The solution:
Representing the given problem in a diagram, we have:
- Gross pay: $38,550; married,
2 dependents; state income tax rate:
3 percent.
Answer:
Step-by-step explanation:
This is 0% of your total income of $0. 0% would also be your average tax rate. Your income puts you in the 0% tax bracket. At higher incomes, exemptions, many deductions and many credits are phased out. This increases your tax bill and your marginal tax rate. With these phase outs, adding $1,000 to your income would result in a 0% marginal tax rate.
Find a quadratic function with the given vertex ans passing through the given point vertex forn E Vertex (4,5): passes through (1, 2)
The quadratic function forms a parabola. The vertex form of the equation is expressed as
y = a(x - h)^2 + k
Where
h and k are the x and y coordinates of the parabola's vertex. Given that the vertex is (4, 5),
h = 4, k = 5
Substituting these values into the above equation, it becomes
y = a(x - 4)^2 + 5
Given that the parabola passes through the point, (1, 2), we would substitute x = 1 and y = 2 into y = a(x - 4)^2 + 5. It becomes
2 = a(1 - 4)^2 + 5
2 = a * 9 + 5
2 = 9a + 5
9a = 2 -5
9a = - 3
a = - 3/9 = - 1/3
Substituting a = - 1/3 into y = a(x - 4)^2 + 5, the equation would be
[tex]y\text{ = -}\frac{1}{3}(x-4)^2\text{ + 5}[/tex]To find the measure of
You have the following expression:
(2z - 3) + (5z - 6) = 180
in order to solvet the previous expression for z, proceed as follow:
(2z - 3) + (5z - 6) = 180 cancel out parenthesis
2z - 3 + 5z - 6 = 180 simplify like terms left side
7z - 9 = 180 add 9 both sides
7z = 180 + 9
7z = 189 divide by 7 both sides
z = 189/7
z = 27
Hence, the value of z is 27
Next, replace the values of z into the expression for the measureof angle M:
Hence, the measure of angle M is 129°
Find the real part and the imaginary part of the following complex number. - 14 - 14/13
Convert: 3 days = minutes
ANSWER
4320 minutes
EXPLANATION
To convert from days to minutes, first, we have to convert from days to hours. It is known that 1 day has 24 hours, so 3 days have,
[tex]3\text{ }days\cdot\frac{24\text{ }hours}{1\text{ }day}=72\text{ }hours[/tex]Then, we convert from hours to minutes. If 1 hour has 60 minutes,
[tex]72\text{ }hours\cdot\frac{60\text{ }minutes}{1\text{ }hour}=4320\text{ }minutes[/tex]Hence, there are 4320 minutes in 3 days.
[tex] {x}^{2} - [/tex]which could be the missing term in the expression if a factor of the expression is x-2ya) 2xyb) -2yc) [tex] {4y}^{2} [/tex]d)4y
This is a difference of two squares.
If one factor is
[tex]x+2y[/tex]An the other is
[tex]x-2y[/tex]We have that the expression is:
[tex](x+2y)\cdot(x-2y)=x^2-4y^2[/tex]So the missing term is 4y², option c
A group of friends wants to go to the amusement park. They have no more than $225to spend on parking and admission. Parking is $5, and tickets cost $20 per person,including tax. Write and solve an inequality which can be used to determine p, thenumber of people who can go to the amusement park.3Inequality:рSubmit AnswerPrivacy Policy Terms of Service
Answer:
Inequality: 5 + 20p ≤ 225
p ≤ 11
Explanation:
The total cost can be calculated as the sum of the parking and ticket costs. So, we can calculate the total cost as:
5 + 20p
Because 20p represents the total ticket cost for p people.
Then, this total cost should be less than or equal to 225. It means that the inequality that represents the situation is:
5 + 20p ≤ 225
Finally, we can solve the inequality by subtracting 5 from both sides as:
5 + 20p - 5 ≤ 225 - 5
20p ≤ 220
Then, divide both sides by 20, to get:
20p/20 ≤ 220/20
p ≤ 11
So, the number of people who can go to the amusement park is less than or equal to 11.
Therefore, the answers are:
Inequality: 5 + 20p ≤ 225
p ≤ 11
solve the following: a. 1/14 - 3 1/8 b. -7/2x^2y^2. + 5/2xy^2 + 3/x^2yc. -2 1/3 + 1 1/9
First we analyze the denominators
2x^2y^2 is the greatest common factor for all three fractions, now we just divide each denominator with that factor and then multiply the answer by numerators
Then, the new fraction will be:
e)
.............................
step 1
Find out the expected value
In this game, the total possible outcomes are 12
The probability of a win is P=1/12
The probability of loss is P=11/12
so
EV=(1/12)*(30-20)-(11/12)*30
EV=(1/12)*(10)-(11/12)*30
EV=(10/12)-(330/12)
EV=-320/12
EV=-26.67p ----> is negative because is a loss for the players
If 60 people play the game
26.67*60=1,600
therefore
The school expect to raise for charity 1,600p
Divide by 100
1,600p/100=$16Example(-9, -2) (1,3)Find the slopeWrite in point slopeWrite in slope intercept formComplete the same three steps for 50extra points using the points(-6,7)(-3,6)
The slope, m, of a line passing therough the points (x₁, y₁ ) and (x₂, y₂) can be calculated using the formula
[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex]For the points (-9, -2) and (1, 3):
x₁ = -9, y₁ = -2, x₂ = 1, y₂ = 3
Substituting these points into the slope formula given above
[tex]\begin{gathered} m\text{ = }\frac{3-(-2)}{1-(-9)} \\ m\text{ = }\frac{5}{10} \\ m\text{ = }\frac{1}{2} \end{gathered}[/tex]The slope, m = 1/2
The point-slope form of the equation of a line passing through the points (x₁, y₁ ) and (x₂, y₂) can be calculated using the formula
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y\text{ - (-2) = }\frac{1}{2}(x\text{ - (-9))} \\ y\text{ + 2 = }\frac{1}{2}(x\text{ + 9)} \end{gathered}[/tex]The slope-intercept form of the equation will be of the form y = mx + c
Reduce the point-slope form written above to the intercept-slope form
[tex]\begin{gathered} y\text{ + 2 = }\frac{1}{2}(x\text{ + 9)} \\ y\text{ + 2 = }\frac{x}{2}+\text{ }\frac{9}{2} \\ y\text{ = }\frac{x}{2}+\frac{9}{2}-2 \\ y\text{ = }\frac{1}{2}x\text{ +}\frac{5}{2} \end{gathered}[/tex]Round to the nearest hundredth.1.9541
In order to round to the neares hundreth 1.9541, consider that hundreths are the second number after the decimal point, moreover, take into account that the value of such a number depends of the value of the next number (that is, third number after decimal point).
If next number is lower than 5, then, the second number remains the same, if next number is 5 or greater, second number is increased 1 unit.
In this case, the next number is 4, then, second number or hundreths remain the same.
Hence, you have:
[tex]1.9541\approx1.95[/tex]Cara has 42.5 pounds of coffee. If she splits the coffee into 2.5 pound bags, how many bags will she need?A)17B)19C)21D)23
Hello, I need help with this precalculus homework question, please? I just need help with section D for the graph. HW Q3
The answer would be option B
An easy way to see this is to look for the Y-intercept (when X=0)
So:
(13x + 13) / (8x +16) = 13/16 = 0.81
So, which graph has a Y intercept of approximately 0.81? The B
A segment has endpoints A and C. What are two names for the segment? Choose the correct answer below O AC and CA OAC and CA O AC and CA O AC and CA
Given that endpoints of a segment: A and C
The two names for the sgment will be:
AC and CA
ANSWER:
AC and CA
hello I am having difficulty on this problem please help thank you
we have a system of inequalities
Inequality A
[tex]-4x+3y<6[/tex]Isolate the variable y
[tex]\begin{gathered} 3y\lt6+4x \\ y<\frac{4}{3}x+\frac{6}{3} \\ y\lt\frac{4}{3}x+2 \end{gathered}[/tex]The solution to the first inequality is the shaded area below the dashed line y=(4/3)x+2
Inequality B
[tex]4x+7y\leq-7[/tex]Isolate the variable y
[tex]\begin{gathered} 7y\leqslant-7-4x \\ y\leqslant\frac{-7}{7}-\frac{4x}{7} \\ \\ y\leqslant-\frac{4}{7}x-1 \end{gathered}[/tex]The solution to the second inequality is the shaded area below the solid line y=-(4/7)x-1
therefore
The solution to the system of inequalities is the shaded area below the dashed line y=(4/3)x+2 and below the solid line y=-(4/7)x-1
Using a graphing tool
see the attached figure below
Remember that
If an ordered pair is a solution to the system of inequalities
then
the ordered pair must lie in the shaded region of the solution
so
the point (-2,-2) is a solution to the system of inequalities
see the figure below
what is the area of a sector bounded by a 114 arc
Step1: Write out the given parameter
Θ=114°,r= 6ft
Step2; Write out the formula
The area of a sector is given as
[tex]\frac{\theta}{360}\times\pi r^2[/tex]Step3: substitute the parameters into the formula
[tex]\frac{114}{360}\times\pi\times6^2[/tex][tex]\begin{gathered} \frac{114}{10}\pi \\ \frac{57}{5}\pi \end{gathered}[/tex]Hence the area of the sector is (57/5)π interms o
Which of the equations below could be the equation of this parabola?5Vertex(0,0)10A. x = 2y2B. y= 2x2C. y = -2x2O D. x = -2y2
Given:
Vertex = (0,0)
General vertex from of equation is:
[tex]y=a(x-h)^2+k[/tex][tex]\text{vertex = (h,k)}[/tex]So:
h = 0
k = 0
then equation is:
[tex]\begin{gathered} y=a(x-h)^2+k \\ h=0;k=0 \\ y=a(x-0)^2+0 \\ y=ax^2 \end{gathered}[/tex]Here value of "a" is negative because the graph is move downward . and all option give mode value is 2 then the equation of functuion:
[tex]y=-2x^2[/tex]The graph of y = –2/x lies in ____.A. Quadrant I and IIIB. Quadrant I and IIC. Quadrant II and IVD. Quadrant III and IV
In order to find the quadrants of y = -2/x, let's choose a positive and a negative value of x, then we calculate the corresponding values of y and check the quadrants:
[tex]\begin{gathered} x=-2\colon \\ y=-\frac{2}{-2}=1 \\ \\ x=2\colon \\ y=-\frac{2}{2}=-1 \end{gathered}[/tex]The point (-2, 1) is in quadrant II (negative x and positive y) and the point (2, -1) is in quadrant IV (positive x and negative y).
Therefore the correct option is C.
A line is drawn over this rectangle . Is the line a line of symmetry?
Answer:
The line is not a line of symmetry because the two parts are not an exact match when you fold the rectangle over the line.
Explanation:
A line of symmetry is a line that divides the figure into two equal parts, so when you fold the figure over the line, the two parts will match exactly. So, taking into account the figure, the line drawn is not a line of symmetry.
The answer is
The line is not a line of symmetry because the two parts are not an exact match when you fold the rectangle over the line.
Fill in the blank. The set {x|XS - 4.3) written in interval notation is
The given expression is :
[tex]\mleft\lbrace x\mright|x\leq-4.3\}[/tex]In the given expression x is less than equal to - 4.3
so, it's domain will lie from - infinity to - 4.3
Thus :
[tex]\text{ Interval Notation: (-}\infty,-4.2\rbrack[/tex]Answer :
[tex]\text{ Interval Notation: (-}\infty,-4.2\rbrack[/tex]What is the intersection of the sets C = {5, 7, 10, 13, 19) and D = {3, 9, 14, 15}?O null setO (5, 7, 9, 10, 13, 14, 15, 19}O {5, 9, 14)O {3, 19)
We are given the following two sets C and D
C = {5, 7, 10, 13, 19}
what is 10•(-1/2)= ??
For this problem, we are given a product between an integer and a fraction.
The expression is shown below:
[tex]10\cdot(\frac{-1}{2})[/tex]To solve this problem, we need to multiply the two numerators and denominators, then simplify the fraction:
[tex]\frac{-10}{2}=-5[/tex]The result is -5.
a pet store has c tanks of fish. Each tank has 24 fish. Using c, write an expression for the total number of fish in the store
a pet store has c tanks of fish. Each tank has 24 fish. Using c, write an expression for the total number of fish in the store
the equation is equal to
Multiply the number of tanks by 24
so
24c
the answer is 24cPart 2
1/13 is the reciprocal of 13
because
(13)(1/13)=1
a number multiplied by its reciprocal is equal to 1
5/6 year = how many months
We will solve as follows:
We multiply the value we want to know (5/6) times the number of months that are in a year(12 months) and divide it by the number of years 12 months represent:
[tex]m=\frac{(\frac{5}{6})\cdot(12)}{1}\Rightarrow m=10[/tex]So, 5/6 of a year are 10 months.
6. Sheila simplified an expression using the following steps. Which property justifies Step 3?
The distributive property of multiplication is represented by the following expression:
[tex]a\cdot(b+c)=a\cdot b+a\cdot c[/tex]Notice that Sheila uses distributive property to simplify the expression:
[tex]\begin{gathered} 5x+4(3+2x) \\ =5x+4\cdot3+4\cdot2x \\ =5x+12+8x \\ =13x+12 \end{gathered}[/tex]consider the function f(x) whose second derivative is f''(x)=4x+4sin(x). if f(0)=4 and f'(0)=2, what is f(3)?
The amount of money Jeremy makes varies directly with the number of hours he works. Ifhe earns $195 for 3 days of work, how much will he earn if he works 12 days?
Given:
a.) Jeremy earns $195 for 3 days of work.
To be able to determine how much will he earn if he works 12 days, we will be using ratios and proportions.
Let,
x = his earnings if he works for 12 days.
[tex]\text{ 195 : 3 = x : 12}[/tex][tex]\text{ 195 : 3 = x : 12 }\rightarrow\text{ }\frac{\text{ 195}}{3}\text{ = }\frac{\text{ x}}{12}[/tex][tex]\frac{\text{ 195}}{3}\text{ = }\frac{\text{ x}}{12}[/tex][tex]\text{ (195)(12) = (x)(3)}[/tex][tex]\text{ 2,340 = 3x}[/tex][tex]\text{ }\frac{\text{2,340}}{3}\text{ = }\frac{\text{3x }}{3}[/tex][tex]\text{ 780 = x}[/tex]Therefore, he'll earn $780 for working 12 days.
Please help. I’m not sure how to do this. the options are a)1.3b)0.3c) 2.2d)0.4
Step 1
Given;
Step 2
[tex]\begin{gathered} constant=\text{ height}\times width \\ let\text{ us use height=0.2} \\ width=2 \end{gathered}[/tex][tex]constant=0.2\times2=0.4[/tex]Answer;
[tex]0.4[/tex]The following data are the distances from the workplace (in miles) for the 5 employees of a small business.
1. Given that the population data is : 15,5,8,2,5
• number of sample in data , ,n = 5
,• Mean = sum of sample in the data / number of sample
= (15+5+8+2+5)/5
= 35/5
Therefore mean = 7
2. Calculate varience as in the box below:
[tex]\begin{gathered} _{}\text{Varience = }\frac{1}{n}\mleft\lbrace(x_i-\vec{x}\mright)^2 \\ \text{ = }\frac{1}{5}\mleft\lbrace(7-15)^2+(7-5)^2+(7-8)^2+(7-2)^2+(7-5)^2\mright\rbrace \\ \text{ = }\frac{1}{5}\mleft\lbrace(-8^2\mright)+(-2)^2+(-1^2)+(5^2)+(2^2)\} \\ \text{ =}\frac{1}{5}\mleft\lbrace64\text{ + 4+ 1 +25+4}\mright\rbrace \\ \text{ = }\frac{1}{5}(98) \\ \text{ = }\frac{98}{5} \\ \therefore S\tan dard\text{ deviation = }\sqrt[]{varience\text{ }} \\ \text{ = }\sqrt[]{\frac{98}{5}}\text{ } \\ \text{ =4.427} \end{gathered}[/tex]• This means that Standard deviation = 4.43
2. There were 132 students on the field trip. The students were divided into as many groups of 8 as possible. One group was smaller. How many students were in the smaller group? A 17 students B. 16 students C. 8 students D. 4 students
So, there were 132 students divided in groups of 8.
If we divide:
So, there will be 8 groups of 16 and 1 group of 4 students. (The smaller group).