I need help with this practice I am having trouble with it The subject is trig

I Need Help With This Practice I Am Having Trouble With It The Subject Is Trig

Answers

Answer 1

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given range

[tex](-\infty,-9\rbrack\cup\lbrack5,\infty)[/tex]

STEP 2: Find the cosecant function

[tex]\begin{gathered} \text{The range of a cosecant function normally excludes the interval }(-1,1)\text{.} \\ The\text{ range in the question excludes the interval }(-9,5)\text{, which has a width 7 times as great.} \\ \text{Thus, we know the vertical factor is 7.} \\ \\ T\text{he midpoint of the excluded interval of the given function is }\frac{(-9+5)}{2}=-\frac{4}{2}=-2 \\ so\text{ that is the vertical translation.} \\ \text{The cosecant function normally has vertical asymptotes at }x=0\text{ and }x=\pi\text{ so the function is } \\ \text{expanded horizontally by a factor of }2. \end{gathered}[/tex]

Hence, the cosecant function is

[tex]undefined[/tex]


Related Questions

f(x) = x^2 - 8x + 7Find the vertexaxis of symmetrygraph itfind the domainfind the range

Answers

Answers:

Vertex: (4, -9)

axis of symmetry: x = 4

Domain: (-∞, ∞)

Range: [-9, ∞)

Explanation:

If we have a quadratic function with the form y = ax² + bx + c, the x-coordinate of the vertex will be at x = -b/2a

So, for f(x) = x² - 8x + 7, we get a = 1, b = -8 and c = 7, then the x-coordinate of the vertex will be:

[tex]x=\frac{-(-8)}{2(1)}=\frac{8}{2}=4[/tex]

Then, the y-coordinate will be the value of f(x) when x = 4

[tex]\begin{gathered} f(x)=x^2-8x+7 \\ f(4)=4^2-8(4)+7 \\ f(4)=16-32+7 \\ f(4)=-9 \end{gathered}[/tex]

Therefore, the vertex of the equation is the point (x, y) = (4, -9).

The axis of symmetry is located in the vertex, since the parabola opens up, the axis of symmetry is the vertical line x = 4.

To graph the function, we need to find some points before and after the vertex. So, we will give values to x as 2, 3, 5, and 6. Then, we can calculate f(x) as:

[tex]\begin{gathered} f(2)=2^2-8(2)+7=4-16+7=-5 \\ f(3)=3^2-8(3)+7=9-24+7=-8 \\ f(5)=5^2-8(5)+7=25-40+7=-8 \\ f(6)=6^2-8(6)+7=36-48+7=-5 \end{gathered}[/tex]

So, to graph the function, we will use the points (2, -5), (3, -8), (5, -8), (6, -5) and the vertex (4, -9). Therefore, the graph is:

Finally, the domain is the set of values that the variable x can take. In this case, x can be any number, so the domain is the set of all real numbers or written as an interval

(-∞, ∞)

And the range is the set of all values that f(x) can take. In this case, f(x) is always greater than -9, so the range is the set [-9, ∞)

1 Find the area of the triangle given below and type your result in the empty box. 19 cm 15 cm 12 cm

Answers

We have a right triangle with sides 12 cm, 15 cm and 19 cm.

The area of the triangle is half the product of the legs, as they represent the base and height of the triangle:

[tex]A=\frac{b\cdot h}{2}=\frac{12\cdot15}{2}=6\cdot15=90\operatorname{cm}^2[/tex]

NOTE: The legs are the shortest sides that form the right angle of the triangle.

Answer: the area of the triangle is 90 cm^2

Statistics approximating the mean of a data set given a frequency distribution

Answers

Solution

- The mean formula is given as:

[tex]\begin{gathered} \bar{x}=\sum_{i=1}^n\frac{fix_i}{f_i} \\ \\ where, \\ x_i=\text{ The ith data point} \\ f_i=\text{ The frequency of the ith data point} \end{gathered}[/tex]

- Thus, we can find the mean as follows:

[tex]\begin{gathered} \text{ We have been told to use the midpoint of the classes. Thus, we can say:} \\ x_i=\lbrace3,8,13,18,23,28\rbrace \\ fi=\lbrace22,21,15,9,4,3\rbrace \\ \\ \text{ Thus, the mean commute distance for students is:} \\ \bar{x}=\frac{3(22)+8(21)+13(15)+18(9)+23(4)+28(3)}{22+21+15+9+4+3} \\ \\ \bar{x}=\frac{767}{74} \\ \\ \bar{x}=10.36486486...\approx10.4\text{ \lparen To 1 decimal place\rparen} \end{gathered}[/tex]

Final Answer

The mean distance is 10.4 miles

Jason owns a small business selling bagels. He knows that in the last week 45
customers paid cash,
8 customers used a debit card, and 6 customers used a credit a
card.
Based on these results, express the probability that the next customer will pay with a
credit card as a decimal to the nearest hundredth.

Answers

The probability that the next customer will pay with a credit card is given by 0.10 approximately.

Given that 8 customers used a debit card and 6 customers used a credit card and 45 customers paid cash.

So the total number of customers = 6+8+45 = 59

The number of customers paid in credit card = 6

Hence the probability that the next customer will pay with a credit card = 6/59 = 0.10 (approximately)

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blake needed at least 225 votes to become president of his seventh-grade class. if three-fourths of the seventh-grade students voted for him and he won. how many seventh-grade students could there be?im looking for the inequality and answer. thank you.

Answers

Given :

The number of votes to win is at least 225 votes

three-fourths of the seventh-grade students voted for him and he won.

Let the number of students = x

So, the inequality will be:

[tex]\frac{3}{4}x\ge225[/tex]

Solve the inequality :

Multiply both sides by 4/3

[tex]undefined[/tex]

Which of the following is equal to the rational expression when x + 1 or -1? 5(x-1) (x + 1)(x-1)

Answers

Answer

Option A is correct.

[tex]\frac{5}{(x+1)}[/tex]

Explanation

We can see that the numerator and the denominator both contain (x - 1).

Hence, that expression cancels out and we are left with

5/(x + 1)

Hope this Helps!!!

Two times x, minus the quantity 7 times y, equals 20

Answers

In order to determine the associated algebraic equation of the given statement, you consider part by part.

Two times x: 2x

minus the quantity 7 times y: - 7y

equals 20: = 20

Which is equivalent to:

2x - 7y = 20

6. The line in each graph represente y = 2x Which grach represents 2> y?

Answers

Given the following question:

Which graph represents 2 > y

Both equations are graphed as follows

Since the sign is not less than or equal to it won't be a red line, but a dotted red line.

Your answer is option C.

Sally test grades in English and 75 and 80 what grade must she get on her next test so the average is in 85?

Answers

Explanation

We are told that Sally scored 75 and 80 on two English tests

We are then asked to determine the next grade she must have so that the average becomes 85

Thus

let the third grade be x

Hence

The total grades of the three tests will be

[tex]75+80+x[/tex]

The average of the three tests will be

[tex]\frac{75+80+x}{3}[/tex]

Since the average is 85, then we will have

[tex]\frac{75+80+x}{3}=85[/tex]

We can now solve for x

[tex]\begin{gathered} 75+80+x=3\times85 \\ 155+x=255 \\ x=255-155 \\ x=100 \end{gathered}[/tex]

Thus, she must score 100 on her third test

solve triangles using law of sines , please show work thank you so much! find m

Answers

By Sine Rule,

[tex]\frac{b}{\sin B}=\frac{a}{\sin A}[/tex]

Where b=14, a=12, sinA = sin57 and sinB = ?

[tex]\begin{gathered} \frac{14}{\sin B}=\frac{12}{\sin 57} \\ \text{Cross multiply to get} \end{gathered}[/tex][tex]\begin{gathered} 12\sin B=14\sin 57 \\ \\ \sin B=\frac{14\sin 57}{12}=\frac{14\times0.83867}{12}=0.978449 \end{gathered}[/tex][tex]B=\sin ^{-1}(0.978449)=78.08\approx78^o[/tex]

Express tante in terms of sec e for ein Quadrant I.

Answers

Explanation:

We would be applying the trigonometry identity that shows thr=e relationship between tanθ and secθ:

[tex]\sec ^2\theta=tan^2\theta\text{ + 1}[/tex]

we make tanθ the subject of formula:

[tex]\begin{gathered} \text{subtract 1 from both sides:} \\ \sec ^2\theta-1=tan^2\theta\text{ + 1}-1 \\ \sec ^2\theta-1=tan^2\theta\text{ } \\ \text{square root both sides:} \\ \sqrt[]{\sec ^2\theta-1)}\text{ =}\sqrt[]{tan^2\theta\text{ }} \end{gathered}[/tex]

. Your friend has 2 credit cards with balances that he cannot afford to pay off all at once. A $500 balanceon a card with 15.99% APR and a $400 card with a 25.99% APR.2. Calculate the monthly finance charges for each credit card. (round to the hundredths place)

Answers

[tex]Monthly\text{ }finance=principal*\frac{APR}{12}[/tex]

A $500 balance on a card with 15.99% (0.1599) APR:

[tex]\begin{gathered} Monthly\text{f}\imaginaryI nance=500*\frac{0.1599}{12} \\ \\ Monthly\text{f}\imaginaryI nance=6.66 \end{gathered}[/tex]

A $400 card with a 25.99% (0.2599)APR:

[tex]\begin{gathered} Monthly\text{f}\mathrm{i}nance=400*\frac{0.2599}{12} \\ \\ Monthly\text{f}\mathrm{i}nance=8.66 \end{gathered}[/tex]

Then, the monthly finance charge is: $6.66 for first credit card and $8.66 for second credit card

Anthony is a waiter at a restaurant. Each day he works, Anthony will make a
guaranteed wage of $35, however the additional amount that Anthony earns from
tips depends on the number of tables he waits on that day. From past experience,
Anthony noticed that he will get about $7 in tips for each table he waits on. How
much would Anthony expect to earn in a day on which he waits on 20 tables? How
much would Anthony expect to make in a day when waiting on t tables?
Total earnings with 20 tables:
Total Earnings with t tables:

Answers

Answer:

His guaranteed wage is 35$, and he makes 7$per each table, so 7$*table.

1) if he waits on t (tables)= 20 --> 35$+7*20

so he makes 35$+140$= 175$

2) t tables: 35$+7*t

Solve for x. x + 58 , x + 128

Answers

given angels are x+58 and x+128.

The sum of the angles in the straight line is 180 degree.

thus,

[tex]\begin{gathered} x+58+x+128=180 \\ 2x+186=180 \\ 2x=180-186 \\ 2x=-6 \\ x=-\frac{6}{2} \\ x=-3 \end{gathered}[/tex]

subsitute x =-3 in the equations,

[tex]\begin{gathered} =x+58 \\ =-3+58 \\ =55^{\circ} \end{gathered}[/tex]

Also,

[tex]\begin{gathered} =x+128 \\ =-3+128 \\ =125^{\circ} \end{gathered}[/tex]

thus, the angles are 55 and 125 degrees.

Find the greatest number that divides 30 and 60 without leaving a remainder.

Answers

The greatest number that divides 30 and 60 without leaving a remainder is its GCF.

Find the GCF of 30 and 60 by listing their factors. We get the following:

The factors of 30 are: 1, 2, 3, 5, 6, 10, 15, 30

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

Since the greatest common factor of the two numbers is 30, then the greatest number that divides 30 and 60 without remainder is 30.

11 less than 4G leaves 37 translate into an expression

Answers

In order to translate the phrase into an expression we need to divide it into 2 sections, the first part states 11 less than 4G, then,

[tex]4G-11[/tex]

the second part states the result, then, we need to add an equal sign

[tex]4G-11=37[/tex]

Answer:

[tex]4G-11=37[/tex]

A randomly generated list of integers from 1 to 5 is being used to simulate anevent, with the numbers 1, 2, 3, and 4 representing a success. What is theestimated probability of a success?

Answers

The theoretical probability is defined as the ratio of the number of favourable outcomes to the number of possible outcomes.

The randomly generated list has the numbers from 1 to 5, therefore, the total amount of elements is 5, which is the number of possible outcomes.

Our event consists of choosing from this list any of the numbers from 1 to 4, which is a total of 4 elements, which represents the number of favourable outcomes.4

Their ratio is:

[tex]\frac{4}{5}[/tex]

Rewritting this ratio as a percentage, we have:

[tex]\frac{4}{5}=\frac{80}{100}=80\%[/tex]

The answer is option B.

Name the ordered pair for a fourth point. Q. so that points P.Q.R. and S will be the vertices of a Given: Points P6.-1), R(0.-1) and S(4.-5) rectangle Response

Answers

to find Q we need to make 2 distance measure

that they fulfill these conditions

PS=RQ and RS=QP

the formula of distances between 2 points is

[tex]\sqrt[]{(x2-x1)^2+(y2-y1)^2}[/tex]

Distance PS

[tex]\begin{gathered} \sqrt[]{(6-4)^2+(-1-(-5))^2} \\ \\ PS=\sqrt[]{20} \end{gathered}[/tex]

Distance RQ

[tex]\begin{gathered} \sqrt[]{(0-x)^2+(-1-y)^2} \\ \\ RQ=\sqrt[]{x^2+(1+y)^2} \end{gathered}[/tex]

where x and y are de coordinates of Q

Distance RS

[tex]\begin{gathered} \sqrt[]{(0-4)^2+(-1-(-5))^2} \\ \\ RS=\sqrt[]{32} \end{gathered}[/tex]

Distance QP

[tex]\begin{gathered} \sqrt[]{(x-6)^2+(y-(-1))^2} \\ \\ QP=\sqrt[]{(x-6)^2+(y+1)^2} \end{gathered}[/tex]

now solve the equals

PS=RQ

[tex]\begin{gathered} \sqrt[]{20}=\sqrt[]{x^2+(1+y)^2} \\ 20=x^2+(1+y)^2 \end{gathered}[/tex]

RS=QP

[tex]\begin{gathered} \sqrt[]{32}=\sqrt[]{(x-6)^2+(y+1)^2} \\ 32=(x-6)^2+(y+1)^2 \end{gathered}[/tex]

if I subtract the two equations I will get

[tex]32-20=(x-6)^2-x^2[/tex]

and i will solve to find x

[tex]\begin{gathered} 12=-12x+36 \\ 12x=36-12 \\ x=\frac{24}{12} \\ \\ x=2 \end{gathered}[/tex]

the value of x is 2, then I can replace x on any equation to find y

so replacing

[tex]\begin{gathered} 20=x^2+(1+y)^2 \\ 20=(2)^2+y^2+2y+1 \\ y^2+2y+1-20+4=0 \\ y^2+2y-15=0 \end{gathered}[/tex]

use factor to solve y

[tex]\begin{gathered} y=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \\ y=\frac{-2\pm\sqrt[]{4+60}}{2} \\ \\ y=\frac{-2\pm8}{2} \\ \\ y=-1\pm4 \end{gathered}[/tex]

then y will have two values

[tex]\begin{gathered} y_1=-1+4=3 \\ y_2=-1-4=-5 \end{gathered}[/tex]

the real coordinate is y=3 because if is y=-5 the point dont form a rectangle

if x=2 and y=3 the point Q is (2,3)

Write a coordinate rule for the composition

Answers

The coordinate rule for the composition is (x,y) → (y/4, -x/4).

What is coordinate plane rule?

Rules for the coordinate plane are as follows: (x, y) → (x ± h, y ± k) , where h and k are the horizontal and vertical shifts. Recall that h is negative if movement is to the left. K is negative if movement is down.

The coordinate of the vertices of △LMN are L(4,8), M(8, 8), and N(16, 4).

The coordinate of the vertices of △QRS are Q(2,-1), R(2, -2), and S(1, -4).

Assume that the vertices of △LMN is represented by (x, y).

Then the vertices of △QRS can get by (y/4, -x/4).

The coordinate rule for the composition is (x, y) → (y/4, -x/4).

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I need to determine the length in feet of arc BC?? Is my answer correct?

Answers

l= π/2

1) To find out the length of the arc BC with a central angle ∠BAC, we'll use the following formula:

[tex]l=\frac{\alpha}{360}\cdot2\pi r[/tex]

2) Now we can plug into that the given data, considering that ∠ BAC is a central angle then we can affirm:

[tex]m\widehat{BC}=m\angle BAC[/tex]

So we can plug into the formula below 45º as the angle of that arc, as it follows:

[tex]\begin{gathered} l=\frac{\alpha}{360}\cdot2\pi r \\ l=\frac{45}{360}\cdot2\pi\cdot2 \\ l=\frac{1}{2}\pi\text{ or }\frac{\pi}{2} \end{gathered}[/tex]

3) Hence, as we can see the answer is the l= π/2

Find the measure of each angle in the proplem RE contains point P

Answers

In the given figure, line LP is lie on the line RE, thus from the linear property

Angle LPR + Angle LPE = 180°

It is given that Angle LPR = 3z, angle LPE = 2z

Angle LPR + Angle LPE = 180°

3z° + 2z° = 180°

5z° = 180°

z = 180/5

z=36

Substitute the value of z = 36 in the angle LPR;

Angle LPR = 3z

= 3(36)

=108°

Angle LPE = 2z

= 2(36)

= 72°

Answer : B) 108 and 72

Dean is on top of a 300 m high cliff. He sees Emily in her new sailboat. If dean calculates the angle of depression to the boat to be 25° how far from the base of the cliff is Emily’s boat

Answers

To answer this question we will use the following diagram as reference:

Let d be the distance from the base of the cliff to Emily's boat, then, from the above diagram we can set the following equation:

[tex]\tan 25º=\frac{300m}{d}\text{.}[/tex]

Then:

[tex]d=\frac{300m}{\tan 25º}\text{.}[/tex]

Simplifying the above result we get:

[tex]d\approx643.35m[/tex]

Answer:

[tex]643.35m[/tex]

i’m a survey 49 peaiple revived a flu vaccine before the flu season and 63 people did not revive the vaccine

Answers

Using the information provided:

Let:

V = Number of people who received the vaccine before the flu

NV = Number of people who didn't receive the vaccine before the flu

F = Number of people who got flu

NF = Number of people who didn't get flue

Can you show the steps in how to solve it

Answers

To break even, the equations must satisfy that

[tex]C(x)=R(x)\text{.}[/tex]

Substituting the explicit form of the equations, we get:

[tex]50x+1600=66x\text{.}[/tex]

Subtracting 50x, we get:

[tex]\begin{gathered} 50x+1600-50x=66x-50x, \\ 1600=16x\text{.} \end{gathered}[/tex]

Dividing by 16, we get:

[tex]\begin{gathered} x=\frac{1600}{16}, \\ x=100. \end{gathered}[/tex]

Answer:

[tex]100\text{ units.}[/tex]

Here is a pattern of squares. S represents the number of small squares in the pattern as a function on n, the step number. Hint: create a table and use your graphing calculator. Step 1 Step 2 Step 3 Step 4 Which expression could define S? n²+3 n +3 n²+2 3n

Answers

In the given figure :

Step 1 has 3 square, step 2 has 6 number of square

step 3 has 11 number of squares

step 4 has 18 number of squares

So, the sequence is 3, 6, 11, 18

As we can see that the figure makes a complete square and two more squares

So the expression will be :

[tex]n^2+2[/tex]

Answer : C)

[tex]n^2+2[/tex]

write a linear equation that passes through the points (3,1) and (-2,6)

Answers

The general equation of a line is

[tex]y=mx+b[/tex]

where m is the slope and b the y-intercept

we can find m by the formula

[tex]m=\frac{y2-y1}{x2-1}[/tex]

where (x2,y2) is a right point of (x1,y1) then if we replace the point of the exercise we can find the slope of the line

[tex]\begin{gathered} m=\frac{1-6}{3-(-2)} \\ \\ m=\frac{-5}{5}=-1 \end{gathered}[/tex]

value of the slope is -1

now to find y-intercept or b we replace the slope and a point of the line on the general equation

for example i will use (3,1)

[tex]\begin{gathered} y=mx+b \\ (1)=(-1)(3)+b \\ 1=-3+b \\ b=1+3 \\ b=4 \end{gathered}[/tex]

no we can replace the slope -1 and b 4 on the general equation to have the equation of the line to the exercise

[tex]\begin{gathered} y=-x+4 \\ \end{gathered}[/tex]

120 lb to 180 lb increase or decrease

Answers

We are asked to find out whether 120 lb to 180 lb is an increase or decrease​?

Since the final amount (180 lb) is greater than the initial amount (120 lb) the difference will be positive.

A positve difference indictes an increase.

[tex]difference=180\: lb-120\: lb=60\: lb[/tex]

Therefore, the difference is positive (that is 60 lb) and it is an increase.

Write a compound inequality for the graph shown below.Use x for your variable.++><++-10-9-8-7-65 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 x0Dand<>D400 050 020XC

Answers

STEP - BY - STEP EXPLANATION

What to do?

Write the compound inequality of the given graph.

Given:

Step 1

Determine the two inequality separately.

[tex]x\ge4[/tex][tex]x<6[/tex]

Step 2

Combine the two inequalities

[tex]4\leq x<6[/tex]

ANSWER

The compound inequality is

4≤x < 6

What is an equation of the line that passes through the points (-1, -6), (6,1)?

Answers

Answer:

y = x - 5

Explanation:

Given:

The points are (-1, -6) and (6, 1)

To find:

the equation of line that pass through the points

To determine the equation of the line, it will be in the form:

[tex]\begin{gathered} y\text{ = mx + b} \\ m\text{ = slope, b = y-intercept} \end{gathered}[/tex]

The slope formula is given as:

[tex]$$m\text{ = }\frac{y_2-y_1}{x_2-x_1}$$[/tex][tex]\begin{gathered} x_1=-1,y_1=-6,x_2=6,y_2\text{ = 1} \\ m\text{ = }\frac{1-(-6)}{6-(-1)} \\ m\text{ = }\frac{1+6}{6+1}=\text{ }\frac{7}{7} \\ m\text{ = 1} \end{gathered}[/tex]

To get the y-intercept, we will use any of the given points and the slope

[tex]\begin{gathered} Using\text{ point \lparen6, 1\rparen: x = 6, y = 1} \\ y\text{ = mx + b} \\ 1\text{ = 1\lparen6\rparen + b} \\ 1\text{ = 6 + b} \\ 1-6\text{ = b} \\ b\text{ = -5} \end{gathered}[/tex]

Next substitute the slope and y-intercept

[tex]\begin{gathered} y\text{ = 1\lparen x\rparen + \lparen-5\rparen} \\ \\ The\text{ equation od the line becomes:} \\ y\text{ = x - 5} \\ \end{gathered}[/tex]

A car wash uses 59 gallons of water every 40 seconds how much water does it use per second

Answers

Answer: 1.475 gallons a second

Step-by-step explanation:

just divide 59/40 and you get your answer for this question

Answer:

1.475

Step-by-step explanation:

59÷40

40 seconds =59

1 seconds=x

c.m

59×1=40x

59÷40

=1.475

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