n applicant receives a job offer from two different companies. Offer A is a starting salary of $58,000 and a 3% increase for 5 years. Offer B is a starting salary of $56,000 and an increase of $3,000 per year.
Answers
Part A.
The inital salary is $58,000, then we have:
[tex]a_1=58000_{}[/tex]Since we have an increase of 3% each year we know that the second year the salary would be:
[tex]\begin{gathered} a_2=1.03a_1 \\ a_2=1.03\cdot58000 \end{gathered}[/tex]The third year the salary would be:
[tex]\begin{gathered} a_3=1.03a_2 \\ a_3=1.03(1.03)58000 \\ a_3=(1.03)^258000 \end{gathered}[/tex]and so on for year 4 and 5.
Since the increase in salary is only the first five years we conclude that this can't be represented by a geometric series.
For the first five year we can calculate the salary using a geometric sequence with common ratio 1.03, then for the first five years the salary is given by
[tex]a_n=(1.03)^{n-1}_{}\cdot58000\text{ for }1\leq n\leq5[/tex]The salary for the any subsequent year is given by:
[tex]a_n=(1.03)^4\cdot58000\text{ for }n>5[/tex]Part B.
Since we are adding a certain quantity each year we conclude that this offer can be represetend by an algebraic series given by:
[tex]\begin{gathered} b_n=56000+(n-1)3000 \\ b_n=56000+3000n-3000 \\ b_n=3000n+53000 \end{gathered}[/tex]Part C.
After five years the income for offer A is:
[tex]a_5=(1.03)^4\cdot58000=65279.51[/tex]For offer B is:
[tex]b_5=3000(5)+53000=68000_{}[/tex]Therefore after 5 years job offer B has a greater total income.
Related Questions
What are all the ordered pairs that are solutions to the inequality 2x-3y>=12
Answers
To answer this question, we need to solve this inequality for y as follows:
[tex]2x-3y\ge12[/tex]Then, we have:
[tex]-3y\ge12-2x\Rightarrow\frac{-3y}{-3}\leq\frac{12}{-3}-\frac{2x}{-3}\Rightarrow y\leq-4+\frac{2x}{3}[/tex]As we can see the direction of the inequality changed because we multiplied it by a negative number.
Then, if we can see the inequality, we find that the values that make this inequality true
are infinite values (the values of y are in function of the values of x).
Then, since we have the values given in the options, we need to check which of these values make the inequality true or we can graph a line for this inequality.
We have that the line is given by:
y = 2x/3 - 4
The x-intercept for this line is:
[tex]undefined[/tex]a bag contains 30 marbles. 8 are pink, 11 are blue, 4 are yellow and 7 are purple. Calculate the probability of randomly selecting a marble that is not blue .
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In order to find the probability of a marble not being blue, we need to find how many marbles are not blue.
To do so, we just need to sum the number of pink, yellow and purple marbles:
[tex]8+4+7=19[/tex]Now, to find the probability, we just need to divide the number of non-blue marbles by the total number of marbles.
[tex]\frac{19}{30}=0.6333=63.33\text{\%}[/tex]Graph AABC with A(4, 7), B(0,0), and C(8, 1).a. Which sides of AABC are congruent? How do you know?b. Construct the bisector of ZB. Mark the intersection of the ray and AC as D.c. What do you notice about AD and CD?
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a) Two sides of a triangle are concruent when they are the same length. First calculate the lenght of each side
[tex]\begin{gathered} AC^2=\text{ (X\_c-X\_a)}^2+(Y_a-Y_c)^2=(8-4)^2+(7-1)^2=\text{ 52} \\ AC=\sqrt{52}=7.2 \end{gathered}[/tex][tex]\begin{gathered} AB^2=(X_a-X_b)^2+(Y_a-Y_b)^2=(4-0)^2+(7-0)^2=\text{ 65} \\ AB=\sqrt{65}=8.06\approx8 \end{gathered}[/tex][tex]\begin{gathered} BC^2=(X_c-X_b)^2+(Y_c-Y_b)^2=(8-0)^2+(1-0)^2=\text{ 65 } \\ BC=\sqrt{65}=8.06\approx8 \end{gathered}[/tex]Sides AB and BC aren congruent.
b)
The bisector divides the triangle in exact halves.
The bisector is the blue line, in green you'll se the length of each side.
c)
a square pyramid has a base height edge length of 3m and a slant height of 6m. find the lateral area and surface area of the pyramid
Answers
hello
given that the pyramid has the shape of a triangle, we can easily find the height of the pyramid using pythagoran's theorem
from triangle b, let's use the formula and solve for y
[tex]\begin{gathered} x^2=h^2+z^2 \\ 6^2=h^2+1.5^2 \\ 36=h^2+2.25 \\ \text{collect like terms} \\ h^2=36-2.25 \\ h^2=33.75 \\ \text{solve for h} \\ h=\sqrt[]{33.75} \\ h=5.809\approx5.81m \end{gathered}[/tex]having known the value of the heigh of the pyramid, we can now proceed to solve for the lateral area and surface area
for the lateral area, the formula is given as
[tex]\begin{gathered} A_l=l\sqrt[]{l^2+4h} \\ l=\text{edge length} \\ h=\text{height of pyramid} \end{gathered}[/tex][tex]\begin{gathered} A_l=l\sqrt[]{l^2+4h} \\ l=3m \\ h=5.81m \\ A_l=3\sqrt[]{3^2+4\times5.81_{}} \\ A_l=17.03m^2 \end{gathered}[/tex]the lateral area of the figure is 17.03 squared meter.
let's solve for the surface area
the formula for the surface area of a square pyramid is given as
[tex]\begin{gathered} A=l^2+2l\sqrt[]{\frac{l^2}{4}+4h^2} \\ l=3m \\ h=5.81 \\ A=3^2+2\times3\sqrt[]{\frac{3^2}{4}+4\times5.81^2} \\ A=9+6\sqrt[]{\frac{9}{4}+135.0244} \\ A=79.298\approx79.3m \end{gathered}[/tex](06.04)The line of best fit for a scatter plot is shown:A scatter plot and line of best fit are shown. Data points are located at 1 and 4, 2 and 6, 2 and 3, 4 and 3, 6 and 1, 4 and 5, 7 and 2, 0 and 6. A line of best fit passes through the y-axis at 6 and through the point 4 and 3.What is the equation of this line of best fit in slope-intercept form? (4 points)y = −6x + three fourthsy = 6x + three fourthsy = negative three fourthsx + 6y = three fourthsx + 6
Answers
Answer:
[tex]y\text{ = -}\frac{3}{4}x\text{ + 6}[/tex]Explanation:
Given the y-intercept and a point, we want to get the equation of the line of best fit
We have the slope-intercept form as:
[tex]y\text{ = mx + b}[/tex]where m is the slope and b is the y-intercept:
[tex]y\text{ = mx + 6}[/tex]Now, to get m, we substitute the point (4,3)
We substitute 3 for y and 4 for x
We have that as:
[tex]\begin{gathered} 3\text{ = 4m + 6} \\ 3-6\text{ = 4m} \\ 4m\text{ = -3} \\ m\text{ = -}\frac{3}{4} \end{gathered}[/tex]Thus, the equation of the line of best fit is:
[tex]y\text{ = -}\frac{3}{4}x\text{ + 6}[/tex]Which of the following rational expressions has the domain restrictions X = -6 and x = 1?
Answers
The domain of the function is possible values of independant varaible such that function is defined or have real values.
So the expression
[tex]\frac{(x+2)(x-3)}{(x-1)(x+6)}[/tex]is not defined for x = -6 and for x = 1, as expression becomes undefined for this values of x (Denominator becomes 0).
So answer is,
[tex]\frac{(x+2)(x-3)}{(x-1)(x+6)}[/tex]Option B is correct.
is it option one or two I don't need to work
Answers
From the options, the function has the next form
[tex]y=a\cdot b^x[/tex]where a and b are two constants.
The function pass through the point (0, 2), then:
[tex]\begin{gathered} 2=a\cdot b^0 \\ 2=a\cdot1 \\ 2=a \end{gathered}[/tex]The function pass through the point (1, 10), then:
[tex]\begin{gathered} 10=2\cdot b^1 \\ \frac{10}{2}=b \\ 5=b \end{gathered}[/tex]Therefore, the function is:
[tex]y=2\cdot5^x^{}[/tex]This is so hard I don’t understand this pls help
Answers
From the given question
There are given that the matrix.
Now,
To find the inverse of any matrix, first find their determinant.
Then,
According to the properties of the matrix:
If the determinant of any matrix is zero, then their inverse has undefined.
So,
From the determinant of the given matrix:
[tex]\begin{gathered} \begin{bmatrix}{4} & {8} & {} \\ {7} & {14} & \\ {} & {} & {}\end{bmatrix}=(14\times4)-(8\times7) \\ =56-56 \\ =0 \end{gathered}[/tex]The determinant of the given matrix is zero
So, their inverse has not been defined.
Hence, the correct option is A.
A circle has a circumference of 25 feet, what is the diameter? Your answer
Answers
Given :
The circumference of the circle = 25 feet
π = 3.14
The circumference of the circle =
[tex]2\pi\cdot r=\pi\cdot d[/tex]Where r is the radius and d is the diameter
so,
[tex]\begin{gathered} \pi\cdot d=25 \\ \\ d=\frac{25}{\pi}=\frac{25}{3.14}\approx7.96 \end{gathered}[/tex]if we rounded to the nearest feet, the diameter = 8 feet
solve the system by substitution type your stepsx=2y-53x-y=5
Answers
Answer:
The solution to the system of equations is
x = 3
y = 4
Explanation:
Given the pair of equations:
[tex]\begin{gathered} x=2y-5\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\text{.}(1) \\ 3x-y=5\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\text{.}(2) \end{gathered}[/tex]To solve these simultaneously, use the expression for x in equation (1) in equation (2)
[tex]\begin{gathered} 3(2y-5)-y=5 \\ 6y-15-y=5 \\ 6y-y-15=5 \\ 5y-15=5 \\ \\ \text{Add 15 to both sides} \\ 5y-15+15=5+15 \\ 5y=20 \\ \\ \text{Divide both sides by 5} \\ \frac{5y}{5}=\frac{20}{5} \\ \\ y=4 \end{gathered}[/tex]Using y = 4 in equation (1)
[tex]\begin{gathered} x=2(4)-5 \\ =8-5 \\ =3 \end{gathered}[/tex]Therefore, x = 3, and y = 4
F (x)=x^2+4 what is f(-4)
Answers
ANSWER
f(-4) = 20
EXPLANATION
To find f(-4) we just have to replace x by -4 in function f(x):
[tex]f(-4)=(-4)^2+4[/tex]First solve the exponents. Remember that if the exponent is even and the result is always positive, either the base is positive or negative:
[tex]f(-4)=16+4=20[/tex]PLEASE HELP 15 POINTS!! I'M GIVING BRAINLIEST
Answers
The value of sinα in the right angle triangle is [tex]\frac{16\sqrt{281} }{78961}[/tex]
What is a right-angle triangle?A right-angled triangle is a triangle, that has one of its interior angles equal to 90 degrees or any one angle is a right angle. Therefore, this triangle is also called the right triangle or 90-degree triangle. The right triangle plays an important role in trigonometry.
sin α = opposite/hypotenuse
opposite = 16, hypotenuse [tex]\sqrt{281}[/tex]
sin α = [tex]\frac{16}{\sqrt{281} }[/tex]
By rationalizing, the denominator which means multiply the fraction by [tex]\frac{\sqrt{281} }{\sqrt{281} }[/tex]
[tex]\frac{16}{\sqrt{281} }[/tex] x [tex]\frac{\sqrt{281} }{\sqrt{281} }[/tex] = [tex]\frac{16\sqrt{281} }{78961}[/tex]
sin [tex]\alpha[/tex] = [tex]\frac{16\sqrt{281} }{78961}[/tex]
In conclusion, the value of sin[tex]\alpha[/tex] = [tex]\frac{16\sqrt{281} }{78961}[/tex]
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Last weekend, 5% of the tickets sold at Seaworldwere discount tickets. If Seaworld sold 60 tickets inall, howmany discount tickets did it sell? Use thepercent proportion.
Answers
Let:
N = Total tickets
d = discount tickets
r = percent of discount tickets sold
so:
[tex]\begin{gathered} d=N\cdot r \\ where\colon \\ N=60 \\ r=0.05 \\ so\colon \\ d=60\cdot0.05 \\ d=3 \end{gathered}[/tex]3 discount tickets were sold
Solve the following equation for x. (x - 5) -6 2 OX= -2 O x=2 x=-17 X=-7
Answers
You have teh following equation:
(x - 5)/2 = - 6
In order to find the solution to the previous equation, proceed as follow:
(x - 5)/2 = -6 multiply by 2 both sides
x - 5 = -6(2)
x - 5 = -12 add 5 both sides
x = -12 + 5 simlify
x = -7
Hence, the solution to the gicen equation is x = -7
8Suppose Z follows the standard normal distribution. Use the calculator provided, or this table, to determine the value of c so that the following is true.p=(-c ≤ Z ≤ c ) =0.9127Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places.
Answers
The value of c such that [tex]P(-c\leq Z\leq c)=0.9127[/tex] is true is 0.0873 where Z follows the standard normal distribution.
It is given to us that -
[tex]P(-c\leq Z\leq c)=0.9127[/tex] is true
It is also given that Z follows the standard normal distribution.
We have to find out the value of c.
Since Z follows the standard normal distribution, so we can say that
Z ∼ N(0,1)
To find out c,
[tex]P(-c\leq Z\leq c)=0.9127\\= > P(Z\leq c)-P(Z\leq -c)=0.9127\\[/tex]
Since there is a symmetric z-distribution, the above equation can be represented as -
[tex][1-P(Z\leq -c)]-P(Z\leq -c) = 0.9127\\= > 1-P(Z\leq -c) - P(Z\leq -c) = 0.9127\\= > 1-2P(Z\leq -c)=0.9127\\= > 2P(Z\leq -c)=0.0873\\= > P(Z\leq -c)=0.04365[/tex]
=> -c ≈ 0.0873 (Using online calculator)
Therefore, the value of c such that [tex]P(-c\leq Z\leq c)=0.9127[/tex] is true is 0.0873 where Z follows the standard normal distribution.
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Answer:
The value of c such that is true is 0.0873 where Z follows the standard normal distribution.
Step-by-step explanation:
A girl cycled a total of 15 kilometers by making 5 trips to work. How many trips will she have to make to cover a total of 24 kilometers? Solve using unit rates.
Answers
We need to find how many trips she will have to make to cover a total of 24 kilometers.
We know that she covered 15 kilometers by making 5 trips. Thus, the number of kilometers made on each trip is:
[tex]\frac{15\text{ kilometers}}{5\text{ trips}}=\frac{15\div5\text{ kilometers}}{5\div5\text{ trip}}=\frac{3\text{ kilometers}}{1\text{ trip}}[/tex]Then, she made 3 kilometers on 1 trip (unit rate).
Now, to cover 24 kilometers, she needs to make 8 trips, because:
[tex]\begin{gathered} 3\text{ kilometers }\times8=24\text{ kilometers} \\ \\ 1\text{ trip }\times8=8\text{ trips} \end{gathered}[/tex]Thus:
[tex]\frac{3\text{ kilometers}}{1\text{ trip}}=\frac{3\text{ kilometers}}{1\text{ trip}}\times\frac{8}{8}=\frac{3\times8\text{ kilometers}}{1\times8\text{ trips}}=\frac{24\text{ kilometers}}{8\text{ trips}}[/tex]Answer: She will have to make 8 trips.
(a) Find an angle between 0 and 2pi that is coterminal with 10pi/3.(b) Find an angle between 0° and 360° that is coterminal with -300°.Give exact values for your answers.(a) __ radians(b) __ °
Answers
To find a coterminal angle between 0 and 2pi, you can subtract 2pi from the given angle, like this
[tex]\frac{10\pi}{3}-2\pi\text{ }[/tex]To do the subtraction, you can convert 2pi into a fraction, like this
[tex]\frac{2\pi\cdot3}{3}=\frac{6\pi}{3}[/tex]So, you have
[tex]\frac{10\pi}{3}-2\pi=\frac{10\pi}{3}-\frac{6\pi}{3}=\frac{4\pi}{3}[/tex]Therefore, 4pi/3 is the angle between 0 and 2pi that y is coterminal with 10pi/3.
For point (b), you can add 360° at the angle given, like this
[tex]360+(-300)=360-300=60[/tex]Therefore, an angle between 0° and 360° that is coterminal with -300° is 60°.
If cos(0) = 24/25, and 0 is in Quadrant I, then what is cos(0/2)? Simplify your answer completely, rationalize the denominator, and enter it in fractional form.
Answers
The given information is:
[tex]\begin{gathered} \cos (\theta)=\frac{24}{25} \\ \theta\text{ is in quadrant I} \end{gathered}[/tex]cos (theta/2) is given by:
[tex]\cos (\frac{\theta}{2})=\pm\sqrt[]{\frac{1+\cos\theta}{2}}[/tex]In Quadrant I, cos (theta) is positive, then the answer is positive. By replacing the known values:
[tex]\begin{gathered} \cos (\frac{\theta}{2})=\sqrt[]{\frac{1+\frac{24}{25}}{2}} \\ \cos (\frac{\theta}{2})=\sqrt[]{\frac{\frac{25+24}{25}}{2}} \\ \cos (\frac{\theta}{2})=\sqrt[]{\frac{\frac{49}{25}}{2}} \\ \cos (\frac{\theta}{2})=\sqrt[]{\frac{49}{25\times2}} \\ \cos (\frac{\theta}{2})=\sqrt[]{\frac{49}{50}} \\ \cos (\frac{\theta}{2})=\frac{\sqrt[]{49}}{\sqrt[]{50}} \\ \cos (\frac{\theta}{2})=\frac{7}{\sqrt[]{50}} \\ \cos (\frac{\theta}{2})=\frac{7}{\sqrt[]{50}}\cdot\frac{\sqrt[]{50}}{\sqrt[]{50}} \\ \cos (\frac{\theta}{2})=\frac{7\sqrt[]{50}}{50} \\ \cos (\frac{\theta}{2})=\frac{7\sqrt[]{25\times2}}{50} \\ \cos (\frac{\theta}{2})=\frac{7\cdot\sqrt[]{25}\cdot\sqrt[]{2}}{50} \\ \cos (\frac{\theta}{2})=\frac{7\cdot5\cdot\sqrt[]{2}}{50} \\ \text{Simplify 5/50} \\ \cos (\frac{\theta}{2})=\frac{7\sqrt[]{2}}{10} \end{gathered}[/tex]For each ordered pair, determine whether it is a solution to the sytem of equations.
Answers
Given
We have the system of equations:
[tex]\begin{gathered} 3x\text{ - 2y = -4} \\ 2x\text{ + 5y = -9} \end{gathered}[/tex]The ordered pair that would be a solution to the given system of equations must satisfy both equations. There can only be one ordered pair and this can be obtained by solving the system of equations simultaneously
Using a graphing tool, the plot of the lines is shown below:
The point where the lines intercept is the solution to the system of equations.
Hence the ordered pair that is a solution is (-2, -1)
Answer:
(4,8) - No
(8, -5) - No
(0, 3) - No
(-2, -1) - Yes
A window had a length of 2ft & width of 3ft. What is the area of the window?
Answers
The formula used to calculate the area of the window will be
[tex]\begin{gathered} \text{Area}=l\times w \\ \text{where,} \\ l=2ft \\ w=3ft \end{gathered}[/tex]By substituting the values, we will have
[tex]\begin{gathered} \text{Area}=l\times w \\ \text{Area}=2ft\times3ft \\ \text{Area}=6ft^2 \end{gathered}[/tex]Hence,
The final answer = 6ft²
SOLVE PLEASE -2x^2+18x+____
Answers
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
- 2x² + 18x + _________
Step 02:
(a + b) = a² + 2ab + b²
a² = -2x²
[tex]a\text{ = }\sqrt[]{-2\cdot x^{2}}\text{ = x }\sqrt[]{-2}[/tex][tex]a\text{ = }\sqrt[]{2}i[/tex]2ab = 18x
[tex]2(x\sqrt[\text{ }]{-2)}\cdot\text{ b = 18 x}[/tex][tex]b\text{ = }\frac{18x}{2x\sqrt[]{-2}}=\frac{9}{\sqrt[]{-2}}=\frac{9}{\sqrt[]{2\text{ }}i}[/tex]Two ways to express the solution:
[tex]\begin{gathered} -2x^{2\text{ }}+\text{ 18x + 9/}\sqrt[]{-2} \\ -2x^2+18x\text{ + 9 / }\sqrt[]{2}i \end{gathered}[/tex]How many people were using program 2 but not program 3?
Answers
Let Program 1, Program 2, and Program 3 be represented by P1, P2, and P3.
Given:
n(P1 n P2) = 6
n(P2 n P3) =8
n(P1 n P3) = 5
n(P1 n P2 n P3) = 2
n(P1 U P2' U P3') =18
n(P2) = 22
n(P3 U P1 U P2') = 16
n(P1 U P2 U P3)' = 17
Representing the information on a Venn diagram:
The number of people that were using Program 2 but not Program 3:
[tex]\begin{gathered} n(P_2UP_3^{\prime})=n(P_2)-n(P_2nP_3)\text{ } \\ =\text{ 22 - 8} \\ =\text{ 16} \end{gathered}[/tex]Number of people surveyed
The number of people surveyed is the sum of the individual subsets:
[tex]\begin{gathered} =\text{ 18 + 10 + 13 + 4 + 6 + 3 + }2\text{ + 17} \\ =\text{ 73} \end{gathered}[/tex]Given the following data, find the diameter that represents the 69th percentile.AnswerHow to enter your answer (opens in new window)Diameters of Golf Balls1.531.36 1.69 1.68 1.701.601.601.361.34 1.531.32 1.401.39 1.391.44
Answers
Given that there is a Table given of diameters
What is the approximate diameter of the largest Circle she can make
Answers
We have that the circumference of a circle can be represented with the following equation:
[tex]C=\pi d[/tex]where d represents the diameter of the circle.
In this case, we have a circle of circumference C = 30 ft made with the lights, then, using the equation and solving for d, assuming that pi equals 3.14, we get:
[tex]\begin{gathered} 30=(3.14)d \\ \Rightarrow d=\frac{30}{3.14}=9.55\approx10ft \end{gathered}[/tex]therefore, the approximate diameter of the largest circle is 10 ft
NEED ANSWER ASAP Solve this system of equations:3x - 2y = - 8y= 3/2x - 2I NEED ALL THE STEPS
Answers
Let's solve it by replacing in the first equation.
3x-2y=-8
y=3/2x-2
So,
3x-2(3/2x -2)=-8
3x-3x+4=-8
Graph the following inequalitiesy ≥ -x/4 + 5
Answers
Solution
The graph of the inequality is shown below
How does g(t) = 1/2t change over the interval t = 0 to t = 1?
Answers
we have the equation
[tex]g(t)=\frac{1}{3^t}[/tex]Find out the rate of change over the interval [0,1]
Remember that
the formula to calculate the rate of change is equal to
[tex]\frac{g(b)-g(a)}{b-a}[/tex]In this problem
a=0
b=1
g(a)=g(0)=1
g(b)=g(1)=1/3
therefore
the function decreases by a factor of 315. Graph the rational function ya*-*Both branches of the rational function pass through which quadrant?Quadrant 2Quadrant 3Quadrant 1Quadrant 4
Answers
SOLUTION:
CONCLUSION:
Both branches of the rational function pass through Quadrant 1.
Convert the radical to exponential form. Assume variables represent positive real numbers.
Answers
Exponential Form of Radicals
A radical can be expressed in exponential form by using the equivalence:
[tex]\sqrt[m]{x^n}=x^{\frac{n}{m}}[/tex]We are given the expression:
[tex]\sqrt[4]{16a^4b^3}[/tex]It can be separated into several radicals:
[tex]\sqrt[4]{16a^4b^3}=\sqrt[4]{16}\cdot\sqrt[4]{a^4}\cdot\sqrt[4]{b^3}[/tex]Now we apply the equivalence on each individual radical:
[tex]\begin{gathered} \sqrt[4]{16a^4b^3}=\sqrt[4]{2^4}\cdot\sqrt[4]{a^4}\cdot\sqrt[4]{b^3} \\ \sqrt[4]{16a^4b^3}=2^{\frac{4}{4}}\cdot a^{\frac{4}{4}}\cdot b^{\frac{3}{4}} \end{gathered}[/tex]Simplifying:
[tex]\sqrt[4]{16a^4b^3}=2ab^{\frac{3}{4}}[/tex]Simplify. Final answer should be in standard form NUMBER 18
Answers
4(2 - 3w)(w^2 - 2w + 10) =
(8 - 12w)(w^2 - 2w + 10) =
8w^2 - 16w + 80 - 12w^3 + 24w^2 - 120w =
- 12w^3 + 32w^2 - 123w + 80