4x - 4y = 20y = -5Solve the system of linear equations by graphing
Answers
The given system of equation:
4x - 4y = 20
y = -5
Plot the equation in the graph
the point at which both the lines meet is the solution of the system of equation:
the graph is :
The lines intersect at (0,-5) i.e x = 0, y = -5
So, the solution of the system of equation is x = 0 & y = -5
Answer:
x = 0
y = -5
Related Questions
¿Qué es 1/3 x5 / 6? ¿Qué es 2/5 x 3/7?
Answers
La primera expresión es
[tex]\frac{1}{3}\times\frac{5}{6}[/tex]Para resolver esta multiplicación de fracciones, tenemos que multiplicar numerador con numerador y denominador con denominador.
[tex]\frac{1\times5}{3\times6}=\frac{5}{18}[/tex]Hence, the first product is 5/18.La segunda expresión es
[tex]\frac{2}{5}\times\frac{3}{7}[/tex]Repetimos el mismo proceso para multiplicar.
[tex]\frac{2\times3}{5\times7}=\frac{6}{35}[/tex]Hence, the second product is 6/35.Which method do you prefer over the others describe the method in your own words and give an example of a quadratic equation that can be solved with the method Please help thanks thanks
Answers
The Solution:
We are required to give an example of a quadratic equation.
Describe a chosen method for solving the quadratic equation.
Solve it using the method you described.
A quadratic equation is an equation in the form:
[tex]ax^2+bx+c=0[/tex]So, an example of a quadratic equation is:
[tex]x^2+x-6=0[/tex]My chosen method of solving the quadratic equation is the Formula Method.
The quadratic formula (also known as Formula Method) is given as
Where
[tex]\begin{gathered} a=\text{ coefficient of x}^2 \\ b=\text{ coefficient of x} \\ c=\text{ constant term} \\ \end{gathered}[/tex]Solving the above quadratic equation using the formula method.
[tex]\begin{gathered} x^2+x-6=0 \\ In\text{ this case} \\ a=1 \\ b=1 \\ c=-6 \end{gathered}[/tex]Substituting these values in the formula, we get
[tex]\begin{gathered} x=\frac{-1\pm\sqrt{1^2-4(1)(-6)}}{2(1)} \\ \\ x=\frac{-1\pm\sqrt{1+24}}{2} \\ \\ x=\frac{-1\pm\sqrt{25}}{2} \\ \\ x=\frac{-1\pm5}{2} \end{gathered}[/tex][tex]\begin{gathered} x=\frac{-1+5}{2}\text{ or }x=\frac{-1-5}{2} \\ \\ x=\frac{4}{2}\text{ or }x=\frac{-6}{2} \\ \\ x=2\text{ or }x=-3 \end{gathered}[/tex]Therefore, the correct answer is x = 2 or -3
in triangle XYZ, point M is the centroid. If XM=8, find the length of MA
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Centroid theorem: the centroid is 2/3 of the distance from each vertex to the midpoint of the opposite side.
For the given triangle:
[tex]XM=\frac{2}{3}XA[/tex]XA is the sum of XM and MA:
[tex]XA=XM+MA[/tex]Use the two equations above to find MA:
[tex]\begin{gathered} XM=8 \\ \\ 8=\frac{2}{3}XA \\ \\ XA=\frac{3}{2}(8) \\ \\ XA=12 \\ \\ \\ 12=8+MA \\ MA=12-8 \\ \\ MA=4 \end{gathered}[/tex]Then, MA is equal to 4Part a: How many pieces are in the step functionpart b: how many intervals make up the step function? What are the interval valuespart c: why do we use open circles in some situations and closed in otherspart e are the pieces of this piecewise function linear or non linear?part f what is the range of this piecewise function?
Answers
a) The step function seen in the figure has 6 pieces, one for each step
b) There are 6 intervals, one for each piece. Their values are:
(0, 1]
(1, 2]
(2, 3]
(3, 4]
(4, 5]
(5, 6]
c) The open circles indicate that the endpoint is not included in the interval. The closed circles indicate the endpoint is included in the interval.
For example, in the second interval, 1 is not included (open circle) and 2 is included (closed circle).
d) This is a function because for eac value of x there iss one and only one of y. If the open circles were closed circles, then thi wouldnot be a function.
e) All the pieces are linear because their graph is a line (flat horizontal line)
f) The range of the function is the set of output values:
Range = {46, 48, 50, 32, 54, 56}
If the lateral areas of two similar prisms are in a ratio of 8 to 18, what is the ratio of the volumes? Enter answers in the same format and order as the original ratio. Round any decimals to the nearest 10th.
Answers
The ration of the lateral areas of the smaller prism to the larger prism is 8 to 18
The first step is t find the scale factor. Recall,
area = square of scale factor
Thus, scale factor = square root of area
Thus,
[tex]\begin{gathered} \text{scale factor = }\sqrt[]{\frac{8}{18}} \\ \text{Dividing the numerator and denominator by 2, we have} \\ \text{scale factor = }\sqrt[]{\frac{4}{9}} \\ scale\text{ factor = 2/3} \end{gathered}[/tex]Volume = cube of scale factor. Thus,
[tex]\begin{gathered} \text{volume = (}\frac{2}{3})^3 \\ \text{Volume = }\frac{8}{27} \\ \end{gathered}[/tex]A city has a population of 300,000 people. Suppose that each year the population grows by 4.5%. What will the population be after 14 years?Use the calculator provided and round your answer to the nearest whole number.
Answers
Given:
Population =300000
Growth rate = 4.5 %.
time = 14 years.
consider the exponential growth equation.
[tex]y=a(1+r)^t[/tex]where a is the initial value and r=growth rate.
Let y be the number of population after t years.
Substitute a=300000, r=4.5/100. t-14 in exponential growth equation, we get
[tex]y=300000(1+\frac{4.5}{100})^{14}[/tex][tex]y=300000(\frac{100}{100}+\frac{4.5}{100})^{14}[/tex][tex]y=300000(\frac{104.5}{100})^{14}[/tex][tex]y=300000(1.045)^{14}[/tex][tex]y=555583.476485[/tex]Hence the population after 14 years is 555584 people.
find the 8th term of geometric sequence where a1=5, r= -2
Answers
for Given:
[tex]\begin{gathered} a_1=5 \\ r=-2 \end{gathered}[/tex]You need to remember that "r" is the Common ratio between the terms of the Geometric Sequence and this is the first term:
[tex]a_1_{}_{}[/tex]The formula the nth term of a Geometric Sequence is:
[tex]a_n=a_1\cdot r^{(n-1)}[/tex]Where "n" is the number of the term, "r" is the Common Ratio, and the first term of the sequence is:
[tex]a_1[/tex]In this case, since you need to find the 8th term, you know that:
[tex]n=8[/tex]Then, you can substitute all the values into the formula:
[tex]a_8=(5)(-2)^{(8-1)}[/tex]Evaluating, you get:
[tex]\begin{gathered} a_8=(5)(-2)^{(7)} \\ a_8=(5)(-128) \\ a_8=-640 \end{gathered}[/tex]Hence, the answer is:
[tex]a_8=-640[/tex]
A probability experiment consist of rolling a 15-sided die. Find the probability of the event below. rolling a number divisible by 6
Answers
SOLUTION
A 15-sided die has 15 faces numbered 1 to 15.
So the total possible outcome is 15.
Of all the numbers from 1 to 15, only 6 and 12 are divisible by 6. Therefore the numbers divisible by 6 is 2.
So the required outcome = 2
Probability =
[tex]\text{Probability = }\frac{required\text{ outcome}}{\text{total possible outcome}}[/tex]So,
[tex]\begin{gathered} \text{Probability = }\frac{required\text{ outcome}}{\text{total possible outcome}} \\ \\ \text{Probability = }\frac{2}{\text{1}5} \end{gathered}[/tex]Give two examples that illustrate the difference between a compound interest problem involving future value and a compound interest problem involving presentvalue.Choose the correct answer below.A. In a compound interest problem involving present value the goal is to find how much money has to be invested initially in order to have a certain amount inthe future. In a problem involving future value the goal is to find how much money there will be after a certain amount of time has passed given an initialamount to invest.B. In a compound interest problem involving present value the goal is to find how much money there will be after a certain amount of time has passed given aneffective annual yield. In a problem involving future value the goal is to find how much money has to be invested initially in order to have a certain effectiveannual yield in the future.OC. In a compound interest problem involving present value the goal is to find how much money there will be after a certain amount of time has passed given aninitial amount to invest. In a problem involving future value the goal is to find how much money has to be invested initially in order to have a certain amountin the future.
Answers
From the list of statements, let's select the examples that illustrate the difference between a compound interest problem involving future value and a compound interest problem involving present value.
Apply the compound interest formula:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Where:
A represents the future value which is the final amount after a given period of time.
P represents the present value which is the initial amount invested.
When you are required to find the present value, the goal is to find how much money has to be invested initially in order to have a certain amount in the future. Here, the future value is always given.
When you are required to find the future value, the goal is to find how much money there will be after a certain amount of time has passed given an initial amount to invest. Here, the present value is always given.
Therefore, the correct examples are:
In a compound interest problem involving present value the goal is to find how much money has to be invested initially in order to have a certain amount in
the future. In a problem involving future value the goal is to find how much money there will be after a certain amount of time has passed given an initial
amount to invest.
ANSWER: A.
In a compound interest problem involving present value the goal is to find how much money has to be invested initially in order to have a certain amount in
the future. In a problem involving future value the goal is to find how much money there will be after a certain amount of time has passed given an initial
amount to invest.
i forgot how i solved this and i need help understanding the second step done by lorne, thank u!
Answers
Given:
[tex](-3x^3+5x^2+4x-7)+(-6x^3+2x-3)[/tex]The second step is writing the terms individually and the addition sign between them, so, we will use the property of the opposite addition
For example, instead of writing: (1 - a), we can write it as 1 + (-a)
So, the expression will be:
[tex](-3x^3)+5x^2+4x+(-7)+(-6x^3)+2x+(-3)[/tex]the top of a rectangular box has an area of 42cm^2. The sides of the box have areas of 30cm^2 and 35cm^2. what are the dimensions of the box?
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We have a rectangular box where we know the area of the faces and we have to find the width w, length l and height h.
The area of the top of the box is equal to the length times the width (l*w) and we also know that it is 42 cm², so we can write:
[tex]l\cdot w=42[/tex]With the same logic, we can write the equations for the other two areas:
[tex]\begin{gathered} l\cdot h=30 \\ w\cdot h=35 \end{gathered}[/tex]NOTE: the area we choose for l or w is indistinct,so we can relate it as we like.
Then, we can solve this system of equations substituting variables as:
[tex]\begin{gathered} l\cdot h=30\longrightarrow l=\frac{30}{h} \\ w\cdot h=35\longrightarrow w=\frac{35}{h} \\ l\cdot w=(\frac{30}{h})(\frac{35}{h})=\frac{1050}{h^2}=42 \\ h^2=\frac{1050}{42} \\ h^2=25 \\ h=\sqrt[]{25} \\ h=5 \end{gathered}[/tex]With the value of h, we can calculate l and w:
[tex]\begin{gathered} l=\frac{30}{h}=\frac{30}{5}=6 \\ w=\frac{35}{h}=\frac{35}{5}=7 \end{gathered}[/tex]Answer:
The dimensions of the box are: length = 6 cm, width = 7 cm and height = 5 cm.
let f(x)=2x+1. write a function g(x) whose grass is a rotation of f (x) about (0,1) by a factor of 3 , followed buy a vertical translation 6 units down
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1) Considering f(x)= 2x+1, And g(x) be f(x) rotated about y=1, with a factor of 3 this
A vertical translation 6 units down= g(x) = 2x -5
A factor of 3: g(x)= 3(2x)-5
write the ratio as a fraction in lowest terms. compare in hours.22 hours to 5 days
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We know 1 day = 24 hours
Let's convert 5 days to hours:
[tex]5\text{days}\times\frac{24\text{hour}}{1\text{day}}=5\times24=120hours[/tex]Now, we have the ratio:
22 hours to 120 hours
We can write it as a fraction:
[tex]\frac{22}{120}[/tex]This is not in its lowest terms. We can divide numerator and denominator by "2", to get:
[tex]\frac{22}{120}=\frac{11}{60}[/tex]Thus, final answer is:
11/60
or
[tex]\frac{11}{60}[/tex]Use the regression calculator to compare the teams’ number of runs with their number of wins.
A 2-column table with 9 rows. Column 1 is labeled R with entries 808, 768, 655, 684, 637, 619, 613, 609, 563. Column 2 is labeled W with entries 93, 94, 66, 81, 86, 75, 61, 69, 55.
What is the y-intercept of the trend line, to the nearest hundredth?
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The y-intercept of the trend line is equal to -23.08.
How to determine the y-intercept of the trend line?In order to determine a linear equation of the trend line that models the data points contained in the table, we would have to use an Excel regression calculator (scatter plot).
In this scenario, the teams’ number of runs would be plotted on the x-axis of the scatter plot while the teams’ number of wins would be plotted on the y-axis of the scatter plot.
On the Excel worksheet, you should right click on any data point on the scatter plot, select format trend line, and then tick the box to display an equation for the trend line on the scatter plot.
From the scatter plot (see attachment) which models the relationship between data points in the table, a linear equation of the trend line is given by:
y = 0.15x - 23.08
In conclusion, a standard linear equation is given by:
y = mx + c
Where:
m represents the slope i.e 0.15.x and y are the points.c represents the y-intercept i.e -23.08.Read more on scatter plot here: brainly.com/question/28605735
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Solve the equation: 3(2y-5)=9 for y
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Applying the distributive property in this case:
[tex]6y-15=9[/tex]Adding 15 at both sides of the equation:
[tex]6y-15+15=9+15\rightarrow6y+0=24[/tex]Then
[tex]6y=24[/tex]Dividing both sides by 6, we finally have:
[tex]\frac{6}{6}y=\frac{24}{6}\rightarrow y=4[/tex]Therefore, the value for y = 4.
(50k³ + 10k² − 35k – 7) ÷ (5k − 4)How do I simplify this problem
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ANSWER :
[tex]10k^{2}+10k+1-\frac{3}{5k-4}[/tex]
EXPLANATION :
From the problem, we have an expression :
[tex](50k^3+10k^2-35k-7)\div(5k-4)[/tex]The divisor is (5k - 4)
Step 1 :
Divide the 1st term by the first term of the divisor.
[tex]\frac{50k^3}{5k}=10k^2[/tex]The result is 10k^2
Step 2 :
Multiply the result to the divisor :
[tex]10k^2(5k-4)=50k^3-40k^2[/tex]Step 3 :
Subtract the result from the polynomial :
[tex](50k^3+10k^2-35k-7)-(50k^3-40k^2)=50k^2-35k-7[/tex]Now we have the polynomial :
[tex]50k^2-35k-7[/tex]Repeat Step 1 :
[tex]\frac{50k^2}{5k}=10k[/tex]The result is 10k
Repeat Step 2 :
[tex]10k(5k-4)=50k^2-40k[/tex]Repeat Step 3 :
[tex](50k^2-35k-7)-(50k^2-40k)=5k-7[/tex]Now we have the polynomial :
[tex]5k-7[/tex]Repeat Step 1 :
[tex]\frac{5k}{5k}=1[/tex]The result is 1
Repeat Step 2 :
[tex]1(5k-4)=5k-4[/tex]Repeat Step 3 :
[tex](5k-7)-(5k-4)=-3[/tex]Since -3 is a number, this will be the remainder.
Collect the bold results we had from above :
(10k^2 + 10k + 1) remainder -3
Note that the remainder can be expressed as remainder over divisor.
That will be :
[tex]\begin{gathered} 10k^2+10k+1+\frac{-3}{5k-4} \\ or \\ 10k^2+10k+1-\frac{3}{5k-4} \end{gathered}[/tex]4y-3x=-16 I need help with this problem and the problem in the picture please help me this work is already late I need to turn it in
Answers
Answer
x = 1.6
y = -2.8
Explanation
The question wants us to solve the simultaneous equation
4y - 3x = -16
8x - 4y = 24
Adding the two equations, we have,
4y - 3x + 8x - 4y = -16 + 24
5x = 8
Divide both sides by 5
(5x/5) = (8/5)
x = 1.6
If x = 1.6,
8 (1.6) - 4y = 24
12.8 - 4y = 24
-4y = 24 - 12.8
-4y = 11.2
y = -2.8
Hope this Helps!!!
The sum of six consecutive integers is -9. What are the integers?
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Therefore the six consecutive integers are -4,-3,-2,-1,0,1 .
What is consecutive integer ?
Integers that follow one another are referred to as consecutive integers. They proceed in a certain order or sequence. For instance, a sequence of natural numbers are all integers. In mathematics, the term "consecutive" refers to an uninterrupted chain of events or a continuous progression, such as when integers follow one another in a sequence where each succeeding number is one more than the one before it. The mean and median are both identical in a collection of successive integers (or in numbers). x + 1 and x + 2 are two consecutive integers if x is an integer.
Here sum of six consecutive integer is -9.
Let us take the 6 consecutive numbers are,
=> x,x+1, x+2, x+3,x+4, x+5
Now sum is -9. Then ,
=> x+x+1+x+2+x+3+x+4+x+5 =-9
=> 6x + 15 = -9
=> 6x = -9-15
=> 6x = -24
=> x = -24/6
=> x= -4
Then 6 integers are ,
=> -4,-3,-2,-1,0,1
Therefore the six consecutive integers are -4,-3,-2,-1,0,1 .
To learn more about consecutive integer
https://brainly.com/question/26352026
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What are the next 4 terms of the sequence 1, 6, 11...?
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The formula to find the sequence is given by:
[tex]a_n=a_1+(n-1)d[/tex]Where a1 is the first term of the sequence, n is the number of terms and d is the common difference. We can find the common difference by the following formula:
[tex]d=a_n-a_{n-1}[/tex]With the given terms of the sequence we can find d:
[tex]\begin{gathered} d=11-6=5 \\ or \\ d=6-1=5 \end{gathered}[/tex]The common difference is d=5.
Now, apply the formual to find the next 4 terms of the sequence:
[tex]\begin{gathered} a_4=1+(4-1)\cdot5=1+3\cdot5=1+15=16 \\ a_5=1+(5-1)\cdot5=1+4\cdot5=1+20=21 \\ a_6=1+(6-1)\cdot5=1+5\cdot5=1+25=26 \\ a_7=1+(7-1)\cdot5=1+6\cdot5=1+30=31 \end{gathered}[/tex]The next 4 terms are: A. 16,21,26,31
State with the equation has one solution, new solution, or infinitely many solutions.
Answers
SOLUTION:
The equation is;
[tex]\begin{gathered} -2g+10=8g \\ 10=10g \\ g=1 \\ \end{gathered}[/tex]The equation has one solution
the next model of a sports car will cost 14.4% more than the current model the current model cost $41,000 how much would a price increase in dollars what would the price of the next model?
Answers
Given that the current model of the car cost;
[tex]\text{ \$41,000}[/tex]We are informed that the next model of a sports car will cost 14.4% more than the current model.
The price increase in dollars will then be given as;
[tex]\begin{gathered} \frac{14.4}{100}\times41000 \\ =\text{ \$}5904 \end{gathered}[/tex]Answer 1: Price increase in dollars is $5904
The cost of the next model will then be the sum of the current model and the price increase in dollars.
This would give;
[tex]\text{ \$41000+\$5904=\$46904}[/tex]Answer 2: The cost of the next price model is $46904
Which of the following methods of timekeeping is the least precise?A. Using a stopwatchB. Using a wrist watchC. Counting your heartbeatsO D. Using a calendar
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It’s c counting your heartbeats
My reasoning is that a wrist watch, a calendar and a stop watch all function on metered, constant intervals of time. A heart beat doesn't. It changes from person to person, from moment to moment. It isn't regular enough to be a precise unit of measure.
Find the square root. Assume that the variable is unrestricted, and use absolute value symbols when necessary. (Simplify your answer completely)
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We are given the following expression:
[tex]\sqrt[]{81x^2}[/tex]To simplify this expression we will use the following property of radicals:
[tex]\sqrt[]{ab}=\sqrt[]{a}\sqrt[]{b}[/tex]Applying the property we get:
[tex]\sqrt[]{81x^2}=\sqrt[]{81}\sqrt[]{x^2}[/tex]Now, the first radical is equal to 9 since 9 x 9 = 81, therefore, we get:
[tex]\sqrt[]{81x^2}=\sqrt[]{81}\sqrt[]{x^2}=9\sqrt[]{x^2}[/tex]For the second radical we will use the following property of absolute values:
[tex]\lvert x\rvert=\sqrt[]{x^2}[/tex]Replacing we get:
[tex]\sqrt[]{81x^2}=\sqrt[]{81}\sqrt[]{x^2}=9\sqrt[]{x^2}=9\lvert x\rvert[/tex]Therefore, the expression reduces to the product of 9 and the absolute value of "x".
I need the answer to this use fractions and pi
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We are to find the positive and negative angles that are coterminal with
[tex]\frac{2\pi}{3}[/tex]By definition
Coterminal Angles are angles that share the same initial side and terminal sides. Finding coterminal angles is as simple as adding or subtracting 360° or 2π to each angle, depending on whether the given angle is in degrees or radians
Hence,
The positive coterminal angle is
[tex]\frac{2\pi}{3}+2\pi[/tex]Simplifying this we get
[tex]\begin{gathered} \frac{2\pi}{3}+2\pi \\ =\frac{2\pi+6\pi}{3} \\ =\frac{8\pi}{3} \end{gathered}[/tex]Therefore, the positive coterminal angle is
[tex]\frac{8\pi}{3}[/tex]The negative coterminal angle is
[tex]\begin{gathered} \frac{2\pi}{3}-2\pi \\ =\frac{2\pi-6\pi}{3} \\ =-\frac{4\pi}{3} \end{gathered}[/tex]Therefore, the negative coterminal angle is
[tex]-\frac{4\pi}{3}[/tex]Which equation represents a line which is perpendicular to the line y - 6x = -3? Submit Answer Oy= 6x +3 Oy= 1/6x +4 O y= - 1/6x + 8 O y = -6x + 2
Answers
When we have two perpendicular lines their slopes are opposite and inverse.
In this case, we have the equation of the line:
y-6x= -3
Let's solve for y and arrange this equation to make it look like the general form of a linear equation: y=mx+b, where m is the slope of the line.
y-6x= -3
y-6x+6x= -3+6x
y= 6x-3
As we can see, the number that is multiplying the x variable in our equation is 6, the slope of this line is 6.
As mentioned, a perpendicular line to the line y= 6x-3 would have a slope opposite and inverse, then the slope of the line perpendicular to the first line (m2) would be:
[tex]m2=-\frac{1}{6}[/tex]from the options that we have, we can see that the only line that has a slope of -1/6 is the line y= -1/6+8, so that is the right option.
I need help with this please. I have tried multiple times but still could not get the correct answers
Answers
Recall that the diagonals of a rhombus are perpendicular bisectors of each other, therefore all the right triangles formed by the diagonals as shown in the given diagram are congruent, therefore:
[tex]\begin{gathered} \measuredangle1=\measuredangle4=\measuredangle2, \\ \measuredangle3=39^{\circ}, \\ \measuredangle1+39^{\circ}=90^{\circ}. \end{gathered}[/tex]Solving the last equation for angle 1 we get:
[tex]\begin{gathered} \measuredangle1=90^{\circ}-39^{\circ}, \\ \measuredangle1=51^{\circ}. \end{gathered}[/tex]Answer:
[tex]\begin{gathered} m\angle1=51^{\circ}, \\ m\angle2=51^{\circ}, \\ m\angle3=39^{\circ}, \\ m\angle4=51^{\circ}. \end{gathered}[/tex]Answer the following questions.(a) 12 is 15% of what?.(b) 45% of 60 is what number?.
Answers
ANSWER:
(a) 80
(b) 27
STEP-BY-STEP EXPLANATION:
(a)
We must calculate what number 15% is equal to 12, therefore, we do the following operation:
[tex]100\cdot\frac{12}{15}=80[/tex](b)
In this case we must calculate 45% of 60, therefore:
[tex]60\cdot\frac{45}{100}=27[/tex]solve for 2 cos x+sqrt2 =0 for o
pi/4
3pi/4
5pi/4
7pi/4
it's 3pi/ 4 and 5pi/4
Answers
Answer:
[tex]\frac{3\pi }{4} \ and \ \frac{5\pi }{4} .[/tex]
Step-by-step explanation:
[tex]1. \ cosx=-\frac{\sqrt{2} }{2};\\x=^+_-\frac{3 \pi}{4}+2 \pi n, \ where \ n=Z.[/tex]
2. finally, the answer is
[tex]\frac{3\pi }{4} \&\frac{5\pi }{4} .[/tex]
use the given graph to find the mean, median and mode of the following distribution: the mean is _______the median is _______the mode(s) is/are: __________Note: when the data is presented in a frequency table, the formula to find the mean is:
Answers
Solution:
Given:
From the graph above, a frequency table can be made as shown below;
To calculate the mean;
[tex]\begin{gathered} \text{Mean}=\frac{\Sigma fx}{\Sigma f} \\ \text{Mean}=\frac{189}{20} \\ \text{Mean}=9.45 \end{gathered}[/tex]Therefore, the mean is 9.45
To calculate the median;
Median is the middle term when the data is arranged in rank order.
Since we have 20 terms, then the middle terms will be the 10th and 11th terms.
The median will be the mean of these two numbers.
[tex]\begin{gathered} 10th\text{ term=9} \\ 11th\text{ term=10} \\ \text{Median}=\frac{9+10}{2} \\ \text{Median}=\frac{19}{2} \\ \text{Median}=9.5 \end{gathered}[/tex]Therefore, the median is 9.5
To calculate the mode;
The mode is the data that appears most in the set. It is the data with the highest frequency.
From the graph
From the graph
1. Find the slope 2.what is wrong with the following slopes ?
Answers
Given two points (x₁, y₁) and (x₂, y₂), the slope (m) is:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]So, to solve this question. Follow the steps.
Step 01: Substitute the points in the equation and solve part 1.
(x₁, y₁) = (-3, -1)
(x₂, y₂) = (-2, 6)
[tex]\begin{gathered} m=\frac{6-(-1)}{-2-(-3)} \\ m=\frac{6+1}{-2+3} \\ m=\frac{7}{1} \\ m=7 \end{gathered}[/tex]The slope is 7.
Step 02: Find what is wrong.
The points are:
(x₁, y₁) = (3, 5)
(x₂, y₂) = (-2, 6)
So, substituting in the equation:
[tex]m=\frac{6-5}{-2-3}=\frac{1}{-5}=-\frac{1}{5}[/tex]What is wrong is that the numerator was substituted by (y₁ - y₂), while the denominator was substituted by (x₂ -x₁).