^{3}+x+2[/tex] could have created this graph of downward parabola.
Option D is correct because the leading coefficient of given function is negative. That's why it is making the downward parabola.
As we can see from the graph that the the parabola is downward.
And we know that if the leading coefficient is less than zero, thus the graph will be downward parabola.
Lets check all the option:
For option A:
[tex]F(x)=x^{3}+x^{2}+x+1[/tex], this is a cubic polynomial and the graph will be a cubic curve.
For option B:
[tex]F(x)=x^{2}+5[/tex], this is a quadratic polynomial and leading coefficient is positive, so the graph will be upward parabola.
For option C:
[tex]F(x)=x^{4}-2x[/tex], for x = 0, F(x) =0, so it will not intersect the y-axis. Also the graph will be upward parabola.
Hence, the option D, [tex]F(x)=-\frac{1}{2}x^{4}-x^{3}+x+2[/tex], could have created this graph of downward parabola.
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Write your answer as a whole number and remainder. 38 : 5 = R
Answers
Answer
7 remainder 3
Explanation
38 : 5 can be written as 38/5
And we know that that will give
(38/5) = 7 remainder 3
Hope this Helps!!!
Stats, Practice Test 5-6 ) There is a class with 6 women and 12 men. a) If I randomly pick 5 students, with replacement. What is the probability that at least 4 of them will be man? b) If I randomly pick 6 students, what is the probability that at least one of them will be a man?
Answers
Step 1: Problem
There is a class with 6 women and 12 men. a) If I randomly pick 5 students, with replacement. What is the probability that at least 4 of them will be man? b) If I randomly pick 6 students, what is the probability that at least one of them will be a man?
Step 2: Concept
←
Question 12, "2.7.19 >
The amount of 20% alcohol solution is [
(Type an integer or a decimal.)
points
O Points: 0 of 1
How many ounces of a 20% alcohol solution must be mixed with 14 ounces of a 25% alcohol solution to make a 21%
alcohol solution?
ounces.
Save
Answers
You need to add 10 ounces of 20% alcohol solution.
x = ounces of 20% alcohol solution to add to the 15 oz of 25% solution
15 oz of a 25% solution = 3.75 oz of pure alcohol
The total amount can be described 15+x ounces.
We solve the problem in terms of the amount of pure alcohol
2x + 3.75 = .23(15+x)
2x + 3.75 = 3.45 + .23x
Subtracting .2x from both sides
3.75 = .03x + 3.45
Subtracting 3.45 from both sides
3 = .03x
Multiply by 100
30 = 3x
Divide by 3
10 = x
x = 10
So, you have to add 10 oz of 20% alcohol solution to 15 oz of 25% alcohol.
At the end we would have 25 oz that we believe would be 23% alcohol. If that is true, then we would have:
23 * 25 = 5.75 oz of pure alcohol in the solution.
We have shown (above) that we have 3.75 oz of pure alcohol in the 15 oz of 25% solution.
How many oz of pure alcohol is there in 10 oz of 20% alcohol?
2*10 = 2 oz
3.75 + 2 = 5.75 oz, which is exactly what we needed
You need to add 10 ounces of 20% alcohol solution.
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QRS and SRT are complementary. if m QRS (8x+10)° and m SRT=(8x)°Determine m QRSm QRS=
Answers
We are given two complementary angles (QRS and SRT).
Two angles are called complementry if they sum up to 90 degrees.
Therefore, by defination
mQRS + mSRT = 90
(8x+10) + (8x) = 90
8x + 8x + 10 = 90
16x = 90-10
16x = 80
x = 80/16
x = 5
Now, put the values in both the euqations and we will get the values of both the angles.
mQRS = 8x + 10 = 8(5) + 10 = 40 + 10 = 50 degrees
mSRT = 8x = 8(5) = 40 degrees
If Vegetable Oil costs $3.47 for 48 ounces, what is the cost of 1 tablespoon of vegetable oil?
A) 7 cents, B) 70 cents C) 4 cents D) $1.40 E) 25 cents
Answers
If Vegetable Oil costs $3.47 for 48 ounces, the cost of 1 tablespoon of vegetable oil is 4 cents.
1 tablespoon has alomst 0.5 ounce
If Vegetable Oil costs $3.47 for 48 ounces
Cost of 48 ounces of vegetable oil = $3.47
cost of 1 ounce of vegetable oil = $ 3.47 / 48 = $0.0722
cost of 0.5 ounce of vegetable oil = $0.0722/2 = $0.0361
cost of 0.5 ounce of vegetable oil is $0.0361
1 dollar = 100 cents
0.0361 dollar = 0.0361 x 100 cents
0.0361 dollar = 3.6 cents = 4 cents (approx)
Therefore, if Vegetable Oil costs $3.47 for 48 ounces, the cost of 1 tablespoon of vegetable oil is 4 cents.
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Based on the graph, what is the solution to the system of equations?
Answers
The solution of the system of equations is where both lines cross each other.
solution = (0,1)
3. SOLVE THE unear equation X - 9 = 35x
Answers
x - 9 = 35x
Subtract x from both sides:
x - 9 -x = 35x - x
-9 = 34x
Divide both sides by 34:
-9/34 = 34x/34
x = -9/34
Review the following table verify that the calculations are correct. If there are errors note the day where the air exist and what the correct calculation should be.
Answers
Given
Number of patients = 6,663
- For Sunday
Patients = 1,187
Percent is:
[tex]\frac{1187}{6663}\times100\%=0.178\times100\%=17.8\%[/tex]- For Monday
Patients = 755
Percent:
[tex]\frac{755}{6663}\times100\%=11.3\%[/tex]Monday is correct.
- For Tuesday
Patients = 1,085
Percent:
[tex]\frac{1085}{6663}\times100\%=16.3\%[/tex]Tuesday is correct.
- For Wednesday
Patients = 1,031
Percent:
[tex]\frac{1031}{6663}\times100\%=15.5\%[/tex]Wednesday is correct.
- For Thursday
Patients = 1,024
Percent:
[tex]\frac{1024}{6663}\times100\%=15.4\%[/tex]- For Friday
Patients = 808
Percent:
[tex]\frac{808}{6663}\times100\%=12.1\%[/tex]Friday is correct.
- For Saturday
Patients = 773
Percent:
[tex]\frac{773}{6663}\times100\%=11.6\%[/tex]Saturday is correct.
Answer:
Errors
Sunday ---> 17.8%
Thursday ---> 15.4%
When the length of each edge of a cube is increased by 1 cm, the volume is increased by 19 cm3.A cube is shown.The length is labeled e.The width is labeled e.The height is labeled e.What is the length (in centimeters) of each edge of the original cube? cm
Answers
Solution
solution given;
let length be x
its
volume be x ³
we have when length is increased by 1cm volume increased by 19 cm³ so
(x+1)³=x³+19cm³
x³+1³+3x²+3x=x³+19
3x²+3x-18=0
3(x²+x-6)=0
x²+3x-2x-6=0
x(x+3)-2(x+3)=0
(x+3)(x-2)=0
either
x=-3 rejected
or
x=2cm
Hence the correct answer for the length of each cube = 2cm
write an express to 4× + 12 by coming like terms
Answers
the initial expression is:
[tex]4x+12[/tex]We can see that they have in common a factor of 4 so we can rewrite it like:
[tex]4(x+3)[/tex]An orange has about I cup of juice. How many oranges are needed to make 2 cups of juice?
Answers
An orange has about 1/4 cup of juice. To find how many oranges are needed to make 2 1/2 cups of juice, we can use the next proportion
[tex]\frac{\frac{1}{4}\text{cup}}{2\frac{1}{2}\text{ cup}}=\frac{1\text{ orange}}{x\text{ oranges}}[/tex]Solving for x:
[tex]undefined[/tex]What is nine increased by four and then doubled?
Answers
Answer:
Step-by-step explanation:
9+4=
13
13*2=
26
Answer:
Step-by-step explanation:
(9 multiplied by 4) multiplied by 2
= 72
Can’t figure this fraction equation. 5/6 is the fraction getting divided by 2. Answer must be in the simplest form
Answers
Solution:
5/6 divided by 2, i.e.
[tex]\frac{5}{6}\div2[/tex]Applying the fraction rule
[tex]\begin{gathered} \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c} \\ =\frac{5\times\:1}{6\times\:2} \\ =\frac{5}{6\times\:2} \\ =\frac{5}{12} \end{gathered}[/tex]Hence, the answer is 5/12
Jimmy can jump 40 dogs in 5 hours, How many dogs can Jimmy Jump per hour?
Answers
To be able to determine how many dogs can Jimmy Jump per hour, let's divide how many dogs can Jimmy Jump by the number of hours he took to complete that certain number of jumps. Thus, we generate this equation,
[tex]\text{Jump rate of Jimmy= }\frac{No\text{. of dogs Jimmy jumped}}{No.\text{ of hours Jimmy took to jumped the no. dogs.}}[/tex]Given:
Jimmy jumped = 40 dogs
No. of hours Jimmy took to jump 40 dogs = 5 hours
We get,
[tex]\text{ Jump rate of Jimmy = }\frac{40\text{ dogs}}{5\text{ hours}}[/tex][tex]\text{ Jump per hour = 8 dogs per hour}[/tex]Therefore, Jimmy can jump 8 dogs per hour.
Why is the quotient of three divided by one-fifth different from the quotient of one-fifth divided by three? Hello my child needs help with this question could someone help
Answers
Solution
We want to get why
[tex]\frac{3}{\text{ \lparen1/5\rparen}}\text{ is different from }\frac{\text{ \lparen1/5\rparen}}{3}[/tex]Reason 1: Commutation Law Does Not Hold For Division (or quotient)
Generally,
[tex]\frac{a}{b}\ne\frac{b}{a}[/tex]Reason 2: Actual Computation
First
[tex]\begin{gathered} \frac{3}{\text{ \lparen1/5\rparen}}=3\div\frac{1}{5} \\ \\ \frac{3}{\text{ \lparen1/5\rparen}}=3\times\frac{5}{1} \\ \\ \frac{3}{\text{ \lparen1/5\rparen}}=15 \end{gathered}[/tex]Secondly
[tex]\begin{gathered} \frac{\text{ \lparen1/5\rparen}}{3}=\frac{1}{5}\div3 \\ \\ \frac{\text{ \lparen1/5\rparen}}{3}=\frac{1}{5}\times\frac{1}{3} \\ \\ \frac{\text{ \lparen1/5\rparen}}{3}=\frac{1}{15} \end{gathered}[/tex]It is now obvious that
[tex]\frac{3}{\text{ \lparen1/5\rparen}}\ne\frac{\text{ \lparen1/5\rparen}}{3}[/tex]The function f(x) = -x2 - 4x + 5 is shown on the graph. What is the domain and range of this function?
Answers
Step 1
The domain includes all the x-values that fall within the function
Hence, the domain of this function is [ All real values of x]
Step 2
Find the range
The range includes all values of y that fall within the function
Hence the range of the function is [-∞, 9]
what are the coordinates of the point on the directed line segment from (2,-1) to (9,6) that partitions the segment into a ratio of 5 to 2
Answers
Ok, so:
Let x and y be coordinate of the point C that partitions the segment.
And Let A = ( 2, -1 ) and B = ( 9 , 6 ).
So, given that C partitions the segment into a ratio of 5 to 2, we have:
Total parts of the segment: 5+2 = 7.
So, the point C is 5/7 of way from A to B.
Let me draw the situation:
Now, we know that the right distance is 7 and the upper distance is 7.
Now we multiply 5/7 per both distances.
5/7 * 7 = 5
5/7 * 7= 5
Now, we take the initial point A ( 2, -1 ), and sum 5 to each coordinate.
Then, the point C = ( 7 , 4 )
5. Julia's test scores on the first four science tests were: 85, 77, 63, 90. Therewill be five tests. She needs an average of at least 80 in order to get a B on herreport card.Part B: What is the minimum score that Julia must earn on her final test in orderto get a B average?
Answers
Let the minimum score be x
(85 + 77 + 63 + 90 + x)/5 = 80
315 + x = 400
x = 400 - 315
= 85
Julia must get a minimum score of 85 to get a B average
For the real-valued functions f(x) = 2x+10 and g(x) = x-1, find the composition f•g and specify its domain using interval notation.(f•g)(x)=Domain of f•g: (The 2x+10 is square rooted)
Answers
Okay, here we have this:
We need to meke the composition (f•g)(x), so in the function f we will replace x with the function g:
[tex]\begin{gathered} \mleft(f•g\mright)\mleft(x\mright)=\sqrt[]{2(x-1)+10} \\ =\sqrt[]{2x-2+10} \\ =\sqrt[]{2x+8} \end{gathered}[/tex]Now let's find the domain of (f•g)(x):
2X+8≥0
2X≥-8
X≥-4
Finally we obtain the following domain: [-4,∞)
In an Oreo factory, the mean mass of a cookie is given as40 grams with a standard deviation of 2 grams. Whatpercentage of the cookies are between 34 grams and 42grams?
Answers
The Solution:
Given:
[tex]\begin{gathered} \bar{x}=mean=40g \\ \sigma=\text{ standard deviation}=2g \end{gathered}[/tex]We are required to find the percentage that is between 34 grams and 42 grams.
By z-score statistic,
The lower limit is:
[tex]Z_1=\frac{x-\mu}{\sigma}=\frac{34-40}{2}=\frac{-6}{2}=-3[/tex]The upper limit is:
[tex]Z_2=\frac{x-\mu}{\sigma}=\frac{42-40}{2}=\frac{2}{2}=1[/tex]The probability is:
[tex]P(Z_1Converting to percent, we multiply by 100:[tex]0.840\times100=84\text{\%}[/tex]Therefore, the correct answer is 84%
Hello pls help meeee
Answers
The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
Given that,
The function is (-x+3)/ (3x-2)
We have to find f(1) and f'(x).
Take the function expression
f(x)= (-x+3)/ (3x-2)
Taking x as 1 value
f(1)= (-1+3)/(3(1)-2)
f(1)=2/1
f(1)=1
Now, to get f'(x)
With regard to x, we must differentiate.
f(x) is in u/v
We know
u/v=(vu'-uv')/ v² (formula)
f'(x)= ((3x-2)(-1)- (-x+3)(3))/ (3x-2)²
f'(x)= ((-3x+2)-(-3x+9))/ 9x²- 12x+4
f'(x)=(-3x+2+3x-9)/ 9x²- 12x+4
f'(x)=2-9/ (9x²- 12x+4)
f'(x)=-7/ (9x²- 12x+4)
Therefore, The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
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If triangle ABC is reflected across the y-axis, what are the coordinates of C?O A. (5,-3)O B. (-5, 3)O C. (3,-5)O D. (-3, -5)
Answers
B) (-5,3)
1) We need to locate the vertex location since the point here is to find the coordinates of C'. So, let's do it before applying the required transformation.
C(5,3)
2) Since we want to know the coordinates of C', and there was a reflection across the y-axis, we can write the following:
C(5,3) Rule (x,y) --> (-x,y) C'(-5,3)
3) Thus, the answer is (-5,3)
what type from f x to g x on the graph ?
Answers
When looking at the graph, we can discard two of the options, rotation (as they don't have any intersection, there are no possibilities of having a rotation axis) and reflection. It occured a translation. To know which of the options is correct, we can see the y intercepts of both lines. The y intercept of f(x) is 0 and the y intercept of g(x) is -4, which means that the line was translated down 4 units.
It means the right answer is D. Vertical Translation down 4 units.