The cost of method because the source's pace procedures the velocity of sound transferring to the proper will be 1/2fs.
When each movements withinside the same route with same velocity n' = n, i.e. there can be no Doppler impact because of the truth relative motion amongst deliver and listener is zero.
The motion of the observer will adjust the frequency of the measured sound from a table certain deliver: An observer moving in the direction of the deliver measures a higher frequency. An observer moving a ways from the deliver measures a lower frequency.
The Doppler impact is an alteration withinside the determined frequency of a legitimate due to motion of each the deliver or the observer. The actual trade in frequency is called the Doppler shift.
It will cause an increase in frequency heard thru an observer at the same time as the deliver is moving withinside the direction of the observer and a decrease in frequency heard thru an observer at the same time as the deliver is moving a ways from the observer. The doppler impact can be determined at the same time as an ambulance with a siren on procedures and passes an observer.
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a certain heat engine operates between temperatures of -10 oc and 180 oc. what is the maximum possible efficiency this engine can achieve? express your answer as a percentage.
The maximum possible efficiency this engine can achieve is 41.9%.
What is efficiency of an engine?The ratio between the total quantity of energy in the fuel and the amount of energy used to carry out productive work is known as the engine efficiency of thermal engines. Thermal engines may be divided into two categories:
Engines that burn fuel internally (such as gasoline, diesel, and gas turbines with Brayton cycles) and externally (steam piston, steam turbine, and the Stirling cycle engine). These engines each have distinct thermal efficiency characteristics.
here ,
T1 = -10 C = 263.15 K
T2 = 180 C = 453.15 K
Maximum efficiency of heat engine,
η = T2−T1 / T2
= (453.15 − 263.15) / 453.15
= 0.419 = 41.9 % ≈ 50%
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What Happens to the Pressure of a Gas if You Decrease the Volume of the Container That Holds It?
Answer: The pressure gets worse.
Explanation:
the moon has a mass of 7.35×1022kg and a radius of 1.74×106m. it orbits around the earth at a distance of 3.84×108m, completing a full rotation every 27.3days. it also spins on its axis at a rate such that the same side of the moon is always facing the earth.• What is the angular momentum of the Moon in its orbit around Earth in kg-m²/s?o Lorb = 1• What is the angular momentum of the Moon in its rotation around its axis in kg-m/s?• How many times larger is the orbital angular momentum than the rotational angular momentum for the Moon?
Angular momentum of moon = 2.88 × [tex]10^{34}[/tex]kg.[tex]\frac{m^{2} }{sec}[/tex]
The orbital angular momentum of the Moon is 1.22 × [tex]10^{5}[/tex] times more than its rotating angular momentum.
Mass of moon = 7.35 × 10²²kg
radius (r) = 1.74 × [tex]10^{6}[/tex]m
Time period (T) = 27.3days = 27.3 × 24 × 3600sec
distance from earth(R) = 3.84 × [tex]10^{8}[/tex] (= orbiting radius)
a) Angular momentum of moon in its orbit around earth is
[tex]L_{orb}[/tex] = [tex]I_{w}[/tex]
in where I = moment of inertia = m[tex]R^{2}[/tex] = 7.35 × 10²² ( 3.84 × [tex]10^{8}[/tex])²
= 1.084 × [tex]10^{40}[/tex] kg.m²
and ω = 2π/T
= 2π/27.3 × 24 × 3600 = 2.66 × [tex]10^{-6}[/tex][tex]\frac{rad}{sec}[/tex]
[tex]L_{orb}[/tex] = [tex]I_{w}[/tex] = 1.084 × [tex]10^{40}[/tex] kg.m² × 2.66 × [tex]10^{-6}[/tex]
[tex]L_{orb}[/tex] = 2.88 × [tex]10^{34}[/tex]kg.[tex]\frac{m^{2} }{sec}[/tex]
b) Angular momentum of moon around it's axis is (due to rotation),
[tex]L_{m} = I_{m} W_{m}[/tex] = [tex]\frac{2}{5}[/tex] mr² × 2π/T = [tex]\frac{2}{5}[/tex] × 7.35 × [tex]10^{22}[/tex] × (1.74 × [tex]10^{6}[/tex])² × 2.66 × [tex]10^{-6}[/tex]kg.[tex]\frac{m^{2} }{sec}[/tex]
[tex]L_{orb}[/tex] = 2.37 × [tex]10^{29}[/tex] kg.[tex]\frac{m^{2} }{sec}[/tex]
c) The required fraction is:
[tex]\frac{L_{orb} }{L_{rot} }[/tex] = [tex]\frac{2.88(10^{34} )}{2.37(10^{29} )}[/tex] = 1.22 × [tex]10^{5}[/tex]
[tex]\frac{L_{orb} }{L_{rot} }[/tex] = 1.22 × [tex]10^{5}[/tex]
What in physics do you mean by orbital angular momentum?
An aspect of an electron's rotational motion called orbital angular momentum is connected to the orbital's geometry. If detection is attempted, the electron will be located in the orbital, which is the area surrounding the nucleus. The orbital around the nucleus has been been referred to as a "electron cloud."
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students perform an experiment by connecting a capacitor and a light bulb to a variable power supply in the circuit shown. the switch is closed to position a, the capacitor becomes fully charged, and then the switch is moved to position b and allowed to fully discharge. what happens to the amount of energy stored in the capacitor as the voltage of the power supply is increased, and what evidence supports this claim?
The amount of energy stored in the capacitor is c)increases as the bulb stays lit the same amount of time. So, correct option is c.
Work must be finished to move charges onto a guide, against the power of shock from the generally existing charges on it. This work done to charges from one plate to the next is put away as expected energy of the electric field of the conveyor.
The bulb will illuminate for a moment when the capacitor begins charging. At first when key is shut, the capacitor goes about as short out, so bulb will illuminate. In any case, at last the capacitor turns out to be completely energized, so it will go about as open circuit, so bulb won't gleam.
Hence, correct option is c.
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(Complete question) is:
A Power С Supply Students perform an experiment by connecting a capacitor and a light bulb to a variable power supply in the circuit shown. The switch is closed to position A, the capacitor becomes fully charged, and then the switch is moved to position B and allowed to fully discharge. What happens to the amount of energy stored in the capacitor as the voltage of the power supply is increased, and what evidence supports this claim?
a)The energy increases as the bulb stays lit a shorter amount of time.
b) The energy increases as the bulb stays lit a longer amount of time.
c) The energy increases as the bulb stays lit the same amount of time. d)The energy decreases as the bulb stays lit a shorter amount of time.
e )The energy decreases as the bulb stays lit a longer amount of time.
How do you do a dilation with a center different from the origin?
The Dilation with a center different from the origin is by stretching process.
Stretching is a type of transformation that changes the size of an image. A scale factor, also known as a scalar factor, measures how big or small an image is.
Some of the shape features that are not changed during the dilation transformation are:
All angles of the shape are equal.The center of the sides of the shape remains the same as the center of the stretched shape.The parallel and vertical lines in the shape remain the same as the parallel and vertical lines of the stretched shape.The image remains the same.The only change in the stretching process is the distance between the points.This means that the original image and the enhanced image may have different side lengths. There are two types of expansion processes.
Horizontal StretchThe stretch transformation of the function y=f(x) is stretched horizontally by a factor C.
Y = f(Cx)
This type of transformation is called horizontal stretching.
Vertical StretchThe Stretch transform in the function y=f(x) is stretched vertically by a factor C.
Y = C * f(x)
This type of transformation is called vertical stretching.
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when an earthquake occurs, two types or sound waves are generated and travel through the earth. i he primary, or p wave nas a speed of about 8.0 km/s and the secondary, or 5, wave has a speed of about 4.5 km/s. a seismograph, located some distance away, records the arrival of the p wave and then, 90.6 s later, records the arrival of the s wave. assuming that the waves travel in a straight line, how far (in terms of m) is the seismograph from the earthquake?
Body waves and surface waves are the two types of waves that an earthquake can produce.
What does an earthquake's sound wave look like?
Seismic waves, which are audible but undetectable to human eyes and hearing, pulse through the strata of the Earth beneath the surface of the planet as it trembles. Sound waves that can be monitored or even recorded to provide advance notice of an impending seismic catastrophe.
How far do seismic waves travel during an earthquake?
Through seismic waves, earthquakes unleash buried energy in the rocks. The seismic waves that result from an earthquake radiate from the epicenter outward.
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Two people push a 2,000-kg car to get it started. An acceleration of at least 5. 0 m/s^2 is required to start the car. Assuming both people apply the same magnitude force, how much force will each need to apply if friction between the car and the road is 300 n?.
Both people will have to apply a force equal to 5150N.
This problem can be solved using Newton's Second Law of Motion which states that the force applied on any particle is equal to the product of mass and acceleration of the particle. The expression can be written as
F = ma ; where 'm' is the mass of particle and 'a' is the acceleration of particle.
Now, m = 2000 kg and a = 5 m/s²
F = 2000 kg × 5 m/s²
F = 10000 N
Now, the friction force will be added to this required force. Because to get the car starting to move, the friction force first needs to be overcome.
Total force = F + Frictional force
Total force = 10000 N + 300 N
Total force = 10300 N
Now individual force applied by each person = 10300 N/2 = 5150 N.
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a flat coil of wire consisting of 200 turns, each with an area of 15 cm, is positioned perpendicularly to a uniform magnetic field that increases its magnitude at a constant rate from -0.24 t to 0.19 t in 6.0 s. if the coil has a total resistance of 54 , what is the magnitude of the induced current when the field is -0.024999999999999994 t
The size of the eddy emf because when field is I = 0.5 A when a flat coil of wire with 200 turns and an area of 15 cm each is placed perpendicular to a consistent magnetic field and increases in strength at a rate of
What would a magnetic field do, simply put?The magnetic field is the area in which a magnet experience the effects of magnetism. The magnetic field is an effective tool for describing how the magnetic force is distributed within and around a magnet object in nature.
E=−NAd BdtE=−(50×10−4m2)×20××4.0T2.0sE=−0.2 VNow; Magnitude of the induced current
I=Induced emf ResistanceI=ERI=0.2V0.40ΩI=0.5A
How are magnetic fields used?The same poles were drawn from one another while the opposite poles were drawn toward one another. When brushed against a magnet, the north-seeking poles of the iron atoms align in the same direction. The force created by the aligned atoms results in the creation of a magnetic field.
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If 104 w/m2 corresponds to 160 db, what is the sound intensity level, in decibels, of ultrasound with intensity 105 w/m2, used to pulverize tissue during surgery?.
The ultrasound with intensity 10⁵ W/m², used to pulverize tissue during surgery, has the sound intensity level of 170 decibels.
The relation between sound intensity and sound intensity level is given by:
β (dB) = 10 x log(I/Io)
Where:
β = sound intensity level in decibels (dB)
I = sound intensity
Io = reference intensity
In the given problem:
β = 160 dB if I = 10⁴ W/m²
Find the reference intensity:
β = 10 x log(I/Io)
160 = 10 x log (10⁴ /Io)
log (10⁴ /Io) = 16
Io = 10⁻¹²
Use Io = 10⁻¹² to calculate the sound intensity level of 10⁵ W/m² sound intensity.
β = 10 x log(10⁵/10⁻¹²)
β = 10 x log(10¹⁷)
= 170 dB
Hence, the sound intensity level is 170 dB
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an arrow is shot straight up in the air at an initial speed of 12.3 m/s. after how much time will the arrow heading downward at a speed of 7.9 m/s? assume the magnitude of g
2.06 second will the arrow heading downward at a speed of 7.9 m/s
Calculation :
As the arrow leaves the bow, it experiences a constant downward acceleration equal to the free fall acceleration g. Upwards, positive direction, the elapsed time/s it takes for the velocity to increase from an initial value of 15.0 m/s upwards (v₀= +12.3 m/s) to a value of 7 .9 m/s downwards change ( vf=−7.9m/s) is
ΔT = ΔV/a
= [tex]\frac{Vf-Vo}{g}[/tex]
=[tex]\frac{12.3-(-7.9)}{9.8}=[/tex] 2.06 sec
Just as distance and displacement (albeit similar) have distinctly different meanings, so do velocity and velocity.speed is a scalar quantity that describes how fast an object is moving. Velocity can be thought of as the speed at which an object travels a distance. A fast-moving object has a high speed and travels a relatively long distance in a short period of time. Compare this to slow, slow-moving objects. Covers a relatively short distance in the same amount of time. A motionless object has zero velocity.
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how would coulomb's law be written if the charge of an electron was instead defined as positive and the proton as negative?
If the charge of an electron were regarded as positive and the charge of a proton as negative, then coulomb's law appears to be
[tex]F = k\frac{q_{1}q_{2} }{r^{2} }[/tex] ⇒ [tex]F = k\frac{-q_{1}(-q_{2}) }{r^{2} }[/tex] ⇒ [tex]F[/tex].
Suppose,
Electrons are positive, the charge can be written as q, and
Protons are negative, their charge can be seen as being -Q.
It would be akin to inverting the signs of all charges if protons had a negative charge and electrons had a positive charge. This makes it very easy to verify that Coulomb's Law adheres to charge symmetry by using the substitutions q1→−q1 and q2→−q2.
[tex]F = k\frac{q_{1}q_{2} }{r^{2} }[/tex] ⇒ [tex]k\frac{-q_{1}(-q_{2}) }{r^{2} }[/tex] ⇒ [tex](-1)^{2} k\frac{q_{1}q_{2} }{r^{2} }[/tex] [tex]= F[/tex]
Therefore, there would be no difference if we switched the sign convention of the charges.
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Bert has a mass of 120kg. He slides down a slide, which goes 12 m down. Calculate the maximum speed he could reach at the bottom of the slide.
a) Work out the GPE
b) How much KE? (GPE lost = KE gained)
c) Rearrange the KE formula to work out velocity
(a) The gravitational potential energy (GPE) of Bert is 14,112 J.
(b) The kinetic energy of Bert is equal to the change in his potential energy.
(c) The velocity of Bert could reach at the bottom of the slide is 15.33 m/s.
What is the gravitational potential energy of Bert?The gravitational potential energy of Bert is calculated as follows;
GPE = mgh
where;
m is mass of Bertg is acceleration due to gravityh is the height of fallGPE = 120 x 9.8 x 12
GPE = 14,112 J
The velocity Bert could reach at the bottom of the slide is calculated as follows;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √ (2gh)
v = √ (2 x 9.8 x 12)
v = 15.33 m/s
Based on the law of law of conservation of energy, the kinetic energy gained = potential energy lost.
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a transformer has 412 loops in the the primary coil and 319 loops in the secondary coil. if the input current is 2 a, what is the output current of the transformer in amps?
the output current of the transformer in amps is 2.58 A
Calculation :
Transformation ratio k=[tex]\frac{N2}{N1} = \frac{V2}{V1}=\frac{I1}{I2}[/tex]
N₁ = 412 , N₂ = 319
I₁ = 2 A
To find I₂,
[tex]\frac{I1}{I2} =\frac{N2}{N1}[/tex]
I₂ = (I₁)([tex]\frac{N1}{N2}[/tex])
I₂ = (4)([tex]\frac{412}{319}[/tex])
I₂ = 2.58 A
Electric current is the flow of charged particles, such as electrons and ions, that travel through a conductor or space. [1]: 2 [2]: 622 Moving particles are called charge carriers and can be one of several types depending on the particle. to the conductor. In electrical circuits, charge carriers are often electrons moving through wires. In semiconductors they can be electrons or holes. In electrolytes the charge carriers are ions and in plasmas ionized gases, ions and electrons.
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when the lobes of two p orbitals are in the same phase and overlap side-by-side, the orbital that is formed has a _____ dissociation energy compared to the σ∗ molecular orbital formed from the out-of-phase direct overlap of the two p orbitals.
In contrast to the σ∗ molecular orbital created by the direct out-of-phase overlap of two p orbitals, the orbital formed when the lobes of two p orbitals overlap side by side has a lower bond dissociation energy.
The atoms come together by collisions. The process in which two atoms get so close to one another that they can pierce each other's orbitals and create a new hybridized orbital where the bonding pair of electrons resides is essentially what this condition refers to. This hybridized orbital is stable because it typically has less energy than the atomic orbital. It is in the state of least energy. Orbital overlap is the term for this little orbital penetration.The directionality of the bond was used to explain the molecular bond angles. The overlap of 1s orbitals during a head-on collision results in the formation of the hydrogen molecule. or we could claim that the head-on overlap is mostly responsible for the formation of the sigma bonds.To know more about molecular
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What group(s) of elements on the periodic table really want to give away an electron? why?.
The groups in the periodic table that really want to give away electrons are groups IA, IIA, and some groups IIIA. The members of these groups are mostly metals.
Metals elementsMetals elements have relatively small ionization energies and electron affinities, so they easily give away electrons and are difficult to accept. Whereas non-metallic atoms have large ionization energies and electron affinities, non-metallic atoms easily accept electrons but find it difficult to release electrons.
Ionization energy is the energy required to remove the outer electrons of an atom in the gaseous state. A small ionization energy value indicates that the atom easily releases electrons and if the ionization energy is large, it is difficult for the atom to release electrons.
So, metal atoms tend to give away electrons because they have a small ionization energy, while non-metal atoms tend to gain electrons because they have a high electron affinity.
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a type e0 galaxy would be select an answer and submit. for keyboard navigation, use the up/down arrow keys to select an answer. a an extra large elliptical. b a spherical galaxy. c a galaxy with a disk but no spiral arms. d an extremely flattened elliptical galaxy. e a spiral galaxy with a large central bulge.
A type E0 galaxy would be a spherical galaxy. Therefore, the correct answer is option B.
Galaxies can be categorized by their shape. They can range from almost spherical to almost flat or even spiral. Here are each class's characteristics:
Spiral galaxy is classified as an "S" galaxy with subclassification a, b, or c based on the size of the bulge. Sa galaxy has a bigger bulge than Sc galaxy.Barred spiral galaxy is classified as "SB" with subclassification a, b, or c.Elliptical galaxy is classified as "E" with subclassification using numbers 0 to 7. E0 galaxy is the roundest elliptical galaxy class, while E7 is the most elliptical-shaped galaxy class.Irregular galaxy is classified into two classes: Irregular I (have some spiral structure that seems disrupted) and Irregular II (much more disturbed).Attached below is a graph of how galaxies are classified by their shape made by Dr. T.H. Jarrett.
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a car's tires of 0.20 m radius have an angular acceleration of 10 rad/s2. assume no slippage. how many revolutions do the tires make in 1.0 s if they start from rest?
The car tires made 0.8 revolutions in 1 s from rest.
Assuming that angular acceleration is constant, the following kinematic equation is used.
θ = θ₀ + ω₀* t + 1/2* α* t²
where,
θ is final angular position in radians
θ₀ is initial angular position in radians
ω₀ is initial angular speed in rad/sec
α is angular acceleration
t is the time measured in seconds
Given that,
Radius = 0.2 m
Angular acceleration α = 10 rad/s²
Time t = 1 sec
If θ₀ = 0, ω₀ = 0, α = 10 rad/s², θ is
θ = 0 + 0* 1 + 1/2* 10 * 1² = 5 rad
Let us convert radians into revolutions:
We know that, 2π radians = 1 revolution
1 radian = 1/(2π) revolutions
5 radian = 5/(2π) revolutions = 5/6.28 = 0.8 revolutions
The tires did 0.8 revolutions in 1 second from rest.
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a 0.00120-nm photon scatters from a free electron. for what (photon) scattering angle does the recoiling electron have kinetic energy equal to the energy of the scattered photon?
a 0.00120-nm photon scatters from a free electron -
a) λ₁ = 5.27 × 10⁻³ nm
b) E = 30 KeV
What is free electron?Free electrons are those that are not constrained by the atom and are hence free to travel. Since we now know that an electric current is just an electron moving, The ability to conduct electricity results from the free electrons' propensity for free motion. Because they are efficient electrical conductors, metals have free electrons.
a)
λ is the wavelength of the photon before scattering,
λ₁ is the wavelength of the photon after scattering,
m(e) is the mass of the electron,
θ is the angle by which the photon's heading changes,
h is Planck's constant, and
c is the speed of light
λ₁ - λ = [h/m(e)c] × [1 - cos θ]
Since we have energy for the incoming x-ray, we need to solve for frequency (f) and then for wavelength (λ) using the following two equations.
E = (h)×(nu),
where E is energy of the x-ray (265KeV),
h is planck's constant (4.14×10⁻¹⁵eV.s) and
nu = f (frequency).
Solving for freqency,
we get f = 6.408 × 10¹⁹ (1/s)
Frequency = c / λ,
and solving for λ,
we get the initial wavelength of the incoming x-ray to be:
λ = c/f
or, λ = [299792458 m/s] / [6.408 × 10¹⁹ 1/s]
or, λ = 4.68× 10⁻¹² m
or, λ = 4.68 × 10⁻³ nm
Going back to the Compton Scatter equation of:
λ₁ - λ = [h/m(e)c] × [1-cos θ]
we need to solve for λ₁:
λ₁ = [h/m(e)c] × [1-cos θ] + λ
or, λ₁ = [2.43 × 10⁻¹² m][1-cos 41°] + 4.68× 10⁻¹² m
or, λ₁ = 5.27 × 10⁻¹² m
or, λ₁ = 5.27 × 10⁻³ nm
b)
Going back, we can solve for the energy of the x-ray using the same two equations:
Frequency = c / λ₁
or, f = 299792458 / 5.27 ×10 ⁻¹²
or, f = 5.68 × 10¹⁹ 1/s
Plugging that into the 2nd equation:
E=(h)×(nu),
= [4.14×10⁻¹⁵eV.s] × [5.68 × 10¹⁹ 1/s]
= 235KeV
and with the conservation of energy
E = 265 KeV - 235 KeV
E = 30 KeV
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just to be sure you understand how to use and interpret the interactive figure, start with the time slider set to zero. what is the distance from dot b to dot d?
The answer is 2 cm.
Coherent light with wavelength 400 nm passes through two very narrow slits that are separated by 0.200 mm and the interference pattern is observed on a screen 4.00 m from the slits. What is the width (in mm) of the central interference maximum?
The width of central interference maximum is 16000×10⁻⁹m if wavelength 400nm passes through two narrow slits.
The width of the central maximum is two times as a significant part of the other maxima. For the m t h request the essential diffraction grinding condition is m λ = d sin θ m where d is the distance between adjoining cuts and the way contrast between neighboring cuts is m λ. Cut is enlightened by the illumination of wavelength 400 A ˚.
We know that width of central maximum is represented by β ,which is equal to=2λD/d
where λ is defined as the wavelength of the light wave,
D is defined as the distance of screen from central maximum
and d is defined between the slits.
So, we have λ=400nm=400×10⁻⁹m, D=4m,d=0.200mm=0.200 ˣ 10⁻³m
Now,on putting the values in above formula, we get
=>β =2×400×10⁻⁹m×4m/0.200 ˣ 10⁻³m
=>β=3200×10⁻⁹m² / 0.200 ˣ 10⁻³m
=>β=3200000×10⁻⁹m²/200 ˣ 10⁻³m
=>β=16000×10⁻⁹m
Hence, width of central maximum is 16000×10⁻⁹m.
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when light is incident on an interface between two materials, the angle of the refracted ray depends on the wavelength, but the angle of the reflected ray does not. why should this be true
Because different visible light colors have distinct wavelengths and barely varying refractive indices, the wavelength of the light influences the angle of refraction.
For instance, you cannot tell the difference when white light passes through a flat piece of glass because it is so slight.
The reflected beam will always be refracted at the same angle that it impacted the surface since light will then continue to go through the same medium and at the same speed.
A periodic wave's wavelength is its spatial period, or the length over which its shape repeats. It is a property of both travelling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings.
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What is the wavelength of a light of frequency 4.47 x 1014 Hz?
The wavelength of light is 0.433 x 10⁻⁶m.
The quantum hypothesis proposed by Planck was that electromagnetic energy quantized in packets of energy or photons.The formula E = hvE stands for energy, h for Planck's constant, and v for frequencyThis is Planck's law, which states that energy is quantizedThis is , meaning that the energy is in the form of discrete packets. He calls quantum or quantum. All electrons belong to some energy level. If it tries to move to a higher energy level, it needs energy, but at the higher energy level it becomes unstable, releasing energy and returning to its initial state.Currently, the amount of energy absorbed or emitted is limited to a certain amount, which is an integer multiple of small units of energy called quanta.Using this concept, experimental measurements have shown that the energy of a photon is proportional to its frequency. Planck's constant h is defined as the constant of proportionality, or the ratio of a photon's energy to its frequency.y=3 x10⁸/4.47 x 10¹⁴=0.433 x 10⁻⁶mTo learn further on energy of a photon -
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the greatest ocean depths on earth are found in the marianas trench near the philippines. calculate the gauge pressure (in atm) due to the ocean at the bottom of this trench, given its depth is 11.0 km and assuming the density of seawater (1029 kg/m3) is constant all the way down.
Given that the trench is 11.0 km deep and that saltwater has a constant density of 1029 kg/m3 throughout, the gauge pressure (in atm) due to the ocean at the bottom of the trench is 992.38 atm.
It is positive for pressures above atmospheric pressure and negative for pressures below atmospheric pressure; gauge pressure is the pressure as compared to atmospheric pressure. Any fluid that is not contained has its pressure increased by the atmospheric pressure. Density is defined as the ratio of mass to volume, or mass per unit volume. It is a way to quantify how much "stuff" an object has in relation to its volume (cubic metre or cubic centimeter). In essence, density is a measurement of how closely stuff is packed together.
P = 100552500/101325
P = 992.38atm
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a particle is located at northern latitude and traveling due north with with velocity . what is the direction of the coriolis force?
The Coriolis force is perpendicular to the velocity vector, so the direction of the Coriolis force would be east.
The Coriolis force is an inertial force that arises due to the rotation of the Earth. It is directed perpendicular to the direction of motion and to the rotation of the Earth. In this case, since the particle is located at the northern latitude and traveling due north, the Coriolis force will be directed east.
To explain this in more detail, we can look at the equation for the Coriolis force:
Fc = -2*m*ω*v
Where Fc is the Coriolis force, m is the mass of the particle, ω is the angular velocity of Earth, and v is the velocity of the particle.
At northern latitudes, the angular velocity of Earth is counter-clockwise (in the northern hemisphere). Since the particle is traveling due north, its velocity vector is also pointed in a counter-clockwise direction. Therefore, the Coriolis force is directed east, perpendicular to the velocity vector.
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what must be the magnitude of the rate of change of the current in order for the self-induced emf to equal 6.70 mvmv ?
The magnitude of the rate of change of the current must be equal to 6.70 mV/mV.
What must the current change rate be in order for the self-induced emf to be equal to 6.70 mvmv?For the self-induced emf to equal 6.70 mV, the magnitude of the rate of current change must match the self-induced emf's magnitude. This implies that the current's rate of change must be 6.70 mV in magnitude.solutionThe equation = -L(di/dt) yields the magnitude of the rate of change of the current, I required for the self-induced emf to equal 6.70 mv. To solve for di/dt, rewrite the equation as di/dt = -/L.Therefore, the self-induced emf's negative value, 6.70 mv, divided by the inductance's value, L, gives the magnitude of the current's rate of change, di/dt. For instance, the magnitude of the current change rate must be -6.70 mv/0.15 Henrys = -44.67 mv/s if the inductance is 0.15 Henrys.How swiftly the current is changing is determined by the magnitude of its rate of change.To learn more about the magnitude of the rate refer to:
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Using the following equation for the combustion of octane, calculate the heat of reaction for 400. 0 g of octane. The molar mass of octane is 114. 33 g/mole.
The heat associated with the combustion of 400 g of octane, assuming complete combustion, is -16859.9 kJ.
Given, the molar mass of octane is 114.33 g/mole.
Let's consider the following thermochemical equation.
C₈H₁₈ + 25/2O₂ ----- 8CO₂ + 9H₂O ΔHᵣₓₙ = -4819
For one mole of octane = -4819kJ
The number of moles in 400 g of octane will be = 400/114.33 = 3.49 moles
So the heat associated with the combustion of 3.49 moles will be
= {3.49 ×(-4819)} kJ
= -16859.9 kJ
Therefore, the heat associated with the combustion of 400g of octane, assuming complete combustion, is -16859.9kJ
The molar heat of combustion is the heat released when one mole of a substance is completely burned. Typical combustion reactions involve the reaction of a carbon-containing material with oxygen to form carbon dioxide and water as products.
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Degeneracy pressure is the source of the pressure that stops the crush of gravity in all the following except
A) a brown dwarf.
B) a white dwarf.
C) a neutron star.
D) a very massive main-sequence star.
E) the central core of the Sun after hydrogen fusion ceases but before helium fusion begins.
In all of the following, with the exception of, degeneracy pressure is the source of the pressure that prevents the crush of gravity. The correct option is D) a very massive main-sequence star.
With the exception of stellar evolution, degeneracy pressure is the cause of the pressure that prevents gravity's crush in all of the instances below. Tiny, relatively chilly, minimal-mass red dwarfs fuse hydrogen over the course of trillions of years or more while remaining on the main sequence.Red dwarfs smaller than 0.35 M are entirely convective, according to stellar simulations. The helium produced by the thermonuclear fusion of hydrogen is thus continuously remixed throughout the star, preventing the buildup of helium at the core and lengthening the fusion period.It's possible that small main-sequence stars will continue to fuse hydrogen for hundreds of billions of years. Red dwarfs are what we call these stars.
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how fast should the platform move, vp , for the person to detect a beat frequency of 7.00 hz ? take the speed of sound to be 344 m/s .
The platform should move at a rate of 48.3 m/s. This is calculated by taking the speed of sound, 344 m/s, and dividing it by the beat frequency of 7.00 Hz (which is equal to 7 beats/second). 344 m/s / 7 beats/second = 48.3 m/s.
Step 1: Calculate the wavelength of the sound wave with a frequency of 7 Hz. The wavelength is the distance a sound wave travels in a single cycle.
Wavelength = Speed of Sound (m/s) / Frequency (Hz)
Wavelength = 344 m/s / 7 Hz
Wavelength = 49.14 m
Step 2: Calculate the speed of the platform (vp) needed to detect the beat frequency of 7 Hz.
Speed of Platform (vp) = Wavelength (m) * Frequency (Hz)
Speed of Platform (vp) = 49.14 m * 7 Hz
Speed of Platform (vp) = 343.98 m/s
Therefore, the platform needs to move at a speed of 343.98 m/s for the person to detect a beat frequency of 7.00 Hz.
The speed of sound is the distance sound travels through a medium in a given amount of time. It is typically measured in meters per second (m/s). It is determined by the properties of the medium, such as temperature, pressure, humidity, and the medium itself. In air, the speed of sound is approximately 343 m/s (1,125 ft/s). In water, the speed of sound is much faster, around 1,484 m/s (4,887 ft/s).
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A riverboat travels km downstream in hours. It travels km upstream in hours. Find the speed of the boat and the speed of the stream.
The boat’s speed when in water is = 20km/hr. The stream’s speed is = 3km/hr
The Riverboat
Downstream= 46km and 2 hours
Upstream= 51km and 3 hours
Speed of the boat?
Let
X= the boat’s speed when it is in the water
C= the stream’s speed
(X+C)= the boat’s speed downstream
(X-C)= the boat’s speed upstream
Distance/speed=time
46/(x+c) = 2
51/ (x-c) = 3
2x + 2c = 46
3x – 3c = 51
6x + 6c = 138 (×3)
6x – 6c = 102 (×2)
Add
12x= 240
x=20
2c = 46-2x = 46 – 40= 6
c = 3
Therefore;
The boat’s speed when in water is = 20km/hr
The stream’s speed is = 3km/hr
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if distance of travel increases and time remains same what happens to the speed
Answer: By increasing speed over a fixed period of time, you increase
the distance you travel in that period of time. If you drive 20 mph
for an hour, you go 20 miles. If you drive 30 mph for that same
hour, you go 30 miles. Just like you knew you would.
Explanation: