Given the expression:
[tex]-3x(4x\text{ + 12)}[/tex]Let's simplify the expression by multiplying -3x to each of the terms inside the parenthesis.
We get,
[tex]-3x(4x\text{ + 12)}[/tex][tex](-3x)(4x)\text{ + (12)}(-3x)[/tex][tex](-12x^2)\text{ + (-36x)}[/tex][tex]-12x^2\text{ - 36x}[/tex]Therefore, the simplified form of the given expression is -12x^2 - 36x.
Identify the vertex and sketch the graph.f (x) = -2x 2 - 24x - 72
ANSWER
Vertex = (-6, 0) Option B
Graph:
EXPLANATION
Given:
[tex]f(x)=-2x^2-24x-72[/tex]Desired Outcome:
Vertex and graph
Rewrite the equation in vertex form
[tex]y=a(x-h)^2+k[/tex]where:
(h, k) is the vertex.
Now, determine the vertex of the equation
[tex]\begin{gathered} h=\frac{-b}{2a} \\ h=\frac{-(-24)}{2(-2)} \\ h=\frac{24}{-4} \\ h=-6 \end{gathered}[/tex][tex]k=-\frac{D}{4a}[/tex]Let's determine the value of D
[tex]\begin{gathered} D=b^2-4ac \\ D=(-24)^2-4(-2)(-72) \\ D=576-576 \\ D=0 \end{gathered}[/tex]Now,
[tex]\begin{gathered} k=-\frac{D}{4a} \\ k=-\frac{0}{4(-2)} \\ k=\frac{0}{8} \\ k=0 \end{gathered}[/tex]Therefore, the vertex (h, k) = (-6, 0) and when we plot this on a graph, we have:
Hence, the correct option is B.
Help me with this math and explaining the question solution and quickly and explain it
To find the distance between V1 and the aquarium we can use the formula of the distance between two points in the plane, that is,
[tex]\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \text{ Where }(x_1,y_1)\text{ and }(x_2,y_2)\text{ are the coordinates of the points} \end{gathered}[/tex]So, in this case, we have
[tex]\begin{gathered} V1(-6,5) \\ AQ(5,5) \\ d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt[]{(5-(-6))^2+(5-5)^2} \\ d=\sqrt[]{(5+6)^2+(5-5)^2} \\ d=\sqrt[]{(11)^2+(0)^2} \\ d=\sqrt[]{(11)^2} \\ d=11 \end{gathered}[/tex]Therefore, the distance between v1 and the aquarium is 11 units.
State the domain and range of the relation. Then determine whether the relation is a function, write yes or no.
Solution:
The domain is the set of independent values of a relationfor which the reltion is valid.
The range is the set of dependent values of a relation for which he relation is valid and real
Given:
From the above image, we have
[tex]\begin{gathered} Domain:\text{ -2, 3} \\ Range:\text{ 4, -2, 0, 2} \end{gathered}[/tex]For a relation to be a function, for every value of x there is only one corresponding value for y.
Since the value of domain in the above figure outputs more than one value, the relation is not a function.
Hence, the correct answer is NO
Which equation does the following grid represent? X X XX X XX X X XX X X XX X X A 0.92 - 0.19 = 0.73 OB. 0.73 +0.19 = 0.92 O C. 1.00 - 0.19 = 0.81 O D. 1.00 +0.73 = 1.73
In the Diagram,
We have a box
Total squares: 100
In Red we have= 92 squares
The blank squares= 8
"X" squares = 19
2) Then, Dividing each by 100:
0.92 red -0.19x =0.73 the amount of red squares not marked with an x
A small regional carrier accepted 23 reservations for a particular flight with 20 seats. 14 reservations went to regular customers who will arrive for the flight. each of the remaining passengers will arrive for the flight with a 50 % chance ,independently of each other. Find the probability that overbooking occurs find the probability that the flight has empty seats
Answer:
P(Overbooking) = 0.0898
P(Empty seats) = 0.7461
Explanation:
The probability that overbooking occurs is the probability that arrives more than 6 passengers from the 9 that remain.
This probability can be calculated as:
[tex]P(x)=\frac{n!}{x!(n-x)!}\cdot p^x\cdot(1-p)^{n-x}[/tex]Where n is the total number of remaining passengers, and p is the probability that a passenger will arrive for the flight. So, the probability that x people arrive is:
[tex]P(x)=\frac{9!}{x!(9-x)!}\cdot0.5^x\cdot(1-0.5)^{9-x}[/tex]So, the probability that arrives 7, 8, or 9 people is:
[tex]\begin{gathered} P(7)=\frac{9!}{7!(9-7)!}\cdot0.5^7\cdot(1-0.5)^{9-7}=0.0703 \\ P(8)=\frac{9!}{8!(9-8)!}\cdot0.5^8\cdot(1-0.5)^{9-8}=0.0176 \\ P(9)=\frac{9!}{9!(9-9)!}\cdot0.5^9\cdot(1-0.5)^{9-9}=0.002 \end{gathered}[/tex]Therefore, the probability that overbooking occurs is:
[tex]\begin{gathered} P(\text{Overbooking)}=P(7)+P(8)+P(9) \\ P(\text{Overbooking)}=0.0898 \end{gathered}[/tex]On the other hand, the probability that the flight has empty seats is the probability that arrives fewer than 6 people for the flight.
So, using the same equation for P(x), we get that the probability that the flight has empty sats is:
[tex]\begin{gathered} P(\text{Empty seats)=P(0) +P(1) + P(2) + P(3) +P(4) + P(5)} \\ P(\text{Empty seats) = 0.7461} \end{gathered}[/tex]Therefore, the answers are:
P(Overbooking) = 0.0898
P(Empty seats) = 0.7461
Math help with problems Is this line linear or nonlinear
Answer:
[tex]It\text{ is linear}[/tex]Explanation:
Here, we want to check if the given line is linear or not
From the image shown, the line connects two points on the axes
This connection is in the form of a line segment
Thus, we can confirm that the line is linear
A truck averages 16 miles per yulion and has a 25 gallon gas tank. What is the furthest distance the truck can travel without stopping for gas?
A truck averages 16 miles per gallon and has a 25 gallon gas tank. What is the furthest distance the truck can travel without stopping for gas?
Apply proportion
16/1=x/25
solve for x
x=16*25
x=400 miles
answer is 400 milesIn the figure below, ∠APE and ∠EPD are congruent. What is the arc measure of major arc BAD on circle P in degrees?
You need to determine the measure of the arc BAD in the given circle P.
The angle measure of angle ∠BPD with the vertex in the center of the circle P is congruent to the measure of the intercepted arc BAD.
This means that to determine the measure of the arc, you need to determine the measure of the angle.
The measure of ∠BPD is equal to the sum of the measures of the adjacent angles that form it:
[tex]\angle\text{BPD}=\angle\text{BPA}+\angle\text{APE}+\angle\text{EPD}[/tex]∠APE and ∠EPD have an unknown measure but we know that they are equal, and we know that the total angle of a circle is 360º, i.e. the sum of all the angles is 360º
Let "x" represent the measure of angles ∠APE and ∠EPD, we can represent the total angle of the circle as follows:
[tex]360º=\angle\text{APE}+\angle\text{EPD}+\angle\text{DPC}+\angle\text{CPB}+\angle\text{BPA}[/tex]We know that
∠APE=∠EPD=x
∠DPC=42º
∠CPB=74º
∠BPA=136º
[tex]\begin{gathered} 360º=x+x+42+74+136 \\ 360=2x+252 \\ 360-252=2x \\ 2x=108 \\ \frac{2x}{2}=\frac{180}{2} \\ x=54º \end{gathered}[/tex]So ∠APE=∠EPD=54º
Now that we know the measure of these angles we can calculate the measure of ∠BPD
[tex]\begin{gathered} \angle\text{BPD}=\angle\text{BPA}+\angle\text{APE}+\angle\text{EPD} \\ \angle\text{BPD}=136+54+54 \\ \angle\text{BPD}=244º \end{gathered}[/tex]∠BPD=244º and, as mentioned before the measure of the intercepted arc is the same as the measure of the central angle, then its intercepted arc BAD = 244º as well.
Jerry bought a $78 table on sale for 20% off. The best estimate for the discount can be found using which expression? 0.2(80) 0.2170)
1) Gathering the data
$78 20% off
2) To find the final price Jerry has paid just multiply
78----20%
3) So, the expression used was 78 x (0.8) and Jerry has paid $62.4 for the table
A candy store sells different sized bags of jelly beans. The line plot shows the welghts of ten bags. Weight of Jelly Bean Bags X XXXala x X+CO i colwt inloo - 50 1 Pounds Mikalya bought all of the bags weighing less than 2 pound. How many pounds of jelly beans did Mikalya buy? OA pound pound OB. is pound pound
bags less than 3/8
[tex]\begin{gathered} \frac{1}{4}\longrightarrow2 \\ \\ \frac{1}{8}\longrightarrow1 \end{gathered}[/tex]are 3
to fin the total pounds we multiply each weight by the number of bags
[tex]\begin{gathered} \frac{1}{4}\times2=\frac{1}{2} \\ \\ \frac{1}{8}\times1=\frac{1}{8} \end{gathered}[/tex]now sum
[tex]\begin{gathered} \frac{1}{2}+\frac{1}{8} \\ \\ \frac{(8\times1)+(2\times1)}{8\times2} \\ \\ \frac{8+2}{16} \\ \\ \frac{10}{16}=\frac{5}{8} \end{gathered}[/tex]total weight is 5/8pounds
Find the slope of each.1. (0, 4) and (2, -3)
Answer:
slope = -3.5
Explanation:
The points we have are:
[tex]\begin{gathered} (0,4) \\ (2,-3) \end{gathered}[/tex]We have to label the coordinates as follows:
[tex]\begin{gathered} x_1=0 \\ y_1=4 \\ x_2=2 \\ y_2=-3 \end{gathered}[/tex]And now we use the formula to calculate the slope between the points:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]We substitute the known values:
[tex]m=\frac{-3-4}{2-0}[/tex]And solve the operations to find the slope "m" between the points:
[tex]\begin{gathered} m=\frac{-7}{2} \\ m=-3.5 \end{gathered}[/tex]Answer: slope = -3.5
A punter kicks a football. Its height (h) in meters, t seconds after the kick is givenby the equation: h(t) = -4.912t^2 +18.24t +0.8. The height of an approaching blocker'shands is modeled by the equation: g(t) = -1.43t+4.26, using the same time. Can theblocker knock down the punt? If so, at what time does this happen?
Answer two questions about Equations A and B:Skill SumA. 5 = -2(x - 1)sidesB. 5 = -20 +21) How can we get Equation B from Equation A?Choose 1 answer:a) Rewrite one side (or both) by combining like terms0215b) Rewrite one side for both) using the distributive propertyc) Multiply/divide both sides by the same non-zero constantd) Multiply/divide both sides by the same variable expression Based on the previous answer, are the equations equivalent? In other words,do they have the same solution?
Rewrite one side(or both) by combining like terms
Explanation:
Equation A: 5 = -2(x - 1)
Equation B: 5 = -20 +2
To get Equation B from Equation A, we equate the right sides of both equations since equating the left side give the same answer.
Left side: 5 = 5
Right side: -2(x - 1) = -20 +2
Then we solve:
-2x + 2 = -18
-2x = -18-2
-2x = -20
x = -20/-2
x = 10
To get Equation B from Equation A, we make x = 10
Rewrite one side(or both) by combining like terms
find an equation of the tangent line to the graph of the function at the given point,use a graphing utility to graph the function and its tangent line at the point, anduse the tangent feature of a graphing utility to confirm your results.
The equation of the tangent line may be identified using the first derivative of the function which gives us its slope.
[tex]\begin{gathered} y=\cos3x \\ \\ y^{\prime}=-3\sin3x \\ \\ m=-3\sin3x \\ \\ m=-3\sin3(\frac{\pi}{4}) \\ \\ m=-3(\frac{\sqrt{2}}{2}) \\ \\ m=-\frac{3\sqrt{2}}{2} \end{gathered}[/tex]The tangent line passes through (/4, -√2/2) so we can solve for the y-intercept, b.
[tex]\begin{gathered} y=mx+b \\ \\ -\frac{\sqrt{2}}{2}=-\frac{3\sqrt{2}}{2}(\frac{\pi}{4})+b \\ \\ -\frac{\sqrt{2}}{2}=-\frac{3\pi\sqrt{2}}{8}+b \\ \\ b=-\frac{\sqrt{2}}{2}+\frac{3\pi\sqrt{2}}{8} \\ \\ b=\frac{-4\sqrt{2}}{8}+\frac{3\pi\sqrt{2}}{8} \\ \\ b=\frac{(3\pi-4)\sqrt{2}}{8} \end{gathered}[/tex]So the equation of the tangent line is:
[tex]y=-\frac{3\sqrt{2}}{2}x+\frac{(3\pi-4)\sqrt{2}}{8}[/tex]please see image, use this information to solve the problem.
The coordinates of the point B is,
[tex](56,7)[/tex]There are 130 people at a meeting. Theyeach give a Valentine's Day card toeveryone else. How many cards weregiven?
Permutations
Suppose there are only two people in the meeting. Person A gives a card to person B and vice-versa. Two cards were given.
Now we have 3 people. Person A gives two cards. Person B gives two cards. Person C gives two cards. Total = 6 cards given.
Each people gives a card to everyone else (except themselves, of course) and it's done by everyone in the meeting, thus for 130 people:
130 x 129 = 16,770 cards were given
Identify the term that completes the equation. XZ2=(WZ) (?)Please help
Given triangles, XZW and XZY are right-angle triangles.
Using the Pythagorean theorem for XZW, we get
[tex]XZ^2+WZ^2=WX^2[/tex]Using the Pythagorean theorem for XZY, we get
[tex]XZ^2+XY^2=ZY^2[/tex][tex]XZ^2=ZY^2-XY^2[/tex]Using the Pythagorean theorem for WXY, we get
[tex]WX^2+XY^2=WY^2[/tex][tex]undefined[/tex]which of the following is the solution of the system of equations below? 6x+6y=-6 5x+y=-13
First, we divide the first equation by -6
[tex]\begin{gathered} 6x+6y=-6 \\ -x-y=1 \end{gathered}[/tex]Then, we combine this equation with the second one
[tex]\begin{gathered} 5x-x+y-y=1-13 \\ 4x=-12 \\ x=-\frac{12}{4} \\ x=-3 \end{gathered}[/tex]Now, we use the x-value to find y
[tex]\begin{gathered} 5x+y=-13 \\ 5(-3)+y=-13 \\ -15+y=-13 \\ y=-13+15 \\ y=2 \end{gathered}[/tex]Hence, the solution to the system is (-3, 2).evaluate the expression [tex]2(2 {}^{5)} [/tex]
64
Explanation
[tex]2(2^5)[/tex]Step 1
operate the exponent,so
[tex]\begin{gathered} 2(2^5) \\ 2(2\cdot2\cdot2\cdot2\cdot2) \\ 2(32) \end{gathered}[/tex]Step 2
now, do the multiplication.
[tex]\begin{gathered} 2(32) \\ 64 \end{gathered}[/tex]so, the answer is 64
I hope this helps you
a) y=2xb) y=2x+2c) y= -2x + 2d) y=2x - 2
Answer
Option D is correct.
y = 2x - 2
Explanation
The key to picking the right equation that fits the data in the table is to check each of the options.
Option A
y = 2x
when x = -3,
y = 2x
y = 2(-3)
y = -6
-6 ≠ - 8
Hence, this option is not correct.
Option B
y = 2x + 2
when x = -3,
y = 2x + 2
y = 2(-3) + 2
y = -6 + 2 = -4
-4 ≠ - 8
Hence, this option is not correct.
Option C
y = -2x + 2
when x = -3,
y = -2x + 2
y = -2(-3) + 2 = 6 + 2
y = 8
8 ≠ - 8
Hence, this option is not correct.
Option D
y = 2x - 2
when x = -3
y = 2 (-3) - 2
y = -6 - 2
y = -8
-8 = -8
This is the correct option.
Hope this Helps!!!
the length of one leg of a right triangle is 15 m. The length of the other leg is 9 m shorter than the length of the hypotenuse. Find the length of the hypotenuse.
Let the hypotenuse is x
The length of the other leg is 9 m shorter than the length of the hypotenuse
The length of second leg = Hypotenuse - 9
The length of second leg = x - 9
the length of one leg of a right triangle is 15 m.
The first leg = 15m
Pythagoras Theorem : In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides
Apply pythagoras for the value of x :
[tex]\begin{gathered} \text{ Hypotenuse}^2=Base^2+Perpendicular^2 \\ x^2=15^2+(x-9)^2 \\ x^2=225+x^2+81-18x \\ x^2-x^2=225+81-18x \\ 18x=306 \\ x=\frac{306}{18} \\ x=17 \end{gathered}[/tex]as x represent the hypotnuese, SO
Hypotenuse = 17m
Analyzing rays and segments which statements are true regarding the diagram check all that apply
It can be observed that point C and point B does not lie on the line n, so CB is not contained in line n.
The point C and point E lie on the line m, so CE is contained on the line m.
The ray BC has start point as B , where as ray CB has start point as C. So ray BC and ray CB are different.
The ray AD and ray AC both has same starting point A, where as end point of both ray AD and AC is collinear. So ray AD is same as ray AC.
The angle EAD is formed by the ray AE and ray AD. The statement angle EAD is created from AE and DA is wrong as ray DA is different from AD.
The angle ECB is created by the ray CE and ray CB with common vertex at C. So statement angle ECB is created from ray CE and CB is correct.
Answer:
Correct statements are,
CE is contained on line m.
Ray AD is same as ray AC.
Angle ECB is created from ray CE and ray CB.
_____ ______ ______says that people are able to decide what to buy and how much they are willing and able to pay depending on the satisfaction they receive from the service/product.
Decision makers say that people can decide what to buy and how much they are willing and able to pay depending on the satisfaction they receive from the service/product.
What is meant by decision maker?A decision maker is a person or group in charge of making crucial strategic decisions based on a variety of factors, such as the amount of time available, the resources at hand, the type and quality of information at hand, and the number of interested parties.
According to those who make decisions, consumers can choose what they want to buy and how much they are willing and able to pay based on how satisfied they are with the service or product.
Making decisions is crucial because it allows you to select from a variety of options. It is important to gather all available information and consider the advantages and disadvantages of it before making a decision. It is imperative to concentrate on actions that can assist in making the best decisions.
To learn more about decision maker refer to:
https://brainly.com/question/1249089
#SPJ1
The figure below shows a juice box in the shape for a rectangular prism
(a)
Given the dimensions of the rectangular prism l = 7 cm, w = 2 cm, h = 8 cm, the surface area of a rectangular prism can be computed using the equation
[tex]SA=2(wl+hl+hw)[/tex]Substitute the values on the equation above and compute, we get
[tex]SA=2\lbrack(2cm\times7cm)+(8cm\times7cm)+(8cm\times2cm)\rbrack=172cm^2[/tex]The volume of the rectangular prism can be computed using the equation
[tex]V=l\times w\times h[/tex]Plug in the values on the equation above and compute, we get
[tex]V=(7cm)\times(2cm)\times(8cm)=112cm^3[/tex](b) For the amount of juice inside the rectangular prism, we will use volume.
(c) For the amount of coating of wax for the box, we will use surface area.
2(x+9)=2x+18What is the Name of the property listed above -commutative property of addition-commutative property of multiplication -Associative property of addition -Associative property of multiplication -Distributive property -additive identity -Multiplication identity -Zero property of multiplication-Multiplication property of -1 -none of the above.
Distributive property
Explanation:Given:
[tex]2(x+9)\text{ = 2x + 18}[/tex]To find:
the name of the property stated
[tex]\begin{gathered} 2(x\text{ + 9\rparen = 2\lparen x\rparen + 2\lparen9\rparen} \\ \\ The\text{ form above is the same as:} \\ a(b\text{ + c\rparen = }a(b)\text{ + a\lparen c\rparen} \\ This\text{ is known as distributive property.} \end{gathered}[/tex][tex]\begin{gathered} 2(x)\text{ + 2\lparen9\rparen = 2x + 18} \\ \\ Hence,\text{ 2\lparen x + 9\rparen = 2x + 18 is a distributive property} \end{gathered}[/tex]What is the distance between the points (-9, 4) and (3,-12)? A 12 units B. 16 units c. 20 units D. 28 units
Answer:
C
Step-by-step explanation:
calculate the distance d using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = (- 9, 4 ) and (x₂, y₂ ) = (3, - 12 )
d = [tex]\sqrt{(3-(-9))^2+(-12-4)^2}[/tex]
= [tex]\sqrt{(3+9)^2+(-16)^2}[/tex]
= [tex]\sqrt{12^2+256}[/tex]
= [tex]\sqrt{144+256}[/tex]
= [tex]\sqrt{400}[/tex]
= 20 units
Which of the following division problems CANNOT be completed?
155 ÷ (-3)
10 ÷ 0
0 ÷ 5
⅔ ÷ ¼
Answer:
I think the first one
but if it's a multiple choice answer then the second and third
Step-by-step explanation:
I was gonna say 0 and 5 because since in algebra you can't divide anything with 0 and you can divide the last one
Choose all that give the correct effect on the linear graph of the parent function ƒ(x).f(x) is replaced with f(x) + 5 shifts the line 5 units upf(x) is replaced with f(x − 8) shifts the line 8 units leftf(x) is replaced with 4f(x) stretch vertically by a factor of 4f(x) is replaced with f(3x) compress horizontally by a factor of 1/3
Since the parent function is f(x), then
f(x) + 5 is the shifted 5 units up of f(x)
Then the first answer is correct
f(x - 8) is shifted 8 units right of f(x)
Then the second answer is wrong
f(x) is replaced by 4f(x) means it stretched vertically by a factor of 4
Then the third answer is correct
f(x) is replaced by f(3x) means it compressed horizontally by a scale factor of 1/3
Then the fourth answer is correct
A sales person is given a choice of two salary plans. Plan 1 is weekly salary of $600 plus 2 percent commission of sales. Plan 2 is a straight commission of 10% of sales. How much in sales must he make in a week for both plans to result in the same salary?
Answer:
He must make $7,500 in sale
Step-by-step explanation:
Let's say:
s = amount make in sales per week
P1 = weekly salary of Plan 1
P2 = weekly salary of Plan 2
P1 and P2 can be expressed using the fixed amount plus the commission.
P1 = 600 + 0.02s
P2 = 0 + 0.1s
P2 = 0.1s
If both plans result in the same salary:
P1 = P2
600 + 0.02s = 0.1s
0.1s - 0.02s = 600
0.08s = 600
s = 600/0.08
s = $7,500
how to answer this system of equations using cramer's rule
Given:
Given the system of equations:
[tex]\begin{gathered} c+w+p=456 \\ c-p=80 \\ p=2w-2 \end{gathered}[/tex]Required: Solution of the system using Cramer's rule
Explanation:
The system of equations can be rewritten as
[tex]\begin{gathered} c+p+w=456 \\ c-p+0w=80 \\ 0c+p-2w=-2 \end{gathered}[/tex]Write down the augmented matrix.
[tex]\begin{bmatrix}{1} & {1} & {1} & {456} \\ {1} & {-1} & {0} & {80} \\ {0} & {1} & {-2} & {-2} \\ {} & {} & {} & {}\end{bmatrix}[/tex]Calculate the main determinant.
[tex]\begin{gathered} D=\det\begin{bmatrix}{1} & {1} & {1} \\ {1} & {-1} & {0} \\ {0} & {1} & {-2}\end{bmatrix} \\ =1\left(2-0\right)-1\left(-2-1\right) \\ =2+3 \\ =5 \end{gathered}[/tex]Substitute the c-column with RHS and find the determinant.
[tex]\begin{gathered} D_c=\det\begin{bmatrix}{456} & {1} & {1} \\ {80} & {-1} & {0} \\ {-2} & {1} & {-2}\end{bmatrix} \\ =456\left(2-0\right)-80\left(-2-1\right)-2\left(0+1\right) \\ =912+240-2=1150 \end{gathered}[/tex]Substitute the p-column with RHS and find the determinant.
[tex]\begin{gathered} D_p=\det\begin{bmatrix}{1} & {456} & {1} \\ {1} & {80} & {0} \\ {0} & {-2} & {-2}\end{bmatrix} \\ =1(-160-0)-1(-912+2) \\ =-160+910 \\ =750 \end{gathered}[/tex]Substitute the w-column with RHS and find the determinant.
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