Given,
The initial velocity of the ball, u=2.3 m/s
The time interval in which the ball hits the ground, t=4 s
As the ball was thrown horizontally, the angle of projection is θ=0°
The distance traveled by the ball in the horizontal direction is given by,
[tex]\begin{gathered} x=u_xt \\ \Rightarrow x=u\cos \theta\times t \end{gathered}[/tex]Where uₓ is the x-component of the initial velocity.
On substituting the known values,
[tex]\begin{gathered} x=2.3\times\cos 0^{\circ}\times4 \\ =9.2\text{ m} \end{gathered}[/tex]Therefore the distance traveled by the ball in the x-direction is 9.2 m. That is the ball landed 9.2 meters away from the building.
Applying the equation of the motion in the y-direction,
[tex]\begin{gathered} y=y_0+u_yt+\frac{1}{2}gt^2 \\ =y_0+u\sin \theta\times_{}t+\frac{1}{2}gt^2 \end{gathered}[/tex]Where y is the final height of the ball which is zero meters, y₀ is the initial height of the ball, i.e., the height of the building, uy is the y-component of the initial velocity.
Let us consider that the upward direction is positive while the downward direction is negative. This makes the acceleration due to gravity, g, a negative value, and the height of the building a positive value.
On substituting the known values,
[tex]\begin{gathered} 0=y_0+2.3\times\sin (0^{\circ})\times4+\frac{1}{2}\times-9.8\times4^2 \\ \Rightarrow-y_0=0-4.9\times4^2 \\ y_0=78.4\text{ m} \\ \approx78\text{ m} \end{gathered}[/tex]Therefore the height of the building is 78 m
The figure below is made of 1-inch cubes. Two cubes have been removed from each row of the middle layer of a prism.What is the volume of the figure above? A. 34 in3 B. 38 in3 C. 40 in3 D. 36 in3
The volume of the prism is given by:
[tex]\begin{gathered} V=w\cdot l\cdot h \\ so\colon \\ V=4\cdot2\cdot5 \\ V=40in^3 \end{gathered}[/tex]Since two cubes have been removed from each row, the new volume is:
[tex]V_T=40in^3-4in^3=36in^3[/tex]Answer:
36 in³
Find the x-component of thisvector:47.3m39.40
We know that
• The angle of direction is 39.4.
,• The magnitude of the vector is 47.3 m.
To find the horizontal component, use the following formula.
[tex]v_x=v\cdot\cos \theta[/tex]Use the given information to find the horizontal component.
[tex]v_x=47.3m\cdot\cos 39.4\approx36.6m[/tex]Therefore, the x-component is 36.6(m).What happens to Centripedal force on the planet around a star if the radius of an orbit is doubled ? assume that velocity remains the same A) the Centripedal force will be half of its original value B) the Centripedal force will be double its original value C) the Centripedal force will be 1/4 of its original value D) the Centripedal force will not change
We will have the following:
We know that:
[tex]F_c=\frac{mv^2}{r}[/tex]If we double the radius, then:
[tex]F_c=\frac{mv^2}{(2r)}\Rightarrow F_c=\frac{1}{2}\frac{mv^2}{r}[/tex]So, the centripetal force will be half of its original value. [Option A]
11. If 100. g of gold-198 decays to 12.5 g in 25.3 days, what is the half-life of gold-198?
Given data
*The amount of gold-198 is N = 100 g
*The gold-198 decays is n = 12.5 g
*The given time is T = 25.3 days
The expression for the radioactivity decay is given as
[tex]N=n(\frac{1}{2})^{\frac{T}{t}}[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} 100=12.5(\frac{1}{2})^{\frac{25.3}{t}} \\ t=8.43\text{ days} \end{gathered}[/tex]A 1,982-kg car starts from rest at the top of a driveway 6.74 m long that is sloped at an angle of 30 degrees with the horizontal. If an average friction force of 2,721 N impedes the motion of the car, find the speed (in m/s) of the car at the bottom of the driveway.Use the approximation that g ≈ 10 m/s2.
In this situation, we cannot apply the law of conservation of energy, as there is friction. For us to solve, let us start by writing the balance equations. We'll have:
[tex]\sum F_x=P*sin(30)-Fat=ma[/tex][tex]\sum F_y=N-P*cos(30)=0[/tex]In order to find out the acceleration, we can use the first equation:
[tex]a=\frac{P*sin(30)-Fat}{m}=\frac{1982*10*sin(30)-2721}{1982}=3.627\frac{m}{s^2}[/tex]The car will then suffer this acceleration on the sloped plane. With this, we can calculate its speed by the end using the equations for a uniformly accelerated movement:
[tex]S(t)=S_0+v_0t+\frac{at^2}{2}\Rightarrow6.74=\frac{3.627*t^2}{2}\Rightarrow t=1.928s[/tex]This is the time the car will take to reach the bottom. By replacing this on the equation for the velocity we get:
[tex]v(t)=v_0+at=0+3.627*1.928=7\frac{m}{s}[/tex]Then, our final answer is 7 m/s
a car travels 680 km in a time of 4 h calculate its speed
Hello..!
To calculate its speed we apply the following data.
Data:
D = 680kmT = 4hrsV = ?Then, we apply the formula that is.
Formula:
V = D/TFinally we develop the problem.
Developing:
V = 680km / 4hV = 170km/hThe speed of the car is 170 kilometers per hour.
The metric unit of charge, the Coulomb, is ________.A) the charge of just one electron or protonB) the smallest unit of charge used in scienceC) is an amount of energy equivalent to equal numbers of electrons and protonsD) equivalent to a large number (6.25 x 1018) of unitary charges
The meteric unit of charge, the Coulomb, is equivalent to a large number of (6.25 x 10^18) of unitary charges.
Hence, the correct option is (D)
1. what is the range of the infrared part of the electromagnetic spectrum A.microwaves to red light B.radio waves to microwavesC. X-rays to gamma raysD. ultraviolet to x-rays
The range of the infrared wave is from the red to the microwave.
the rannge of wavelength of the infrared is ,
[tex]2-14\mu m[/tex]Hence, A is the correct option.
I need to know how to do these and the formula too.
Answer:
a = 4m kgm/s & b. v = 4 m/s
Explanation:
a:
A is approaching in the opposite direction of B
So let's take the velocity of A as negative.
Here we'd need to solve this using conservation of momentum.
m1u1 + m2u2 = m1v1 + m2v2
So initial momentum = (m X (-4)) + (m X 8) = -4m + 8m = 4m
b:
After collision sphere A stops, so v = 0 for sphere A
Using the conservation of momentum formula, we get
(m X (-4)) + (m X 8) = (0 X m) + (m X v) [let the final velocity of B be v]
⇒ 4m = vm
⇒ v = 4 m/s
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Take a look.
[tex]\sqrt[2]{24+5}[/tex]Tory experiments with pulleys in physics class. She applies 60 newtons of force to a single pulley to lift a bowling ball. By adding another pulley, she'd get a mechanical advantage of 2. Whats the minimum input force she'll need to lift the ball if she adds another pulley?
Given,
The force applied by Tory, F=60 N
Mechanical advantage after adding the second pulley, MA=2
As Tory applies 60 N of force when there is only one pulley, the weight of the ball is 60 N.
Thus the output force is 60 N.
The mechanical advantage is given by,
[tex]MA=\frac{\text{output force}}{input\text{ force}}[/tex]On substituting the known values,
[tex]\begin{gathered} 2=\frac{60}{\text{input force}} \\ \Rightarrow input\text{ force}=\frac{60}{2} \\ =30\text{ N} \end{gathered}[/tex]Thus the minimum input force tory need to apply is 30 N
You have been given 3.152 g of copper from which you are to fashion a wire whose resistance is 2,473.562 ohms. The density of copper is 8900 kg/m 3 and the resistivity of copper is 1.7 x 10 -8 ohm m. What will the diameter, in mm, of the wire be that you fashion?
Given:
Mass of copper, m = 3.152 g = 0.003152 kg
Resistance = 2,473.562 ohms
Density of copper = 8900 kg/m³
Resistivity of copper = 1.7 x 10⁻⁸ ohm.m
Let's find the diameter of the wire.
Apply the density formula to find the volume:
[tex]\begin{gathered} \rho=\frac{m}{v} \\ \\ v=\frac{m}{\rho}=\frac{0.003152}{8900} \\ \\ v=3.54*10^{-7}\text{ m}^3 \\ \\ (\pi r^2)l=3.54*10^{-7}\text{ m}^3 \end{gathered}[/tex]Now, apply the formula:
[tex]\begin{gathered} R=\frac{\rho l}{A} \\ \\ l=\frac{RA}{\rho} \\ \\ l=\frac{2473.562*\pi r^2}{1.7*10^{-8}} \\ \\ \frac{l}{\pi r^2}=\frac{2473.562}{1.7*10^{-8}} \\ \\ \frac{l}{\pi r^2}=1.455*10^{11} \\ \\ l=1.455*10^{11}*\pi r^2 \end{gathered}[/tex]Now, combine both expressions for L:
[tex]1.455*10^{11}*\pi r^2*\pi r^2=3.54*10^{-7}[/tex]Solving further:
[tex]\begin{gathered} (\pi r^2)^2=\frac{3.54*10^{-7}}{1.455*10^{11}} \\ \\ (\pi r^2)=\sqrt{2.434*10^{-18}} \\ \\ \pi r^2=1.56*10^{-9} \\ \\ r^2=\frac{1.56*10^{-9}}{\pi} \\ \\ r=\sqrt{\frac{1.56*10^{-9}}{\pi}} \\ \\ r=2.228*10^{-5} \end{gathered}[/tex]r is the radius.
We know that:
Diameter = 2 x radius
Thus, we have:
[tex]\begin{gathered} d=(2.228*10^{-5})*2 \\ \\ d=4.4569*10^{-5}\text{ m} \\ \\ d=0.044569*10^{-3}m \\ \\ d=0.0446\text{ mm} \end{gathered}[/tex]Therefore, the diameter in mm will be 0.0446 mm
ANSWER:
0.0446 mm
An aluminum sphere is 8.55 cm in diameter. What will be it's % change in volume if it is heated from 30 C to 155 C?
We know that
• The sphere diameter is 8.55 cm.
,• The temperature change is from 30 C to 155 C.
First, we have to find the radius of the sphere. The radius is the half diameter.
[tex]\begin{gathered} r=\frac{d}{2}=\frac{8.55\operatorname{cm}}{2} \\ r=4.275\operatorname{cm} \end{gathered}[/tex]Now we have to find the volume of the sphere using the following formula.
[tex]V=\frac{4}{3}\pi(r)^3[/tex]Where r = 4.275 cm.
[tex]\begin{gathered} V=\frac{4}{3}\pi(4.275\operatorname{cm})^3 \\ V\approx327.26(cm)^3 \end{gathered}[/tex]Then, we use the following formula
[tex]V_2-V_1=BV_0(T_2-T_1)[/tex]Where the initial volume is 327.26 cubic cm, B is a constant about thermal expansion for aluminum, and we have to find the final volume to then calculate the percentage change.
[tex]\begin{gathered} \Delta V=75\times10^{-6}\cdot327.26(155-30) \\ \Delta V=75\times10^{-6}\cdot327.26(125) \\ \Delta V\approx3.07(cm)^3 \end{gathered}[/tex]This means that the volume change is 3.07 cubic centimeters.
At last, we have to divide the volume change by the initial volume, and then we have to multiply it by 100% to express it as a percentage.
[tex]\frac{\Delta V}{V_1}\times100=\frac{3.07}{327.26}\times100\approx0.938[/tex]Therefore, the percentage change is 0.938%.A cyclist advances 38 km in 1 hour and 30 minutes. Your average speed was: Select one: 47 0 25.3 km/h OR 22 km/h OR 18 km/h OR 38 km/h
Hello..!
We initially apply the data to the problem.
Data:
D = 38kmT = 1.5hV = ?Then, we apply the formula that is.
Formula:
V = D/TFinally we develop the problem.
Developing:
V = 38km / 1.5hV = 25.3km/hTherefore the correct option is 25.3 kilometers per hour.
Answer:
Formula
V = d/tResolve
V = 38km / 1.5hV = 25.3 km/hHope this helped
Two skaters with the same mass face each other standing still. Both skaters push off each other and they love in opposite directions. What’s the momentum before pushing off? Total momentum after pushing off? Momentum of each in comparison to each other after pushing off
We will have the following:
Total momentum before pushing each other off: 0.
Total momentum after pushing each other off: 0.
Momentum of each other after pushing off in comparison to each other:
*Person 1: A positive value.
*Person 2: A negative value of equal magnitude to the momentum of person 1.
Describe the cause of waves as a fluid motion
Wind is the most frequent cause waves. The friction between the wind and the surface of the water produces wind-driven waves, also known as surface waves. A wave crest is produced when wind continuously disturbs the water's surface in an ocean or lake.
Waves that include longitudinal and transverse motions include water waves, for instance. The particles move in clockwise rings through the waver as a wave passes over it. The circles' radius gets smaller the deeper into the ocean you go.The disturbance propagates through the medium as a result of the medium's particles oscillating repeatedly and periodically about their equilibrium position. Without any real transfer of the medium's particles, energy and momentum are moved from one place to another.To know more about waves
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A vector has the components Ax=22 m and Ay=13 m. What is the magnitude of thisvector? What angle does this vector make with the positive x axis?
Answer:
Magnitude = 25.55 m
Angle = 30.58 degrees
Explanation:
If the vector has the components Ax = 22 and Ay = 13, we can represent the vector as:
Therefore, the magnitude of this vector is the magnitude of the red vector. It means that we can calculate its length using the Pythagorean theorem where 22 and 13 are the legs, so:
[tex]\sqrt[]{Ax^2+Ay^2}=\sqrt[]{22^2+13^2}=\sqrt[]{484+169}=\sqrt[]{653}=25.55\text{ m}[/tex]Then, we can find the angle using the trigonometric function tangent, so:
[tex]\begin{gathered} \tan \theta=\frac{Ay}{Ax} \\ \tan \theta=\frac{13}{22} \\ \tan \theta=0.5909 \\ \theta=\tan ^{-1}(0.5909) \\ \theta=30.58 \end{gathered}[/tex]So, the answers are:
Magnitude = 25.55 m
Angle = 30.58 degrees
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Two samples of water are prepared, one with red food coloring and one with blue. When carefully combined, the red-colored water is able to float on top of the bluecolored water. Which statement best explains this result?
A. The blue-colored water is hotter and more dense.
B. The red-colored water is cooler and more dense .
C. The blue-colored water is cooler and less dense.
D. The red- colored water is hotter and less dense.
Answer:
B. The red-colored water is cooler and more dense .
Match each expression on the left with an equivalent expression on the right. Some answer choices on the right will not be used.1/50.451/80.6259/203/40.1250.24/55/8
1/5 = 0.2
1/8 = 0.125
9/20 = 0.45
3/4 = 0.75
4/5 = 0.8
5/8 = 0.625
Explanations:This exercise is to convert the given fractions to decimals
Let us find the decimal equivalents of each of the fractions first, then the equivalent choices can be matched together
1/5 = 0.2
1/8 = 0.125
9/20 = 0.45
3/4 = 0.75
4/5 = 0.8
5/8 = 0.625
A closed-pipe resonator is closed at both ends. Is this true or false?
A closed cylinder air column must have a closed end and an open end.
Then, the answer is:
[tex]\text{False}[/tex]Abby, who has a mass of 45.0 kg, is riding at 40.0 m/s in her red sports car whenshe must suddenly slam on the brakes to avoid hitting a deer crossing the road. Shestrikes the air bag, that brings her body to a stop in 0.500 s. What average forcedoes the seat belt exert on her?
We are given the following information
Mass = m = 45.0 kg
Initial speed = vi = 40.0 m/s
Time = t = 0.500 s
We are asked to find the average force that the seat belt exerted on her.
Recall from Newton's second law of motion,
[tex]F=m\cdot a[/tex]Where a is the acceleration of the car and is given by
[tex]v_f=v_i+a\cdot t[/tex]Where vf is the final velocity of the car that must be 0 since the car was stopped.
[tex]\begin{gathered} 0=40.0+a\cdot0.500 \\ a=\frac{-40.0}{0.500} \\ a=-80\; \; \frac{m}{s^2} \end{gathered}[/tex]The negative sign indicates deacceleration since the card was stopped.
So, the force is
[tex]\begin{gathered} F=m\cdot a \\ F=45\cdot80 \\ F=3600\; N \end{gathered}[/tex]Therefore, the seat belt exerted a force of 3600 N on her.
What percentage of the speed of light in vacuum is the speed of light in a diamond? Incorrect: Your answer is incorrect. answer in:_____%
Explanation
Step 1
find the speed of ligth in the diamond:
to do that we can use the formula
[tex]refractive\text{ index\lparen}\mu)=\frac{c(\text{ speed of light in vaccum\rparen}}{s(\text{ speed of light in the material\rparen}}[/tex]we know that :
[tex]\begin{gathered} refractive\text{ index of diamond\lparen}\mu)=2.42 \\ speed\text{ of llight in the vaccum=c=300000 }\frac{km}{s} \end{gathered}[/tex]so, replace and solve for speed of light in the diamond
[tex]\begin{gathered} refractive\text{ index\lparen}\mu)=\frac{c(\text{ speed of light in vaccum\rparen}}{s(\text{ speed of light in the material\rparen}} \\ 2.42=\frac{3*10^5\frac{km}{s}}{s} \\ s=\frac{3\times10^5\frac{km}{s}}{2.42} \\ s=123966.9\text{ }\frac{km}{s} \\ \end{gathered}[/tex]finally, to find the percentage apply this formula
[tex]\begin{gathered} \text{ \% }=\frac{speed\text{ of light in diamond}}{spped\text{ of ligth invaccum}}*100\text{ \%} \\ replace \\ \text{ \%=}\frac{123966.9\frac{km}{s}}{3*10^5\frac{km}{s}}*100\text{ \%} \\ \text{ \%=0.413*100\%} \\ \text{ \%=41.3 \%} \\ rounded\text{ 41\%} \end{gathered}[/tex]so, the answer is
41 %
I hope this helps you
Traumatic brain Injury such as concussion results when the undergoes very large acceleration Generally an than 800 m/s ^ 2 lasting for any length of time will not , whereas an acceleration greater than 1, 000 m/s ^ 2 for at least 1 injury. Suppose a small child rolls off a bed that is 0.47 m above the floor. If the floor is hardwood the child’s head is brought to rest in approximately 2.1 mm. If the floor is carpeted,this stopping distance is increased to about 1.3 cm . Calculate the magnitude and duration of the deceleration in both cases, to determine the risk of injury. Assume the child remains horizontal during the fall to the floor. Note that a more complicated fall could result in a head velocity greater or less than the speed you calculate. Hardwood floor magnitude m/s^2Hardwood floor duration msCarpeted floor magnitude m/s^2Carpeted floor duration ms
ANSWER:
Hardwood floor magnitude: 2193.15 m/s^2
Hardwood floor duration: 1.38 ms
Carpeted floor magnitude: 354.27 m/s^2
Carpeted floor duration: 8.56 ms
STEP-BY-STEP EXPLANATION:
We have the following information:
Distance of the bed from the floor: 0.47 m
Stopping distance by hardwood: 2.1 mm
Stopping distance by carpet: 1.3 cm
We must find the speed of the child when he hits the ground using the following formula:
[tex]v^2=u^2+2gh[/tex]Where v is the final velocity, u is the initial velocity, g is the gravitational acceleration and h is the distance traveled.
Replacing and solving for v
[tex]\begin{gathered} v^2=0^2+2\cdot9.8\cdot0.47 \\ v=\sqrt[]{9.212} \\ v=3.035\text{ m/s} \end{gathered}[/tex]We can find the deceleration provided by the hardwood when stopping the child using the formula:
[tex]v^2=u^2-2aS[/tex]Since the child will stop, the final speed will be 0, the initial speed will be the speed gained by the child while falling that we found in the first step, and the distance S to stop is given in the question.
Replacing and solving for a:
[tex]\begin{gathered} 2.1\text{ mm }\cdot\frac{1\text{ m}}{1000\text{ mm}}=2.1\cdot10^{-3}m \\ 0^2=3.035^2-2\cdot a\cdot(2.1\cdot10^{-3}) \\ 2\cdot a\cdot(2.1\cdot10^{-3})=9.211 \\ a=\frac{9.211}{2\cdot(2.1\cdot10^{-3})} \\ a=2193.15\text{ }\frac{m}{s^2} \end{gathered}[/tex]From the calculated deceleration, we can find the time it takes for the child to stop after hitting the hardwood using the formula:
[tex]\begin{gathered} v=u-at \\ \text{replacing and solving for t:} \\ t=\frac{v-u}{-a} \\ t=\frac{0-3.035}{-2193.15} \\ t=0.00138\text{ s} \\ t=1.38\text{ ms} \end{gathered}[/tex]We repeat the same procedure but now with the data of the carpet, therefore:
[tex]\begin{gathered} 1.3\text{ cm }\cdot\frac{1\text{ m}}{100\text{ cm}}=1.3\cdot10^{-2}m \\ 0^2=3.035^2-2\cdot a\cdot(1.3\cdot10^{-2}) \\ 2\cdot a\cdot(1.3\cdot10^{-2})=9.211 \\ a=\frac{9.211}{2\cdot(1.3\cdot10^{-2})} \\ a=354.27\text{ }\frac{m}{s^2} \end{gathered}[/tex]Time for stopping by the carpet:
[tex]\begin{gathered} t=\frac{v-u}{-a} \\ t=\frac{0-3.035}{-354.27} \\ t=0.00856\text{ s} \\ t=8.56\text{ ms} \end{gathered}[/tex]When you describe a metal surface as smooth, what property are youdescribing?7O A. ColorO B. HardnessO C. ShapeO D. TextureSUBMIT
Answer: D. Texture
Explanation:
Texture is used to describe the characteristics of a surface. A surface can be described as smooth or rough. Thus, the correct option is
D. Texture
I need help with questions number 2 I have the answer to number 1
Given,
the distance from Redd's door to the park, s=15 m
The total distance is the sum of the distance from her door to the park and the distance from the park to her door.
That is,
[tex]\begin{gathered} \text{total distance}=s+s \\ =15+15 \\ =30\text{ m} \end{gathered}[/tex]The displacement is defined as the shortest distance from the starting and ending point of a path. The starting and ending point of Redd's path is the door.
Therefore the total displacement is zero meters.
Therefore, distance = 30 m
and displacement = 0 m
A spring stores 68 J of potential energy when it is stretched by 6 cm. What is the spring constant?
The formula for calculating the elastic potential energy is expressed as
Elastic potential energy = 1/2kx^2
where
k represents the spring constant
x represents the compression or distance by which the spring was stretched.
From the information given,
Elastic potential energy = 68
x = 6 cm
we would convert 6 cm to m. Recall,
100cm = 1 m
6 cm = 6/100 = 0.06 m
By substituting these values into the formula, we have
68 = 1/2 x k x 0.06^2
68 = 0.0018k
k = 68/0.0018
k = 37777.78 N/m
The spring constant is 37777.78 N/m
The neutrons within the nucleus of an atom have what charge?Question 15 options:negativesame as an electronsame as a protonno charge
The nuclues of an atom contains the proton and the nuetron. The proton is positively charged while the nuetron has no charge.
I just need part c please The first one I know it’s 32
We are given that in a falling object the distance "d" is directly proportional to the square of the time and the proportionality constant is 16. This means that the function of distance is given by:
[tex]d(t)=16t^2[/tex]The average rate of change is given by the following formula:
[tex]r=\frac{d(t_f)-d(t_0)}{t_f-t_0}[/tex]Where:
[tex]t_f,t_0=\text{ final and initial time}[/tex]Now, we substitute the values of "d(t)":
[tex]r=\frac{16t_f^2-16t_0^2}{t_f-t_0}[/tex]We can factor the numerator and we get:
[tex]r=16\frac{(t_f-t_0)(t_f+t_0)}{t_f-t_0}[/tex]Simplifying we get:
[tex]r=16(t_f+t_0)[/tex]For the first 2 seconds we have:
[tex]\begin{gathered} t_0=0 \\ t_f=2s \end{gathered}[/tex]Substituting the values we get:
[tex]\begin{gathered} r=16(2s+0s) \\ r=32 \end{gathered}[/tex]Therefore, the average rate of change is 32
For the next 2 seconds we have:
[tex]\begin{gathered} t_0=2s \\ t_f=4s \end{gathered}[/tex]Now, we substitute the values:
[tex]\begin{gathered} r=16(4s+2s) \\ r=96 \end{gathered}[/tex]Therefore, the rate of change in the next two seconds is 96.
For the next 2 seconds we have:
[tex]\begin{gathered} t_0=4s \\ t_f=6s \end{gathered}[/tex]Substituting the values we get:
[tex]\begin{gathered} r=16(6s+4s) \\ r=160 \end{gathered}[/tex]Therefore, the rate of change is 160
A strobe-light series of pictures is taken of a red ball and a blue ball. The red ball was allowed to drop straight down, and the blue ball was given an initial horizontal velocity. Lines are drawn connecting each red ball image with the corresponding blue ball image. Describe the lines connecting the images.1) The lines slope down from the red ball to the corresponding blue ball.2) The lines slope up from the red ball to the corresponding blue ball.3) The lines are vertical.4) The lines are horizontal.
The lines are horizontal.
Horizontal velocity doesn't have any effect on the acceleration or speed of falling. In every picture, the red and the blue are both at the same HEIGHT, even though the blue one is pulling away horizontally.
i’m a really confused on what to do the teacher didn’t really explain it well so i’m clueless on what to do..
ANSWER:
0, no direction
balanced
STEP-BY-STEP EXPLANATION:
We must add all the forces, the horizontal and vertical.
We must take into account the direction of the force, to the right and up are positive while to the left and down are negative.
Therefore:
[tex]\begin{gathered} F_{Rvertical}=F_n+F_g=20+(-20)=20-20=0 \\ F_{\text{Rhorizontal}}=F_{\text{app}}+F_{\text{fric}}=20+(-20)=20-20=0 \end{gathered}[/tex]Being the vertical and horizontal forces 0, the net force is 0 as it has no magnitude and no direction.
It is balanced, since the net force is 0