1 금35Lolo19.Which type of variation is modeled in the table?jointdirectcombinedInverse

1 35Lolo19.Which Type Of Variation Is Modeled In The Table?jointdirectcombinedInverse

Answers

Answer 1

The answer to your question is inverse varaiation.

Explanation: Inverse variation is a reciprocal term. Or say a variable is increasing while the other is decreasing.

So it is observed that as when y increases, then x decreases.

And also when y decreases, then x increases.

Thus, It is an inverse variation.


Related Questions

List the coordinates coordinates of vertices of trapezoid ABCD after it has been rotated 90 Counterclockwise bout the origin and then reflected over the x-axis. A(-5,-3) B(-4,0),c(-2,0),D(O,-3)

Answers

Answer:

The coordinates of the final image is;

[tex]A^{\prime\prime}(3,5),B^{\prime\prime}(0,4),C^{\prime}^{\prime}(0,2),D^{\prime}^{\prime}(3,0)[/tex]

Explanation:

From the question, the pre-image was been rotated 90 Counterclockwise bout the origin.

Which has a rule;

[tex](x,y)\rightarrow(-y,x)[/tex]

Applying the rule to the given points. we have;

[tex]\begin{gathered} A(-5,-3)\rightarrow A^{\prime}(3,-5) \\ B(-4,0)\rightarrow B^{\prime}(0,-4) \\ C(-2,0)\rightarrow C^{\prime}(0,-2) \\ D(0,-3)\rightarrow D^{\prime}(3,0) \end{gathered}[/tex]

Then the produced image was then reflected over the x-axis;

Reflection across the x-axis have the rule;

[tex](x,y)\rightarrow(x,-y)[/tex]

Applying the rule to the resulting image;

[tex]\begin{gathered} A^{\prime}(3,-5)\rightarrow A^{\prime^{}}^{\prime}(3,5) \\ B^{\prime}(0,-4)\rightarrow B^{\prime}^{\prime}(0,4) \\ C^{\prime}(0,-2)\rightarrow C^{\prime^{}}^{\prime}(0,2) \\ D^{\prime}(3,0)\rightarrow D^{\prime}^{\prime}(3,0) \end{gathered}[/tex]

Therefore, the coordinates of the final image is;

[tex]A^{\prime\prime}(3,5),B^{\prime\prime}(0,4),C^{\prime}^{\prime}(0,2),D^{\prime}^{\prime}(3,0)[/tex]

find the area of a hexagon with sides 20 mm long. Round your answer to the nearest tenth

Answers

When you know the length of the sides of a hexagon you use the next formula to find its area:

[tex]A=\frac{3\sqrt{3}}{2}s^2[/tex]

s is the length of the sides

For the given hexagon:

[tex]\begin{gathered} A=\frac{3\sqrt{3}}{2}(20mm)\placeholder{⬚}^2 \\ \\ A=\frac{3\sqrt{3}}{2}(400mm^2) \\ \\ A=3\sqrt{3}(200mm^2) \\ \\ A=600\sqrt{3}mm^2 \\ \\ A\approx1039.2mm^2 \end{gathered}[/tex]Then, the area of the given hexagon is 1039.2 square millimeters

Large balloons are sold in packages of 12. Select the expressions that can represent the total number of balloons in p packages of largeballoonsA 12-PB. 12*pC. P+12D. P-12E 12p

Answers

Since each package has 12 balloons if we buy p packages the total number of ballons will be given by tha multiplication of 12 by p, that is:

[tex]12p[/tex]

Therefore the answer is B and E.

I need help with this problem. Please show work and simplify the answer!

Answers

[tex]\frac{2}{3}\times\frac{5}{6}\times\frac{14}{1}=[/tex][tex]\frac{10}{18}\times\frac{14}{1}=[/tex][tex]\frac{140}{18}=\frac{70}{9}[/tex]

PLEASE HELP!!!!! I WILL GIVE BRAINLIEST!!!!

Evaluate the expression . Write your answer as a simplified mixed number, or as a decimal. Show your work

Answers

Answer:

[tex]-3\frac{15}{16}[/tex]

Step-by-step explanation:

Given:

[tex](-\frac{1}{4}+2.875)\div(-\frac{2}{3})[/tex]

First, convert 2.875 to an improper fraction:

[tex]2.875=2\frac{875}{1000}=2\frac{7}{8}=\frac{23}{8}[/tex]

The expression becomes:

[tex](-\frac{1}{4}+\frac{23}{8})\div(-\frac{2}{3})[/tex]

Then, add the terms in the parentheses:

[tex]-\frac{1}{4}+\frac{23}{8}=-\frac{2}{8}+\frac{23}{8}=\frac{21}{8}[/tex]

The new expression is:

[tex]\frac{21}{8}\div-\frac{2}{3}[/tex]

Dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second fraction. Therefore:

[tex]\frac{21}{8}\times-\frac{3}{2}[/tex]

Next, multiply the numerators and denominators:

[tex]-\frac{63}{16}[/tex]

Finally, simplify to a mixed fraction:

[tex]-3\frac{15}{16}[/tex]

Hello! I need some help with this homework question, please? I just need help with C or D Q2

Answers

[tex]The\: domain\: of\: f\circ f\: is\: all\: Real\: numbers[/tex]

C) Considering that f(x)=x² we can write the composite function f(f(x)) y plugging into the x-variable the function f(x) itself:

[tex]\begin{gathered} f(f(x)) \\ f\mleft(x\mright)=x^2 \\ f(f(x))=(x^2)^2 \\ f(f(x))=x^4 \end{gathered}[/tex]

Now, let's find the Domain. Considering that this is a polynomial function that has no restraints nor discontinuity we can write out the following:

[tex]\begin{gathered} The\: domain\: of\: f\circ f\: is\: all\: Real\: numbers \\ D=\: \mleft(-\infty\: ,\: \infty\: \mright) \end{gathered}[/tex]

In quadrilateral BADC, AB = AD andBC = DC. The line AC is a line ofsymmetry for this quadrilateral

Answers

Given the quadilateral: BADC

AB = AD

BD = DC

The line AC is a diagonal of the quadilateral.

The given quadilateral is a kite.

Let's answer the following questions using the given information.

Part a:

Diagonal AC and diagonal BD are perpendicular.

The diagonals of a kite are perpendicular, this is because the point of intersection of both diagonals form a right angle (90 degrees).

Therefore, based on the line of symmetry, we can say diagonals AC and BD are perependicular because the quadilateral is symmetric along the diagonals AC and BD of the figure.

• Part b:

Based on the line of symmetry, angle ABC and angle ADC have the same measure because the qudilateral has

Drag the prisms to the table in order from least volume to greatest volume.

Answers

Fourth prism, first prism, second prism and fourth prism is order from least volume to greatest.

What is Three dimensional shape?

a three dimensional shape can be defined as a solid figure or an object or shape that has three dimensions—length, width, and height.

The volume of first prism with sides 2, 1.5 and 3.2

Volume=2×1.5×3.2

=9.6 in³

The volume of second prism with sides 1.5, 1.5 and 6

Volume=1.5×1.5×6

=13.5 in³

The volume of third prism with sides 2, 5/2 and 7/2

Volume=2×2.5×3.5

=17.5 in³

The volume of fourth prism with sides 1/2, 1/2 and 1/2

Volume=0.5×0.5×0.5

=0.125 in³

Hence fourth prism, first prism, second prism and fourth prism is order from least volume to greatest.

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i only need the final answers, i do not need an explanation i am just double checking my final answer

Answers

[tex]\begin{gathered} \text{Investment 1} \\ 12000\cdot0.06=720 \\ 720\text{ interest after 1 year} \\ \text{Investment 2} \\ 5000\cdot0.05=250 \\ 250\text{ interest after 1 year} \\ \text{Combined interest} \\ 720+250=970 \end{gathered}[/tex][tex]\begin{gathered} \text{Divide total interest by total investment} \\ \frac{970}{12000+5000}=\frac{970}{17000}=0.05705882352941176470588235294118 \\ \text{Converted to percent that is} \\ 5.705882352941176470588235294118\% \end{gathered}[/tex]

Its a project for my consumer math class and i have to record all the information on a template

Answers

We are asked to fill up the transactions in the table.

Remember that Payments, fees, and withdrawals are always subtracted from the balance, and deposits are always added to the balance.

The starting balance is $275

1st transaction:

Payment of $85.67 to the electric company on 2nd October.

Since it is a payment, it must be subtracted from the previous balance.

Balance = $275 - $85.67 = $189.33

2nd transaction:

You want to deposit the $20 that your friend gave to you.

Since it is a deposit, it must be added to the previous balance.

Balance = $189.33+$20 = $209.33

Warren flipped a coin and rolled a 20-sided number cube. What is the probability that his coin landed on tails and his number cube rolled a factor of 20? answer as a simplified fraction.

Answers

Warren flipped a coin and rolled a 20-sided number cube. What is the probability that his coin landed on tails and his number cube rolled a factor of 20? answer as a simplified fraction.​

we have that

the probability that his coin landed on tails is

P=1/2

and

Factors of 20 are ----> 1,2,4,5,10,20

so

The probability that his number cube rolled a factor of 20 is

P=6/20=3/10

therefore

the probability that his coin landed on tails and his number cube rolled a factor of 20 is equal to

P=(1/2)*(3/10)

P=3/20

Solve $9.75 x $40 to get $390.00, using long multiplication

Answers

I will be using a rough sketcher to show the long multiplication:

The process is shown below:

Note:

the last zero is taken down last, after the multiplication is done [shown by green arrow]

Lastly, we put the decimal point "2 places to the left" since the multiplication problem has "2 decimal places"

the u.s senate has 100 members. after a certain election, there were 6 more democrats than republicans, with no other parties represented. how many memebrs of each party were there in the senate?

Answers

As per the unitary method, the number of democrats are 53 and the number of republicans are 47.

Unitary method:

Unitary method is the process of finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given,

The U.S senate has 100 members. after a certain election, there were 6 more democrats than republicans, with no other parties represented.

Here we need to find the number of democrats and the number of republicans.

Let us consider the number of Republican's be "x"

And then the number of Democrats is "x+6".

We know that the total number of members in the senate is 100.

So, it can be written as

x + (x + 6) = 100

2x + 6 = 100

2x = 100 - 6

2x = 94

x = 94/2

Then the value of x is,

x = 47

Therefore, there are 47 republicans in the senate then the number of democrats is

x + 6 => 47 + 6 => 53

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what is the volume of the cone? use Pi and round to the nearest tenth

Answers

Let's begin by listing out the information given to us:

Radius (r) = 7ft

Height (h) = 25ft

The volume of a cone is calculated as shown below:

V = ⅓πr²h

V = ⅓ * 3.14 * 7² * 25 = 1282 1/6

V = 1282 1/6 or 1282.667 = 1282.7 = 1283 ft³

V = 1283 ft³

Which equation models the total profit,y,based on the number of tickets sold,x?

Answers

Answer

D. y - 300 = 4(x - 100)

Step-by-step explanation

Variables

• x: tickets sold

,

• y: profit

Equation of a line in point-slope form

[tex]y-y_1=m(x-x_1)[/tex]

where m is the slope and (x₁, y₁) is a point on the line.

The slope of the line that passes through the points (x₁, y₁) and (x₂, y₂) is calculated as follows:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

This line passes through the points (100, 300), that is, when 100 tickets are sold, the club had $300 in profit, and the point (200, 700). Then, its slope is:

[tex]\begin{gathered} m=\frac{700-300}{200-100} \\ m=\frac{400}{100} \\ m=4 \end{gathered}[/tex]

Substituting into the general equation with m = 4 and the point (100, 300), we get the next equation of the line:

[tex]y-300=4(x-100)[/tex]

A survey claims that the percent of a city's residents that favor building a new football stadium is likely between 52.3% and 61.7%. What was the sample proportion (what percent of the people in the sample survey said that they wanted to build a new stadium )?

Answers

The confidence interval for the sample proportion is calculated using the following formula:

[tex]\lbrack p\lbrack\text{hat\rbrack}\pm Z_{1-\frac{\alpha}{2}}\cdot\sqrt[]{\frac{p\lbrack hat\rbrack(1-p\lbrack hat\rbrack)}{n}}\rbrack[/tex]

Where p[hat] represents the sample proportion. As you see you add/subtract the margin of error to the sample proportion to determine both bonds of the interval, which means that the sample proportion is in the middle of the interval.

The percent of residents in favor of building a new football stadium is between 52.3% and 61.7% → the sample proportion used to determine this interval is in the middle of both bonds. To calculate the said value you have to find the average of both values:

[tex]52.3\%

The sample proportion used to estimate the interval was p[hat]=0.57

. A town committee has a budget of $75 to spend on snacks for the volunteers participating in aclean-up day. The committeechairperson decides to purchase granola bars and at least 50 bottlesof water. Granola bars cost $.50 each, and bottles of water cost $.75 each. Write and graph asystem of linear inequalities for the number of bottles of water and the number of granola bars thatcan be purchased

Answers

Assume that the number of granola bars is x and the number of bottles is y

Since they decided to purchase at least 50 bottles

At least means greater than or equal, so

[tex]x\ge50[/tex]

Since the cost of 1 bar = $0.50, then

The cost of all bars = 0.50x

Since the cost of 1 bottle = $0.75, then

The cost of all bottles = 0.75y

Since their budget is $75

They can not exceed that, then

[tex]0.50x+0.75y\le75[/tex]

The solution will be in the common part of the two colors

The red represents the second inequality

The blue represents the first inequality

the first three terms of a sequence are given around the nearest thousandth if needed 16,4,1,... Find the 6th term

Answers

16, 4, 1....

2^4, 2^2, 2^0

[tex]2^4,2^2,2^0,2^{-2},2^{-4},2^{-6},2^{-8}\ldots[/tex]

6th term would be 2^-6:

[tex]2^{-6}[/tex]

Series

iley invested $1,000 in savings bonds. If bonds earn 6.75% interest compounded semi-annually, how much will riley earn in 15 years?

Answers

Answer: Riley will earn 2707 in 15 years

Explanation:

The formula for calculating compound interest is expressed as

A = P(1 + r/n)^nt

where

A is the final amount after t years

A is the principal or initial amount

r is the interest rate

n is the number of compounding periods in a year

t is the time

From the information given,

P = 1000

r = 6.75% = 6.75/100 = 0.0675

t = 15

n = 2 because it was compounded twice in a year

By substituting these values into the formula,

A = 1000(1 + 0.0675/2)^2 * 15

A = 1000(1.03375)^30

A = 2707

Riley will earn 2707 in 15 years

Z (7x+3)° m n (6x+11)

Answers

In this problem, the two angles are equal because of the properties, so:

[tex](7x+3)=(6x+11)[/tex]

and we can solve for x

[tex]\begin{gathered} 7x-6x=11-3 \\ x=8 \end{gathered}[/tex]

So the angles are:

[tex]\begin{gathered} 7(8)+3=59 \\ 6(8)+11=59 \end{gathered}[/tex]

4Complete the table of values for the following function: y = VX-8X1006493625y-81

Answers

y= √x - 8

Replace each value of x and solve for y

x= 100

y= √100 - 8 = 10-8 = 2

x= 64

y= √64-8 = 8 - 8 = 0

x= 9

y= √9 - 8 = 3 - 8 = -5

x= 36

y=√36 - 8 = 6-8= -2

x= 25

y= √25- 8 = 5 - 8 = -3

For the last values, replace y and solve for x

y=-8

-8= √x - 8

-8+8 = √x

0= √x

x= 0^2

x=0

y=1

1=√x-8

1+8= √x

9 = √x

9^2 = x

x= 81

How do I write five hundred and eight hundredths as a decimal number.

Answers

start by writing the whole part, sine there us only hundreds we can write it as

[tex]500[/tex]

then write the decimal part, we can see that there are no tenths in this expression so we start with a 0, then for the hundredths, we can put the number 8

[tex].08[/tex]

The complete number should be

[tex]500.08[/tex]

5) A ball is dropped from a height of 400 feet. Each time it hits the ground, it rebounds 75% of the distance it has fallen. How far will the ball travel before coming to rest?

Answers

Initial height: 400 m

Each time it hits the ground, it rebounds 75% the distance it has fallen. Let us say this distance is d, then the new height is:

[tex]\begin{gathered} h=75\text{\% of }d=\frac{75}{100}\cdot d \\ \Rightarrow h=\frac{3}{4}d \end{gathered}[/tex]

If the initial height is 400 m, then the subsequent heights are given by the recurrence equation:

[tex]\begin{gathered} h_0=400 \\ h_n=(\frac{3}{4})^n\cdot h_0 \\ \Rightarrow h_n=400\cdot(\frac{3}{4})^n \end{gathered}[/tex]

And the total distance traveled D is:

[tex]\begin{gathered} D=h_0+2\cdot\sum ^{\infty}_{n\mathop=1}\lbrack(\frac{3}{4})^n\cdot h_0\rbrack \\ \Rightarrow D=400+800\cdot\sum ^{\infty}_{n\mathop{=}1}(\frac{3}{4})^n \end{gathered}[/tex]

Now, let us analyze the sum term:

[tex]\sum ^{\infty}_{n\mathop{=}1}(\frac{3}{4})^n=\frac{3}{4}+(\frac{3}{4}_{})^2+(\frac{3}{4})^3+\cdots_{}[/tex]

From the infinite geometric sequence:

[tex]\begin{gathered} \sum ^{\infty}_{n\mathop=0}r^n=\frac{1}{1-r} \\ \Rightarrow\sum ^{\infty}_{n\mathop{=}1}r^n=\frac{1}{1-r}-1 \end{gathered}[/tex]

Where r < 1. From our problem, r = 3/4 < 1, then:

[tex]\begin{gathered} \sum ^{\infty}_{n\mathop{=}1}(\frac{3}{4})^n=\frac{1}{1-\frac{3}{4}}-1=\frac{1}{\frac{1}{4}}-1=4-1 \\ \Rightarrow\sum ^{\infty}_{n\mathop{=}1}(\frac{3}{4})^n=3 \end{gathered}[/tex]

Finally, using this result:

[tex]D=400+800\cdot3=400+2400=2800[/tex]

what is the slope of the equation y = - 7x + 9

Answers

EXPLANATION

The slope of a line is given by the following expression:

[tex]\text{Slope = }\frac{rise}{run}=\frac{(y_2-y_1)}{(x_2-x_1)}[/tex]

In this case, we have that the slope is represented by the generic form:

y = mx + b

Where m is the slope and b is the y-intercept.

So, the slope is -7.

Answer: m=-7

assume that y varies inversely with x. If y = -4 when x = 1/2 , find x when y=2

Answers

it is given that x and y have inverse relation

so K = xy

put y = -4 and x = 1/2

[tex]\begin{gathered} k=\frac{1}{2}\times-4 \\ k=-2 \end{gathered}[/tex]

now

y = 2

then'

[tex]\begin{gathered} -2=x\times2 \\ x=\frac{-2}{2} \\ x=-1 \end{gathered}[/tex]

so the value of x = -1

[tex]\begin{gathered} x\infty\frac{1}{y} \\ x=\frac{K}{y} \\ K=xy \end{gathered}[/tex]

EFGH is translate 5 units to the left and 2 units up.A. E(-1,-3)B. E(6,-6)C. E (-1,1)D. E(9,-3)

Answers

To translate the figure 5 units to the left and 2 up, apply the following translation to each coordinate of the figure

[tex]T_{(-5,2)}\colon(x,y)\rightarrow(x-5,y+2)[/tex]

So, you have

[tex]\begin{gathered} E(4,-1)\rightarrow E^{\prime}(4-5,-1+2)\rightarrow E^{\prime}(-1,1) \\ F(0,-3)\rightarrow F^{\prime}(0-5,-3+2)\rightarrow F^{\prime}(-5,-1) \\ G(2,-4)\rightarrow G^{\prime}(2-5,-4+2)\rightarrow G^{\prime}(-3,-2) \\ H(6,-2)\rightarrow H^{\prime}(6-5,-2+2)\rightarrow H^{\prime}(1,0) \end{gathered}[/tex]

Therefore, the coordinates of E' are (-1,1) and the correct answer is C. E(-1,1).

What is the x-value of the solution to this system of equations? x = 2y - 4 7x + 5y = -66 F-2 G 19 7 H -8 62 19

Answers

Answer:

x = -8

Explanation:

Given the below system of equations;

[tex]\begin{gathered} x=2y-4\ldots\ldots\ldots\ldots\ldots\text{.Equation 1} \\ 7x+5y=-66\ldots\ldots\ldots\ldots\text{Equation 2} \end{gathered}[/tex]

The solve the above, let's go ahead and put equation 1 into equation 2 and solve for y;

[tex]\begin{gathered} 7(2y-4)+5y=-66 \\ 14y-28+5y=-66 \\ 19y=-66+28 \\ 19y=-38 \\ y=-\frac{38}{19} \\ y=-2 \end{gathered}[/tex]

To find x, we have to substitute the value of y into equation 1 and solve for x;

[tex]\begin{gathered} x=2(-2)-4=-4-4=-8 \\ x=-8 \end{gathered}[/tex]

Use the Venn diagram to complete the sentences. Write All or Some or No in each blank

Answers

If we look at the image, we must see that the parallelogram's circle is greater than the trapezoid's circle, in other words, the trapezoids are contained in the parallelograms. In addition, no information about the quadrilaterals is provided in the Venn diagram. The correct word in each sentence are

1. No trapezoids are quadrilaterals.

2. No quadrilaterals are trapezoids.

3. Some parallelograms are trapezoids.

4. All trapezoid are parallelograms.

Find the angle between the vectors u = 5i – 2j and v = 2i + 3j.

Answers

STEP - BY - STEP EXPLANATION

What to find?

The angle between the given vectors.

Given:

u = 5i – 2j and v = 2i + 3j.

To solve the given problem, we will follow the steps below:

Step 1

Write the formula that can be use to solve the above.

[tex]cos\theta=\frac{\vec{a}\vec{.b}}{\vec{|a}\vec{||b}|}[/tex]

Step 2

Determine;

→ →

a. b

[tex]\begin{gathered} \vec{a}\vec{.b}=(5)(2)+(-2)(3) \\ \\ =10-6 \\ \\ =4 \end{gathered}[/tex]

Step 3

Determine;

→ →

|a| and | b|

[tex]\begin{gathered} \vec{|a|}=\sqrt{5^2+(-2)^2} \\ \\ =\sqrt{25+4} \end{gathered}[/tex][tex]=\sqrt{29}[/tex]

[tex]\begin{gathered} \vec{|b|}=\sqrt{2^2+3^2} \\ \\ =\sqrt{4+9} \\ \\ =\sqrt{13} \end{gathered}[/tex]

Step 4

Substitute the values into the formula.

[tex]\begin{gathered} cos\theta=\frac{4}{\sqrt{29}\times\sqrt{13}} \\ \\ =\frac{4}{\sqrt{377}} \end{gathered}[/tex]

Step 5

Take the arc cos of both-side.

[tex]\theta=cos^{-1}(0.20601)[/tex][tex]\theta=78.1\degree[/tex]

ANSWER

θ = 78. 1°

Use the change of base formula to compute log/174.Round your answer to the nearest thousandth.

Answers

Answer:

The Expression is given below as

[tex]\log_{\frac{1}{7}}4[/tex]

Represent the expression above to be

[tex]=x[/tex]

That is, we will have that

[tex]\log_{\frac{1}{7}}4=x[/tex]

Applying the change of base rule below, we will have that

[tex]\begin{gathered} \log_ab=y \\ b=a^y \\ lnb=lna^y \\ lnb=ylna \\ y=\frac{lnb}{lna} \end{gathered}[/tex][tex]\begin{gathered} \log_{\frac{1}{7}}4=x \\ (\frac{1}{7})^x=4 \\ (7^{-1})^x=4 \\ 7^{-x}=4 \\ take\text{ ln of both sides} \\ ln7^{-x}=ln4 \\ -xln7=ln4 \\ dividie\text{ both sides by -ln7} \\ \frac{-xln7}{-ln7}=\frac{ln4}{-ln7} \\ x=-0.712 \end{gathered}[/tex]

Hence,

The final answer is

[tex]\rightarrow-0.712[/tex]

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