i need help on this answer

Answers

Answer 1

The correlation coefficient "r" can take values from -1 to 1

If the correlation coefficient is less than zero, r < 0, the correlation will be considered negative.

If the correlation coefficient is greater than zero, r > 0. the correlation will be considered positive.

A correlation coefficient equal to zero, r = 0, then there is no correlation between both variables.

If the absolute value of the coefficient is less than 0.35: 0 < | r | < 0.35 → you can say that the correlation between the variables is weak or low.

If the absolute value of the coefficient is between 0.35 and 0.38: 0.35 < | r | 0.65 → you can say that the correlation between both variables is moderate.

If the absolute value of the coefficients is greater than 0.66: | r | > 0.66 → you can say that there is a strong/ high correlation between the variables.

If the absolute value of the coefficient is greater than 0.90: | r |>0.90 → You can conclude that the correlation between both variables is very high or marked.

To be able to classify the type of correlation, the first step is to calculate the correlation coefficient between both variables. You can do that manually using the formula:

[tex]r=\frac{\Sigma x_1x_2-\frac{(\Sigma x_1)(\Sigma x_2)}{n}}{\sqrt[]{\lbrack\Sigma x^2_1-\frac{(\Sigma x_1)^2}{n}\rbrack\lbrack\Sigma x^2_2-\frac{(\Sigma x_2)^2}{n}\rbrack}}[/tex]

First, let's determine the sums

X₁: Height (in)

[tex]\begin{gathered} \Sigma x_1=20+30+40+40+70+90 \\ \Sigma x_1=290 \end{gathered}[/tex][tex]\begin{gathered} \Sigma x^2_1=20^2+30^2+40^2+40^2+70^2+90^2 \\ \Sigma x^2_1=17500 \end{gathered}[/tex]

X₂: Length (in)

[tex]\begin{gathered} \Sigma x_2=18+16+15+16+9+4 \\ \Sigma x_2=78 \end{gathered}[/tex][tex]\begin{gathered} \Sigma x^2_2=18^2+16^2+15^2+16^2+9^2+4^2 \\ \Sigma x^2_2=1158 \end{gathered}[/tex][tex]\begin{gathered} \Sigma x_1x_2=(20\cdot18)+(30\cdot16)+(40\cdot15)+(40\cdot16)+(70\cdot9)+(90\cdot4) \\ \Sigma x_1x_2=3070 \end{gathered}[/tex]

There are 5 ordered pairs, so the sample size is n=6

Replace every value on the formula:

[tex]\begin{gathered} r=\frac{3070-\frac{290\cdot78}{6}}{\sqrt[]{\lbrack17500-\frac{290^2}{6}\rbrack\lbrack1158-\frac{78^2}{6}\rbrack}} \\ r=\frac{3070-3861}{\sqrt[]{3483.33\cdot144}} \\ r=-0.99 \\ \end{gathered}[/tex]

The correlation coefficient is r= -0.99

→ r is a negative value, which means that the correlation between the height and length of the rectangles is negative

→ the absolute value of the coefficient is greater than 0.90; | r | =0.99, so the correlation between both variables can be considered as a strong correlation

You can say the there is a strong negative correlation between both variables (option F)


Related Questions


Describe how to transform the graph of g(x) - Inx into the graph of f(x)- In(x-4)+3

Answers

To transform the graph of g(x) = lnx into the graph of of f(x) = ln(x-4) + 3 we have to translate 4 units to the right and 3 units up.

What is graph transformation?

The technique of altering an existing graph or graphed equation to create a different version of the following graph is known as graph transformation.

As given in the question,

Parent function  g(x)=ln x

resultant function  f(x)=ln(x-4)+3

By the translation rules :

If f(x) needs to be translated in f(x-h), it mean function shifted right by h unit

and if f(x) needs to be translated in f(x)+k it mean function shifted up by k unit.

As per these rules, graph of  g(x) = lnx function shifted right by 4 unit and function shifted up by 3 unit.

Therefore, Translate 4 units to the right and 3 units up.

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help meeeeeeeeeeeeeee pleaseeeeeee

Answers

Answer: Width = 4.7 meters, Length = 6.7 meters

Step-by-step explanation:

Let the width be [tex]w[/tex]. It follows that the length is [tex]w+2[/tex].

[tex]w(w+2)=32\\\\w^2+ 2w-32=0\\\\w=\frac{-2 \pm \sqrt{2^2 -4(1)(-32)}}{2(1)}\\\\w \approx 4.7 \text{ } (w > 0)\\\\\implies w+2 \approx 6.7[/tex]

is something is greater than 6 , do i include 6

Answers

Answer:

No, 6 will not be included

Explanation:

Let the number greater than 6 be represented by x

The statement "x greater than 6" can be written as:

x > 6

Therefore, 6 will not be included in the list

1.2 where was the Declaration of Independence signed

Answers

August 2, 1776, in the Pennsylvania State House.

Step-by-step explanation:After much debate, the Second Continental Congress ultimately agreed to the Declaration of Independence, and then signed it

d) The diagonal of a rectangular garden measures 11½ m while its width measures 7m. Express the perimeter of the garden as a percentage of its area (3marks).​

Answers

We need to know about area and perimeter of a rectangle to solve the problem. The perimeter of the garden as a percentage of its area is 50.5%

The perimeter of a rectangle is the total of all it's sides. The perimeter can be calculated by adding up the sides of the rectangle. The area of a rectangle can be calculated by multiplying the length with the breadth of the rectangle. The diagonal and width of a rectangle are given, we need to find the length using Pythagoras' theorem.

diagonal =11.5m

width=7 m

length=[tex]\sqrt{11.5^{2} -7^{2} }[/tex]=[tex]\sqrt{132.25-49} =\sqrt{83.25}[/tex]=9.12 m

perimeter=2x(l+b)=32.24 m

area= lxb= 9.12x7=63.84 [tex]m^{2}[/tex]

perimeter as percentage of area=32.24/63.84 x100=50.5%

Therefore the perimeter of the rectangle as a percentage of area is 50.5%.

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Given ∠3≅∠13, which lines, if any, must be parallel based on the given information? Justify your conclusion. Responses a∥b, Converse of the Alternate Interior Angles Theorem a is parallel to b, , Converse of the Alternate Interior Angles Theorem c∥d, Converse of the Same-Side Interior Angles Theorem c is parallel to d, , Converse of the Same-Side Interior Angles Theorem c∥d, Converse of the Corresponding Angles Theorem c is parallel to d, , Converse of the Corresponding Angles Theorem not enough information to make a conclusion not enough information to make a conclusion Two horizontal, parallel lines, line c and line d, where line c is above line d. These lines are intersected by two diagonal parallel lines, line a and line b. Line a is to the left of line b. The angles created by each intersection are numbered. From top left, going clockwise, the angles where line a intersects line c are labeled eleven, ten, nine, and twelve. The angles where line b intersects line c are labeled seven, six, five, and eight. The angles where line a intersects line d are labeled fifteen, fourteen, thirteen and sixteen. The angles where line b intersects line d are labeled three, two, one and four.

Answers

The order of the arrangement of the angles in the question (see attached drawing based on a similar question on the website, created with MS Word) indicate that the angles ∠3 and ∠13 are congruent. The correct option is therefore;

a║b, Converse of the Alternate Interior Theorem

What are congruent angles?

Congruent angles are angles that have the same measure.

The lines that must be parallel, such that ∠3 ≅ ∠13 is indicated by the definition of the relationship between ∠3 and ∠13 as follows;

Statement      [tex]{}[/tex]                                                          Reason

1. ∠3 ≅ ∠13                 [tex]{}[/tex]                                             1. Given

2. ∠3 and ∠13 are alt int. ∠s[tex]{}[/tex] between a and b     2. Definition

3. Line a is parallel to line b                    [tex]{}[/tex] 3. Conv of the alt int. ∠s theorem    

The lines that must be parallel are line a and line b

The reason for the conclusion is based on the converse of the alternate interior angles theorem as follows;

Angle ∠3 and angle ∠13 are alternate interior angles, which are angles located on the inside and on the opposite sides of the common transversal of two lines.

The converse of the alternate interior angles theorem state that if the alternate interior angles formed between two lines, a and b and their common transversal are congruent, then the two lines, a and b are parallel (a ║ b).

The correct option is therefore;

a ║ b, Converse of the Alternate Interior Angles Theorem

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Can you please help me out with a question

Answers

[tex]\begin{gathered} \sin ce\text{ the diameter of marble is given then the marble is a sphere} \\ \text{from the question;} \\ \text{diameter = 62mm, this implies } \\ \text{radius = }\frac{62}{2}\text{ = 31mm} \\ \text{applying the formula for volume of sphere} \\ \text{volume of sphere = }\frac{4}{3}\pi r^3 \\ \text{volume of sphere = }\frac{4}{3}\text{ }\times\text{ }\frac{22}{7}\times31^3 \\ \text{volume of sphere = 124838.48}mm^3 \\ \text{volume of sphere }\cong124,838mm^3\text{ to the nearest cubed millimeter} \\ \\ \text{hence volume of marble = 124, 838mm}^3 \end{gathered}[/tex][tex]\begin{gathered} \sin ce\text{ the marble cracked into equal pieces then} \\ \\ \text{volume of one piece = }\frac{\text{volume of sphere}}{2} \\ \text{volume of one piece = }\frac{124,838}{2}mm^3 \\ \text{volume of one piece = 62,419mm}^3\text{ to the nearest cubed millimeter} \end{gathered}[/tex]

What is the solution to the following system of equations? (1
point)
4x + 2y = 12
x - y = 3
(3,0)
(0, 3)
(0, -3)
(2,3)

Answers

4x + 2y = 12
x - y = 3
x = y + 3

Using substitution to figure out both x and y
4(y+3) + 2y = 12
4y + 12 + 2y = 12
6y = 0
y = 0

x - 0 = 3
x = 3

(x, y)
(3, 0)

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help meeeeeeeeeeeeee pleaseeeeeeeeeee rn rnnnn!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
help meeeeeeeeeeeeee pleaseeeeeeeeeee rn rnnnn!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

The point of maxima and minima of any function can be known by equating its derivative to zero. The rocket will take 1.5 sec to reach the maximum height and the maximum height is 27 feet.

What is differentiation?

The differentiation of a function is defined as the rate change of its value at around a point. It can be written in mathematical form as g'(x) = (g(x + h) - g(x)) /(x + h - x).

Its geometric meaning is that it is the slope of the function at a given point.

Given that,

Initial height of the launching pad is 4 feet,

Initial velocity of rocket is 48 feet/sec,

Height of the rocket as a function of time, h(t) = -16t² + 48t + 3

In order to find the time for maximum height equate h'(t) = 0 as follows,

-32t + 48 = 0

⇒ t = 48 / 32

⇒ t = 3 / 2

⇒ t = 1.5

To find the maximum height find h(t) for t = 1.5 as follows,

h(1.5) = -16 × 1.5² + 48 × 1.5 + 3

= -36 + 60 + 3

= -36 + 63

= 27

Hence, the time taken by the rocket to reach the maximum height is 1.5 sec and the maximum height reached is 27 feet.

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1. MOVIES By the end of its first week, a
movie had grossed $2.3 million. By the
end of its sixth week, it had grossed
$6.8 million. Graph the data with the
week on the horizontal axis and the
revenue on the vertical axis, and draw a
line through the points. Then find and
interpret the slope of the line.
10
Revenue (millions of dollars)
OU
0 2 4 6 8 10
Week

Answers

0.9

The first step is to label the points being (1,2.3),(6,6.8) in which the first ordered pairs is the number of weeks, and the second one is the dollars in millions.

Hence, the slope is: m=(6.8-2.3)/(6-1) = 4.5/5 = 9/10 = 0.9

The slope represents the dollar rate in the millions per week. In this case, the movie grossed $0.9 million per week from week one to the sixth week.

Please explain cos-cot equations. Then I would like to figure out the rest.If sin θ=3/5 and θ is in quadrant II, thencos(θ)=________ ;tan(θ)=________ ;cot(θ)=_________;sec(θ)=_________;csc(θ)=_________;Give exact values.

Answers

Remember that the sine of an angle in a right triangle is equal to the quotient between the side opposite to the angle and the hypotenuse of the triangle.

Since the sine of the given angle θ is equal to 3/5, we can represent θ as part of a right triangle whose hypotenuse has a measure of 5 and the side opposite to θ has a measure of 3:

The length of the side adjacent to θ must be equal to 4 in order to satisfy the Pythagorean Theorem:

[tex]3^2+4^2=5^2[/tex]

On the other hand, the cosine of an angle is defined as the quotient between the side adjacent to the angle and the hypotenuse of the triangle. Then, the cosine of θ must be equal to 4/5:

[tex]\cos \theta=\frac{4}{5}[/tex]

The rest of the trigonometric relations are defined in terms of the sine and the cosine as follows:

[tex]\begin{gathered} \tan \theta=\frac{\sin \theta}{\cos \theta} \\ \cot \theta=\frac{\cos \theta}{\sin \theta} \\ \sec \theta=\frac{1}{\cos \theta} \\ \csc \theta=\frac{1}{\sin \theta} \end{gathered}[/tex]

Since sinθ=3/5 and cosθ=4/5, then:

[tex]\begin{gathered} \tan \theta=\frac{3}{4} \\ \cot \theta=\frac{4}{3} \\ \sec \theta=\frac{5}{4} \\ \csc \theta=\frac{5}{3} \end{gathered}[/tex]

The price for five pounds of
candy is $8. How much does it cost for
one pound?

Answers

Answer:

1.60

8/5=1.60

Step-by-step explanation:

Answer: $1.60

Step-by-step explanation: Easy, just divide 8 by 5.      8/5 = 1.6

What is the range of this relation?

Answers

Answer: (-9, -3, -2, 6, 8)

Step-by-step explanation:

Directions: Simplify by combining like terms in each of the following expressions.
1. 10s2 + 10s2 - 13st =
2. 13st + - 2st - t2 =
3. x2+ x2 + x3 =
4. 6 x - 6 x + 2 =
5. 24x - 3s - 4t =
6. 86 + 86x - 1 =
7. 4x + 3x - 2 =
8. 7s - 4s + 3s =
9. 12 +11x - 10 x =
10. 12x + 24 x - 3 x - 4 =
11. 16t + 8t - 12t =
12. 17g + 19g - 2g +g =
13. 16 + 16 -16 + 16x =
14. 4s - 3s + 3s =
15. 12t - 11t + t =

(math is my weakest subject pls help 22 points)

Answers

A method that is frequently used to make algebraic expressions simpler.

How to simplify expressions?

A method that is frequently used to make algebraic expressions simpler.

1. 10s2 + 10s2 - 13st =s*(20s-13t)

2. 13st + - 2st - t2 = 11st-t2

3. x2+ x2 + x3 = 2x2+x3

4. 6 x - 6 x + 2 =2

5. 24x - 3s - 4t =24x - 3s - 4t

6. 86 + 86x - 1 =86x+85

7. 4x + 3x - 2 = 7x-2

8. 7s - 4s + 3s = 6s

9. 12 +11x - 10 x =x+12

10. 12x + 24 x - 3 x - 4 =33x-4

11. 16t + 8t - 12t =12t

12. 17g + 19g - 2g +g =35g

13. 16 + 16 -16 + 16x = 16+16x

14. 4s - 3s + 3s =4s

15. 12t - 11t + t =2t.

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ame of the
GXIS.
4. Practice: Organizing Information (3 points)
Fill in the blanks.
The factory is operational for at most 12 hours a day. A reasonable domain for
the graph of daily energy use would be <__x___

Answers

A domain of the situation is given by:

The factory is operational for at most 12 hours a day.

[tex]0\leq x\leq12[/tex]

Answer:

[tex]0\leqslant x\leqslant12[/tex]

please help asap if you help i'll give brainilist. Two pieces of metal measure one and one sixth yards and three twelfths yards each. Three times the amount of metal is needed for a project. How many total yards of metal is needed?

four and one quarter yards
four and one sixth yards
one and one quarter yards
one and ten eighteenths yards

Answers

Answer:

Step-by-step explanation:

four and one quarter yards. explanation: add 1 1/6 + 3/12 = 1 5/12. now, multiply that by 3.

Using the arithmetic operations the total yards of metal is needed 4(1/4).

What is arithmetic operation?

The study and application of numbers in all other branches of mathematics is the focus of the branch of mathematics known as arithmetic operations. In essence, it consists of addition, subtraction, multiplication, and division operations.

According to the given:

First pieces of metal =  1 (1/6)

                                 = 7/6

Then Second pieces of metal = 3/12

Adding both the pieces, we have

=7/6 + 3/12

= (14 + 3)12

= 17/12.

now multiply that by 3.

We get,

= (17/12)3

= 17/4

= 4(1/4)

Using the arithmetic operations the total yards of metal is needed 4(1/4).

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A rectangular prism has a width of 4 cm, a height of 3 cm and a depth of 5 cm. What is the volume of the prism?

Answers

We have that the equation of the volume of a rectangular prism is:

[tex]V=w\cdot h\cdot d[/tex]

in this case, we have the following information:

[tex]\begin{gathered} w=4\operatorname{cm} \\ h=3\operatorname{cm} \\ d=5\operatorname{cm} \end{gathered}[/tex]

then, using the formula we have:

[tex]\begin{gathered} V=4\cdot3\cdot5=12\cdot5=60 \\ V=60\operatorname{cm}^3 \end{gathered}[/tex]

therefore, the volume of the prism is 60 cm^3

Given h(x) = 4x - 4, solve for x when h(x) = 0

Answers

Answer: 1

Step-by-step explanation:

Well, what they have asked is to find the zero of this equation, or the value of the variable when the equation is equal to 0.

So, h(x) = 4x-4 = 0

4x = 4

x = [tex]\frac{4}{4}[/tex]

x = 1

Using the paths shown, how long is the shortest route from Hampton to Lexington?

Answers

In this case, we have to add mixed numbers to find the shortest path from the shown alternatives. We need to work with mixed numbers, fractions, and even decimals.

To answer this question, we know that:

1. The path from Hampton to Middletown is 8 + 1/4 mi.

2. Now, we have two alternatives to go from Middletown to Campbell:

First, we have a path that is equivalent to 6 + 1/8 mi (direct). On the other path, we need to go from Middletown to Danville, and then to Campbell. The measure of the latter path is then:

[tex]3\frac{3}{8}+3\frac{3}{8}=(3+\frac{3}{8})+(3+\frac{3}{8})=(\frac{8\cdot3+3\cdot1}{8})+(\frac{8\cdot3+3\cdot1}{8})[/tex]

Thus, we have:

[tex]\frac{(24+3)}{8}+\frac{(24+3)}{8}=\frac{27+27}{8}=\frac{2\cdot(27)}{8}=\frac{2}{8}\cdot27=\frac{1}{4}\cdot27=\frac{27}{4}[/tex]

Which is equivalent to:

[tex]\frac{27}{4}=\frac{24}{4}+\frac{3}{4}=6+\frac{3}{4}=6\frac{3}{4}=6.75mi[/tex]

If we compare the measures of the two paths, we have that:

a. The path from Middletown to Campbell (directly) is equal to:

[tex]6\frac{1}{8}=6+\frac{1}{8}=6.125mi[/tex]

b. The path from Middletown to Danville, and then from Danville to Campbell is equal to 6.75 miles (it is longer).

Therefore, the shortest path, in this part of the "journey", is equal to 6.125 miles or 6 + 1/8 miles.

Now, the complete measure of the path from Hamptom to Lexington is the sum of:

1. The measure of the path from Hamptom to Middletown (8 + 1/4 miles) plus

2. The measure of the path from Middletown to Campbell (6 + 1/8 miles) (directly) plus

3. The measure of the path from Campbell to Lexington (5 + 3/4 miles).

And this is, numerically, as follows:

[tex](8+\frac{1}{4})+(6+\frac{1}{8})+(5+\frac{3}{4})=8+6+5+\frac{1}{4}+\frac{3}{4}+\frac{1}{8}[/tex][tex]19+\frac{4}{4}+\frac{1}{8}=19+1+\frac{1}{8}=20+\frac{1}{8}=20\frac{1}{8}mi[/tex]

We can express the latter result as a fraction as follows:

[tex]20+\frac{1}{8}=\frac{20\cdot8+1\cdot1}{8}=\frac{160+1}{8}=\frac{161}{8}mi[/tex]

Therefore, the shortest route from Hamptom to Lexington is:

1. As a fraction:

[tex]\frac{161}{8}mi[/tex]

2. Or as a mixed number:

[tex]20\frac{1}{8}mi[/tex]

[Notice that we sum two fractions with the same denominator above:

[tex]\frac{1}{4}+\frac{3}{4}=\frac{3+1}{4}=\frac{4}{4}=1[/tex]

.]

a week before the election, based on a random sample of 1200 voters, the support rate for candidate a is 53%. can we assert, with 95% confidence, that candidate a is winning the election (in other words, his support rate is higher than 50%)?

Answers

With 95% confidence, candidate A can win the election within 50.18% and 55.82%.

Probability is the branch of discrete mathematics. It is used for calculating how likely an event is to occur or happen.

According to the question, n = 1200

The support rate for candidate A ([tex]p_{A}[/tex]) = 53% ≅ 0.53

So, [tex]z_{c}[/tex] for 95% confidence = 1.96

Confidence interval for [tex]p_{A}[/tex]

= ( [tex]p_{A}[/tex]   ±   [tex]z_{c}[/tex] ([tex]\sqrt{\frac{p_{A}( 1 - p_{A} ) }{n} }[/tex]) )

= ( 0.53  ±  1.96([tex]\sqrt{\frac{0.53(1-0.53)}{1200} }[/tex]) )

= ( 0.53  ±  1.96([tex]\sqrt{\frac{0.53*0.47}{1200} }[/tex]) )

= ( 0.53  ±  1.96([tex]\sqrt{\frac{0.2491}{1200} }[/tex]) )

= ( 0.53  ±  1.96([tex]\sqrt{0.0002075833}[/tex]) )

= ( 0.53  ±  1.96(0.014407751) )

= ( 0.53  ±  0.028239191 )

= ( 0.53 - 0.02823,0.53 + 0.02823 )

= ( 0.50177,0.55823 )

( 0.50177,0.55823 ) ≅ ( 50.18%,55.82%)

Candidate A can win the election between 50.18% and 55.82% with a confidence level of 95%.

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Determine whether a relation is a function.

Answers

Answer:

so i think id be no

Step-by-step explanation:

if each  input  value  Leads to only  one output  value  that Classify the Relationship  as a Function  tell me if im wrong

anslating Triangle D. (2 pts.)Figure AFigure BSelect all the true statements.A. Figure A is congruent to Figure BB Figure B is a translation of Figure A.C. Triangle C is congruent to Triangle C.D. Triangle D'is congruent to Triangle D.

Answers

According to the problem, the transformation is a translation.

It is important to know that translations are rigid transformations, which means the figures won't change their shape or size. In other words, the images are congruent to the pre-images.

Hence, triangle C is congruent to triangle C', triangle D is congruent to triangle D', but the figures are not congruent because their shape is different.

Therefore, the right answers are B, C, and D.

F(x)=2x and g(x)= sqrt(x+1)Find (fg)(x)

Answers

First, let us define what (fg)(x) is:

[tex](fg)(x)=f(x)\times g(x)[/tex]

Given:

[tex]f(x)=2x[/tex][tex]g(x)=\sqrt[]{x+1}[/tex]

So the solution to (fg)(x) will be:

[tex]\begin{gathered} =2x\times\sqrt[]{x+1} \\ =2x\text{ }\sqrt[]{x+1} \end{gathered}[/tex]

By completing the square , solve x^2+12x-c=0 where c is a positive constant.
Give your answers in surd form in terms of c.
You must show all your working.

Answers

The roots of [tex]x^{2}[/tex] +12x -c = 0 in surd form is -6 ± [tex]\sqrt{c + 36}[/tex]

What is a quadratic equation?

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax2 + bx + c = 0, where a and b are the coefficients of [tex]x^{2}[/tex] and x respectively and c is the constant term.

[tex]x^{2}[/tex] + 12x - c = 0

taking c to the other side, we have

[tex]x^{2}[/tex] + 12x = c

adding the square of half the coefficient of x, which is 6

[tex]x^{2}[/tex] + 12x + [tex]6^{2}[/tex] = c + [tex]6^{2}[/tex]

The left side is now a perfect square which can be simplified as [tex](x + 6)^{2}[/tex]

So,

[tex](x + 6)^{2}[/tex] = c + 36

taking the square root of both sides, we have

x + 6 = [tex]\sqrt{ c + 36}[/tex]

Therefore,

x = -6 ±[tex]\sqrt{c + 36}[/tex]

In conclusion, the solution to the equation is x = -6 ±[tex]\sqrt{c + 36}[/tex]

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ABCD is a rhombus. Find xA) x = 3B) x = 10 D) x = 5C) x = 2

Answers

ANSWER

5

EXPLANATION

The given shape is a rhombus

The sum of interior angles of a rhombus add up to 360 degrees

The opposite angles of a rhombus are equal to each other.

hence, adding up all the interior angles, we have;

[tex]\begin{gathered} 9x+9x+135+135=360 \\ 18x+270=360 \end{gathered}[/tex]

collecting like terms, we have;

[tex]\begin{gathered} 18x=360-270 \\ 18x=90 \\ x=\frac{90}{18} \\ x=5 \end{gathered}[/tex]

Therefore the value of x is 5

Charlie subtracts two polynomials, 5x^2 – 9x^2, and says that the difference proves that polynomials are not closed under subtraction.Kate argues that the difference does in fact show that polynomials are closed under subtraction. Who is correct? Type only 'Charlie' orKate' as your answer in the box.

Answers

Charlie

Here, we want to check if polynomials is closed under subtraction or not

To check this, we proceed either ways, if the answer is same, then it is closed. If otherwise, then it is not

We have;

[tex]\begin{gathered} 5x^2-9x^2=-4x^2 \\ \\ \text{And;} \\ \\ 9x^2-5x^2=4x^2 \end{gathered}[/tex]

As we can see, both results are not equal

If subtraction was closed under polynomials, then the results of both should have been equal. This means Charlie is correct.

Determine the type of triangle that is drawn below.

Answers

⇒ ΔVWX is a Scalene triangle because all the sides and all the angle are not equal.

What is the area of the polygon?
A=
? square units

Answers

Answer:

30 square units.

Step-by-step explanation:

Divide the full polygon into two halves. The left half is 5 wide by 5 tall, making the area of the left 25 square units. The right half is 4 wide by 5 tall, and is perfectly cut in half. We can calculate the area normally, and then cut it in half: (5×4)/2 = 10 square units. Add the two polygons together, totalling 30 square units.

Nate and his family plan to take a 2,438 mile cross-country trip this summer.if they drive 85 miles each day ,how many days will they be driving? explain your answer

Answers

28.68235294117647 days (29 days ) will be taken by nate and his family to take a cross country trip of 2438 miles .

What is division ?

Divide is the polar opposite of multiply. You get four in each group when you divide twelve into three equal groups then multiply three groups of four to create twelve. Determining how many equal groups are formed or how many individuals are in each group following a fair distribution is the fundamental goal of splitting.

Calculation

speed  = 85miles / day

distance = 2438

time = 2438 / 85 = 28.68235294117647 days

learn more about division here :

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What are the rational numbers between 2 & 3

Answers

Answer:

The rational numbers between 2 & 3 include:

1. 4120

2. 4220

3. 4320

4. 4420

5. 4520

6. 4620

7. 4720

8. 4820

9. 4920

10. 5020

Step-by-step explanation:

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