The given expression is tan(A - B)
Since tan (A - B) is equal to
[tex]\tan (A-B)=\frac{\tan A-\tan B}{1+\tan A\tan B}\rightarrow(1)[/tex]Since the values of cos A and sin B are
[tex]\begin{gathered} \cos A=\frac{35}{37} \\ \sin B=\frac{9}{41} \end{gathered}[/tex]We will use the rules
[tex]\begin{gathered} \tan ^2A=\sec ^2A-1\rightarrow(2) \\ \cot ^2B=\csc ^2B-1\rightarrow(3) \end{gathered}[/tex]csc B = 1/sin B, cot B = 1/tan B, sec A = 1/cos A
[tex]\begin{gathered} \csc B=\frac{1}{\frac{9}{41}}=\frac{41}{9} \\ \sec A=\frac{1}{\frac{35}{37}}=\frac{37}{35} \end{gathered}[/tex]Substitute the value of csc B in rule (3) to find cot B
[tex]\begin{gathered} \cot ^2B=(\frac{41}{9})^2-1 \\ \cot ^2B=\frac{1600}{81} \\ \sqrt[]{\cot^2B}=\pm\sqrt[]{\frac{1600}{81}} \\ \cot B=\frac{40}{9} \end{gathered}[/tex]Reciprocal it to find tan B
[tex]\tan B=\frac{1}{\cot B}=\frac{9}{40}[/tex]Substitute the value of sec A in rule (2) to find tan A
[tex]\begin{gathered} \tan ^2A=(\frac{37}{35})^2-1 \\ \tan ^2A=\frac{144}{1225} \\ \sqrt[]{\tan^2A}=\pm\sqrt[]{\frac{144}{1225}} \\ \tan A=\frac{12}{35} \end{gathered}[/tex]Substitute the values of tan A and tan B in rule (1) above
[tex]\begin{gathered} \tan (A-B)=\frac{\frac{12}{35}-\frac{9}{40}}{1+(\frac{12}{35})(\frac{9}{40})} \\ \tan (A-B)=\frac{165}{1508} \end{gathered}[/tex]The value of tan(A - B) is 165/1508
in the graph of y= 8x + 5, 8 is theof the line
the function is:
[tex]y=8x+5[/tex]where 8 is the slope of the function
-56/6+10x1
please answer it is for a test
Answer:
-0.6 repeating
Step-by-step explanation:
-56/6 + 10 x 1
-56/6 + 10
-9.3 repeating + 10
-0.6 repeating
Answer:
i think 0.666666667
Step-by-step explanation:
2x+6y=-12Find the y and x
we have the follwing:
[tex]2x+6y=-12[/tex]solving for y:
[tex]\begin{gathered} 2x+6y=-12 \\ 6y=-12-2x \\ y=\frac{-12-2x}{6} \end{gathered}[/tex]Answer:
[tex]\begin{gathered} y=\frac{-12}{6}-\frac{2}{6}x \\ y=-0.33x-2 \end{gathered}[/tex]Four different stores have the same digital camera on sale. The original price and discounts offered by each store are listed below. Rank the stores from the cheapest to most expensive sale price of the camera.
Store A: price $99.99 and discount of 15%
Store B: price $95.99 and discount of 12%
Store C: price $90.99 and discount of 10%
Store D: price $89.99 and successive discounts of 5% and 5%
Answer:
Step-by-step explanation:
store A $99.99 x 0.15= 14.9985
99.99-14.9985 = 84.99
store B $95.99 X 0.12= 11.5188
95.99 - 11.5188= 84.47
store C $90.99 x 0.10= 9.099
90.99-9.099= 81.891
store D = $89.99 x 0.05=4.4995
89.99- 4.4995= 85.4905 x 0.05= 4.27
85.4905- 4.27= 81.22
STORE D
STORE C
STORE B
STORE A
A tire company wants to determine if tires made with a new type of tread will last longer than the tires made with the original type of tread. The company has access to 24 different vehicles. The vehicles will be driven for one year and the depth of the remaining tread will be measured. The average depth for the new type of tread will be compared to the average depth of the original type of tread.Which of the following describes a matched pairs design for this experiment?A. Each of the 24 vehicles is numbered 1–24. These numbers are put into a random number generator. The first 12 unique numbers generated will represent the vehicles that will receive the tires with the new tread. The remaining 12 vehicles will receive the tires with the original tread.B. There are six vehicles of each vehicle type: sedan, SUV, minivan, and truck. For each type, the vehicles will be numbered 1–6, and a random number generator will be used to pick three unique numbers. These three vehicles will receive tires with the new tread and the other three vehicles in the group will receive tires with the original tread.c. There are six vehicles of each vehicle type: sedan, SUV, minivan, and truck. Each vehicle type is numbered 1–4, and these numbers are entered into a random number generator. The first two unique numbers selected will represent the group of vehicles that will receive tires with the new type of tread. The remaining two groups will receive tires with the original type of tread.D. The vehicles will be put into groups of two based on the size of the vehicle, with the largest two put together, the next largest two, etc. For each of the 12 groups of two, one of the vehicles is selected and a coin will be flipped. If it is heads, this car will receive tires with the new tread and the other vehicle will receive tires with the original tread. If it is tails, then the opposite will be done.
A matched pairs design is a special case of a randomized block design. It can be used when the experiment has only two treatment conditions; and subjects can be grouped into pairs, based on some blocking variable. Then, within each pair, subjects are randomly assigned to different treatments.
Based in the definition above, the correct answer is D.
Which matrix represents the system of equations below? -12x-13y +132 = 15 7x-10 y– 3z = 11 7x+14y +5z =-5
The system of equations we have is:
[tex]\begin{gathered} -12x-13y+13z=15 \\ 7x-10y-3z=11 \\ 7x+14y+5x=-5 \end{gathered}[/tex]To write the matrix for the system of equations, we need to write only the coefficients of each variable in the matrix. Also, each column will belong to the coefficients of one variable, and each line will belong to each equation (the first line of the matrix will be for equation one, the second line for the second equation, and so on)
We start by writing the first equation into the matrix:
[tex]\begin{bmatrix}{-12} & {-13} & {13\text{ |15}} \\ {\square} & {\square} & \\ {\square} & {\square} & {\square}\end{bmatrix}[/tex]We write the coefficients of each variable x, y, and z, and then in the final column, we write the number that is after the equal symbol in this case 15 (also note that we put a line before 15 to separate the coefficients of the variables from the result of the equation).
Now we take the second equation of the system: 7x-10y-3z=11, and we write the coefficient number in the second line of the matrix:
[tex]\begin{bmatrix}{-12} & {-13} & {13\text{ |15}} \\ {7} & {-10} & {-3\text{ |11}} \\ {\square} & {\square} & {\square}\end{bmatrix}[/tex]And finally, we do the same with the third equation: 7x+14y+5z=-5, and we put the coefficients in order:
[tex]\begin{bmatrix}{-12} & {-13} & {13\text{ |15}} \\ {7} & {-10} & {-3\text{ |11}} \\ {7} & {14} & {5\text{ |-5}}\end{bmatrix}[/tex]A line passes through the point (4,7) and has slope of 5/4. Write an equation in slope intercept form for this line.
Given the point (4,7) and the slope 5/4, we can use the line equation in the form slope-point to get the following:
[tex]\begin{gathered} (x_0,y_0)=(4,7) \\ m=\frac{5}{4} \\ y-y_0=m(x-x_0) \\ \Rightarrow y-7=\frac{5}{4}(x-4)=\frac{5}{4}x-\frac{5\cdot4}{4}=\frac{5}{4}x-5 \\ \Rightarrow y=\frac{5}{4}x-5+7=\frac{5}{4}x+2 \\ y=\frac{5}{4}x+2 \end{gathered}[/tex]therefore, the equation in slope intercept form is y = 5/4x + 2
Can you help me on either of these questions it doesn't matter you can pick
12)
The midpoint of NH can be calculated using the formula:
[tex]M_{NH}=\frac{N+H}{2}...(1)[/tex]From the graph, we identify:
[tex]\begin{gathered} N=0 \\ \\ H=-6 \end{gathered}[/tex]Now, using equation (1):
[tex]\begin{gathered} M_{NH}=\frac{0-6}{2}=\frac{-6}{2} \\ \\ \Rightarrow M_{NH}=-3 \end{gathered}[/tex]According to the graph, this is the point K
Solve each quadratic equation.f(x) = (x + 7)2 – 2
Let's find the solutions:
[tex]\begin{gathered} f(x)=0 \\ \mleft(x+7\mright)^2-2=0 \end{gathered}[/tex]Solve for x:
Add 2 to both sides:
[tex]\begin{gathered} (x+7)^2-2+2=0+2 \\ (x+7)^2=2 \end{gathered}[/tex]Take the square root of both sides:
[tex]\begin{gathered} \sqrt[]{(x+7)^2}=\pm\sqrt[]{2} \\ x+7=\pm\sqrt[]{2} \end{gathered}[/tex]Subtract 7 from both sides:
[tex]\begin{gathered} x+7-7=\pm\sqrt[]{2}-7 \\ x=\pm\sqrt[]{2}-7 \\ so\colon \\ x=\sqrt[]{2}-7\approx5.586 \\ x=-\sqrt[]{2}-7\approx-8.414 \end{gathered}[/tex]You can verify the results using the graph:
What is the area of trapezoid KLMO?A) 224cm^2B) 112 cm^2C) 128 cm^2D) 96 cm^2
Given:
The length of the bases of the trapezoid
[tex]\begin{gathered} KL=a=12cm \\ \\ OM=b=16cm \end{gathered}[/tex]Height of the trapezoid:
[tex]LN=h=8cm[/tex]Required:
The area of trapezoid KLMO
Explanation:
The formula for area of trapezoid is given by
[tex]A(trapezoid)=\frac{a+b}{2}\times h[/tex]Substituting the given values in the above equation we get
[tex]\begin{gathered} A(trapezoid\text{ }KLMO)=\frac{a+b}{2}\times h \\ \\ A(trapezoid\text{ }KLMO)=\frac{12+16}{2}\times8=\frac{28}{2}\times8=14\times8=112cm^2 \end{gathered}[/tex]Final answer:
The area of trapezoid KLMO is 112 sq.cm
I’m not sure why I keep getting this question wrong?
The value of (3x + 27)/8x when x = 3 is $1.50. That is it costs $1.50 to make 3 dozens cookies (option C)
Explanation:[tex]\begin{gathered} \text{The cost model for making x dozens of cookies:} \\ \frac{3x\text{ + 27}}{8x} \end{gathered}[/tex][tex]\begin{gathered} \text{when x = 3, we substitute x with 3} \\ \frac{3x\text{ + 27}}{8x}\text{ = }\frac{3(3)\text{ + 27}}{8(3)} \\ =\text{ }\frac{\text{9 + 27}}{24} \\ =\text{ }\frac{36}{24}=\frac{3}{2} \\ =\text{ }1.50 \end{gathered}[/tex]Since the cost we got is for 3 dozens of cookies, we say the cost for making 3 dozens of cookies is $1.50
The value of (3x + 27)/8x when x = 3 is $1.50. That is it costs $1.50 to make 3 dozens cookies (option C)
Which inequality is true when the value of u is 1? O-- 10 > -1.5 u – 10 > 1.5 O –u – 10 – 1.5 O – 10 >1.5
First, let's solve each one of the inequalities for u
1) -u-10>-1.5
u<-10+1.5
u<-8.5 then this statement is not true for u=1
2) u-10>1.5
u>1.5+10
u>11.5 then this statement is not true for u=1
3) -u-10<1.5
u>-10-1.5
u>-11.5 which is true for u=1
4)-u-10>1.5
u<-11.5 which is not true for u=1
then the correct option will be -u-10<1.5Gabriella is a 11 years younger than Mikal the sum of their ages is 51 what is mikhails age
Answer:
30
Step-by-step explanation:
11 plus 30 is 51 therefor your sum is 30
given the polygon below, if
The value of ∠Q = 130
A polygon is a flat or plane two-dimensional closed shape with straight sides. It doesn't have any curved edges. A polygon's sides are also known as its edges.
Given that in the polygon ∠T = ∠S and ∠S = 115
We have to find q
The formula to calculate the sum of the inner angles of an n sides polygon is
(n-2) x 180
= (5-2) x 180
= 3 x 180
= 540
Sum of inner angles of polygon = 540
Since T = S
In the polygon P = R = 90
Q = 540 – 2 x 115 – 2 x 90
Q = 540 – 230 – 180
Q = 540 – 410
Q = 130
Therefore the value of ∠Q = 130
To learn more about polygons visit
https://brainly.com/question/10441863
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Find the unit price in cents per diaper for each of the brands shown below. Round to the nearest tenth of a cent.Brand A: 36 Diapers, $ 11.99 ? : ¢ per diaper Brand B: 50 Diapers, $11.49? : ¢ per diaper Note: Rounding to the nearest tenth of a cent is the same as rounding to the nearest thousandth of a dollar.Which is the better buy?
It is required that you find the unit price in cents per diaper.
To do this, convert the prices in dollars to cents by multiplying by 100.
[tex]\begin{gathered} \$11.99=11.99\times100\text{ cents} \\ =1199¢ \end{gathered}[/tex][tex]\begin{gathered} \$11.49=11.49\times100\text{ cents} \\ =1149¢ \end{gathered}[/tex]Next, divide the respective prices in cents by the corresponding number of diapers:
For brand A:
[tex]\frac{1199}{36}\approx33.3¢\text{ per diaper}[/tex]For brand B:
[tex]\frac{1149}{50}=22.98\approx23.0¢\text{ per diaper}[/tex]Next, notice that Brand B has a lower unit price. Hence, it is the better buy.
Brand B is the better buy,
Hello, I'm finding this a tad bit difficult.A little help please. Question 1a. Calculate the total are including the frame.Question 1b: Calculate the external perimeter of this picture frame.
Part a.
In the first part of the problem we need to calculate the total area including the frame, for this, we use the formula for the area of a parallelogram:
In this case, the values of a, b and c are:
[tex]\begin{gathered} a=42\operatorname{cm} \\ b=65\operatorname{cm} \\ c=0.39m=39\operatorname{cm} \end{gathered}[/tex]Thus, the area is:
[tex]\begin{gathered} A=65\operatorname{cm}\times39\operatorname{cm} \\ A=2,535\operatorname{cm}^2 \end{gathered}[/tex]2,535 centimeters squared.
Part b.
In this part, we are asked to find the external perimeter of the picture frame.
For this, we use the formula to find the perimeter of a parallelogram:
Substituting the values of a and b from part a into the perimeter formula:
[tex]\begin{gathered} P=2(a+b) \\ P=2(42\operatorname{cm}+65\operatorname{cm}) \\ P=2(107\operatorname{cm}) \\ P=214\operatorname{cm} \end{gathered}[/tex]The perimeter of the frame is 214 centimeters.
Answer:
A. Area
[tex]2,535\operatorname{cm}^2[/tex]B. Perimeter
[tex]214\operatorname{cm}[/tex]I need help with the Try it! section. i will flow a walk through if you can give one
Solution
For this case we need to remember that the general equation for a line is given by:
y= mx+ b
Where m represent the slope and b the intercept
And we can find the slope with this formuala:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]And we can use (50, 725) and (100,1325) and we have:
[tex]m=\frac{1325-725}{100-50}=12[/tex]And the intercept would be:
725 = 50*12 +b
b= 725 - 600
b= 125
and the equation would be given by:
y= 12 x + 125
And the y intercept represent the starting value of 125$ no matter the number of guests
In the accompanying diagram of parallelogramABCD, m_A = (2x + 10) and mZB = 3x. Find thenumber of degrees in m_B.D3x(2x + - 10)ABBYour answer
Answer
Angle B = 102°
Angle A = 78°
Explanation
The first thing to note in answering this is that for parallelograms,
- Opposite angles are equal to each other.
- Adjacent angles (angles close to each other) sum up to give 180°.
So, in the given parallelogram, we can see that the two angles given are adjacent angles. Hence,
2x + 10° + 3x = 180°
5x + 10° = 180°
5x = 180° - 10°
5x = 170°
Divide both sides by 5
(5x/5) = (170°/5)
x = 34°
So, we can solve for Angle B now
Angle B = 3x = 3 (34°) = 102°
Angle A = 2x + 10° = 2(34°) + 10° = 68° + 10° = 78°
Hope this Helps!!!
Find the volume of the solid. Use 22/7 for II
We have a rectangular solid prism. The formula to find the volume of this prism is as follows:
[tex]V=\text{lwh}[/tex]Where:
• l = length,. In this case, we have that ,l = 6cm,.
,• w = width,. In this case, we have that ,w = 5cm,.
,• h = height,. In this case, ,h = 1cm,.
Then, we have:
[tex]V=6\operatorname{cm}\cdot5\operatorname{cm}\cdot1\operatorname{cm}=30\text{cubic cm.}[/tex]Therefore, the value for the volume of the rectangular prism is equal to 30 cubic centimeters (30cm³) (30 cubic cm) (last option).
X + 5y = 8, -x + 2y = -1
x+5y=8
-x+2y=-1 => x=2y+1
(2y+1)+5y=8 => 7y=7 => y=1 => x=3
The answer is x=3 and y=1
Determine the area of the shaded sector. Use 3.14 for 7. Round your answer to the nearest tenth.
If the diameter is 26, the radius is 26/2 = 13
The area of a circle is (pi)(radius)^2 = 3.14(13)^2 = 3.14(169) = 530.66
A complete circle has 360 degrees
Half a circle is 180 degrees
So the shaded area is (360 - 180 - 120)/360 of the complete circle
Doing the operations: (360 - 180 - 120)/360 = 60/360 = 1/6 of the complete circle
If the complete circle area is 530.66, the shaded area is (1/6)(530.66) = 88.443
They ask for the result to be rounded to the nearest tenth, so the result would be 88.4
Answer: 88.4
I need help on number 10, the faster u do it the more stars I’ll give u!
Given the equation;
[tex]P=(l+w)[/tex]At;
[tex]\begin{gathered} l=14ft \\ w=9ft \end{gathered}[/tex]substituting the given values;
[tex]undefined[/tex]Oliver Queen is able to hit the bull's-eye (center of the target) 87% of the time. If he shoots 29 arrows, what is the probability that he hits the bull
eye exactly 13 times?
The probability that he hits the bull's-eye in one shot is given by p = 0.87
Then, the probability that the hits the bull's-eye m times in n shots is given by:
[tex]P(m|n)=\frac{n!}{m!(n-m)!}p^m(1-p)^{n-m}[/tex]For n = 29 and m = 13 we have:
[tex]\begin{gathered} P(13|29)=\frac{29!}{13!16!}0.87^{13}\cdot0,13^{16} \\ P(13|29)=4.0\cdot10^{-8} \end{gathered}[/tex]16. The graph shows the relationship between the total cost and the amount of rice purchased 32 20 Total price ($) Amount of rice (lb) Part A: What does the ordered pair (6, 30) represent? Part B: Which point on the graph represents the unit price? Part C: How many pounds would you have to buy for the total cost to be $20? Explain how to find the answer
For the information given in the statement you have:
Part A: According to the graph, the point (6,30) means that the total cost of 6 pounds of rice is $30.
Part B: The unit price per pound of rice can be seen in the graph at point (1,4), that is, the price of 1 pound of rice is $ 4.
Part C: To find out how many pounds you would have to buy for the total cost to be $ 20 you have to find the point whose second coordinate is 20, that is, point (4,20), then you would have to buy 4 pounds of rice for the total cost to be $20.
Find the value of X in the length of MO
We are given that:
N is between M & O
[tex]\begin{gathered} MN=2x+4 \\ MO=6x \\ NO=28 \\ \\ \text{If N is the midpoint of M \& O, we have:} \\ MN=NO \\ 2x+4=28 \\ \text{Subtract ''4'' from both sides, we have:} \\ 2x=28-4 \\ 2x=24 \\ \text{Divivde both sides by ''2'', we have:} \\ x=\frac{24}{2}=12 \\ x=12 \\ \\ \therefore x=12 \end{gathered}[/tex]We will obtain the value of MO by substituting the value of ''x'' into MO. We have:
[tex]\begin{gathered} MO=6x \\ x=12 \\ MO=6(12)=72 \\ MO=72 \\ \\ \therefore MO=72 \end{gathered}[/tex]Solve each equation for the variable. -10 = Зm +5
-10 = Зm +5
Subtract 5 from both sides of the equation:
-10-5 = 3m+5-5
-15 = 3m
Divide both sides by 3
-15/3 = 3m/3
-5= m
m= -5
Choose the linear equation that best fits the data on the graph
We have several points in a graph and want to know what of the options is the best fit.
Due the options has very diferent slopes for the line we can solve the problem by inspection, so:
• The slope of the line must be negative, because the points data show a negative slope. ,So, the options A and B are discarded.
,• The points show a big slope. For Option C, when x = 4, y = -7 that is near from data, for Option D, when x =4, y = -1 which is very far from data.
So the correct answer is the option C.
The average daily high temperatura for the month of may in Ocala, Florida is approximated by the fuction f(n)= 0.2n + 80, where n is the day of the month. May has 31 days. The maximum daily high temperature ocurred on May 31 st. What was the msximum temperature?
n = day of the month
Therefore,
The maximum temperature for may 31st will be
[tex]\begin{gathered} f(n)=0.2n+80 \\ f(31)=0.2(31)+80 \\ f(31)=6.2+80=86.2\text{ } \end{gathered}[/tex]I need help with this question(Please no long explanation just the answer)
To find the answer to this question, we only have to add $12.80 once more time to the Simple Interest Earned.
[tex]12.80+38.40=51.2[/tex]At the fourth year, the Simple Interest Earned is $51.2 and the new account balance is $451.2.
Identify the statement that best describes the output for the following R command. filter (Fingers, SSLast != “NA”)a) A list of the values in SSLast that are “NA”.b) A list of the values in SSLast excluding the “NA” values.c) A list of all the values in SSLast, but not in Fingers.d) A list of all values in Fingers excluding the “NA” values.
solution
filter(Fingers, SSLast != "NA") includes only cases for which the variable SSLast is not equal to NA. Therefore
answer:
b) A list of the values in SSLast excluding the “NA” values.