Hello there. To solve this question, we have to remember some properties about logarithms.
Given the logarithmic equation:
[tex]\log(x)=-5[/tex]We want to determine the value of x.
For this, remember the following rule:
[tex]\text{ For }a,\,b\in\mathbb{R}^+\text{ and }b\cancel{=}1,\text{ }\log_b(a)=c\Rightarrow a=b^c[/tex]Such that, in this case, the logarithm has base 10, therefore
[tex]x=10^{-5}[/tex]This power of 10 can be easily found :
[tex]x=0.00001[/tex]It has 5 digits after the decimal place, being the fifth digit a 1.
This is the answer contained in the option B.
Use the data set to determine which statements are correct. Check all that apply. 35, 41, 18, 75, 36, 21, 62, 29, 154, 70 The median is 36.The median is 38.5.There is an outlier.The lower quartile is 29. The lower quartile is 18. The upper quartile is 29.The upper quartile is 70. The interquartile range is 41.
Q1 = 35.75
Q2 = 40
Q3= 45.5
IQR = 9.75
Lower Outlier =15
Upper Outlier=55
1) Let's calculate the quartiles, by using a formula for that and considering that the Distributions is:
2) But we need to orderly write this distribution, so:
15 29 29 35 35 36 36 37 38 40 40 42 44 45 45 47 51 52 52 55
The first Quartile is given by the formula, below where n is the number of observations in this case, since we have a decimal let's find the average between the 5th and the 6th number:
[tex]\begin{gathered} Q_1=\frac{1}{4}(n+1)^{th} \\ Q_1=\frac{1}{4}(20+1)^{th} \\ Q_1=\frac{1}{4}(21)^{th} \\ Q_1=5.25 \\ Q_{,1}=\frac{35+36}{2}=35.75 \end{gathered}[/tex]Then The upper Quartile:
[tex]\begin{gathered} Q_3=\frac{3}{4}(n+1)^{th} \\ Q_3=\frac{3}{4}(21)^{th} \\ Q_3=\text{ 15.75 position} \\ Q_3=\frac{45+47}{2}=45.5 \end{gathered}[/tex]3) And the Second Quartile is going to be the median
[tex]Q_2=\text{ Median =}\frac{40+40}{2}=40[/tex]The interquartile range is going to be the difference, between the first quartile and the third one
IQR = 45.5 -35.75 =9. 75
The outliers in the distribution
15 29 29 35 35 36 36 37 38 40 40 42 44 45 45 47 51 52 52 55
They can be found by a formula:
[tex]\begin{gathered} Lower\colon Q_1-(1.5\text{ }\times IQR) \\ \text{Lower: 35.75-(1.5}\times9.75) \\ L=35.75-(14.625) \\ L=21.125\approx21 \\ \\ \text{Upper: Q}_3+(1.5\times IQR) \\ \text{Upper: }45.5+(1.5\times9.75) \\ \text{Upper: }60.125\approx60 \end{gathered}[/tex]The lower outlier is below 21.125, and the upper one 60.125 so in our distribution, Lowe Outlier is 15, and the Upper one, is closer to 60.125 in this case, 55.
The answers are:
Q1 = 35.75
Q2 = 40
Q3= 45.5
IQR = 9.75
If the cost of a loaf of bread is now $2.75 and is increasing at 5% per year, what will it cost 10 years from now. Write an exponential equation for this scenario then use it to solve the problem
To estimate the cost (C) after t years with an increasing rate r, use the formula below:
[tex]C(t)=C_0*\left(1+r\right)^t[/tex]
In this question:
C0 = initial cost = $2.75
r = rate = 0.05
t = time = 10 years
Substituting the values in the equation:
[tex]\begin{gathered} C(10)=2.75*\left(1+0.05\right)^{10} \\ C(10)=2.75*1.05^{10} \\ C(10)=2.75*1.629 \\ C(10)=4.48 \end{gathered}[/tex]Answer:
Equation:
[tex]\begin{gathered} C(t)=2.75(1+0.05)^t \\ C(10)=2.75(1+0.05)^{10} \end{gathered}[/tex]Cost: C(10) = $4.48.
Find the x-and y-intercepts of the graph of x - 2y = 32. State each answer as an integer or an improper fraction in simplest form.
The x- intercepts of the function is (32,0) and y- intercepts of the function is (0, -16).
Given,
In the question:
The equation is :
x - 2y = 32
To find the x-and y-intercepts of the graph.
Now, According to the question;
Equation is :
x - 2y = 32
Find x - intercepts
Isolate the dependent variable:
y = x/2 - 16
Find the x - intercept of the function
x = 32
Equation is :
x - 2y = 32
Find y - intercepts
Isolate the dependent variable:
y = x/2 - 16
Find the y - intercept of the function
y = -16
Hence, The x- intercepts of the function is (32,0) and y- intercepts of the function is (0, -16).
Learn more about x and y intercepts at:
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How many solutions does this equation have? Solve on paper and enter your answer on Zearn.
1/5(25+15x) = 3x+5
No solutions
One solution
Infinitely many solutions
Answer: Infinity many solutions
Step-by-step explanation:
1/5(25+15x) = 3x+5 (Multiply 1/5 with the parentheses)
5+3x=3x+5
^ Both sides are the same, meaning that any number can be plugged into x.
We can also simplify it by subtracting 3x and 5 from both sides:
5+3x=3x+5
3x-3x=5-5
0=0
The point enter your response here is also on the graph of the equation.
An equation that has a graph that is symmetric to the origin, has a reflection of each point through the origin, reflects across the x-axis and y-axis.
Therefore, if one point of the graph is (-4,1).
Reflected to both axis, we can find that another is is (-x,-y) = (-(-4), -1) = (4, -1)
So, the answer is the point (4, -1)
Someone explain I know the answer Reflect the figure at the right across the y-axis. Then rotate theimage 180° around the origin. Draw the image after eachtransformation. What single transformation could you performon the figure to get the same final image?
The single transformation one could per form on the figure to get the final image is a rotation of 270 degrees counterclockwise around the origin.
The original figure cordinates (x,y)
A Reflection of the figure at the right across the y-axis, gives a coordinate(-x, y)
The y axis will remain the same. While the x axis will change sign.
A rotation of 180 degrees around the origin around the origin will have the coordinates (-x, -y)
The x and y axis changes signs.
When we carry out both transformation, the coordinates we get represent a transformation of 270 degrees counterclockwise around the ori
y varies directly as z and inversely as x; write the sentence as an equation
Given:
(y) varies directly as (z) and inversely as (x):
[tex]\begin{gathered} y\propto z;y\propto\frac{1}{x} \\ \\ so,y\propto\frac{z}{x} \end{gathered}[/tex]so, the equation will be:
[tex]y=\frac{kz}{x}[/tex]Where: k is the proportionality constant
Barney and Robin went shopping at H&M. The store was having a sale on all shirts and pants. Barney spent $70 on 3 shirts and 2 pairs of pants and Robin bought 1 shirt and 4 pairs of pants for $90. d) Use a graphing calculator, to graph your equations in parts a and b. What is the coordinate point where these two lines intersect? How does this compare to your response in part c?
Barney spent $70 on 3 shirts and 2 pairs of pants
Robin bought 1 shirt and 4 pairs of pants for $90
Let x be the cost for each shirt
Let y be the cost for each pair of pants
3x+2y=70 (1)
x+4y=90 (2)
Having this system of equations, we can graph on the graph calculator:
The solution of two linear equations corresponds to the intersection of the two lines because the coordinate pair naming every point on a graph is a solution to its corresponding equation:
In this case the solution is: (10, 20) and corresponds to the cost of the shirt and pant.
Shirt: $10
Pant:$20
Consider the first few terms as well as the last few terms of the sum. Find a way to simplify and use your observation to evaluate the sum. Write the exact answer. Do not round.
The first three terms of the sum are:
[tex]\begin{gathered} \frac{1}{3}-\frac{1}{3+1}=\frac{1}{3}-\frac{1}{4}\to\text{first} \\ \frac{1}{4}-\frac{1}{4+1}=\frac{1}{4}-\frac{1}{5}\to\text{second} \\ \frac{1}{5}-\frac{1}{6}\to\text{ third} \end{gathered}[/tex]On the other hand, the three last terms of the sum are
[tex]\begin{gathered} \frac{1}{10}-\frac{1}{10+1}=\frac{1}{10}-\frac{1}{11}\to\text{tenth} \\ \frac{1}{11}-\frac{1}{12}\to\text{ eleventh} \\ \frac{1}{12}-\frac{1}{13}\to\text{twelfth} \end{gathered}[/tex]Notice that there is a -1/4 in the first term, a 1/4 in the second term, a 1/5 in the second term, and 1/5 in the third term, and so on. Once we add those factors, the result will be zero. Thus, the result of the sum is equal to the first number in the first term minus the second number in the twelfth term.
[tex]\begin{gathered} \sum ^{12}_{i=3}(\frac{1}{i}-\frac{1}{i+1})=\frac{1}{3}-\frac{1}{13}=\frac{13-3}{39}=\frac{10}{39} \\ \Rightarrow\sum ^{12}_{i=3}(\frac{1}{i}-\frac{1}{i+1})=\frac{10}{39} \end{gathered}[/tex]The answer is 10/39
can you help me on this one?I need to determine whether the figure is a parallelogram using the distance formula.
If we graph the given points, we have:
One property of the parallelograms is that their opposite sides are equal.
Then, we have to verify if the segments QT and RS are equal.
[tex]QT=RS[/tex]To find the measure of segments QT and RS, we can use the distance formula.
[tex]\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}\Rightarrow\text{ Distance formula} \\ \text{ Where} \\ (x_1,y_1)\text{ and }(x_2,y_2)\text{ are the coordinates of the points} \end{gathered}[/tex]• Measure of segment QT
[tex]\begin{gathered} (x_1,y_1)=Q(-10,-2) \\ (x_2,y_2)=T(-11,-8) \\ d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt[]{(-11-(-10))^2+(-8-(-2))^2} \\ d=\sqrt[]{(-11+10)^2+(-8+2)^2} \\ d=\sqrt[]{(-1)^2+(-6)^2}\rbrack \\ d=\sqrt[]{1+36} \\ d=\sqrt[]{37} \\ d\approx6.08\Rightarrow\text{ The symbol }\approx\text{ is read 'approximately'} \end{gathered}[/tex]• Measure of segment RS
[tex]\begin{gathered} (x_1,y_1)=R(1,-1) \\ (x_2,y_2)=S(1,-7) \\ d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt[]{(1-1)^2+(-7-(-1))^2} \\ d=\sqrt[]{(0)^2+(-7+1)^2} \\ d=\sqrt[]{0+(-6)^2} \\ d=\sqrt[]{(-6)^2} \\ d=\sqrt[]{36} \\ d=6 \end{gathered}[/tex]As we can see, the segments QT and RS are different.
[tex]\begin{gathered} QT\ne RS \\ 6.08\ne6 \end{gathered}[/tex]Then, the figure does not satisfy the mentioned property of parallelograms.
Therefore, the figure is not a parallelogram.
ABOUT HOW MANY NO RESPONCES COULD YOU EXPECT FROM A POPULATION OF 500 WITH 15 OUT OF 60 YES RESPONSES FROM A SAMPLE. A. 15B. 45C. 125D.375 NOT A TEST.
Total population = 500
15 out of 60 gives a YES response
This implies
Probability of getting a YES response is
[tex]\frac{15}{60}[/tex]Out of the 500 population
The number of YES responses will be
[tex]500\times\frac{15}{60}[/tex]Simplifying this gives
[tex]\begin{gathered} 500\times\frac{15}{60} \\ =500\times\frac{1}{4} \\ =125 \end{gathered}[/tex]Hence out of 500 population 125 responses will be YES
Therefore, the number of NO responses is
[tex]500-125=375[/tex]Therefore, the number of NO responses is 375
Question 2: Construct a perpendicular to
AB at A and at B (Hint: Extend AB)
Answer:
Explanation:
Here, we want to construct a perpendicular line at the points
The steps are as follows:
a) We extend the line through A and B
b) Place the compass at Point A, and draw a small semi-circle. Now, divide this semi-circle into 2. The line drawn will be perpendicular to AB and it will pass through A
c) Repeat the same process for B
We have the sketch as follows:
need help with question 4
need answer in cubic feet
Answer: 140cubic feet
Step-by-step explanation:
14Cubic feet x 10cubic feet is 140cubic
What is money? 1. A store of value2. A medium of exchange3. A measure of valuea. Money simplifies the exchange process because it’s a means of indicating how much something costs.b. To use money to buy the goods and services you want.c. People are willing to hold onto it because they’re confident that it will keep its value over time.it is math even if it doesnt look like it
Given data:
Money can be defined a medium of exchange.
Thus, money is juat a medium of echnage.
Select the correct answer.A local magazine, available by subscription and at newsstands, mailed a comment card to each of its subscribers. It asked the readers how satisfied they were with the magazine's coverage of local events and interests. Based on the information received from the comment cards, the magazine created a television ad saying that 97% of its readers were extremely satisfied with the content of the magazine.Why might this sample be biased?A. The magazine changed its content for the issue including the comment card.B. Very few comment cards were returned.C. The survey only considered subscribers, and not those who purchase the magazine at newsstands.D. Not enough comment cards were distributed.
Hello there. To solve this question, we'll analyze each of the options and determine why it is the case for this sample to be biased.
We know that this local maganize is available by subscription and at newsstands and they asked the readers by mailing them comment cards for the subscribers.
A. The magazine changed its content for the issue including the comment card.
Since the question didn't mention this fact, we cannot assume this to be a correct option, we only know they sent comment card to the readers.
B. Very few comment cards were returned
The question says that 97% of the readers were extremely satisfied with the content of the magazine. But we know that these readers that received a comment card were subscribers.
This means that, considering each subscriber sent its comment card back, 3% of them were not satisfied, but we don't know how many subscribers this magazine has.
Hence this answer is not correct as well.
C. The survey only considered subscribers, and not those who purchase the magazine at newsstands.
This might be the answer, considering that the comment card were only mailed to the subscribers and, since we don't know the proportion between subscribers and those who buy at the newsstands, this sample is biased.
D. Not enough comment cards were distributed.
The question said that the magazine mailed a comment card for each of its subscribers, so we cannot take this option into consideration.
To solve the rational equation2. 3-x+65X+25how can the expressionX+2be rewritten usingthe least common denominator?
The expression given is:
[tex]\frac{2}{x}+\frac{3-x}{6}[/tex]The Least Common Denominator (L.C.D) of the expression is the product of the denominator:
[tex]6\times x=6x[/tex]Since
[tex]\frac{2}{x}+\frac{3-x}{6}=\frac{5}{x+2}[/tex]Then, we can multiply both the numerator and denominator with the L.C.D of 6x:
[tex]\begin{gathered} \frac{5}{x+2} \\ \\ \frac{5}{x+2}\times\frac{6x}{6x} \\ \\ \frac{30x}{6x(x+2)} \end{gathered}[/tex]Therefore, the final answer is: Option B
What are the coordinate points of I if it is halfway between points F (2, 3)and X (10,9) on FX?
ANSWER
EXPLANATION
If point I is halfway between points F and X on the line FX, then point I is the midpoint of this line. Its coordinates are given by half the distance in each direction - the x and y-directions, betwen points F and X,
2. 2. How many rectangles similar to this one 1 Is possible from the figure below? Ans = A.) 24 B) 25 C) 20
Similar triangles are triangles with corresponding angles and corresponding sides. They don't necessarily mean triangles of the same size(congruent).
From the diagram attached
Lucy earns $326.87 each week. The federal government withholds 18% ofthat for federal income tax. How much is withheld from her pay annuallyfor federal income tax?a. $58.84b. $2,967.05c. $13,937.74d. $3,059.50
ANSWER:
d. $3,059.50
STEP-BY-STEP EXPLANATION:
The first thing is to calculate the annual salary, knowing that a year has a total of 52 weeks, therefore:
[tex]\begin{gathered} a=326.87\cdot52 \\ a=16997.24 \end{gathered}[/tex]The annual price is $ 16,997.24, we calculate 18% of this value, as follows:
[tex]\begin{gathered} tax=16,997.24\cdot\frac{18}{100} \\ tax=3059.50 \end{gathered}[/tex]Which means that federal income tax is $ 3,059.50
2xy^2-x^2Evaluate where x=2 and y=5is that first step correct and what would be the order of operations from there
To evaluate this , replace the terms with the numbers as
2 xy^2 - x^2
[tex]2xy^2-x^2[/tex][tex]2\cdot2\cdot5^2-2^2[/tex][tex]4\cdot5^2-4[/tex][tex]4\cdot25\text{ - 4}[/tex][tex]100-4=96[/tex]Points L,M and N are collinear.M is between L and N. You are given LM=13 and LN=20.Find the length of MN
ANSWER
MN = 7
EXPLANATION
Let's draw a diagram first:
Since all the points are collinear we can use the segment addition postulate:
[tex]LM+MN=LN[/tex]Replacing with the values we know:
[tex]13+MN=20[/tex]And solving for MN:
[tex]MN=20-13=7[/tex]We have that the length of segment MN is 7.
This picture is the paragraph of information to answer the questions. The second picture is the questions
Question 1
a) It could not represent the scenario because the vertex of the parabola is located at (-5,9), and x=-5 is a region beyond the bank.
b) This function does not fit the scenario because the parabola opens up, as if the fish fell towards the sky.
c) This function does not fit the scenario because the expression is negative for all values of x, which means that the fish always remains under water.
Question 2
The x-value at the center of the boat is 5.
Question 3
The fish jumps 4 feet high.
Question 4
The zeros of the function are x=3 and x=7 and they represent the locations over the x-axis where the fish comes out of the water and re-enters the river.
Question 5
The fish comes out of the water 2 feet away from the center of the boat.
Question 6
The domain is: 0≤x≤50.
The range is: -2021≤y≤4.
Question 7
a) The path of the fish is increasing at the interval [0,5).
b) The path of the fish is decreasing at the interval (5,50]
Question 8
a) The fish swims under water at the intervals [0,3) and (7,50].
b) The fish swims abov the water at the interval (3,7).
Explanation:Question 1:
Write the functions in vertex form.
a)
[tex]\begin{gathered} F\left(x\right)=-x^2-10x-16 \\ =-\left(x+5\right)^2+9 \end{gathered}[/tex]The vertex is located at (-5,9), but the bank is the line x=0 and the region x<0 corresponds to land. The fish cannot swim on the land, so it would be impossible for the fish to reach that point. Additionally, the function is negative for all positive values of x, so in the region that corresponds to the river, the fish never comes out of the water.
b)
[tex]F\left(x\right)=x^2-6x+13[/tex]Since the coefficient of the quadratic term is positive, the parabola opens up. Then, this trajectory corresponds to an object that "falls upwards", which is not possible.
c)
[tex]\begin{gathered} F\left(x\right)=-x^2+6x-13 \\ =-\left(x-3\right)^2-4 \end{gathered}[/tex]Notice that the function is negative for all values of x, which can be interpreted as if the fish never came out of the water, which does not correspond to the described situation.
Question 2:
Write the expression that describes the trajectory of the fish in vertex form. The x-coordinate of the vertex corresponds to the center of the boat.
[tex]\begin{gathered} F\left(x\right)=-x^2+10x-21 \\ =-\left(x-5\right)^2+4 \end{gathered}[/tex]The vertex of the parabola is (5,4), so the center of the boat is located at x=5.
Question 3:
The maximum height of the fish corresponds to the y-coordinate of the vertex. So, the fish's maximum height is y=4 (4 feet).
Question 4:
Set F(x)=0 and solve for x:
[tex]\begin{gathered} F\left(x\right)=0 \\ \Rightarrow-\left(x-5\right)^2+4=0 \\ \Rightarrow4=\left(x-5\right)^2 \\ \Rightarrow\left(x-5\right)^2=4 \\ \Rightarrow x-5=±\sqrt{4} \\ \Rightarrow x-5=±2 \\ \Rightarrow x=5±2 \\ \therefore x_1=3,x_2=7 \\ \end{gathered}[/tex]Then, the zeros of the function are x=3 and x=7, they represent the horizontal location at which the fish is located at the surface of the river, so they are the points where the fish comes out of the water and re-enters the water.
Question 5:
The points x=3 and x=7 are both 2 units away from x=5. Then, the fih comes out of the water and re-enters the water 2 feet away from the center of the boat.
Question 6:
a)
The domain corresponds to all the values of x that the function can take. Since the river is 50 feet wide and the bank is the y-axis, then, the river covers the region 0≤x≤50, which is the same as the domain.
b)
The range corresponds to all the values over the y-axis that the function can take when evaluated at values from the domain.
To find the range, we have to find the maximum and minimum values of F(x) for 0≤x≤50. Since the maximum value of the function is 4 (the maximum height), just check for the values of F(0) and F(50) to find the possibilities for the minimum:
[tex]\begin{gathered} F\left(0\right)=-\left(0-5\right)^2+4 \\ =-25+4 \\ =-21 \end{gathered}[/tex][tex]\begin{gathered} F\left(50\right)=-\left(50-5\right)^2+4 \\ =-\left(45\right)^2+4 \\ =-2025+4 \\ =-2021 \end{gathered}[/tex]Then, the minimum value of the function F for the values in the domain is -2021. Therefore, the range is: -2021≤y≤4.
Question 7:
The path of the fish increases until it reaches it maximum point at x=5, then it decreases. Then:
a) The path of the fish increases at 0≤x<5.
b) The path of the fish decreases as 5.
Question 8:
The fish is initially under water, it comes out at the first zero of the function x=3, it travels through the air until it re-enters the water at x=7 and it continues under water from that point on. Then:
a) The fish is under water in the interval 0≤x<3 and 7.
b) The fish is above the water in the interval 3.
Help me out with details
Answer:
The numbers are proportional with each other. If you were to divide the length on the table by the corresponding width, you'd get the same answer each time(0.6)
[tex]2x {}^{2} + 2x - 4 = 0[/tex]Find zeros/roots by completing the sqaures
Answer:
x = 1 and -2
Explanation
Given the expression
2x^2 + 2x - 4 = 0
We are to find the zero of the equation using the completing the square method
Step 1: Divide through by 2
2x^2/2 + 2x/2 - 4/2 = 0/2
x^2 + x - 2 = 0
Step 2: Add 2 to both sides of the equation
x^2 + x - 2 + 2 = 0+2
x^2 + x = 2
Step 3: Complete the square by adding the square of half of coefficient of x to both sides as shown
Coefficient of x is 1
Half of 1 = 1/2
Square of 1/2 = (1/2)^2 = 1/4
Add 1/4 to both sides
x^2 + x + (1/2)^2= 2 + 1/4
(x+1/2)^2 = 9/4
Sqare root both sides
x + 1/2 = \sqrt[9/4]
x + 1/2 = 3/2
x = 3/2 - 1/2 and -3/2 - 1/2
x = 2/2 and -4/2
x = 1 and -2
Write the equation of the line that passes through the points (-2,-2) and (8,0)
Considering the expression of a line, the equation of the line that passes through the points (-2,-2) and (8,0) is y= -1/5x + 8/5.
Linear equationA linear equation o line can be expressed in the form y = mx + b
where
x and y are coordinates of a point.m is the slope.b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.Knowing two points (x₁, y₁) and (x₂, y₂) of a line, the slope m of said line can be calculated using the following expression:
m= (y₂ - y₁)÷ (x₂ -x₁)
Substituting the value of the slope m and the value of one of the points in the expression of a linear equation, the value of the "b" can be obtained.
Equation of the line in this case
Being (x₁, y₁)= (-2, 2) and (x₂, y₂)= (8, 0), the slope m can be calculated as:
m= (0 - 2)÷ (8 -(-2))
m= (0 - 2)÷ (8 +2)
m= (-2)÷ (10)
m= -1/5
Considering point 1 and the slope m, you obtain:
2= (-1/5)×(-2) + b
2= 2/5 +b
2 -2/5= b
8/5= b
Finally, the equation of the line is y= -1/5x + 8/5.
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It is known that the events ANB are mutually exclusive that p(a)=0.60 and p(b)=0.16
The probability of two mutually exclusive events to happen simultaniously can be described as below:
[tex]P(A\text{ and }B)=P(A)\cdot P(B)[/tex]We can replace the terms above with the probabilities to determine the answer for this problem.
[tex]P(A\text{ and }B)=0.6\cdot0.16=0.096[/tex]The probability of both events happening simultaneously is 0.096.
Given the explicit formula below, which is the appropriate list of the first 4 numbers:An = 3(2)n-1A2, 6, 18, 54, .B3, 6, 9, 12,..С3, 6, 12, 24, ...D1, 3, 5, 7, ...
The simpliest way to answer the question is by iteration, substituting n with the numbers 1, 2, 3, 4 to find the first 4 numbers. So we have the formula;
[tex]A_n=3(2)^{n-1}[/tex]When n = 1,
[tex]\begin{gathered} A_n=3(2)^{n-1} \\ A_1=3(2)^{1-1} \\ A_1=3(2)^0 \\ A_1=3 \end{gathered}[/tex]When n = 2,
[tex]\begin{gathered} A_n=3(2)^{n-1} \\ A_2=3(2)^{2-1} \\ A_2=3(2)^1 \\ A_2=6^{} \end{gathered}[/tex]When n = 3,
[tex]\begin{gathered} A_n=3(2)^{n-1} \\ A_3=3(2)^{3-1} \\ A_3=3(2)^2 \\ A_3=12 \end{gathered}[/tex]When n = 4,
[tex]\begin{gathered} A_n=3(2)^{n-1} \\ A_4=3(2)^{4-1} \\ A_4=3(2)^3 \\ A_4=24 \end{gathered}[/tex]Therefore when n = {1, 2, 3, 4}, An = {3, 6, 12, 24}, making 3, 6, 12, 24 the first 4 numbers of our formula.
Therefore the answer is LETTER C.
This is super confused im not the best with graphs
ANSWER
C. The function is negative when x < 0
EXPLANATION
We want to identify the statement that best describes the function graphed.
To do this, we have to study the graph of the function.
The function graphed has both positive and negative values. The positive values of the function are the part of the function that is above the horizontal red line while part of the negative values of the function is the part of the function that is below the horizontal red line.
We notice that the part of the function that is below the horizontal red line occurs when x is less than 0 (the part of the graph to the left of the vertical red line).
Hence, we can conclude that the correct statement that describes the function is:
The function is negative when x < 0. The answer is option C.
he spent $54integer:
Since the person is spending it means that the money they have is decreasing.
when anything is decreasing we use the negative sign
[tex]He\text{ spent \$54}\rightarrow-54[/tex]Simplify the following expression.(3x – 5)(4 – 9x) + (2x + 1)(6x2 + 5)O12.3 – 21.12 - 671 - 15O12 x3 – 21–2 + 671 - 1512r 3 + 21,2 – 675 + 15O12 x3 + 21x2 + 67x + 15Submit
The Solution:
Given the expression below:
[tex]\mleft(3x-5\mright)\mleft(4-9x\mright)+\mleft(2x+1\mright)\mleft(6x^2+5\mright)[/tex]We are required to simplify the above expression.
[tex]\begin{gathered} \mleft(3x-5\mright)\mleft(4-9x\mright)+\mleft(2x+1\mright)\mleft(6x^2+5\mright) \\ 3x(4-9x)-5(4-9x)+2x(6x^2+5)+1(6x^2+5) \end{gathered}[/tex]Clearing the brackets, we get
[tex]\begin{gathered} 12x-27x^2-20+45x+12x^3+10x+6x^2+5 \\ 12x^3+6x^2-27x^2+12x+45x+10x-20+5 \end{gathered}[/tex][tex]12x^3-21x^2+67x-15[/tex]Therefore, the correct answer is
[tex]12x^3-21x^2+67x-15[/tex]