Answers
The first thing we have to do is find the pascal coefficients of the triangle for this we use the following image
From our exercise we know that
[tex]\begin{gathered} (2x^3-3y)^3\to(a+b)^3 \\ a=2x^3 \\ b=-3y \end{gathered}[/tex]Then our coefficients of Pascal's triangle are 1 - 3 - 3 - 1
Using the right triangle we get:
[tex]1a^3+3a^2b+3ab^2+1b^3[/tex]We substitute the values of a and b in our new expression to find our solution
[tex]1(2x^3)^3+3(2x^3)^2(-3y)+3(2x^3)(-3y)^2+1(-3y)^3[/tex][tex]\begin{gathered} 8x^9+3(4x^6)^{}(-3y)+3(2x^3)(9y^2)^{}-27y^3 \\ 8x^9-36x^6y+54x^3y^2-27y^3 \end{gathered}[/tex]So the solution is:
[tex]8x^9-36x^6y+54x^3y^2-27y^3[/tex]
Related Questions
3 view. writing simplity expressions The volume of a cube is calculated by multiplying all three side lengths. If a cube has a side of 16 cm, which expression can be used to calculate the volume? A. 161 B. 167 C. 162 D. 164 에 2y Click to add speaker notes
Answers
If we have a cube with a side length of 16 cm, we can calculate the volume as the length side powered to the 3rd or multiplying the side length 3 times:
[tex]V=l\cdot l\cdot l=l^3=16^3[/tex]Answer: V = 16^3 (Option C).
15. Find the missing sides/angles.i=94jk=42k
Answers
From the figure given,
[tex]\begin{gathered} j=\text{opposite}=\text{?} \\ k=adjacent=\text{?} \\ hypotenuse=94 \\ \theta=42^0 \end{gathered}[/tex]Let us solve for 'j'
To solve for j, we will employ the method of Sine of angles.
[tex]\begin{gathered} \text{ Sine of angles=}\frac{opposite}{\text{hypotenuse}} \\ \sin \theta=\frac{j}{hypotenuse} \end{gathered}[/tex][tex]\begin{gathered} \sin 42^0=\frac{j}{94} \\ \text{cross multiply} \\ j=94\sin 42^0 \\ j=94\times0.6691 \\ j=62.8954\approx62.9units(nearest\text{ tenth)} \end{gathered}[/tex]Let us solve for k
To solve for k, we will employ the method of Cosine of angles.
[tex]\begin{gathered} \text{ Cosine of angles=}\frac{k}{\text{hypotenuse}} \\ \cos \theta=\frac{k}{hypotenuse} \\ \cos 42^0=\frac{k}{94} \\ \text{cross multiply} \\ k=94\cos 42^0 \\ k=94\times0.7431 \\ k=69.8514\approx69.9units(nearest\text{ tenth)} \end{gathered}[/tex]Hence, the value of j=62.9units,
k=69.9units.
[tex](x + 4)x + 5)[/tex]write the equivalente expression
Answers
given that (x+4) (x+5) and they are asking for equivalent form.
at first both terms are in multiplication form,so multiply x with (x+5) so we get that
[tex](x+4)(x+5)=x^2+5x+4x+20=x^2+9x+20[/tex]The circumference of a circle is 56.52 what is the diameter
Answers
SOLUTION
We have been given the circumfeence of the circle as 56.52 and we are told to find the diameter
Circumference of a circle C is found as
[tex]\begin{gathered} C\text{ }=\pi d \\ \text{Where }\pi\text{ = 3.14 and d is the diameter. So from } \\ C\text{ }=\pi d \\ 56.52\text{ }=3.14d \\ d\text{ = }\frac{56.52}{3.14} \\ \\ d\text{ = 18} \end{gathered}[/tex]Therefore, the diameter is 18
*DUE TODAY* ANSWER ASAP Olivia has read 40 pages of a 70 page book, 60 pages of an 85 page book and 43 of a 65 page book. What is the percentage of pages Olivia has not read? PLEASE GIVE ME A STEP BY STEP EXPLANATION PLEASE!
Answers
STEP2: turn all of the fractions you have just made into percentages ( divide the numerator by the denominator then, times by 100)
STEP 3: add all of the percentages up and put the sum of them all over 300 ( e.g each percentage added up / 300 )
STEP 4: turn that fraction you just made back into a percentage then that should be your answer!!!
If you need any more help just ask me!
the cost of 9kg of rice is $111.24a)what is the cost of 10kg?b)what is the cost of 10.6kg?
Answers
SOLUTION:
Case: Unit rates
Given: 9kg of rice cost $111.24
First we calculate the cost per kg
Since 9kg cost $111.24
1kg will be:
[tex]\begin{gathered} 1kg\text{ of rice =}\frac{111.24}{9} \\ 1kg\text{ of rice = 12.36} \end{gathered}[/tex]1kg costs $12.36
a) the cost of 10kg
The cost of 10kg will be:
[tex]\begin{gathered} 10kg\text{ of rice will be} \\ =\text{ 10 }\times12.36 \\ =\text{ 123.60} \end{gathered}[/tex]The cost of 10kg of rice is $123.60
b) the cost of 10.6kg
The cost of 10.6kg will be:
[tex]\begin{gathered} 10.6kg\text{ of rice will be} \\ =10.6\text{ }\times12.36 \\ =\text{ 131.0}2 \end{gathered}[/tex]The cost of 10.6kg of rice is $131.02
Final answer:
a) The cost of 10kg of rice is $123.60
b) The cost of 10.6kg of rice is $131.02
10.6 kg cost will be 131.016
Joseph deposited $60 in an account earning 10% interest compounded annually.To the nearest cent, how much will he have in 2 years?Use the formula B=p(1+r)t, where B is the balance (final amount), p is the principal (starting amount), r is the interest rate expressed as a decimal, and t is the time in years.
Answers
Solution:
Using;
[tex]\begin{gathered} B=p(1+r)^t \\ \\ \text{ Where }p=60,r=10\text{ \%}=0.1,t=2 \end{gathered}[/tex][tex]\begin{gathered} B=60(1+0.1)^2 \\ \\ B=72.6 \end{gathered}[/tex]ANSWER: $72.6
One month Chris rented 8 movies and 4 video games for a total of 49$.The next month he rented 3 movies and 2 video games for a total of 21$.Find the rental cost for each movie and each video game.
Answers
Given
One month Chris rented 8 movies and 4 video games for a total of 49$.The next month he rented 3 movies and 2 video games for a total of 21$. Find the rental cost for each movie and each video game.
Solution
Step 1
Let m represent the movies
And let v represent the video
Therefore,
[tex]\begin{gathered} 8m+4v=\text{ \$49}\ldots Equation\text{ 1} \\ 3m+2v=\text{ \$ 21 }\ldots Equation\text{ 2} \end{gathered}[/tex]Step 2
I kinda started it but I don’t know how to find the answer
Answers
Solution
[tex]\begin{gathered} x^2+2x-16=0 \\ \\ \text{ using quadratic formula} \\ \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ a=1,b=2,c=-16 \\ \\ \Rightarrow x=\frac{-2\pm\sqrt{2^2-4(1)(-16)}}{2(1)} \\ \\ \Rightarrow x=\frac{-2\pm\sqrt{4+64}}{2} \\ \\ \Rightarrow x=-1-\sqrt{17} \\ \\ \Rightarrow x=-1+\sqrt{17} \\ \\ \text{ since }x>0 \\ \\ \text{ Therefore the value of }x=-1+\sqrt{17} \end{gathered}[/tex]18. What is the multiple zero and multiplicity of f(x) = (x - 1)(x - 1)(x + 7)?multiple zero = 2; multiplicity = 1multiple zero = 2; multiplicity = -1multiple zero = -1; multiplicity = 2multiple zero = 1; multiplicity = 2
Answers
A polynomial written in factorized form is giving us the information we need about the roots or zeros.
In this case, the polynomial is:
[tex]f(x)=(x-1)(x-1)(x+7)=(x-1)^2(x+7)[/tex]In this case, we have two zeros: x=1 and x=-7.
NOTE: a zero "a" will be expressed in a factor (x-a). That is why the zeros are 1 and -7.
As x=1 appears 2 times as a factor, we can group the factor.
x=1 is a zero with multiplicity of 2.
Answer: the multiple zero is x=1 and has a multiplicity of 2.
multiple zero = 1; multiplicity = 2 [Fourth option]
a. angle addition postulate with angles forming a straight line angle.b. triangle sum theorem c. linear pair postulate
Answers
A. angle addition postulate with angles forming a straight line angle
1) Examining that table, we can see that step 4 is a consequence of the third step, the triangle sum theorem.
2) Then in step 4, we have the following reason to state that the sum of those angles is 180º: Then as we can see below:
We have a Linear Pair between the angles ∠ABD, ∠DBE, and ∠CBE since those angles combined add up to 180º (a straight angle) in red.
3). Hence, the answer is A
Which of these standard form equations is equivalent to (x + 1)(x - 2)(x + 4)(3x + 7)?
Answers
The standard form equation that is equivalent to the expression is x⁴ + 16x³ + 3x² - 66x - 56
How to determine the standard form equation that is equivalent?From the question, we have the following expression that can be used in our computation:
(x + 1)(x - 2)(x + 4)(3x + 7)
The above equation is a product of linear factors
This means that the result of the equation is a polynomial with a degree of the number of factors in the expression
So, we have
(x + 1)(x - 2)(x + 4)(3x + 7)
Open the first two brackets
This gives
(x² + x - 2x - 2)(x + 4)(3x + 7)
Evaluate the like terms
So, we have
(x² - x - 2)(x + 4)(3x + 7)
Open the first two brackets
This gives
(x³ + 4x² - x² - 4x - 2x - 8)(3x + 7)
Evaluate the like terms
So, we have
(x³ + 3x² - 6x - 8)(3x + 7)
Open the remaining brackets
This gives
(x⁴ + 7x³ + 9x³ + 21x² - 18x² - 42x - 24x - 56)
Evaluate the like terms
So, we have
(x⁴ + 16x³ + 3x² - 66x - 56)
Remove the bracket
x⁴ + 16x³ + 3x² - 66x - 56
The expression cannot be further simplified
Hence, the result is x⁴ + 16x³ + 3x² - 66x - 56
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"Solve for all values of x on the given intervals. Write all answer in radians." I am stuck on number 4
Answers
Answer:
[tex]x=\frac{2\pi}{3}+2\pi n,x=\frac{4\pi}{3}+2\pi n[/tex]Explanation:
Given the equation:
[tex]\sin x\tan x=-2-\cot x\sin x[/tex]Add 2+cot(x)sin(x) to both sides of the equation.
[tex]\begin{gathered} \sin x\tan x+2+\cot x\sin x=-2-\cot x\sin x+2+\cot x\sin x \\ \sin x\tan x+2+\cot x\sin x=0 \end{gathered}[/tex]Next, express in terms of sin and cos:
[tex]\begin{gathered} \sin x\frac{\sin x}{\cos x}+2+\frac{\cos x\sin x}{\sin x}=0 \\ \frac{\sin^2x}{\cos x}+2+\cos x=0 \\ \frac{\sin^2x+2\cos x+\cos^2x}{\cos(x)}=0 \\ \implies\sin^2x+2\cos x+\cos^2x=0 \end{gathered}[/tex]Apply the Pythagorean Identity: cos²x+sinx=1
[tex]2\cos x+1=0[/tex]Subtract 1 from both sides:
[tex]\begin{gathered} 2\cos x+1-1=0-1 \\ 2\cos x=-1 \end{gathered}[/tex]Divide both sides by 2:
[tex]\cos x=-\frac{1}{2}[/tex]Take the arccos in the interval (-∞, ):
[tex]\begin{gathered} x=\arccos(-0.5) \\ x=\frac{2\pi}{3}+2\pi n,x=\frac{4\pi}{3}+2\pi n \end{gathered}[/tex]The values of x in the given interval are:
[tex]x=\frac{2\pi}{3}+2\pi n,x=\frac{4\pi}{3}+2\pi n[/tex]If x varies directly as y, and x=-30 when y=-6, find x when y=-4.
Answers
Let us now introduce a constant 'k' inorder to get the relationship between x and y,
[tex]\begin{gathered} x\propto ky \\ x=ky \end{gathered}[/tex]Let us substitute x = -30 and y = -6 inorder to get the relationship,
[tex]\begin{gathered} -30=k\times-6 \\ -30=-6k \\ \text{divide both sides by -6} \\ \frac{-30}{-6}=\frac{-6k}{-6} \end{gathered}[/tex][tex]\begin{gathered} k=5 \\ \text{The relationshiop betw}een\text{ x and y is,} \\ x=5y \end{gathered}[/tex]Let us now solve for x when y = -4,
[tex]\begin{gathered} x=5y \\ x=5\times-4 \\ x=-20 \end{gathered}[/tex]Hence, x is -20.
21. What is the probability of getting an odd number? a.1/3b.2/3c.1/4d.1/5
Answers
The probability of getting an odd number from 1-10 is 1/5.
Given, we have numbers from1-10
The odd numbers ranging from 1-10 are 5
Hence we know the probability formula = Number of favourable outcomes/ totall number of outcomes.
Probability of getting an odd number = 1/5
Hence we get the answer as 1/5.
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-8, {0, -3, 1, -1}, {-1, 1, -2}, {3, -5, 4, -1}, {4, -2, 2}
Answers
Solution
17. -8
18. 0, -3 ,1 , -1
19. -1 ,1 ,-2
20. 3, -5 ,4 ,-1
21. 4, -2. 2
Find the degree and leading coefficient for the given polynomial.−5x^2 − 8x^5 + x − 40degree leading coefficient
Answers
The given polynomial is
- 5x^2 - 8x^5 + x - 40
It can be rewritten as
- 8x^5 - 5x^2 + x - 40
The degree of the polynomial is the highest exponent of the variable in the polynomial. The highest exponent of x is 5. Thus,
degree = 5
The leading coefficient is the coefficient of the term with the highest variable. The coefficient of x^5 is - 8. Thus,
Leading coefficient = - 8
Find the slope of the function 8x - 2y = 10.
Answers
Solve the equation in terms of y, so that it is in the slope-intercept form
[tex]\begin{gathered} 8x-2y=10 \\ -2y=10-8x \\ \frac{-2y}{-2}=\frac{10-8x}{-2} \\ y=-5+4x \\ y=4x-5 \end{gathered}[/tex]Since it is already in the slope-intercept form y = mx + b, where m is the slope. We find that m = 4.
Therefore, the slope of the function is equal to 4.
A sequence is shown below.10, 12, 14, 16, ...Which function can be used to determine the nthnumber in the sequence?
Answers
Answer:
The nth term of the given sequence can be determined using the function;
[tex]a_n=2n+8[/tex]Explanation:
Given the sequence;
[tex]10,12,14,16,\ldots[/tex]The sequence is an arithmetic progression with a common difference d and first term a;
[tex]\begin{gathered} d=12-10 \\ d=2 \\ a=10 \end{gathered}[/tex]Recall that the nth term of an AP can be calculated using the formula;
[tex]a_n=a+(n-1)d[/tex]substituting the given values;
[tex]\begin{gathered} a_n=a+(n-1)d \\ a_n=10+(n-1)2 \\ a_n=10+2(n-1) \\ a_n=10+2n-2 \\ a_n=2n+10-2 \\ a_n=2n+8 \end{gathered}[/tex]Therefore, the nth term of the given sequence can be determined using the function;
[tex]a_n=2n+8[/tex]A patient takes three 25 mg capsules a day. How many milligrams is he taking daily?
Answers
Given:
A patient takes three 25 mg capsules a day.
[tex]3\times25\text{ mg=75mg}[/tex]Answer: A patient is taking 75 mg capsules every day.
Write the number 0.2 in the form a over b using integers
Answers
We can express 0.2 in the form:
[tex]\frac{2}{10}[/tex]The scores of Janet in her math tests are 65, 78, 56, 73, 67, 92. Find themedian score of Janet.
Answers
Answer
70
Explanations;
Given the following datasets that represents the scores of Janet in her math tests
65, 78, 56, 73, 67, 92.
The median is the middle value of the dataset after rearrangement. On rearranging in ascending order;
56, 65 (67, 73) 78, 92
Since there are 2 numbers at the middle, hence the median is the mean value of the data
[tex]\begin{gathered} Median=\frac{67+73}{2} \\ Median=\frac{140}{2} \\ Median=70 \end{gathered}[/tex]Hence the median scores is 70
Parker has tangerines and apricots in a ratio of 12:95. How many apricots does hehave if he has 96 tangerines?On the double number line below, fill in the given values, then use multiplication ordivision to find the missing value.
Answers
We know that if Parker has 12 tangerines he has 95 apricots, so to find how many apricots he has we need to do a rule of tree
[tex]\begin{gathered} x\text{ apricots }\cdot\frac{12\text{ tangerines}}{95\text{ apricots}}=96\text{ tangerines} \\ x\text{ apricots = 96 tangerines }\cdot\frac{95\text{ apricots}}{12\text{ tangerines}} \\ x\text{ apricots =}\frac{96\cdot95}{12}\text{ apricots = }\frac{9120}{12}\text{ apricots} \\ x=760 \end{gathered}[/tex]So the answer is that Parker has 760 apricots is he has 96 tangerines.
Graph the line y = 3/2x + 7y=3/2 x + 2
Answers
Given:
The equation of line is,
[tex]y=\frac{3}{2}x+2[/tex]Find the points on line.
[tex]\begin{gathered} y=\frac{3}{2}x+2 \\ \text{For x=2} \\ y=\frac{3}{2}\times2+2=5 \\ \text{For x}=-2 \\ y=\frac{3}{2}\times(-2)+2=-1 \\ \text{For x=0} \\ y=\frac{3}{2}(0)+2=2 \\ \text{ For x=4} \\ y=\frac{3}{2}(4)+2=8 \end{gathered}[/tex]So, the points are ( 2,5),(-2,-1),(0,2),(4,8).
The graph of the equation of line is,
What is the least common denominator for the following rational equation?x/x+2 + 1/x+4 = x-1/x^2-2x-24
Answers
Least Common Denominator (LCD)
We are required to find the LCD for the expression:
[tex]\frac{x}{x+2}+\frac{1}{x+4}=\frac{x-1}{x^2-2x-24}[/tex]We need to have every denominator as the product of the simplest possible expressions.
Since x+2 and x+4 are already factored, we need to factor the expression:
[tex]x^2-2x-24=(x-6)(x+4)[/tex]Now we have the following prime factors:
x+2, x+4, x-6 and x+4
The LCD is the product of all the prime factors:
LCD = (x+2)(x+4)(x-6)
How many solutions does the equation −5a + 5a + 9 = 8 have? (5 points)NoneOneTwoInfinitely many
Answers
ANSWER:
1st option: none
STEP-BY-STEP EXPLANATION:
We have the following equation:
[tex]−5a\:+\:5a\:+\:9\:=\:8\:[/tex]We solve for a:
[tex]\begin{gathered} −5a\:+\:5a\:+\:9\:=\:8\: \\ \\ 0+9=8 \\ \\ 9=8\rightarrow\text{ false} \end{gathered}[/tex]Therefore, the equation has no solution, the correct answer is 1st option: none
please help with this question
Answers
if each u it cube has edge's of length 1/2 foot, what is the volume of the blue-outlined prism
we have that
the volume of each cube is equal to
V=(1/2)^3
V=1/8 ft3
the rectangular prism volume is equal to
calculate the volume by the numbers of cube
so
V=(5)(2)(2)=20 cubes
Multiply by the volume of each cube
20*(1/8)=2.5 ft3
the volume of the rectangular prism is 2.5 ft3
Very confused on question 5 need help as soon as possible
Answers
To solve this, we can use the remainder theorem.
The theorem says:
Given a polynomial P(x), the remainder of
[tex]\frac{P(x)}{x-a}[/tex]Is equal to P(a)
This means, that we are looking for a value of x such as P(a) = 0
We need to find the roots of the polynomial. We can do this, by trying values of x.
Let's use:
x = 0, 1, 2, 3
[tex]x^3+3x^2-16x-48[/tex]Then:
[tex]\begin{gathered} x=0\Rightarrow0^3+3\cdot0^2-16\cdot0-48=-48 \\ x=1\Rightarrow1^3+3\cdot1^2-16\cdot1-48=1+3-16-48=-60 \\ x=2\Rightarrow2^3+3\cdot2^2-16\cdot2-48=8+12-32-48=-60 \\ x=3\Rightarrow3^3+3\cdot3^2-16\cdot3-48=27+27-48-48=-42 \end{gathered}[/tex]Let's try negative values,
x = -1, -2, -3
[tex]\begin{gathered} x=-1\Rightarrow(-1)^3+3(-1)^2-16(-1)-48=-1+3+16-48=-30 \\ x=-2\Rightarrow(-2)^3+3(-2)^2-16(-2)-48=-8+12+32-48=-12 \\ x=-3\Rightarrow(-3)^3+3(-3)^2-16(-3)-48=-27+27+48-48=0 \end{gathered}[/tex]We have found that the polynomial evaluated in x = -3 is equal to zero, which means:
[tex]\frac{x^3+3x^2-16x-48}{x+3}[/tex]has remainder zero.
The answer is (x + 3)
I just don't know how to indicate values on ration equations
Answers
Solving the equation we have:
[tex]\begin{gathered} \frac{x+3}{x-3}=\frac{12}{3} \\ \frac{x+3}{x-3}=4\text{ (Simplifying the fraction)} \\ x+3=4(x-3)\text{ (Multiplying x-3 on both sides of the equation)} \\ x+3=4x-12\text{ (Distributing)} \\ x+3+12=4x\text{ (Adding 12 to both sides of the equation)} \\ 3+12=4x-x\text{ (Subtracting x from both sides of the equation)} \\ 15=3x\text{ (Adding)} \\ \frac{15}{3}=x\text{ (Dividing by 3 on both sides of the equation)} \\ 5=x\text{ } \end{gathered}[/tex]The solution is x=5 and it is valid as the result of replacing it in the denominator is not zero. ( 5 - 3 ≠ 0)
Convert repeating decimal 0.155….to fraction
Answers
Given the repeating decimal 0.155...
We will convert it to a fraction as follows:
[tex]\begin{gathered} 0.1555.\ldots=0.1+0.055\ldots \\ \\ =\frac{1}{10}+\frac{5}{100-10} \\ \\ =\frac{1}{10}+\frac{5}{90}=\frac{9}{90}+\frac{5}{90}=\frac{14}{90}=\frac{7}{45} \end{gathered}[/tex]so, the answer will be:
[tex]0.1555\ldots=\frac{7}{45}[/tex]