I need help with the hidden message. Help me please. Thank You I really appreciate it if you have helped me.
Answers
We have symbols that represent a letter and a number.
With the equations or relations in the left we have to find the numeric value for each picture, and then use the letter to complete the hidden message.
First equation is:
[tex]\begin{gathered} \text{spyder web + spyder web =16} \\ 2\cdot\text{spyder web = 16} \\ \text{spyder web = }\frac{16}{2}=8 \end{gathered}[/tex]So, the value of a spyder web is 8 and the letter for that is i.
The second equation is:
[tex]\begin{gathered} \text{candy - spyder web = 9} \\ \text{candy - 8 =9} \\ candy\text{ = 9+8=17} \end{gathered}[/tex]The value of candy is 17 and the letter is T.
The Third equation is:
[tex]\begin{gathered} \text{spyder web }\cdot\text{ cat - candy = 7} \\ 8\cdot\text{cat - 17 =7} \\ 8\cdot\text{cat=7+17=24} \\ \text{cat}=\frac{24}{8}=3 \end{gathered}[/tex]The value of cat is 3 and the letter is S.
The fourth equation is:
[tex]\begin{gathered} ballons\text{ / cat =11} \\ \text{ballons /3 =11} \\ \text{ballons}=11\cdot3=33 \end{gathered}[/tex]The value of ballons is 33 and the letter is E.
The fifth equation is:
[tex]\begin{gathered} \text{bat + (ballons - candy) = 23} \\ \text{bat + (33-17) = 23} \\ bat+16=23 \\ \text{bat = 23 - 16 = 7} \end{gathered}[/tex]The value of bat is 7, but there is some mistake, it must be 6 and the letter C.
The sixth equation is:
[tex]\begin{gathered} \text{bat}+\text{cat}\cdot pumpkin\text{ = 27} \\ 6+3\cdot\text{pumpkin}=27 \\ 3\cdot\text{ pumpkin = 27-6=21} \\ \text{pumpkin =}\frac{21}{3}=7 \end{gathered}[/tex]The value of pumpkin is 7 and the letter is O.
The seventh equation is:
[tex]\begin{gathered} \text{spyder / spyder web }\cdot\text{ pumpkin = 21} \\ \frac{spyder}{8}\text{ }\cdot7=21 \\ \text{spyder = 21}\cdot\frac{8}{7}=3\cdot8=24 \end{gathered}[/tex]The value of spyder is 24 and the letter is B.
The last equation is:
[tex]\begin{gathered} tree\text{ +ghost}=0 \\ tree\text{ + 0=0} \\ \text{tre}e\text{ = 0} \end{gathered}[/tex]The only value for ghost is zero and the letter L and the value of tree is zero too and the letter is O.
The hidden message is:
BOIL IS IOOOCEOT
Related Questions
Precalculus:Consider the right triangle where a = 3mi and alpha = 45 degrees Find an approximate value (accurate up to three or more decimals) of each of the following. Give the angle in degrees.
Answers
Given:
[tex]\begin{gathered} a=3mi \\ \alpha=45\degree \end{gathered}[/tex]Required:
To find the value of beta, b and c.
Explanation:
The given triangle is right triangle.
Therefore,
[tex]\begin{gathered} \sin\alpha=\frac{a}{c} \\ \\ \sin45=\frac{3}{c} \\ \\ 0.7071=\frac{3}{c} \\ \\ c=\frac{3}{0.7071} \\ \\ c=4.2426mi \end{gathered}[/tex]Now
[tex]\begin{gathered} \tan\alpha=\frac{a}{b} \\ \\ \tan45=\frac{3}{b} \\ \\ 1=\frac{3}{b} \\ \\ b=3 \end{gathered}[/tex]The sum of the angle in triangle is 180 degree.
Therefore
[tex]\begin{gathered} 90+45+\beta=180 \\ \beta=180-90-45 \\ \beta=45\degree \end{gathered}[/tex]Final Answer:
[tex]\begin{gathered} b=3mi \\ c=4.2426mi \\ \beta=45\degree \end{gathered}[/tex]Look at the graph of f(x). Which of the following are true? Select all that apply. 2 answers
Answers
Answer:
Explanation:
Answer:
A. [tex]f(x)[/tex] is [tex]y=sec(x-\pi )[/tex] shifted 6 units up.
C. [tex]f(x)[/tex] is [tex]y=sec(x)+6[/tex] shifted [tex]\pi[/tex] units to the left.
Step-by-step explanation:
If you guessed the answer to this question, or did not answer, go back and review how to write to equation of a trigonometric function.
Your welcome...
The number of needles in each packet are 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4, 5, 6, 7,and 8. Find the range of the given data.
Answers
Given that
The number of needles in the packet is 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4, 5, 6, 7, 8
And we have to find the range of this data.
Explanation -
To find the range first we will arrange the numbers in the order as
1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4, 5, 6, 7, 8
Now we will subtract the lowest number from the highest to get the range.
So
nge = 8 - 1 = 7
Final answer -
Hence the range is 7, So the final answer is 7.14. To surf the internet at the Airport costs $20,40 for 20 minutes and it costs $26.25 for 35minutes. How much would it cost to surf the internet for exactly 55 minutes.
Answers
Cost = $20.40 / 20 min
Cost = $26.25 / 35 min
To calculate the cost to suft 55 min just add the previous values given
Cost = 20.40 + 26.25
= $46.65
what is the lcm of 25 and 37?
Answers
SOLUTION:
Step 1:
In this question, we are meant to find the LCM of 25 and 37.
Step 2:
The least common multiple, lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by lcm(a, b), is the smallest positive integer that is divisible by both a and b
Find mZ1 in the picture below.1(3y² + 2y – 10)(2y² + 7y + 4)
Answers
m∠1=29
In this question,
1) Since we have, vertical angles, whose measure are written as polynomials then we can write according to the Vertical angles theorem:
3y² + 2y – 10 =2y² + 7y + 4
3y²-2y² -7y+2y-10-4=0
y²-5y-14=0
1.1) Finding the roots by Sum and Product
S(x) = ___ +___ = -5
P(x) =____ x ___ = -14
x1=-2 or 7
Since our Domain, cannot allow negative numbers, let's keep the positive one 7
2) Moreover to that, m∠1 + 2y² + 7y + 4 = 180º
m∠1 +2(7)²+7(7)+4=180
m∠1 +151 =180
m∠1=180-151
m∠1=29
Part 311Use the relationships in circle O to find the missing measures in circle S.1 pointIf WR = 12 units and MN = 8 units, determine MW.Type your answerwMRNePrestipus
Answers
From the properties of secant line and the tangent to the circle
If a secant segment and tangent segment are drawn to a circle from the same external point, the length of the tangent segment is the geometric mean between the length of the secant segment and the length of the external part of the secant segment.
[tex]\frac{Whole\text{ Secant}}{\tan gent\text{ Line}}=\frac{\tan gent}{External\text{ Secant Part}}[/tex]
In the given figure we hvae :
Whole secant length (RM),
Tangnt line MN = 8 units
External secant part (WM)
Since RM = WR + WM
RM=12 + WM
Susbtitute the value:
[tex]\begin{gathered} \frac{Whole\text{ Secant}}{\tan gent\text{ Line}}=\frac{\tan gent}{External\text{ Secant Part}} \\ \frac{RM}{MN}=\frac{MN}{MW} \\ \frac{12+MW}{8}=\frac{8}{MW} \\ \text{Apply crossmultiplication:} \\ MW(12+MW)=8\times8 \\ 12MW+(MW)^2=64 \\ \text{ Let MW = x} \\ 12x+x^2=64 \\ x^2+12x-64=0 \\ \text{ Factorize:} \\ x^2+16x-4x-64=0 \\ x(x+16)-4(x+16)=0 \\ (x-4)(x+16)=0 \\ \text{ So, x = 4, -16} \\ \text{ Since measurement cannot be negative thus: x = 4 unit} \\ x\text{ = }MW=4 \end{gathered}[/tex]Answer : MW= 4 units
Which equations can you solve to find the value of m choose all that apply
Answers
m = 7.50 + 12.50
m - 7.50 = 12.50
Explanation:Cost of the book = $7.50
Amount remaining on the gift card = $12.50
m = Amount on the gift card in dollars when Salim received it
Amount on the gift card in dollars when Salim received it = Cost of the book + Amount remaining on the gift card
m = $7.50 + $12.50
m = 7.50 + 12.50
Another form of the equation:
subtract 7.5 from both sides:
m - 7.50 = 7.50 - 7.50 + 12.50
m - 7.50 = 12.50
Hence, equation that can be used to solve m:
m = 7.50 + 12.50
m - 7.50 = 12.50
How is a number related to its opposite?
Answers
The opposite of any given number is simply that number multiplied by negative 1. For instance, the opposite of 15 is 15 x (-1) and that is -15.
Therefore, a number is always a negative of its opposite
At the city museum, child admission is $5.90 and adult admission is $9.40. On Saturday, 170 tickets were sold for a total sales of $1332.00. How many adulttickets were sold that day?Number of adult tickets:
Answers
In this case, we'll have to carry out several steps to find the solution.
Step 01:
data:
city museum
Step 02:
system of equations:
x = # child tickets
y = # adult tickets
equations:
x + y = 170 eq. 1
5.90x + 9.40y = 1332 eq.2
x + y = 170 * (- 5.90)
5.90x + 9.40y = 1332
-5.90x - 5.90y = - 1003
5.90x + 9.40y = 1332
--------------------------------
3.5y = 329
y = 329 / 3.5
y = 94
The answer is:
# adult tickets = 94
Countries represented at each festival 6 5 4 Number of festivals 3 N 1 0 0-5 6-11 12-17 18-23 24-29 Number of countries How many festivals had 12 or more countries represented.
Answers
11 festivals
Explanation
to find the nunmber of festivals that had 12 or more countries, sum the festivals for all values in number of countries greather than 12, it its
[tex]\begin{gathered} \text{column 3 (12-17)=5 festivals} \\ \text{column 4(18-23)=4 festivals} \\ column5(24-29)=2\text{ festivals} \\ so,\text{ the total of festivals for 12 or more countries is} \\ \text{total}=5+4+2 \\ total=11\text{ festivals} \end{gathered}[/tex]I hope this helps you
Kelly is building a playpen for her dog. The area of the playpen is 22.75 square feet. The length is 6.5 feet and the width is w feet.
Answers
w = 3.5 feet
Explanation:Area = 22.75 square feet
length = 6.5 feet
width = w
Since we have beeen given dimensions in the form of length and width, the shape at the play house is a rectangle:
Area of rectangle = length × width
22.75 square feet = 6.5 feet × w
22.75 = 6.5w
divide both sides by 6.5:
22.75/6.5 = 6.5w/6.5
w = 3.5 feet
What is the real part of 4 – 5i? 54-5i-5
Answers
Every imaginary number have the following form:
[tex]a\text{ +bi (1)}[/tex]Where a= real part , b= imaginary part
Basically on this case the real part would be the number without the i and the imaginary part the number with i
The real part is:
[tex]4[/tex]And the imaginary part:
[tex]-5[/tex]Final answer:
[tex]4[/tex]5. Solve the system of equations by graphing. y = -x + 2 3x + 3y = 6
Answers
Answer:
The system of equations has infinite number of solutions.
The solution to the system of equations is any point on the line of the graph.
Explanation:
Given the system of equations;
[tex]\begin{gathered} y=-x+2 \\ 3x+3y=6 \end{gathered}[/tex]Plotting the two equations using a graph calculator we have;
From the graph, we can observe that the line of the two equations fall on each other.
That means that the equations are the same.
Therefore, the system of equations has infinite number of solutions.
The solution to the system of equations is any point on the line of the graph.
i have no idea how to do this please help
Answers
Answer:
D. -1
Explanation:
• There are 5 x(s)
,• There are 6 1-boxes.
The equation modeled is:
[tex]5x+6=1[/tex]We solve for x.
[tex]\begin{gathered} 5x=1-6 \\ 5x=-5 \\ x=-\frac{5}{5} \\ x=-1 \end{gathered}[/tex]The value of x that makes the equation true is -1.
If the spinner is spun, what is the probability that the spinner will land on a multiple of 4?
Answers
Answer: A
Step-by-step explanation:
There are 10 possible outcomes on the spinner listed 1-10.
The multiples of 4 are 4, 8, 12, 16, and so on.
On the spinner, there are only 4 and 8 (of the multiples), and out of the 10 outcomes, that's 2/10 of them both.
If you multiply that fraction by 10 (we multiply by 10 since 2/10 isn't on the answer choices, also a number over 100 is also a percent)
that gives us 20/100, or 20%.
Hope that helps!
see attached for question and diagram
Answers
Given: D = (1,3) and E = (3,-3)
The graph of DE is as following:
a) Translation (0,2) then reflection on x-axis
So, at first move 2 units upward t hen reflect across x-axis
Note: the rule of reflection across x-axis: (x,y) to (x,-y)
the final result in green color
B) reflection in x-axis then clock wise rotation
(1,3) to (1,-3) to (-3 , -1)
(3,-3) to (3,3) to (3,-3)
Note : reflection cross x-axis will give the red dash line
Then make rotation for the red dash line will give the green line
1990, the cost of tuition at a large Midwestern university was $101 per credit hour. In 2005, tuition had risen to $236 per credit hour.
Answers
Solution:
According to the problem, the linear equation would be:
[tex]C(X)=101+9(x-1990)[/tex]now, if x=2013, the tuition will be:
[tex]C(2013)=101+9(2013-1990)=101+9(23)[/tex]this is equivalent to
[tex]C(2013)=101+9(23)=308[/tex]In the expansion of (2a+4b)^8, which of the following are possible variable terms? Explain your reasoning?
Answers
In the expansion of (2a+4b)⁸ the possible variable terms are a⁸, a⁵b³, a³b⁵, a⁷b, and b⁸.
What is an Expression?
In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.
We need to find the possible variable terms in the expansion of (2a+4b)^8
The given expression can be written as:
(2a + 4b)⁸ = (2a + 4b)² x (2a + 4b)² x (2a + 4b)² x (2a + 4b)²
= (4a² + 8ab + 16b²) x (4a² + 8ab + 16b²) x (4a² + 8ab + 16b²) x (4a² + 8ab + 16b²)
Now, further simplify the above expression.
(16a⁴ + 32a³b + 64a²b² + 32a³b + 64 a²b² + 128b⁴ + 64a²b² + 128ab³ + 256b⁴) x (16a⁴ + 32a³b + 64a²b² + 32a³b + 64 a²b² + 128b⁴ + 64a²b² + 128ab³ + 256b⁴)
Hence, In the expansion of (2a+4b)⁸ the possible variable terms are a⁸, a⁵b³, a³b⁵, a⁷b, and b⁸.
To learn more about Expression refer here
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What are the leading coefficient and degree of the polynomial?-8u^6-15+4u+18u^9
Answers
The degree of a polynomial is given by the higher exponent of the variable.
In this polynomial, we have terms with the variable with exponents 6, 0, 1 and 9.
Therefore the degree of the polynomial is 9.
The leading coefficient is the number that multiplies the variable with a higher exponent.
The leading term is 18u^9, so the leading coefficient is 18.
17 * 7*20000000000000
Answers
Here, we want to multiply the given terms
The best way to go about this
Answer: 2.38e+15
Step-by-step explanation:
A swim team consist of seven boys and four girls a relay team of four swimmers is chosen at random from the team members what is the probability that three boys are selected for the relay team given that the first selection was a girl express your answer as a fraction in lowest terms or a decimal rounded to the nearest million
Answers
At start, we have:
- 7 boys
- 4 girls
It is given that the first selection was a girl. Since there were 4 girls, there is 3 left to be picked. So we have:
- 1 girl picked
- 7 boys to be picked
- 3 girls to be picked
We want the next 3 pickes to be boys.
The probability that the first pick will be a boy is the number of boys to be picked from over the total team left to be picked from. We have 7 boys and a total of 7 + 3 = 10 members, so:
[tex]P_1=\frac{7}{10}[/tex]Next, we want another pick of boy, but now we have got only
- 6 boys
- 3 girls
So, the probability of the second pick to be boy is:
[tex]P_2=\frac{6}{9}[/tex]And for the third, we have:
- 5 boys
- 3 girls
Probability of
[tex]P_3=\frac{5}{8}[/tex]Since we want these three to occur, the final probability is the product of them:
[tex]P=P_1\cdot P_2\cdot P_3=\frac{7}{10}\cdot\frac{6}{9}\cdot\frac{5}{8}=\frac{7}{1}\cdot\frac{1}{3}\cdot\frac{1}{8}=\frac{7}{24}[/tex]So, the answer as a fraction in the lowest form is:
[tex]\frac{7}{24}[/tex]Consider the diagram and angle measures shown below.m∠1 = (3x +25)m∠2 = (7x+5)m∠3 =(-2x + 70)4322 || 7What is the value of m∠3 ?
Answers
First, we need to find the value of x
m<4 = m<1 = (3x + 25)° ( corresponding angle)
Let the angle between m<2 and m<3 be m<5
m< 5 = m<4 = (3x + 25)° ( vertical angle)
m<2 + m<5 + m<3 = 180° (angles on a straight line
(7x+5)° + (3x+25)° + (-2x + 70)° = 180°
7x + 5 + 3x + 25 -2x + 70 = 180
Rearrange
7x + 3x -2x + 5 + 25 + 70 = 180
8x + 100 = 180
subtract 100 from both-side of the equation
8x = 180 - 100
8x = 80
Divide both-side of the equation by 8
x = 10
m<3 = -2x + 70
substitute x = 10 in the above
m<3 = -2(10) + 70 = -20 + 70 = 50°
A painting sold for $216 in 1977 and was sold again in 1985 for $467. Assume that the growth in the value V of the collectors items was exponential.
A. Find the value k of the exponential growth rate. Assume v=216
K=?
Answers
The value k of the exponential growth rate is k = 0.1012
For given situation, we use the formula for exponential growth :
V(t) = V0(1 + k)^t
where, V(t) is the value of the collectors items
V0 is the initial value of painting
k is the exponential growth rate
t is the time interval
A painting sold for $216 in 1977 and was sold again in 1985 for $467.
So, V0 = $216
t = 1985 - 1977
t = 8
V(8) = $467
We need to find k
V(8) = V0(1 + k)^8
467 = 216 * (1 + k)^8
2.162 = (1 + k)^8
taking 8th root on both the sides,
1 + k = ± (2.162)^(1/8)
1 + k = (2.162)^(1/8) or 1 + k = -(2.162)^(1/8)
k = 0.1012 or k = -2.1012
Therefore, the value k of the exponential growth rate is k = 0.1012
Learn more about the exponential growth here:
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Choose ALL answers that describe thequadrilateral DEFGit DE FG,EF | GD, diagonal DF = 16, and diagonalEG=16.
Answers
Having two sets of parallel lines means that it can either be a rectangle, a square, a parallelogram, or a rhombus.
Having the diagonals congruent makes this figure either a rectangle or a square.
Since the length of the side is not given, we can only assume that this is a rectangle.
Summarizing it all, quadrilateral DEFG is a parallogram that is a rectangle because of the two pairs of parallel lines, and it has congruent diagonals.
which system of equations is better to start up to solve using the subsition method or the elemination method?
Answers
For the set of equations, the answer will be:
The elimination method is better because both equations are in general form.
7. Translate the following Marco has $6 less than Ann has
Answers
Solution:
Let x represent the amount Marco has,
let y represent the amount Ann has.
Given that Marcos has $6 less than Ann has, this implies that
[tex]\begin{gathered} x=y-6 \\ \end{gathered}[/tex]Ann has
[tex]y[/tex]Marco has
[tex]y-6[/tex]A ball is thrown from an initial height of 3 meters with an initial upward velocity of 30 m/s. The ball’s height h (in meters) after t seconds is given by the following. h=3+30t-5t^2 Find all values of t for which the ball’s height is 13 meters. Round your answer(s) to the nearest hundredth.
Answers
Answer:
The values of t for which the ball's height is 13 meters is;
[tex]\begin{gathered} t=0.35\text{ s} \\ or \\ t=5.65\text{ s} \end{gathered}[/tex]Explanation:
The function of the ball's height h (in meters) is given as;
[tex]h=3+30t-5t^2[/tex]the value of time t for which the ball's height is 13 meters, can be derived by substituting h=13 into the function of h.
[tex]\begin{gathered} h=3+30t-5t^2 \\ 13=3+30t-5t^2 \\ 3+30t-5t^2=13 \end{gathered}[/tex]subtract 13 from both sides and solve the quadratic equation;
[tex]\begin{gathered} 3+30t-5t^2-13=13-13 \\ -5t^2+30t-10=0 \end{gathered}[/tex]solving the quadratic equation, using the quadratic formula;
[tex]\begin{gathered} t=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ t=\frac{-30\pm\sqrt{30^2-4\times-5\times-10}}{2\times-5} \\ t=\frac{-30\pm\sqrt{900-200}}{-10} \\ t=\frac{-30\pm\sqrt{700}}{-10} \\ t=0.3542=0.35 \\ or \\ t=5.64575=5.65 \end{gathered}[/tex]The values of t for which the ball's height is 13 meters is;
[tex]\begin{gathered} t=0.35\text{ s} \\ or \\ t=5.65\text{ s} \end{gathered}[/tex]I hope you are having a blessed day. Question is attached as a screenshot. Thank you :)
Answers
Solution:
Given the graphs of
[tex]\begin{gathered} y=x, \\ y=-x+4, \\ y=0 \end{gathered}[/tex]to be as plotted below:
The region ABC is bounded as shown above.
To find its area, the region ABC takes the shape of a triangle. Thus, we are to evaluate the area of the triangle ABC.
Step 1: Evaluate the midpoint between the distance AB.
The midpoint (x,y) of the distance AB is evaluated as
[tex]\begin{gathered} (x,y)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ \text{where} \\ x_1=0,y_1=0,x_2=2,y_2=2 \\ \text{thus,} \\ (x,y)=(\frac{0+2}{2},\frac{0+2}{2}) \\ =(1,1) \end{gathered}[/tex]Thus, the midpoint of the distance AB is (1,1).
Step 2: Evaluate the height of the region (triangle).
The height of the region is the same as the distance between points A and the midpoint of the distance AB.
Thus,
The distance is evaluated as
[tex]\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \text{where} \\ x_1=2,y_1=2,x_2=1,y_2=1 \\ \text{thus,} \\ d=\sqrt[]{(1_{}-2_{})^2+(1_{}-2_{})^2} \\ =\sqrt[]{(-1_{})^2+(-1_{})^2} \\ =\sqrt[]{1+1} \\ d=\sqrt[]{2} \end{gathered}[/tex]Step 3: Evaluate the distance between points B and C.
The distance is evaluated similarly as
[tex]\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \text{where} \\ x_1=0,y_1=0,x_2=4,y_2=0 \\ \text{thus,} \\ d=\sqrt[]{(4_{}-0_{})^2+(0_{}-0_{})^2} \\ =\sqrt[]{4^2+0^2} \\ d=4\text{ units} \end{gathered}[/tex]Step 4: Evaluate the area of the triangle ABC.
Given that the distance BC is 4 units and the height of the region is √2 units, the area of the region ABC is evaluated as the area of the triangle ABC.
Thus,
[tex]\begin{gathered} \text{Area = }\frac{1}{2}\times4\times\sqrt[]{2} \\ \Rightarrow Area\text{ =2}\sqrt[]{2} \end{gathered}[/tex]Hence, the area of the region is
[tex]2\sqrt[]{2}[/tex]The fourth option is the correct answer.
What is the congruence correspondence, if any, that will prove the given triangles congruent?A. SASB. AASC. noneD. ASA
Answers
None (option C)
Explanation:Congruent triangles have same shape and size
Rules that can be used to prove triangle congruency:
SAS - side angel side
AAS = Angle angle Side
SSS = side-side-side
ASA = Angle-side-angle
From the triangles given, we see they are not of the same size even though they look alike.
Also the corresponding angles of both triangles do not look the same.
As a result, we do not have conguruence correspondence that will prove the triangles are congruent.
None