In order to calculate the percent yield of a reaction we will use:
%yield = (actual yield/theoretical yield) * 100
%yield = (0.145/0.105) * 100
%yield = 138%
Answer:
See attached worksheet
Explanation:
As the worksheet explains, the fiorst step is to have a balanced equation of the prioction of hydrogen gas from magnesium and hydrochloric acid.
2Mg + 2HCl ⇒ H2 + 2MgCl
Then convert the mass of manesium into moles Mg (0.045 moles Mg)
Since the balanced equation promises us that we'll get 1 mole of H2 for every 2 moles of Mg, we can predict that the 0.045 moles of Mg will be enough to make (0.045 moles Mg)*(1 mole H2/2 moles Mg) = 0.0225 moles of H2.
At 22.4 l/mole at STP, this means the gas volume of H2 is (0.0225 moles)*(22.4L/mole) = 0.504 L of H2 at STP.
Since the lab is not at STP, the above volume must be adjected for actual lab conditions. Use the combined gas law:
P1V1/T1 = P2V2/T2
where P is pressure, V is volume, and T is temperature, in Kelven. (add 273.15 to C for Kelvin). The subscripts 1 and 2 represent starting (1) and final (2) conditions.
Stand pressure in kPa is 101.3 kPa.
We want V2, so rearrange the equation:
V2 = V1(T2/T1)(P1/P2)
Note that I've arranged the tempaerature and pressure values as ratios. It helps guide the process for cancelling units and understanding the impact of changes in these values.
See the worksheet for more details. V2 is calculated to be 0.542L (542ml) of H2 under the lab conditions.
Percent theorectical yield is the amount obtained divided by the amount expected:
(145ml)/(542ml) = 26.8% theorectical yield.
What is the molar mass for dinitrogen trioxide
Answer
The molar mass of N₂O₃ = 76.0104 g/mol
Step-by-step explanation:
Using the atomic masses of elements from the periodic table; (N = 14.0067, O = 15.999).
Therefore, the molar mass of dinitrogen trioxide is calculated below.
N₂O₃ = 2(N) + 3(O)
N₂O₃ = 2(14.0067) + 3(15.999)
N₂O₃ = 28.0134 + 47.997
N₂O₃ =76.0104 g/mol
The molar mass of N₂O₃ = 76.0104 g/mol
In the following equation, which species is the oxidized?SiO2(s) + 2C(s) → Si(s) + 2CO(g)
Answer
Carbon (C)
Procedure
The initial oxidation states of our balanced reaction are
Reduction is the gain of electrons or a reduction in the oxidation state of an atom, ion, or certain atoms in a molecule.
Oxidation is the loss of electrons or an increase in the oxidation state of an atom, ion, or certain atoms in a molecule.
Therefore we conclude that carbon is being oxidized.
this is for my final review please help also any advice is helpful
Answer:
[tex]Saturated[/tex]Explanation:
Here, we want to get the given definition
We have the solvent taking in as much solute as it can take
That is what we call a saturated solution
It simply means the amount of solute in the solvent is at the maximum
What mass of sulfur trioxide and what is the limiting reactant?
In this question, we have the following reaction:
2 SO2 + O2 -> 2 SO3, this reaction is already balanced
Considering molar ratio, we have:
2 SO2 = 1 O2
2 SO2 = 2 SO3
1 O2 = 2 SO3
Now, we need to find the limiting reactant, we will do it by checking the number of moles of both SO2 and O2 and compare it with the molar ratio
Let's start with SO2, molar ratio = 64.066g/mol
64.066g = 1 mol
35.0g = x moles
x = 0.546 moles of SO2 in 35 grams
According to the molar ratio, if we have 0.546 moles of SO2, we need half of it of O2, therefore:
0.546/2 = 0.273 moles of O2 is required
We need to check the number of moles of O2 to analyze if we have less or more moles than we actually need, O2 molar mass = 32g/mol
32g = 1 mol
35g = x moles
x = 1.094 moles of O2
If we have 1.094 moles and we need only 0.273 moles, this means that O2 is in excess and SO2 is the limiting reactant
Using the limiting reactant we can find the mass produced of SO3, according to the molar ratio, we will have the same number of moles from both SO2 and SO3, 0.546 moles
Now to find the mass, we use the number of moles, 0.546 and also the molar mass of SO3, 80.06g/mol
80.06g = 1 mol
x grams = 0.546 moles
x = 43.71 grams of SO3
Limiting reactant = SO2
Excess reactant = O2
SO3 formed = 43.71 grams
Calculate the molarity of a solution that contains 15.7 g of CaCO3 dissolved in enough water to make 275 mL of solution. (MW: CaCO3=100.09 g/mol
We can find molarity using the following equation:
In this problem, our solute is CaCO3, and we have 15.7 g of it. To express this amount in moles, what we do is to divide by the molar weight of CaCO3. (Always that you want to pass from grams to moles you do this, just to divide the amount that you have by the molar weight of the substance).
This is:
Now, we have 275mL of solution and this is 0.275L of solution. (To pass from mL to L we just divide by 1000).
Finally, replacing in the formula to find molarity, we have:
The answer is 0.57M.
Name the type of reaction below:
CuSO4*5H2O → CuSO4 + H2O
CuSO4 + 5H2O → CuSO4 + H2O In this reaction addition of water takes place therefore this is a hydration reaction.
What is hydration ?A chemical event called hydration occurs when two substances interact with water. Water is added to an unsaturated substrate in organic chemistry, which is often an alkene or an alkyne. The industrial production of ethanol, isopropanol, and butan-2-ol uses this sort of reaction.
Alkenes are often hydrated to produce alcohol, which is one of the most frequent hydration reactions.
While copper cannot conduct a displacement reaction with water, it may produce copper complexes through a redox/electrochemical reaction with water, oxygen.
Thus, this is hydration reaction.
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what compound is produced Be and Cl
Answer: Beryllium Chloride
A gas's volume decreases. Which of the following could most easily explain that?a. Its temperature increased.b. Its pressure increased.c. Its energy content increased.d. Its density decreased
This is an ideal gas problem, so let's see the relationships of volume with pressure and temperature:
- The relationship between volume and pressure is inversely proportional.
- The relationship between volume and temperature is directly proportional.
When the gas's volume decreases, the temperature would decrease too but the pressure would increases, so the answer would be B. Its pressure increased.
Help with this question, I’ve already got part a done I need part b and c
The number of moles of excess reagent left after the reaction is complete would be sodium phosphate and The mass of excess reagent that will remain unreacted is copper (II) nitrate.
The molar amounts of reactants and products that will result from a balanced chemical equation are shown. Rarely are reactants combined in the exact amount required in the actual world. Before the others, one reactant will be entirely depleted. The limiting reactant is the one that is consumed first in a reaction. The residual amount is deemed "in excess" once the other reactants have been partially consumed.
Calculate the volume of the product each reactant produced to identify the limiting reactant. The limiting reactant is the one that yields the smallest amount of product.
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If the freezing point of a soda is – 4.5 ºC and you leave it in your car overnight when the temperature dips to 25 ºF, will the soda freeze? (Pay close attention to the units!)
Explanation:
We leave a soda in the car overnight and the temperature dips to 25 °F. To see if it will freeze we have to convert the °F to °C.
T(°C) = ( T(°F) - 32 ) *5/9
T(°C) = (25 - 32) *5/9
T(°C) = -3.9 °C
Since -3.9 °C is a temperature greater than the freezing point (-4.5 °C) the soda won't freeze.
Answer: The soda won't freeze.
How many atoms does PbNO3 has?
Answer: 7 atoms
Explanation:
Answer:
5 atoms
Explanation:
Pb= 1 atom
N = 1 atom
O = 3 atoms
Thus, total no. of atoms are 5
I attached a picture of the questions I have. These are separate questions.
Electron configuration is defined as the description of where each electron is located, in terms of levels and sublevels around the nucleus. In this question, we have the following electron configuration:
1s2 2s2 2p6 3s2 3p6
This electron configuration has 8 electrons in its valence shell (the last number represents the shell number, in this case is 3) and according to the octet rule, this is a stabilized element, therefore it must be a Noble Gas
The period will be 3, since this is the valence shell
The group will be Noble gas, or group 18
Noble gas, usually, will not bond to other elements, since they are stabilized according to the octet rule
PLEASE HELP - 100 PTS AND BRAINLIEST
Indicate the number of protons, neutrons, and electrons in isolated ions having the following nuclear symbols:
a) 19F1- has ? protons, ? neutrons, and ? electrons.
b) 24Mg2+ has ? protons, ? neutrons, and ? electrons.
c) 56Fe3+ has ? protons, ? neutrons, and ? electrons.
The number of protons, neutrons, and electrons in isolated ions having the following nuclear symbols:
a) ¹⁹F⁻ has 9 protons , 9 neutrons , 10 electrons
b) ²⁴Mg²⁺ has 12 protons , 12 neutrons , 10 electrons
c) ⁵⁶Fe³⁺ has 26 protons , 26 neutrons , 23 electrons
Atomic number represent the no. of protons. number of protons is equal to number of electrons in neutral atom. neutrons is the difference between mass number and atomic number.
a) Atomic number of fluorine is 9. for neutral F atom has 9 protons , 9 neutrons , 9 electrons. In ¹⁹F⁻ , -1 represents one extra electron.
¹⁹F⁻ has 9 protons , 9 neutrons , 10 electrons
b) Atomic number of Magnesium is 12. In ²⁴Mg²⁺ , 2+ represents 2 electrons are removed.
²⁴Mg²⁺ has 12 protons , 12 neutrons , 10 electrons
c) Atomic number of iron is 26.
⁵⁶Fe³⁺ has 26 protons , 26 neutrons , 23 electrons
Thus, The number of protons, neutrons, and electrons in isolated ions having the following nuclear symbols:
a) ¹⁹F⁻ has 9 protons , 9 neutrons , 10 electrons
b) ²⁴Mg²⁺ has 12 protons , 12 neutrons , 10 electrons
c) ⁵⁶Fe³⁺ has 26 protons , 26 neutrons , 23 electrons
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The molar mass of NO2 is
46.01 g/mol.
What is the mass
of 3.45 moles NO2?
[ ? ] g NO₂
The mass of nitrogen dioxide present in 3.45 moles is equal to 158.73 g.
What is a mole?A mole can be defined as a scientific unit that is used to determine the huge number of quantities of molecules, atoms, ions, etc. The mass of the 1 mole of an element is called atomic mass and the mass of one mole of any compound is called molar mass.
The number of particles in 1 mole was found to be equal to 6.023 × 10 ²³ per mole which is known as Avogadro’s constant.
Given, the number of moles of nitrogen dioxide = 3.45 mol
The molar mass of NO₂ = 46.01 g/mol
It means that 1 mole of NO₂ has mass = 46.01 g
Then 3.45 moles of NO₂ will have mass = 3.45 × 46.01 = 158.73 g
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What formula for a molecule formed from P and Cl would be? PCl 5 PCl 2 P 3Cl PCl PCl 3
The question requires us to identify the molecular formula of a molecule formed between phosphorus (P) and chlorine (Cl).
The first step to solve this question is write the electronic configuration of both atoms involved (P and Cl) and, from the number of valence electrons, identify how many bonds each one should make.
P has atomic number 15, thus its electronic configuration is: 1s2 2s2 2p6 3s2 3p3
Cl has atomic number 17, thus its electronic configuration is: 1s2 2s2 2p6 3s2 3p5
Note that P has 5 valence electrons (3s2 and 3p3) while Cl has 7 valence electrons (3s2 3p5).
For P, we should expect 3 bonds to other atoms in order to reach the octet, while for Cl, we should expect 1 bond to another atom to achieve the octet.
With that in mind, we can say that each Cl will bond to one P, and we need 3 Cl. Therefore, the molecular formular is PCl3 (the last option).I
Find the pH of the following solutions and tell if they are acidic, basic or neutral. [OH-] = 1.0 x 10-2M[OH-] = 1.0 x 10-11M[OH-] = 3.5 x 10-2M[OH-] = 4.4 x 10-11
In this question, we have to find the pH of 4 solutions with the given OH- concentration, and in order to do that, we have to find the pOH first, and then we can find the pH, the formula for pOH is the same as pH:
pOH = -log [OH-]
Solution 1:
pOH = -log [1.0*10^-2]
pOH = 2
pH + pOH = 14
pH = 14 - 2
pH = 12, this is a BASIC solution
Solution 2:
pOH = -log [1.0*10^-11]
pOH = 11
pH + pOH = 14
pH = 14 - 11
pH = 3, this is an ACIDIC solution
Solution 3:
pOH = -log [3.5*10^-2]
pOH = 1.45
pH + pOH = 14
pH = 14 - 1.45
pH = 12.55, this is a BASIC solution
Solution 4:
pOH = -log [4.4*10^-11]
pOH = 10.36
pH + pOH = 14
pH = 14 - 10.36
pH = 3.64, this is an ACIDIC solution
What will be the final temperature of a 496−g sample of water, initially at 17.0°C, after 74.2 kJ have been added to it?
The final temperature of a 496−g sample of water, initially at 17.0°C, after 74.2 kJ have been added to it is 52.61°C.
Given,
Mass of sample water, m = 496g
Initial temperature of the water, t1 = 17°C
Heat added to the water, Q = 74.2 kj = 74200 kj
The quantity of the heat which is added in water to cause a change in the state of the sample water can be given as
Q = mc∆t
where
c is given as specific heat capacity of water = 4200J/kg°C
∆t = change in temperature of the water
The change in temperature of the water after adding heat is given as
∆t = Q/ mc
By substituting all the values, we get
= 74200/ 0.496 × 4200
= 35.61°C
Thus, from the calculated data we get the value of final temperature
change in temperature = Final temperature - initial temperature
Final temperature = 35.61 + 17 = 52.61°C
Thus, we concluded that the final temperature of a 496−g sample of water, initially at 17.0°C, after 74.2 kJ have been added to it is 52.61°C.
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The temperature of a liquid is gradually decreased. What is happening to the viscosity at the same time?
The viscosity of the liquid will be increasing.
ExplanationThe bond that holds the particles of liquid together is weak compared to solid.
The application of heat to a substance gradually causes a decrease in its viscosity because the molecules of the liquid substance get excited when the liquid is heated up.
When the temperature of the liquid is gradually decreased, the energy that causes the molecules to move will no longer be enough to overcome the forces that bind the molecules together causing the liquid to become thicker and increasing the viscosity of the liquid.
Therefore we can conclude that when the temperature of a liquid is gradually decreased, the viscosity of the liquid will be increasing.
What is the pH for the following concentration: [H3O+] = 3.24 x 10-3 M
To determine the pH we can apply the equation for the pH of a solution:
pH = -log [H3O+]
Where [H3O+] is the molar concentration of the acid, so now we can apply the equation and do the respective operation:
[tex]\begin{gathered} pH=\text{ -log }\mleft[H_3O+\mright] \\ pH=\text{ -log }\lbrack3.24\times10^{-3}\rbrack \\ pH\text{ = - (-2.49)} \\ pH\text{ = 2.49} \end{gathered}[/tex]What is the molarity of “Cl” in each solution? -0.200 M of NaCl-0.190 M of SrCl2-0.110 M of AlCl3
a) The molarity of Cl⁻ in 0.200 M of NaCl is 0.200 M.
a) The molarity of Cl⁻ in 0.190 M of SrCl₂ is 0.380 M.
c) The molarity of Cl⁻ in 0.110 M of AlCl₃ is 0.330 M.
a) 0.200 M of NaCl
The chemical reaction,
NaCl(aq) → Na⁺(aq) + Cl¯(aq)
From the above-balanced equation,
1 mole of Cl was created from 1 mole of NaCl
Therefore,
0.200 M NaCl will produce 0.200 M of Cl⁻
b) 0.190 M of SrCl₂
The chemical reaction:
SrCl₂(aq) → Sr²⁺ (aq) + 2Cl¯ (aq)
From the above-balanced equation,
2 moles of Cl were created from 1 mole of SrCl2.
Hence,
0.190 M of SrCl₂ will produce = 0.190 × 2 = 0.380 M of Cl⁻
c) 0.110 M of AlCl₃
The chemical reaction:
AlCl₃(aq) → Al³⁺ (aq) + 3Cl¯ (aq)
From the above-balanced equation,
3 moles of Cl were created from 1 mole of AlCl₃
Hence,
The molarity of Cl⁻ in 0.110 M of AlCl₃ is:
= 0.110 × 3 = 0.330 M
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In the equation: I2 + 5Cl2 + 6 H2O —>2HIO3 + 10HCL A. Has iodine been oxidized or has it been reduced B. Has chlorine been oxidized or has it been reduced
Answer
A - Iodine is being oxidized
B - Cl2 is being reduced
Explanation
[tex]I_{2(s)}^0\text{ + 5Cl}_{2(g)}^0\text{ + 6H}_2O_{(l)}\rightarrow2HI^VO_{3(aq)}\text{ + HCl}_{(aq)}^{-I}[/tex]Which of the following is/aresoluble in water?Alcohols with threecarbon atomsAlcohols with less thanthree carbon atomsAlcohols with six carbonatomsabсd Both A and B
It is known that the three first alcohols are soluble in water, those are methanol, ethanol and propanol. It means that alcohols with less than 3 carbon atoms (methanol, ethanol) and with 3 carbon atoms (propanol) are soluble in water.
Therefore, the correct answer is Both A and B. The correct choice is D.
17.Which of the following is the correct formula for the compound formed from the elements beryllium and oxygen?Select one:a. BeOb. Be2O2c. BeO3d. Be4O8
Answer
a. BeO
Explanation
The ionic compound formed from the elements beryllium and oxygen is beryllium oxide. The beryllium ion has a charge of +2 and has the symbol
Be²⁺. The oxide ion has a charge of -2 and has the symbol O²⁻.
Therefore, the correct formula for the compound from the elements beryllium and oxygen will be BeO
Please solve this!! I won't be able totalk since I'm in school but just end it ifim not there and I'll give you a 5 starswhen I come back to look at it.
The first step to solve this question is to balance the given equation. To do it, make sure that the amount of every element is equal in both, reactants and products.
[tex]Mg_3N_2+3K_2O\rightarrow3MgO+2K_3N[/tex]Now, use the stoichiometric ratio between the coefficients of potassium oxide and potassium nitride:
[tex]14molK_2O\cdot\frac{1molMg_3N_2}{3molK_2O}=4.66molMg_3N_2[/tex]The answer is 4.66moles of magnessium nitride.
For the reaction C2H6 + O2 + CO2 + H20, match the proper coefficient to thechemical substance it goes with for a balanced reaction.a7?C2H66?024.?CO22?H20
Step 1
The conservation of matter or mass is applied here. The same atoms must appear on both sides of the reaction.
The same number of atoms must appear on both sides of the reaction too.
---------------
Step 2
The reaction:
2 C2H6 + 7 O2 => 4 CO2 + 6 H2O (this is a combustion reaction)
The numbers next to the molecules are coefficients.
According to the question, the answer is:
2 C2H6
7 O2
4 CO2
6 H2O
Hello I am stuck in this problem May you help me? Thank you!
Group 17 is located on the right side of the periodic table. The atomic radius increases from right to left. It means that group 17 elements have a small atomic radius. Also, they have only one electron in the valence shell, their ionization energy is low, and it is easy to lose that electron. This fact explains its high reactivity.
Answer: Nonmetals have a small atomic radius and can lose electrons easily.
How many moles of Cl2 are needed to to produce 250.g of PCl5 ?
The number of moles of [tex]Cl_2[/tex] required to produce 250 grams of [tex]PCl_5[/tex] would be 3 moles.
Stoichiometric problemPhosphorus and chlorine react to form phosphorus pentachloride according to the following balanced equation:
[tex]2P + 5Cl_2 -- > 2PCl_5[/tex]
From the equation of the reaction, the mole ratio of chlorine and phosphorus pentachloride is 5:2. Thus, 5 moles of chlorine will produce 2 moles of phosphorus pentachloride.
Recall that: mole = mass/molar mass
The molar mass of [tex]PCl_5[/tex] is 208.24 g/mol
Thus, 250 g of [tex]PCl_5[/tex] would be equivalent to:
mole = 250/208.24
= 1.20 mol
2 mol [tex]PCl_5[/tex] = 5 moles [tex]Cl_2[/tex]
1.20 mol = 5 x 1.2/2
= 3 moles
In other words, 250 g [tex]PCl_5[/tex] will require 3 moles of [tex]Cl_2[/tex].
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The equation for the synthesis of ammonia is N2 + 3 H2 -> 2 NH3. How many moles of H2 I needed to produce 6 mol of NH3? A. 4 B. 6 C. 8 D. 9
The equation for the synthesis of ammonia is:
N₂ + 3 H₂ ---> 2 NH₃
We have to find the number of moles of H₂ needed to produce 6 mol of NH₃. To do that we will use the equation that we were given.
We can read the equation of the reaction as a recipe. When 1 mol of N₂ reacts with 3 moles of H₂, 2 moles of NH₃ are produced. So the relationship between H₂ and NH₃ is that 3 moles of H₂ are needed to produce 2 moles of NH₃. We wiill use that relationship to solve the problem.
6 moles of NH₃ * 3 moles of H₂/(2 moles of NH₃) = 9 moles of H₂
Answer: D) 9 moles of H₂ are needed.
If 20 grams of butane, C4H10, is burned in a combustion reaction, how many grams of carbon dioxide could you get?
Step 1 - Balancing the combustion equation
The combustion of an alkane always gives, as products, H2O and CO2. Remembering that combustion always involves a reaction with O2, we can write the chemical equation for the combustion of C4H10 as:
[tex]C_4H_{10(g)}+\frac{13}{2}O_{2(g)}\rightleftarrows4CO_{2(g)}+5H_2O[/tex]Step 2 - Discover how many grams of carbon dioxide can be produced
Looking at the equation above, we can see that 1 mole of C4H10 produces 4 moles of CO2. This is a fixed proportion. We can convert this proportion in moles to a proportion in mass by multiplying each number of moles by the respective molar mass (C4H10 58g/mol; CO2 44g/mol)of the substances:
[tex]\begin{gathered} mC_4H_{10}=1\times58=58\text{ g} \\ \\ mCO_2=4\times44=176\text{ g} \end{gathered}[/tex]We discovered thus that each 58 g of C4H10 produce 176g of CO2. Since this is a fixed proportion in mass, we can use it to discover how many grams of CO2 would be formed by the combustion of 20g of butane (C4H10):
[tex]\begin{gathered} 58\text{ g of C4H10------ 176 g of CO2} \\ 20\text{ g of C4H10 ----- x} \\ \\ x=\frac{176\times20}{58}=60.7\text{ g of CO2} \end{gathered}[/tex]The combustion of 20 g of C4H10 would produce thus 60.7 g of CO2.
For each ionic compound below determine the formula and the cation anion ( metal:nonmetal) ratio.Ionic compound 1.
The first shown ionic compound has only two elements, Li and F.
On a periodica table, we can see that Li is on the first group, so it is the metal one.
F is on the 17th group, so it is the nonmetal.
We have only one of each of them, so the formula will only have one of each.
The formula is:
[tex]LiF[/tex]And we have 1 of each, so their ratio is 1:1.