Simplify using exponential notation. 5a^6 x 7a^7

Answers

Answer 1

Given:

[tex]5a^6\times7a^7[/tex]

Let's simplify using exponential notation.

To simplify, multiply the the base, then use law of indicies to add the exponents

We have:

[tex]undefined[/tex]


Related Questions

how do you solve y=x-2 and graph it

Answers

The equation

y = x - 2

is the equation of a line in the slope-intercept form with a slope of 1 and a y-intercept at (0, -2).

You can graph it by locating two points on the line. One point is (0, -2). The other one can be found with the slope. The slope of 1 means that the next point is 1 unit to the left and 1 unit up, respect the previous point. In this case, the next point is (1, -1). After you locate these two points, draw the line that connects them, as follows

Based on the information given in the following graph of a power function, can you determinethe equation of the power function? Why or why not? If you can, find the equation of the powerfunction. If not, describe the equation of the power function as much as you can.

Answers

SOLUTIONS

To determine the equation of the power function? Why or why not? If you can, find the equation of the power

[tex]\begin{gathered} (4,2) \\ x=4,y=2 \end{gathered}[/tex]

It is easy to get the graph of the exponential function since x - value = 4 and y - value = 2.

An exponential function is defined by the formula f(x) = x^a, where the input variable x occurs as an exponent. The exponential curve depends on the exponential function and it depends on the value of the x.

The general equation of an exponential function is

[tex]y=x^a[/tex][tex]\begin{gathered} y=2,x=4 \\ 2=4^a \\ 4^{\frac{1}{2}}=4^a \\ a=\frac{1}{2} \end{gathered}[/tex]

[tex]y=x^{\frac{1}{2}}[/tex]

volume= {1}{3} * \pi * r ^{2}* hHELPsolve for H

Answers

[tex]h=\frac{3V}{\pi r^2}[/tex]

Explanation

[tex]Volume=\frac{1}{3}\pi r^2h[/tex]

Step 1

multiply each side by 3

[tex]\begin{gathered} V=\frac{1}{3}\pi r^2h \\ V\cdot3=\frac{1}{3}\pi r^2h\cdot3 \\ 3V=\pi r^2h \end{gathered}[/tex]

Step 2

divide both sides by

[tex]\pi r^2[/tex][tex]\begin{gathered} 3V=\pi r^2h \\ \frac{3V}{\pi r^2}=\frac{\pi r^2\text{ h}}{\pi r^2} \\ h=\frac{3V}{\pi r^2} \end{gathered}[/tex]

how do you find the length of a side of a triangle when given the length of only one other side?

Answers

WE can find the sides if the triangle by apply the Sine rule :

[tex]\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}[/tex]

where, a,b & c are the sides of triangle

For eg :

Consider an triangle with one side AB = 5

and angles A = 60, angle B = 45 and angle C= 75

So, substitute the value in the expression of Sine

[tex]\begin{gathered} \frac{BC}{\sin A}=\frac{AC}{\sin B}=\frac{AB}{\sin C} \\ \frac{BC}{\sin 60}=\frac{AC}{\sin 45}=\frac{5}{\sin 75} \\ \text{ Substitute the values :} \\ \frac{BC}{\sin60}=\frac{AC}{\sin45}=\frac{5}{\sin75} \\ \frac{BC}{0.866}=\frac{AC}{0.707}=\frac{5}{0.965} \\ \text{ Simplify : }\frac{AC}{0.707}=\frac{5}{0.965} \\ \frac{AC}{0.707}=\frac{5}{0.965} \\ AC=\frac{5}{0.965}\times0.707 \\ AC=3.66 \\ \text{Now, Simplify: }\frac{BC}{0.866}=\frac{5}{0.965} \\ BC=\frac{5}{0.965}\times0.866 \\ BC=4.4 \end{gathered}[/tex]

The sides : AB = 5, AC = 3.66 & BC = 4.4

Below, the two-way table is given for aclass of students.FreshmenSophomoreJuniorsSeniorsTotal46246Male2Female 33TotalIf a student is selected at random, find theprobability the student is a junior given that it'smale. Round to the nearest whole percent.[?]%

Answers

Male students. 14

Female students: 16

Total students: 30

Since there are 2 male juniors, the probability of being junior and male is: 6.67%

[tex]\frac{2}{30}\cdot100=6.67[/tex]

If we round to the nearest whole porcent: 7%

E-0-16Name a pair of similar triangles.Explain why each pair of triangles is similar.Use the given information to find each missing measure.

Answers

The horizontal arrows denote that segments RS and VT are parallel. This means that angleR and angleV are congruent. Similarly, angleS and angleT are congruent. They are denoted in blue and red color, respectively:

Therefore,

[tex]\Delta\text{TUV}\approx\Delta SUR[/tex]

by the AA-theorem (angle-angle theorem). That is because:

[tex]\begin{gathered} \angle R=\angle V \\ \angle S=\angle T \\ \angle U=\angle U \end{gathered}[/tex]

Now, lets find the missing measure x. Since the above triangles are similar, we have

[tex]\frac{x}{3}=\frac{x+1}{3+9}[/tex]

which gives

[tex]\frac{x}{3}=\frac{x+1}{12}[/tex]

By multiplying both side by 3, we get

[tex]x=\frac{x+1}{4}[/tex]

and by multiplying both side by 4, we have

[tex]4x=x+1[/tex]

then, x is given as

[tex]\begin{gathered} 4x-x=1 \\ 3x=1 \end{gathered}[/tex]

therefore, we obtain

[tex]x=\frac{1}{3}[/tex]

then, the missing side x measures 1/3.

Now, lets find y. In this case, we have

[tex]\frac{y}{3}=\frac{2}{9+3}[/tex]

then, it yields

[tex]\frac{y}{3}=\frac{2}{12}[/tex]

by multipluying both sides by 3, we have

[tex]\begin{gathered} y=3\cdot\frac{2}{12} \\ y=\frac{2}{4} \\ y=\frac{1}{2} \end{gathered}[/tex]

Therefore, the missing side y measures 1/2.

If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true?

The figure must be an isosceles trapezoid because it has 2 congruent base angles.
The figure must be a rectangle because all rectangles have exactly 2 lines of symmetry.
The figure could be a rhombus because the 2 lines of symmetry bisect the angles.
The figure could be a square because the diagonals of a square bisect the right angles.

Answers

The third option is correct. That is, the figure could be a rhombus because the 2 lines of symmetry bisect the angles.

What is rhombus?

A rhombus is a quadrilateral that is an equilateral parallelogram and has all of its opposite pairs of sides parallel. Sometimes the word "rhombus" is substituted with "rhomb," and a rhombus is also referred to as a "diamond."

Given: A quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors.

Since the two lines of symmetry in a quadrilateral are angle bisectors, the figure may be a rhombus if the quadrilateral has exactly two lines of symmetry. Figures with four sides and angles are called quadrilaterals. Rectangle is a type of quadrilateral.

Therefore, If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then the figure could be a rhombus because the 2 lines of symmetry bisect the angles.

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Answer:

third option

Step-by-step explanation:

Using only the values given in the table for thefunction, f(x), what is the interval of x-values over whichthe function is increasing?Х-6-5-4-3-2.-101f(x)343-10-11-6-1-2-15O (-6,-3)O (-3,-1)O (-3,0)O (-6, -5)

Answers

Given the table:

Х f(x)

-6 34

-5 3

-4 -10

-3 -11

-2. -6

-1 -1

0 -2

1 -15

Let's find the increasing intervals.

A function is increasing over the interval when the values of f(x) increases as the values of x increases.

At the interval:

From x = -3 to x = -1, the values of f(x) increases from -11 to -1.

Therefore, the interval of x-values over which the function is increasing is:

(-3, -1)

ANSWER:

(-3, -1)

The organizer of a conference is selecting workshops to include. She will select from 3 workshops about anthropology and 10 workshops about psychology. In how many ways can she select 7 workshops if 2 or fewer must be about anthropology?

Answers

give the following from the question:

the organizer will select from 3 workshop about anthropology and 10 workshops about psychology.

we were asked in how many ways she can select 7 workshops if 2 or fewer must be anthropology

so,

If 2 or fewer must be anthropology,

Then tha means it is either she selects 2 from anthropology and 5 from psychology or 1 from anthropology and 6 from psycology.

that is:

= 3C2 x 10C5 or 3C1 x 10C6

= 3!/(3-2)!2! x 10!/(10-5)!5! + 3!/(3-1)!1! x 10!/(10-6)!6!

= 3x2!/2! x 10x9x8x7x6x5!/5!5! + 3x2!/2! x 10x9x8x7x6!/4!6!

= 3 x 252 + 3 x 210

= 756 + 630

= 1,386 ways

The ways she can select 7 workshops if 2 or fewer must be about anthroplogy is 1,386 ways

A bike wheel as a radius of 13 inches. a. About how far does the bike wheel tra in 1 rotation? 5 rotations? 30 rotations? b. Write an equation relating the distance the bike travels in inches, b, to the number of wheel rotations, x. c. About how many rotations does the bike wheel make when the bike travels 1 mile?

Answers

The radius of the bike wheel is given as 13 inches. One rotation would be equal to the entire circumference of the bike wheel. Hence;

[tex]undefined[/tex]

The line that passes through the points (3,0) and (-5,8) isA.)DecreasingB.)IncreasingC.)HorizontalD.)Vertical

Answers

The slope of a line

It is a parameter that can help us to know the behavior of a line, specifically if it's increasing, decreasing

Find an equation of an ellipse satisfying the given conditions Vertices: (0 - 6) and (0.6) Length of minor axis: 8

Answers

As the given vertices are at a distance of 12 units:

As the major axis is vertical you have the next generall equation:

[tex]\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1[/tex]

To find the center (h,k) of the ellipse use the coordinates of that vertices as follow:

[tex](\frac{0+0}{2},\frac{6-6}{2})=(0,0)[/tex]

Now use the distance between those vertices to find a:

[tex]a=\frac{12}{2}=6[/tex]

b is the distance of minor axis divided into 2:

[tex]b=\frac{4}{2}=2[/tex]

Then, you get the next equation for the given ellipse:

[tex]\begin{gathered} \frac{(x-0)^2}{2^2}+\frac{(y-0)^2}{6^2}=1 \\ \\ \frac{x^2}{4}+\frac{y^2}{36}=1 \end{gathered}[/tex]

The figure below is an isosceles trapezoid:KLIK = 12x - 34IL = 4x - 10X =Blank 1:

Answers

From the definition, it must have symmetry in the present figure. It seems to be a vertical line going through the middle of the drawing. From this, we can say that:

[tex]\begin{gathered} IK=JL \\ 12x-34=4x-10 \end{gathered}[/tex]

Now, we can solve it.

[tex]\begin{gathered} 12x-34=4x-10 \\ 12x-4x=34-10 \\ 8x=24 \\ x=\frac{24}{8} \\ x=3 \end{gathered}[/tex]

Which identity/formula was used to simplify from step 2 to step 3?

Answers

Solution:

The reciprocal identities of trigonometry include the identities below

[tex]\begin{gathered} \csc \theta=\frac{1}{\sin \theta} \\ \sec \theta=\frac{1}{\cos \theta} \\ \cot \theta=\frac{1}{\tan \theta} \\ \tan \theta=\frac{1}{\cot \theta} \\ \cos \theta=\frac{1}{\sec \theta} \\ \sin \theta=\frac{1}{\csc \theta} \end{gathered}[/tex]

The quotient identity include the identities below

[tex]\begin{gathered} \tan \theta=\frac{\sin \theta}{\cos \theta} \\ \cot \theta=\frac{\cos \theta}{\sin \theta} \end{gathered}[/tex]

The sum formula of trigonometric identity include

[tex]\begin{gathered} \sin (\alpha+\beta)=\sin \alpha\cos \beta+\cos \alpha\sin \beta \\ \sin (\alpha-\beta)=\sin \alpha\cos \beta-\cos \alpha\sin \beta \\ \cos (\alpha+\beta)=\cos \alpha\cos \beta-\sin \alpha\sin \beta \\ \cos (\alpha-\beta)=\cos \alpha\cos \beta+\sin \alpha\sin \beta \end{gathered}[/tex]

The double-angle formula is given below as

Hence,

The final answer is QUOTIENT IDENTITY

I NEED HELP WITH THIS TWO7) the shirt costs $25. the discount is 18% how many dollars is the discount? 8) 40% of 120 students passed the test. How many students passed?

Answers

If the shirt costs 25 and the discount is 18%, then the amount discounted is shown as follows;

[tex]\begin{gathered} \text{Cost}=25 \\ \text{Discount}=0.18 \\ \text{Discounted amount=25}\times0.18 \\ \text{Discounted amount=4.5} \end{gathered}[/tex]

The discount is $4.5.

If 40% of students passed out of 120, then the number that passed is shown below;

[tex]\begin{gathered} Total\text{ number=120} \\ \text{Percentage that passed=0.40} \\ \text{Number that passed=120}\times0.40 \\ \text{Number that passed=48} \end{gathered}[/tex]

The number of students that passed is 48

Answer: 7. $20.50 & 8. 48 students

Step-by-step explanation:

At 1:00 AM the temperature was 87º. A cold front came through and at 7:00 PM the temperature was 45°. What is the rate of change in the temperature in degrees per hour?

Answers

the rate of change in the temperature per hour is the quotient of the change of temperature divided by the change in hours. Since we have

1:00 AM =1 hr - 87 degrees

7:00 PM=19 hrs - 45 degrees,

then the rate is

[tex]\frac{45-87\text{ }}{19-1}=\frac{-42}{18}=-\frac{7}{3}=-2.33[/tex]

Then, the temperature changed -2.33 degrees per hour.

Points A(-2,-3),B(-2,4),and C(3,6) are three vertices of parallelogram ABCD. Opposite sides of a parallelogram have the same length. Draw the parallelogram in the coordinate plane and label the coordinates of the fourth point.

Answers

Given:

Points A(-2,-3),B(-2,4),and C(3,6) are three vertices of parallelogram ABCD.

As we know, the opposite sides of the parallelogram are parallel and congruent

To draw the parallelogram, we will draw the points and connect the sides

AB, AC, and BC

then, draw two lines parallel to AB from C and BC from A, the intersection will give the point D

The graph of the parallelogram will be as shown in the following picture

As shown the coordinates of the fourth point D = (3, -1)

[tex]7x(x + 4) = [/tex]simplify

Answers

Given expression:

[tex]=\text{ 7x(x + 4)}[/tex]

Expanding:

[tex]\begin{gathered} =\text{ 7x }\times\text{ x + 7x }\times\text{ 4} \\ =\text{ 7 }\times\text{ x }\times\text{ x + 7 }\times\text{ x }\times\text{ 4} \\ =\text{ 7 }\times x^2\text{ + 7 }\times\text{ 4 }\times\text{ x} \end{gathered}[/tex]

Simplifying the expression:

[tex]\begin{gathered} =7\times x^2\text{ + }28\times x \\ =7x^2\text{ + 28x} \end{gathered}[/tex]

Answer:

[tex]7x^2\text{ + 28x}[/tex]

Recall: Averaging Two NumbersMaddie earned an 88% on her first test and an 80% onyour second test. What is her average test score? (Note:Click on the little calculator icon above to pull up acalculator.)

Answers

We know that

• She earned an 88% on her first test.

,

• She earned an 80% on her second test.

To know her average score, we just have to sum these percentages and divide them by 2, since they are just 2.

[tex]\bar{x}=\frac{88+80}{2}=\frac{168}{2}=84[/tex]Therefore, the average test score is 84%.

A rectangle or televisions length is 3 inches more than twice its width the perimeter of the television is 144 inches what is the width of the television

Answers

The width of the television is 23 in.

What is rectangle?

A rectangle is a closed 2-D shape, having 4 sides, 4 corners, and 4 right angles. The opposite sides of a rectangle are equal and parallel.

Given that, A television's length is 3 inches more than twice its width the perimeter of the television is 144 inches

Perimeter of a rectangle = 2(length+width)

According to question,

l = 3+2w

Therefore,

Perimeter = 2(w + 3+2w) = 144

3w + 3 = 72

3w = 69

w = 23

Hence, The width of the television is 23 in.

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1. An equation is shown below. 60 10 100 = Determine the value of the missing numerator. Your answer

Answers

Answer:

m = 6

Explanations:

The given equation is:

[tex]\frac{m}{10}=\text{ }\frac{60}{100}[/tex]

Cross multiply:

100m = 60 x 10

100m = 600

Divide both sides by 100

[tex]\begin{gathered} \frac{100m}{100}=\text{ }\frac{600}{100} \\ m\text{ = 6} \end{gathered}[/tex]

The missing numerator is 6

de a and perform the symmetry lest on each of the following is. eld plerd Find the in 16 r2 + 25y2 = 400 A00 (c) r2 + 4y2 = 4 (e) 4x2 + y2 = 64 (B) 9x² + 4y2 = 36 (b) 25x+6y (d) 4x + y = A () Ay? (h) 7x + y - 112 Graph the vertices, foci, endpoints of the minor axis, and endpoints of the latera recta, then draw AB is a chord of the partial ellipse with equation f(x) = ba? - x'. (a) 576x2 + 625y2 = 360,000, A (15,f(15)), B(20, f(20)) (b) 49x 2 + 625y2 = 30,625, A (15, f(15)), B(20,f(20)) – x. Find the length of AB using

Answers

The given ellipse is

[tex]576x^2+625y^2=360,000[/tex]

Where A(15, f(15)), B(20, f(20)).

First, we find f(15) and f(20) by evaluating the given expression

[tex]\begin{gathered} f(15)=576(15)^2+625y^2=360,000 \\ 576\cdot225+625y^2=360,000 \\ 129,600+625y^2=360,000 \\ 625y^2=360,000-129,600 \\ 625y^2=230,400 \\ y^2=\frac{230,400}{625} \\ y^2=368.64 \\ y=\sqrt[]{368.64} \\ y=19.2 \end{gathered}[/tex]

We use the same process to find f(20).

[tex]\begin{gathered} f(20)=576(20)^2+625y^2=360,000 \\ 576\cdot400+625y^2=360,000 \\ 625y^2=360,000-230,400 \\ x^2=\frac{129,600}{576} \\ x=\sqrt[]{225}=15 \\ \end{gathered}[/tex]

So, the points are A(15, 19.2) and B(20, 15). To find the distance between these points, we have to use the distance formula

[tex]\begin{gathered} d_{AB}=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ d_{AB}=\sqrt[]{(20-15)^2+(15-19.2)^2} \\ d_{AB}=\sqrt[]{5^2+(-4.2)^2}=\sqrt[]{25+17.64}=\sqrt[]{42.64} \\ d_{AB}\approx6.5 \end{gathered}[/tex]Hence, the length of AB is around 6.5 units.

Bobs car rental is offering a special of 40$ a day for a seden as long as you purchase the car damage protection insurance for 20$

Answers

In this case, we have a proportional relationship, since the cost varies directly with the days, this means that as x increases, y increases, and as x decreases, y decreases. A proportional relationship has the form:

y=kx

Where k is the constant of proportionality.

The ratio between them (x and y) is always the same, in this case, the ratio or constant of proportionality is 40, since each day the rent cost increases $40, then:

Constant of proportionality = 40 , replacing 40 for k into the above equation, we get:

equation: y = 40x

We can use this equation to find some pair of values (x,y) to fill the table, like this:

For x equals 2:

y= 40*2 = 80

For x equals 3:

y= 40*3 = 120

For x equals 4:

y=40*4 = 160

For x equals 5:

y=40*5=200

Then, we can fill the table as follows:

We can also use these data to graph the relationship, by taking the point (5,200) and joining it to the origin, we get:

A jewelry salesperson earns 5 1/5 % commission on all sales. Today he sold $7,310 in jewelry. What is his total commission earned?
The total commission the salesperson earned is

Answers

The total commission salesperson earned is $394.5.

What is commission?

Commissions are a type of variable-pay compensation for provided services or sold goods. Commissions are a typical method of encouraging and rewarding salespeople. It is also possible to create commissions to promote particular sales behaviours. For instance, while offering significant reductions, commissions might be decreased.

Given:  A jewelry salesperson earns 5 1/5 % commission on all sales. Today he sold $7,310 in jewelry.

We have to find the commission earned on $7310.

Here, [tex]5\frac{1}{5} = \frac{(5)(5)+2}{5} =\frac{27}{5}[/tex]

5 1/5% = 27/5%

Today he sold $7310 in Jwellary.

So, the commission is,

[tex]\frac{(7310)(27)}{(5)(100)} = 394.5[/tex]

Hence, the total commission of $7310 is $394.5.

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Alfred needs to buy small pumpkins that cost $2.75 each. The function he uses is ()=2.75. Use the function to determine the cost of 25 pumpkins.

Answers

From the question, we have a linear function for the cost of each pumpkin, and this function is:

[tex]f(x)=2.75x[/tex]

As we can see, the cost for one pumpkin is:

[tex]f(1)=2.75(1)=\text{ \$2.75}[/tex]

Now, to find the cost for 25 pumpkins, we need to substitute the value of x = 25 into the function, since this is a function that gives us the cost as a function of the number of pumpkins:

[tex]\begin{gathered} f(x)=2.75x \\ \\ f(25)=2.75(25)=68.75 \\ \\ f(25)=68.75 \\ \\ \end{gathered}[/tex]

As we can see, we multiply 2.75 times 25, and we got 68.75.

Therefore, in summary, it will cost $68.75 for 25 pumpkins.

The coordinates below represents points that were translated.Match the coordinates with the correct algebraic representations

Answers

Answer:

R(1, 8) >> R'(10, -10) ........(x+9, y-18)

V(-2, -10) >> V'(5, -3).......(x+7, x+7)

U(3, -9) >> U'(10, -16).......(x+7, y-7)

T(-4, 7) >> T'(-11, 14)..........(x -7, y+7)

Explanations:

When a pont A(x, y) is translated by a in the x-axis, and b in the y-axis, the new point becomes A'(x+a, y+b)

For the expression R(1, 8) >> R'(10, -10)

The coordinates of R' ae formed using the expression (x+9, y-18)

For the expression V(-2, -10) >> V'(5, -3)

The coordinates of V' are formed by using the expression (x+7, x+7)

For the expression U(3, -9) >> U'(10, -16)

The coordinates U' are formed by using the expression (x+7, y-7)

For the expression T(-4, 7) >> T'(-11, 14)

The coordinates T' are formed by using the expression (x -7, y+7)

from the base of the tower, you meassure its shadow to be 17.25m.at same the time your shadoe is 0.21m.you are 1.68 tall.how tall ia the tower?(round to two decimal plaves if necessary)

Answers

The Solution:

Representing the given in a diagram, we have

By similarity theorem, we have that:

[tex]\frac{BA}{BT}=\frac{BC}{BD}[/tex]

So,

[tex]\begin{gathered} BA=1.68m \\ BT=h=(1.68+x)m \\ BC=0.21m \\ BD=17.25m \end{gathered}[/tex]

Substituting these values in the formula above, we get

[tex]\frac{1.68}{1.68+x}=\frac{0.21}{17.25}[/tex]

Solving for x:

We shall cross multiply,

[tex]0.21(1.68+x)=1.68\times17.25[/tex][tex]0.3528+0.21x=28.98[/tex][tex]0.21x=28.98-0.3528=28.6272[/tex]

Dividing both sides by o.21, we get

[tex]x=\frac{28.6272}{0.21}=136.32\text{ m}[/tex]

The height of the tower is

[tex]h=1.68+x=1.68+136.32=138m[/tex]

Therefore, the correct answer is 138 meters.

Convert the following unit areas as indicated. Choose the right answe Area Conversion Number Table English Area Conversion Number Metric Area Square Miles Square Miles Acres Acres Square Yards Square Feet Square Inches 2.59 259 4.05 x 10-3 4.05 x 10-1 8.36 x 10-1 9.29 x 10-2 6.45 Square Kilometers Hectares Square Kilometers Hectares Square Meters Square Meters Square Centimeters 50 in.2 to cm2

Answers

Answer:

322.5 square centimeters

Explanation:

To convert from square inches to square centimeters, we need to multiply the number by the conversion factor 6.45, so 50 in² are equivalent to:

50 in² x 6.45 = 322.5 cm²

Therefore, the answer is 322.5 square centimeters.

PLSSSSSS HELPPPP ASAPP i only need everything in measuring segments , congruent segments and segment addition

Answers

the answer are:

1. A(X +Y),,B (X+Y) OR d(A,B)

2. If two segments having the same length are congruent segments.This is written as for example: AB is congruent with CD.

AB=CD

3. AC=B, because B is inside points A and C it means that it was the additional point to add and arrive at C.

[tex]1144 \times \frac{25}{3699} + 114 \sqrt[1441]{36} - y + x \div 15663 = 2 - \sqrt[44410]{3651} + {2554}^{2} [/tex]first equation. then text

Answers

how does equation look in session history???

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