Hi , can you help me please , I did the run and ride the results is y=-4/3x + 4/3. what would the graph look like with ours results?
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Given the equation of a straight line below
[tex]y=-\frac{4}{3}x+\frac{4}{3}[/tex]The general equation of a line,
[tex]y=mx+c_{}[/tex]Where
[tex]\begin{gathered} m\text{ is the slope of the line} \\ c\text{ is the y-intercept} \end{gathered}[/tex]The slope, m, of the given line is
[tex]m=-\frac{4}{3}[/tex]The graph of the equation of the line given is shown below
Hence, the slope of the given equation of a line is, m = -4/3
Related Questions
Consider the sequence below:-2,1,6,13,22, ....What explicit expression can be used to find the nth term of this sequence?
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Answer:
f(n)=n²-3
Explanation:
In the sequence:
[tex]-2,1,6,13,22,...[/tex]First, we find the difference between the terms.
[tex]\begin{gathered} 1-(-2)=3 \\ 6-1=5 \\ 13-6=7 \\ 22-13=9 \end{gathered}[/tex]It is observed that the difference between successive terms is the addition of consecutive odd numbers.
This is an example of a quadratic sequence.
The general form of a quadratic sequence is:
[tex]\begin{gathered} f(n)=an^2+bn+c \\ f(1)=-2 \\ \implies a+b+c=-2 \\ f(2)=1 \\ \implies4a+2b+c=1 \\ f(3)=6 \\ \implies9a+3b+c=6 \end{gathered}[/tex]If we solve the system of equations:
[tex]\begin{gathered} a+b+c=-2 \\ 4a+2b+c=1 \\ 9a+3b+c=6 \\ a=1,b=0,c=-3 \end{gathered}[/tex]The explicit expression for this sequence is:
[tex]f(n)=n^2-3[/tex]The principal is trying to come up with a playground policy to protect students from the risk of getting heatstroke on especially hot and humid days. If that's her goal, at which temperature should students stop being allowed outside for recess?A 80 degrees B 90 degrees C 105 degreesD 130 degrees
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The temperature should be the following:
*Temperatures greater than 80° on hot or humid days should be the temperature limit.
Write the function in slope intercept form Maya wants to rent a bike at the beach The cost includes a rental fee and a price per half hour
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A line equation can be written in slope-intercept form, which is
[tex]y=mx+b[/tex]Where m represents the slope and b the y-intercept.
We can find the slope and y-intercept of our line by using two points from the graph and solving the system. I'm going to use (0, 10) and (2.5, 20), but you can use any pair of points that belong to the line.
From the first point we already have our y-intercept, if we substitute this point at the slope-intercept form we have
[tex]10=m\cdot0+b\Rightarrow b=10[/tex]Using this value for b in our form and using the second point, we can find our slope
[tex]\begin{gathered} 20=2.5m+10 \\ 10=2.5m \\ \frac{10}{2.5}=m \\ m=4 \end{gathered}[/tex]This means that our line equation is
[tex]y=4x+10[/tex]NO -6 -10 Use the graph to complete the function table. Input Output -7 1 5 Submit
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In order to complete the function table, we just need to locate the input values in the x-axis and then find the corresponding values of y in the line.
For x = -7, we have y = 9
For x = 1, we have y = -3
For x = 5, we have y = -9
So the output values for the table are
You invest $3,150.00 in a stock plan. The first year, it loses 5% of its value. The second year, it gains 9% of its value. What is the difference between the value of your stocks at the end of the second year and your initial investment?
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Given:
The investment is $3,150.00.
The loss percent for the first year is 5 %.
The gain percent for the second year is 9 %.
Required:
We need to find the investment amount at end of the second year.
Explanation:
The investment amount at the end of the first year is
[tex]=3150(1-\frac{5}{100})[/tex][tex]=3150(1-0.05)[/tex][tex]=2992.5[/tex]The investment amount at the end of the first year is $2992.5.
The investment amount at the end of the second year is
[tex]=2992.5(1+\frac{9}{100})[/tex][tex]=2992.5(1+0.09)[/tex][tex]=3261.825[/tex][tex]=3261.83[/tex]The investment amount at the end of the second year is $3261.83.
Final answer:
The investment amount at the end of the second year is $3261.83.
I am in alternative school I am a 12th grader I dropped out Beginning 10th grade then came back to school 12th grade I have applied math I have no clue what I'm doing I'm scared for my finals in May I need help
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we have the expression
4÷5×6+7×55
Remember that
Applying PEMDAS
P ----> Parentheses first
E -----> Exponents (Powers and Square Roots, etc.)
MD ----> Multiplication and Division (left-to-right)
AS ----> Addition and Subtraction (left-to-right)
so
step 1
Multiplication and Division (left-to-right)
5x6=30
7x55=385
substitute in the given expression
4÷30+385
step 2
Multiplication and Division (left-to-right)
4÷30=0.13
substitute
0.13+385
step 3
Addition and Subtraction (left-to-right)
0.13+385=385.13
therefore
the answer is 385.13The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).8,20,50,...Find the 10th term.
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Solve for x. Round your awnser to the nearest tenth.
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We are given a right triangle and we have to find the length of one of its sides. It will be useful to remember the definition of the tangent of an angle inside a right triangle. For an angle α<90° in a right triangle we have:
[tex]\tan \alpha=\frac{\text{opposite side}}{\text{adjacent side}}[/tex]If α is the 26° angle in the image then its opposite side is 11 and its adjacent side is x. Then we get:
[tex]\tan 26^{\circ}=\frac{11}{x}[/tex]We can multiply both sides of this equation by x:
[tex]\begin{gathered} \tan 26^{\circ}\cdot x=\frac{11}{x}\cdot x \\ \tan 26^{\circ}\cdot x=11 \end{gathered}[/tex]And we divide both sides by tan(26°):
[tex]\begin{gathered} \frac{\tan 26^{\circ}\cdot x}{\tan 26^{\circ}}=\frac{11}{\tan 26^{\circ}} \\ x=\frac{11}{\tan26^{\circ}}=22.6 \end{gathered}[/tex]Then the answer is 22.6.
In a survey of 100 people, 7 out of every 25 said that Abraham Lincoln was the greatest U.S President. What percent of people surveyed does this represent?
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28%
EXPLANATION
Percentage of people surveyed that said Abraham Lincoln was the greatest U.S president is;
[tex]=\frac{7}{25}\times100[/tex][tex]=\text{ 28 \%}[/tex]Felicia is considering two companies for the installation of her new carpet. The carpet companies installation rates are shown.Carpet Company A: C = 1.35y + 100 where c is the cost and y is the number of square yards.Carpet Company B: This company charges $2.05 per square yard for the carpet and the installation.Identity the unit rate in dollars per square yard for each carpet company.Part 2 is asking me "Which company has the greatest rate of change? Explain how this would affect the slope when graphed on a coordinate plane"
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The cost for a unit square yard is given as:
Company A = $101.35 per square yard
Company B charges $2.05 per square yard
Company B has the greatest slope. The line for Company B is steeper as a result of this.
Explanation:Company A:
C = 1.35y + 100
The cost for a unit square yard is given as:
C = 1.35(1) + 100
= $101.35
Company B charges $2.05
Part 2
Company B has the greatest slope. The line for Company B is steeper as a result of this.
what theorems or postulates could you use to prove this relationship
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From the diagram given, we can see that line a is parallel to line b. This means that the position of each of the angle on line a is equal to the position of each of the angle in line b
From the figure <1 = <(7x+19)degree (corresponding angle). Also <5 = 7x+19 = <1 (corresponding angle as well)
From the above, we can say that <5 = <1 and since <5 and <6 lies on the same stright line, their sum will be 180.
Don't forget that <5 is now replaced as <1. Hence <1+<6 = 180 (supplementary angle).
From the expalnation above, the theorems that was used to prove the relationship between <1 and <6 are supplementary angle, corresponding angle and same side interior angle
Hence option D is correcct
two segments are interesting outside the circle, choose the correct equation to set up before having to solve for y
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Option (C)
Given:
Two segments are interesting outside the circle.
The objective is to find the correct equation.
Since the two lines drawn from a point outside the circle passes through two points in a circle, the line is call secant line.
Consider the given figure as,
If two secant line is drawn from a point outside the circle, the equation wil be,
[tex]a(a+b)=c(c+d)[/tex]Now, substitute the given values in the above formula,
[tex]\begin{gathered} 4(4+6)=2(2+y) \\ 4(10)=2(2+y) \end{gathered}[/tex]Hence, option (C) is the correct answer.
Sec 0=9/4, 0 in quadrant 4. Find tan 0. Show your work
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Determine the value of angle theta.
[tex]\begin{gathered} \sec \theta=\frac{9}{4} \\ \theta=\sec ^{-1}(\frac{9}{4}) \\ =296.3878\text{ (As }\theta\text{ lie in fourth quadrant)} \end{gathered}[/tex]Determine the value of tan theta.
[tex]undefined[/tex]A recipe uses 111cups of milk to make 10 servings. If the same amount of milk is used foreach serving, how many servings can be made using 1 gallon of milk?Show your work.ka1 pint = 2 cups1 quart = 2 pints1 gallon = 4 quartsHelp!
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1 gallon --------------------- 4 quarts
1 quarts ------------------- 2 pints
4 quarts --------------- x
x = 8 pints
1 pints ------------------------ 2 cups
8 pints ---------------------- x
x = 16 cups
1.25 cups ----------------------- 10 servings
16 cups ------------------------ x
x = 12.8 servings
It is possible to made 12.8 servings
The area of the entire figure below is 111 square unit.The area of the entire figure below is 111 square unit.
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Looking at the image, the width of the rectangle is 7 small rectangles and the length is 9 small rectangles, therefore the area of 1 square unit is equal to 9 * 7 = 63 small rectangles.
From these small rectangles, an area of 5 * 4 = 20 small rectangles is shaded.
Therefore the shaded area is calculated as:
[tex]\frac{20}{63}\cdot1\text{ square unit}=\frac{20}{63}\text{ of a square unit}[/tex]A 20% tip on a $26.00 dinner bill ishow much money?
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Mela, this is the solution:
Dinner bill = $ 26
Tip = 20% or 0.2
Tip = 26 * 0.2
Tip = $ 5.20
Find the greatest common factor of the following terms. 20x^5,80x^6, and 30x
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Answer:
10x
Explanation:
Given the terms: 20x⁵, 80x⁶, and 30x
In order to find the greatest common factor, express each of the terms as a product of its factors.
[tex]\begin{gathered} 20x^5=10x\times2x^4 \\ 80x^6=10x\times8x^5 \\ 30x=10x\times3 \end{gathered}[/tex]Observing the three products, 10x is the only common factor,
Therefore, the greatest common factor is 10x.
PLEASE HELP!!!
As part of a major renovation at the beginning of the year, Atiase Pharmaceuticals, Incorporated, sold shelving units (recorded as Equipment) that were 10 years old for $800 cash. The shelves originally cost $6,400 and had been depreciated on a straight-line basis over an estimated useful life of 10 years with an estimated residual value of $400.
1. Complete the table below, indicating the account, amount, and direction of the effect on disposal. Assume that depreciation has been recorded to the date of sale. (Enter any decreases to Assets, Liabilities, or Stockholders' Equity with a minus sign. Do not round intermediate calculations.)
ASSETS = LIABILITIES + STOCKHOLDERS' EQUITY
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The total asset account balance is $400 and total liabilities and stockholders’ equity balance is $400.
Given that,
Aliases Pharmaceuticals, Incorporated sold shelving units (recorded as Equipment) that were ten years old for $800 cash as part of a significant upgrade at the beginning of the year. The shelves had a $6,400 initial cost that had been straight-line depreciated over a 10-year anticipated useful life, leaving a $400 estimated residual value.
What is Accounting equation?It is the relationship among the assets, liabilities and stockholders’ equity. Total liabilities, as well as stockholders' equity, equal total assets. This equation states that an increase in assets will result in an increase in either liabilities or owners' equity. The accounting equation is solved using the formula below.
Assets = Liabilities +Stockholders equity
Calculate accumulated depreciation for 10 years.
Accumulated depreciation for 10 years=[(Original cost of the equipment-Residual value) / Useful life] ×10 years
=[($6400-$400)/10 years]×10 years
=$600×10 years
=$6000
Calculate book value of equipment.
Book value equipment=Original cost of the equipment-Accumulated depreciation for 10 years
=$6400-$6000
=$400
Calculate gain on sale of equipment.
Gain on equipment sale equals selling price minus book value of equipment
=$800-$400
=$400
Therefore, the total asset account balance is $400 and total liabilities and stockholders’ equity balance is $400.
The table we can see in the picture.
To learn more about liability visit: https://brainly.com/question/18484315
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Solve the following logarithmic equation. Express all solutions in exact form.√log x-3 =log x-3
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Square both side of equation and simplify the equation.
[tex]\begin{gathered} (\sqrt[]{\log x-3})^2=(\log x-3)^2 \\ \log x-3=(\log x)^2-6\log x+9 \\ (\log x)^2-6\log x-\log x+9+3=0 \\ (\log x)^2-7\log x+12=0 \end{gathered}[/tex]Assume log x = y. So equation is,
[tex]y^2-7y+12=0[/tex]Simplify the equation to obtain the value of y.
[tex]\begin{gathered} y^2-7y+12=0 \\ y^2-4y-3y+12=0 \\ y(y-4)-3(y-4)=0 \\ (y-3)(y-4)=0 \\ y=3,4 \end{gathered}[/tex]So the value of y is 3 or 4,
[tex]\begin{gathered} \log x=3 \\ x=e^3 \end{gathered}[/tex]Or
[tex]\begin{gathered} \log x=4 \\ x=e^4 \end{gathered}[/tex]I have 2 sets of numbers and need to calculate the percentage between them.
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It is 0.696% for Part A, and 0.634% for Part B
Male students are more represented in Part A.
Explanation:Given that there are 19100 students.
For Part A, the percentage of male students is part A is:
[tex]\begin{gathered} \frac{\text{Sum of male students in part A}}{\text{Total male students}} \\ \\ =\frac{133}{19100}\times100 \\ \\ =0.696 \end{gathered}[/tex]For Part A, the percentage of male students is part B is:
[tex]\begin{gathered} \frac{121}{19100}\times100 \\ \\ =0.634 \end{gathered}[/tex]10c - 6(2c - 1) = -2( c- 3) Your answer
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10c - 6(2c - 1) = -2( c- 3)
[tex]10c-6\left(2c-1\right)=-2\left(c-3\right)[/tex]in this case, we have a equation with an unknown value (c9
Step 1
operate to eliminate ()
[tex]\begin{gathered} 10c-(6\cdot2c)-(6)(-1)=-2c+6 \\ 10c-12c+6=-2c+6 \\ 10c-12c+2c=6-6 \\ 12c-12c=0 \\ 0=0 \end{gathered}[/tex]it means, that for any value of x, it will work
this equation has infinite solutions
18, 32Using rounding, what is the best estimate for the product of these numbers?200300600800
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We are given the following two numbers
18 and 32
Using rounding, what is the best estimate for the product of these numbers?
We can round up 18 to 20
We can round down 32 to 30
20×30 = 600
Therefore, the best estimate for the product of 18 and 32 is 600.
Find the product. 1. 9 х 10 4 2 10 5. 2 1 X 12 12
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First, convert into an improper fraction, then operate and simplify:
[tex]\begin{gathered} 3\frac{2}{8}\cdot\frac{9}{10}\rightarrow\frac{3\cdot8+2}{8}\cdot\frac{9}{10}\rightarrow\frac{26}{8}\cdot\frac{9}{10}\rightarrow\frac{13}{4}\cdot\frac{9}{10}\rightarrow\frac{117}{40} \\ \\ 2\frac{4}{10}\cdot\frac{4}{5}\rightarrow\frac{2\cdot10+4}{10}\cdot\frac{4}{5}\rightarrow\frac{24}{10}\cdot\frac{4}{5}\rightarrow\frac{12}{5}\cdot\frac{4}{5}\rightarrow\frac{48}{25} \\ \\ 1\frac{4}{12}\cdot\frac{2}{12}\rightarrow\frac{12+4}{12}\cdot\frac{2}{12}\rightarrow\frac{16}{12}\cdot\frac{2}{12}\rightarrow\frac{4}{3}\cdot\frac{1}{6}\rightarrow\frac{4}{18}\rightarrow\frac{2}{9} \\ \\ 3\frac{2}{3}\cdot\frac{2}{8}\rightarrow\frac{3\cdot3+2}{3}\cdot\frac{2}{8}\rightarrow\frac{11}{3}\cdot\frac{1}{4}\rightarrow\frac{11}{12} \end{gathered}[/tex]I can’t figure this out. Getting different answer than listed. Please help with attached pic.
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Solution
We are required to use synthetic division to rewrite the expression
[tex](x^3+6x^2-5)\div(x+2)[/tex]The synthetic division is shown below
Re-write the result in polynomial form
[tex]=x^2+4x-8+\frac{11}{x+2}[/tex]The answer is
[tex]=x^2+4x-8+\frac{11}{x+2}[/tex]how many marriage licenses were issued in 2006 ? round answer to the nearest hundred
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To solve the exercise we have to replace the value requested on the equation given to model the problem as above
[tex]y=3.4905(2006)^2-17674(2006)+21533000=124853.658[/tex]As we see and approximating the result to the options, we get that the correct answer is the second one (124900)
Triangles RTS and XYZ are similar. Match each given side of triangle XYZ with the corresponding side on triangle RTS. R À À S TY YZ XY 111 XZ :: RS :: RT :: TS hp
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we know that
if the triangles are similar, thrn itcs corresponding sides are proportional
so
In this problem
the corresponding sides are
YZ and TS
XY and RT
XZ and RS
Enter an equation in standard form to model the linear situation.A bathtub that holds 52 gallons of water contains 17 gallons of water. You begin filling it, and after 5minutes, the tub is full
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First step is to find the slope of the linear situation
Use (0,17) and (5,52) as the given points
[tex]m=\frac{52-17}{5-0}=\frac{35}{5}=7[/tex]y intercept is 17, then the linear equation in slope intercept form is
[tex]y=7x+17[/tex]Now, clear 17 from this equation to find the standard form
[tex]\begin{gathered} y=7x+17 \\ -7x+y=17 \end{gathered}[/tex]Which equation could be used to find how many soft drink refills Ryan ordered
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Solution
We are given
Restaurant charge = $16.99
Soft drink refill charge each = $1.75
Ryan paid = C
Let x denotes the number of soft drink refill Ryan ordered, so we have
[tex]16.99+1.75x=C[/tex]Therefore, the answer is
[tex]1.75x+16.99=C[/tex]Given the equation of the straight line AB is 3x+KY=8 where k is a constant. the straight line AB is parallel to the straight line connecting the point P(-1, 6) with the point Q(5, -3). Find the value of k then calculate the x-intercept of the straight line AB
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If we have two parallel lines, than their slopes must be the same.
One way of comparing slopes of linear equations is to write them in the slope-intercept form:
[tex]y=mx+b[/tex]In this form, m is the slope and b is the y-intercept.
So, let's write the first equation in this form:
[tex]\begin{gathered} 3x+ky=8 \\ ky=-3x+8 \\ y=-\frac{3}{k}x+\frac{8}{k} \end{gathered}[/tex]To find the value of k, we can find the slope of the parallel line and compair it to the slope in this equation.
The slope of a line given two points on it can be calculated as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}_{}[/tex]Since we have points (-1, 6) and (5, -3), we can calculate the slope of the parallel line:
[tex]m=\frac{-3-6}{5-(-1)}=\frac{-9}{5+1}=-\frac{9}{6}=-\frac{3}{2}[/tex]Since both lines are parallel, their slopes are the same.
We know that the slope of the first line is -3/k and the second line is -3/2, so, since they are parallel:
[tex]\begin{gathered} -\frac{3}{k}=-\frac{3}{2} \\ -3\cdot2=-3\cdot k \\ 2=k \\ k=2 \end{gathered}[/tex]Since we have the value for k, we can substitute it into the equation for AB:
[tex]\begin{gathered} y=-\frac{3}{k}x+\frac{8}{k} \\ y=-\frac{3}{2}x+\frac{8}{2} \\ y=-\frac{3}{2}x+4 \end{gathered}[/tex]To find the x-intercept, we can see that it happens when the value of y is equal to 0, so we can plug in y = 0 and find the value of x:
[tex]\begin{gathered} y=0 \\ 0=-\frac{3}{2}x+4 \\ \frac{3}{2}x=4 \\ x=\frac{2}{3}\cdot4 \\ x=\frac{8}{3} \end{gathered}[/tex]So, the value of k is 2 and the x-intercept is 8/3.
Find AB if BC is 20 and AD is 24
Answers
BC = 20
If < B = 67
Then
Th using the sine rule
[tex]\frac{\sin\text{ 67}}{AB}=\frac{\sin 46}{20}[/tex]cross -multiply
[tex]AB\text{ sin 46=20sin67}[/tex]Divide both-side of the equation by sin46
[tex]AB\text{ =}\frac{20\sin 67}{\sin 46}[/tex][tex]AB\approx25.59[/tex]