In materials such as metals the outer most electrons are loosely bound and therefore their movement is chaotic, this allows for the transportation of energy in form of electricity therefore, this materials are good conductors. The statement is true.
2.
The magnetic field of magnet A extends further than the
magnetic field of magnet B.
State what can be concluded about the strengths of these
two magnets.
The magnetic field of magnet A extends further than the magnetic field of magnet B concludes that magnet A is larger in size and have stronger magnetic field than magnet B.
What is a magnetic field?A magnetic field is a vector field that represents the effect of magnetic effect on moving charges, currents, and magnetic bodies. A charge moving in a magnetic field experiences a force perpendicular to its velocity and magnetic field.
Does size affect the strength of a magnet ? The answer is yes, but it's because the size of a magnet is proportional to its ability to align and produce a stronger magnetic field than smaller pieces of the same material. Because it means there are more domains.
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A ball rolls down a hill that leads to a cliff.
How does the ball move when it reaches the edge of the cliff?
C. The ball keeps moving forward and falls downward at the same time.
B. The ball's forward motion ends at the edge of the cliff, where it falls straight down.
A. The ball falls downward in a spiral-shaped path.
The ball's forward motion continues briefly beyond the edge of the cliff, and then it falls straight down.
Answer:
Option C is correct. The ball keeps moving forward and falls downward at the same time.
Explanation:
When the ball reaches the edge of the cliff, its forward motion will indeed continue due to its inertia. Inertia is the property of an object to maintain its state of motion. However, gravity will also be acting on the ball, causing it to accelerate downward.
As a result, the ball will move forward and descend downward at the same time. The trajectory of the ball will be a curved path that combines the horizontal motion (forward movement) and the vertical motion (downward fall) simultaneously. This curved path is known as a parabolic trajectory.
The exact shape of the trajectory will depend on factors such as the initial velocity, angle of the cliff, and air resistance. If there is no air resistance and the cliff is not too steep, the ball's trajectory may resemble a smooth parabolic curve. However, if there is air resistance or the cliff is steep, the trajectory might deviate from a perfect parabola.
Eventually, due to the downward acceleration caused by gravity, the ball's vertical motion will dominate, and it will fall straight down. But immediately after reaching the edge of the cliff, the ball will experience a combination of forward motion and downward descent.
Identify a stressor in your life.
Create an action plan to manage the stressor you identified. Use the Stress Action Plan template to guide your work. Your action plan should include:
A description of the stressor you chose
At least two paragraphs explaining how you will apply the information learned in the lesson to effectively manage your stress
At least two effective strategies you will use and one ineffective strategy you will avoid
You can improve how you handle stress and difficulties (adversity) in your life by using a variety of stress management techniques. You may lead a more well-balanced existence by controlling your stress.
What are the importance of managing stress?You put your complete well-being at danger if you're under a lot of stress every day. Your mental balance and physical health both suffer from stress. Your capacity for clear thinking, successful functioning, and enjoyment of life is reduced. You could feel helpless in combating stress. There won't ever be more hours in the day, the bills won't stop rolling in, and your obligations to your job and family will always be demanding. Stress is a natural, spontaneous reaction to a stressful situation on the body, mind, and emotions. Everyone's life entails it as a normal aspect. Stress can spur growth, activity, and change when it is used constructively. Long-term, negative stress, though, might lower your level of well-being.Though it may not seem like it, you actually have a lot more control. Achieving effective stress management enables you to release the grip that stress has on your life and improves your ability to be happier, healthier, and more effective. The ultimate objective is a well-balanced existence with time for work, relationships, relaxation, and fun—as well as the resilience to hold up under stress and face obstacles head-on. However, there is no one approach to stress management that works for everyone. Discovering what works best for you through experimentation is crucial. You can do it with the aid of the stress-reduction advice that follows.To know more about Stress Management, visit:
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dentify the objective of this lab. select all that apply: group of answer choices to submurged different objects in the fluid. to determine density of unknown materials using archimedes' principle to discover the relationship between aarchimedes' principal and hydrostatic pressure in object submerged in a fluid. to test archimedes' principle for objects of different densities
The objective of the experiment of submerging different objects in fluid is to determine the density of the unknown material using Archimedes' principle.
Archimedes' principle- The amount of the upward force felt by the object when submerged in fluid is equal tot he weight of the mass of the fluid displaced.
So, in this experiment,
The objects of unknown densities are submerged in liquid, they displaces some amount of liquid. The amount of liquid is related to the buoyancy of the unknown object as,
Vₐpg = Vσg
where,
p is the density of the unknown object,
σ is the density of the fluid and Vₐ is the volume of the body submerged in fluid and V is the volume of the water displaced.
So, by this relation, we can find the density of the unknown material.
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A ball is thrown up into the air with 100 j of kinetic energy, which is transformed to gravitational potential energy at the top of its trajectory. The ball encounters some air resistance. What is its kinetic energy when it returns to its original height?.
The kinetic energy when it returns to its original height is 100 J
The ball is thrown up with a Kinetic Energy K. E. = 0.5×m×v² = 100 J
Therefore the final height is given by
u² = v² -2·g·s
Where:
u = final velocity = 0
v = initial velocity
s = final height
Therefore v² = 2·g·s = 19.62·s
P.E = Potential Energy = m·g·s
Since v² = 2·g·s
Substituting the value of v² in the kinetic energy formula, we obtain
K. E. = 0.5×m×2·g·s = m·g·s = P.E. = 100 J
When the ball returns to the original height, we have
v² = u² + 2·g·s
Since u = 0 = initial velocity in this case we have
v² = 2·g·s and the Kinetic energy = 0.5·m·v²
Since m and s are the same then 0.5·m·v² = 100 J.
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A spring is pulled down by a weight by 1.24 meters. The spring constant (k) is 330 N/m. What is the mass of the weight?
Given,
The extension of the spring due to the attached mass, x=1.24 m
The spring constant, k=330 N/m
The weight of a mass m is given by,
[tex]F=mg[/tex]Where g is the acceleration due to gravity,
The magnitude of the restoring force of a spring is given by,
[tex]\begin{gathered} F=kx \\ \Rightarrow mg=kx \end{gathered}[/tex]Therefore,
[tex]m=\frac{kx}{g}[/tex]On substituting the known values,
[tex]\begin{gathered} m=\frac{330\times1.24}{9.8} \\ =41.76\text{ kg} \end{gathered}[/tex]Thus the mass of the weight is 41.76 kg
You throw a ball vertically upward from the roof of a tall building.
The ball leaves your hand at a point even with the roof railing with
an upward speed of 15.0 m/s; the ball is then in free fall. On its
way back down, it just misses the railing. Find the ball's posi-
tion and velocity 1.00 s and 4.00 s after leaving your hand
11.1 m and -18.4 m is the ball's position, 5.2 m/s and -24.2 m/s is the ball's velocity after leaving your hand
s = ut + 1/2at²
s = 15(t) + 1/2(-9.8)(t)²
s = 15t - 4.5(t)²
t = 1 second,
s = 15(1) - 4.9(1)²
s = 15 - 4.5
s = 11.1 m [at t = 1 second]
t = 4 seconds,
s = 15(4) - 4.9(4)²
s = 60 - 4.9(16)
s = 60 - 78.4
s = -18.4 m [t = 4 seconds]
v = u + at
v = 15 + (-9.8)t
time = 1 second,
v = 15 - 9.8
v = 5.2 m/s [ t = 1 second]
time = 4 seconds,
v = 15 - (9.8)(4)
v = 15 - 39.2
v = -24.2 m/s [for t = 4 seconds]
velocity's a vector quantity have magnitude and direction.
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Given a horizontal uncharged insulating rod. A negatively charged rod touches the middle of the horizontal rod. Which of these best describes what happens? A)the rod becomes positively charged on its left end and negatively charged on its right end B)the middle of the rod becomes negatively charged C)the rod becomes positively charged all over its surface D)the rod becomes negatively charged all over its surfaceE) the rod remains uncharted
Answer:
E) The rod remains uncharted.
Explanation:
The negatively charges rod has an excess of electrons. These electrons repel each other, so when this rod touches the horizontal uncharged insulating rod, they will try to go to the uncharge rod. However, this is an insulating rod, so there will be no transfer of electrons. It means that the rod remains uncharted.
The driver of a car going 16.0 m/s suddenly sees the lights of a barrier 84.0 m ahead. It takes the driver 0.75 s to apply the brakes, and the average acceleration during braking is -10.0 m/s2.
(a) what is the total displacement of the car.
The driver of a car going 16.0 m/s suddenly sees the lights of a barrier 84.0 m ahead. It takes the driver 0.75 s to apply the brakes, and the average acceleration during braking is -10.0 m/s2. The total displacement of the car 9.19 m
The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.
s = u*t + 1/2 a [tex]t^{2}[/tex]
s = displacement
u = initial speed
t = time
a = acceleration
s = 16 * 0.75 + 1/2 * ( -10 ) * [tex](0.75)^{2}[/tex] = 9.19 m
The total displacement of the car will be 9.19 m
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6. Suppose that two chrome steel balls attract each other with a gravitational
force of 16 units. If the mass of both objects was doubled, and if the distance
between the objects was doubled, then what would be the new force of attraction
between the two objects?
4 units
8 units
16 units
32 units
64 units
Answer:
Explanation:
Given:
m₁
m₂
R₁
F₁ = 16 units
m₁' = 2·m₁
m₂' = 2·m₂
R₂ = 2·R₁
_________
F₂ - ?
The force of gravity:
F₁ = G·m₁·m₂ / (R₁)²
F₂ = G·m₁'·m₂' / (R₂)² = G·(2·m₁)·(2·m₂) / (2·R₁)² =
= 4·m₁·m₂ / (4·R₁²) = m₁·m₂ / (R₁)² = F₁
F₂ = F₁ = 16 units
A car travelling with an initial velocity of
15.0 m/s, accelerates at 2.40 m/s² over a
distance of 180 m. What is the final
velocity of the car (m/s)?
?] m/s
The final velocity of the car 120.93 m/sec.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.
Given in the question, a car travelling with an initial velocity of 15.0 m/s, accelerates at 2.40 m/s² over a distance of 180 m
Using equation of motion,
v² = u² + 2as
v² = 15² + 2*40*180
v = 120.93 m/sec
The final velocity of the car 120.93 m/sec.
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1. If a pair of running shoes would weigh 11.55 newtons on Jupiter, what is the strength of gravity there?
2. If the same pair of shoes weighs 0.3 newtons on Pluto, what is the strength of gravity on pluto?
3.What does the pair of shoes weigh on earth?
The strength of gravity of planets Jupiter and Pluto are 23.1m/s² and 0.6m/s² respectively.
We are given that,
The mass of the shoes = m=0.500 kg
The weigh of the shoes on the Jupiter = W₁=11.55 N
The weigh of the shoes on the Pluto = W₂=0.3 N
Therefore, the weight to mass ratio determines the strength of gravity, or the acceleration caused by gravity.
Then the strength of gravity on Jupiter can be calculated as,[tex]g_{j} = \frac{w_{1} }{m}[/tex]
Putting the values in above equation we can get,
[tex]g_{j} = \frac{11.55N}{0.500kg}\\ g_{j} = 23.1m/s^{2}[/tex]
Since, the gravity strength of planet Jupiter would be 23.1m/s²
The strength of gravity of planet Pluto can be calculated when shoes weigh is 0.3 N,[tex]g_{p} =\frac{w_{2} }{m} \\g_{p} = \frac{0.3N}{0.500kg} \\g_{p} = 0.6 m/s^{2}[/tex]
Thus, the gravity strength of planet Pluto may be 0.6m/s².
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Consider a system of a cliff diver and the earth. The gravitational potential energy of the system decreases by 26,500 J as the diver drops to the water from a height of 33.0 m. Determine her weight in newtons.
Given data:
* The change in gravitational potential energy is 26500 J.
* The change in height of the diver is 33.0 m.
Solution:
The change in gravitational potential energy in terms of change in height of the diver is,
[tex]dU=mg\times dh[/tex]where m is the mass of diver, g is the acceleration due to gravity, dh is the change in height, and dU is the change in gravitational potential energy,
Substituting the known values,
[tex]\begin{gathered} 26500=mg\times33 \\ mg=\frac{26500}{33} \\ mg=803.03\text{ N} \end{gathered}[/tex]The weight of the diver is,
[tex]\begin{gathered} W=mg \\ W=803.03\text{ N} \end{gathered}[/tex]Thus, weight of the diver is 803.03 N.
Describe where infrared is found on the ems compared to the other six forms of radiation.
Between visible light and microwave is where infrared falls. Infrared has a higher energy than radio but a lower energy than gamma rays.
Where, in relation to the other six types of radiation, is infrared found on the EMS?The term "infrared" refers to electromagnetic waves that exist within the electromagnetic spectrum at frequencies slightly below those of red visible light and just above those of microwaves. According to the California Institute of Technology, the wavelengths of infrared radiation are longer than those of visible light (Caltech).
Where can I find radio waves on the EMS?The majority of the radio portion of the electromagnetic spectrum (EM spectrum) is found between 1 cm and 1 km, or 30 GHz and 300 kHz in frequency. The EM spectrum's radio region is relatively vast. Astronomers usually employ wavelength in the infrared and optical spectrum.
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A ball is fired at 5 m/s to the right and bounces off a second ball, initially at rest, and comes back to the left at 1m/s. What is the velocity of the second ball? Assume both balls have a mass of 3.86kg and make to the right positive.
ANSWER:
6 m/s
STEP-BY-STEP EXPLANATION:
Given:
Mass of balls (m) = 3.86 kg
Initial speed of ball 1 (u1) = 5 m/s
Final speed of ball 1 (v1) = - 1 m/s
Initial speed of ball 2 (u2) = 0 m/s
We make the balance for the moment and we are left with the following:
[tex]\begin{gathered} m_1\cdot u_1+m_2\cdot u_2=m_1\cdot v_1+m_2\cdot v_2 \\ \\ \text{ We repalcing:} \\ \\ 3.86\cdot5+3.86\cdot0=3.86\cdot-1+3.86\cdot v_2 \\ \\ 19.3=-3.86+3.86v_2 \\ \\ 3.86v_2=19.3+3.86 \\ \\ v_2=\frac{23.16}{3.86} \\ \\ v_2=6\text{ m/s} \end{gathered}[/tex]Therefore, the speed of the second ball is equal to 6 m/s
How much heat is necessary to change 295 g of ice at -5°C to water at 20°C? Answer must be in kcal
Given:
• Mass of ice = 295 g ==> 0.295 kg
,• Initial temperature, T1 = -5°C
,• Final temperature, T2 = 20°C
Let's find the amount of heat necessary to change the ice to water.
To find the amount of heat, let's apply the Specific Heat Capacity formula:
[tex]\begin{gathered} Q=mc\Delta T \\ \\ Q=mc(T_2-T_1) \end{gathered}[/tex]Where:
m is the mass in kg = 0.295 kg
T1 is the initial temperature
T2 is the final temperature.
c is the specific heat capacity
Let's first find the amount of heat required to change ice from -5°C to 0°C.
[tex]\begin{gathered} Q_1=0.295*0.50*(0-(-5)) \\ \\ Q_1=0.295*0.50*5 \\ \\ Q_1=0.74\text{ kcal} \end{gathered}[/tex]Now, let's find the heat required to change from 0°C(ice) to 0°C(water).
We have:
[tex]\begin{gathered} Q_2=m*L \\ \end{gathered}[/tex]
Where L is the latent fusion of water:
[tex]\begin{gathered} Q_2=0.295*79.7 \\ \\ Q_2=23.51\text{ kcal} \end{gathered}[/tex]Now, let's find the heat required to change 0°C (water) to 20°C(water).
We have:
[tex]\begin{gathered} Q_3=mc_{water}(T_2-T_1) \\ \\ Q_3=0.295*1.0*(20-0) \\ \\ Q_3=0.295*1.0*20 \\ \\ Q_3=5.9\text{ kcal} \end{gathered}[/tex]Therefore, the total heat required is:
Q = Q1 + Q2 + Q3
Thus, we have:
[tex]\begin{gathered} Q=0.74+23.51+5.9 \\ \\ Q=30.15\text{ kcal} \end{gathered}[/tex]Therefore, the amount of heat neccesary is
a hoopof moment of inertia released from the top of an inclined plane 20m high and length 32m rolls drawn without slipping determine the speed and acceleration when it reaches the foot of the inclined plane
The speed and acceleration when it reaches the foot of the inclined plane is 14√2 m/s
Torricelli's theorem states that the speed of a liquid flowing through an orifice is equal to the speed it would attain if falling freely a distance equal to the height of the liquid's free surface above the orifice.
Given that
A hoop of the moment of inertia released from the top of an inclined plane 20m high and length 32m rolls drawn without slipping
W have to determine the speed and acceleration when it reaches the foot of the inclined plane
By using Torricelli's theorem
V= √2gh
Here g= 9.8 and h = 20m
V= √2x9.8x20
V= √4x9.8
V= 14√2 m/s
Therefore the speed and acceleration when it reaches the foot of the inclined plane is 14√2 m/s
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This question is typical on some driver’s license exams: A car moving at 46 km/h skids
15 m with locked brakes.
How far will the car skid with locked brakes
at 115 km/h? Assume that energy loss is due
only to sliding friction.
Answer in units of m.
A car moving at 46 km/h skids 15 m with locked brakes. The distance travelled by the car when it skids is 94.74 m.
What is the acceleration of the car?The acceleration of the car is calculated by applying the following kinematic equation.
v² = u² - 2as
where,
v is the final velocity of the car
u is the initial velocity of the car
a is the acceleration of the car
s is the distance travelled by the car
when the car stops, the final velocity, v = 0
0 = u² - 2as
2as = u²
a = u²/2s
where,
u = 46 km/h = 12.7 m/s
a = (12.7²) / (2 x 15)
a = 5.37 m/s²
When the speed of the car changes from 42 km/h to 126 km/h, the distance travelled by the car at the same acceleration is calculated as follows;
s = u²/2a
where,
u = 115 km/h = 31.9 m/s
s = (31.9²) / ( 2 x 5.37)
s = 94.74 m
The distance travelled by the car when it skids is 94.74 m.
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1 point1. Inertia is the tendency of an object to stay at rest or in motion. *TrueFalse
The given statement is true
Inertia is the tendency of an object to stay at rest or in motion
State two assumptions of the Kinetic Theory.
Answer:
Explanation: 1: The gas particles move in a straight line before colliding with something, usually the wall of their containers.
2: The is no attraction or repulsion between the gas particles.
A bowling ball is dropped from the top of a building that has a height of h = 159 m.a) Assuming air resistance is negligible, what is the ball's speed, vf in m/s, when it strikes the ground? b) If drag produces an opposing force of 10 N while the ball's falling, what is the ball's speed, vf in m/s, when it strikes the ground? Assume the ball has a mass of 5 kg.c) A different ball was dropped and the final speed was measured to be vf = 6.5 m/s while the drag force was measured to be 50 Newtons. What is the mass of this ball in kg?
ANSWER:
a) 55.82 m/s
b) 49.8 m/s
c) 5.17 kg
STEP-BY-STEP EXPLANATION:
Given:
Height (h) = 159 m
Initial speed (vi) = 0 m/s
a)
We calculate the final speed using the following formula:
[tex]\begin{gathered} (v_f)^2=(v_i)^2+2gh \\ \\ \text{ we replacing:} \\ \\ (v_f)^2=(0)^2+2(9.8)(159) \\ \\ v_f=\sqrt{3116.4} \\ \\ v_f=55.82\text{ m/s} \end{gathered}[/tex][tex]\begin{gathered} (v_f)^2=(v_i)^2+2gh \\ \\ \text{ we replacing:} \\ \\ (v_f)^2=(0)^2+2(9.8)(159) \\ \\ v_f=\sqrt{3116.4} \\ \\ v_f=55.82\text{ m/s} \end{gathered}[/tex]b)
To determine the final velocity with the opposing force, we have to determine the net force and then calculate the acceleration that would be used to calculate the velocity, like this:
[tex]\begin{gathered} F_n=mg-10 \\ \\ \text{ we replacing} \\ \\ F_n=5\cdot9.8-10 \\ \\ F_n=49-10=39\text{ N} \\ \\ F=m\cdot a \\ \\ a=\frac{F}{m}=\frac{39}{5} \\ \\ a=7.8\text{ m/s^^b2} \\ \\ \text{ Therefore:} \\ \\ (v_f)^2=(v_i)^2+2ah \\ \\ \text{ we replacing:} \\ \\ (v_f)^2=(0)^2+2(7.8)(159) \\ \\ v_f=\sqrt{2480.4} \\ \\ v_f=49.8\text{ m/s} \end{gathered}[/tex]c)
We can calculate the mass in the following way, first, we must calculate the acceleration to be able to determine the mass:
[tex]\begin{gathered} (v_{f})^{2}=(v_{i})^{2}+2ah \\ \\ \text{ we replacing:} \\ \\ 6.5^2=0^2+2\cdot a\cdot(159) \\ \\ 318a=42.25 \\ \\ a=\frac{42.25}{318} \\ \\ a=0.133\text{ m/s^^b2} \\ \\ \text{ Now we can calculate the mass using the force balance:} \\ \\ ma=mg-50 \\ \\ a=g-\frac{50}{m} \\ \\ \text{ we replacing:} \\ \\ 0.133=9.8-\frac{50}{m} \\ \\ 1.333-9.8=-\frac{50}{m} \\ \\ -9.667m=-50 \\ \\ m=\frac{-50}{-9.667} \\ \\ m=5.17\text{ kg} \end{gathered}[/tex]A dvd is rotating with an ever-increasing speed. how do the centripetal acceleration arad and tangential acceleration atan compare at points p and q?.
The centripetal acceleration arad and tangential acceleration atan compare at points P and Q by Q having a greater arad and atan than point P.
arad = v² / r
v = 2 π r / T
arad = 4 π² r / T²
Since time period will be constant at any point in the radius line,
arad ∝ r
So larger the radius, larger will be the centripetal acceleration. The radius at point P is smaller than the radius at point Q.
arad at Q > arad at P
atan = r α
α = 2 π / T²
atan = 2 r π / T²
Since time period will be constant at any point in the radius line,
atan ∝ r
So larger the radius, larger will be the tangential acceleration. The radius at point P is smaller than the radius at point Q.
atan at Q > atan at P
Therefore, Q has a greater arad and atan than point P.
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Spiral galaxy rotation curves are generally fairly flat out to large distances. Suppose that spiral galaxies did not contain dark matter. How would their rotation curves be different?.
Spiral galaxy rotation curves are generally fairly flat out to large distances. Suppose that spiral galaxies did not contain dark matter. Their rotational curves be different as the orbital speeds would fall off sharply with increasing distance from the galactic center.
Plotting the orbital speeds vs radius graph gives us the rotational curves. According to the theoretical calculations, the curve increases as the radial distance decrease and then decreases as the radial distance increases. The theoretical graph does not take the dark matter into account.
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Which object is made up of a magnetic material?
A. A copper wire
B. A plastic spoon
C. An iron nail
D. An ice cube
Answer: C
Explanation: because it is made out of metal.
Answer:
C- iron nail.
Explanation:
iron nails are attracted to magnets and that's made of magnetic material.
The angular speed of earth around its own axis
7.26 x 10-5 rad/sec
The angle of one rotation is 2π. The time required for this rotation is 24 hours to calculate the angular speed of the Earth as it rotates completely around its own axis. Average Angular Velocity Wav is the average rate of change of angular displacement.
On converting the hours into seconds we get,
Time = 24 hr x 60 min/hr x 60 sec/min = 86400 sec
The angular speed is given by the formula, ω = θ /t.
after substituting the value given in the equation we get,
ω = 2π / 86400 Seconds
ω = 0.0000726 radians/sec = 7.26 x 10-5 rad/sec
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360 degrees per 24 hours
The retail industry's customer service representatives outperformed all other industries in 2008, and the cable and satellite tv representatives scored lowest. what might be responsible for this difference in service
The retail industry's customer service representatives outperformed all other industries in 2008, and the cable and satellite tv representatives scored lowest due to little knowledge of their product and service.
In the case of retail industry, it was easy to show courteousness, helping mentality and to offer discounts in 2008. The service executives had good knowledge on the products sold in the retail industry which helped them to handle the issues efficiently. Hence they received very high scores compared to other industries.
But cable and satellite TVs were in its initial stages in 2008 and hence the representatives had a little knowledge on the same to address customer doubts. Hence it was difficult for them to address the issues and giving discounts was also not possible due to the high cost required for installation and service.
Therefore, the cable and satellite tv representatives scored lowest due to little knowledge of their product and service.
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What is the total displacement during the interval from t=0 until t=11 s?
Brainlist if answered correctly.
Answer:
830 cm
Explanation:
From 0 - 4
acceleration = slope = 90 /4 = 22.5
distance = 1/2 at^2 = 1/2 (22.5)(4^2) = 180 cm
from 4-7 velocity is constant 90 cm/s = 270 cm
from 7-11 acceleration = slope = 10 /4 = 2.5 m/s^2
distance =vo t + 1/2 a t^2 = 90(4) + 1/2 (2.5)(4^2) = 380 cm
Summed = 180 + 270 + 380 = 830 cm
Answer:
Explanation:
Given:
t₀ = 0 s
V₀ = 0 cm/s = 0 m/s
t = 11 s
V = 100 cm/s = 1 m/s
________________
| S | - ?
Movement module:
| S | = V·t = 1·11 = 11 m
(The displacement is numerically equal to the area of the triangle AOB):
if a gram of antimatter meets a kilogram of matter, the amount of mass to survive is group of answer choices 1 kilogram. 999 grams. 1 gram. 1.1 kilogram.
If a gram of antimatter meets a kilogram of matter, the amount of mass to survive is 1 gram.
Matter :
A substance called matter is made up of different kinds of particles, occupies space, and has inertia.
The various types of particles each have a unique mass and size according to the fundamentals of modern physics.
Antimatter :
As the opposite particles of the corresponding particles in "ordinary" matter, the antimatter is defined as matter made up of them.
The two particles' combined mass is entirely converted into energy. The term "matter-antimatter annihilation" refers to this process.
If a gram of antimatter meets a kilogram of matter, the amount of mass to survive is 1 gram.
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A 29-g rifle bullet traveling 220 m/s embeds itself in a 3.9-kg pendulum hanging on a 3.0-m-long string, which makes the pendulum swing upward in an arc.
The vertical component (height) of the pendulum's maximum displacement is 0.146 meters.
What is maximum displacement?In physics, the maximum displacement or range traveled by a point on a vibrating body or wave calculated from its equilibrium position is known as amplitude. It is one-half of the length of the vibration path.
We have a collision when the bullet hits the pendulum, and momentum is preserved in any collision. Let the pendulum's beginning momentum and the bullet's initial momentum be, p₁ and p₂, respectively.
Following the impact, the pendulum and the bullet travel as one object with the same velocity, v. Let p₃ be the momentum of the pendulum and as well as the bullet following the impact.
Hence,
First momentum = Last Momentum
p₁ + p₂ = p₃
[3.4kg x 0m/s] +([2.90 x 10⁻²] x 200m/s) = 3.48kg x v
Simplified, we have
5.8kg · m/s = 3.49kg · v
Making v the subject of the formula, we have
v = 1.69m/s
As a result, the combined velocity of the pendulum and bullet after the contact is v = 1.69 m/s.
We are now using the conservation of energy equation. The potential energy at the maximum height will be equal to the kinetic energy of the pendulum plus the bullet.
mgh = 1/2mv²
Where
m is the mass in kilograms
g is the acceleration due to gravity
h is height in meters; and
v is velocity
If we divide both sides with m and make h the subject of the formula, we have:
h = v²/2g
= (1.69m/s)²/2 (9.81)m/s²
= 0.14557084607m
Hence,
The vertical component of the pendulum's maximum displacement (h) [tex]\approx[/tex] 0.146m
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Full Question:
A 29-g rifle bullet traveling 220 m/s embeds itself in a 3.9-kg pendulum hanging on a 3.0-m-long string, which makes the pendulum swing upward in an arc.
Determine the vertical component of the pendulum's maximum displacement. Express your answer in two significant figures and include the appropriate units.
A balloon bursts when more air is filled in it.
give reason?