Many elite runners will train with a speed chute
like the one in the picture. In 1-2 sentences,
explain how wearing a speed chute will change
the net forces acting on the runner. What can be
said about the force the runner is applying if
they run at the same speed with a speed chute
as they did without the speed chute?
You must also provide a reference to a lesson
page that supports your answer in one of the
following ways.
1. As explained in Lesson 4 page 6
2. An electron is a negative a particle

Answers

Answer 1

Elite athletes adhere to a strict training regimen that gradually develops their ability to run longer distances. Furthermore, they frequently run (often 5 to 6 times per week). However, when the conditions are good or they have more time, the average runner might run a lot more.

What kind of speed chute will the top runners use to train?Stride length and cadence both affect running pace. The stride cadence is the quantity of steps taken every second, and the stride length is the amount of ground covered by each step.Therefore, the product of these variables can be used to mathematically characterize the pace of running.Elite runners adhere to a strict training regimen that progressively builds up their ability to run longer distances. Furthermore, they run often (often 5 to 6 times per week). On the other side, when the weather is good or they have extra time, the average runner might run a lot more.In comparison to the average person, professional runners' skin is typically 11 mm thinner.

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Related Questions

compute the warping stress at the edge and at the interior of the slab assuming the temperature differential between top and bottom of slab is 3of per inch of thickness

Answers

During a summer midday, warping strains are produced in reinforced cement concrete pavements that are tensile in the bottom fibre and compressive in the top fibre.

There is a temperature difference between the top and bottom layers

the pavement when it is nighttime because the top surface is colder than the bottom surface. which results in the pavement warping.

Internal tensile tensions form at the top as the top slab attempts to contract but is unable to do so.

bottom-up compression stress

There is a temperature difference between the top and bottom layers of the pavement when it is nighttime because the top surface is colder than the bottom surface. This results in pavement warping

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Amid a summer late morning, warping strains are delivered in strengthened cement concrete asphalts that are ductile within the bottom fibre and compressive within the best fibre.

There may be a temperature contrast between the best and foot layers the asphalt when it is nighttime since the beat surface is colder than the foot surface. which comes about within the asphalt warping. Internal pliable pressures form at the best as the best piece endeavors to contract but is incapable to do so.

bottom-up compression stress There could be a temperature distinction between the beat and foot layers of the asphalt when it is night time since the best surface is colder than the foot surface. This comes about in asphalt distorting

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A 1,100-N crate is being pushed across a level floor at a constant speed by a force of 290 N at an angle of 20.0° below the horizontal, as shown in the figure (a) below.
Image for A 1,100-N crate is being pushed across a level floor at a constant speed by a force of 290 N at an angle of 20
(a) What is the coefficient of kinetic friction between the crate and the floor?
(b) If the 290-N force is instead pulling the block at an angle of 20.0° above the horizontal, as shown in the figure (b), what will be the acceleration of the crate? Assume that the coefficient of friction is the same as that found in part (a).

Answers

For the given values, the acceleration of the block is  0.4 m/s2.

What is the coefficient of friction?

The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing those surfaces from moving. Typically, it is represented by the Greek letter mu (μ). In terms of math, is equal to μ = F/N, where F stands for frictional force and N for normal force.

Given the weight of the crate = 1100

Hence Mass of the crate m = 1100/9.8 = 112.245 kg

a) Since it is moving with a constant velocity, the net force acting on the block is zero

Fnet = 290cos 20 - μ*(290sin20 + 1100)

---> μ =  290cos 20/(290sin20 + 1100) = 0.227

b) Net force acting on the block = 290cos 20 - 0.227*(1100 - 290sin20) = 45.08 N

Acceleration of the block = F/m = 45.08/112.245 = 0.4 m/s2

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. An electron has a de Broglie wavelength of 2.80 *
10-10 m. Determine (a) the magnitude of its momentum and (b) its
kinetic energy (in joules and in electron volts

Answers

The de- Broglie wavelength of 2.80× 10⁻¹⁰ m is associated with a momentum of 2.36 × 10⁻²⁴ Kg m/s. The kinetic energy will be 3.07 × 10⁻¹⁸ J which is equal to 19.015 ev.

What is de-Broglie wavelength?

De-Broglie proposed  the dual nature of matter which stated that matter can behave as both wave and particle. For a matter wave, the wavelength of the wave will be the ratio of the Planck's' constant h and its momentum p.

thus, λ = h/p

Given the wavelength = 2.80× 10⁻¹⁰ m.

momentum p = h/λ

= 6.62 × 10 ⁻³⁴ / (2.80× 10⁻¹⁰ m)

=  2.36 × 10⁻²⁴ Kg m/s

The kinetic energy ke = 1/2 mv² = p² /2m.

mass of an electron = 9.1 × 10 ⁻³⁴ Kg.

hence, Ke =  (2.36 × 10⁻²⁴ Kg m/s )² /  9.1 × 10 ⁻³⁴ Kg

                 = 3.07 × 10⁻¹⁸  J.

1 J = 6.24 × 10¹⁸ ev.

thus, KE in ev = 3.07 × 10⁻¹⁸  J ×  6.24 × 10¹⁸ ev = 19 ev.

Therefore, the kinetic energy of the electron is 19 ev.

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How much heat energy is released when 6.29g of copper cools from 135.0°C to 50.0°C? The specific heat of coppers 0.385 J/g°C. (Include your calculation to receive credit.)

Answers

The amount of heat energy released by the copper of mass 6.29 g is  205.84 J.

What is heat?

Heat is a form of energy that brings about the sensation of warmth

To calculate the amount of heat energy released, we use the formula below.

Formula:

Q = cm(t₂-t₁).................. Equation 1

Where:

Q = Amount of heat releasedc = Specific heat capacity of the copper = 0.385 J/g°Cm = mass of copper = 6.29 gt₂ = Final temperature = 135 °Ct₁ = Initial temperature = 50 °C

Substitute these values into equation 1

Q = 6.29×0.385×(135-50)Q = 205.84 J

Hence, the amount of heat energy released is  205.84 J.

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You have two identical capacitors and an external potential
source. (a) Compare the total energy stored in the capacitors when
they are connected to the applied potential in series and in parallel.
(b) Compare the maximum amount of charge stored in each case.
(c) Energy storage in a capacitor can be limited by the inaximuni
electric field between the plates. What is the ratio of the electric
field for the series and parallel combinations?

Answers

Four times as much energy is retained in the parallel capacitors connection than in the capacitors connection.

What does the word "energy" mean?

People have figured out how to transform energy from one type to the other and use it to accomplish tasks, making modern civilization possible.

Briefing:

Given two identical capacitor

i.e they have the same capacitance C

A) Now for series connection,

1/Ceq=1/C+1/C

1/Ceq=(1+1)/C

1/Ceq=2/C

Then, Ceq=C/2

Ceq=½C

So the energy stored in a capacitor is given as

Us= ½CeqV²

Us=½×½CV²

Us=¼CV²

Now, for parallel connection

Ceq=C+C

Ceq=2C

Then,

Energy is given as

Up=½CeqV²

Up=½×2CV²

Up=CV²

Comparing this to series

Us=¼CV², since CV²=Up

Then, Us=¼Up

Up=4Us

Up/Us=4

As a result, the energy saved in the parallels capacitor connection is four times that of the series capacitor connections.

B) Charges

to connect in series

We are aware that the same charge travels in series. Now that they are the same capacitance and are in series, the voltage differential is V/2, so they will split the voltage.

And the charge is given as

Q=CeqV

Qs=½CV

Qs=½CV for each capacitor

Then the total charge will be

Qs=½CV×2.

Qs=CV

Now, for parallel connection

The charge for parallel is given as

Q=CeqV

Qp=2CV

Now comparing

Qp/Qc=2CV / CV

Qp/Qc=2

The maximum charge of the parallel is four times that of the series again

C) Electric field is given as

E=V/d

Ep=V/d

Due to their identical capacitance, they will split the voltage in a series, where the voltage differential is now V/2.

Es=V/2d.

Then,

Ep/Es=V/d ÷ V/2d

Ep/Es= 2

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If a raindrop forms in the sky and lands on your head 1 min later how high up in the air did the raindrop form?

Round to the nearest whole number.

Answers

The height of the raindrop that forms in the sky and lands on your head 1 minute later is 17640 m.

What is free fall?

Free fall refers to the motion of an object that is at a height above the ground and which is then allowed to fall freely under the influence of gravity.

The motion of an object that is allowed to undergo free fall is given by the equation below:

h = ut + ¹/₂ gt²

where

h is the height of the object above the ground

u is the initial velocity of the object

t is the time taken for the fall

g is the acceleration due to gravity

The height of the raindrop that forms in the sky and lands on your head 1 minute later is calculated using the equation given above:

h = ?

u = 0 m/s

t = 1 minute or 60 seconds

g = 9.8 m/s²

h = 0 * 60 +  ¹/₂ * 9.8 * 60 * 60

h = 17640 m

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An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph

Answers

The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.

What is speed?

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Given that an insect lands 0.1m from the center of the turn table.

Rotational speed of the turn table = 55 rev/min

= (55×2π/60) rad/second

= 5.759 rad/second.

Hence, the speed of the insect be = Rotational speed × length

= 5.759 rad/second × 0.1 M.

= 0.5759 meter/second.

Therefore, the speed of the insect be 0.5759 meter/second.

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If you pull with a constant force of 400n , how much mechanical work does it take to pull pinball launcher back 0.2meters

Answers

If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

What is Work?

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

[tex]Work done(W)=Force(f)*Displacement(d)[/tex]

W = 400 × 0.2

W = 80 J.

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in an ac circuit, which of the following depend on the frequency? select all that applies. group of answer choices inductive reactance resistance capacitive reactance inductance

Answers

The reactance of the inductor and, thus, its impedance would rise as the frequency rose and approached infinity, serving as an open circuit.

what is inductive reactance resistance?

The resistance that the inductive circuit provides is known as inductive reactance. Inductive reactance, then, is the term used to describe an inductor's electrical resistance when it is utilized in an AC circuit.

The inductive reactance X l =ωLWhere: ƒ is the Frequency and L is the Inductance of the Coil and 2πƒ = ω.

Hence, X l ∝ω

As frequency increases →ω

Therefore, inductive reactance increases with frequency.

Following that, it is clear from the inductive reactance equation above that increasing either the frequency or the inductance would result in an increase in the coil's overall inductive reactance value.

The reactance of the inductor and, thus, its impedance would rise as the frequency rose and approached infinity, serving as an open circuit. Inductive reactance is therefore "directly proportional to frequency" and has a low value at low frequencies and a large value at higher frequencies.

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A student is spinning a rubber stopper of unknown mass around his head with a
velocity of 9 m/s that has a centripetal force of 10 N and a radius of 0.75m. It takes
0.50 s to make one revolution. What is the mass of the stopper?

Answers

The mass of the stopper is 92.59 g.

What is centripetal force?

According to the definition of centripetal force, this force is applied to an object moving curvilinearly and is targeted at the axis of rotation or the center of curvature.

Given that:  velocity of the stopper: v = 9 m/s.

Radius of the circle: r = 0.75 m

centripetal force: F = 10 N.

From F = mv²/r; we get:

The mass of the stopper: m = Fr/v²

= (10×0.75)/(9²) kg

= 0.09259 kg

= 92.59 g.

Hence, the mass of it is 92.59 gram.

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1. What is the gravitational attraction force between the earth and the moon? What is the force of gravity between the earth and the sun?

Answers

The gravitational attraction force between the Earth and the Moon is approximately 1.982 × 10^20 Newtons.

The gravitational attraction force between the Earth and the Sun is approximately 3.52 × 10^22 Newtons.

The gravitational attraction between two objects can be calculated using Newton's law of universal gravitation, which states that the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. The equation for the gravitational force (F) is given by:

F = (G * m1 * m2) / r^2

Where:

F is the gravitational force between the objects,

G is the gravitational constant (approximately 6.67430 × 10^-11 m^3 kg^-1 s^-2),

m1 and m2 are the masses of the two objects, and

r is the distance between the centers of the two objects.

Gravitational attraction between Earth and Moon:

The mass of the Earth is approximately 5.972 × 10^24 kg, and the mass of the Moon is approximately 7.342 × 10^22 kg. The average distance between the Earth and the Moon is about 384,400 kilometers (or 384,400,000 meters).

Plugging in these values into the equation, we can calculate the gravitational attraction force between the Earth and the Moon:

F = (G * m1 * m2) / r^2

= (6.67430 × 10^-11 * 5.972 × 10^24 * 7.342 × 10^22) / (384,400,000)^2

Calculating this, we find that the gravitational attraction force between the Earth and the Moon is approximately 1.982 × 10^20 Newtons.

Gravitational attraction between Earth and Sun:

The mass of the Sun is about 1.989 × 10^30 kg, and the average distance between the Earth and the Sun (known as an astronomical unit or AU) is about 149.6 million kilometers (or 149,600,000,000 meters).

Using the same equation as above:

F = (G * m1 * m2) / r^2

= (6.67430 × 10^-11 * 5.972 × 10^24 * 1.989 × 10^30) / (149,600,000,000)^2

Calculating this, we find that the gravitational attraction force between the Earth and the Sun is approximately 3.52 × 10^22 Newtons.

With a 9.0 voltage battery connected with two resistors, one is 10 ohms and the other resistor is at 20 ohms, what is the voltage drop across the battery?

A) -1.00v
B) -3.00v
C) -9.00v
D) -12.00v

Answers

With a 9.0 voltage battery connected with two resistors, one is 10 ohms and the other resistor is at 20 ohms the voltage drop across the battery 1 volt. Thus, option A is correct.

What will be the voltage supplied?

Given data

voltage supplied Vs= 1.5 volts

resistance R1= 1000 ohms

resistance R2= 500 ohms

The total resistance is

Rt= 1000+ 500

Rt= 1500 ohms

In series connection the current is the same for all components while the voltage divides across all components,the voltages consumed by each individual resistance is equal to the source voltage.

Therefore, With a 9.0 voltage battery connected with two resistors, one is 10 ohms and the other resistor is at 20 ohms the voltage drop across the battery 1 volt. Thus, option A is correct.

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Calculate the components of strain energy density on the surface of a steel shaft with a diameter of 120 mm, when it is subjected to a torque T-20 kN.m and a moment M-15 kN.m at its free ends. Use E = 200 GPa and v=0.25 for the material properties.

Answers

When the atoms that make up a molecule are permitted to rearrange themselves during a chemical process, strain energy is released. Strain energy, a type of potential energy, is created when an elastic element undergoes external effort that causes it to deform from its unstressed state.

The strain energy formula is what?

The area under the stress-strain curve near the site of deformation and strain energy density are two terms describing the amount of strain energy per unit volume. The entire system returns to its original shape after the force is released. Usual abbreviation is U. U = F / 2 is the formula for strain energy.

What are the five different strains?

There are four basic types of strain that are often identified by the direction in which forces are applied. The four strain types are shear strain, volumetric strain, lateral strain, and longitudinal strain.

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! HELP !
look at the image and read the passage before the questions for better understanding : )

questions :
(choose the correct answer - a , b , or c . )
1. the engineering students install flaps that extend off the cargo load to maximize drag force during landing and prevent their cargo from opening on landing. which statement explains why the flaps would be helpful in preventing damage upon landing?
a. the flaps increase the mass of the cargo
b. the flaps reduce the impulse of the cargo
c. the flaps reduce the momentum of the cargo

(for this one, choose out of the options which is the best fit for the paragraph.)
2. at terminal velocity, the parachute will produce a drag force (a. less than b. greater than c. equal to) the weight of the cargo to stop it from accelerating toward the ground. for the cargo parachute system to work properly, the parachute should be made large enough to (c. minimize d. maximize) the drag force. the parachute will reduce the momentum of the cargo by reducing its (e. velocity f. impulse).

(choose either a, b, or c.)
3. a student makes a prototype of the parachute system. he wants to test the parachute's effectiveness in assuring a safe landing. select all of the variables that should be measured for his experiment.
a. weight of the cargo
b. the velocity of the plane
c. size of the parachute

Answers

The flaps increase the mass of the cargo as the engineering students install flaps that extend off the cargo load to maximize drag force during landing and prevent their cargo from opening on landing.

What Newton's second law states?

Newton's second law states that force is proportional to mass and acceleration.

F = m a

The applied force creates an acceleration in the elephant a = F / m. If the mass of the elephant increases m2> m, the expression takes the form a = F / m2. With the denominator is greater the acceleration should decrease by the same factor that increases the mass.

The frequency of a wave depends on the properties of medium density and the elasticity properties change the amplitude depends on the energy carried by the wave, that is, the amplitude is proportional to the height of the wave (oscillation).

Therefore, The flaps increase the mass of the cargo as the engineering students install flaps that extend off the cargo load to maximize drag force during landing and prevent their cargo from opening on landing.

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NEED HELP URGENT An object is thrown vertically up in the air. Its initial velocity is 6 m/s. What is the object's maximum height? (use g=9.8 m/s^2)

Answers

5m/s because 1-1 is the answer because no it storm and yea

The picture below shows the Apollo 11 spacecraft that took astronauts to the Moon in 1969. The spacecraft weighed 6.1 million pounds, and its motors produced 7.5 million pounds of thrust. Use the picture to answer any questions that follow.
answer choices
The spacecraft produced an upward force of thrust that was equal to the downward force of gravity.
The spacecraft produced an upward force of thrust that was greater than the downward force of gravity.
The spacecraft produced a downward force of thrust that was equal to the downward force of gravity.
The spacecraft produced a downward force of thrust that was less than the downward force of gravity.

Answers

The spacecraft generated an upward push force higher than the gravitational pull to the earth's surface.

What is Apollo11?

On July 16, 1969, Apollo 11 lifted off from Cape Kennedy with Commander Neil Armstrong, Pilot of the Command Module Michael Collins, and Pilot of the Lunar Module Edwin "Buzz" Aldrin aboard. They were sent into an initial orbit of 114 by 116 miles around the Earth. On July 20, 1969, Armstrong took "...one modest step for a man, one giant leap for mankind," as he said in a televised visual and audio broadcast seen by an estimated 650 million people.

A rocket will take off and continue to accelerate so long as the force thrusting it upwards is stronger than the forces pulling and thrusting it downwards (gravity and drag).

We can better grasp how forces cause objects, like rockets, to move thanks to Newton's first law. Unless an imbalanced force acts upon a stationary object, it will stay stationary. A moving object will also keep moving in a straight line at a steady speed unless it is being affected by an unbalanced force.

When the upward thrust force of a rocket is higher than the downward weight force of gravity, the rocket will launch. A rocket accelerates upward due to this imbalanced force. As long as there is an upward force produced by the thrust of the rocket engine, a rocket will continue to accelerate.

An imbalanced force is required for an object to begin moving. The forces pulling an object in one way are greater than the forces pushing it in the opposing direction, according to this definition. The imbalanced force, also known as the resultant force, is the difference between the forces pushing in one direction and the opposite direction.

At the moment of liftoff, a rocket is subject to two forces:

By forcing gases downward in the opposite direction, thrust propels the rocket higher.

Weight is the gravitational force that pulls the rocket down and toward the centre of the Earth. 9.8 newtons (N) of weight are present for every kilogramme of mass.

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Answer:

The spacecraft produced an upward force of thrust that was greater than the downward force of gravity.

Explanation:

which rock name is best for the sample in the photograph? you can scratch this rock with your fingernail. it feels soapy. (not in rock kit)

Answers

The sample of rock in the photograph (attached below) which feels soapy and could be scratched with our fingernail is called: talc mineral.

What is Talc mineral?

Talc is the softest mineral (rock) we can find on Earth. Talc composes of magnesium silicate and is most often found in the metamorphic rocks of the convergent plate. We can scratch this rock with our fingernails and it can even be crushed to form a white powder. In powder form, it can absorb moisture, oils, and odor, and could be used as a lubricant. Talc mineral is widely known as a soapstone as in its rock form, talc feels soapy.

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the two forces to the right are friction which one would be the force of kinetic friction?

Answers

Answer:

40 N

Explanation:

Both forces to the right are friction forces.  The 40 N force has to be the kinetic friction force because kinetic friction is always less than static friction.  So, the 80 N force has to be the static friction force, which is always greater than the kinetic friction.

Which statement best explains the backward motion of the boat as the person moves forward?
A.Every mass exerts a force on every other mass.

B. An object at rest tends to stay at rest.

C.Friction opposes the motion of an object.

D. For every action there is an equal and opposite reaction.

Answers

According to Newton's third law, For every action there is an equal and opposite reaction.

What is the change in momentum of a baseball that experiences a 15 N force over 0.3 s
during a collision with a bat?

Answers

The product of the change in velocity and the change in mass is the change in momentum. Because its value is constant, the mass does not change.

Δp = m Δvwhere p is the change in momentum, m is the mass, and v is the change in the object's velocity.

When a baseball bat hits a ball, what happens to its momentum?

The ball flies off in the opposite direction from where it came from, as is typical of ball-bat collisions. If we make the bat weigh 25 ounces, if we swing it at the same speed, we get a significant boost in bat momentum, which raises the ball's exit velocity.

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A rectangle measuring 30.0 cm by 40.0 cm is located inside a region of a spatially uniform magnetic field of 1.25 T , with the field perpendicular to the plane of the coil (the figure (Figure 1) ). The coil is pulled out at a steady rate of 2.00 cm/s traveling perpendicular to the field lines. The region of the field ends abruptly as shown.
A rectangle measuring 30.0 cm by 40.0 cm is locate
A) Find the emf induced in this coil when it is all inside the field.
B) Find the emf induced in this coil when it is partly inside the field.
C) Find the emf induced in this coil when it is all outside the field.

Answers

The induced emf of the coil is 0, 0.0132V, 0, respectively.

(A) Generally, the equation for the flux is  mathematically given as

ε = BA = B(30×40×1/10⁴)

So, the magnetic flux through the coil is constant.

From Faraday's law, ε = - d/dt B ---(1) for the induced emf.

Since magnetic flux is constant, LHS. of (1) =0

Induced emf=0

(B) Let x be the length of the coil's magnetic field area.

induced emf=B(40×x×1/10⁴)

=0.0132V

(C) In conclusion, Therefore, there is no variation in the magnetic flux across the coil when magnetic flux=0.

induced emf=0

What is magnetic flux?

Magnetic flux through a surface—when the magnetic field is variable—relies on dividing the surface into small surface elements over which the magnetic field can be considered locally constant. The total flow is then the formal sum of these surface elements.

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A U-tube of constant cross-sectional area, open to the atmosphere, is partially filled with a heavy liquid with density 9.17 g/cm3 . A light liquid with density 2.13 g/cm3 is then poured into both arms.
If the equilibrium configuration of the tube is as shown, with a difference in the height of the heavy liquid of 1.1 cm, determine the value of the difference in height of the light liquid hℓ . Answer in units of cm.

Answers

The area of a two-dimensional shape created when a three-dimensional object, like a cylinder, is cut perpendicular to a predetermined axis at a point is known as the cross-sectional area. For instance, a cylinder's cross-section is a circle when it is cut parallel to the base.

A uniform cross section is what?

A cross section that is the same size and shape is said to have a uniform cross section. For instance, if a cube-shaped box were to be cut vertically, each cut would have the same uniform shape of a square. Every cross section taken parallel to the base of a tree's base would be uniformly shaped like a circle if the tree were a perfect cylinder.

What is the equation for a cylinder's cross-sectional area?

Assuming the provided cylinder has a height of 25 cm and a radius of 4 cm, calculate its cross-sectional area. We are aware that a circle-shaped cross-section results from cutting the cylinder parallel to the base. The area of a circle is therefore A = r2 square units.

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An ideal gas undergoes a process during which the
pressure is kept directly proportional to the volume, so that p = aV,
where a is a positive constant. If the volume changes from V1 to V2,
how much work is done by the gas? Express your answer in terms of
V1, V2, and a.

Answers

If the volume changes in an ideal gas from V1 to V2, that has p = aV. Then the work done by the gas is W = a [(V₂²-V₁²)÷2].

The work done on a system is a measure of the energy transferred from the system to the surroundings or vice versa.

Work Formulation:  W = pΔV = p(V₂ - V₁)

The formula W = pΔV can only be used to calculate the work of a gas at constant pressure (isobaric process).

If the gas pressure changes, the work W must be calculated in an integral way. In general, work is calculated by the following integral equation.

                                    W = ∫p dV

The work done by a gas system undergoing a cyclical process (its p-V graph is given) is equal to the area loaded by the cycle.

The pressure function p = aV

The initial volume of the gas is V₁

The final volume of the gas is V₂

The equation for the work done can be given by,

[tex]W = \int\limits^{v_2}_{v_1} {pd}V[/tex]

Substitute the pressure value given in the problem to find the work done by the gas.

[tex]W = \int\limits^{v_2}_{v_1} {aV}dVW[/tex]

[tex]W = a\int\limits^{v_2}_{v_1} {V}dVW[/tex]

[tex]W = a{ [\frac{v^2}{2} ]}^{v_2}_{v_1}[/tex]

[tex]W = a[\frac{V_2^2-V^2_1}{2} ][/tex]

Then the work done by the gas is  [tex]a[\frac{V_2^2-V^2_1}{2} ][/tex]

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A 7.00kg bowling ball moves at 3,00m/s. How much kinetic energy does the bowling ball have?​

Answers

four..................

Vocabulary Terms - Define the following terms
1. Scalar-
2. Vector-
3. Magnitude-
4.1 Vectors in Physics Worksheet
4. Vector Components-
Conceptual Questions
5. What distinguishes a vector from a scalar?
6. What does the magnitude of a vector refer to?

Answers

Answer:
1. Scalar- a physical quantity that is completely described by its magnitude
2. Vector- a vector is a variable quantity, such as force, that has size and derection
3. Magnitude- large size or great importance.
4. Vector Components- allow us to break a single vector quad tity into two (or more) scalar quantities with which we have more mathematical experience
5. What distinguishes a vector from a scalar?
Ans: Vectors have magnitude and derection, scalars only have magnitude.
6. What does the magnitude of a vector refer to?
Ans: the magnitude of a vector is the length of a vector. The magnitude of the vector a is denoted as ||a||

Explanation:
Hopes it help


which of the following modifications did maxwell have to include in the modified version of ampere's law to make it valid for all situations?

Answers

Option A. Introducing a displacement current. Maxwell had to introduce a displacement current in the modified version of Ampere's Law in order to make it valid for all situations.

Introducing a Displacement Current in Ampere's Law

The displacement current is a modification to the traditional Ampere's Law that takes into account the changing electric field due to changing magnetic fields. Maxwell's modification was necessary to account for the effect of electromagnetic waves, making the law applicable in all situations. This displacement current is related to the Faraday Law, as it is required for the conservation of charge.

Since the question is not complete, here's the full task:

Which of the following modifications did Maxwell have to include in the modified version of ampere's law to make it valid for all situations?

Give me the options:

A. Introducing a displacement currentB. Introducing a vector potentialC. Introducing a magnetic fieldD. Introducing a Faraday law

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If 80 Joules were necessary to move a 12 N crate, how far was the crate moved?

Answers

Main answer

Work Done = Force x Displacement

W= F x S

80=12 x S

S=80/12

S=6.67 m

Supporting Details

Here, Work Done is a form of energy given in joules which is equal to the force required to move an object in a given time period. Here the SI unit of Work Done(energy) is Joules, Force is Newton and displacement is meters.

      So, we simply substitute the values given to us in the question and find the value of S. So after transposing 12 to the left-hand side and dividing by 12, we finally get the distance moved by the crate (according to the question ) as 6.67 m

Internal Link

The displacement of the crate is given as :

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If you drive west at 40 mph for 2.5 hours how far would u travel

Answers

Answer:

100 Miles

Explanation:

If...

40 miles x 2.5 is 100

Then...

It travels 100 miles in 2.5 hours!

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URGENT PLS HELP A moon of mass m orbits a planet of mass M in uniform circular motion with a constant tangential velocity. The distance between the center of the moon and the center of the planet is R. The gravitational field strength at the center of the moon is Gmoon. A satellite of mass m/5 is halfway between the center of the moon and the center of the planet. What is the gravitational field strength at the satellite?

Answers

The gravitational field strength at the satellite is 80 % of the gravitational field strength at the center of the moon.

What is the gravitational field of the moon?

The gravitational field strength of the moon is calculated as follows;

G. moon = F/M

where;

F is the gravitational forcem is mass

F = GMM/R²

G. moon = F/M

G. moon = GM/R²

Where;

G is universal gravitational constantM is the mass of the moonR is the radius of the moon

For a satellite with the following characteristics;

mass of satellite = M/5

distance of the satellite = R/2

G. S = G (M/5) / (¹/₂R)²

G. S = G (M/5) / (¹/₄R²)

G. S = 4GM / 5R²

G. S = 4/5 ( GM/R² )

G. S = 0.8 ( GM/R² )

G. S = 0.8 ( G. moon )

G. S = 80 % of G. moon

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TRUE/FALSE. the magnetic force on a charged particle in a magnetic field is a maximum if the particle is stationary.

Answers

The aforementioned claim is untrue

because

the stationary nature of the particle implies or proves that its velocity is zero. Therefore, the magnetic force acting on the charged particle is neither maximum nor zero.

In a magnetic field, there is charge:

Both the electric and magnetic fields can affect how a charge behaves. A magnetic field can exert force on a charged particle if it is present in an area of the field.

The magnetic field's strength is determined by:

the particle's charge.

the speed of the particle.

the field of magnetism.

the relationship between the magnetic field and the charge's speed.

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