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We shall begin by plotting the graph of the equations given which are;
[tex]\begin{gathered} y=\frac{1}{3}x+6 \\ y=-\frac{2}{3}x+3 \end{gathered}[/tex]The black line shows the graph of y = [1/3]x + 6
The red line shows the graph of y = [-2/3]x + 3
The solution to these system of equations is at the point (-3, 5)
Related Questions
solve the equation for all values of x by completing the square. x²+8x=-15
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since (8/2)^2=16, we will add 16 in both sides of the equation, obtaining
[tex]x^2+8x+16=1[/tex]now, we factor the left side of the equation (it's a perfect square)
[tex](x+4)^2=1[/tex]then we have two options or x+4=1 or x+4=-1
solving both of the we have that the values for x are x=-3 and x=-5Write anequivalent expression by distributing thesign outside the parentheses:-(2h + 9.6k) +1
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The given expression is
-(2h + 9.6k) +1
Due to the - sign outside the parentheses, every + sign inside the parentheses would be changed to a - sign. Thus, the expression becomes
- 2h - 9.6k + 1
Leila bought a sofa on sale for $268. This price was 33% less than the original price.What was the original price?
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Let P be the original price.
Since $268 is 33% less than the original price, then $268 is equal to 67% of the original price:
[tex]268=\frac{67}{100}\times P[/tex]Then:
[tex]\begin{gathered} P=\frac{100}{67}\times268 \\ =400 \end{gathered}[/tex]Therefore, the original price was $400.
Answer: $356.44
Step-by-step Explanation: To find the original price of the sofa you need to multiply 33% by $268, but you need to turn the percent into a decimal, to do so you need to divide 33 by 100 & that is 0.33. So 0.33 x $268 is 88.44. After, you add both $268 and $88.44 to get the original price & that is $356.44.
can u help me fix what i did wrong in the equation
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Based on the question, the vertical asymptote is x = -4 and x = 3. This means the denominator cannot have these x-values or else, the function becomes undefined. Hence, from these x-values, we can say that the factors of the denominator are:
[tex](x+4)(x-3)[/tex]Multiplying the factors, we get:
[tex]\begin{gathered} \Rightarrow x^2-3x+4x-12 \\ \Rightarrow x^2+x-12 \end{gathered}[/tex]So, the denominator of our rational function must be x² + x - 12 in order to have those vertical asymptotes.
Another given information is that our x-intercepts are at x = -2 and x = 5. This means that the numerator must be zero at these x-values. Hence, we can say that some factors of the numerator are:
[tex](x+2)(x-5)[/tex]Multiplying these two factors, we get:
[tex]\begin{gathered} \Rightarrow x^2-5x+2x-10 \\ \Rightarrow x^2-3x-10 \end{gathered}[/tex]This means x² - 3x - 10 should be part of our numerator.
Another given information is that the horizontal asymptote is at y = 4. This means that the ratio between the leading coefficients of the numerator and denominator is 4. (since both have the same degree)
So, in order to have a ratio of 4, we will multiply our numerator by 4.
[tex]4(x^2-3x-10)\Rightarrow4x^2-12x-40[/tex]Therefore, our numerator must be 4x² - 12x - 40. And as mentioned above, the denominator must be x² + x - 12. So, the rational function is:
[tex]y=\frac{4x^2-12x-40}{x^2+x-12}[/tex]A spinner with 5 equally sized slices has 2 yellow slices, 2 red slices, and 1 blue slice. Yolanda spun the dial 40 times and got the following results. Answer the following. Round your answer to the nearest thousandth
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Given: A spinner with 5 equally sized slices has 2 yellow slices, 2 red slices, and 1 blue slice.
Yolanda spun the dial 40 times and got Yellow 13 times, Red 13 times and Blue 14 times.
Required:
(a) Experimental probability of landing on Blue or Red
(b) Theoretical probability of landing on Blue or Red
(c) What happens when number of spins increases.
Explanation:
(a) Experimental probability =
[tex]Experimental\text{ Probability = }\frac{Number\text{ of trials in which the event occurs}}{total\text{ number of trials}}[/tex]Here, the event is landing on blue or red.
Number of trials in which Blue or Red occurs is 14+13=27
Total number of trials is 40.
So experimental probability is
[tex]\frac{27}{40}=0.675[/tex]Hence, experimental probability is 0.675.
(b) Theoretical probability is
[tex]Theoretical\text{ Probability = }\frac{Favorable\text{ Outcome}}{total\text{ outcome}}[/tex]Here, favorable outcomes for red and blue = 2+1 = 3.
And total possible outcomes = 5
So theoretical probability is
[tex]\frac{3}{5}=0.6[/tex]Hence, theoretical probability is 0.6.
(c) Now, as the number of spins will increase, number of trials will increase and experimental probability will become more and more precise. Hence, it will come closer to theoretical property. So both probabilities will become closer and closer though they might not be equal.
Final Answer:
(a) 0.675
(b) 0.600
(c) Option 1
Find the volume of a candy corn, assume they are rectangular pyramids with a length of 8.2 mm, a width of 3.5 mm and a height of 20.1 mm
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Given:
Lenght =8.2mm , width = 3.5mm and height = 20.1
The volume of pyramid is given by,
V=1/3 (base area) (height)
As it is rectangular pyramid,
first find area of reactangle . this will be base area for pyramid.
area of reactangle=lenght * weight
[tex]\begin{gathered} A=l\cdot w \\ =8.2\cdot3.5 \\ =28.7\text{ cm}^2 \end{gathered}[/tex]Volume is,
[tex]\begin{gathered} V=\frac{1}{3}\cdot A\cdot h \\ =\frac{1}{3}\cdot28.7\cdot20.1 \\ =192.29\text{ cm}^3 \end{gathered}[/tex]A square with an area of 1 square meter is decomposed into 9 identical small squares. Each small square is decomposed into two identical triangles.
A. What is the area, in square meters, of 6 triangles? If you get stuck, draw a diagram.
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The area of the 6 required triangles is 1/3m².
What are triangles?A polygon with three edges and three vertices is called a triangle. It is one of the fundamental geometric shapes. Triangle ABC is the designation for a triangle with vertices A, B, and C. In Euclidean geometry, any three points that are not collinear produce a distinct triangle and a distinct plane. The seven different kinds of triangles that can be found in nature—equilateral, right isosceles, obtuse isosceles, acute isosceles, right scalene, obtuse scalene, and acute scalene—must be studied and built.So, one square meter is equal to one huge square.
The larger square has now been divided into nine smaller squares.9 tiny square meters of space equals 1 square meter of space.So, using the unitary method, we can discover a single little square.1 tiny square is equal to 1/9 square meter.Each little square now has two similar triangles on each side of it.Now,
One triangle's surface area equals half that of a small square, or (1/2) (1/9) = 1/18 square meters.Using the unitary approach once more, determine the area of 6 triangles.The area of 6 triangles is equal to the 6 * area of 1 triangle, which is:6 * (1/18) = 1/3 square meter.Therefore, the area of the 6 required triangles is 1/3m².
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Translate to a system of equations. Do not solve.Two angles are supplementary. One angle is 4 less than three times the other . Find the measures of the angles l.
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Two angles are supplementary
That means they add to 180
x+y = 180
One angle is 4 less than three times the other
We know that is means equals and less than comes after
x = 3y-4
Sanjay attempts a 50-yard field goal in a football game. For his attempt to be a success, the football needs to pass through the uprights and over the crossbar that is 10 feet above the ground.Sanjay kicks the ball from the ground with an initial velocity of 64 feet per second, at an angle of 34° with the horizontal.Is Sanjay's attempt successful? If not, how many feet too low is the ball?
Answers
Let us draw a sketch to understand the situation
We will use some rules here
[tex]\begin{gathered} v_x=vcos\theta=64cos(34) \\ d_x=v_xt=64cos(34)t \end{gathered}[/tex]Since the horizontal distance is 50 yards
Since 1 yard = 3 feet, then
[tex]d_x=50\times3=150feet[/tex]We will use it to find the time t
[tex]\begin{gathered} d_x=150 \\ 64cos(34)t=150 \\ t=\frac{150}{64cos(34)}\text{ s} \end{gathered}[/tex]Now, we will find the vertical distance (h) by using this rule
[tex]\begin{gathered} v_y=vsin\theta=64sin(34) \\ d_y=h=v_yt-\frac{1}{2}at^2=64sin(34)t-\frac{1}{2}(32)t^2 \end{gathered}[/tex]Note that: a is the acceleration of gravity which is 32 ft/s^2
We will substitute t by its value
[tex]h=64sin(34)(\frac{150}{64cos(34)})-16(\frac{150}{64cos(34)})[/tex]We can simplify it by using sin34/cos34 = tan34, and 1/cos34 = sec34
But I will put it on the calculator to find the final answer
[tex]h=55.94\text{ ft}[/tex]Since the height of the crossbar is 10 feet, then
Sanjay's attempt successful
Bryan invests $500 in an account earning 4% interest that compounds annually. If hemakes no additional deposits or withdrawals, how much will be in the account:1. After 10 years?
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Using the compound interest formula:
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ _{\text{ }} \\ _{} \end{gathered}[/tex]Where:
P = Principal = 500
r = interest rate = 4% = 0.04
n = Number of times interest is compounded per year = 1
t = time = 10
so:
[tex]\begin{gathered} A=500(1+\frac{0.04}{1})^{10\cdot1} \\ A\approx740.12 \end{gathered}[/tex]Answer:
$740.12
With the exception of column one, all amounts are in dollars. Calculate the annual interest rate on this loan. Give your answer to the nearest hundredth percent. Do not include the % sign in your response.
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Given:
Amortization table is given
Let r be the annual rate of interest.
[tex]\frac{r}{12}\text{ be the monthly rate of interest.}[/tex]Second payment:
P= $259873.20 ; interest = $539.24
[tex]\text{Interest for the 2nd payment = }P(\frac{r}{12}\times\frac{1}{100})[/tex][tex]539.24=259873.20(\frac{r}{1200})[/tex][tex]\frac{539.24}{259873.20}\times1200=r[/tex][tex]r=\frac{647088}{259873.20}[/tex][tex]r=2.49[/tex]Therefore, the annula rate of interest is 2.49%
Solve for the remaining angles and side of the two triangles that can be created. Round to the nearest hundredth:B = 30 .b = 6,a = 7AnswerHow to enter your answer (opens in new window) 2 PointsTriangle 1: (where angle A is acute):Triangle 2: (where angle A is obtuse):AA:C =C:C:
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ANSWER:
Triangle 1:
A = 35.69°
C = 114.31°
c = 10.94
Triangle 2:
A = 144.31°
C = 5.69°
c = 1.19
STEP-BY-STEP EXPLANATION:
Given:
B = 30°, b = 6, a = 7
We calculate the angle A by means of the law of sines:
[tex]\begin{gathered} \frac{a}{\sin A}=\frac{b}{\sin B} \\ \\ \text{ We replacing} \\ \\ \frac{7}{\sin A}=\frac{6}{\sin30} \\ \\ \sin A=\frac{7}{6}\cdot\sin30 \\ \\ \sin A=\frac{7}{12} \\ \\ A=\sin^{-1}\left(\frac{7}{12}\right)\: \\ \\ A_{acute}=35.69\degree \\ \\ A_{obtuse}=144.31\degree \end{gathered}[/tex]We calculate the value of angle C, knowing that the sum of all internal angles is equal to 180°
[tex]\begin{gathered} \text{ Acute} \\ \\ 180=35.69+30+C \\ \\ C=180-30-35.69=114.31\degree \\ \\ \text{ Obtuse} \\ \\ 180=144.31+30+C \\ \\ C=180-30-144.31=5.69\degree \end{gathered}[/tex]Side c is also calculated with the law of sines, like this:
[tex]\begin{gathered} \text{ Acute} \\ \\ \frac{b}{\sin B}=\frac{c}{\sin C} \\ \\ \frac{6}{\sin(30)}=\frac{c}{\sin114.31} \\ \\ c=\frac{6}{\sin(30)}\cdot\sin114.31 \\ \\ c=\:10.94 \\ \\ \text{ Obtuse} \\ \\ \frac{7}{\sin(A)}=\frac{c}{\sin(C)} \\ \\ c=\frac{6}{\sin(30)}\sin(5.69) \\ \\ c=1.19 \end{gathered}[/tex]Therefore;
Triangle 1:
A = 35.69°
C = 114.31°
c = 10.94
Triangle 2:
A = 144.31°
C = 5.69°
c = 1.19
The mean of the following data values is 32. 19, 23, 35, 41, 42A. True B. False
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Remember that mean of a set is another name for the average of that set. To find the mean of a data set, add all the values together and divide by the number of values in the set.
Thus, if we have the following set of values: 19, 23, 35, 41, 42, the mean would be:
[tex]\frac{19\text{ + 23 + 35 + 41 + 42}}{5}=\frac{160}{5}=32[/tex]The correct answer:
Answer:TRUE
exponents hwsimplify.
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a) -36 b) 36
1) To simplify those expressions let's expand them to better grasp the result:
[tex]\begin{gathered} -6^2=-1\times6^2=-1\cdot36=-36 \\ \end{gathered}[/tex]When the minus sign is accompanying the number without parentheses, we can read it as -1 times the power. That's why -6²=-1 * 36 = -36
b) For the second power we can write out the following:
[tex](-6)^2=(-6)\cdot(-6)=36[/tex]2) Hence, we can state that the answers are -36 and 36
Use the table. What percentage of the people surveyed were teachers who wanted a later start time?
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The Solution.
The percentage of the people survey that were teachers that voted yes to start later is
[tex]\text{ }\frac{\text{ number of teachers that voted YES}}{\text{ Total number of people surveyed}}\times100[/tex]Which is
[tex]\frac{20}{75}\times100=0.266667\times100=26.6667\approx26.67\text{ \%}[/tex]b. The percentage of the people surveyed that were teachers is
[tex]\frac{\text{ number of teachers surveyed}}{\text{ Total number of people surveyed}}\times100[/tex]Which is
[tex]\frac{30}{75}\times100=0.4\times100=40\text{ \%}[/tex]Hence, the correct answer are:
a. 26.67% b. 40%
What is the image of (2,-3) after a 180 degree counterclockwise rotation about the origin?a. (-3, 2) b.(-2, 3) c. (-3, -2)d.(-2,3)
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Answer:
b.(-2, 3)
Explanation:
A 180 roration transforms the coordinates of a point according to the following rule.
[tex](x,y)\rightarrow(-x,-y)[/tex]For our point (2, -3), applying the above rule gives.
[tex](2,-3)\rightarrow(-2,3)[/tex]Hence, the coordinates of the image are (-2, 3 ) which is choice B.
If AC = 66, find the value of x. Round your answer to the nearest tenth if necessary.AB = 8x - 25BC = 9x - 17
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We need to represent the segments in a like, like in the following image:
From the image we can see that the sum of the segments AB and BC must be equal to the whole
Write an equation in slope-intercept form that contains the points (2, 8) and (4, 9).
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Given two points, the equation of the line in slope form can be obtained using this equation
[tex]\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{y_{}-y_1}{x_{}-x_1}[/tex]Now we can name the points
x1 = 2, y1 = 8
x2 = 4 , y2 =9
These coordinates can then be substituted into the equation
[tex]\frac{9-8}{4-2}\text{ =}\frac{y\text{ - 8}}{x\text{ - 2}}[/tex][tex]\begin{gathered} \frac{1}{2}\text{ = }\frac{y\text{ - 8}}{x\text{ - 2}} \\ \\ x-2\text{ = 2 (y - 8)} \\ \\ x\text{ - 2 = 2y - 16} \end{gathered}[/tex]x - 2 + 16 = 2y
2y = x - 2 +16
2y = x + 14
Divide both sides by 2
y = x/2 + 14/2
[tex]y\text{ = }\frac{x}{2}\text{ + 7}[/tex]This is the equation in slope-intercept form
where the slope = 1/2
SCC Library667737985Based on the graph of this normal distribution,a. The mean isb. The median isThe mode isd. The standard deviation isCheck Answer
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The Solution.
From the graph,
a. The mean = 73
b. The median = 73
c. The mode = 73
d. The standard deviation (S.D) is;
[tex]S.D=73-67=6[/tex]classify the systems of equations as consistent dependent, consistent independent,or inconsistent
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Recall that:
1) A system of 2 equations is inconsistent if both equations represent different parallel lines.
2) A system of 2 equations is consistent dependent if the equations are equivalent.
3) A system of 2 equations is consistent independent if the slopes of both equations are different.
A) Multiplying the second equation by 2 we get:
[tex]\begin{gathered} \frac{1}{2}y\times2=(x-2)\times2, \\ y=2x-4. \end{gathered}[/tex]Notice that the above equation is the same as the first equation, therefore the equations of the first system of equations are equivalent, then the system is consistent dependent.
B) Notice that the slope of both equations is 4, also, notice that the y-intercept of the first equation is (0,2), and the y-intercept of the second equation is (0,-3), therefore the equations of the system of equations represent different parallel lines, then the system is inconsistent.
C) Notice that the slope of the first equation is 5 and the slope of the second one is 6, therefore the system of equations is consistent independent.
Answer:
A) Consistent dependent.
B) Inconsistent.
C) Consistent independent.
please explain briefly..limits and derivatives
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The logarithmic-radical expression √[㏒ₐ f(x)] is true for 0 < f(x) ≤ 1. (Correct choice: D)
What is the domain of a logarithmic-radical function?
Logarithms are trascendent expressions whose domain is described below:
Ran (logₐ f(x)) = (0, + ∞)
Since 0 < a < 1, then we find the following feature: logₐ f(x) > 0 for 0 < f(x) ≤ 1.
In addition, the domain of radical functions is described below:
Dom (√f(x)) = f(x) ≥ 0
Therefore, the logarithmic-radical expression defined in the statement is true for 0 < f(x) ≤ 1.
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Help with question 13 ( the D just represents the word angle )
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Using the law of sines, we would have that:
[tex]\frac{b}{\sin B}=\frac{c}{\sin C}[/tex]Solving for C,
[tex]\begin{gathered} \frac{b}{\sin B}=\frac{c}{\sin C}\rightarrow\frac{\sin C\cdot b}{\sin B}=c\rightarrow\sin C\cdot b=c\cdot\sin B \\ \\ \rightarrow\sin C=\frac{c\cdot\sin B}{b}_{}\rightarrow C=\sin ^{-1}(\frac{c\cdot\sin B}{b}_{}) \end{gathered}[/tex]Plugging in the data given,
[tex]\begin{gathered} C=\sin ^{-1}(\frac{(10.3)\cdot\sin (58.8)}{(10.5)}_{}) \\ \\ \Rightarrow C=57 \end{gathered}[/tex]Therefore, we can conclude that:
trig The last sub-problem of this section stumped me pls help
Answers
For this problem, we are given a triangle and we need to determine its height.
The distance of the UFO from point A is equal to the side c of the triangle, this side forms a right triangle with the height, where the height is the opposite cathetus from angle alpha and side c is the hypothenuse. We can use the sine relationship to determine the height, as shown below:
[tex]\begin{gathered} \sin(87.4)=\frac{h}{425.58}\\ \\ h=425.58\cdot\sin(87.4)\\ \\ h=425.58\cdot0.9989706=425.14 \end{gathered}[/tex]The height is approximately 425.14 km.
How do I solve these?If f(x)=3xsquared + 9x-4 then evaluate the following:f(1)=3x^2+9x-4f(x+h)=3x^2+9x-4
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a) We need to evaluate when x = 1
f(1): this means we will replace x with 1 in the given function
[tex]\begin{gathered} f\mleft(x\mright)=3x^2+9x-4 \\ f\mleft(1\mright)=3(1)^2+9(1)-4 \\ f(1)\text{ = 3(1) + 9 - 4 = 3 + 9 - 4} \\ f(1)\text{ = 8} \end{gathered}[/tex]b) We need to evaluate the function when x = x + h
[tex]\begin{gathered} f\mleft(x\mright)=3x^2+9x-4 \\ f(x\text{ + h): we will replace x with x + h in the given function} \\ f(x+h)=3(x+h)^2\text{ + 9(x + h) - 4} \end{gathered}[/tex]Expanding:
[tex]\begin{gathered} f(x\text{ + h) }=3(x^2+2xh+h^2)\text{ + 9(x + h) - 4} \\ f(x\text{ + h) }=3x^2+6xh+3h^2\text{ + 9x + 9h - 4} \\ \text{Since there are no like terms we can simplify, we can leave it in expanded form:} \\ f(x\text{ + h) }=3x^2+6xh+3h^2\text{ + 9x + 9h - 4} \\ \\ or\text{ the non expanded form:} \\ f(x+h)=3(x+h)^2\text{ + 9(x + h) - 4} \end{gathered}[/tex]Which of the following equations does the graph below represent?
A. 2x + 2y = 8
B. -2x - 2y = 8
C. -2x + y = 8
D. -2x + 2y = 8
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Answer: D
Step-by-step explanation:
The answer is D, as seen on the graph, the Y-Intercept is at Y = 4, and the gradient is 1, so according to the equation y = mx + c,
"m" must equal 1, and "c" must equal 4, so the equation needs to be:
y = x + 4.
In Option D, the equation can be rearranged to 2y = 2x + 8, dividing both the LHS and RHS by 2, we get y = x + 4.
This type of question can be tough at first, however it's just a matter of practice, keep practicing, keep working hard, and you'll be an expert in no time!
There is 1/5 of a foot of ribbon left onthe spool. If Brittany cuts it into 3equal pieces, how long (in feet) willeach piece be?
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We know that
• There is 1/5 of a foot of ribbon.
If Brittany cuts it into 3 equal pieces, we have to divide to find the length of each piece.
[tex]\frac{\frac{1}{5}}{3}=\frac{1}{15}[/tex]Therefore, each piece is 1/15 of a foot long.Order: ABC 175 mg po. Stock ABC 350 mg po scored tablets. How many tablets would patient take per dose?
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The number of tablets that the individual would take per dose would be = 0.5 tablet.
What is a drug?A drug is a substance that is usually prescribed by a physician which when taken has the ability to alter the physiological condition of an individual.
The order or prescribed dosage of the drug ABC = 175mg / dose
The vehicle measurement of the drug = 350mg/tab
If 1 tablet = 350 mg
X tablet = 175 mg
Make X tablet the subject of formula;
X tablet n= 175/350
X tablet = 0.5 tablet or 1/2 tablet.
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Two markers A and B on the same side of a canyon rim are 56 feet apart. A third marker C, located across the rim. is positioned so that BAC = 69º and ABC = 51° Complete parts (a) and (b) below (a) Find the distance between C and A.
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To answer this question, it will be helpful to have a drawing of the situation to find the asked distance:
With this information, it will be easier to have all the information to solve for the distance CA.
Therefore, to find the distance CA, we can apply the Law of Sines, in which we have to find the angle C. We know that the sum of the interior angles of a triangle is equal to 180. Then, we have:
[tex]mNow, we can apply the Law of Sines to find the distance CA:[tex]\frac{AC}{\sin(51)}=\frac{56}{\sin(60)}\Rightarrow AC=\frac{56\cdot\sin (51)}{\sin (60)}[/tex]Then, we have:
[tex]AC=50.2527681652ft[/tex]Then, to round to one decimal place, we have that AC is approximately 50.3 ft.
To find the distance between the two rims, we have:
Now, we can also apply the Law of Sines to find the distance CD (the distance between the two rims):
[tex]\frac{CD}{\sin(69)}=\frac{CA}{\sin(90)}\Rightarrow CD=CA\cdot\sin (69),\sin (90)=1[/tex]Then, we have:
[tex]CD=50.2527681652\cdot\sin (69)\Rightarrow CD=46.9150007363ft[/tex]Therefore, the distance between the two canyon rims (round to one decimal place) is 46.9 ft.
If we take 50.3 ft (for CA), instead, we have 47 ft.
hello I've been stuck on this question and it is a plane trigonometry question hopefully you can help me answer it and thank you for your time
Answers
let us start by writing out our parameters
linear velocity v = 50mi/hr
diameter d = 44 in
[tex]\text{Angular Velocity = }\frac{Angle\text{ turned through}}{\text{time}}[/tex]from the diagram above, let the angle turned through be
14. Factor x4 + 3x2 - 28.(x2 - 7)(x - 2)(x + 2)(x2 - 2)(x2 + 14)(x2 + 7)(x - 2)(x + 2)(x2 + 4)(x2 - 7)
Answers
Answer:
[tex]x^4+3x^2-28=(x^2+7)(x-2)(x+2)[/tex]Step-by-step explanation:
To factorize the expression, we can use a variable substitution. Let's say that z=x^2.
[tex]\begin{gathered} x^4+3x^2-28 \\ z^2+3z-28 \end{gathered}[/tex]Then, to factorize this we need to factor in the form:
[tex](z+\text{?)(z}+\text{?)}[/tex]The numbers that go in the blanks, have to:
*Add together to get 3
[tex]-4+7=3[/tex]*Multiply together to get -28
[tex]-4\cdot7=-28[/tex]So, we get:
[tex]z^2+3z-28=(z-4)(z+7)[/tex]Substitute the equation z=x^2
[tex](x^2-4)(x^2+7)[/tex]Factorizing the perfect square binomial:
[tex]x^4+3x^2-28=(x^2+7)(x-2)(x+2)[/tex]