Answers
We accept the claim. This comes from the fact that if there is no mechanical assistance after point A (that is the tallest) then we make sure that the potential energy converts in kinetic energy and that way we make sure that the rollercoaester reaches all the other hills. If the tallest point is not the first one and there's no mechanical assitances then the rollercoester won't reach the hills that are taller than the first one (the kinetic energy won't be enough to reach it).
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A ball is thrown upward from an initial height of 2 meters. The ball reaches a height of 5 meters then falls to the ground. What is the total distance traveled by the ball?
Answers
We will have the following:
First, we find the distance it traveled upward:
[tex]d_u=5m[/tex]Now, we find the distance it traveled to the ground:
[tex]d_d=5m+2m\Rightarrow d_d=7m[/tex]Now, the total distance is:
[tex]d_T=d_u+d_{\text{d}}\Rightarrow d_T=5m+7m[/tex][tex]\Rightarrow d_T=12m[/tex]So, the ball traveled a total of 12 meters.
A box weighing 100 newtons is pushed up an inclined plane that is 5 meters long. It takes a force of 75 newtons to push it to the top, which has a height of 3 meters. Work Output? Work Input? Efficiency?
Answers
The work output can be given as,
[tex]W_O=Fh[/tex]Substitute the known values,
[tex]\begin{gathered} W_O=(75\text{ N)(3 m)(}\frac{1\text{ J}}{1\text{ Nm}}) \\ =225\text{ J} \end{gathered}[/tex]Thus, the work output of the procedure is 225 J.
The work input of the procedure is,
[tex]W_i=wd[/tex]Substitute the known values,
[tex]\begin{gathered} W_i=(100\text{ N)(5 m)(}\frac{1\text{ J}}{1\text{ Nm}}) \\ =500\text{ J} \end{gathered}[/tex]Thus, the work input of the procedure is 225 J.
The efficiency of the work done is given as,
[tex]e=\frac{W_O}{W_i}[/tex]Substitute the known values,
[tex]\begin{gathered} e=\frac{225\text{ J}}{500\text{ J}} \\ =0.45 \end{gathered}[/tex]Thus, the efficiency of procedure is 0.45 or 45%.
3x5 - 2^2 - can you help me solve this?
Answers
Given, 3×5-2²
The multiplication operator precedes a subtraction operator. Thus the multiplication is performed before the subtraction is performed.
Thus,
[tex]\begin{gathered} 3\times5-2^2 \\ =15-4 \\ =11 \end{gathered}[/tex]Thus the answer we get after solving the given equation is 11.
Answer:11
Explanation:2 to the second =4. 3 times 5 equals 15. 15-4=11
The virtual image of a lens is always on the same side of the lens as the object. Is this true or false?
Answers
The lens follows the law of refraction to form an image of the object.
Thus, for the formation of real image, the image should be formed on the opposite side of the lens.
The virtual image is formed when the image is on the same side of the lens as where the object is present.
Thus, the given statement is true.
Mass is the quantity of matter an object has. Is this true or false?
Answers
The mass of the object is the amount of matter present in the object.
Thus, the mass of the object does not change with the gravity or any other force unless the matter is removed from the object.
Hence, the given statement is true.
Each set of protons and electrons represents a different atom. Place theatoms in order of their overall charge. Order them from most positive to mostnegative.1 30 protons, 26 electrons11 17 protons, 10 electrons10 protons, 10 electrons12 protons, 11 electrons
Answers
Firstly, we need to remember how to find the liquid charge for a single atom. We can start by saying that
[tex]Q=n_pq_p+n_eq_e[/tex]Where Q is the total charge, np is the number of protons, qp is the charge of a proton, ne is the number of electrons and qe is the charge of an electron
As we know, the charge of an electron is the opposite of the proton's. If we consider it as -1 and 1, respectively, we're left with
[tex]Q=n_p-n_e[/tex]Then, let us find the charge for each atom.
So, for our atoms, we have
[tex]Q_1=30-26=4[/tex][tex]Q_2=17-10=7[/tex][tex]Q_3=10-10=0[/tex][tex]Q_4=12-11=1[/tex]Then, our answer is
[tex]Q_2>Q_1>Q_4>Q_3[/tex]Why are quarks important to physics and to the real, modern world?
Answers
Because Quarks are the fundamental building blocks of the universe.
Quark is any member of a group of elementary subatomic particles that interact by means of a strong force and are a fundamental constituent of matter.
A pumpkin pie in a 10.50 in diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the pie plate moves through a distance of 258 in. Express the angular distance that the pie plate has moved through in revolutions, radians, and degrees.
Answers
The angular distance traveled in degree, radian and revolution are : 49°, 0.273 radian and 0.14 revolution respectively
What is angular velocity?The angular distance traveled around a circular path is the number of radians the path subtends.It can also be defined as the angle made by a body while moving in a circular path.
From the definition, angular distance (theta) = distance moved/radius.
radius = diameter/2
radius= 10.50/2= 5.25inches
angular distance= 258/5.25= 49.14°
in revolution , = 49.14/360=0.14 revolution
in radian ,= 49.14/180= 0.273radian
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A motion detector detected that a toy car covered 2 m at a constant speed of 0.25 m/s. Sketchthe graph to represent the motion of an obiect.
Answers
Explanation
the function for the distance is given by
[tex]\text{distance}=\text{ sp}eed\cdot time\text{ }[/tex]then, let
speed= 0.25 m/s
time= t
distance= 2m
hence, replace
[tex]\begin{gathered} \text{distance}=\text{ sp}eed\cdot time\text{ } \\ \text{distance}=0.25\frac{m}{s}\cdot t \\ d(t)=0.25t\Rightarrow equation\text{ of the line} \end{gathered}[/tex]Step 2
now, to graph the line we need 2 points
a) when t= 0
[tex]\begin{gathered} d(t)=0.25t\Rightarrow equation\text{ of the line} \\ d(0)=0.25\cdot0 \\ d(0)=0 \\ so \\ \text{coordinate 1(0,0)} \end{gathered}[/tex]P1(0,0)
b) when the car has covered 2m
let d=2
replace and solve for x
[tex]\begin{gathered} d(t)=0.25t\Rightarrow equation\text{ of the line} \\ 2=0.25t \\ \text{divide both sides by 0.25} \\ \frac{2}{0.25}=\frac{0.25t}{0.25} \\ 8=t \\ \text{hence, after 8 seconds, the distance is 2 m, so the coordinate is} \\ (8,2) \end{gathered}[/tex]P2(8,2)
finally, draw a line that passes through the point P1(0,0) and P2(8,2)
I hope this helps you
If the average kinetic energy of the molecules in an ideal gas initially at 26 degrees celsius doubles, which of the following is the final temperature of the gas?325 degrees Celsius, 554 degrees Celsius, 52
Answers
We will have the following:
The final termperature should then be 52 °C.
Describe how a convex lens could be used to make a magnifying lens.
Answers
Explanation and Answer:
when the object is placed between the optical center and the first focal point of the convex lens. its image is formed on the same side where the object is placed. the image is erect, magnified, and virtual.
we can see the ray diagram to understand it better,
as we can see from the ray diagram, a convex lens is used as a magnifying lens.
The image formed is larger than the original object.
if the object is placed between the first focal and the optical center. the image formed is larger than the object. the formed image is erect, virtual, and magnified. This way convex lens work as a magnifying lens.
9. In this time interval, what is the vehicle's displacement? (In case it is difficult tosee... at the beginning, t=0s and x=Om at the end t=5s and x=1m)
Answers
The term displacement is simply as the distance between the initial position and the final position. It can be measured or calculated in meters
The displacement from the given position is calculated as
[tex]\begin{gathered} d=1-0 \\ =1\text{ m} \end{gathered}[/tex]Hence, the vehicle's displacement is d = 1 m
What is the voltage of a circuit that has a resistance of 100 and an internal current of 2 amps 200 volts0 0.02 voltsO 50 volts
Answers
Given,
The resistance of the circuit, R=100 Ω
The current in the circuit, I = 2 A
From Ohm's law, we have,
[tex]V=IR[/tex]Where V is the voltage.
On substituting the known values,
[tex]V=2\times100=200\text{ V}[/tex]Thus the voltage of the internal circuit is 200 V.
That is the correct answer is the 1st option.
If it takes 299 calories to melt a mass of ice into water at a temperature of zero degrees Celsius then what was the mass of the ice in grams? A)0.0471 B)3.75 C)161000
Answers
Given:
The heat absorbed by ice to melt into water is Q = 299 calories.
To find the mass of the ice in grams.
Explanation:
When the ice starts melting into water, the temperature of the system does not change, all the heat provided to the system is used up to convert the ice to water. This is known as latent heat of fusion.
The latent heat of fusion for water is
[tex]L_f=79.8\text{ cal/g}[/tex]The formula to calculate mass is
[tex]Q=mL_f[/tex]Substituting the values, the mass will be
[tex]\begin{gathered} m=\frac{Q}{L_f} \\ =\frac{299}{79.8} \\ =3.75\text{ g} \end{gathered}[/tex]Final Answer: The mass of ice is 3.75 g
If I am finding the x component of acceleration and it’s m/s^3, would the answer be m/s^3
Answers
No, the aceleration is alwas m/s^2
If you have something in m/s^3, probablly you are missing a multiplication times the time or maybe you have to integrated the function
[tex]y^{\prime}\left(t\right)=\frac{0.018m}{s^2}[/tex]
A stone is dropped down a well. When it hits the bottom of the well it is travelling at 20 m/s. The mass of the stone is 0.02 kg.
a. Calculate the kinetic energy of the stone as it hits the bottom of the well.
b. What is the gravitational potential energy of the stone at the top of the well?
c. Calculate the height of the well.
Answers
I need help finding the area for these acceleration time graphs problem C.
Answers
We are given that an object starts with an initial velocity of 5 m/s and that we are required to determine its velocity after 2 seconds. We are given the area of acceleration vs time. In a graph of acceleration vs time, the area under the curve represents the velocity of the object under the given acceleration.
We can determine the velocity reached by the object between t = 0 and t = 2 finding the area under the curve. Since the acceleration is constant the area under the curve is a square, therefore:
[tex]v=(2\frac{m}{s^2})(2s)=4\frac{m}{s}[/tex]This is the velocity after the object starts accelerating the final velocity is determined by adding the initial velocity therefore, the final velocity is:
[tex]v_f=4\frac{m}{s}+5\frac{m}{s}=9\frac{m}{s}[/tex]
Lola has a two-year lease that requires her to pay $295 rent per month.What is the total amount she will pay for rent during the term of herlease?a. $3,540b. $8,850c. $885d. $7,080
Answers
If the price that needs to be paid per month is $295, first let's convert the total amount of time (2 years) to months.
1 year has 12 months, therefore 2 years have 24 months.
Now, to find the total amount, let's multiply the cost per month by the number of months:
[tex]295\cdot24=7080[/tex]Therefore the total amount is $7,080. Correct option: d.
Consider an airless, non-rotating planet of mass M and radius R. and electromagnetic launcher standing on the surface of this planet shoots a projectile with initial velocity v0 directed straight up. Unfortunately, due to some error, v0 is less than the planet's escape velocity ve; specifically, v0 = 0.762ve. Unable to escape the planet's gravitational pull, the projectile rises to a maximal height h above the ground, then falls back to the ground. Calculate the ratio h/R of the projectile's maximum height to the planet's radius.
Answers
Given data:
The mass of planet is M.
The radius of planet is R.
The initial velocity of projectile is v₀=0.762ve.
The amount of kinetic and potential energy should be equal according to conservation of energy,
[tex]\begin{gathered} KE=PE \\ \frac{1}{2}mv^2_e=\frac{GMm}{R}^{}_{} \\ R=\frac{GM^{}_{}}{v^2_e} \end{gathered}[/tex]The escape velocity is given by,
[tex]v_e=\sqrt[]{\frac{2GR}{M}}[/tex]Here, G is the universal gravitational acceleration.
The time taken to reach the maximum height will be,
[tex]\begin{gathered} v_0=gt \\ t=\frac{v_0}{g} \end{gathered}[/tex]The maximum height reached by the projectile is given by,
[tex]\begin{gathered} h=v_0t+\frac{1}{2}gt^2 \\ h=v_0(\frac{v_0}{g})+\frac{1}{2}g(\frac{v_0}{g})^2 \\ h=\frac{v^2_0}{g}_{}+\frac{1}{2}\frac{v^2_0}{g}_{} \\ h=\frac{3}{2}\frac{v^2_0}{g}_{} \\ h=\frac{3}{2}R \\ \frac{h}{R}=1.5 \end{gathered}[/tex]Answer:
1.39
Explanation:
(1/2)mVe^2=(mMG)/R
Ve^2=2MG/R
(1/2)mVo^2=mMG(1/R-1/(R+h))=mMG(h/(R^2+Rh))
Vo^2=2MG(1/R)(h/(R+h))
Vo^2=Ve^2(h/(R+h))
Vo^2/Ve^2=h/(R+h)
Ve^2/Vo^2=(R+h)/h
1/.762^2=(R+h)/h
1.72h-h=R
.72h=R
h/R=h/.72h
h/R=1.39
It took 89.5 degrees to stop the wheel from 47.8 rpm. What is the angular acceleration? (Please give a negative number)
Answers
8 rad/s^2 is the angular acceleration when It took 89.5 degrees to stop the wheel from 47.8 rpm.
θ =89.5=1,562 radian
Wf= 5 rad
Wi=0
2αθ=Wf^2-Wi^2
α=(Wf^2-Wi^2)÷2θ
α=8 rad/s^2
The rate at which the angular velocity alters over time in a circular motion is known as the angular acceleration. Rotational acceleration is another name for it. It has both magnitude and direction, making it a vector quantity. The symbol for angular acceleration is alpha.
Variable velocity is the cause of acceleration. If an item is rotating and changing speed, we refer to it as angular acceleration. According to the connection, the angular displacement of an item rotating depends on time t. Any time a body spins, there is angular acceleration. A quantitative vector can be used to indicate the change in angular velocity per unit of time.
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A serving size of Lays Potato Chips is 15 chips. There are 160 calories in one serving and 10 grams of fat. If you eat two servings how many calories and grams of fat are there? Question 5 options: 320 calories, 20 gram of fat 160 calories, 10 grams of fat 340 calories, 15 grams of fat 325 calories, 25 grams of fat
Answers
If you eat two servings of Lays Potato Chips, you would have consumed 320 calories and 20 gram of fat.
One serving of Lays Potato Chips = 15 chips
Calories in one serving of Lays Potato Chips = 160 cal
Fat in one serving of Lays Potato Chips = 10 g
Calories in two serving of Lays Potato Chips = 160 * 2 = 320 cal
Fat in two serving of Lays Potato Chips = 10 * 2 = 20 g
Two serving of Lays Potato Chips will have twice the fat and calories of one serving of Lays Potato Chips. So multiply the values of calories and fats by 2 to get the required value.
Therefore, if you eat two servings Lays Potato Chips, you would have consumed 320 calories and 20 gram of fat.
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If you eat two servings of Lays Potato Chips, there are 320 calories and 20 gram of fat so option 1 is correct.
Given:
A serving size of Lays Potato Chips is 15 chips.
There are 160 calories in one serving and 10 grams of fat.
Calories in two serving of Lays Potato Chips = calories in one serving *2
= 160 * 2
= 320 calories.
Fat in two serving of Lays Potato Chips = fat in one serving * 2
= 10 * 2
= 20 grams
Therefore, if you eat two servings Lays Potato Chips, there are 320 calories and 20 gram of fat so option 1 is correct.
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The horsepower (hp) that a shaft can safely transmit varies jointly with its speed (in revolutions per minute, rpm) and the cube of its diameter. If a shaft of a certain material 2 inches in diameter can transmit 36 hp at 75 rpm, what diameter must the shaft have in order to transmit 134 hp at 35 rph
Answers
the shaft must have 4 inches of diameter
Explanation
Step 1
given that The horsepower (hp) that a shaft can safely transmit varies jointly with its speed (in revolutions per minute, rpm) and the cube of its diameter.
[tex]Power\propto diamter^3v[/tex]so
a) If a shaft of a certain material 2 inches in diameter can transmit 36 hp at 75 rpm
[tex]\begin{gathered} 36\text{ hp=\lparen2 in\rparen}^3*75\text{ rpm*k} \\ 36=600\text{ k} \\ k=\frac{36}{600}=0.06 \end{gathered}[/tex]b)what diameter must the shaft have in order to transmit 134 hp at 35 rph
[tex]\begin{gathered} Power\propto diamter^3v \\ Power=d^3*v*k \\ replace \\ 134=d^3*35*0.06 \\ 134=d^3*2.1 \\ divide\text{ both sides by 2.1} \\ \frac{134}{2.1}=\frac{d^3*2.1}{2.1} \\ 63.80=d^3 \\ cubic\text{ root in both sides} \\ \sqrt[3]{63.80}=\sqrt[3]{d^3} \\ 3.996=d \\ rounded \\ d=4\text{ inches} \end{gathered}[/tex]therefore
the shaft must have 4 inches of diameter
I hope this helps you
A force F1 of magnitude 5.70 units acts on an object at the origin in a direction = 38.0° above the positive x-axis. (See the figure below.) A second force F2 of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F1 + F2.magnitude unitsdirection ° counterclockwise from the +x-axisTwo forces act on an object. Force vector F1 acts up and right on the right side of the object at an angle above the horizontal. Force vector F2 acts vertically upwards on the top side of the object.
Answers
ANSWER:
Magnitude: 9.62 units
Direction: 62.1°
STEP-BY-STEP EXPLANATION:
Given:
F1 = 5.7 units
F2 = 5 units
Angle () = 38°
The vertical component of force F1 is:
[tex]\begin{gathered} F_{1y}=F_1\cdot\sin\theta \\ \\ \text{ We replacing:} \\ \\ F_{1y}=5.7\cdot\sin(38)=3.5j\text{ units} \end{gathered}[/tex]The horizontal component of force F1 is:
[tex]\begin{gathered} F_{1x}=F_1\cdot\cos\theta \\ \\ \text{ We replacing:} \\ \\ F_{1x}=5.7\cdot\cos(38)=4.5i\text{ units} \end{gathered}[/tex]Therefore, the total force F1 is:
[tex]\begin{gathered} F_1=F_{1x}+F_{1y} \\ \\ F_1=4.5i+3.5j \end{gathered}[/tex]The vertical component of force F2 is:
[tex]F_{2y}=5j\text{ units}[/tex]The horizontal component of force F2 is:
[tex]F_{2x}=0i[/tex]Therefore, the total force F2 is:
[tex]\begin{gathered} F_2=F_{2x}+F_{2y} \\ \\ F_2=0i+5j \end{gathered}[/tex]The resultant force (F1 + F2) would be:
[tex]\begin{gathered} F=F_1+F_2 \\ \\ F_=4.5i+3.5j+0i+5j \\ \\ F=4.5i+8.5j \end{gathered}[/tex]The magnitude of the resultant force is:
[tex]\begin{gathered} F=\sqrt{(F_x)^2+(F_y)^2} \\ \\ \text{ We replacing:} \\ \\ F=\sqrt{4.5^2+8.5^2} \\ \\ F=\sqrt{20.25+72.25}=\sqrt{92.5} \\ \\ F=9.62\text{ units} \end{gathered}[/tex]The direction is:
[tex]\begin{gathered} \theta =\tan ^{-1}\left(\frac{F_y}{F_x}\right) \\ \\ \text{ We replacing:} \\ \\ \theta =\tan ^{-1}\left(\frac{8.5}{4.5}\right) \\ \\ \theta=62.1\degree \end{gathered}[/tex]If John takes 45 minutes to bicycle a total of four kilometers northwest to his grandmothers house , what is the velocity in km/hr?
Answers
time = 45 minutes
distance = 4 kilometers
direction = Northwest
Since the velocity is in km/hr, convert minutes to hours:
1 hour = 60 minutes
45 / 60 = 0.75
45 min = 0.75 hours
Velocity = distance / time = 4 km/ 0.75 h = 5.33 km/ h , northwest.
You have measured a carts mass and observed that it changed position. What other information do you need to determine the carts momentum during that time? A. The carts electric charge. B. The net force on the cart. C. The displacement of the cart. D. The carts gravitational potential energy
Answers
Given that we know the mass and displacement of an object for a given amount of time, to determine the momentum we can use the fact that the change in momentum is equal to the impulse. This can be written as:
[tex]Ft=m\Delta v[/tex]Where:
[tex]\begin{gathered} F=\text{ net force} \\ t=\text{ time} \\ m=\text{ mass} \\ \Delta v=\text{ change in velocity} \end{gathered}[/tex]Therefore, we need to know the net force in order to determine the momentum in that time.
When analyzing a combination circuit, which parts are combined first to determine total resistance? Select one:a.the parallel componentsb.the series components c.it does not matter d.the diagonal components
Answers
ANSWER
a. The parallel components
EXPLANATION
When analyzing a combination circuit, we always want to transform it into a series circuit by replacing the parallel sections with an equivalent resistor.
If the circuit is more complex, then we can consider each parallel branch as a subcircuit and solve those first in the same order: first the parallel components and then the series components.
A motorboat travels 408 kilometers in 6 hours going upstream and 882 kilometers in 9 hours going downstream. What is the rate of the boat, and what is the rate of the current?
Answers
We have the next variables
x = speed of the boat in still water
y = speed of the current
(x-y) = Upstream speed
(x+y) = downstream speed
So we have the next equations for the distance
[tex]\begin{gathered} 6\mleft(x-y\mright)=408 \\ \end{gathered}[/tex][tex]\begin{gathered} 9(x+y)=882 \\ \end{gathered}[/tex]We simplify each equation
[tex]\begin{gathered} x-y=68 \\ x+y=98 \end{gathered}[/tex]we sum both equations
[tex]\begin{gathered} 2x=166 \\ x=\frac{166}{2} \\ x=83 \end{gathered}[/tex]Then we calculate the y
[tex]\begin{gathered} y=98-x \\ y=15 \end{gathered}[/tex]x = speed of the boat in still water=83 km/hr
y = speed of the current 15 km/hr
Questlon 7 of 10 Which two factors affect the amount of thermal energy an object has? O A. The directions in which the particles of the object are moving [ B. The amount of space between the particles of the object C. The mass of the object O D. The average kinetic energy of the particles of the object SUBM
Answers
C. The mass of the object
D. The average kinetic energy of the particles of the object
Thermal energy can be considered as kinetic energy, which involves the motions of the molecules of the object.
If an object has high kinetic energy, then the object has higher thermal energy.
A woman tries to throw a rock over a wall, releasing the rock at a height of 1.55m abovethe ground. If she throws the rock at 6 m/s, will it reach the top of the wall 3.75m aboveher?
Answers
Answer:
[tex]H_{\max }-H_{\text{wall}}=-0.3635m\Rightarrow Negative[/tex]Explanation: We need to find if the rock can reach the height of the wall, provided the initial velocity of 6m/s and it is thrown from the height of 1.55m above the ground., the equations used to solve this problem are as follows:
[tex]\begin{gathered} v(t)=v_o-gt\Rightarrow(1) \\ y(t)=y_o+v_ot-\frac{1}{2}gt^2\Rightarrow(2) \end{gathered}[/tex]Plugging in the known values in the equation (1) and (2) we get the following results:
[tex]\begin{gathered} v(t)=6ms^{-1}-(9.8ms^{-2})t\Rightarrow(3) \\ y(t)=1.55m+(6ms^{-1})t-\frac{1}{2}(9.8ms^{-2})t^2\Rightarrow(4) \\ \end{gathered}[/tex]Setting equation (3) equal to zero gives the time to reach the maximum height as follows:
[tex]\begin{gathered} v(t)=6ms^{-1}-(9.8ms^{-2})t=0 \\ t=\frac{(6ms^{-1})}{(9.8ms^{-2})}=0.61s \\ t=0.61s \end{gathered}[/tex]Substituting the time t calculated above in equation (4) gives the maximum height, the steps for the calculation are shown as follows:
[tex]\begin{gathered} y(0.62)=1.55m+(6ms^{-1})(0.62s)-\frac{1}{2}(9.8ms^{-2})(0.62s)^2 \\ y(0.62)=1.55m+3.72m-1.88356m=3.3865m \\ y(0.62)=3.3865m \\ H_{\max }=3.3865m \\ H_{\max }-H_{\text{wall}}=3.3865m-3.75m=-0.3635m\Rightarrow Negative \\ \\ \end{gathered}[/tex]Therefore, the ball can not reach the height of the wall!
Question 17 of 30Which of the following is the energy of atoms vibrating inside an object?A. RadiantB. ElectricC. ThermalD. MechanicalSUBMIT
Answers
ANSWER:
C. Thermal
STEP-BY-STEP EXPLANATION:
Thermal energy, or heat, is the internal energy of substances; is the vibration and movement of atoms and molecules within a substance.
Therefore, the correct answer is C. Thermal